- A delivery team is reviewing the components of the Apgar score before a high-risk birth. Of the five Apgar parameters, which two are generally the last to improve and therefore most often account for a reduced score in an otherwise vigorous term newborn at 1 minute?
- Heart rate and respiratory effort
- Color and reflex irritability
- Muscle tone and heart rate
- Respiratory effort and muscle tone
Correct answer: Color and reflex irritability
Color and reflex irritability is correct because peripheral perfusion lags behind central oxygenation, so acrocyanosis frequently costs a point on color, and the grimace/reflex response is also commonly blunted in the first minute even when heart rate, tone, and breathing are robust. Heart rate above 100 and vigorous crying typically secure full points quickly in a healthy term infant, so the heart-rate, respiratory-effort, and tone categories are usually not the limiting factors; the color and reflex categories most often explain a 1-minute score below 10.
- A newborn assessed at 5 minutes has a persistent Apgar score of 3 despite initial resuscitation. According to standard newborn assessment protocol, what is the recommended next step regarding Apgar scoring?
- Discontinue scoring because only the 1- and 5-minute values are valid
- Repeat the score once at 30 minutes only
- Replace Apgar scoring with a single arterial blood gas value
- Continue assigning Apgar scores every 5 minutes up to 20 minutes
Correct answer: Continue assigning Apgar scores every 5 minutes up to 20 minutes
Continuing to assign Apgar scores every 5 minutes up to 20 minutes is correct because when the 5-minute score remains below 7, the protocol calls for repeated scoring at 10, 15, and 20 minutes to track the infant's response to ongoing resuscitation. Scoring is not limited strictly to the 1- and 5-minute marks when the infant is depressed, a single 30-minute repeat does not match the every-5-minute schedule, and although blood gases add information, they do not replace serial Apgar assessment.
- A 15-year-old boy is evaluated for pubertal staging. Examination shows the penis enlarged in both length and breadth, the testes and scrotum further enlarged with darkened scrotal skin, and coarse curly pubic hair that has not yet spread to the medial thighs. Using the Tanner system, which stage does this represent?
- Tanner stage 2
- Tanner stage 3
- Tanner stage 4
- Tanner stage 5
Correct answer: Tanner stage 4
Tanner stage 4 is correct because in boys this stage features continued enlargement of the penis in length and breadth, further growth and darkening of the testes and scrotum, and adult-type coarse pubic hair that has not yet extended to the medial thighs. Stage 2 shows only early testicular enlargement, stage 3 shows lengthening of the penis with sparser hair spreading over the pubis, and stage 5 is adult genitalia with pubic hair spread to the medial thighs, so the findings described fall specifically in stage 4.
- An endocrinologist explains that the Tanner staging system separately rates two physical characteristics in each sex to track puberty. Which pair of characteristics does the Tanner system score?
- Height velocity and bone age
- Body mass index and voice change
- Axillary hair and facial acne
- Breast or genital development and pubic hair growth
Correct answer: Breast or genital development and pubic hair growth
Breast or genital development and pubic hair growth is correct because Tanner staging assigns stages 1 through 5 based on breast development in girls (or external genital development in boys) along with the separately rated pubic hair pattern. Height velocity and bone age are tracked by growth charts and radiographs rather than Tanner stages, and body mass index, voice change, axillary hair, and acne are not the defined Tanner parameters even though some occur during puberty.
- A 35-year-old woman with trisomy 21 (Down syndrome) presents with progressive memory loss and functional decline. Adults with Down syndrome are at markedly increased risk of early-onset dementia most directly because the extra chromosome 21 leads to overexpression of which gene product?
- Amyloid precursor protein
- Huntingtin protein
- Presenilin-2
- Alpha-synuclein
Correct answer: Amyloid precursor protein
Amyloid precursor protein is correct because the gene encoding it lies on chromosome 21, so trisomy 21 produces a gene-dosage excess that accelerates amyloid-beta deposition, explaining the very high rate of early Alzheimer-type dementia in adults with Down syndrome. The huntingtin gene is on chromosome 4, presenilin-2 is on chromosome 1, and alpha-synuclein relates to Parkinson and Lewy body disease rather than the amyloid pathology driven by triplicated chromosome 21.
- A 38-year-old pregnant woman is counseled that maternal age increases the risk of trisomy 21. The great majority of Down syndrome cases arise from which chromosomal mechanism, which becomes more frequent with advancing maternal age?
- Robertsonian translocation involving chromosome 21
- Mosaicism arising from postzygotic mitotic error
- Uniparental disomy of chromosome 21
- Meiotic nondisjunction of chromosome 21
Correct answer: Meiotic nondisjunction of chromosome 21
Meiotic nondisjunction of chromosome 21 is correct because roughly 95 percent of Down syndrome results from failure of homologous chromosomes to separate during maternal meiosis, producing a gamete with an extra chromosome 21, and this error rises sharply with maternal age. Robertsonian translocations account for only a small fraction and are not strongly age-related, mosaicism from a postzygotic mitotic error explains a small minority of cases, and uniparental disomy is not a recognized common cause of Down syndrome.
- Genetic counseling is provided to a couple about preventing recurrence of a neural tube defect in a future pregnancy, given that their previous child had a myelomeningocele. Compared with the standard prenatal dose, how should periconceptional folic acid supplementation be adjusted for a woman with a prior affected pregnancy?
- The dose should be the same as routine supplementation
- Supplementation should be stopped to avoid masking vitamin B12 deficiency
- A substantially higher dose should be started before conception
- Supplementation should begin only after the first trimester
Correct answer: A substantially higher dose should be started before conception
Starting a substantially higher folic acid dose before conception is correct because women with a previously affected pregnancy carry a much greater recurrence risk, so high-dose supplementation beginning before conception and continuing through early pregnancy is recommended to support neural tube closure during weeks 3 to 4. Keeping the routine low dose is inadequate for this high-risk group, stopping supplementation increases risk, and delaying until after the first trimester misses the critical closure window entirely.
- A fetus is diagnosed with anencephaly on second-trimester ultrasound. Anencephaly and spina bifida share the same fundamental embryologic origin. Both are caused by abnormal closure of which structure during the third to fourth week of development?
- The neural tube
- The branchial (pharyngeal) arches
- The cloacal membrane
- The atrial septum
Correct answer: The neural tube
The neural tube is correct because both anencephaly and spina bifida are classic neural tube defects arising from failure of the neural tube to close during the third to fourth week, with the cranial end affected in anencephaly and the caudal end in spina bifida. The pharyngeal arches give rise to head and neck structures, the cloacal membrane relates to anorectal and urogenital openings, and the atrial septum forms the heart, none of which produces this category of midline dorsal defect.
- A 12-month-old infant is evaluated at a well-child visit. Which combination of milestones is most consistent with typical development at 12 months of age?
- Crawls only, has no pincer grasp, and does not babble
- Walks up stairs alternating feet and speaks in three-word sentences
- Jumps with both feet and names four colors
- Stands and may take first steps, uses a mature pincer grasp, and says one to two words
Correct answer: Stands and may take first steps, uses a mature pincer grasp, and says one to two words
Standing and possibly taking first steps, using a mature pincer grasp, and saying one to two words is correct because by about 12 months infants pull to stand and begin walking, develop a refined thumb-finger pincer grasp, and say a few meaningful words such as mama or dada. Crawling with no pincer grasp and no babble describes a younger infant, stair-climbing with three-word sentences corresponds to roughly age 3, and jumping with color naming reflects the preschool years.
- A clinician follows an infant from birth and tracks the order in which gross motor skills appear. Which sequence correctly reflects the typical cephalocaudal progression of infant gross motor development?
- Walks, then sits, then holds head up
- Holds head up, then sits, then walks
- Sits, then holds head up, then walks
- Walks, then holds head up, then sits
Correct answer: Holds head up, then sits, then walks
Holding the head up, then sitting, then walking is correct because motor development proceeds in a cephalocaudal (head-to-toe) direction, so infants gain head control first (around 2 to 4 months), then trunk control for sitting (around 6 months), and finally lower-limb control for walking (around 12 months). The other sequences violate this orderly head-to-toe pattern by placing walking or sitting before head control, which is not how normal motor maturation unfolds.
- A teratology lecture emphasizes that ionizing radiation, certain drugs, and infections all cause the most severe structural birth defects when exposure occurs during a specific developmental window. During which gestational interval are major morphologic malformations of organs most likely to be induced?
- Weeks 1 through 2 after fertilization
- Weeks 3 through 8 after fertilization
- Weeks 20 through 28 of gestation
- Weeks 36 through 40 of gestation
Correct answer: Weeks 3 through 8 after fertilization
Weeks 3 through 8 after fertilization is correct because this embryonic period of organogenesis is when organ systems are actively forming and are most vulnerable to structural disruption, making it the window for major morphologic malformations. Weeks 1 to 2 produce an all-or-none response rather than malformation, and exposures in the later fetal weeks (20 to 28 or 36 to 40) tend to cause functional deficits or growth restriction rather than gross structural anomalies.
- A 70-year-old man undergoes a comprehensive geriatric evaluation. Which change is considered a normal physiologic consequence of aging rather than a disease process?
- Resting tremor with bradykinesia
- Decline in glomerular filtration rate and reduced renal reserve
- Progressive loss of recognition of family members
- New-onset resting chest pain with exertion
Correct answer: Decline in glomerular filtration rate and reduced renal reserve
A decline in glomerular filtration rate with reduced renal reserve is correct because nephron number and renal functional reserve normally decrease with age, which is expected senescence and has important implications for drug dosing in older adults. A resting tremor with bradykinesia indicates Parkinson disease, progressive loss of recognition of family members indicates dementia, and exertional chest pain indicates ischemic heart disease, all of which are pathologic conditions rather than normal aging.
- A developmental pediatrician explains that the central nervous system develops over a uniquely prolonged window compared with most other organs. Which feature of central nervous system development accounts for its extended period of vulnerability to injury and teratogens?
- It completes structural development entirely within the first 8 weeks
- Neuronal proliferation, migration, and myelination continue from the embryonic period into postnatal life
- It is fully protected from teratogens by the placenta after week 12
- It develops only during the third trimester
Correct answer: Neuronal proliferation, migration, and myelination continue from the embryonic period into postnatal life
Continuation of neuronal proliferation, migration, and myelination from the embryonic period into postnatal life is correct because, unlike organs whose structural windows close by the end of the embryonic period, the brain keeps building and remodeling its circuitry well past birth, giving it an unusually long span of susceptibility to insults such as alcohol and infection. The brain does not finish developing within 8 weeks, the placenta does not shield it after week 12, and its development spans far more than the third trimester alone.
- A 4-year-old child is asked to copy shapes and follow directions during a developmental screen. Which combination of milestones is most consistent with typical development at 4 years of age?
- Copies a cross, hops on one foot, and tells a simple story
- Scribbles spontaneously, walks alone, and uses single words
- Copies a triangle, skips alternating feet, and reads simple sentences
- Stacks two blocks and points to one named object
Correct answer: Copies a cross, hops on one foot, and tells a simple story
Copying a cross, hopping on one foot, and telling a simple story is correct because by age 4 children can copy a cross (and often a square), balance well enough to hop on one foot, and narrate a short coherent story. Scribbling with single words and walking alone reflects a roughly 12- to 18-month-old, copying a triangle and skipping with reading describes a 5- to 6-year-old, and stacking only two blocks while pointing to one object corresponds to about 15 to 18 months.
- A research team is developing a screening test for a treatable infection and deliberately tunes the assay to capture nearly every infected person, accepting that many uninfected people will be wrongly flagged for follow-up confirmatory testing. Which combination of test properties does this tuning favor?
- High specificity with low sensitivity
- High sensitivity with low specificity
- High positive predictive value with low sensitivity
- Equal sensitivity and specificity at a single fixed point
Correct answer: High sensitivity with low specificity
This tuning favors high sensitivity with low specificity. Capturing nearly every infected person requires a sensitive test that produces few false negatives, while accepting many wrongly flagged uninfected people reflects a tolerance for false positives, which is low specificity. Favoring specificity would instead minimize false positives, and predictive value is not an intrinsic property that can be tuned independently of prevalence.
- A blood test for an infectious disease is positive in 160 of 200 people who truly have the disease and negative in 270 of 300 people who truly do not have it. What is the sensitivity of this test?
- 90 percent
- 57 percent
- 60 percent
- 80 percent
Correct answer: 80 percent
The sensitivity is 80 percent. Sensitivity is the proportion of truly diseased people who test positive, calculated as 200160=80%, the 160 true positives divided by the 200 people who actually have the disease. The data on the 300 disease-free people pertain to specificity and are not used in computing sensitivity, so only the diseased group matters here.
- A clinician orders two tests in sequence for the same disease, calling a patient positive only when both the first and the second test return positive results. Compared with using either test alone, how does this serial testing strategy change overall sensitivity and specificity?
- It raises specificity and lowers sensitivity
- It raises sensitivity and lowers specificity
- It raises both sensitivity and specificity
- It leaves both unchanged
Correct answer: It raises specificity and lowers sensitivity
Serial testing, requiring both tests to be positive, raises specificity and lowers sensitivity, because demanding agreement from two tests greatly reduces false positives but also discards true cases that one test alone would have caught. This trades sensitivity for specificity, the opposite of parallel testing in which a positive on either test increases sensitivity at the expense of specificity.
- A new biomarker test for an autoimmune disease has a specificity of 96 percent. In a sample of 250 people who genuinely do not have the disease, approximately how many would be expected to test positive?
Correct answer: 10
About 10 disease-free people would test positive. A specificity of 96 percent means 0.96×250=240 disease-free people correctly test negative, leaving the remaining 4 percent, 0.04×250=10 people, as false positives. The figure 240 represents true negatives rather than the false positives requested by the question.
- A continuous laboratory assay is plotted as a receiver operating characteristic curve. As the investigators slide the decision threshold along this curve toward values that classify more people as positive, which trade-off best describes the movement along the curve?
- Both sensitivity and the false-positive rate decrease together
- Sensitivity increases while the false-positive rate also increases
- Sensitivity stays fixed while only specificity changes
- Sensitivity decreases while the false-positive rate increases
Correct answer: Sensitivity increases while the false-positive rate also increases
Moving the threshold to classify more people as positive increases sensitivity while the false-positive rate also increases. Capturing more true positives by lowering the bar inevitably sweeps in more false positives, which is why the receiver operating characteristic curve rises toward the upper right. The two quantities move together in this direction rather than in opposite directions, and sensitivity does not stay fixed as the threshold shifts.
- A diagnostic test has a sensitivity of 50 percent and a specificity of 50 percent for a given disease. How does the discriminating ability of this test compare with simply guessing at random whether a patient has the disease?
- It is no better than chance at distinguishing diseased from disease-free people
- It is far better than chance because both values are above zero
- It perfectly separates diseased from disease-free people
- It is useful only for confirming disease but not for ruling it out
Correct answer: It is no better than chance at distinguishing diseased from disease-free people
A test with sensitivity and specificity each at 50 percent is no better than chance at distinguishing diseased from disease-free people, because it correctly classifies only half of each group, the same result a coin flip would achieve. Such a test corresponds to a receiver operating characteristic area under the curve of about 0.5, the diagonal line of no discrimination, so it provides no useful diagnostic information in either direction.
- A disease has a prevalence of 25 percent in a clinic population. A test with a sensitivity of 80 percent and a specificity of 90 percent is applied to 1,000 patients, in which 250 are diseased and 750 are disease-free. The diseased yield 200 true positives and the disease-free yield 75 false positives. What is the positive predictive value?
- About 80 percent
- About 90 percent
- About 73 percent
- About 25 percent
Correct answer: About 73 percent
The positive predictive value is about 73 percent. It equals the true positives divided by all positives, which is 275200≈0.73, the 200 true positives over the 275 total positives made up of 200 true positives plus 75 false positives. The 80 percent value is the sensitivity, which ignores the false positives among those who test positive and therefore overstates how trustworthy a positive result is.
- Using the same clinic population of 1,000 patients with a 25 percent disease prevalence and a test of 80 percent sensitivity and 90 percent specificity, the 250 diseased patients produce 50 false negatives and the 750 disease-free patients produce 675 true negatives. What is the negative predictive value?
- About 90 percent
- About 80 percent
- About 73 percent
- About 93 percent
Correct answer: About 93 percent
The negative predictive value is about 93 percent. Among the negatives there are 675 true negatives and 50 false negatives, so the value is 675+50675=725675≈0.93. The negative predictive value is the proportion of people testing negative who are truly disease-free, and it differs from the specificity because it is computed among all negative results rather than among the disease-free group.
- A patient's probability of having a disease before any testing is estimated at 30 percent based on symptoms and risk factors. In diagnostic reasoning, what is this 30 percent figure called, and what role does it play in interpreting a subsequent test result?
- The specificity, which fixes the false-positive rate of the test
- The pretest probability, which combines with the test result to yield the posttest probability
- The sensitivity, which determines how many cases the test will catch
- The negative predictive value, which is independent of the test result
Correct answer: The pretest probability, which combines with the test result to yield the posttest probability
This 30 percent figure is the pretest probability, the estimated chance of disease before testing, and it combines with the test result to yield the posttest probability, essentially a predictive value tailored to this patient. Sensitivity and specificity are intrinsic test properties that do not depend on the patient's pretest estimate, and the negative predictive value is itself influenced by the underlying probability of disease rather than independent of it.
- A health system rolls out a screening test with fixed sensitivity and specificity to two regions. Region A has a disease prevalence of 8 percent and region B has a prevalence of 8 percent as well, but region B's laboratory mistakenly uses a stricter cutoff that lowers false positives. Holding prevalence equal, how does the stricter cutoff in region B affect the positive predictive value there?
- It raises the positive predictive value because fewer false positives occur among the positives
- It lowers the positive predictive value because sensitivity falls
- It has no effect because prevalence is identical in both regions
- It makes the positive predictive value equal to the prevalence
Correct answer: It raises the positive predictive value because fewer false positives occur among the positives
The stricter cutoff raises the positive predictive value in region B because reducing false positives means a larger share of all positive results are true positives. Even with prevalence held equal, the predictive value depends on both prevalence and the test's operating characteristics, so cutting false positives improves the trustworthiness of a positive result, and the value does not simply equal the prevalence.
- A clinician notes that for a rare disease, a negative result on a moderately sensitive test is very reassuring, while a positive result on the same test is frequently a false alarm. Which pair of predictive values best characterizes a low-prevalence setting?
- Low negative predictive value and high positive predictive value
- High negative predictive value and low positive predictive value
- Both predictive values are high
- Both predictive values are low
Correct answer: High negative predictive value and low positive predictive value
In a low-prevalence setting the negative predictive value is high and the positive predictive value is low. Because most people are truly disease-free, a negative result is almost always correct, giving a high negative predictive value, while the large disease-free group generates many false positives that outnumber the few true positives, driving the positive predictive value down. The two predictive values move oppositely with prevalence rather than together.
- A diagnostic test maintains a fixed sensitivity and specificity, but a clinician observes that a positive result is much more meaningful when the test is used in symptomatic patients than in asymptomatic volunteers. Which underlying difference best accounts for the greater meaning of a positive result in symptomatic patients?
- Symptomatic patients have a higher pretest probability of disease, raising the positive predictive value
- The test becomes more sensitive in symptomatic patients
- The test becomes more specific in symptomatic patients
- Symptoms eliminate the possibility of false-positive results
Correct answer: Symptomatic patients have a higher pretest probability of disease, raising the positive predictive value
Symptomatic patients have a higher pretest probability of disease, which raises the positive predictive value, so a positive result in them is more likely to reflect true disease. Sensitivity and specificity are intrinsic and do not change between symptomatic and asymptomatic groups, and symptoms do not eliminate false positives; rather, the higher underlying probability of disease shifts how a positive result should be interpreted.
- A cohort study follows workers exposed and unexposed to a dust over ten years. The cumulative incidence of lung fibrosis is 90 per 1,000 in the exposed and 30 per 1,000 in the unexposed. What is the relative risk of lung fibrosis associated with dust exposure?
Correct answer: 3.0
The relative risk is 3.0, found by dividing the incidence in the exposed by the incidence in the unexposed, 3090=3.0 per 1,000. A cohort study measures incidence directly, so the relative risk is the appropriate ratio. The value 60 is the absolute risk difference per 1,000 rather than the ratio, and 0.33 would arise from inverting the comparison of exposed to unexposed.
- A case-control study of a rare neurologic disorder finds that among cases, 80 were exposed and 20 were unexposed to a pesticide, while among controls, 40 were exposed and 160 were unexposed. What is the odds ratio for the exposure?
Correct answer: 16
The odds ratio is 16. In a case-control study the odds ratio equals the cross-product, calculated as exposed cases times unexposed controls divided by unexposed cases times exposed controls, or 20×4080×160=80012,800=16. Comparing simple proportions rather than the cross-product would give a different value, and inverting the ratio would yield a number below 1.
- An investigator is choosing a measure of association for a prospective cohort study that directly follows exposed and unexposed groups forward and records new cases over time. Which measure is most directly and validly calculated from this design?
- The odds ratio, because incidence cannot be measured prospectively
- The attack rate, which only applies to chronic exposures
- The positive predictive value of the exposure
- The relative risk, because incidence in each group is measured directly
Correct answer: The relative risk, because incidence in each group is measured directly
The relative risk is most directly and validly calculated, because a prospective cohort design measures the incidence of new cases in the exposed and unexposed groups, and the ratio of these incidences is the relative risk. The odds ratio is reserved for designs that cannot measure incidence, such as case-control studies, while the attack rate applies to acute outbreaks and predictive value is a diagnostic test concept, not a measure of exposure-disease association.
- Two case-control studies examine the same exposure and outcome. Study 1 investigates a very rare disease and study 2 investigates a common disease that affects nearly half the population. In which study is the calculated odds ratio expected to most closely approximate the true relative risk?
- Study 2, because common diseases give more stable estimates
- Both equally, because the odds ratio always equals the relative risk
- Study 1, because the rare-disease assumption makes the odds ratio approximate the relative risk
- Neither, because case-control studies cannot estimate relative risk in any form
Correct answer: Study 1, because the rare-disease assumption makes the odds ratio approximate the relative risk
The odds ratio in study 1 most closely approximates the true relative risk because the rare-disease assumption holds, and when disease is uncommon the odds ratio converges on the relative risk. In study 2, with a disease affecting nearly half the population, that assumption fails and the odds ratio overstates the relative risk. The odds ratio does not always equal the relative risk, and case-control studies can approximate it when the disease is rare.
- A cohort study reports a relative risk of 1.0 for an exposure, and a separate cohort reports a relative risk of 0.7 for the same exposure with a confidence interval entirely below 1. Comparing these two findings, what do they collectively suggest about the exposure?
- The first study shows no association while the second suggests the exposure is protective
- Both studies show the exposure increases risk
- Both studies show the exposure is harmful and significant
- The two relative risks describe the same protective effect
Correct answer: The first study shows no association while the second suggests the exposure is protective
The first study, with a relative risk of 1.0, shows no association because risk is equal in the exposed and unexposed, while the second, with a relative risk of 0.7 and a confidence interval below 1, suggests the exposure is protective and statistically significant. A value of 1.0 is the null, so it cannot indicate harm, and the two findings are not identical because one shows no effect and the other shows reduced risk.
- A drug lowers the incidence of a serious complication from 30 percent in the control group to 18 percent in the treatment group over one year. What is the number needed to treat to prevent one complication?
- About 8.3
- About 12
- About 5.6
- About 40
Correct answer: About 8.3
The number needed to treat is about 8.3. It equals 1 divided by the absolute risk reduction, and the absolute reduction is 0.30−0.18=0.12, so 0.121≈8.3. Using the relative reduction of 40 percent or the residual 18 percent treatment rate instead of the absolute difference would yield incorrect values, because the number needed to treat depends on the absolute risk difference.
- A reviewer has a trial in which the control event rate is 24 percent and the treatment event rate is 16 percent. To compute the number needed to treat, which sequence of steps is correct?
- Divide 16 by 24, then take the reciprocal
- Subtract 16 percent from 24 percent to get the absolute risk reduction, then take its reciprocal
- Add 24 percent and 16 percent, then divide into 1
- Multiply 24 percent by 16 percent, then take the reciprocal
Correct answer: Subtract 16 percent from 24 percent to get the absolute risk reduction, then take its reciprocal
The correct sequence is to subtract the treatment event rate from the control event rate to obtain the absolute risk reduction, here 0.24−0.16=0.08, and then take its reciprocal, 0.081=12.5. Dividing the rates yields the relative risk rather than the absolute reduction, and adding or multiplying the rates does not produce the absolute risk difference required for the number needed to treat.
- A medication increases the rate of a serious liver injury from 1 percent in untreated patients to 6 percent in treated patients. What is the number needed to harm, representing how many patients must be treated for one additional liver injury?
- About 17
- About 6
- About 100
- About 20
Correct answer: About 20
The number needed to harm is about 20. It equals 1 divided by the absolute risk increase, which is 0.06−0.01=0.05, so 0.051=20. The number needed to harm parallels the number needed to treat but uses the absolute increase in a harmful outcome, so treating 20 patients leads to one extra liver injury attributable to the drug.
- A guideline panel compares two drugs for preventing the same event over the same period. Drug X has a number needed to treat of 9 and drug Y has a number needed to treat of 9 as well, but drug Y causes a serious side effect with a number needed to harm of 50, whereas drug X has a number needed to harm of 500. Considering both benefit and harm, which drug offers the better balance?
- Drug Y, because its number needed to harm is smaller
- Both are identical because the numbers needed to treat are equal
- Drug X, because with equal benefit its harms are far less frequent
- Drug Y, because a low number needed to harm indicates safety
Correct answer: Drug X, because with equal benefit its harms are far less frequent
Drug X offers the better balance because the two drugs provide equal benefit, reflected in identical numbers needed to treat, but drug X harms far fewer patients, shown by its much larger number needed to harm of 500 versus 50 for drug Y. A smaller number needed to harm indicates more frequent harm, not greater safety, so equal benefit combined with rarer harm makes drug X preferable.
- A trial of a preventive therapy reports an absolute risk reduction of 0.02 over five years. A second therapy for a different but comparably serious outcome reports an absolute risk reduction of 0.10 over the same period. Which therapy has the smaller number needed to treat, and what does that imply about treatment burden?
- The first therapy, because a smaller absolute reduction gives a smaller number needed to treat
- Both have the same number needed to treat because both reduce risk
- Neither, because the number needed to treat cannot be compared across outcomes
- The second therapy, because a larger absolute risk reduction gives a smaller number needed to treat, so fewer patients must be treated per event prevented
Correct answer: The second therapy, because a larger absolute risk reduction gives a smaller number needed to treat, so fewer patients must be treated per event prevented
The second therapy has the smaller number needed to treat because a larger absolute risk reduction yields a smaller reciprocal, so fewer patients must be treated to prevent one event. The first therapy's reduction of 0.02 gives 0.021=50, while the second therapy's reduction of 0.10 gives 0.101=10, meaning the second imposes far less treatment burden per event prevented.
- An observational study finds that patients taking a particular heartburn medication have higher rates of pneumonia. Investigators realize that the patients prescribed this medication tend to be older and frailer, and frailty independently raises pneumonia risk while also prompting clinicians to prescribe the medication. Frailty in this scenario is best described as which type of variable?
- A mediator on the causal pathway from the medication to pneumonia
- A confounding variable
- The outcome variable
- An effect modifier that has no association with the medication
Correct answer: A confounding variable
Frailty is a confounding variable because it is associated with the exposure of taking the medication and is independently a risk factor for the outcome of pneumonia, yet it does not lie on the causal pathway between the drug and pneumonia, so it distorts the apparent association. A mediator would lie on the causal pathway, the outcome here is pneumonia itself, and an effect modifier that is unassociated with the exposure cannot confound the relationship.
- Investigators planning a cohort study are worried that sex will confound the relationship between an occupational exposure and a disease. They decide in advance to enroll only male workers. Which design-phase strategy for controlling confounding does enrolling only males represent?
- Matching cases to controls on sex
- Restriction of eligibility to one level of the confounder
- Stratified analysis performed after data collection
- Multivariable regression adjustment
Correct answer: Restriction of eligibility to one level of the confounder
Enrolling only male workers is restriction, a design-phase strategy that controls confounding by limiting eligibility to a single level of the confounding variable so it cannot vary across the study. Matching pairs participants on a confounder rather than excluding levels of it, while stratified analysis and multivariable regression are analytic methods applied after data collection rather than restrictions imposed at enrollment.
- An analyst suspects that a measured variable confounded an exposure-outcome association in an already-completed study. She splits the data into subgroups defined by levels of that variable and examines the exposure-outcome association separately within each subgroup. Which technique for addressing confounding is she using?
- Randomization
- Restriction at enrollment
- Blinding of outcome assessors
- Stratified analysis
Correct answer: Stratified analysis
Splitting the data into subgroups by levels of the suspected confounder and examining the association within each is stratified analysis, an analytic method that controls a measured confounder after data collection by holding it roughly constant within strata. Randomization and restriction are design-phase strategies that must occur before or during enrollment, and blinding reduces information bias rather than confounding, so neither matches the post-hoc stratification described.
- An investigator argues that a variable should not be adjusted for as a confounder because it actually lies on the causal pathway between the exposure and the disease, mediating part of the exposure's effect. Adjusting for such a pathway variable would most likely cause which problem?
- It would inappropriately remove part of the true causal effect of the exposure
- It would have no effect because pathway variables are confounders
- It would always strengthen the observed association
- It would convert the study into a randomized trial
Correct answer: It would inappropriately remove part of the true causal effect of the exposure
Adjusting for a variable that lies on the causal pathway, a mediator, would inappropriately remove part of the true causal effect of the exposure, because the mediator carries some of that effect and controlling for it blocks the very pathway being studied. A mediator is not a confounder, so adjusting for it does not leave the estimate unchanged, does not reliably strengthen the association, and certainly does not transform an observational study into a randomized trial.
- A reviewer concludes that an observed association between an exposure and a disease was entirely spurious because a third variable was associated with both the exposure and the outcome and was unevenly distributed between the comparison groups. Which feature most strongly distinguishes this confounding from a genuine effect of the exposure?
- The association persisted even after the third variable was controlled
- The association disappeared or substantially changed once the third variable was accounted for
- The association was found in a randomized controlled trial
- The third variable lay directly on the causal pathway between exposure and disease
Correct answer: The association disappeared or substantially changed once the third variable was accounted for
The hallmark distinguishing confounding from a genuine effect is that the association disappears or substantially changes once the confounding variable is accounted for, revealing the original link as spurious. If the association persisted after control, the third variable would not explain it; randomization tends to prevent confounding rather than demonstrate it; and a variable on the causal pathway would be a mediator, not a confounder.
- A researcher wants to study the natural history and risk factors of a chronic disease by enrolling a large group of currently healthy adults, recording their baseline characteristics, and following them for fifteen years to see who develops the disease. Which study design does this describe?
- Case-control study
- Cross-sectional study
- Prospective cohort study
- Ecological study
Correct answer: Prospective cohort study
This describes a prospective cohort study, because a group of initially healthy people is characterized at baseline and followed forward over time to observe who develops the disease, allowing direct measurement of incidence and risk factors. A case-control study starts from disease status and looks backward, a cross-sectional study captures one moment in time, and an ecological study uses group-level rather than individual data.
- An investigator assembles patients who already have a rare cancer and a comparison group without the cancer, then interviews both groups about their past occupational exposures to identify possible causes. Which study design is this, and why is it well suited to a rare disease?
- A case-control study, because starting from existing cases efficiently captures a rare outcome
- A prospective cohort study, because it follows exposure forward to disease
- A randomized controlled trial, because it assigns exposure at random
- A cross-sectional study, because it measures exposure and disease at one time
Correct answer: A case-control study, because starting from existing cases efficiently captures a rare outcome
This is a case-control study, which is well suited to a rare disease because it begins with existing cases and compares their past exposures with those of controls, efficiently capturing a rare outcome without following huge populations for years. A prospective cohort would require enormous numbers and long follow-up to accrue rare cases, a randomized trial cannot ethically assign suspected harmful exposures, and a cross-sectional study cannot establish the temporal order needed to study causes.
- A team designs a study in which eligible patients are allocated by a chance mechanism to receive either a new drug or a placebo, and both groups are then followed forward to compare outcomes. Which feature of this design most directly supports a causal interpretation of any difference in outcomes?
- The retrospective collection of exposure histories
- The chance-based allocation, which tends to balance both known and unknown baseline factors between groups
- The selection of participants based on their disease status
- The measurement of exposure and outcome at a single point in time
Correct answer: The chance-based allocation, which tends to balance both known and unknown baseline factors between groups
The chance-based allocation most directly supports a causal interpretation because randomly assigning patients tends to balance both known and unknown baseline factors between the groups, so any outcome difference is more plausibly due to the drug. Retrospective exposure collection and selection by disease status describe observational designs prone to confounding, and single-time measurement describes a cross-sectional study, none of which provides the causal strength of randomization.
- An investigator examines all residents of a town at one moment, recording whether each person currently has both a particular dietary habit and a chronic skin condition, then assesses their association. Which study design is this, and what is a key reason it cannot establish that the diet caused the skin condition?
- A cohort study, which is limited by loss to follow-up over time
- A case-control study, which is limited by recall of past diet
- A cross-sectional study, which measures exposure and outcome simultaneously and so cannot establish which came first
- A randomized trial, which is limited by ethical constraints on assigning diet
Correct answer: A cross-sectional study, which measures exposure and outcome simultaneously and so cannot establish which came first
This is a cross-sectional study, which measures exposure and outcome simultaneously at one point in time, so it cannot establish temporal sequence and therefore cannot show that the diet preceded and caused the skin condition. Loss to follow-up characterizes cohort studies, recall of past exposure characterizes case-control studies, and ethical constraints on assignment characterize randomized trials, none of which is the snapshot design described here.
- When research evidence is organized into a hierarchy by strength for guiding treatment decisions, which ordering correctly ranks designs from strongest to weakest?
- Case report, then cohort study, then randomized controlled trial, then systematic review of trials
- Systematic review of randomized trials, then randomized controlled trial, then cohort study, then case report
- Cohort study, then randomized controlled trial, then case report, then systematic review
- Randomized controlled trial, then case report, then systematic review, then cohort study
Correct answer: Systematic review of randomized trials, then randomized controlled trial, then cohort study, then case report
The correct ordering from strongest to weakest is a systematic review of randomized trials, then an individual randomized controlled trial, then a cohort study, then a case report. Pooled high-quality randomized evidence sits at the top because it combines multiple controlled studies, randomized trials and cohort studies follow as decreasingly rigorous designs, and a single uncontrolled case report provides the weakest evidence, so any sequence placing a case report above these is incorrect.
- A surgeon obtains a patient's signed consent for a planned removal of the right ovary. During the operation, the surgeon unexpectedly finds a suspicious mass on the left ovary and is unsure whether to remove it as well, since the patient never consented to anything on the left side and is not in immediate danger. Absent a life-threatening emergency, what is the most appropriate action?
- Leave the unanticipated mass and discuss it with the patient after she awakens to obtain consent for any further procedure
- Remove the left ovarian mass too, since the abdomen is already open and it is efficient
- Ask the circulating nurse to authorize the additional removal
- Remove the mass and document that the patient impliedly consented to anything found
Correct answer: Leave the unanticipated mass and discuss it with the patient after she awakens to obtain consent for any further procedure
Consent is procedure-specific, so absent a true emergency the surgeon should not extend surgery beyond what was authorized and should discuss the unanticipated finding with the patient afterward to obtain consent for any additional operation. Convenience, a nurse's authorization, or an assumption of blanket implied consent cannot substitute for the patient's specific informed agreement to a new procedure.
- A physician is deciding how much information to share before a procedure and learns that the prevailing legal standard in her jurisdiction asks what a typical patient in similar circumstances would want to know in order to make the decision. This benchmark for the scope of disclosure is best described as which of the following?
- The reasonable-patient standard
- The professional or reasonable-physician standard
- The subjective patient standard
- The minimum necessary standard
Correct answer: The reasonable-patient standard
Judging disclosure by what a typical patient in similar circumstances would want to know is the reasonable-patient standard, which centers the information needs of patients rather than custom among physicians. The reasonable-physician standard measures against what doctors customarily disclose, the subjective standard focuses on one particular patient's idiosyncratic wishes, and the minimum necessary standard governs access to health records.
- A patient rolls up her sleeve and holds out her arm without objection when the nurse approaches to draw a routine blood sample that was already discussed and ordered. The patient's cooperative gesture, without a formal signature, most clearly illustrates which type of consent for this low-risk routine task?
- Implied consent inferred from the patient's conduct
- Therapeutic privilege
- Substituted judgment
- Presumed consent under the emergency exception
Correct answer: Implied consent inferred from the patient's conduct
Extending the arm for an already-discussed routine blood draw conveys implied consent, which is reasonably inferred from the patient's voluntary conduct for low-risk routine care. Therapeutic privilege concerns withholding information, substituted judgment involves a surrogate, and the emergency exception applies to incapacitated patients facing life-threatening conditions.
- A physician recommends a surgery and discloses its risks and benefits, but never mentions that a less invasive nonsurgical option with comparable outcomes exists. The patient consents to surgery. Which element of valid informed consent was most clearly deficient?
- Assessment of the patient's decision-making capacity
- Confirmation of voluntariness
- Verification that the patient signed the form
- Disclosure of reasonable alternatives to the proposed treatment
Correct answer: Disclosure of reasonable alternatives to the proposed treatment
Failing to mention a reasonable, comparable alternative means the disclosure of alternatives was incomplete, so the patient could not weigh her options as valid consent requires. The deficiency lies in the content of disclosure rather than in the patient's capacity, the voluntariness of the choice, or the presence of a signature.
- A 4-year-old needs an urgent appendectomy, and his parents are providing consent on his behalf. Strictly speaking, what is the correct term for the parents' authorization given for a young child who cannot consent for himself?
- Implied consent by the child
- The child's own informed consent
- Informed permission given by the parents on the child's behalf
- Therapeutic privilege exercised by the parents
Correct answer: Informed permission given by the parents on the child's behalf
Because a young child cannot legally consent, parents provide informed permission on the child's behalf, which is the precise term distinguishing surrogate authorization from a patient's own consent. The child cannot give implied or informed consent at this age, and therapeutic privilege refers to withholding information rather than authorizing care.
- A clinician is preparing to give a school-aged child an injection and, although the parents have already consented, takes time to explain the procedure in simple terms and ask whether the child is willing to go along with it. Seeking a child's affirmative agreement to participate in care, in addition to parental permission, is best described as which of the following?
- Obtaining the child's informed consent
- Obtaining the child's assent
- Substituted judgment
- Emancipation of the minor
Correct answer: Obtaining the child's assent
Seeking a child's developmentally appropriate willingness to participate, alongside parental permission, is obtaining assent, which respects the child within the limits of his maturity. It is not full legal consent, which the child cannot give, nor substituted judgment or emancipation, which involve surrogate decisions or a minor's legal independence.
- A patient consents to a procedure after the physician knowingly minimizes a well-established serious risk, telling her it almost never happens when in fact it is fairly common. The patient later experiences that complication. With respect to the validity of her consent, what is the central problem?
- The patient lacked capacity to decide
- The decision was involuntary due to coercion
- The consent was based on inaccurate disclosure, so it was not truly informed
- The signed form was missing a witness
Correct answer: The consent was based on inaccurate disclosure, so it was not truly informed
Misrepresenting the likelihood of a known serious risk corrupts the disclosure, so the patient's agreement was not based on accurate information and therefore was not truly informed. The flaw is the integrity of the disclosure rather than the patient's capacity, the voluntariness of her choice, or a witnessing technicality.
- A physician suspects that a quiet, very deferential patient is agreeing to a treatment mainly because an adult child in the room is strongly pushing for it and the patient seems afraid to disagree. To protect the integrity of consent, which step is most appropriate?
- Proceed because a family member supports the plan
- Ask the adult child to sign the consent form
- Document that consensus was reached in the room
- Speak with the patient privately to confirm the decision is genuinely her own
Correct answer: Speak with the patient privately to confirm the decision is genuinely her own
Because voluntariness is essential to valid consent, the physician should speak with the patient privately to ensure the choice is truly hers and free of family pressure. Proceeding on family support, having a relative sign, or noting a group consensus would not establish that the patient herself is freely consenting.
- After a thorough consent discussion for an elective operation, a patient says she has heard enough and explicitly tells the physician she does not want to hear any more details about the risks and just wants to proceed. Honoring a competent patient's explicit request to forgo further disclosure is best described as which of the following?
- Respecting the patient's waiver of further information
- Exercising therapeutic privilege
- Applying substituted judgment
- Invoking the emergency exception
Correct answer: Respecting the patient's waiver of further information
A competent patient may choose to waive additional disclosure, and honoring that explicit request is respecting her informational waiver, which itself reflects her autonomy. It is not therapeutic privilege, where the physician withholds information for the patient's protection, nor substituted judgment or the emergency exception.
- A patient signs a consent form for a complex procedure, but when asked to describe what the operation involves, she cannot state the basic nature of the procedure or any of its major risks and clearly never absorbed the explanation. Which conclusion about the consent is most accurate?
- The consent is valid because the form was signed
- The consent is valid because the physician spoke at length
- The consent is not valid because the patient did not understand the disclosed information
- The consent is valid because a witness was present
Correct answer: The consent is not valid because the patient did not understand the disclosed information
Valid informed consent requires genuine understanding, so a signature without any comprehension of the procedure or its risks does not constitute valid consent. A signed form, a lengthy explanation, or a witness cannot substitute for the patient actually understanding what she is agreeing to.
- A patient who signed a consent form for an elective procedure says, just before it begins, that she has changed her mind and no longer wants it done, even though she had previously agreed. The procedure is not emergent. How should the team respond to her withdrawal of consent?
- Stop and honor her withdrawal, since consent can be revoked at any time before and during a procedure
- Proceed because she already signed the form
- Tell her she cannot back out once she has consented
- Sedate her to prevent further objection
Correct answer: Stop and honor her withdrawal, since consent can be revoked at any time before and during a procedure
Consent is an ongoing, revocable process, so a competent patient may withdraw it at any time before or during a procedure, and the team must honor that withdrawal. A prior signature does not lock her in, telling her she cannot back out is false, and sedating her over the objection would be a serious violation.
- A medical assistant suggests speeding up a busy clinic by having patients sign blank consent forms when they arrive, to be filled in later once the physician decides what to do. From the standpoint of valid informed consent, what is the fundamental problem with this practice?
- It would slow the clinic down too much
- Blank forms are difficult to file properly
- Patients dislike signing forms in the waiting room
- A signature obtained before any specific discussion cannot reflect informed agreement to a defined procedure
Correct answer: A signature obtained before any specific discussion cannot reflect informed agreement to a defined procedure
Consent must follow disclosure about a specific intervention, so a signature collected before any discussion of a defined procedure cannot represent informed agreement. The core issue is the absence of disclosure and understanding, not workflow speed, filing logistics, or patient preference about waiting-room paperwork.
- A physician realizes that two close relatives of a patient cannot agree on who should serve as the decision-maker for an incapacitated patient who left no designation, and the disagreement is delaying care. When no healthcare proxy was named, which framework most commonly guides who is authorized to make decisions?
- Whichever relative arrives at the hospital first
- The physician's personal choice among the relatives
- A legally recognized hierarchy of surrogate decision-makers, often beginning with the spouse and then other close family
- The relative who is financially responsible for the bill
Correct answer: A legally recognized hierarchy of surrogate decision-makers, often beginning with the spouse and then other close family
When no proxy is designated, decision-making authority typically follows a legally recognized hierarchy of surrogates, commonly starting with a spouse and proceeding to adult children and other close relatives. Order of arrival, the physician's personal preference, or financial responsibility for the bill does not determine surrogate authority.
- A patient signs a hospital's general consent-to-treat form on admission, which authorizes routine nursing care and basic evaluation. The surgical team later assumes this form also covers a planned invasive operation. Why is this assumption incorrect?
- General consent forms cover any procedure performed during the stay
- A general admission consent does not substitute for specific informed consent to a distinct invasive procedure
- Only emergency procedures require separate consent
- Specific consent is needed only for outpatient procedures
Correct answer: A general admission consent does not substitute for specific informed consent to a distinct invasive procedure
A broad admission consent authorizes routine care but does not replace the specific informed-consent discussion required for a distinct invasive operation. Such general forms do not blanket-authorize all procedures, the need for specific consent is not limited to emergencies or outpatient settings, and a separate procedure requires its own disclosure.
- A patient asks her physician what circumstances could legally require her health information to be shared without her permission. Which of the following is a recognized exception that may permit or require disclosure of protected health information without patient authorization?
- A neighbor's general curiosity about her illness
- A pharmaceutical company's marketing department requesting her records
- Another patient asking for her diagnosis
- Reporting a legally mandated condition such as a notifiable communicable disease to public health authorities
Correct answer: Reporting a legally mandated condition such as a notifiable communicable disease to public health authorities
Reporting a legally notifiable communicable disease to public health authorities is a recognized exception that permits disclosure without the patient's authorization to protect community health. Curiosity, marketing requests, and another patient's inquiry are not legitimate exceptions and would breach confidentiality.
- A billing clerk needs a patient's diagnosis code to process an insurance claim but does not need the full clinical notes, social history, or unrelated test results. Limiting the clerk's access to only the information required to complete the billing task reflects which confidentiality principle?
- Therapeutic privilege
- The minimum necessary standard
- The emergency exception
- Substituted judgment
Correct answer: The minimum necessary standard
Restricting disclosure to only the information needed for the specific task, such as a billing code rather than the entire record, embodies the minimum necessary standard for protecting health information. It is unrelated to therapeutic privilege, the emergency exception, or substituted judgment, which concern disclosure to patients and surrogate decision-making.
- A clinic transmits patient records to a referral specialist directly involved in the patient's care, sharing only the relevant clinical information for that referral. Sharing protected health information for the purpose of providing care to the patient falls under which permitted category of use?
- Marketing
- Treatment
- Public sale of data
- Curiosity-based access
Correct answer: Treatment
Sharing relevant clinical information with another clinician involved in the patient's care is a treatment use, one of the core permitted purposes for disclosing health information. It is fundamentally different from marketing, selling data, or curiosity-driven access, none of which are legitimate care-related uses.
- An adult patient with decision-making capacity tells the physician she does not want her own diagnosis disclosed to anyone, including her spouse and adult children, even though they have been asking. How should the physician handle the family's questions?
- Honor the patient's wishes and decline to disclose her information to the family
- Tell the family everything because they are immediate relatives
- Disclose to the spouse only, as the closest relative
- Share the information so the family can help with care decisions
Correct answer: Honor the patient's wishes and decline to disclose her information to the family
A capable adult controls who may receive her health information, so the physician must honor her wish to keep it from family members despite their requests. Disclosing to relatives, even a spouse, against her clearly stated wishes would breach her confidentiality and autonomy.
- A physician finishes seeing an inpatient and notices that the previous user left the electronic health record open and logged in at the shared workstation. With respect to protecting confidentiality, what is the most appropriate response?
- Continue using the open session since it is convenient
- Leave it open for the next person to save time
- Use the open session to look up an unrelated patient quickly
- Log out the open session and ensure each user accesses records under their own credentials
Correct answer: Log out the open session and ensure each user accesses records under their own credentials
Leaving a record open under another user's login undermines accountability and confidentiality, so the physician should log it out and ensure access occurs under each individual's own credentials. Using or leaving the open session, especially to view an unrelated patient, would expose protected information and obscure who accessed it.
- A patient brings a friend into the examination room for support, and the physician is about to discuss sensitive results in front of that friend. To best protect confidentiality before continuing, what should the physician do?
- Confirm with the patient that she is comfortable discussing her information with the friend present
- Assume the friend may hear everything because the patient brought her
- Ask the friend to relay the results to the patient later
- Discuss the results and let the patient interrupt if she objects
Correct answer: Confirm with the patient that she is comfortable discussing her information with the friend present
Before disclosing sensitive information in front of a companion, the physician should confirm the patient consents to having that person present, since the patient controls who hears her health information. Assuming consent from the friend's presence, delegating disclosure to the friend, or proceeding until the patient objects all risk an unwanted breach.
- A patient who is a public figure is hospitalized, and a journalist calls the front desk asking staff to confirm whether the person is a patient and to describe the condition. There is no authorization from the patient. How should staff respond?
- Decline to confirm the admission or share any information without the patient's authorization
- Confirm the admission since the person is already publicly known
- Provide a general description of the condition to satisfy public interest
- Refer the journalist to the patient's physician for the details
Correct answer: Decline to confirm the admission or share any information without the patient's authorization
Without the patient's authorization, staff must not even confirm an admission or share any clinical details, regardless of the person's fame or public interest. Confirming the stay, describing the condition, or routing the reporter to the physician would each disclose protected information the patient has not agreed to release.
- A primary care physician wants to discuss a shared patient's medications with the patient's specialist to coordinate care. The patient previously gave general consent for her treating clinicians to communicate about her care. Sharing relevant information between these clinicians for coordination is best characterized as which of the following?
- An impermissible breach of confidentiality
- A legitimate care-coordination disclosure among treating clinicians
- A marketing activity requiring separate authorization
- A public health report
Correct answer: A legitimate care-coordination disclosure among treating clinicians
Treating clinicians may share relevant information to coordinate a patient's care, making this exchange a legitimate care-coordination disclosure rather than a breach. It is not marketing requiring special authorization, nor a public health report, both of which serve entirely different purposes.
- A clinic posts a sign-in sheet at the front desk that requires each arriving patient to write their full name and the specific reason for the visit, which all later patients can read. From a confidentiality standpoint, what is the main concern with this sign-in practice?
- Sign-in sheets are never permitted in any form
- It slows down patient check-in
- Displaying patients' names alongside reasons for visit exposes protected information to other patients
- It uses too much paper over time
Correct answer: Displaying patients' names alongside reasons for visit exposes protected information to other patients
Listing names together with reasons for the visit lets other patients view information that should remain private, creating a confidentiality concern even though basic sign-in logs can be acceptable when limited. The issue is the exposure of clinical reasons to others, not an absolute ban on sign-in sheets, check-in speed, or paper use.
- A patient seen at a substance use treatment program is later the subject of a routine records request from an outside party. Records related to certain sensitive categories of care, such as substance use treatment, generally receive which level of confidentiality protection?
- No special protection beyond ordinary records
- Automatic release to any requesting party
- Protection only if the patient is a minor
- Heightened protections that often require specific patient authorization before release
Correct answer: Heightened protections that often require specific patient authorization before release
Sensitive records such as those from substance use treatment commonly carry heightened confidentiality protections, frequently requiring specific patient authorization before disclosure. They are not treated like ordinary records, are not automatically releasable, and the added protection does not depend on the patient being a minor.
- A physician dictating a patient's history in an open work area lowers her voice and steps into a private space when she realizes others nearby could overhear identifying clinical details. Taking reasonable precautions to prevent incidental exposure of conversations to bystanders reflects which confidentiality concept?
- Therapeutic privilege
- Substituted judgment
- Mandatory reporting
- Implementing reasonable safeguards against unnecessary disclosure
Correct answer: Implementing reasonable safeguards against unnecessary disclosure
Lowering her voice and moving to a private space are reasonable safeguards meant to minimize incidental disclosure of protected information to bystanders. These privacy precautions are unrelated to therapeutic privilege, substituted judgment, or mandatory reporting, which address disclosure to patients, surrogate decisions, and legal duties.
- A physician is about to deliver an unexpected serious diagnosis and pauses to silence her phone, ask a colleague to hold pages, and ensure no one will walk in during the conversation. Minimizing interruptions during the delivery of serious news primarily serves to do which of the following?
- Allow the physician to give the patient full, undistracted attention during a difficult moment
- Shorten the overall length of the conversation
- Reduce the amount of information that must be shared
- Satisfy a billing documentation requirement
Correct answer: Allow the physician to give the patient full, undistracted attention during a difficult moment
Silencing devices and preventing interruptions lets the physician devote complete, undistracted attention to the patient during an emotionally difficult conversation. The aim is presence and support, not shortening the talk, reducing necessary information, or meeting a billing requirement.
- After hearing devastating news, a patient becomes silent and looks down for a long moment without speaking. The physician resists the urge to fill the gap and simply waits quietly, giving the patient time. Using silence in this way during a serious-news conversation is best understood as which of the following?
- A sign the physician has nothing more to say
- A deliberate communication technique that gives the patient space to process the news
- An indication the conversation should end immediately
- A failure to communicate effectively
Correct answer: A deliberate communication technique that gives the patient space to process the news
Allowing a thoughtful silence is a deliberate, supportive technique that gives the patient room to absorb difficult news and gather a response. It is not a sign of nothing to say, a cue to end the encounter, or a communication failure, but rather an intentional act of respect.
- A patient who just learned of a serious diagnosis reacts with intense anger, raising her voice and accusing the physician of missing it sooner. The physician stays calm, does not argue, and acknowledges that the patient is understandably upset. This response to a strong emotional reaction is best described as which of the following?
- Disciplining the patient for inappropriate behavior
- Ending the encounter to avoid conflict
- Acknowledging and validating the patient's emotion rather than becoming defensive
- Insisting the patient calm down before continuing
Correct answer: Acknowledging and validating the patient's emotion rather than becoming defensive
Remaining calm and acknowledging the patient's anger as an understandable reaction validates the emotion and preserves the relationship during a difficult moment. Reprimanding the patient, walking out, or demanding she calm down would escalate distress and undermine the therapeutic connection.
- A physician must give serious news to a patient who has come to the visit alone and appears to have no one waiting for her. As part of supporting the patient after the disclosure, which action is most appropriate?
- Tell her to handle the news on her own
- Hand her written materials and end the visit promptly
- Help arrange support, such as offering to contact someone she trusts or connecting her with available resources
- Withhold the news until she returns with someone
Correct answer: Help arrange support, such as offering to contact someone she trusts or connecting her with available resources
Supporting a patient who received serious news alone includes helping arrange support, such as offering to reach a trusted person or connecting her with resources. Leaving her to cope alone, rushing her out with a pamphlet, or improperly delaying needed information would all fall short of compassionate communication.
- A physician is about to discuss a complex new diagnosis and decides to draw a simple diagram and use an everyday analogy comparing the blocked artery to a clogged pipe. Using visual aids and analogies during the explanation primarily serves to do which of the following?
- Impress the patient with the physician's artistic skill
- Improve the patient's understanding of an unfamiliar medical concept
- Replace the need to answer the patient's questions
- Shorten the documentation in the chart
Correct answer: Improve the patient's understanding of an unfamiliar medical concept
Diagrams and relatable analogies make unfamiliar medical concepts more concrete, improving the patient's understanding of the diagnosis. They are not about displaying skill, replacing questions, or shortening documentation, but about supporting comprehension.
- During a serious conversation, a patient mentions in passing that she is most worried about who will care for her young children, but the physician was focused on the treatment plan. Noticing and gently following up on the patient's expressed concern about her children rather than ignoring it best reflects which communication skill?
- Delivering a warning shot
- Exercising therapeutic privilege
- Performing de-identification
- Recognizing and responding to the patient's cues
Correct answer: Recognizing and responding to the patient's cues
Catching the patient's offhand worry about her children and following up on it is recognizing and responding to patient cues, which surfaces what matters most to her. It is distinct from a warning shot, therapeutic privilege, and data de-identification, which serve unrelated communication and privacy functions.
- A patient overwhelmed by a new diagnosis keeps asking the same question about prognosis several times within one visit, having forgotten the earlier answers. Which response best reflects effective communication in this situation?
- Tell the patient she already asked and refuse to repeat
- Patiently answer again and recognize that distress can impair memory and require repetition
- Express frustration at having to repeat information
- Assume the patient is not capable of understanding anything
Correct answer: Patiently answer again and recognize that distress can impair memory and require repetition
Strong emotion impairs information retention, so patiently repeating the answer acknowledges that distress can require repetition and supports the patient's understanding. Refusing to repeat, showing frustration, or assuming the patient cannot understand would damage trust and ignore the effect of distress on memory.
- A physician explaining a treatment writes down the key steps and a phone number for questions, then provides a brief printed summary the patient can take home and review later. Providing written take-home information after a verbal explanation primarily helps to do which of the following?
- Reinforce verbal communication and support recall after the visit
- Replace the need for any verbal discussion
- Transfer responsibility for understanding entirely to the patient
- Reduce the physician's liability for the outcome
Correct answer: Reinforce verbal communication and support recall after the visit
Take-home written information reinforces what was discussed and helps the patient recall details after leaving, complementing the spoken explanation. It is meant to supplement, not replace, verbal discussion, and its purpose is supporting comprehension rather than shifting responsibility or limiting liability.
- A patient receiving difficult news asks the physician directly, How long do I have? and the physician genuinely cannot give a precise answer. Which response best balances honesty with support?
- Give a falsely precise number to satisfy the patient
- Refuse to discuss prognosis at all
- Acknowledge the uncertainty honestly, offer the best available general information, and remain supportive
- Tell the patient not to worry about such questions
Correct answer: Acknowledge the uncertainty honestly, offer the best available general information, and remain supportive
When a precise prognosis is impossible, honestly acknowledging the uncertainty while offering the best general information and ongoing support respects the patient and maintains trust. Inventing a false number, refusing to engage, or dismissing the question would each fail the patient's need for honest, compassionate communication.
- A patient says, I just feel like everything is falling apart, and I do not know how I will get through this. Rather than immediately offering solutions, the physician says, This is a lot to carry, and it makes sense that it feels overwhelming. Naming and normalizing the patient's distress in this way is best described as which of the following?
- Giving a directive instruction
- Validating the patient's experience to provide emotional support
- Issuing a warning shot
- Conducting a mandatory report
Correct answer: Validating the patient's experience to provide emotional support
Telling the patient that her overwhelmed feelings make sense validates her experience and offers emotional support before problem-solving. It is not a directive, a warning shot preceding bad news, or a reporting action, but a supportive empathic response.
- An intern is taught that when delivering serious news, it is better to say the words cancer or died directly rather than relying only on vague phrases like growth or passed on, while remaining gentle. The main rationale for using clear, direct words in serious-news communication is to do which of the following?
- Make the conversation as blunt and brief as possible
- Demonstrate the physician's medical knowledge
- Discourage the patient from asking questions
- Prevent misunderstanding so the patient grasps the reality of the situation
Correct answer: Prevent misunderstanding so the patient grasps the reality of the situation
Clear, direct language prevents the confusion that vague euphemisms can cause, ensuring the patient truly understands the situation while the physician remains gentle. The goal is accurate comprehension, not bluntness for its own sake, showing off knowledge, or shutting down questions.
- A physician is preparing to break bad news and reminds herself to watch the patient's facial expressions and body language throughout, not just listen to the words. Attending to a patient's nonverbal signals during a difficult conversation primarily helps the physician to do which of the following?
- Gauge how the patient is reacting and adjust the approach accordingly
- Decide how quickly to end the conversation
- Avoid having to ask the patient any questions
- Determine the correct diagnosis
Correct answer: Gauge how the patient is reacting and adjust the approach accordingly
Reading facial expressions and body language helps the physician gauge the patient's emotional reaction and adapt the pace and content of the conversation accordingly. It is not a tool for rushing to an end, avoiding questions, or making a diagnosis, but for responsive, attuned communication.
- Before a difficult family meeting about a critically ill patient, the care team briefly meets among themselves to agree on the facts and a consistent message so the family does not receive conflicting information from different members. Coordinating the team's message before such a meeting primarily serves to do which of the following?
- Limit how much the family is allowed to ask
- Speed the meeting so it can be billed sooner
- Decide which team member will avoid the family
- Ensure the family receives consistent, non-contradictory information
Correct answer: Ensure the family receives consistent, non-contradictory information
Pre-meeting coordination aligns the team on the facts and message so the family hears a consistent account rather than conflicting statements that breed confusion and distrust. It is not meant to restrict the family's questions, hurry billing, or help a member avoid the family.
- A patient autonomously chooses to stop a treatment, and the physician disagrees with the decision but continues to provide care, support, and accurate information without abandoning or punishing the patient for the choice. The physician's ongoing commitment to the patient despite disagreeing with her decision best reflects which professional value?
- Fidelity to the patient and nonabandonment
- Therapeutic privilege
- Substituted judgment
- Mandatory reporting
Correct answer: Fidelity to the patient and nonabandonment
Continuing to support and care for a patient despite disagreeing with her autonomous choice reflects fidelity and the duty of nonabandonment, keeping faith with the patient regardless of the decision. It is unrelated to therapeutic privilege, substituted judgment, or mandatory reporting.
- A terminally ill patient asks for enough pain medication to relieve severe suffering, and the physician provides a dose intended to control pain, accepting that adequate analgesia might also hasten death as an unintended side effect. The reasoning that permits a beneficial action with a foreseen but unintended harmful consequence is best described as which of the following?
- Physician-assisted dying
- The doctrine of double effect
- Therapeutic privilege
- Substituted judgment
Correct answer: The doctrine of double effect
Providing medication intended to relieve suffering while accepting a foreseen but unintended risk of hastening death reflects the doctrine of double effect. It differs from intentionally causing death, from withholding information under therapeutic privilege, and from surrogate substituted judgment.
- A capable, fully informed patient with a terminal illness asks her physician to withdraw a life-sustaining ventilator because she no longer wishes to continue it, understanding the consequence. Regarding a competent patient's request to stop an unwanted life-sustaining treatment, which statement is most accurate?
- Once started, a life-sustaining treatment can never be withdrawn
- A competent patient has the right to refuse or have unwanted life-sustaining treatment withdrawn
- Only a court can authorize withdrawing such treatment
- The physician must continue the treatment against her wishes
Correct answer: A competent patient has the right to refuse or have unwanted life-sustaining treatment withdrawn
A competent, informed patient may refuse or request withdrawal of unwanted life-sustaining treatment, and honoring that choice respects her autonomy. Treatment is not irrevocable once begun, a court order is not required for a capable patient's own decision, and continuing against her wishes would violate her rights.
- An ethics discussion distinguishes between not starting a ventilator in the first place and stopping a ventilator already in use at a capable patient's request. Regarding withholding versus withdrawing a life-sustaining treatment, what is the prevailing ethical view?
- Withdrawing is always ethically prohibited while withholding is allowed
- Withholding and withdrawing life-sustaining treatment are generally regarded as ethically equivalent
- Withholding is always worse than withdrawing
- Neither may ever be done for any patient
Correct answer: Withholding and withdrawing life-sustaining treatment are generally regarded as ethically equivalent
Mainstream medical ethics holds that withholding and withdrawing a life-sustaining treatment are ethically equivalent when consistent with the patient's wishes, so stopping a treatment is not inherently worse than never starting it. The other options misstate this widely accepted view.
- A physician disagrees with a colleague's decision but, recognizing the colleague is honestly trying to serve the patient and acting within accepted practice, communicates the concern respectfully and through appropriate channels rather than undermining the colleague in front of the patient. This conduct best reflects which professional value?
- Therapeutic privilege
- Substituted judgment
- Professionalism and respectful collegial communication
- Conscientious objection
Correct answer: Professionalism and respectful collegial communication
Raising a concern respectfully through appropriate channels rather than disparaging a colleague before the patient reflects professionalism and constructive collegial communication. It is not therapeutic privilege, substituted judgment, or conscientious objection, which address disclosure, surrogate decisions, and moral refusals.
- A patient consents to be examined by medical students as part of his care, but during a procedure under anesthesia, students wish to perform an additional educational examination that the patient was never told about or asked to allow. With respect to the patient's autonomy, what does this situation most directly require?
- No consent, because the patient is already in a teaching hospital
- Consent only from the supervising attending
- Specific informed consent from the patient before students perform educational examinations not previously authorized
- Consent only if a complication occurs
Correct answer: Specific informed consent from the patient before students perform educational examinations not previously authorized
Respect for autonomy requires the patient's specific informed consent before students perform educational examinations he was never told about, especially under anesthesia. Being in a teaching hospital, the attending's permission, or the absence of complications does not waive the patient's right to consent to such examinations.
- A patient confides feelings of hopelessness and the physician is unsure how to balance respecting the patient's privacy with the duty to ensure safety. When core ethical principles such as respecting autonomy and protecting the patient from harm appear to pull in different directions, this situation is best described as which of the following?
- A simple administrative matter
- A reason to ignore one principle entirely without reflection
- A purely legal question with no ethical content
- An ethical dilemma involving conflicting principles that must be weighed in context
Correct answer: An ethical dilemma involving conflicting principles that must be weighed in context
When respecting autonomy and protecting the patient from harm pull in opposite directions, the physician faces an ethical dilemma requiring the competing principles to be weighed in the specific context. It is neither a mere administrative task, a license to disregard a principle without thought, nor a question devoid of ethical substance.
- A busy attending asks a clerk who was not present for any discussion with the patient to obtain the patient's signature on a surgical consent form and answer any questions that arise about the operation. Why is this delegation inappropriate for valid informed consent?
- Only a notary may witness a consent form
- Consent forms must always be signed in the operating room
- The person obtaining consent must be knowledgeable enough to disclose the relevant information and answer the patient's questions
- A clerk is never allowed to be present during any patient discussion
Correct answer: The person obtaining consent must be knowledgeable enough to disclose the relevant information and answer the patient's questions
Valid informed consent requires that the person obtaining it be sufficiently knowledgeable to disclose the relevant information and answer the patient's questions, which a clerk uninvolved in the care cannot do. The flaw is the lack of qualified disclosure, not notary rules, the location of signing, or a blanket ban on clerks being present.
- A 20-year-old African American man develops dark urine and fatigue several days after starting an antimalarial drug, and his smear shows red cells with rounded membrane defects and inclusions of denatured hemoglobin on supravital staining. Which inherited red cell enzyme deficiency best explains this drug-induced hemolysis?
- Glucose-6-phosphate dehydrogenase deficiency
- Iron deficiency
- Hereditary spherocytosis
- Sickle cell trait
Correct answer: Glucose-6-phosphate dehydrogenase deficiency
Glucose-6-phosphate dehydrogenase deficiency is correct because this X-linked enzyme defect reduces NADPH and reduced glutathione, leaving red cells unable to defend against oxidative stress, so oxidant drugs trigger acute hemolysis with Heinz bodies and bite cells. Hereditary spherocytosis is a membrane protein disorder producing chronic hemolysis without an oxidant trigger, sickle cell trait does not cause oxidant-induced hemolysis, and iron deficiency causes microcytic anemia rather than acute oxidative hemolysis.
- A patient with glucose-6-phosphate dehydrogenase deficiency has a smear showing red cells that appear to have a piece bitten out of them. These bite cells form because splenic macrophages remove which intracellular structure?
- Howell-Jolly bodies
- Heinz bodies of denatured hemoglobin
- Pappenheimer bodies
- Basophilic stippling
Correct answer: Heinz bodies of denatured hemoglobin
Heinz bodies of denatured hemoglobin is correct because oxidative stress in glucose-6-phosphate dehydrogenase deficiency precipitates hemoglobin into Heinz bodies, and splenic macrophages pluck these inclusions from the cell, leaving a bite-cell appearance. Howell-Jolly bodies are nuclear remnants seen in asplenia, basophilic stippling consists of ribosomal aggregates, and Pappenheimer bodies are iron granules, none of which is the denatured hemoglobin removed to create bite cells.
- A 30-year-old man develops dark urine in the morning, episodic abdominal pain, and a venous thrombosis, and flow cytometry shows red cells lacking CD55 and CD59. The complement-mediated intravascular hemolysis in this disorder results from a deficiency that traces to a defect in which membrane anchor?
- Band 3 protein
- Spectrin
- The glycosylphosphatidylinositol anchor
- Glycophorin A
Correct answer: The glycosylphosphatidylinositol anchor
The glycosylphosphatidylinositol anchor is correct because paroxysmal nocturnal hemoglobinuria arises from a PIGA mutation that prevents synthesis of this anchor, so the complement regulatory proteins CD55 and CD59 cannot attach, leaving red cells vulnerable to complement-mediated intravascular hemolysis. Spectrin and band 3 defects cause hereditary spherocytosis, and glycophorin A is a separate surface glycoprotein, none of which explains the loss of GPI-anchored complement regulators.
- A 65-year-old woman has fatigue and a macrocytic anemia, and laboratory testing reveals a low vitamin B12 level, anti-intrinsic factor antibodies, and atrophic gastritis. Which mechanism best explains the vitamin B12 deficiency in this condition?
- Bacterial overgrowth consuming dietary B12
- Dietary lack of B12 in a balanced diet
- Pancreatic enzyme deficiency
- Autoimmune destruction of gastric parietal cells reducing intrinsic factor
Correct answer: Autoimmune destruction of gastric parietal cells reducing intrinsic factor
Autoimmune destruction of gastric parietal cells reducing intrinsic factor is correct because pernicious anemia is an autoimmune gastritis in which loss of parietal cells and antibodies against intrinsic factor prevent the binding needed for ileal B12 absorption, producing megaloblastic anemia with neurologic involvement. Bacterial overgrowth and pancreatic insufficiency are separate malabsorption causes, and dietary deficiency is uncommon given hepatic B12 stores, so neither is the autoimmune mechanism described.
- A 60-year-old strict vegan develops numbness, gait imbalance, and impaired vibration sense along with a macrocytic anemia. The neurologic deficits of vitamin B12 deficiency are caused by degeneration of which part of the nervous system?
- The dorsal columns and lateral corticospinal tracts of the spinal cord
- The cerebellar vermis
- The anterior horn cells only
- The peripheral autonomic ganglia
Correct answer: The dorsal columns and lateral corticospinal tracts of the spinal cord
The dorsal columns and lateral corticospinal tracts of the spinal cord is correct because vitamin B12 is required for myelin maintenance, and its deficiency causes subacute combined degeneration affecting the dorsal columns and corticospinal tracts, producing loss of vibration and position sense with spastic weakness. Isolated anterior horn cell, cerebellar vermis, or autonomic ganglion degeneration does not account for this characteristic combined dorsal column and corticospinal pattern.
- A medical student compares two megaloblastic anemias. A patient with folate deficiency and a patient with vitamin B12 deficiency both have macrocytosis and hypersegmented neutrophils, but one accumulates an elevated metabolite that helps distinguish them. Which finding is characteristically elevated in vitamin B12 deficiency but not isolated folate deficiency?
- Lactate dehydrogenase
- Methylmalonic acid
- Indirect bilirubin
- Homocysteine
Correct answer: Methylmalonic acid
Methylmalonic acid is correct because vitamin B12 is a cofactor for the enzyme that converts methylmalonyl-CoA to succinyl-CoA, so B12 deficiency raises methylmalonic acid, whereas folate deficiency does not. Homocysteine rises in both deficiencies, and lactate dehydrogenase and indirect bilirubin reflect ineffective erythropoiesis common to both, so methylmalonic acid is the metabolite that specifically separates B12 from folate deficiency.
- A 4-year-old boy with hemophilia A is found to have a markedly prolonged activated partial thromboplastin time. When his plasma is mixed with normal plasma, the activated partial thromboplastin time corrects. What does this correction on a mixing study indicate?
- Presence of a factor inhibitor
- A platelet function defect
- A factor deficiency
- A vitamin K-independent process
Correct answer: A factor deficiency
A factor deficiency is correct because adding normal plasma supplies the missing clotting factor (factor VIII in hemophilia A), so the prolonged activated partial thromboplastin time normalizes, confirming deficiency rather than inhibition. If a factor inhibitor were present, the time would fail to correct because the antibody would also neutralize factor in the added normal plasma, and platelet defects do not prolong the activated partial thromboplastin time.
- A 25-year-old woman has lifelong easy bruising, heavy menstrual bleeding, and prolonged bleeding after dental work, with a normal platelet count but a prolonged bleeding time and reduced ristocetin-induced platelet aggregation. Which is the most common inherited bleeding disorder consistent with these findings?
- Factor XIII deficiency
- Hemophilia A
- Glanzmann thrombasthenia
- Von Willebrand disease
Correct answer: Von Willebrand disease
Von Willebrand disease is correct because deficiency or dysfunction of von Willebrand factor impairs platelet adhesion and reduces ristocetin-induced aggregation, causing mucocutaneous bleeding with a normal platelet count, and it is the most common inherited bleeding disorder. Hemophilia A is X-linked and causes deep bleeding with a normal bleeding time, Glanzmann thrombasthenia is rare with absent aggregation to all agonists, and factor XIII deficiency causes delayed bleeding with normal routine studies.
- A patient with von Willebrand disease is found to have a mildly prolonged activated partial thromboplastin time in addition to abnormal platelet function. Why can von Willebrand factor deficiency prolong the activated partial thromboplastin time?
- Von Willebrand factor normally stabilizes and carries factor VIII in plasma
- Von Willebrand factor cross-links fibrin
- Von Willebrand factor activates plasminogen
- Von Willebrand factor is the trigger of the extrinsic pathway
Correct answer: Von Willebrand factor normally stabilizes and carries factor VIII in plasma
Von Willebrand factor normally stabilizes and carries factor VIII in plasma is correct because by binding and protecting factor VIII from degradation, von Willebrand factor maintains circulating factor VIII levels, so its deficiency lowers factor VIII and can prolong the activated partial thromboplastin time alongside the platelet adhesion defect. Von Willebrand factor does not trigger the extrinsic pathway, cross-link fibrin, or activate plasminogen, which are functions of tissue factor, factor XIII, and plasminogen activators.
- A 40-year-old man with recurrent unprovoked deep vein thromboses is found to have a point mutation that makes factor V resistant to cleavage by activated protein C. Which inherited thrombophilia is the most common heritable cause of this hypercoagulable state?
- Protein S deficiency
- Factor V Leiden
- Antithrombin deficiency
- Prothrombin gene mutation
Correct answer: Factor V Leiden
Factor V Leiden is correct because this single point mutation alters the activated protein C cleavage site on factor V, so factor Va remains active longer and promotes excess thrombin generation, making it the most common inherited cause of venous thromboembolism. A prothrombin gene mutation raises prothrombin levels, and antithrombin and protein S deficiencies are far less common heritable thrombophilias, none of which involves activated protein C resistance from an altered factor V.
- A medical student reviews anticoagulant pharmacology. A hospitalized patient is given unfractionated heparin, which produces its anticoagulant effect by enhancing the activity of which natural inhibitor of thrombin and factor Xa?
- Plasmin
- Protein C
- Antithrombin
- Tissue factor pathway inhibitor
Correct answer: Antithrombin
Antithrombin is correct because heparin binds antithrombin and dramatically accelerates its inactivation of thrombin and factor Xa, producing rapid anticoagulation. Protein C inactivates factors Va and VIIIa rather than being heparin's target, tissue factor pathway inhibitor blocks the tissue factor-factor VIIa complex, and plasmin degrades fibrin during fibrinolysis, none of which is the cofactor whose activity heparin potentiates.
- A medical student studies the intrinsic coagulation pathway. The activated partial thromboplastin time evaluates the intrinsic and common pathways. Which factor, when deficient, prolongs the activated partial thromboplastin time but is not associated with clinical bleeding?
- Factor IX
- Factor VIII
- Factor X
- Factor XII
Correct answer: Factor XII
Factor XII is correct because although factor XII deficiency prolongs the activated partial thromboplastin time as part of the intrinsic contact pathway, it does not cause clinical bleeding because it is not required for hemostasis in vivo. Deficiencies of factor VIII and factor IX cause hemophilia with significant bleeding, and factor X is in the common pathway and its deficiency also causes bleeding, so factor XII is the asymptomatic exception.
- A 6-year-old boy has a severe bleeding disorder, and the laboratory finds a prolonged activated partial thromboplastin time that corrects with normal plasma. Genetic testing shows a deficiency of factor IX. This X-linked deficiency of factor IX is also known as what?
- Hemophilia B
- Hemophilia A
- Bernard-Soulier syndrome
- Von Willebrand disease
Correct answer: Hemophilia B
Hemophilia B is correct because it is the X-linked recessive bleeding disorder caused by deficiency of factor IX, clinically resembling hemophilia A with deep tissue and joint bleeding and a prolonged activated partial thromboplastin time. Hemophilia A is factor VIII deficiency, von Willebrand disease impairs platelet adhesion, and Bernard-Soulier syndrome is a glycoprotein Ib platelet defect, none of which is the factor IX deficiency described.
- A medical student studies blood group inheritance. A person whose red cells carry the A antigen and whose serum contains anti-B antibodies has which ABO blood type?
- Type B
- Type A
- Type AB
- Type O
Correct answer: Type A
Type A is correct because individuals with blood type A express the A antigen on their red cells and naturally produce anti-B antibodies against the antigen they lack, consistent with the reciprocal relationship of the ABO system. Type B carries B antigen and anti-A, type AB carries both antigens and neither antibody, and type O carries neither antigen but both anti-A and anti-B, so none matches the described pattern.
- A patient with type AB blood needs a plasma transfusion. Because type AB plasma contains neither anti-A nor anti-B antibodies, an individual with type AB blood is considered the universal donor of which blood product?
- Packed red cells
- Platelets concentrated by type
- Plasma
- Whole blood
Correct answer: Plasma
Plasma is correct because type AB plasma lacks both anti-A and anti-B antibodies, so it can be given to recipients of any ABO type without causing antibody-mediated hemolysis, making AB the universal plasma donor. This is the reverse of red cells, where type O is the universal donor, so packed red cells and whole blood do not fit, and platelets are matched differently rather than by AB universal-donor plasma status.
- A 22-year-old woman with sickle cell anemia is started on a medication that increases fetal hemoglobin levels and reduces the frequency of painful vaso-occlusive crises. Which drug accomplishes this by inducing hemoglobin F production?
- Folic acid
- Iron sucrose
- Deferoxamine
- Hydroxyurea
Correct answer: Hydroxyurea
Hydroxyurea is correct because it raises fetal hemoglobin, which interferes with hemoglobin S polymerization and thereby reduces sickling, vaso-occlusive crises, and acute chest syndrome in sickle cell disease. Iron sucrose treats iron deficiency and would be harmful with iron overload, folic acid supports red cell production but does not raise hemoglobin F, and deferoxamine is an iron chelator rather than an inducer of fetal hemoglobin.
- A patient with beta thalassemia major who has received many transfusions over years develops bronze skin, diabetes, and cardiac dysfunction. To prevent these complications, the patient is treated with a medication that binds and removes excess iron. Which class of drug is used for this purpose?
- Iron chelators
- Corticosteroids
- Erythropoiesis-stimulating agents
- Folate supplements
Correct answer: Iron chelators
Iron chelators are correct because chronic transfusions in beta thalassemia major cause iron overload that damages the heart, liver, and endocrine organs, and chelating agents such as deferoxamine or deferasirox bind iron for excretion to prevent these complications. Erythropoiesis-stimulating agents and folate would not remove iron, and corticosteroids do not address iron overload, so iron chelation is the appropriate therapy.
- A 50-year-old man has chronic lymphocytic leukemia, and a peripheral smear shows numerous mature lymphocytes along with fragile cells that rupture during slide preparation. These fragile ruptured lymphocytes characteristic of chronic lymphocytic leukemia are called what?
- Auer rods
- Smudge cells
- Teardrop cells
- Schistocytes
Correct answer: Smudge cells
Smudge cells are correct because the fragile, easily disrupted lymphocytes of chronic lymphocytic leukemia smear out during slide preparation, producing the characteristic smudge or basket cells. Auer rods are azurophilic crystalline inclusions of acute myeloid leukemia, teardrop cells indicate marrow fibrosis or infiltration, and schistocytes are fragmented cells of microangiopathy, none of which is the disrupted lymphocyte of chronic lymphocytic leukemia.
- A pathologist examines a bone marrow aspirate from a 40-year-old man with acute myeloid leukemia and identifies azurophilic, rod-shaped crystalline inclusions within the cytoplasm of malignant blasts. The presence of these structures confirms a myeloid lineage. What are these inclusions called?
- Dohle bodies
- Howell-Jolly bodies
- Auer rods
- Russell bodies
Correct answer: Auer rods
Auer rods are correct because these needle-shaped azurophilic inclusions are aggregates of primary granule material found within myeloblasts, confirming a myeloid origin in acute myeloid leukemia and being especially prominent in the promyelocytic subtype. Howell-Jolly bodies are nuclear remnants in red cells, Dohle bodies are pale cytoplasmic inclusions in reactive neutrophils, and Russell bodies are immunoglobulin inclusions in plasma cells, none of which is the myeloblast inclusion described.
- A 25-year-old man presents with a rapidly enlarging jaw mass, and biopsy of an endemic African case shows sheets of intermediate-sized B cells with interspersed pale macrophages creating a starry-sky pattern, driven by a translocation involving the MYC oncogene. Which chromosomal translocation underlies this Burkitt lymphoma?
- T(14;18)
- T(9;22)
- T(15;17)
- T(8;14)
Correct answer: T(8;14)
t(8;14) is correct because Burkitt lymphoma is driven by translocation of the MYC oncogene on chromosome 8 to the immunoglobulin heavy chain locus on chromosome 14, causing constitutive MYC overexpression and the extremely rapid proliferation that produces the starry-sky appearance. The t(9;22) defines chronic myelogenous leukemia, t(15;17) defines acute promyelocytic leukemia, and t(14;18) defines follicular lymphoma, none of which involves MYC as in Burkitt lymphoma.
- A medical student compares lymphoma spread. A patient with Hodgkin lymphoma is noted to have disease that progresses in an orderly fashion from one nodal group to adjacent groups. Compared with non-Hodgkin lymphoma, how does Hodgkin lymphoma characteristically spread?
- In a contiguous, orderly fashion to adjacent lymph node groups
- Almost exclusively through the bloodstream to bone
- By widespread noncontiguous nodal involvement at diagnosis
- Only to extranodal mucosal sites
Correct answer: In a contiguous, orderly fashion to adjacent lymph node groups
In a contiguous, orderly fashion to adjacent lymph node groups is correct because Hodgkin lymphoma classically spreads predictably from one nodal region to the next contiguous region, which historically guided staging and radiation planning. Non-Hodgkin lymphoma is more likely to present with noncontiguous, widespread nodal and extranodal disease, so the other options describe non-Hodgkin patterns rather than the orderly contiguous spread typical of Hodgkin lymphoma.
- A pathologist reviews a lymph node biopsy and identifies large binucleate cells with two mirror-image nuclei each containing a prominent eosinophilic nucleolus, resembling owl eyes. The identification of these cells is required for the diagnosis of which lymphoma?
- Follicular lymphoma
- Hodgkin lymphoma
- Burkitt lymphoma
- Chronic lymphocytic leukemia
Correct answer: Hodgkin lymphoma
Hodgkin lymphoma is correct because the diagnostic Reed-Sternberg cell is a large cell with bilobed or binucleate mirror-image nuclei and prominent owl-eye nucleoli, and its presence within an appropriate inflammatory background defines classical Hodgkin lymphoma. Follicular and Burkitt lymphomas and chronic lymphocytic leukemia are characterized by other malignant lymphoid populations and do not require Reed-Sternberg cells for diagnosis.
- A 70-year-old man with multiple myeloma is found to have a normocytic anemia and acute kidney injury, and review of his radiographs shows sharply marginated lytic lesions in the skull. These so-called punched-out bone lesions in multiple myeloma result from activation of which cells?
- Chondrocytes
- Fibroblasts
- Osteoclasts
- Osteoblasts
Correct answer: Osteoclasts
Osteoclasts is correct because malignant plasma cells in multiple myeloma secrete cytokines that stimulate osteoclast-mediated bone resorption while suppressing osteoblasts, producing the characteristic punched-out lytic lesions and hypercalcemia. Osteoblasts build bone and are suppressed in myeloma, and chondrocytes and fibroblasts are not responsible for the lytic destruction seen in this disease.
- A 68-year-old woman with multiple myeloma develops confusion, constipation, polyuria, and bone pain, and laboratory studies show an elevated serum calcium. The hypercalcemia in multiple myeloma is most directly caused by which process?
- Increased renal calcium reabsorption from parathyroid hyperplasia
- Excess vitamin D production by plasma cells
- Calcium release from hemolyzed red cells
- Osteolytic bone destruction releasing calcium
Correct answer: Osteolytic bone destruction releasing calcium
Osteolytic bone destruction releasing calcium is correct because widespread osteoclast-driven bone resorption in multiple myeloma liberates calcium into the blood, producing hypercalcemia with its neurologic, gastrointestinal, and renal manifestations. The plasma cells do not overproduce vitamin D, the process is independent of parathyroid hyperplasia, and hemolysis does not release the quantity of calcium responsible, so bone destruction is the principal mechanism.
- A medical student studies macrophage biology in chronic infection. In tuberculosis, macrophages transform into large cells with abundant pink cytoplasm resembling epithelial cells and may fuse into multinucleated giant cells within granulomas. The cytokine that drives this macrophage activation and granuloma maintenance is which one?
- Interferon gamma
- Interleukin-10
- Interleukin-4
- Interleukin-5
Correct answer: Interferon gamma
Interferon gamma is correct because it is secreted by Th1 cells and natural killer cells and is the principal activator of macrophages, driving their transformation into epithelioid and giant cells and maintaining the granulomas that wall off intracellular pathogens such as mycobacteria. Interleukin-4 and interleukin-5 promote Th2 and eosinophil responses, and interleukin-10 is anti-inflammatory, none of which is the macrophage-activating cytokine of granuloma formation.
- A 4-year-old boy with chronic granulomatous disease has recurrent infections with catalase-positive organisms. Which laboratory test, which measures the oxidative burst by detecting conversion of a dye, is used to diagnose this defect?
- Hemoglobin electrophoresis
- The dihydrorhodamine (or nitroblue tetrazolium) test
- The direct antiglobulin test
- The osmotic fragility test
Correct answer: The dihydrorhodamine (or nitroblue tetrazolium) test
The dihydrorhodamine or nitroblue tetrazolium test is correct because chronic granulomatous disease results from defective NADPH oxidase, and these tests detect the failure to generate reactive oxygen species, with neutrophils unable to oxidize the dye. The direct antiglobulin test detects antibody-coated red cells, hemoglobin electrophoresis identifies hemoglobinopathies, and the osmotic fragility test assesses membrane disorders, none of which evaluates the neutrophil oxidative burst.
- A boy with chronic granulomatous disease is especially susceptible to organisms that produce catalase. Why does catalase production make certain organisms particularly dangerous in this disease?
- Catalase directly inhibits antibody production
- Catalase blocks T-cell activation
- Catalase degrades the microbe's own hydrogen peroxide that the deficient neutrophil could otherwise use
- Catalase activates complement against host cells
Correct answer: Catalase degrades the microbe's own hydrogen peroxide that the deficient neutrophil could otherwise use
Catalase degrading the microbe's own hydrogen peroxide that the deficient neutrophil could otherwise use is correct because neutrophils in chronic granulomatous disease cannot make their own reactive oxygen species, so they normally borrow hydrogen peroxide produced by the microbe, but catalase-positive organisms destroy that peroxide and evade killing. Catalase does not inhibit antibody production, activate complement against host cells, or block T-cell activation, so those mechanisms do not explain the susceptibility.
- A patient with widespread cancer is treated with a drug engineered to recognize a tumor surface protein and recruit immune effectors. Monoclonal antibodies such as rituximab treat B-cell malignancies by binding which surface marker found on B cells?
Correct answer: CD20
CD20 is correct because rituximab is a monoclonal antibody that binds CD20 on B lymphocytes, leading to their destruction through complement and antibody-dependent cellular cytotoxicity, and it is used to treat B-cell lymphomas and certain autoimmune diseases. CD3 marks T cells, CD14 marks monocytes, and CD56 marks natural killer cells, none of which is the B-cell target of rituximab.
- A medical student studies B-cell development. After a naive B cell first encounters its antigen and receives T-cell help, it undergoes a process in germinal centers that introduces point mutations into the variable region genes to produce higher-affinity antibodies. This process is called what?
- Somatic hypermutation
- Positive selection
- VDJ recombination
- Clonal deletion
Correct answer: Somatic hypermutation
Somatic hypermutation is correct because within germinal centers, activated B cells introduce point mutations into the immunoglobulin variable region genes, and selection of higher-affinity clones drives affinity maturation of the antibody response. VDJ recombination generates the initial receptor diversity before antigen exposure, positive selection occurs in T-cell development, and clonal deletion removes self-reactive cells, none of which is the germinal center process described.
- A medical student studies B-cell receptor formation. Early in B-cell development in the bone marrow, gene segments are randomly recombined to assemble a unique antigen receptor before any antigen is encountered. This process that generates the primary diversity of the antibody repertoire is called what?
- Affinity maturation
- VDJ recombination
- Isotype switching
- Anergy
Correct answer: VDJ recombination
VDJ recombination is correct because the random rearrangement of variable, diversity, and joining gene segments during B-cell development in the bone marrow creates the enormous primary diversity of antigen receptors before antigen exposure. Isotype switching changes the antibody class after activation, affinity maturation refines binding through somatic hypermutation, and anergy is a tolerance mechanism, none of which generates the initial receptor diversity.
- A nursing infant is protected from infection during the first months of life by antibodies acquired across the placenta and through breast milk. The protection an infant gains from these maternally derived antibodies is an example of which type of immunity?
- Artificially acquired passive immunity
- Artificially acquired active immunity
- Naturally acquired passive immunity
- Naturally acquired active immunity
Correct answer: Naturally acquired passive immunity
Naturally acquired passive immunity is correct because the infant receives preformed maternal antibodies through the placenta and breast milk without producing its own response, and this protection occurs through a natural rather than medical process. Naturally acquired active immunity follows infection, artificially acquired passive immunity comes from injected antibody preparations, and artificially acquired active immunity comes from vaccination, none of which describes maternal antibody transfer.
- A 19-year-old woman experiences wheezing, hives, and itching within minutes of a bee sting, mediated by preformed IgE on mast cells. Which type of hypersensitivity reaction does this immediate response represent?
- Type IV (delayed) hypersensitivity
- Type II (antibody-mediated) hypersensitivity
- Type III (immune complex) hypersensitivity
- Type I (immediate) hypersensitivity
Correct answer: Type I (immediate) hypersensitivity
Type I (immediate) hypersensitivity is correct because the rapid reaction to an allergen is driven by IgE bound to mast cells and basophils, which cross-links on antigen exposure to release histamine and other mediators within minutes. Type II involves antibodies against cell-surface antigens, type III involves immune complex deposition, and type IV is a delayed T-cell-mediated response, none of which produces this immediate IgE-mediated reaction.
- A patient develops a positive tuberculin skin test, showing induration 48 to 72 hours after intradermal injection of the antigen. This delayed reaction, which peaks days after exposure, is an example of which hypersensitivity mechanism?
- Type IV (delayed, T-cell-mediated) hypersensitivity
- Type I (IgE-mediated) hypersensitivity
- Type II (cytotoxic antibody) hypersensitivity
- Type III (immune complex) hypersensitivity
Correct answer: Type IV (delayed, T-cell-mediated) hypersensitivity
Type IV (delayed, T-cell-mediated) hypersensitivity is correct because the tuberculin reaction depends on sensitized T cells that recruit and activate macrophages, producing induration that takes one to three days to develop rather than minutes. Type I reactions are immediate and IgE-mediated, type II involves antibodies against cell antigens, and type III involves immune complex deposition, none of which explains this antibody-independent delayed cellular response.
- A patient develops fever, arthralgias, and a rash about ten days after receiving a foreign antiserum, with deposition of antigen-antibody complexes in vessel walls and low complement levels. This reaction is an example of which hypersensitivity type?
- Type I (immediate) hypersensitivity
- Type III (immune complex) hypersensitivity
- Type IV (delayed) hypersensitivity
- Type II (antibody-mediated) hypersensitivity
Correct answer: Type III (immune complex) hypersensitivity
Type III (immune complex) hypersensitivity is correct because serum sickness results from circulating antigen-antibody complexes that deposit in tissues, activate complement, and cause fever, rash, arthralgias, and a fall in complement levels days after exposure. Type I is immediate and IgE-mediated, type II targets cell-surface antigens, and type IV is delayed and T-cell-mediated, none of which is the immune complex mechanism of serum sickness.
- A patient with autoimmune hemolytic anemia has IgG antibodies that coat red cells and cause their premature destruction by splenic macrophages. This destruction of antibody-coated cells by phagocytes recognizing the bound antibody is an example of which hypersensitivity type?
- Type I (immediate) hypersensitivity
- Type IV (delayed) hypersensitivity
- Type II (antibody-mediated cytotoxic) hypersensitivity
- Type III (immune complex) hypersensitivity
Correct answer: Type II (antibody-mediated cytotoxic) hypersensitivity
Type II (antibody-mediated cytotoxic) hypersensitivity is correct because autoimmune hemolytic anemia involves antibodies binding antigens on the red cell surface, leading to complement-mediated lysis or phagocytic destruction of the targeted cells. Type I is IgE-mediated immediate allergy, type III involves soluble immune complexes, and type IV is T-cell-mediated, none of which describes antibody binding to a cell-surface antigen to cause destruction.
- A medical student studies how warm and cold autoimmune hemolytic anemias differ. A patient develops acrocyanosis and hemolysis on exposure to cold, and testing reveals IgM antibodies that bind red cells at low temperatures. Cold agglutinin disease is typically mediated by which antibody class?
- Immunoglobulin E
- Immunoglobulin G
- Immunoglobulin A
- Immunoglobulin M
Correct answer: Immunoglobulin M
Immunoglobulin M is correct because cold agglutinin disease is caused by IgM antibodies that bind red cells at cold temperatures, agglutinate them, and fix complement, leading to hemolysis and acrocyanosis on cold exposure. Warm autoimmune hemolytic anemia is mediated by IgG active at body temperature, while IgE mediates allergy and IgA acts at mucosal surfaces, so neither is the cold-reactive agglutinin described.
- A medical student studies the structure of immunoglobulin M. In its secreted form, IgM circulates as a large multimeric molecule with ten antigen-binding sites, making it highly effective at agglutination and complement activation. What is the polymeric structure of secreted IgM?
- A pentamer
- A dimer
- A monomer
- A trimer
Correct answer: A pentamer
A pentamer is correct because secreted IgM consists of five linked monomeric units joined by a J chain, giving it ten antigen-binding sites and making it especially efficient at agglutinating antigens and activating the classical complement pathway. IgM is not a monomer in its secreted form, and it does not circulate primarily as a dimer or trimer, so the pentameric structure is what gives IgM its potent early effector function.
- A medical student reviews the primary versus secondary antibody response. On first exposure to an antigen, the body produces a particular antibody class first, before class switching occurs. Which immunoglobulin is the first antibody produced in a primary immune response?
- Immunoglobulin E
- Immunoglobulin M
- Immunoglobulin A
- Immunoglobulin G
Correct answer: Immunoglobulin M
Immunoglobulin M is correct because it is the first antibody class produced during a primary immune response before B cells undergo class switching to other isotypes, so a rising IgM titer indicates recent or acute infection. Immunoglobulin G predominates in the secondary response and provides long-term immunity, immunoglobulin A protects mucosal surfaces, and immunoglobulin E mediates allergy, none of which appears first in a primary response.
- A patient recovering from an infection mounts a faster, stronger antibody response upon re-exposure to the same pathogen, producing predominantly high-affinity IgG. This enhanced response is possible because of which population of long-lived cells generated by the first exposure?
- Neutrophils
- Mast cells
- Memory B cells
- Naive B cells
Correct answer: Memory B cells
Memory B cells is correct because the primary response generates long-lived memory B cells that respond rapidly and vigorously on re-exposure, producing a faster, higher-titer, class-switched IgG secondary response. Naive B cells have not yet encountered antigen and respond slowly, mast cells mediate allergy, and neutrophils are innate phagocytes, none of which accounts for the accelerated memory response.
- A medical student studies adaptive immunity. CD8-positive cytotoxic T cells recognize antigen displayed by cells throughout the body. On which molecule do these cytotoxic T cells recognize endogenously derived antigen, such as viral peptides?
- MHC class II
- CD4
- The B-cell receptor
- MHC class I
Correct answer: MHC class I
MHC class I is correct because virtually all nucleated cells display endogenously derived peptides, including viral proteins, on MHC class I molecules for surveillance by CD8-positive cytotoxic T cells, which then kill infected cells. MHC class II presents extracellular antigen to CD4 helper T cells, CD4 is a coreceptor for class II, and the B-cell receptor recognizes free antigen, none of which presents endogenous peptide to cytotoxic T cells.
- A medical student reviews how dendritic cells display antigens acquired from outside the cell on MHC class I to activate cytotoxic T cells. This ability of professional antigen-presenting cells to route extracellular antigen onto MHC class I is known as what?
- Cross-presentation
- Affinity maturation
- Anergy
- Opsonization
Correct answer: Cross-presentation
Cross-presentation is correct because dendritic cells can take up extracellular antigens and load them onto MHC class I to prime CD8-positive cytotoxic T cells, a process essential for generating responses against viruses and tumors that do not directly infect dendritic cells. Opsonization marks pathogens for phagocytosis, anergy is functional inactivation, and affinity maturation refines antibody binding, none of which describes this antigen-routing pathway.
- A 2-year-old child with eczema, recurrent infections, and a tendency to bleed is found to have a low platelet count with abnormally small platelets and is diagnosed with an X-linked syndrome. Which immunodeficiency is characterized by the triad of eczema, thrombocytopenia with small platelets, and recurrent infections?
- Chronic granulomatous disease
- Wiskott-Aldrich syndrome
- DiGeorge syndrome
- Severe combined immunodeficiency
Correct answer: Wiskott-Aldrich syndrome
Wiskott-Aldrich syndrome is correct because this X-linked disorder from a WAS gene mutation produces the classic triad of eczema, thrombocytopenia with characteristically small platelets, and recurrent infections from combined immune dysfunction. DiGeorge syndrome features thymic and parathyroid aplasia with hypocalcemia, chronic granulomatous disease is a phagocyte oxidative defect, and severe combined immunodeficiency lacks functional lymphocytes, none of which produces this specific triad.
- A newborn presents with hypocalcemic tetany, a congenital heart defect, and recurrent viral and fungal infections, and imaging shows an absent thymus. This combination results from failed development of which embryologic structures?
- The neural crest of the spinal cord
- The yolk sac blood islands
- The third and fourth pharyngeal pouches
- The mesonephric ducts
Correct answer: The third and fourth pharyngeal pouches
The third and fourth pharyngeal pouches is correct because DiGeorge syndrome results from a 22q11 deletion that disrupts development of these pouches, leading to thymic aplasia with T-cell deficiency, parathyroid hypoplasia with hypocalcemia, and conotruncal cardiac defects. The neural crest, yolk sac blood islands, and mesonephric ducts give rise to other structures and do not account for the combined immune, cardiac, and parathyroid findings.
- A medical student studies a primary immunodeficiency in which B cells fail to develop because of a defect in a signaling enzyme. A boy has recurrent bacterial infections after six months of age, absent B cells, and very low immunoglobulins of all classes due to a defective tyrosine kinase. Which immunodeficiency is this?
- Common variable immunodeficiency
- Hyper-IgM syndrome
- Selective IgA deficiency
- X-linked (Bruton) agammaglobulinemia
Correct answer: X-linked (Bruton) agammaglobulinemia
X-linked (Bruton) agammaglobulinemia is correct because a defect in Bruton tyrosine kinase blocks B-cell maturation, so affected boys have absent B cells and very low immunoglobulins, with recurrent bacterial infections beginning as maternal antibody wanes after six months. Common variable immunodeficiency has present but dysfunctional B cells, selective IgA deficiency affects only IgA, and hyper-IgM syndrome shows high IgM with low other classes, none of which is the B-cell maturation arrest described.
- A patient with recurrent sinopulmonary and gastrointestinal infections has a normal immune workup except for a markedly low IgA with normal IgG and IgM levels. This most common primary immunodeficiency carries a risk of which reaction during transfusion?
- Anaphylaxis from anti-IgA antibodies
- Iron overload
- Graft-versus-host disease
- Hemolysis from ABO incompatibility
Correct answer: Anaphylaxis from anti-IgA antibodies
Anaphylaxis from anti-IgA antibodies is correct because patients with selective IgA deficiency can form anti-IgA antibodies and develop severe anaphylactic transfusion reactions when exposed to IgA-containing blood products, so they require washed or IgA-deficient products. ABO hemolysis results from blood group mismatch, iron overload follows chronic transfusion, and graft-versus-host disease results from donor lymphocytes, none of which is the specific risk tied to anti-IgA antibodies.
- A medical student studies the alternative complement pathway. Unlike the classical pathway, the alternative pathway can be activated without antibody. What initiates the alternative complement pathway?
- C1q binding antibody Fc regions
- Spontaneous hydrolysis of C3 that deposits on microbial surfaces
- Thrombin cleaving fibrinogen
- Mannose-binding lectin binding sugars
Correct answer: Spontaneous hydrolysis of C3 that deposits on microbial surfaces
Spontaneous hydrolysis of C3 that deposits on microbial surfaces is correct because the alternative pathway is triggered by low-level spontaneous C3 hydrolysis, with the resulting fragment binding microbial surfaces and amplifying complement activation independently of antibody. C1q binding antibody initiates the classical pathway, mannose-binding lectin initiates the lectin pathway, and thrombin cleaving fibrinogen is a coagulation event, none of which starts the alternative pathway.
- A patient with paroxysmal nocturnal hemoglobinuria is started on a monoclonal antibody that blocks complement to reduce hemolysis. The drug eculizumab inhibits the complement cascade by binding which component, thereby preventing formation of the membrane attack complex?
Correct answer: C5
C5 is correct because eculizumab binds C5 and prevents its cleavage into C5a and C5b, blocking assembly of the membrane attack complex and reducing the complement-mediated intravascular hemolysis of paroxysmal nocturnal hemoglobinuria. Inhibiting C3, C1q, or factor B would act at different points, but the drug specifically targets C5, which is also why it raises the risk of Neisseria infection from impaired terminal complement.
- A medical student reviews mast cell biology. Upon allergen exposure, mast cells rapidly release preformed mediators stored in their granules to produce immediate allergic symptoms. Which preformed mediator is released first to cause vasodilation and increased vascular permeability?
- Interferon gamma
- Leukotrienes synthesized de novo
- Interleukin-2
- Histamine
Correct answer: Histamine
Histamine is correct because it is a preformed mediator stored in mast cell granules and released immediately upon allergen-induced cross-linking of IgE, producing rapid vasodilation, increased vascular permeability, and bronchoconstriction. Leukotrienes are synthesized de novo and contribute to the later phase, while interleukin-2 and interferon gamma are T-cell cytokines, none of which is the preformed granule mediator of the immediate reaction.
- A medical student studies leukocyte differentials. A patient recovering from a viral infection has a relative increase in mononuclear cells that mature into tissue macrophages and present antigen. Which circulating leukocyte is the precursor of tissue macrophages?
- Monocyte
- Neutrophil
- Eosinophil
- Platelet
Correct answer: Monocyte
Monocyte is correct because monocytes are the largest circulating leukocytes that migrate into tissues and differentiate into macrophages and dendritic cells, performing phagocytosis and antigen presentation. Neutrophils are short-lived first responders, eosinophils target parasites and allergy, and platelets are cell fragments for hemostasis, none of which becomes a tissue macrophage.
- A medical student examines a smear from a patient who underwent splenectomy after trauma and notes red cells containing small round basophilic nuclear remnants. These Howell-Jolly bodies persist after splenectomy because the spleen normally performs which function?
- Storing vitamin B12
- Pitting nuclear remnants from red cells
- Producing erythropoietin
- Synthesizing clotting factors
Correct answer: Pitting nuclear remnants from red cells
Pitting nuclear remnants from red cells is correct because the spleen normally removes residual nuclear material from circulating red cells, so after splenectomy or in functional asplenia these Howell-Jolly bodies remain visible. The spleen does not produce erythropoietin, which comes from the kidney, does not synthesize clotting factors, which is a hepatic function, and does not store vitamin B12, so none of those explains the persistence of nuclear remnants.
- A patient who underwent splenectomy is counseled about a heightened risk of overwhelming sepsis. Asplenic patients are particularly vulnerable to severe infection by which category of organisms?
- Anaerobic gut flora
- Catalase-positive staphylococci
- Encapsulated bacteria
- Intracellular mycobacteria
Correct answer: Encapsulated bacteria
Encapsulated bacteria is correct because the spleen is essential for clearing encapsulated organisms such as Streptococcus pneumoniae, Haemophilus influenzae, and Neisseria meningitidis, so asplenic patients are at high risk for overwhelming sepsis from these and require vaccination. Catalase-positive organisms threaten patients with chronic granulomatous disease, mycobacterial risk relates to interferon pathway defects, and anaerobic gut flora are not the characteristic asplenia threat.
- A medical student studies acute-phase reactants. During systemic inflammation, the liver increases production of a protein that binds phosphocholine on microbes, activates complement, and is widely used as a clinical marker of inflammation. Which protein is this?
- Haptoglobin only
- Transferrin
- Albumin
- C-reactive protein
Correct answer: C-reactive protein
C-reactive protein is correct because it is a hepatic acute-phase reactant that rises with inflammation, binds phosphocholine on the surface of microbes and damaged cells to opsonize them and activate complement, and serves as a common laboratory marker of inflammatory activity. Albumin and transferrin are negative acute-phase reactants that fall during inflammation, and although haptoglobin rises, it primarily binds free hemoglobin rather than serving as the inflammatory marker described.
- A patient with chronic inflammation develops an anemia with low serum iron, low total iron-binding capacity, and a high ferritin. Which key regulatory peptide, increased by inflammatory cytokines, drives this pattern by blocking iron release from stores?
- Hepcidin
- Transferrin
- Intrinsic factor
- Erythropoietin
Correct answer: Hepcidin
Hepcidin is correct because inflammatory cytokines such as interleukin-6 increase hepcidin, which degrades ferroportin to trap iron in enterocytes and macrophages, lowering serum iron and iron-binding capacity while ferritin stays high, the characteristic pattern of anemia of chronic disease. Erythropoietin stimulates red cell production, transferrin transports iron, and intrinsic factor enables B12 absorption, none of which produces this iron-sequestration pattern.
- A 16-year-old girl with recurrent severe Neisseria infections is found to have an isolated deficiency of one terminal complement component. A screening assay that measures the integrity of the entire classical complement pathway would show which result in this patient?
- Only a low IgA level
- An absent or markedly low total hemolytic complement (CH50)
- A normal total hemolytic complement
- An elevated total hemolytic complement
Correct answer: An absent or markedly low total hemolytic complement (CH50)
An absent or markedly low total hemolytic complement (CH50) is correct because the CH50 assay requires all classical pathway components through the membrane attack complex to lyse the indicator cells, so a deficiency of any terminal component drives the CH50 toward zero. A normal or elevated CH50 would not be expected with a functional component missing, and a low IgA level is unrelated to complement integrity, so the markedly reduced CH50 is the expected finding.
- A medical student studies cytokine signaling in hematopoiesis. A patient with severe anemia from chemotherapy is treated with a recombinant hormone that stimulates red cell production. The receptor for erythropoietin signals primarily through which intracellular pathway?
- The cyclic AMP pathway
- The inositol triphosphate pathway
- The JAK-STAT pathway
- The Wnt pathway
Correct answer: The JAK-STAT pathway
The JAK-STAT pathway is correct because erythropoietin binds its receptor and activates Janus kinases that phosphorylate STAT transcription factors, driving the survival and proliferation of erythroid progenitors, a pathway whose dysregulation by JAK2 mutation underlies polycythemia vera. The cyclic AMP, inositol triphosphate, and Wnt pathways mediate other forms of signaling and are not the principal route for erythropoietin receptor signaling.
- A 7-year-old child with acute lymphoblastic leukemia has a markedly elevated white cell count, and the team worries about leukostasis. Leukostasis from extreme leukocytosis causes symptoms primarily through which mechanism?
- Iron deposition in tissues
- Consumption of clotting factors
- Antibody-mediated red cell destruction
- Impaired microcirculatory blood flow from sludging of leukocytes
Correct answer: Impaired microcirculatory blood flow from sludging of leukocytes
Impaired microcirculatory blood flow from sludging of leukocytes is correct because very high blast counts increase blood viscosity and obstruct the microvasculature of the lungs and brain, producing hypoxia, headache, and altered mental status in leukostasis. Antibody-mediated red cell destruction, consumption of clotting factors, and iron deposition describe other processes and do not explain the microvascular obstruction from excess circulating leukemic cells.
- A 60-year-old man develops a fever during a transfusion of packed red cells without hemolysis or hypotension, and the reaction is attributed to recipient antibodies against donor white blood cell antigens and accumulated cytokines. Which transfusion reaction is this, and how is it best prevented?
- Febrile nonhemolytic reaction, prevented by leukoreduction
- Transfusion-associated circulatory overload, prevented by slower infusion
- Anaphylactic reaction, prevented by washing
- Acute hemolytic reaction, prevented by ABO matching
Correct answer: Febrile nonhemolytic reaction, prevented by leukoreduction
Febrile nonhemolytic reaction, prevented by leukoreduction is correct because fever without hemolysis during transfusion typically results from recipient antibodies against donor leukocytes and cytokines released by white cells in the unit, and removing leukocytes before storage prevents it. Acute hemolytic reactions are ABO-driven and life-threatening, anaphylaxis relates to anti-IgA antibodies, and circulatory overload is volume-related, none of which is this leukocyte-mediated febrile reaction.
- A medical student studies thymus-independent antigens. A vaccine made from a pure bacterial polysaccharide elicits a weaker, shorter-lived antibody response in young children because of which limitation of such antigens?
- They activate only cytotoxic T cells
- They cannot recruit T-cell help, so no class switching or memory develops
- They are degraded too quickly to reach lymph nodes
- They induce tolerance in all recipients
Correct answer: They cannot recruit T-cell help, so no class switching or memory develops
They cannot recruit T-cell help, so no class switching or memory develops is correct because pure polysaccharides are thymus-independent antigens that activate B cells directly without helper T-cell involvement, producing mainly IgM with little class switching, affinity maturation, or durable memory, which is poor in young children. The antigens do reach lymphoid tissue, do not act through cytotoxic T cells, and do not uniformly induce tolerance, so those options do not explain the limitation.
- A 30-year-old woman with a parasitic infection has a peripheral smear demonstrating a marked rise in basophils. Basophils and tissue mast cells contribute to immediate hypersensitivity largely through release of which two granule mediators?
- Major basic protein and eosinophil peroxidase
- Defensins and lysozyme
- Histamine and heparin
- Perforin and granzyme
Correct answer: Histamine and heparin
Histamine and heparin is correct because basophils and mast cells store these mediators in their granules and release them during immediate hypersensitivity, with histamine causing vasodilation and increased permeability and heparin acting as an anticoagulant. Perforin and granzyme are cytotoxic lymphocyte products, major basic protein and eosinophil peroxidase are eosinophil granule proteins, and defensins and lysozyme are antimicrobial peptides, none of which are the basophil and mast cell mediators described.
- A medical student reviews how the body limits a clot to the site of injury. On intact endothelium, an enzyme converts ADP, a platelet activator, to keep platelets quiescent away from the wound. Which endothelial property helps prevent inappropriate platelet activation on healthy vessel walls?
- Endothelial secretion of tissue factor
- Endothelial release of thromboxane A2
- Endothelial exposure of collagen
- Endothelial production of prostacyclin and nitric oxide
Correct answer: Endothelial production of prostacyclin and nitric oxide
Endothelial production of prostacyclin and nitric oxide is correct because healthy endothelium secretes these vasodilators that inhibit platelet activation and aggregation, helping confine clot formation to sites of injury. Thromboxane A2 promotes platelet aggregation, tissue factor initiates coagulation, and exposed collagen triggers platelet adhesion, all of which would promote rather than prevent clotting, so they are not the antithrombotic endothelial functions described.
- A medical student studies platelet activation. When platelets are activated at a site of injury, they release the contents of their dense granules to recruit and activate additional platelets. Which substance released from platelet dense granules is a major amplifier of platelet aggregation?
- Adenosine diphosphate
- Antithrombin
- Plasminogen
- Tissue factor
Correct answer: Adenosine diphosphate
Adenosine diphosphate is correct because activated platelets release this mediator from their dense granules to bind P2Y12 receptors on nearby platelets, amplifying activation and aggregation, which is why P2Y12 inhibitors are effective antiplatelet drugs. Tissue factor initiates the coagulation cascade, plasminogen is the fibrinolytic precursor, and antithrombin is a natural anticoagulant, none of which is the dense granule platelet agonist described.
- A medical student reviews the regulation of blood cell numbers. After tissue hypoxia, the kidney increases output of a hormone that drives red cell production. Where in the kidney is erythropoietin primarily produced in response to low oxygen?
- Glomerular podocytes
- Peritubular interstitial cells of the renal cortex
- Collecting duct principal cells
- The renal pelvis urothelium
Correct answer: Peritubular interstitial cells of the renal cortex
Peritubular interstitial cells of the renal cortex is correct because these fibroblast-like interstitial cells sense hypoxia through hypoxia-inducible factor and produce erythropoietin to stimulate marrow red cell production. Glomerular podocytes form the filtration barrier, collecting duct principal cells handle water and sodium, and the renal pelvis urothelium lines the urinary tract, none of which is the site of erythropoietin synthesis.
- A medical student studies iron storage. A patient's bone marrow biopsy is stained for iron, revealing abundant storage iron within macrophages. Which protein is the major intracellular iron storage molecule whose serum level reflects total body iron stores?
- Hepcidin
- Ceruloplasmin
- Ferritin
- Transferrin
Correct answer: Ferritin
Ferritin is correct because it is the principal intracellular protein that stores iron in a soluble, nontoxic form, and its serum concentration generally parallels total body iron stores, falling in iron deficiency and rising with iron overload or inflammation. Transferrin transports iron in plasma, hepcidin regulates iron release, and ceruloplasmin participates in copper transport and iron oxidation, none of which is the main iron storage molecule.
- A medical student reviews the breakdown of heme. After macrophages catabolize the heme from senescent red cells, the iron is recycled and the porphyrin ring is converted in sequence to bilirubin. Which green pigment is the immediate intermediate formed when heme oxygenase opens the heme ring before it becomes bilirubin?
- Hemosiderin
- Urobilinogen
- Stercobilin
- Biliverdin
Correct answer: Biliverdin
Biliverdin is correct because heme oxygenase opens the porphyrin ring of heme to form the green pigment biliverdin, which is then reduced to unconjugated bilirubin for transport to the liver. Urobilinogen and stercobilin are downstream gut products of bilirubin metabolism, and hemosiderin is an iron storage form, none of which is the immediate green intermediate of heme degradation.
- A medical student studies the lymphatic system. Antigen carried in lymph reaches a lymph node and first enters through vessels that drain into a particular space before percolating through the node. Through which vessels does antigen-containing lymph enter a lymph node?
- Afferent lymphatic vessels
- Efferent lymphatic vessels
- The central arteriole
- High endothelial venules
Correct answer: Afferent lymphatic vessels
Afferent lymphatic vessels is correct because lymph carrying antigen and antigen-presenting cells enters the lymph node through multiple afferent lymphatics that drain into the subcapsular sinus before the lymph filters through the node. Efferent lymphatics carry lymph out of the node, high endothelial venules admit blood-borne lymphocytes, and the central arteriole is a splenic structure, none of which is the entry route for antigen-laden lymph.
- A pathologist examines a reactive lymph node and identifies a region beneath the capsule rich in B cells organized into follicles with germinal centers. In which anatomic zone of the lymph node are B cells predominantly located?
- The medullary sinus
- The cortex (follicles)
- The hilum
- The paracortex
Correct answer: The cortex (follicles)
The cortex (follicles) is correct because B cells are concentrated in the outer cortex of the lymph node within primary and secondary follicles, the latter containing germinal centers where B cells proliferate and undergo affinity maturation. The paracortex is the T-cell-rich zone, the medullary sinuses contain macrophages and plasma cells, and the hilum is the vascular entry point, none of which is the principal B-cell follicular region.
- A pathologist examines a lymph node from a patient with a strong cellular immune response and notes marked expansion of the deep cortical region rich in T cells. Which zone of the lymph node is this T-cell-dependent area?
- The subcapsular sinus
- The follicle
- The paracortex
- The germinal center
Correct answer: The paracortex
The paracortex is correct because it is the T-cell-rich zone of the lymph node located between the follicular cortex and the medulla, and it expands during cell-mediated immune responses such as viral infections. The follicles and germinal centers are B-cell zones, and the subcapsular sinus is where afferent lymph enters, none of which is the T-cell-dependent paracortical region.
- A medical student studies the difference between the spleen's two functional regions. Aged red cells and blood-borne particles are filtered and removed in which compartment of the spleen?
- The periarteriolar lymphoid sheath
- The germinal centers
- The white pulp
- The red pulp
Correct answer: The red pulp
The red pulp is correct because it contains the splenic cords and sinusoids where macrophages filter the blood, removing senescent or damaged red cells and pitting inclusions from otherwise viable cells. The white pulp, the periarteriolar lymphoid sheath, and germinal centers are lymphoid regions devoted to adaptive immune responses rather than the mechanical filtration of aged red cells.
- A medical student studies tumor lysis syndrome after chemotherapy. Rapid destruction of a large number of malignant cells releases intracellular contents, producing a characteristic metabolic derangement. Which set of laboratory abnormalities is classic for tumor lysis syndrome?
- High potassium, high phosphate, high uric acid, and low calcium
- High calcium and low uric acid
- Low potassium and high glucose only
- Low potassium, low phosphate, and high calcium
Correct answer: High potassium, high phosphate, high uric acid, and low calcium
High potassium, high phosphate, high uric acid, and low calcium is correct because lysis of malignant cells dumps intracellular potassium, phosphate, and nucleic acids (metabolized to uric acid) into the blood, and the released phosphate binds calcium to cause hypocalcemia, threatening arrhythmias and acute kidney injury. The other combinations do not reflect the release of intracellular contents that defines tumor lysis syndrome.
- A 29-year-old woman with multiple sclerosis has a lumbar puncture during evaluation. Which cerebrospinal fluid finding is most characteristic of multiple sclerosis and reflects intrathecal antibody production?
- Markedly low glucose with neutrophilic pleocytosis
- Oligoclonal bands not present in matched serum
- Xanthochromia with elevated red blood cells
- Very high opening pressure with normal cell count
Correct answer: Oligoclonal bands not present in matched serum
Oligoclonal bands not present in matched serum is correct because multiple sclerosis produces immunoglobulin synthesis within the central nervous system, generating oligoclonal bands in cerebrospinal fluid that are absent from a paired serum sample. Low glucose with neutrophils suggests bacterial meningitis, xanthochromia suggests subarachnoid hemorrhage, and a markedly elevated pressure suggests intracranial hypertension, none of which is the intrathecal antibody signature of multiple sclerosis.
- A 31-year-old woman with multiple sclerosis notices that her neurologic symptoms transiently worsen when she takes a hot bath or exercises in the heat. Which phenomenon best explains this temperature-related worsening?
- Permanent axonal transection from elevated temperature
- A new demyelinating relapse triggered by warmth
- Heat stroke affecting the hypothalamus
- Uhthoff phenomenon, in which heat impairs conduction in demyelinated axons
Correct answer: Uhthoff phenomenon, in which heat impairs conduction in demyelinated axons
Uhthoff phenomenon is correct because increased body temperature further slows or blocks conduction along already demyelinated axons, causing a temporary, reversible worsening of multiple sclerosis symptoms that resolves when the patient cools down. It is not a true new relapse or fixed axonal loss, and it is not heat stroke, none of which describes this reversible heat sensitivity.
- A 60-year-old man with idiopathic Parkinson disease has the cardinal motor features evaluated. Which set of findings represents the classic motor triad of Parkinson disease?
- Resting tremor, bradykinesia, and rigidity
- Spasticity, hyperreflexia, and clonus
- Chorea, dystonia, and myoclonus
- Intention tremor, dysmetria, and nystagmus
Correct answer: Resting tremor, bradykinesia, and rigidity
Resting tremor, bradykinesia, and rigidity is correct because these, together with postural instability, are the cardinal motor features of Parkinson disease, arising from degeneration of dopaminergic nigrostriatal neurons. Chorea and dystonia suggest other movement disorders, spasticity with hyperreflexia indicates an upper motor neuron lesion, and intention tremor with dysmetria indicates cerebellar disease, none of which is the parkinsonian triad.
- A neuropathologist examines the brainstem of a patient who had Parkinson disease and identifies eosinophilic cytoplasmic inclusions composed largely of aggregated alpha-synuclein within surviving neurons. What are these inclusions called?
- Neurofibrillary tangles
- Negri bodies
- Lewy bodies
- Pick bodies
Correct answer: Lewy bodies
Lewy bodies is correct because these round eosinophilic intraneuronal inclusions of aggregated alpha-synuclein are the pathologic hallmark of Parkinson disease, found in the substantia nigra and elsewhere. Neurofibrillary tangles are tau aggregates of Alzheimer disease, Negri bodies occur in rabies, and Pick bodies occur in frontotemporal dementia, none of which is the synuclein inclusion of Parkinson disease.
- A 68-year-old man with newly diagnosed Parkinson disease asks why a drug is combined with levodopa to reduce peripheral side effects such as nausea. Carbidopa improves levodopa therapy by inhibiting which process outside the central nervous system?
- Breakdown of dopamine by monoamine oxidase in the brain
- Central reuptake of dopamine into neurons
- Peripheral conversion of levodopa to dopamine by DOPA decarboxylase
- Renal excretion of levodopa
Correct answer: Peripheral conversion of levodopa to dopamine by DOPA decarboxylase
Peripheral conversion of levodopa to dopamine by DOPA decarboxylase is correct because carbidopa inhibits this enzyme in the periphery without crossing the blood-brain barrier, leaving more levodopa to enter the brain and reducing peripheral dopamine-related nausea and hypotension. It does not block central dopamine reuptake, central monoamine oxidase, or renal excretion, none of which is carbidopa's mechanism.
- A 45-year-old man with a family history of an autosomal dominant disorder develops chorea, behavioral changes, and progressive dementia in midlife, and genetic testing shows an expanded CAG trinucleotide repeat. Which structure shows the most prominent atrophy in this disorder?
- The caudate nucleus of the striatum
- The cerebellar vermis
- The hippocampus
- The substantia nigra
Correct answer: The caudate nucleus of the striatum
The caudate nucleus of the striatum is correct because Huntington disease, caused by a CAG repeat expansion in the huntingtin gene, preferentially destroys striatal neurons, producing caudate atrophy with enlargement of the frontal horns and the characteristic chorea. The hippocampus, cerebellar vermis, and substantia nigra are not the principal sites of degeneration in Huntington disease.
- A neuroscientist studies the basal ganglia changes in Huntington disease. Early loss of which inhibitory neurons of the indirect pathway best explains the chorea seen in this disorder?
- Dopaminergic neurons of the substantia nigra pars compacta
- GABAergic medium spiny neurons projecting to the external globus pallidus
- Cholinergic neurons of the nucleus basalis
- Glutamatergic neurons of the subthalamic nucleus
Correct answer: GABAergic medium spiny neurons projecting to the external globus pallidus
GABAergic medium spiny neurons projecting to the external globus pallidus is correct because early degeneration of these indirect-pathway neurons in Huntington disease disinhibits movement, producing the excessive involuntary chorea. Dopaminergic nigral neurons degenerate in Parkinson disease, cholinergic basal forebrain neurons in Alzheimer disease, and subthalamic glutamatergic neurons are not the early target, none of which explains Huntington chorea.
- A neuropathologist examines the cortex of a patient who died with Alzheimer disease and identifies extracellular plaques. The core of these senile plaques in Alzheimer disease is composed primarily of which protein?
- Alpha-synuclein
- Hyperphosphorylated tau
- Prion protein
- Beta-amyloid (Abeta) peptide
Correct answer: Beta-amyloid (Abeta) peptide
Beta-amyloid (Abeta) peptide is correct because the extracellular senile plaques of Alzheimer disease are formed by aggregation of beta-amyloid, derived from cleavage of amyloid precursor protein, whereas the intracellular neurofibrillary tangles are made of hyperphosphorylated tau. Alpha-synuclein forms Lewy bodies and prion protein causes spongiform disease, neither of which composes Alzheimer plaques.
- A 52-year-old man with Down syndrome develops progressive memory loss and is found to have early Alzheimer-type pathology. Which mechanism best explains the markedly increased risk of early Alzheimer disease in Down syndrome?
- An extra copy of the amyloid precursor protein gene on chromosome 21
- Deletion of the presenilin gene
- Loss of the APOE gene
- A CAG repeat expansion in the huntingtin gene
Correct answer: An extra copy of the amyloid precursor protein gene on chromosome 21
An extra copy of the amyloid precursor protein gene on chromosome 21 is correct because trisomy 21 gives a third copy of this gene, increasing beta-amyloid production and causing nearly all individuals with Down syndrome to develop Alzheimer pathology by middle age. Presenilin or APOE loss and a huntingtin expansion are not the mechanism linking Down syndrome to Alzheimer disease.
- A 24-year-old man with schizophrenia is treated with haloperidol, and the clinician explains why these high-potency typical agents relieve hallucinations and delusions. Blockade of dopamine receptors in which pathway most directly accounts for the antipsychotic effect on positive symptoms?
- The nigrostriatal pathway
- The tuberoinfundibular pathway
- The mesocortical pathway
- The mesolimbic pathway
Correct answer: The mesolimbic pathway
The mesolimbic pathway is correct because excess dopaminergic activity in this pathway underlies the positive symptoms of schizophrenia, so dopamine D2 blockade there reduces hallucinations and delusions. Nigrostriatal blockade causes extrapyramidal effects, tuberoinfundibular blockade raises prolactin, and mesocortical blockade may worsen negative symptoms, none of which is the pathway mediating the antipsychotic benefit on positive symptoms.
- A 26-year-old man on a high-potency antipsychotic develops fever, severe muscle rigidity, autonomic instability, and a markedly elevated creatine kinase. Which life-threatening reaction does this represent?
- Serotonin syndrome
- Neuroleptic malignant syndrome
- Malignant hyperthermia from anesthesia
- Acute dystonic reaction
Correct answer: Neuroleptic malignant syndrome
Neuroleptic malignant syndrome is correct because dopamine blockade by antipsychotics can produce fever, lead-pipe rigidity, autonomic instability, altered mental status, and elevated creatine kinase, treated by stopping the drug and giving dantrolene or bromocriptine. Serotonin syndrome features clonus and hyperreflexia, malignant hyperthermia follows anesthetic triggers, and an acute dystonic reaction is a focal muscle spasm without this systemic picture.
- A 30-year-old man with schizophrenia treated with risperidone develops breast enlargement and galactorrhea. Blockade of dopamine in which pathway best explains this elevated prolactin?
- The tuberoinfundibular pathway
- The mesolimbic pathway
- The nigrostriatal pathway
- The mesocortical pathway
Correct answer: The tuberoinfundibular pathway
The tuberoinfundibular pathway is correct because dopamine from this pathway normally inhibits prolactin release, so antipsychotic blockade removes that inhibition and raises prolactin, causing galactorrhea and gynecomastia. The mesolimbic and mesocortical pathways relate to psychotic and cognitive symptoms, and the nigrostriatal pathway relates to movement, none of which controls prolactin secretion.
- A 35-year-old woman has discrete episodes of depressed mood and episodes of distinctly elevated, expansive mood with decreased need for sleep, grandiosity, and impulsive spending lasting over a week and impairing function. Which mood disorder best fits this presentation?
- Cyclothymic disorder
- Bipolar I disorder
- Persistent depressive disorder
- Major depressive disorder, recurrent
Correct answer: Bipolar I disorder
Bipolar I disorder is correct because at least one full manic episode lasting about a week with grandiosity, decreased need for sleep, and impaired functioning, typically alternating with depressive episodes, defines this disorder. Cyclothymic disorder involves milder, subthreshold symptoms, persistent depressive disorder is chronic low mood, and recurrent major depression lacks manic episodes, none of which captures full mania.
- A 22-year-old man is treated for an acute manic episode. Which medication is a classic mood stabilizer that, in this setting, also requires monitoring of serum levels, thyroid, and renal function?
- Buspirone
- Sertraline
- Lithium
- Bupropion
Correct answer: Lithium
Lithium is correct because it is a first-line mood stabilizer for acute mania and maintenance in bipolar disorder, with a narrow therapeutic index requiring monitoring of serum levels and of thyroid and renal function. Sertraline and bupropion are antidepressants that can precipitate mania, and buspirone is an anxiolytic, none of which is the level-monitored mood stabilizer described.
- A 28-year-old combat veteran has, for several months after a roadside explosion, intrusive flashbacks and nightmares, avoidance of reminders, hypervigilance with an exaggerated startle, and negative mood changes. Which disorder best fits this presentation?
- Post-traumatic stress disorder
- Generalized anxiety disorder
- Acute stress disorder
- Adjustment disorder
Correct answer: Post-traumatic stress disorder
Post-traumatic stress disorder is correct because re-experiencing, avoidance, negative cognition and mood, and hyperarousal persisting more than a month after exposure to a traumatic event define this disorder. Acute stress disorder describes similar symptoms lasting under a month, generalized anxiety disorder lacks a defining trauma and re-experiencing, and adjustment disorder follows a non-life-threatening stressor, none of which matches this post-traumatic picture.
- A 40-year-old woman with post-traumatic stress disorder is started on pharmacotherapy along with trauma-focused psychotherapy. Which medication class is considered first-line pharmacologic treatment for post-traumatic stress disorder?
- Stimulants
- Typical antipsychotics
- Long-term benzodiazepines
- Selective serotonin reuptake inhibitors
Correct answer: Selective serotonin reuptake inhibitors
Selective serotonin reuptake inhibitors is correct because agents such as sertraline and paroxetine are first-line pharmacotherapy for post-traumatic stress disorder, reducing core symptoms alongside trauma-focused therapy. Long-term benzodiazepines are generally avoided due to dependence and limited efficacy, and typical antipsychotics and stimulants are not first-line, making them incorrect.
- A 30-year-old man has recurrent unexpected episodes of intense fear that peak within minutes, with palpitations, shortness of breath, chest tightness, and a fear of dying, followed by persistent worry about further attacks. Which disorder best fits this presentation?
- Generalized anxiety disorder
- Somatic symptom disorder
- Specific phobia
- Panic disorder
Correct answer: Panic disorder
Panic disorder is correct because recurrent unexpected panic attacks with abrupt surges of fear and somatic symptoms, plus persistent concern about additional attacks, define this disorder. Generalized anxiety disorder involves chronic worry without discrete attacks, specific phobia is cued by a particular object, and somatic symptom disorder centers on persistent bodily symptoms, none of which is recurrent unexpected panic.
- A 27-year-old man during a panic attack hyperventilates and develops tingling around the mouth and in the fingers with carpopedal spasm. Which acid-base disturbance most directly produces these symptoms during hyperventilation?
- Metabolic acidosis
- Respiratory alkalosis
- Respiratory acidosis
- Metabolic alkalosis
Correct answer: Respiratory alkalosis
Respiratory alkalosis is correct because hyperventilation blows off carbon dioxide, raising blood pH and lowering ionized calcium, which causes perioral and digital paresthesias and carpopedal spasm during a panic attack. Respiratory acidosis results from hypoventilation, and metabolic acidosis and alkalosis are not produced by acute hyperventilation, making them incorrect.
- A 35-year-old man develops severe, strictly unilateral periorbital pain lasting under two hours, recurring in clusters over several weeks, accompanied by ipsilateral tearing, nasal congestion, and ptosis, and he paces restlessly during attacks. Which headache disorder is most consistent with these findings?
- Migraine without aura
- Tension-type headache
- Cluster headache
- Trigeminal neuralgia
Correct answer: Cluster headache
Cluster headache is correct because severe unilateral periorbital pain with ipsilateral autonomic features such as lacrimation, rhinorrhea, and ptosis, occurring in clusters with restless agitation, characterizes this disorder, more common in men. Migraine patients prefer to lie still, tension headache is bilateral and pressing, and trigeminal neuralgia is brief electric facial jabs, none of which fits this autonomic cluster pattern.
- A 32-year-old man with frequent cluster headache attacks is treated acutely to abort an attack. Besides triptans, which therapy provides rapid relief of an acute cluster headache?
- A loop diuretic
- Oral acetaminophen
- High-flow 100 percent oxygen
- A topical corticosteroid
Correct answer: High-flow 100 percent oxygen
High-flow 100 percent oxygen is correct because inhaling high-concentration oxygen aborts many acute cluster headache attacks quickly and is a standard acute treatment alongside triptans. Oral acetaminophen is too slow and weak for these severe attacks, a loop diuretic acts on the kidney, and a topical corticosteroid is not an abortive therapy, none of which rapidly terminates a cluster attack.
- A 35-year-old obese woman has headaches, transient visual obscurations, and bilateral papilledema, with a markedly elevated cerebrospinal fluid opening pressure but normal imaging and normal fluid composition. Which condition is most consistent with these findings?
- Idiopathic intracranial hypertension
- Bacterial meningitis
- Subarachnoid hemorrhage
- Normal pressure hydrocephalus
Correct answer: Idiopathic intracranial hypertension
Idiopathic intracranial hypertension is correct because headache with papilledema, transient visual obscurations, and high opening pressure in a young obese woman with normal imaging and normal cerebrospinal fluid defines this disorder, which threatens vision. Bacterial meningitis shows abnormal fluid and fever, subarachnoid hemorrhage shows blood with thunderclap onset, and normal pressure hydrocephalus shows a gait-cognition-incontinence triad without papilledema, none of which fits this picture.
- A 70-year-old man has a gait disturbance described as magnetic and shuffling, urinary incontinence, and cognitive decline, with imaging showing enlarged ventricles out of proportion to atrophy. Which condition is most consistent with this classic triad?
- Alzheimer disease
- Parkinson disease
- Vascular dementia
- Normal pressure hydrocephalus
Correct answer: Normal pressure hydrocephalus
Normal pressure hydrocephalus is correct because the triad of gait apraxia, urinary incontinence, and dementia with ventriculomegaly out of proportion to atrophy characterizes this condition, which may improve with cerebrospinal fluid shunting. Alzheimer disease lacks the early gait and continence findings, Parkinson disease has a parkinsonian gait with tremor, and vascular dementia follows strokes, none of which is this shunt-responsive triad.
- A 65-year-old man develops rapidly progressive dementia over a few months with startle myoclonus, and his electroencephalogram shows periodic sharp wave complexes. Which disorder, caused by an abnormal misfolded protein, is most consistent with these findings?
- Creutzfeldt-Jakob disease
- Alzheimer disease
- Frontotemporal dementia
- Lewy body dementia
Correct answer: Creutzfeldt-Jakob disease
Creutzfeldt-Jakob disease is correct because a prion-mediated, rapidly progressive dementia over weeks to months with myoclonus and periodic sharp waves on electroencephalography is characteristic of this spongiform encephalopathy. Alzheimer disease and frontotemporal dementia progress over years, and Lewy body dementia features fluctuating cognition and visual hallucinations, none of which shows this rapid prion-related course.
- A 58-year-old man develops striking early personality and behavioral changes, disinhibition, and loss of social tact with relatively preserved memory, and imaging shows frontal and temporal lobe atrophy. Which dementia is most consistent with these findings?
- Alzheimer disease
- Normal pressure hydrocephalus
- Vascular dementia
- Frontotemporal (Pick) dementia
Correct answer: Frontotemporal (Pick) dementia
Frontotemporal (Pick) dementia is correct because prominent early behavioral and personality change with disinhibition and frontotemporal atrophy, while memory is relatively spared early, characterizes this disorder, often with tau-containing Pick bodies. Alzheimer disease begins with memory loss, vascular dementia follows strokes, and normal pressure hydrocephalus presents with a gait-continence-cognition triad, none of which matches this behavioral-variant dementia.
- A 68-year-old man has fluctuating cognition, recurrent well-formed visual hallucinations, and spontaneous parkinsonism. This combination is most characteristic of which neurodegenerative dementia?
- Alzheimer disease
- Vascular dementia
- Dementia with Lewy bodies
- Creutzfeldt-Jakob disease
Correct answer: Dementia with Lewy bodies
Dementia with Lewy bodies is correct because fluctuating attention and cognition, recurrent vivid visual hallucinations, and parkinsonism are core features of this disorder, which is associated with alpha-synuclein Lewy bodies in the cortex. Alzheimer disease lacks early hallucinations and parkinsonism, vascular dementia has a stepwise course, and Creutzfeldt-Jakob disease is rapidly progressive with myoclonus, none of which matches this profile.
- A medical student studies the differential diagnosis of dementia. Which condition is a potentially reversible cause of cognitive impairment that should be excluded before diagnosing an irreversible dementia?
- Hypothyroidism
- Trisomy 21
- A CAG repeat expansion
- An APOE epsilon-4 allele
Correct answer: Hypothyroidism
Hypothyroidism is correct because it is a treatable cause of cognitive slowing and is routinely screened for, along with vitamin B12 deficiency and depression, before attributing symptoms to an irreversible dementia. Trisomy 21, a huntingtin CAG expansion, and an APOE epsilon-4 allele are genetic factors that are not reversible causes to be corrected, making them incorrect.
- A 75-year-old hospitalized woman develops acute, fluctuating confusion with inattention and an altered level of consciousness over hours after surgery, with disorganized thinking that waxes and wanes. Which feature best distinguishes delirium from dementia?
- Gradual onset over years
- Acute onset with impaired attention and a fluctuating course
- Stable, clear level of consciousness
- Absence of any reversible cause
Correct answer: Acute onset with impaired attention and a fluctuating course
Acute onset with impaired attention and a fluctuating course is correct because delirium develops rapidly with prominent inattention, altered consciousness, and fluctuation, typically from an identifiable medical cause, distinguishing it from the gradual, stable course of dementia. Gradual onset, a clear stable sensorium, and absence of a reversible cause describe dementia rather than delirium.
- A 45-year-old man with alcohol dependence presents acutely with confusion, ophthalmoplegia, and gait ataxia. Which treatment must be given urgently, before glucose, to address the underlying deficiency?
- Intravenous magnesium only
- Intravenous thiamine
- Oral folate
- Vitamin B12 injection
Correct answer: Intravenous thiamine
Intravenous thiamine is correct because Wernicke encephalopathy results from thiamine deficiency, and giving glucose first can precipitate or worsen it, so thiamine must be administered promptly to reverse the confusion, ophthalmoplegia, and ataxia. Magnesium, folate, and vitamin B12 do not treat the thiamine deficiency responsible for this triad.
- A 50-year-old man with alcohol use disorder stops drinking abruptly and, two to three days later, develops agitation, confusion, fever, tachycardia, tremor, and visual hallucinations. Which condition is this potentially fatal withdrawal state?
- Korsakoff syndrome
- Wernicke encephalopathy
- Delirium tremens
- Hepatic encephalopathy
Correct answer: Delirium tremens
Delirium tremens is correct because severe alcohol withdrawal peaking a few days after cessation produces autonomic hyperactivity, confusion, tremor, and hallucinations and can be fatal, treated with benzodiazepines. Wernicke encephalopathy is a thiamine-deficiency triad, Korsakoff syndrome is chronic amnesia, and hepatic encephalopathy stems from liver failure, none of which is this acute withdrawal emergency.
- A 24-year-old man brought to the emergency department after drug use is agitated, paranoid, and hyperthermic, with dilated pupils, hypertension, tachycardia, and chest pain. Intoxication with which class of substance best explains these findings?
- Opioids
- Cannabis
- Benzodiazepines
- Cocaine or other stimulants
Correct answer: Cocaine or other stimulants
Cocaine or other stimulants is correct because sympathomimetic intoxication produces agitation, paranoia, mydriasis, hypertension, tachycardia, hyperthermia, and chest pain from coronary vasospasm. Opioids and benzodiazepines cause sedation and miosis or normal pupils with respiratory depression, and cannabis causes conjunctival injection and increased appetite, none of which matches this sympathetic surge.
- A 30-year-old man who suddenly stops a high opioid dose develops dilated pupils, lacrimation, rhinorrhea, yawning, piloerection, abdominal cramping, and diarrhea, while remaining alert. Which condition do these findings represent?
- Opioid intoxication
- Alcohol withdrawal
- Cocaine intoxication
- Opioid withdrawal
Correct answer: Opioid withdrawal
Opioid withdrawal is correct because cessation of opioids produces an uncomfortable but not life-threatening syndrome of mydriasis, lacrimation, rhinorrhea, piloerection, cramping, and diarrhea with preserved consciousness. Opioid intoxication causes miosis and sedation, cocaine intoxication causes a stimulant picture, and alcohol withdrawal can cause seizures and delirium tremens, none of which is the flu-like opioid withdrawal described.
- A 16-year-old girl with severe anorexia nervosa is evaluated. Which physiologic complication is most directly caused by the chronic starvation and low body weight of this disorder?
- Polycythemia
- Hyperthyroidism with weight loss
- Amenorrhea from hypothalamic suppression
- Hypertension
Correct answer: Amenorrhea from hypothalamic suppression
Amenorrhea from hypothalamic suppression is correct because the energy deficit of anorexia nervosa suppresses hypothalamic gonadotropin-releasing hormone, lowering gonadotropins and estrogen and stopping menses, along with osteoporosis and bradycardia. Hyperthyroidism, polycythemia, and hypertension are not features of starvation, which instead causes a low metabolic state and hypotension, making them incorrect.
- A medical student studies operant conditioning schedules. Gambling on a slot machine, which pays out unpredictably after a variable number of plays, is most resistant to extinction because it follows which reinforcement schedule?
- Variable-ratio schedule
- Continuous reinforcement
- Fixed-ratio schedule
- Fixed-interval schedule
Correct answer: Variable-ratio schedule
Variable-ratio schedule is correct because reinforcement after an unpredictable number of responses, as in gambling, produces high steady response rates that are highly resistant to extinction. A fixed-interval schedule rewards the first response after a set time, continuous reinforcement rewards every response and extinguishes quickly, and a fixed-ratio schedule rewards a set number of responses, none of which best explains gambling persistence.
- A psychologist describes a patient who unconsciously attributes his own unacceptable hostile feelings to other people, accusing colleagues of being angry at him. Which ego defense mechanism does this best illustrate?
- Displacement
- Projection
- Rationalization
- Reaction formation
Correct answer: Projection
Projection is correct because attributing one's own unacceptable impulses or feelings to others, such as perceiving one's own hostility as coming from colleagues, defines this defense mechanism. Displacement redirects an impulse to a safer target, rationalization justifies behavior with acceptable reasons, and reaction formation expresses the opposite of an impulse, none of which is the externalizing pattern of projection.
- A patient with a serious chronic illness behaves as though the diagnosis simply is not true and refuses to discuss it or pursue treatment. Which immature defense mechanism does this represent?
- Intellectualization
- Sublimation
- Denial
- Suppression
Correct answer: Denial
Denial is correct because refusing to accept an external reality that is too threatening, such as not acknowledging a serious diagnosis, defines this defense mechanism. Sublimation channels impulses into productive activity, intellectualization focuses on abstract details to avoid emotion, and suppression is a conscious decision to set aside distress, none of which is the unconscious rejection of reality seen in denial.
- A 4-year-old boy has persistent deficits in social communication and reciprocity along with restricted, repetitive behaviors and insistence on sameness, present from early childhood. Which disorder best fits this presentation?
- Autism spectrum disorder
- Attention-deficit/hyperactivity disorder
- Oppositional defiant disorder
- Separation anxiety disorder
Correct answer: Autism spectrum disorder
Autism spectrum disorder is correct because persistent deficits in social communication and interaction together with restricted, repetitive patterns of behavior and interests beginning in early development define this disorder. Attention-deficit/hyperactivity disorder centers on inattention and hyperactivity, oppositional defiant disorder on defiance, and separation anxiety disorder on distress at separation, none of which is the social-communication and repetitive-behavior pattern of autism.
- A boy with intellectual disability has a long face with a prominent jaw, large ears, and enlarged testes after puberty, and genetic testing shows a CGG trinucleotide repeat expansion. Which disorder is most consistent with these findings?
- Fragile X syndrome
- Down syndrome
- Klinefelter syndrome
- Prader-Willi syndrome
Correct answer: Fragile X syndrome
Fragile X syndrome is correct because a CGG repeat expansion in the FMR1 gene causes the most common inherited intellectual disability, with a long face, large ears, prominent jaw, and macroorchidism. Down syndrome results from trisomy 21, Klinefelter syndrome from an extra X chromosome with small testes, and Prader-Willi from chromosome 15 imprinting with hyperphagia, none of which is this CGG-repeat disorder.
- A 7-year-old boy is described by his teacher as inattentive, easily distracted, fidgety, and unable to wait his turn in multiple settings, impairing his schoolwork. He is started on the most common first-line pharmacologic class for this condition. Which class is that?
- Antipsychotics
- Stimulants such as methylphenidate or amphetamine
- Benzodiazepines
- Mood stabilizers
Correct answer: Stimulants such as methylphenidate or amphetamine
Stimulants such as methylphenidate or amphetamine is correct because these agents increase synaptic dopamine and norepinephrine and are first-line treatment for attention-deficit/hyperactivity disorder, improving attention and reducing hyperactivity. Antipsychotics, benzodiazepines, and mood stabilizers are not first-line for this disorder, making them incorrect.
- A medical student studies neurotransmitter changes in psychiatric disease. The monoamine hypothesis attributes the symptoms of major depression most directly to a functional deficiency of which neurotransmitters?
- Glutamate and GABA
- Acetylcholine and histamine
- Serotonin and norepinephrine
- Glycine and substance P
Correct answer: Serotonin and norepinephrine
Serotonin and norepinephrine is correct because the monoamine hypothesis proposes that reduced activity of these monoamines (and dopamine) underlies depression, consistent with antidepressants that increase their availability. Glutamate and GABA balance excitation and inhibition, acetylcholine and histamine are not the central monoamines of this theory, and glycine and substance P are not the deficient transmitters, making them incorrect.
- A medical student studies the reward pathway implicated in addiction. The reinforcing, rewarding effects of most drugs of abuse converge on increased dopamine in which pathway?
- The dorsal column pathway
- The nigrostriatal pathway
- The tuberoinfundibular pathway
- The mesolimbic pathway from the ventral tegmental area to the nucleus accumbens
Correct answer: The mesolimbic pathway from the ventral tegmental area to the nucleus accumbens
The mesolimbic pathway from the ventral tegmental area to the nucleus accumbens is correct because most addictive drugs increase dopamine release in this reward circuit, reinforcing drug-seeking behavior. The nigrostriatal pathway governs movement, the tuberoinfundibular pathway regulates prolactin, and the dorsal column pathway is sensory, none of which is the reward pathway central to addiction.
- A medical student studies neurotransmitter localization. Degeneration of dopaminergic neurons in Parkinson disease occurs primarily in which midbrain structure that projects to the striatum?
- The locus coeruleus
- The substantia nigra pars compacta
- The raphe nuclei
- The nucleus basalis of Meynert
Correct answer: The substantia nigra pars compacta
The substantia nigra pars compacta is correct because this midbrain nucleus contains the dopaminergic neurons that project to the striatum and degenerate in Parkinson disease, producing depigmentation of the nigra. The locus coeruleus is noradrenergic, the raphe nuclei are serotonergic, and the nucleus basalis is cholinergic, none of which is the principal dopaminergic source lost in Parkinson disease.
- A medical student studies the source of central serotonin. Serotonergic projections that modulate mood, sleep, and pain throughout the brain arise predominantly from neurons in which brainstem location?
- The substantia nigra
- The raphe nuclei
- The locus coeruleus
- The red nucleus
Correct answer: The raphe nuclei
The raphe nuclei is correct because these midline brainstem nuclei are the principal source of serotonin, projecting widely to influence mood, sleep, appetite, and pain modulation, and are relevant to antidepressant action. The substantia nigra is dopaminergic, the locus coeruleus is noradrenergic, and the red nucleus is a motor relay, none of which is the serotonergic source described.
- A medical student studies the principal noradrenergic nucleus of the brain. Most central norepinephrine, involved in arousal and the stress response, originates from neurons in which structure?
- The locus coeruleus
- The raphe nuclei
- The nucleus basalis of Meynert
- The subthalamic nucleus
Correct answer: The locus coeruleus
The locus coeruleus is correct because this pontine nucleus is the major source of central norepinephrine, with broad projections governing arousal, attention, and the stress response. The raphe nuclei are serotonergic, the nucleus basalis is cholinergic, and the subthalamic nucleus is part of basal ganglia motor circuitry, none of which is the principal noradrenergic nucleus.
- A 25-year-old patient sustains a complete spinal cord injury at the cervical level and initially has flaccid paralysis, areflexia, and loss of all sensation and reflexes below the lesion. This transient period of depressed reflex activity immediately after the injury is known as which phenomenon?
- Neurogenic shock
- Spinal shock
- Autonomic dysreflexia
- Brown-Sequard syndrome
Correct answer: Spinal shock
Spinal shock is correct because acute severe spinal cord injury causes a temporary loss of reflex activity below the lesion with flaccidity and areflexia, which later gives way to spasticity and hyperreflexia. Neurogenic shock is a hemodynamic state of hypotension and bradycardia, autonomic dysreflexia is a later hypertensive crisis, and Brown-Sequard syndrome is a hemisection pattern, none of which is this initial areflexic period.
- A patient with a chronic high spinal cord injury develops a sudden severe headache, dangerous hypertension, sweating above the lesion, and bradycardia after bladder distension. Which condition does this represent?
- Spinal shock
- Neurogenic bladder only
- Orthostatic hypotension
- Autonomic dysreflexia
Correct answer: Autonomic dysreflexia
Autonomic dysreflexia is correct because in patients with high cord lesions a noxious stimulus below the injury, such as a distended bladder, triggers unopposed sympathetic discharge causing severe hypertension, with reflex bradycardia and flushing above the lesion, a medical emergency. Spinal shock is the acute areflexic phase, orthostatic hypotension is low pressure on standing, and a neurogenic bladder alone does not cause this crisis.
- A medical student studies central sensory processing. Almost all ascending sensory pathways, except olfaction, relay through which structure before reaching the cerebral cortex?
- The hypothalamus
- The basal ganglia
- The cerebellum
- The thalamus
Correct answer: The thalamus
The thalamus is correct because it serves as the major relay station for sensory information, processing and projecting input to the cortex, with olfaction being the notable exception that bypasses it. The hypothalamus regulates homeostasis, the cerebellum coordinates movement, and the basal ganglia modulate motor activity, none of which is the principal sensory relay to the cortex.
- A patient with a small stroke in the ventral posterolateral nucleus of the thalamus develops complete loss of all sensation on the opposite side of the body, later followed by severe spontaneous burning pain in the numb region. This delayed pain syndrome is best described as which condition?
- Trigeminal neuralgia
- Complex regional pain syndrome
- Thalamic (central post-stroke) pain
- Phantom limb pain
Correct answer: Thalamic (central post-stroke) pain
Thalamic (central post-stroke) pain is correct because a lesion of the sensory thalamus can cause contralateral sensory loss followed weeks later by intractable spontaneous pain in the affected area, a central pain syndrome. Complex regional pain syndrome follows limb injury, trigeminal neuralgia is paroxysmal facial pain, and phantom limb pain follows amputation, none of which is this thalamic central pain.
- A 60-year-old man with a longstanding seizure focus has complex partial seizures with impaired awareness, lip-smacking automatisms, and a rising epigastric sensation preceding the events. These features most often localize the seizure focus to which lobe?
- The temporal lobe
- The occipital lobe
- The parietal lobe
- The frontal lobe
Correct answer: The temporal lobe
The temporal lobe is correct because focal seizures with impaired awareness, oroalimentary automatisms such as lip-smacking, and a rising epigastric aura are classic for a temporal lobe (often mesial) origin, the most common site of focal epilepsy. The occipital lobe causes visual phenomena, the parietal lobe causes sensory symptoms, and the frontal lobe causes motor or hypermotor seizures, none of which matches this temporal semiology.
- A 6-year-old child has frequent brief staring spells lasting seconds with no postictal confusion, during which the electroencephalogram shows generalized 3-Hz spike-and-wave discharges, often provoked by hyperventilation. Which seizure type is this?
- Tonic-clonic seizures
- Focal seizures with impaired awareness
- Absence (petit mal) seizures
- Myoclonic seizures
Correct answer: Absence (petit mal) seizures
Absence (petit mal) seizures is correct because brief staring spells without postictal confusion, with generalized 3-Hz spike-and-wave activity provoked by hyperventilation in a child, define absence epilepsy. Focal seizures with impaired awareness have automatisms and postictal confusion, tonic-clonic seizures involve convulsions, and myoclonic seizures are brief jerks, none of which is this 3-Hz absence pattern.
- A medical student studies the visual pathway beyond the optic tract. After synapsing in the lateral geniculate nucleus, visual information travels via the optic radiations to which cortical region for processing?
- The primary auditory cortex of the temporal lobe
- The primary visual cortex of the occipital lobe
- The primary somatosensory cortex of the parietal lobe
- The primary motor cortex of the frontal lobe
Correct answer: The primary visual cortex of the occipital lobe
The primary visual cortex of the occipital lobe is correct because the optic radiations carry visual signals from the lateral geniculate nucleus to the calcarine (primary visual) cortex in the occipital lobe. The auditory cortex processes sound, the somatosensory cortex processes touch, and the motor cortex controls movement, none of which is the destination of the visual pathway.
- A 65-year-old man has a stroke producing a left homonymous hemianopia with macular sparing. A lesion in which artery's territory, supplying the occipital cortex, best explains this defect?
- The left posterior communicating artery
- The left middle cerebral artery
- The right anterior cerebral artery
- The right posterior cerebral artery
Correct answer: The right posterior cerebral artery
The right posterior cerebral artery is correct because it supplies the right occipital visual cortex, so its occlusion causes a left homonymous hemianopia, often with macular sparing due to collateral supply to the occipital pole. The middle cerebral artery causes cortical face-arm deficits, the anterior cerebral artery affects the medial leg area, and the posterior communicating artery relates to third nerve compression, none of which produces this occipital field defect.
- A 70-year-old woman with a left middle cerebral artery stroke has right-sided weakness affecting the face and arm more than the leg, with aphasia. This pattern reflects the somatotopic organization of which structure supplied by the middle cerebral artery?
- The cerebellar cortex
- The medial motor cortex (leg region)
- The lateral motor cortex (face and arm region)
- The dorsal columns
Correct answer: The lateral motor cortex (face and arm region)
The lateral motor cortex (face and arm region) is correct because the middle cerebral artery supplies the lateral convexity where the face and arm are represented, so its occlusion causes contralateral face and arm weakness more than leg, plus aphasia if the dominant hemisphere is involved. The medial leg area is supplied by the anterior cerebral artery, and the cerebellar cortex and dorsal columns are not in the middle cerebral artery territory.
- A 24-year-old woman presents with the sudden onset of the worst headache of her life, described as a thunderclap, with neck stiffness and photophobia, and noncontrast imaging shows blood in the subarachnoid space. Rupture of which lesion is the most common cause of this nontraumatic hemorrhage?
- The middle meningeal artery
- A bridging vein
- A saccular (berry) aneurysm
- A hypertensive penetrating arteriole
Correct answer: A saccular (berry) aneurysm
A saccular (berry) aneurysm is correct because rupture of these aneurysms, often at the circle of Willis junctions, is the leading cause of nontraumatic subarachnoid hemorrhage with a thunderclap headache and meningismus. Bridging vein tears cause subdural hematomas, middle meningeal artery rupture causes epidural hematomas, and hypertensive arteriolar rupture causes intraparenchymal hemorrhage, none of which typically causes subarachnoid hemorrhage.
- A patient recovering from a subarachnoid hemorrhage develops new focal neurologic deficits several days later due to delayed cerebral vasospasm. Which calcium channel blocker is given to reduce this complication?
- Diltiazem
- Verapamil
- Nimodipine
- Amlodipine
Correct answer: Nimodipine
Nimodipine is correct because this dihydropyridine calcium channel blocker preferentially affects cerebral vessels and improves neurologic outcomes by reducing the effects of vasospasm after subarachnoid hemorrhage. Verapamil and diltiazem act more on the heart, and amlodipine is used for systemic hypertension, none of which is the agent specifically indicated to limit cerebral vasospasm.
- A 50-year-old man with poorly controlled hypertension suddenly collapses with a severe headache, vomiting, and dense hemiparesis, and imaging shows bleeding deep within the brain at the basal ganglia. This hypertensive intraparenchymal hemorrhage most often results from rupture of small vessels weakened by which process?
- Charcot-Bouchard microaneurysm formation
- Bridging vein tears
- Berry aneurysm rupture
- Septic embolization
Correct answer: Charcot-Bouchard microaneurysm formation
Charcot-Bouchard microaneurysm formation is correct because chronic hypertension produces these tiny aneurysms on small penetrating arteries supplying deep structures such as the basal ganglia, and their rupture causes hypertensive intracerebral hemorrhage. Bridging vein tears cause subdural bleeds, berry aneurysm rupture causes subarachnoid hemorrhage, and septic emboli relate to endocarditis, none of which is the deep hypertensive bleed mechanism.
- A neonate develops fever, poor feeding, and a bulging fontanelle, and bacterial meningitis is suspected. Which organisms are the most common causes of bacterial meningitis in this neonatal age group?
- Neisseria meningitidis and Streptococcus pneumoniae
- Group B Streptococcus and Escherichia coli
- Haemophilus influenzae type b only
- Listeria monocytogenes and Cryptococcus only
Correct answer: Group B Streptococcus and Escherichia coli
Group B Streptococcus and Escherichia coli is correct because these organisms, often acquired around birth, along with Listeria, are the leading causes of neonatal bacterial meningitis. Neisseria meningitidis and Streptococcus pneumoniae predominate later in childhood and adulthood, Haemophilus influenzae type b has declined with vaccination, and the Listeria-Cryptococcus pairing does not describe the typical neonatal causes.
- A 65-year-old man recovering from bacterial meningitis is treated with adjunctive dexamethasone. The main rationale for giving corticosteroids in bacterial meningitis is to reduce which complication?
- The need for any antibiotics
- Inflammation-related neurologic sequelae such as hearing loss
- Bleeding from the meninges
- Future seizures from a structural scar
Correct answer: Inflammation-related neurologic sequelae such as hearing loss
Inflammation-related neurologic sequelae such as hearing loss is correct because dexamethasone dampens the inflammatory response to bacterial lysis, reducing neurologic complications including sensorineural hearing loss, particularly in pneumococcal meningitis. It does not replace antibiotics, address meningeal bleeding, or primarily prevent scar-related seizures, making those options incorrect.
- A 65-year-old man with a unilateral resting tremor and bradykinesia improves substantially when started on a dopamine agonist that directly stimulates striatal dopamine receptors. Which drug is a dopamine agonist used in Parkinson disease?
- Pramipexole
- Carbidopa
- Donepezil
- Benztropine
Correct answer: Pramipexole
Pramipexole is correct because it directly stimulates dopamine receptors in the striatum, providing symptomatic benefit in Parkinson disease and sometimes used to delay levodopa, though it can cause impulse control disorders. Carbidopa blocks peripheral levodopa breakdown, donepezil treats Alzheimer disease, and benztropine is an anticholinergic for tremor, none of which is a direct dopamine agonist.
- A 22-year-old man develops drug-induced acute dystonia with a sustained twisting neck spasm hours after his first dose of an antipsychotic. Which medication rapidly relieves this acute dystonic reaction?
- A loop diuretic
- An anticholinergic such as benztropine or diphenhydramine
- Additional antipsychotic
- A beta-blocker
Correct answer: An anticholinergic such as benztropine or diphenhydramine
An anticholinergic such as benztropine or diphenhydramine is correct because acute dystonia from dopamine blockade is treated by restoring the dopamine-acetylcholine balance with an anticholinergic agent, which quickly relieves the muscle spasm. A loop diuretic and beta-blocker do not address the dystonia, and more antipsychotic would worsen it, making them incorrect.
- A medical student studies the inner ear's role in balance. Rotational (angular) acceleration of the head, such as spinning, is detected primarily by which structures of the vestibular apparatus?
- The cochlea
- The semicircular canals
- The utricle and saccule only
- The round window
Correct answer: The semicircular canals
The semicircular canals is correct because their fluid-filled loops, oriented in three planes, detect angular (rotational) acceleration of the head via deflection of the cupula. The cochlea detects sound, the utricle and saccule sense linear acceleration and gravity, and the round window is a membrane for pressure relief, none of which detects rotational acceleration.
- A 45-year-old woman has recurrent episodes of vertigo lasting hours accompanied by fluctuating low-frequency hearing loss, tinnitus, and a sensation of ear fullness, attributed to excess endolymph. Which inner ear disorder is most consistent with these findings?
- Vestibular neuritis
- Benign paroxysmal positional vertigo
- Meniere disease
- Otosclerosis
Correct answer: Meniere disease
Meniere disease is correct because episodic vertigo lasting hours with fluctuating sensorineural hearing loss, tinnitus, and aural fullness reflects endolymphatic hydrops in this disorder. Benign paroxysmal positional vertigo causes brief positional spells without hearing loss, vestibular neuritis causes sustained vertigo without auditory symptoms, and otosclerosis causes conductive hearing loss, none of which matches this triad.
- A medical student performs a Rinne test on a patient, comparing air and bone conduction with a tuning fork. In a normal ear, the Rinne test shows which result?
- Air conduction is heard longer than bone conduction
- Bone conduction is heard longer than air conduction
- Both are heard equally only in conductive loss
- Neither is heard in sensorineural loss
Correct answer: Air conduction is heard longer than bone conduction
Air conduction is heard longer than bone conduction is correct because in a normal ear, and in sensorineural hearing loss, air conduction exceeds bone conduction (a positive Rinne test). Bone conduction exceeding air conduction (a negative Rinne) indicates conductive hearing loss, so the other options misstate the normal and pathologic Rinne findings.
- A 65-year-old man has gradual, bilateral, symmetric high-frequency hearing loss and difficulty understanding speech in noisy settings, attributed to age-related degeneration of cochlear hair cells. Which condition does this represent?
- Meniere disease
- Otosclerosis
- Cerumen impaction
- Presbycusis
Correct answer: Presbycusis
Presbycusis is correct because age-related sensorineural hearing loss characteristically affects high frequencies bilaterally with impaired speech discrimination in noise, due to loss of cochlear hair cells at the high-frequency base. Otosclerosis and cerumen impaction cause conductive loss, and Meniere disease causes episodic low-frequency loss with vertigo, none of which is the symmetric age-related high-frequency loss described.
- A medical student studies the muscles of facial expression. A lesion of the facial nerve (cranial nerve VII) causing a peripheral (lower motor neuron) palsy produces weakness affecting which part of the face?
- The muscles of mastication
- Only the lower ipsilateral face, sparing the forehead
- Only the contralateral lower face
- The entire ipsilateral half of the face, including the forehead
Correct answer: The entire ipsilateral half of the face, including the forehead
The entire ipsilateral half of the face, including the forehead is correct because a peripheral facial nerve lesion (as in Bell palsy) weakens all facial muscles on the same side, including the forehead, since the lower motor neuron carries all the fibers. A central lesion spares the forehead because of bilateral cortical input to the upper face, and the muscles of mastication are supplied by the trigeminal nerve, making the other options incorrect.
- A 40-year-old man develops acute unilateral facial droop affecting the forehead, inability to close the eye, and loss of taste on the anterior tongue, with no other neurologic deficits. Which condition is most consistent with this idiopathic peripheral facial palsy?
- Bell palsy
- A cortical stroke
- Trigeminal neuralgia
- Myasthenia gravis
Correct answer: Bell palsy
Bell palsy is correct because acute idiopathic peripheral facial nerve palsy causes unilateral weakness of the whole half of the face including the forehead, often with impaired taste and eye closure, frequently treated with corticosteroids. A cortical stroke spares the forehead, trigeminal neuralgia causes facial pain not weakness, and myasthenia gravis causes fatigable weakness without forehead-specific palsy, none of which fits this presentation.
- A medical student studies the gross structure of the brain. The primary somatosensory cortex, which receives touch and proprioceptive information, is located in which gyrus?
- The precentral gyrus
- The superior temporal gyrus
- The postcentral gyrus
- The cingulate gyrus
Correct answer: The postcentral gyrus
The postcentral gyrus is correct because this gyrus of the parietal lobe contains the primary somatosensory cortex, organized as a sensory homunculus that receives touch, pressure, and proprioceptive input. The precentral gyrus is the primary motor cortex, the superior temporal gyrus contains auditory cortex, and the cingulate gyrus is part of the limbic system, none of which is the primary somatosensory area.
- A patient with damage to the dominant inferior parietal lobule develops a combination of finger agnosia, left-right disorientation, agraphia, and acalculia. This tetrad is known as which syndrome?
- Gerstmann syndrome
- Wernicke aphasia
- Kluver-Bucy syndrome
- Frontal lobe syndrome
Correct answer: Gerstmann syndrome
Gerstmann syndrome is correct because damage to the dominant angular gyrus region produces the tetrad of finger agnosia, left-right confusion, agraphia, and acalculia. Wernicke aphasia is a fluent receptive aphasia, Kluver-Bucy syndrome follows bilateral temporal lobe damage with hyperorality and placidity, and frontal lobe syndrome involves personality and executive change, none of which is this parietal tetrad.
- A patient with bilateral destruction of the medial temporal lobes, including the amygdalae, develops hyperorality, hypersexuality, placidity, and a tendency to examine objects with the mouth. This behavioral syndrome is known as which condition?
- Gerstmann syndrome
- Korsakoff syndrome
- Kluver-Bucy syndrome
- Locked-in syndrome
Correct answer: Kluver-Bucy syndrome
Kluver-Bucy syndrome is correct because bilateral amygdala and medial temporal damage produces hyperorality, hypersexuality, placidity with loss of fear, and visual or oral exploration of objects. Korsakoff syndrome is an amnestic disorder, Gerstmann syndrome is a parietal tetrad, and locked-in syndrome is a pontine lesion with preserved awareness but quadriplegia, none of which is this temporal-amygdala behavioral syndrome.
- A patient with a ventral pontine lesion is fully conscious but completely paralyzed except for vertical eye movements and blinking, with which he can communicate. This condition is best described as which syndrome?
- Coma
- Persistent vegetative state
- Brain death
- Locked-in syndrome
Correct answer: Locked-in syndrome
Locked-in syndrome is correct because a lesion of the ventral pons interrupts descending motor pathways while sparing the reticular activating system and the midbrain control of vertical gaze, leaving the patient awake and aware but able to move only the eyes. A persistent vegetative state lacks awareness, brain death is irreversible loss of all brain function, and coma is unarousable unresponsiveness, none of which preserves awareness with vertical eye movement.
- A medical student studies arousal and consciousness. Maintenance of wakefulness and arousal depends most directly on which structure projecting diffusely to the cortex?
- The cerebellum
- The reticular activating system of the brainstem
- The basal ganglia
- The dorsal columns
Correct answer: The reticular activating system of the brainstem
The reticular activating system of the brainstem is correct because this network in the brainstem tegmentum projects widely to the thalamus and cortex to maintain arousal and wakefulness, and its damage produces coma. The cerebellum coordinates movement, the basal ganglia modulate motor activity, and the dorsal columns carry sensation, none of which is the principal arousal system.
- A medical student studies hypothalamic control of the circadian rhythm. The body's master circadian clock, which entrains sleep-wake cycles to the light-dark cycle, resides in which hypothalamic structure?
- The supraoptic nucleus
- The suprachiasmatic nucleus
- The arcuate nucleus
- The mammillary bodies
Correct answer: The suprachiasmatic nucleus
The suprachiasmatic nucleus is correct because this hypothalamic nucleus receives retinal input and serves as the master circadian pacemaker, regulating the sleep-wake cycle and influencing melatonin release. The supraoptic nucleus makes antidiuretic hormone, the arcuate nucleus regulates appetite and hormones, and the mammillary bodies relate to memory, none of which is the circadian clock.
- A medical student studies sleep neurochemistry. Secretion of melatonin, which promotes sleep onset and signals darkness, is produced by which structure?
- The pineal gland
- The anterior pituitary
- The adrenal medulla
- The thyroid gland
Correct answer: The pineal gland
The pineal gland is correct because it synthesizes and secretes melatonin in response to darkness, under control of the suprachiasmatic nucleus, helping to regulate the sleep-wake cycle. The anterior pituitary secretes trophic hormones, the adrenal medulla secretes catecholamines, and the thyroid secretes thyroid hormone, none of which produces melatonin.
- A 45-year-old obese man snores loudly and has witnessed episodes of stopping breathing during sleep, with daytime sleepiness and morning headaches. Which condition is most consistent with these findings?
- REM sleep behavior disorder
- Narcolepsy
- Restless legs syndrome
- Obstructive sleep apnea
Correct answer: Obstructive sleep apnea
Obstructive sleep apnea is correct because repetitive upper airway collapse during sleep causes apneic pauses, loud snoring, fragmented sleep, daytime sleepiness, and morning headaches, often in obese patients and treated with continuous positive airway pressure. Narcolepsy features cataplexy and sleep attacks, restless legs syndrome causes an urge to move the legs, and REM sleep behavior disorder involves acting out dreams, none of which matches this apneic picture.
- A medical student studies neurotransmitter synthesis. Tyrosine hydroxylase catalyzes the rate-limiting step in the synthesis of which group of neurotransmitters?
- GABA
- Serotonin
- Acetylcholine
- Catecholamines such as dopamine and norepinephrine
Correct answer: Catecholamines such as dopamine and norepinephrine
Catecholamines such as dopamine and norepinephrine is correct because tyrosine hydroxylase converts tyrosine to L-DOPA, the rate-limiting step in catecholamine synthesis leading to dopamine, norepinephrine, and epinephrine. Serotonin is made from tryptophan via tryptophan hydroxylase, acetylcholine from choline and acetyl-CoA, and GABA from glutamate, none of which uses tyrosine hydroxylase.
- A medical student studies brain energy metabolism. Under normal conditions, the brain relies almost exclusively on which substrate as its primary energy source?
- Lactate exclusively
- Free fatty acids
- Ketone bodies as the primary fuel at all times
- Glucose
Correct answer: Glucose
Glucose is correct because the brain normally depends almost entirely on glucose for energy and is highly sensitive to hypoglycemia, although it can adapt to use ketone bodies during prolonged starvation. Free fatty acids do not readily cross the blood-brain barrier, ketones are a backup rather than the normal primary fuel, and lactate is not the exclusive substrate, making the other options incorrect.
- A medical student studies cerebral blood flow regulation. Under normal physiologic conditions, cerebral blood flow is most potently increased by a rise in which factor?
- Blood glucose
- Arterial oxygen tension
- Arterial carbon dioxide tension (PaCO2)
- Serum sodium
Correct answer: Arterial carbon dioxide tension (PaCO2)
Arterial carbon dioxide tension (PaCO2) is correct because a rise in carbon dioxide is a powerful cerebral vasodilator that increases cerebral blood flow, which is why hyperventilation lowering carbon dioxide is used to reduce intracranial pressure. Oxygen tension has a weaker effect except at low levels, and blood glucose and serum sodium are not the primary regulators of cerebral blood flow.
- A 67-year-old man reports right hip pain that builds over the course of the day with prolonged walking and eases when he sits to rest. He has no fever, and the joint is not warm. Stiffness on first standing in the morning resolves within about ten minutes. Which underlying tissue change best explains his symptoms?
- Progressive loss of articular cartilage with reactive bony change
- Autoantibody-mediated synovial inflammation
- Deposition of immune complexes in the joint capsule
- Bacterial seeding of the synovial space
Correct answer: Progressive loss of articular cartilage with reactive bony change
Progressive loss of articular cartilage with reactive bony change is correct because osteoarthritis is a degenerative joint disease in which mechanical wear erodes cartilage, the underlying bone responds with sclerosis and osteophytes, and pain therefore worsens with use and improves with rest with only brief morning stiffness. Autoantibody-mediated synovitis describes rheumatoid arthritis, immune-complex deposition describes lupus arthropathy, and bacterial seeding describes septic arthritis, none of which produces this load-dependent degenerative pattern.
- A 58-year-old woman with osteoarthritis is examined. Which physical finding involving the distal interphalangeal joints is most characteristic of her degenerative joint disease?
- Boutonniere deformity
- Heberden nodes
- Ulnar deviation of the fingers
- Swan-neck deformity
Correct answer: Heberden nodes
Heberden nodes are correct because bony enlargements of the distal interphalangeal joints are a hallmark of osteoarthritis, reflecting osteophyte formation from cartilage loss. Ulnar deviation, swan-neck deformity, and boutonniere deformity are all deformities of rheumatoid arthritis, which characteristically spares the distal interphalangeal joints, so none of those fits the degenerative process.
- A 48-year-old woman with rheumatoid arthritis is most likely to have which pattern of joint involvement?
- Asymmetric involvement of a single large weight-bearing joint
- Symmetric involvement of the wrists and metacarpophalangeal joints
- Isolated involvement of the distal interphalangeal joints
- Migratory involvement of the great toe
Correct answer: Symmetric involvement of the wrists and metacarpophalangeal joints
Symmetric involvement of the wrists and metacarpophalangeal joints is correct because rheumatoid arthritis is a systemic autoimmune synovitis that classically affects the small joints of the hands and wrists in a symmetric distribution while sparing the distal interphalangeal joints. Isolated distal interphalangeal disease and asymmetric single large-joint disease are typical of osteoarthritis, and migratory great-toe involvement suggests crystal arthropathy, so none of those matches the rheumatoid pattern.
- A rheumatologist orders laboratory testing for a 50-year-old woman with several months of symmetric small-joint swelling and prolonged morning stiffness. Which laboratory abnormality is most consistent with the systemic inflammatory nature of rheumatoid arthritis rather than osteoarthritis?
- Elevated serum uric acid
- Elevated C-reactive protein and erythrocyte sedimentation rate
- Elevated serum creatine kinase
- Low serum calcium
Correct answer: Elevated C-reactive protein and erythrocyte sedimentation rate
Elevated C-reactive protein and erythrocyte sedimentation rate is correct because rheumatoid arthritis is a systemic inflammatory disease that raises acute-phase reactants, whereas osteoarthritis is degenerative and typically leaves these markers normal. Elevated uric acid points to gout, elevated creatine kinase points to muscle injury or inflammatory myopathy, and low calcium points to metabolic bone or parathyroid disease, none of which reflects rheumatoid inflammation.
- A 54-year-old man wakes with sudden, severe pain and swelling of the base of the great toe. He recently increased his beer intake and takes a thiazide diuretic. The acute inflammation in gout is triggered by which event?
- Cartilage breakdown releasing matrix fragments
- IgE-mediated mast cell degranulation in the joint
- Autoantibodies binding citrullinated synovial proteins
- Monosodium urate crystals engulfed by neutrophils, activating the inflammasome
Correct answer: Monosodium urate crystals engulfed by neutrophils, activating the inflammasome
Monosodium urate crystals engulfed by neutrophils, activating the inflammasome is correct because gout flares occur when precipitated urate crystals are phagocytosed, activating the NLRP3 inflammasome and driving interleukin-1-mediated acute joint inflammation. IgE-mediated degranulation underlies allergic reactions, anti-citrullinated antibodies drive rheumatoid arthritis, and cartilage matrix breakdown reflects osteoarthritis, none of which causes the crystal-induced flare of gout.
- A 60-year-old man with recurrent gout asks why his attacks often begin in the great toe rather than larger joints. Which factor best explains the predilection of urate crystals for the first metatarsophalangeal joint?
- Higher synovial glucose concentration in distal joints
- Greater immune-complex deposition in small joints
- Lower temperature in distal extremities promoting urate precipitation
- Increased blood flow to the toes
Correct answer: Lower temperature in distal extremities promoting urate precipitation
Lower temperature in distal extremities promoting urate precipitation is correct because urate is less soluble at cooler temperatures, so the relatively cool first metatarsophalangeal joint favors crystal formation, a classic site called podagra. Increased toe blood flow and higher synovial glucose are not mechanisms of crystal precipitation, and immune-complex deposition describes lupus rather than crystal-driven gout.
- A 62-year-old man with chronic gout has a serum uric acid that remains elevated despite dietary changes. Which dietary or metabolic source contributes most directly to his urate burden?
- Dietary fiber intake
- Purine-rich foods and alcohol increasing urate generation
- Vitamin C supplementation
- High dietary calcium
Correct answer: Purine-rich foods and alcohol increasing urate generation
Purine-rich foods and alcohol increasing urate generation is correct because purine catabolism yields uric acid, so organ meats, shellfish, and especially alcohol raise the urate pool and precipitate gout, with alcohol also impairing renal urate excretion. Vitamin C tends to lower urate, dietary fiber and calcium do not drive urate production, so none of those increases the gout burden.
- A patient with frequent gout flares is to begin a urate-lowering xanthine oxidase inhibitor. To avoid a serious metabolite-related adverse effect, which agent acts as a selective, non-purine xanthine oxidase inhibitor often chosen in patients intolerant of allopurinol?
- Rasburicase
- Probenecid
- Colchicine
- Febuxostat
Correct answer: Febuxostat
Febuxostat is correct because it is a non-purine selective xanthine oxidase inhibitor that lowers urate production and is an alternative for patients who cannot tolerate allopurinol. Probenecid is a uricosuric that increases excretion rather than blocking production, colchicine treats the acute inflammatory flare without lowering urate, and rasburicase is a recombinant uricase used for tumor lysis rather than chronic gout, so none of those is the xanthine oxidase inhibitor described.
- A 70-year-old woman with osteoporosis undergoes dual-energy x-ray absorptiometry. According to current diagnostic standards, osteoporosis is defined by a bone mineral density T-score at or below which threshold?
Correct answer: -2.5
-2.5 is correct because osteoporosis is defined as a bone mineral density T-score of -2.5 or lower, meaning bone density is 2.5 standard deviations or more below the young-adult mean. A T-score between -1.0 and -2.5 defines osteopenia, while scores of 0 or -0.5 are within the normal range, so none of those thresholds defines osteoporosis.
- A 72-year-old woman with severe osteoporosis is started on teriparatide rather than a bisphosphonate. Teriparatide, a recombinant parathyroid hormone analog, builds bone through which mechanism when given intermittently?
- Inhibiting osteoclast resorption by binding hydroxyapatite
- Blocking RANK ligand to prevent osteoclast formation
- Anabolic stimulation of osteoblast activity and new bone formation
- Replacing estrogen at bone receptors
Correct answer: Anabolic stimulation of osteoblast activity and new bone formation
Anabolic stimulation of osteoblast activity and new bone formation is correct because intermittent parathyroid hormone analog dosing favors osteoblast-driven bone building, making teriparatide an anabolic agent rather than an antiresorptive one. Binding hydroxyapatite to inhibit osteoclasts describes bisphosphonates, blocking RANK ligand describes denosumab, and replacing estrogen describes hormone therapy, none of which is the anabolic teriparatide mechanism.
- A postmenopausal woman with osteoporosis is prescribed denosumab. This monoclonal antibody reduces bone resorption by neutralizing which target?
- Sclerostin
- RANK ligand
- Tumor necrosis factor alpha
- Interleukin-6
Correct answer: RANK ligand
RANK ligand is correct because denosumab is a monoclonal antibody against RANK ligand, the signal osteoblasts use to drive osteoclast formation and activity, so blocking it reduces resorption and increases bone density. Sclerostin is the target of a different anabolic antibody, while tumor necrosis factor alpha and interleukin-6 are inflammatory cytokine targets in rheumatologic disease rather than the resorption signal denosumab blocks.
- A clinician counsels a 30-year-old woman on lifelong osteoporosis prevention. Which strategy most effectively maximizes peak bone mass and reduces future fracture risk?
- Maintaining a very low body weight
- Avoiding all weight-bearing activity to protect joints
- Daily high-dose glucocorticoids
- Adequate calcium, vitamin D, and regular weight-bearing exercise
Correct answer: Adequate calcium, vitamin D, and regular weight-bearing exercise
Adequate calcium, vitamin D, and regular weight-bearing exercise is correct because building and preserving bone requires sufficient mineral substrate, vitamin D for calcium absorption, and mechanical loading that stimulates osteoblastic bone formation. Glucocorticoids and very low body weight accelerate bone loss, and avoiding weight-bearing activity removes the mechanical stimulus bone needs, so none of those prevents osteoporosis.
- A 38-year-old man asks his dermatologist what the letter D in the melanoma ABCDE rule signifies. The D refers to which feature?
- Drainage from the lesion
- Depth of dermal invasion
- Diameter greater than 6 millimeters
- Density of pigment
Correct answer: Diameter greater than 6 millimeters
Diameter greater than 6 millimeters is correct because in the ABCDE screening mnemonic D stands for diameter, with lesions larger than about 6 millimeters (roughly a pencil eraser) raising concern for melanoma. Depth of invasion is the histologic Breslow measurement used for prognosis, not part of ABCDE, while drainage and pigment density are not represented by the letter D.
- A 45-year-old woman has a dark lesion that is uneven so that one half does not match the other, with a notched edge and several shades of brown and black. Which two ABCDE features are exhibited?
- Diameter and Evolution
- Border regularity and symmetry
- Color variation and Elevation only
- Asymmetry and Border irregularity, along with Color variation
Correct answer: Asymmetry and Border irregularity, along with Color variation
Asymmetry and Border irregularity, along with Color variation is correct because a lesion whose halves do not match shows asymmetry (A), a notched ragged edge shows border irregularity (B), and multiple shades show color variegation (C), all melanoma warning signs. Diameter and evolution describe size and change over time rather than these described features, elevation is not an ABCDE letter, and border regularity with symmetry would be reassuring rather than concerning.
- A pathologist evaluating a suspected melanoma notes the tumor has progressed from spreading laterally within the epidermis to growing downward into the dermis. This transition to a vertical growth phase is clinically significant because it primarily increases the risk of which event?
- Spontaneous regression
- Metastasis through dermal lymphatics and vessels
- Conversion to a benign nevus
- Loss of pigmentation
Correct answer: Metastasis through dermal lymphatics and vessels
Metastasis through dermal lymphatics and vessels is correct because once melanoma enters a vertical growth phase and invades the dermis it gains access to lymphatics and blood vessels, sharply raising metastatic potential, which is why Breslow depth predicts prognosis. Vertical growth does not cause conversion to a benign nevus, spontaneous regression, or loss of pigmentation, so none of those reflects the danger of dermal invasion.
- A 32-year-old man has sharply demarcated red plaques with thick silvery-white scale on his elbows, knees, and scalp. Which immune pathway is the principal driver of the keratinocyte hyperproliferation in psoriasis?
- The IL-23 and Th17 axis with IL-17 release
- IgE-mediated mast cell activation
- Complement-mediated lysis of keratinocytes
- CD8 cytotoxic destruction of melanocytes
Correct answer: The IL-23 and Th17 axis with IL-17 release
The IL-23 and Th17 axis with IL-17 release is correct because psoriasis is driven by dendritic cell IL-23 stimulating Th17 cells to secrete IL-17, which fuels the rapid keratinocyte turnover producing scaly plaques. IgE-mediated mast cell activation underlies allergic disease, complement-mediated keratinocyte lysis is not the mechanism, and cytotoxic melanocyte destruction relates to pigmentary disorders, none of which drives psoriatic hyperproliferation.
- A dermatologist gently removes the silvery scale from a psoriatic plaque and observes tiny bleeding points. This finding is known as which sign?
- Darier sign
- Nikolsky sign
- Gottron sign
- Auspitz sign
Correct answer: Auspitz sign
Auspitz sign is correct because removing psoriatic scale exposes dilated dermal capillaries close to a thinned overlying epidermis, producing pinpoint bleeding characteristic of psoriasis. The Nikolsky sign is epidermal shearing in blistering disease, the Darier sign is wheal formation on rubbing mastocytosis, and Gottron papules are knuckle lesions of dermatomyositis, none of which is the bleeding seen after scale removal.
- A patient with severe plaque psoriasis unresponsive to topical therapy is considered for a biologic agent. A drug targeting which cytokine pathway would most directly address the central immunologic driver of psoriasis?
- Inhibition of interleukin-17
- Inhibition of immunoglobulin E
- Inhibition of histamine receptors
- Inhibition of leukotriene synthesis
Correct answer: Inhibition of interleukin-17
Inhibition of interleukin-17 is correct because IL-17 is a key effector cytokine in the psoriatic inflammatory cascade, so blocking it (or the upstream IL-23) directly suppresses the disease, which is why these biologics are highly effective. Blocking immunoglobulin E targets allergic disease, antihistamines target itch and allergy, and leukotriene inhibitors target asthma, none of which is the central psoriasis pathway.
- A 28-year-old man with psoriasis notices that his fingernails show small depressions in the nail plate and yellowish discoloration with separation of the nail from the bed. These nail changes in psoriasis are best described as which findings?
- Nail pitting and onycholysis
- Beau lines
- Koilonychia
- Splinter hemorrhages
Correct answer: Nail pitting and onycholysis
Nail pitting and onycholysis are correct because psoriatic involvement of the nail matrix produces pinpoint depressions (pitting) and lifting of the distal nail from its bed (onycholysis), often signaling associated psoriatic arthritis. Koilonychia is spoon nails from iron deficiency, Beau lines are transverse grooves after systemic stress, and splinter hemorrhages relate to endocarditis or trauma, none of which is the classic psoriatic nail pattern.
- A 6-year-old boy has progressive difficulty running and climbing stairs, enlarged calves, and a markedly elevated serum creatine kinase. Genetic testing of the dystrophin gene is recommended. The dystrophin protein normally serves which function in muscle?
- Generating cross-bridge force between actin and myosin
- Storing calcium within the sarcoplasmic reticulum
- Linking the intracellular cytoskeleton to the extracellular matrix to stabilize the sarcolemma
- Conducting action potentials along the muscle membrane
Correct answer: Linking the intracellular cytoskeleton to the extracellular matrix to stabilize the sarcolemma
Linking the intracellular cytoskeleton to the extracellular matrix to stabilize the sarcolemma is correct because dystrophin anchors actin to the dystroglycan complex, protecting the muscle membrane during contraction; its absence in Duchenne muscular dystrophy leads to membrane tears, calcium influx, and fiber death. Cross-bridge force generation is the role of actin and myosin, calcium storage is the sarcoplasmic reticulum, and impulse conduction involves ion channels, none of which is dystrophin's function.
- A family asks about the inheritance pattern of Duchenne muscular dystrophy after their son is diagnosed. This disorder follows which inheritance pattern?
- Autosomal dominant
- Mitochondrial
- Autosomal recessive
- X-linked recessive
Correct answer: X-linked recessive
X-linked recessive is correct because the dystrophin gene is on the X chromosome, so Duchenne muscular dystrophy predominantly affects males who inherit the mutant allele from carrier mothers. Autosomal dominant and recessive patterns would affect both sexes and do not fit the male predominance, and mitochondrial inheritance is maternal and affects both sexes, so none of those matches the dystrophin gene pattern.
- A 4-year-old boy is being evaluated for suspected Duchenne muscular dystrophy. Which laboratory finding would be expected very early, even before significant weakness, reflecting ongoing muscle fiber breakdown?
- Elevated serum uric acid
- Markedly elevated serum creatine kinase
- Elevated antinuclear antibody titer
- Low serum potassium
Correct answer: Markedly elevated serum creatine kinase
Markedly elevated serum creatine kinase is correct because absent dystrophin allows continual leakage of this muscle enzyme into the blood, producing very high levels early in Duchenne muscular dystrophy. Elevated uric acid relates to gout, a positive antinuclear antibody relates to autoimmune disease such as lupus, and low potassium relates to electrolyte disorders, none of which reflects the muscle breakdown of dystrophinopathy.
- A newborn-screening discussion notes that newer therapies for Duchenne muscular dystrophy aim to restore production of a functional, if shortened, dystrophin protein. Which therapeutic strategy attempts to skip a mutated exon so the reading frame is restored?
- Bisphosphonate therapy
- Antisense oligonucleotide exon-skipping therapy
- Colchicine therapy
- Allopurinol therapy
Correct answer: Antisense oligonucleotide exon-skipping therapy
Antisense oligonucleotide exon-skipping therapy is correct because these agents mask a targeted exon during splicing so the disrupted reading frame is restored, yielding a partially functional, Becker-like dystrophin in eligible Duchenne patients. Bisphosphonates treat bone loss, colchicine treats gout flares, and allopurinol lowers urate, none of which addresses the dystrophin gene defect.
- A 26-year-old woman with systemic lupus erythematosus is found on screening to have a positive antinuclear antibody. Why is the antinuclear antibody test used for screening rather than for confirming the diagnosis of lupus?
- It is highly sensitive but not specific, being positive in many autoimmune conditions
- It is highly specific but poorly sensitive for lupus
- It detects crystals in the joint fluid
- It directly measures complement consumption
Correct answer: It is highly sensitive but not specific, being positive in many autoimmune conditions
It is highly sensitive but not specific, being positive in many autoimmune conditions is correct because nearly all lupus patients are antinuclear antibody positive, making a negative test useful to rule out disease, but the test is also positive in other autoimmune and even some healthy individuals, so it cannot confirm lupus alone. It does not detect joint crystals or directly measure complement, and characterizing it as specific but insensitive is the opposite of its actual performance.
- A 30-year-old woman with lupus has a flare. Which laboratory pattern of complement and antibody levels typically accompanies active systemic lupus erythematosus?
- Low complement with positive antimitochondrial antibody
- High C3 and C4 with falling anti-double-stranded DNA titers
- Normal complement with elevated creatine kinase
- Low C3 and C4 with rising anti-double-stranded DNA titers
Correct answer: Low C3 and C4 with rising anti-double-stranded DNA titers
Low C3 and C4 with rising anti-double-stranded DNA titers is correct because active lupus consumes complement through immune-complex formation while anti-dsDNA titers rise, so these markers track disease flares, especially nephritis. High complement with falling anti-dsDNA suggests quiescent disease, elevated creatine kinase reflects muscle disease, and antimitochondrial antibodies indicate primary biliary cholangitis, none of which signals an active lupus flare.
- A 35-year-old woman with systemic lupus erythematosus reports that her facial rash worsens after sun exposure. This photosensitivity in lupus is best explained by which mechanism?
- Defective melanin production in basal keratinocytes
- Bacterial superinfection of sun-damaged skin
- Ultraviolet-induced keratinocyte injury exposing nuclear antigens that drive autoimmune inflammation
- Increased sebaceous gland activity from heat
Correct answer: Ultraviolet-induced keratinocyte injury exposing nuclear antigens that drive autoimmune inflammation
Ultraviolet-induced keratinocyte injury exposing nuclear antigens that drive autoimmune inflammation is correct because ultraviolet light causes keratinocyte apoptosis and surface display of nuclear antigens, which lupus autoantibodies target, amplifying cutaneous inflammation and flares. Defective melanin production causes pigmentary disorders, bacterial superinfection is not the mechanism, and increased sebaceous activity relates to acne, none of which explains lupus photosensitivity.
- A 24-year-old woman is being worked up for possible systemic lupus erythematosus. Which antibody, besides anti-double-stranded DNA, is highly specific for this disease and helps confirm the diagnosis?
- Anti-Smith antibody
- Rheumatoid factor
- Anti-cyclic citrullinated peptide antibody
- Anti-Scl-70 antibody
Correct answer: Anti-Smith antibody
Anti-Smith antibody is correct because, like anti-dsDNA, it is highly specific for systemic lupus erythematosus, so its presence strongly supports the diagnosis even though it is less sensitive. Rheumatoid factor and anti-cyclic citrullinated peptide antibodies are markers of rheumatoid arthritis, and anti-Scl-70 is associated with diffuse systemic sclerosis, none of which is specific for lupus.
- A 65-year-old woman with longstanding rheumatoid arthritis reports new dryness of the eyes and mouth. Biopsy of a minor salivary gland shows lymphocytic infiltration. This associated condition is which of the following?
- Scleroderma renal crisis
- Gout
- Sjogren syndrome
- Psoriatic arthritis
Correct answer: Sjogren syndrome
Sjogren syndrome is correct because lymphocytic destruction of the lacrimal and salivary glands causes dry eyes and dry mouth and commonly accompanies rheumatoid arthritis as a secondary autoimmune process. Gout is a crystal arthropathy, scleroderma renal crisis is an acute hypertensive kidney complication of systemic sclerosis, and psoriatic arthritis accompanies psoriasis, none of which is the sicca syndrome described.
- A 14-year-old soccer player develops anterior knee pain and a tender bump at the tibial tubercle that worsens with running and jumping. Radiographs show fragmentation at the tubercle apophysis. Which condition does this represent?
- Osgood-Schlatter disease
- Rheumatoid arthritis
- Gout
- Osteosarcoma
Correct answer: Osgood-Schlatter disease
Osgood-Schlatter disease is correct because repetitive traction of the patellar tendon on the immature tibial tubercle apophysis in an active adolescent causes the characteristic painful, tender bump that worsens with activity. Rheumatoid arthritis is a symmetric inflammatory polyarthritis, gout is a crystal arthropathy of older adults, and osteosarcoma is a malignant bone tumor with a different aggressive presentation, none of which is this traction apophysitis.
- A 16-year-old boy develops progressive knee pain and swelling, and radiographs show a destructive metaphyseal lesion with a sunburst periosteal pattern and Codman triangle. Which primary bone malignancy is most likely?
- Giant cell tumor
- Osteosarcoma
- Osteoid osteoma
- Chondrosarcoma
Correct answer: Osteosarcoma
Osteosarcoma is correct because the most common primary bone malignancy of adolescents arises at the metaphysis near the knee and produces the sunburst pattern and Codman triangle from aggressive periosteal new bone. Osteoid osteoma is a small benign nidus with night pain relieved by aspirin, giant cell tumor occurs at the epiphysis of adults with a soap-bubble appearance, and chondrosarcoma affects older adults, none of which shows this adolescent sunburst lesion.
- A 25-year-old man develops dull thigh pain that is worse at night and is dramatically relieved by aspirin. Radiographs show a small radiolucent nidus surrounded by sclerotic bone. Which benign bone tumor does this describe?
- Osteoid osteoma
- Osteosarcoma
- Ewing sarcoma
- Chondrosarcoma
Correct answer: Osteoid osteoma
Osteoid osteoma is correct because this benign tumor classically presents in young adults with night pain that responds strikingly to aspirin and shows a small lucent nidus ringed by reactive sclerosis on imaging. Osteosarcoma and Ewing sarcoma are aggressive malignancies, and chondrosarcoma is a cartilage-forming malignancy of older adults, none of which matches the aspirin-responsive benign nidus.
- A 10-year-old boy presents with leg pain and a destructive diaphyseal bone lesion with an onion-skin periosteal reaction. Biopsy shows sheets of small round blue cells with a translocation between chromosomes 11 and 22. Which malignancy does this represent?
- Ewing sarcoma
- Osteosarcoma
- Osteoid osteoma
- Osteochondroma
Correct answer: Ewing sarcoma
Ewing sarcoma is correct because this childhood malignancy produces a diaphyseal lesion with an onion-skin periosteal reaction and small round blue cells carrying the t(11;22) EWS-FLI1 translocation. Osteosarcoma arises at the metaphysis with osteoid and a sunburst pattern, osteoid osteoma is benign with night pain, and osteochondroma is a benign cartilage-capped exostosis, none of which has the t(11;22) small round blue cell features.
- A toddler from a region with poor sunlight exposure and inadequate vitamin D develops bowing of the legs, a delayed anterior fontanelle closure, and beading of the costochondral junctions. Which disorder does this describe?
- Paget disease
- Osteoporosis
- Rickets
- Osteopetrosis
Correct answer: Rickets
Rickets is correct because vitamin D deficiency in a growing child impairs mineralization of the cartilaginous growth plate and osteoid, producing bowed legs, a rachitic rosary at the costochondral junctions, and skeletal deformity. Osteoporosis is low bone mass in adults, Paget disease is disordered remodeling in older adults, and osteopetrosis is dense brittle bone from defective osteoclasts, none of which is childhood mineralization failure.
- A 9-year-old child has recurrent fractures, anemia from marrow crowding, and dense, thick bones on radiographs. Biopsy shows defective osteoclasts unable to resorb bone. Which disorder does this represent?
- Osteopetrosis
- Osteomalacia
- Osteoporosis
- Rickets
Correct answer: Osteopetrosis
Osteopetrosis is correct because defective osteoclast function prevents normal bone resorption, leaving abnormally dense yet brittle bone that fractures easily and crowds out marrow, causing anemia. Osteoporosis features low bone mass, osteomalacia and rickets feature impaired mineralization with soft bone, none of which produces the dense, thick, brittle bone of failed resorption.
- A 70-year-old man with Paget disease of bone has hearing loss and an enlarged skull. The hearing loss in Paget disease most directly results from which process?
- Immune-complex deposition in the cochlea
- Crystal deposition in the inner ear
- Bony overgrowth compressing the auditory nerve or ossicles
- Demyelination of the auditory pathway
Correct answer: Bony overgrowth compressing the auditory nerve or ossicles
Bony overgrowth compressing the auditory nerve or ossicles is correct because disordered remodeling in Paget disease thickens and enlarges skull bones, which can narrow foramina and impinge on the cochlear nerve or impair ossicle movement, producing hearing loss. Immune-complex deposition, crystal deposition, and demyelination are not the mechanisms of pagetic hearing loss, so none of those explains it.
- A 55-year-old man with longstanding Paget disease of bone develops new, persistent bone pain and a soft-tissue mass at an affected site. Which serious complication must be excluded?
- Rheumatoid arthritis
- Acute gout flare
- Osteosarcoma arising in pagetic bone
- Osteoporotic fracture
Correct answer: Osteosarcoma arising in pagetic bone
Osteosarcoma arising in pagetic bone is correct because malignant transformation of Paget disease, although uncommon, classically presents with new unrelenting pain and a soft-tissue mass and carries a poor prognosis. A gout flare causes acute crystal arthritis, rheumatoid arthritis is a symmetric polyarthritis, and an osteoporotic fracture causes acute pain without a growing soft-tissue mass, none of which matches sarcomatous degeneration.
- A 28-year-old woman has joint pain, fatigue, and a butterfly rash, and meets diagnostic criteria for systemic lupus erythematosus. The arthritis of lupus differs from rheumatoid arthritis chiefly in that lupus arthritis is typically which of the following?
- Erosive and deforming with joint destruction
- Associated with tophi over the joints
- Nonerosive and reversible without permanent joint damage
- Caused by crystal deposition
Correct answer: Nonerosive and reversible without permanent joint damage
Nonerosive and reversible without permanent joint damage is correct because lupus arthritis usually produces pain and sometimes reducible deformities (Jaccoud arthropathy) without the cartilage and bone erosions characteristic of rheumatoid arthritis. Erosive destructive arthritis describes rheumatoid disease, tophi describe gout, and crystal deposition describes crystal arthropathies, none of which is the typical nonerosive lupus joint disease.
- A 24-year-old albino patient with markedly fair skin asks why he is at increased risk for skin cancer. His condition results from a defect in melanin synthesis, most often involving which enzyme?
- Tyrosinase
- Lysyl oxidase
- Phenylalanine hydroxylase
- Glucose-6-phosphate dehydrogenase
Correct answer: Tyrosinase
Tyrosinase is correct because oculocutaneous albinism most commonly results from deficient tyrosinase, the enzyme that converts tyrosine to melanin precursors, so absent melanin leaves skin unprotected from ultraviolet damage and raises skin cancer risk. Lysyl oxidase cross-links collagen and elastin, phenylalanine hydroxylase deficiency causes phenylketonuria, and glucose-6-phosphate dehydrogenase deficiency causes hemolysis, none of which controls melanin production.
- A 35-year-old woman develops sharply marginated, depigmented white patches on her hands and around the mouth. Biopsy shows complete absence of melanocytes in the affected skin. Which condition does this represent?
- Albinism
- Melasma
- Tinea versicolor
- Vitiligo
Correct answer: Vitiligo
Vitiligo is correct because autoimmune destruction of melanocytes produces well-demarcated depigmented macules with absent melanocytes on biopsy, often affecting the hands and face. Albinism is a congenital enzyme defect with melanocytes present but nonfunctional, melasma is hyperpigmentation, and tinea versicolor is a yeast infection causing scaly pigment change, none of which shows the autoimmune melanocyte loss of vitiligo.
- A 19-year-old man has multiple comedones, inflamed papules, and pustules on the face. The initial event in the pathogenesis of acne vulgaris is which of the following?
- Autoantibodies against desmoglein
- Follicular hyperkeratinization plugging the pilosebaceous unit
- Type III immune-complex deposition
- Defective dystrophin in dermal muscle
Correct answer: Follicular hyperkeratinization plugging the pilosebaceous unit
Follicular hyperkeratinization plugging the pilosebaceous unit is correct because acne begins with abnormal keratin plugging of the follicle, which together with excess sebum, Cutibacterium acnes colonization, and inflammation produces comedones and pustules. Anti-desmoglein autoantibodies cause pemphigus, immune-complex deposition causes vasculitis or lupus nephritis, and dystrophin defects cause muscular dystrophy, none of which initiates acne.
- A 5-year-old child has intensely itchy, ill-defined erythematous patches in the antecubital and popliteal fossae, with a personal history of asthma and allergic rhinitis. Which skin condition does this represent?
- Pemphigus vulgaris
- Psoriasis
- Atopic dermatitis
- Tinea corporis
Correct answer: Atopic dermatitis
Atopic dermatitis is correct because pruritic, poorly demarcated eczematous patches in flexural areas of a child with the atopic triad of asthma and allergic rhinitis are characteristic of this condition tied to skin barrier dysfunction and type 2 inflammation. Psoriasis favors extensor surfaces with thick scale, pemphigus produces blisters, and tinea corporis is a ringed fungal infection, none of which fits the flexural atopic pattern.
- A 60-year-old man develops a tender, fluctuant, erythematous nodule on the back of the neck that drains pus from multiple points. Which term best describes this deeper, multi-headed bacterial skin infection?
- Carbuncle
- Contact dermatitis
- Erythema nodosum
- Seborrheic keratosis
Correct answer: Carbuncle
Carbuncle is correct because a coalescence of interconnected infected hair follicles forms a deep, painful, multi-headed abscess that drains from several points, usually due to Staphylococcus aureus. Contact dermatitis is a noninfectious itchy rash, erythema nodosum is tender panniculitis of the shins, and seborrheic keratosis is a benign waxy growth, none of which is the deep follicular abscess described.
- A patient develops painful target-shaped lesions with central duskiness on the palms and forearms one week after a herpes simplex outbreak. Which reactive skin condition does this represent?
- Erythema multiforme
- Psoriasis
- Acanthosis nigricans
- Lichen planus
Correct answer: Erythema multiforme
Erythema multiforme is correct because target lesions with a central dusky zone appearing after an infection such as herpes simplex are the hallmark of this immune-mediated reactive eruption. Psoriasis produces scaly plaques, acanthosis nigricans produces velvety flexural hyperpigmentation, and lichen planus produces flat-topped violaceous papules, none of which forms postinfectious target lesions.
- A 50-year-old woman develops pruritic, flat-topped, polygonal, violaceous papules on the wrists with fine white lines visible on the surface. Which condition does this describe?
- Psoriasis
- Lichen planus
- Dermatitis herpetiformis
- Bullous pemphigoid
Correct answer: Lichen planus
Lichen planus is correct because pruritic, purple, polygonal, flat-topped papules with overlying lacy white Wickham striae are classic for this T-cell-mediated condition, summarized by the six P's. Psoriasis produces silvery-scaled plaques, dermatitis herpetiformis produces grouped vesicles with IgA deposits, and bullous pemphigoid produces tense blisters, none of which shows Wickham striae.
- A patient on a thiazide diuretic develops several gout flares yearly. The clinician chooses an agent to prevent flares during initiation of urate-lowering therapy without lowering urate itself. Which mechanism best fits this prophylactic agent given at low dose?
- Xanthine oxidase inhibition
- Microtubule inhibition limiting neutrophil activation
- Uricosuric blockade of tubular urate reabsorption
- Recombinant uricase degradation of urate
Correct answer: Microtubule inhibition limiting neutrophil activation
Microtubule inhibition limiting neutrophil activation is correct because low-dose colchicine prevents flares that often occur when urate-lowering therapy mobilizes crystals, working by impairing neutrophil microtubule function and migration rather than altering urate levels. Xanthine oxidase inhibition and recombinant uricase lower urate, and uricosuric blockade increases excretion, none of which is the antiinflammatory prophylactic mechanism of colchicine.
- A 65-year-old man with chronic kidney disease and recurrent gout cannot tolerate allopurinol and has refractory hyperuricemia. Which biologic enzyme therapy directly converts uric acid into the more soluble allantoin for excretion?
- Pegloticase (recombinant uricase)
- Probenecid
- Febuxostat
- Indomethacin
Correct answer: Pegloticase (recombinant uricase)
Pegloticase (recombinant uricase) is correct because humans lack uricase, so this recombinant enzyme catalyzes the breakdown of uric acid into water-soluble allantoin, rapidly lowering severe refractory urate burdens. Probenecid increases renal urate excretion, febuxostat blocks urate production via xanthine oxidase, and indomethacin treats the inflammatory flare, none of which enzymatically degrades urate to allantoin.
- A 50-year-old man with rheumatoid arthritis and a history of dust exposure in coal mining develops multiple pulmonary nodules on chest imaging. This association of rheumatoid arthritis with pneumoconiotic lung nodules is known as which syndrome?
- CREST syndrome
- Felty syndrome
- Sjogren syndrome
- Caplan syndrome
Correct answer: Caplan syndrome
Caplan syndrome is correct because it describes the combination of rheumatoid arthritis with pneumoconiosis and resulting pulmonary rheumatoid nodules in patients with occupational dust exposure such as coal mining. Felty syndrome is rheumatoid arthritis with splenomegaly and neutropenia, Sjogren syndrome is sicca with gland infiltration, and CREST is a limited scleroderma variant, none of which is the dust-related nodular lung syndrome.
- A 32-year-old man develops asymmetric arthritis of the knee, painful red eyes, and dysuria several weeks after an episode of bacterial diarrhea. He is HLA-B27 positive. Which condition does this triad represent?
- Rheumatoid arthritis
- Reactive arthritis
- Gout
- Osteoarthritis
Correct answer: Reactive arthritis
Reactive arthritis is correct because a sterile, post-infectious arthritis with conjunctivitis and urethritis following gastrointestinal or genitourinary infection in an HLA-B27 positive patient is the classic seronegative spondyloarthropathy formerly called Reiter syndrome. Rheumatoid arthritis is a chronic symmetric autoimmune polyarthritis, gout is a crystal arthropathy, and osteoarthritis is degenerative, none of which presents with this post-infectious triad.
- A 45-year-old woman develops rapidly progressive skin thickening over the trunk and proximal limbs, along with new severe hypertension and rising creatinine. Anti-Scl-70 antibodies are positive. Which condition does this represent?
- Systemic lupus erythematosus
- Diffuse cutaneous systemic sclerosis
- Psoriasis
- Dermatomyositis
Correct answer: Diffuse cutaneous systemic sclerosis
Diffuse cutaneous systemic sclerosis is correct because widespread skin fibrosis extending proximally with anti-Scl-70 (anti-topoisomerase) antibodies and a scleroderma renal crisis of acute hypertension and renal failure defines the diffuse form of systemic sclerosis. Lupus features the malar rash and anti-dsDNA, psoriasis produces scaly plaques, and dermatomyositis produces a heliotrope rash with muscle weakness, none of which is the diffuse fibrosing disease described.
- A 60-year-old woman reports new headache, jaw pain when chewing, and transient visual loss, with a tender, hardened temporal artery and a very high erythrocyte sedimentation rate. Immediate treatment is needed to prevent which outcome?
- Tophus formation
- Joint erosion
- Permanent vision loss from ischemic optic neuropathy
- Epidermal sloughing
Correct answer: Permanent vision loss from ischemic optic neuropathy
Permanent vision loss from ischemic optic neuropathy is correct because giant cell (temporal) arteritis is a granulomatous vasculitis that can occlude the ophthalmic artery, so urgent glucocorticoids are given even before biopsy to prevent irreversible blindness. Joint erosion relates to rheumatoid arthritis, tophus formation to gout, and epidermal sloughing to severe drug reactions, none of which is the feared outcome of temporal arteritis.
- A 12-year-old girl is referred for evaluation of a sideways curvature of the spine noted on a school screening; forward bending reveals a rib hump and a lateral spinal curve with no underlying cause identified. Which condition does this represent?
- Osteoporotic kyphosis
- Ankylosing spondylitis
- Adolescent idiopathic scoliosis
- Paget disease
Correct answer: Adolescent idiopathic scoliosis
Adolescent idiopathic scoliosis is correct because a lateral spinal curvature with vertebral rotation producing a rib hump on forward bending, arising without a known cause in a growing adolescent, defines this most common scoliosis. Ankylosing spondylitis causes inflammatory fusion in young men, osteoporotic kyphosis causes a forward-bent posture in older adults, and Paget disease causes disordered bone remodeling, none of which is idiopathic adolescent lateral curvature.
- A 30-year-old man with longstanding ankylosing spondylitis develops a rigid spine on imaging described as a bamboo spine. This appearance results from which process?
- Crystal deposition along the spine
- Osteophyte formation from cartilage wear
- Lytic destruction by metastases
- Syndesmophyte formation bridging adjacent vertebrae
Correct answer: Syndesmophyte formation bridging adjacent vertebrae
Syndesmophyte formation bridging adjacent vertebrae is correct because chronic inflammation at entheses in ankylosing spondylitis leads to vertical bony bridges that fuse vertebrae, producing the bamboo spine and progressive rigidity. Osteophytes from cartilage wear characterize osteoarthritis, lytic metastatic destruction produces bone loss not bridging, and crystal deposition causes arthropathy rather than vertebral fusion, none of which yields the bamboo spine.
- A 40-year-old woman develops a painless lump near the knee that radiographs show as a bony outgrowth with a cartilage cap projecting from the metaphysis, pointing away from the joint. Which benign tumor does this represent?
- Giant cell tumor
- Osteosarcoma
- Ewing sarcoma
- Osteochondroma
Correct answer: Osteochondroma
Osteochondroma is correct because it is the most common benign bone tumor, presenting as a cartilage-capped bony projection from the metaphysis that grows away from the nearby joint and is usually painless. Osteosarcoma and Ewing sarcoma are aggressive malignancies, and giant cell tumor is an epiphyseal lesion with a soap-bubble appearance, none of which is the benign cartilage-capped exostosis.
- A 28-year-old woman has a lytic, expansile lesion at the epiphysis of the distal femur described as having a soap-bubble appearance on radiographs, with biopsy showing multinucleated giant cells. Which bone tumor does this represent?
- Giant cell tumor of bone
- Osteosarcoma
- Ewing sarcoma
- Chondrosarcoma
Correct answer: Giant cell tumor of bone
Giant cell tumor of bone is correct because this locally aggressive but usually benign tumor occurs at the epiphysis of long bones in young adults, shows a soap-bubble lytic appearance, and contains osteoclast-like multinucleated giant cells on biopsy. Osteosarcoma arises at the metaphysis with osteoid, Ewing sarcoma is a diaphyseal small round blue cell tumor, and chondrosarcoma forms cartilage in older adults, none of which is the epiphyseal giant cell tumor.
- A 16-year-old female athlete with disordered eating and absent menses sustains a stress fracture. This triad of low energy availability, menstrual dysfunction, and low bone density increases fracture risk primarily through which mechanism?
- Autoimmune destruction of osteoblasts
- Crystal deposition weakening bone
- Estrogen deficiency accelerating bone resorption
- Defective collagen cross-linking
Correct answer: Estrogen deficiency accelerating bone resorption
Estrogen deficiency accelerating bone resorption is correct because in the female athlete triad, low energy availability suppresses the reproductive axis, and the resulting low estrogen removes its restraint on osteoclasts, lowering bone density and predisposing to stress fractures in a young person. Crystal deposition, autoimmune osteoblast destruction, and defective collagen cross-linking are not the mechanisms of triad-related bone loss, so none of those applies.
- A 55-year-old man is told that the long-term skeletal complication of his chronic kidney disease involves bone changes from mineral and hormone imbalance. Which combination of laboratory findings underlies renal osteodystrophy?
- High calcium with low parathyroid hormone
- Low phosphate, high calcium, and suppressed parathyroid hormone
- Normal phosphate and calcium with elevated uric acid
- High phosphate, low calcium, low active vitamin D, and high parathyroid hormone
Correct answer: High phosphate, low calcium, low active vitamin D, and high parathyroid hormone
High phosphate, low calcium, low active vitamin D, and high parathyroid hormone is correct because failing kidneys retain phosphate and cannot activate vitamin D, lowering calcium and driving secondary hyperparathyroidism, which together produce the bone disease of renal osteodystrophy. The other patterns describe states such as primary hyperparathyroidism or unrelated conditions, none of which captures the phosphate-retention, low-calcium, high-parathyroid-hormone picture of renal bone disease.
- A 35-year-old man has reddish-brown papules over the knuckles and a violaceous discoloration of the upper eyelids, along with proximal muscle weakness and difficulty rising from a chair. Antibodies and biopsy confirm an inflammatory myopathy. The knuckle lesions are termed which finding?
- Heberden nodes
- Gottron papules
- Tophi
- Osler nodes
Correct answer: Gottron papules
Gottron papules are correct because these scaly violaceous papules over the knuckles, together with the heliotrope eyelid rash and proximal weakness, are characteristic skin findings of dermatomyositis. Heberden nodes are osteoarthritic bony nodules of the distal interphalangeal joints, tophi are urate deposits of gout, and Osler nodes are tender lesions of endocarditis, none of which is the knuckle papule of dermatomyositis.
- A 50-year-old patient is found to have an underlying internal malignancy alongside new dermatomyositis. The recognition that dermatomyositis in an adult may be a paraneoplastic phenomenon is clinically important because it should prompt which action?
- Bone density screening only
- Immediate joint replacement surgery
- Lifelong allopurinol therapy
- Age-appropriate cancer screening to search for an occult malignancy
Correct answer: Age-appropriate cancer screening to search for an occult malignancy
Age-appropriate cancer screening to search for an occult malignancy is correct because adult-onset dermatomyositis carries an increased risk of underlying cancer, so a diagnosis should trigger thorough age-appropriate malignancy evaluation. Joint replacement, lifelong allopurinol, and isolated bone density screening do not address the paraneoplastic association, so none of those is the appropriate response.
- A 60-year-old woman with osteoarthritis of the knee is counseled on first-line management. Besides analgesics, which intervention most directly addresses the mechanical contribution to her degenerative joint disease?
- Methotrexate
- Lifelong systemic glucocorticoids
- Allopurinol
- Weight loss and quadriceps-strengthening exercise
Correct answer: Weight loss and quadriceps-strengthening exercise
Weight loss and quadriceps-strengthening exercise is correct because reducing joint load and strengthening supporting muscles directly counter the mechanical wear that drives osteoarthritis, improving pain and function. Allopurinol treats gout, methotrexate treats inflammatory autoimmune arthritis, and chronic systemic glucocorticoids are not appropriate for degenerative osteoarthritis, so none of those addresses its mechanical basis.
- A 45-year-old woman with rheumatoid arthritis is started on a disease-modifying antirheumatic drug to slow joint destruction. Which agent is the conventional first-line disease-modifying therapy that inhibits dihydrofolate reductase?
- Methotrexate
- Acetaminophen
- Colchicine
- Allopurinol
Correct answer: Methotrexate
Methotrexate is correct because it is the conventional anchor disease-modifying antirheumatic drug for rheumatoid arthritis, inhibiting dihydrofolate reductase and dampening the autoimmune synovitis to slow erosive joint damage. Acetaminophen only relieves pain, colchicine treats gout, and allopurinol lowers urate, none of which is the first-line disease-modifying agent that halts rheumatoid joint destruction.
- A 60-year-old man with hyperlipidemia has a coronary plaque examined under the microscope. The lipid-laden cells that give the early fatty streak its appearance are derived from which circulating cell that has engulfed oxidized lipoprotein?
- Mature B lymphocytes
- Macrophages that have become foam cells
- Circulating erythrocytes
- Megakaryocytes from the marrow
Correct answer: Macrophages that have become foam cells
The foam cells of the fatty streak are macrophages that migrated into the intima and engulfed oxidized low-density lipoprotein through scavenger receptors. As they accumulate lipid they take on a foamy cytoplasmic appearance and form the earliest visible atherosclerotic lesion. B lymphocytes, erythrocytes, and megakaryocytes do not become foam cells.
- A researcher studies the earliest event that initiates an atherosclerotic lesion. Which of the following is generally considered the inciting step that allows lipoproteins and monocytes to enter the vessel wall?
- Endothelial injury and dysfunction of the arterial lining
- Spontaneous rupture of a mature fibrous cap
- Complete calcification of the media
- Formation of a venous valve
Correct answer: Endothelial injury and dysfunction of the arterial lining
Atherosclerosis is initiated by endothelial injury and dysfunction, which increases permeability to lipoproteins and promotes leukocyte adhesion and entry into the intima. This response-to-injury process precedes lipid accumulation and plaque formation. Cap rupture is a late event, medial calcification is downstream, and venous valves are unrelated to arterial atherogenesis.
- A 68-year-old diabetic man with widespread atherosclerosis is noted to have markedly reduced HDL cholesterol. The protective role of HDL against atherosclerosis is best attributed to which function?
- Delivering triglycerides to adipose tissue
- Activating the clotting cascade in the intima
- Carrying dietary lipids from the intestine
- Reverse cholesterol transport from peripheral tissues to the liver
Correct answer: Reverse cholesterol transport from peripheral tissues to the liver
HDL is protective because it carries out reverse cholesterol transport, removing excess cholesterol from peripheral tissues including arterial walls and returning it to the liver for excretion. Low HDL therefore raises atherosclerotic risk. Delivering triglycerides to adipose tissue and carrying dietary lipids are roles of VLDL and chylomicrons, not HDL.
- A 72-year-old smoker is found to have a carotid bruit and an asymptomatic high-grade carotid stenosis from atherosclerosis. Embolization of plaque material from this lesion most characteristically causes which transient event?
- Intermittent claudication of the calf
- A transient ischemic attack with brief focal neurologic deficits
- Exertional angina pectoris
- Mesenteric ischemia after meals
Correct answer: A transient ischemic attack with brief focal neurologic deficits
Carotid atherosclerotic plaques can shed emboli that travel to the cerebral circulation, producing a transient ischemic attack with brief focal deficits such as transient monocular blindness or weakness. Claudication reflects lower-extremity disease, angina reflects coronary disease, and mesenteric ischemia reflects splanchnic arterial disease, each from atherosclerosis in a different bed.
- A patient with refractory hyperlipidemia is started on a PCSK9 inhibitor to lower LDL further. These drugs reduce serum LDL by which mechanism?
- Blocking intestinal absorption of cholesterol at the brush border
- Inhibiting HMG-CoA reductase in the liver
- Binding bile acids in the gut lumen
- Preventing degradation of hepatic LDL receptors so more remain to clear LDL
Correct answer: Preventing degradation of hepatic LDL receptors so more remain to clear LDL
PCSK9 normally promotes degradation of hepatic LDL receptors, so inhibiting PCSK9 allows more receptors to recycle to the cell surface and clear additional LDL from the blood. This lowers serum LDL substantially. Brush-border absorption blockade describes ezetimibe, HMG-CoA reductase inhibition describes statins, and bile-acid binding describes resins.
- A 55-year-old man with metabolic syndrome has elevated triglycerides and small dense LDL particles. Which lipoprotein is the primary endogenous transporter of triglycerides synthesized by the liver into the circulation?
- High-density lipoprotein (HDL)
- Lipoprotein(a)
- Low-density lipoprotein (LDL)
- Very-low-density lipoprotein (VLDL)
Correct answer: Very-low-density lipoprotein (VLDL)
VLDL is the main lipoprotein that transports endogenously synthesized triglycerides from the liver to peripheral tissues. As VLDL is metabolized by lipoprotein lipase it becomes LDL, the major cholesterol carrier. HDL handles reverse cholesterol transport, and lipoprotein(a) is an atherogenic LDL-like particle, not the principal triglyceride transporter.
- A 70-year-old man presents 6 hours into a myocardial infarction. Gross changes lag behind cell death, so the tissue may look normal early. By approximately which time window does the infarcted myocardium first show gross pallor or a mottled appearance?
- Roughly 12 to 24 hours after onset
- Within the first 30 minutes
- Within the first 2 hours
- Only after several weeks
Correct answer: Roughly 12 to 24 hours after onset
Gross changes of myocardial infarction lag behind biochemical cell death, with pallor or a mottled, tan-to-yellow appearance becoming visible roughly 12 to 24 hours after onset. In the first hours the tissue looks grossly normal even though irreversible injury has begun. A mature gray-white scar forms only after weeks.
- A 64-year-old man with an inferior myocardial infarction develops sinus bradycardia and transient heart block. This is most often explained because the same coronary artery that supplies the inferior wall also supplies which conduction structure in most people?
- The left bundle branch only
- The atrioventricular node, via the right coronary artery
- The aortic valve cusps
- The interventricular septum apex
Correct answer: The atrioventricular node, via the right coronary artery
In most people the right coronary artery supplies both the inferior wall and the atrioventricular node, so an inferior infarction can cause sinus bradycardia and atrioventricular block. This explains the conduction disturbances seen with right coronary occlusion. The aortic cusps and septal apex are not supplied by this artery in a way that produces this pattern.
- A 60-year-old man dies suddenly 5 days after a large myocardial infarction, and autopsy shows hemopericardium from a ruptured free wall. This catastrophic mechanical complication occurs during which phase of healing when the wall is weakest?
- Within the first hour of infarction
- Only after a dense scar has fully matured
- Decades after the original event
- During the period of macrophage-rich softening, several days to about a week after infarction
Correct answer: During the period of macrophage-rich softening, several days to about a week after infarction
Free wall rupture occurs most often several days to about a week after infarction, when macrophages have removed necrotic tissue and the wall is softened by ongoing degradation before strong collagenous scar forms. This is the period of maximal mechanical weakness. A fully mature scar resists rupture, and rupture does not occur within the first hour.
- A patient presents with chest pain and an electrocardiogram. Which finding on the electrocardiogram is the most specific indicator of a fully completed (old) transmural infarction rather than acute ischemia?
- Peaked T waves
- ST-segment depression
- A short PR interval
- Pathologic Q waves
Correct answer: Pathologic Q waves
Pathologic Q waves indicate loss of viable transmural myocardium and are the classic marker of a completed (often old) infarction. They develop because the dead tissue generates no electrical forces, leaving an early negative deflection. Peaked T waves and ST depression reflect acute ischemia, and a short PR interval relates to pre-excitation, not prior infarction.
- A 58-year-old man with crushing substernal chest pain radiating to the left arm is suspected of having a myocardial infarction. Which cardiac biomarker is the preferred test because of its high sensitivity and specificity for myocardial injury?
- Cardiac troponin
- Aspartate aminotransferase
- Lactate dehydrogenase
- Total creatine kinase
Correct answer: Cardiac troponin
Cardiac troponin is the preferred biomarker for myocardial infarction because of its high sensitivity and near-exclusive specificity for cardiac muscle injury. It rises within hours and remains elevated for days. Aspartate aminotransferase, lactate dehydrogenase, and total creatine kinase are older, less specific markers no longer relied upon for diagnosis.
- A 66-year-old man is treated with primary percutaneous coronary intervention within 90 minutes of an ST-elevation myocardial infarction. The major benefit of restoring coronary flow this quickly is best described as which of the following?
- Immediate regeneration of already-dead myocytes
- Permanent prevention of any future atherosclerosis
- Conversion of the infarct to liquefactive necrosis
- Salvage of still-viable but ischemic myocardium to limit infarct size
Correct answer: Salvage of still-viable but ischemic myocardium to limit infarct size
Early reperfusion limits infarct size by restoring blood flow to myocardium that is ischemic but not yet irreversibly injured, salvaging viable tissue. The benefit hinges on time, since the wave of necrosis spreads from subendocardium outward. Reperfusion cannot regenerate dead myocytes, prevent atherosclerosis, or change the coagulative pattern of cardiac infarction.
- A 72-year-old woman with chronic systolic heart failure has marked fatigue and dyspnea, and her measured ejection fraction is 28 percent. Ejection fraction is calculated as which of the following?
- End-diastolic volume divided by stroke volume
- Stroke volume divided by end-diastolic volume
- Heart rate multiplied by stroke volume
- Systolic pressure divided by diastolic pressure
Correct answer: Stroke volume divided by end-diastolic volume
Ejection fraction is the stroke volume divided by the end-diastolic volume, expressing the fraction of the filled ventricle that is ejected each beat. A value of 28 percent indicates severely reduced systolic function. Heart rate times stroke volume gives cardiac output, and the pressure ratio is unrelated to ejection fraction.
- A 65-year-old man with right-sided heart failure has dependent pitting edema, hepatomegaly, and elevated jugular venous pressure. These findings reflect congestion in which circulation?
- The systemic venous circulation
- The pulmonary venous circulation only
- The coronary circulation
- The bronchial arterial circulation
Correct answer: The systemic venous circulation
Right-sided heart failure causes backup into the systemic venous circulation, producing peripheral edema, hepatic congestion, and jugular venous distention. Left-sided failure instead congests the pulmonary venous circulation and causes dyspnea. The coronary and bronchial circulations are not the source of these systemic congestion findings.
- A patient with heart failure is found to have markedly elevated B-type natriuretic peptide. The increased secretion of this peptide in heart failure is triggered chiefly by which stimulus?
- Low serum potassium
- A rise in arterial oxygen saturation
- Decreased venous return to the heart
- Increased ventricular wall stretch from volume and pressure overload
Correct answer: Increased ventricular wall stretch from volume and pressure overload
B-type natriuretic peptide is released mainly from ventricular myocardium in response to increased wall stretch from volume and pressure overload, so it rises in heart failure and aids diagnosis. It promotes natriuresis and vasodilation as a counterregulatory signal. Low potassium, higher oxygen saturation, and reduced venous return do not drive its release.
- A 70-year-old man with heart failure with reduced ejection fraction is started on an SGLT2 inhibitor, which improves outcomes even without diabetes. SGLT2 inhibitors act primarily at which site to produce diuresis?
- The collecting duct aldosterone receptor
- The thick ascending limb sodium-potassium-chloride cotransporter
- The distal tubule sodium-chloride cotransporter
- The proximal tubule, blocking sodium-glucose cotransport
Correct answer: The proximal tubule, blocking sodium-glucose cotransport
SGLT2 inhibitors act at the proximal tubule, blocking sodium-glucose cotransport and producing osmotic diuresis and natriuresis that benefit heart failure independent of glucose lowering. Loop diuretics target the thick ascending limb, thiazides the distal tubule, and mineralocorticoid antagonists the collecting duct receptor.
- A 30-year-old man with a family history of sudden death has dyspnea and a systolic murmur that increases with the Valsalva maneuver, and echocardiography shows asymmetric septal thickening with outflow obstruction. Which condition best explains this heart failure presentation?
- Restrictive cardiomyopathy from amyloid
- Hypertrophic cardiomyopathy
- Dilated cardiomyopathy from a viral myocarditis
- Acute pericardial tamponade
Correct answer: Hypertrophic cardiomyopathy
Asymmetric septal hypertrophy with dynamic outflow obstruction and a murmur that intensifies with reduced preload from Valsalva is characteristic of hypertrophic cardiomyopathy, a common inherited cause of sudden cardiac death in young people. Dilated and restrictive cardiomyopathies have different morphology, and tamponade is an acute compressive emergency.
- A patient with advanced heart failure is described as having a low ejection fraction and a dilated, poorly contracting ventricle on imaging. Compared with a normal heart, which pressure-volume change best characterizes this dilated failing ventricle?
- A leftward shift with very small chamber volumes
- A rightward-shifted loop with increased end-diastolic and end-systolic volumes
- An identical loop with normal volumes
- Loss of all diastolic filling
Correct answer: A rightward-shifted loop with increased end-diastolic and end-systolic volumes
The dilated failing ventricle operates at larger volumes, so its pressure-volume loop shifts rightward with increased end-diastolic and end-systolic volumes and a reduced ejection fraction. The leftward small-volume pattern would suggest a hypovolemic or hypertrophic stiff ventricle, not dilated systolic failure, and filling is not entirely lost.
- A 75-year-old patient with systolic heart failure and a wide QRS complex with left bundle branch block undergoes implantation of a biventricular pacemaker. This cardiac resynchronization therapy improves symptoms primarily by correcting which problem?
- Dyssynchronous ventricular contraction caused by the conduction delay
- An obstructed coronary artery
- A stenotic aortic valve
- An accessory atrioventricular pathway
Correct answer: Dyssynchronous ventricular contraction caused by the conduction delay
Cardiac resynchronization therapy paces both ventricles to restore coordinated contraction in patients whose left bundle branch block causes dyssynchronous, inefficient pumping. Resynchronizing contraction improves stroke volume and symptoms. It does not open coronary arteries, replace a valve, or ablate an accessory pathway.
- A patient measures their blood pressure at home and consistently records readings around 118/76 mm Hg. According to current United States classification, this falls into which category?
- Elevated blood pressure
- Stage 1 hypertension
- Stage 2 hypertension
- Normal blood pressure
Correct answer: Normal blood pressure
A blood pressure below 120 systolic and below 80 diastolic is classified as normal under current United States guidelines, so 118/76 is normal. Elevated blood pressure is 120 to 129 systolic with diastolic under 80, stage 1 begins at 130 to 139 systolic or 80 to 89 diastolic, and stage 2 at 140 or higher systolic or 90 or higher diastolic.
- A 40-year-old woman has hypertension and an abdominal bruit, and imaging shows narrowing of a renal artery. Activation of which system best explains the high blood pressure in this renovascular hypertension?
- Excess parathyroid hormone
- The renin-angiotensin-aldosterone system from reduced renal perfusion
- Suppression of antidiuretic hormone
- Increased natriuretic peptide secretion
Correct answer: The renin-angiotensin-aldosterone system from reduced renal perfusion
Renal artery stenosis reduces perfusion to the affected kidney, which senses low pressure and activates the renin-angiotensin-aldosterone system, raising angiotensin II and aldosterone to drive hypertension. This is the mechanism of renovascular hypertension. Parathyroid hormone, antidiuretic hormone suppression, and natriuretic peptides do not cause this pattern.
- A 25-year-old man has hypertension in the arms with weak, delayed femoral pulses and lower blood pressure in the legs. Which congenital vascular abnormality best explains this finding?
- Coarctation of the aorta
- Atrial septal defect
- Patent foramen ovale
- Pulmonary valve stenosis
Correct answer: Coarctation of the aorta
Coarctation of the aorta narrows the aorta typically distal to the left subclavian artery, producing upper-extremity hypertension with diminished, delayed femoral pulses and lower leg pressures. This brachial-femoral mismatch is the classic clue. Atrial septal defect, patent foramen ovale, and pulmonary stenosis do not cause this pressure gradient.
- A 30-year-old patient with hypertension is started on an ACE inhibitor and within days develops swelling of the lips and tongue. This adverse effect, angioedema, is attributed to accumulation of which mediator?
- Histamine from mast cell tumors
- Serotonin from platelets
- Aldosterone from the adrenal gland
- Bradykinin, normally degraded by ACE
Correct answer: Bradykinin, normally degraded by ACE
ACE inhibitor-induced angioedema results from accumulation of bradykinin, which the enzyme normally helps degrade, leading to increased vascular permeability and tissue swelling. The same bradykinin buildup underlies the characteristic dry cough. Histamine from mastocytosis, platelet serotonin, and aldosterone are not the cause of this drug reaction.
- A long-standing hypertensive patient develops progressive kidney damage. The renal injury of chronic hypertension is classically described pathologically as which entity?
- Benign nephrosclerosis
- Diabetic nodular glomerulosclerosis
- Acute tubular necrosis
- Polycystic kidney disease
Correct answer: Benign nephrosclerosis
Chronic hypertension produces benign nephrosclerosis, marked by hyaline arteriolosclerosis, glomerular scarring, and a grossly granular kidney surface from ischemic atrophy. This slow vascular injury reduces renal function over years. Diabetic nodular sclerosis, acute tubular necrosis, and polycystic kidney disease have different causes and morphology.
- A patient with hypertension is taught that lifestyle changes can lower blood pressure. Which dietary intervention is specifically recommended and shown to reduce blood pressure?
- A high-sodium, low-potassium diet
- Eliminating all dietary protein
- Increasing saturated fat intake
- Reducing dietary sodium and following a diet rich in fruits and vegetables
Correct answer: Reducing dietary sodium and following a diet rich in fruits and vegetables
Reducing dietary sodium and adopting an eating pattern rich in fruits, vegetables, and low-fat dairy, as in the DASH approach, is a proven lifestyle measure to lower blood pressure. Increasing sodium, eliminating protein, or raising saturated fat would not lower pressure and could worsen cardiovascular risk.
- A pregnant woman at 34 weeks develops hypertension and needs antihypertensive therapy. Which agent is contraindicated in pregnancy because of fetal renal and developmental toxicity?
- Labetalol
- ACE inhibitors
- Methyldopa
- Nifedipine
Correct answer: ACE inhibitors
ACE inhibitors are contraindicated in pregnancy because they cause fetal renal damage, oligohydramnios, and other developmental toxicity, especially in the second and third trimesters. Labetalol, methyldopa, and nifedipine are considered acceptable choices for treating hypertension in pregnancy.
- A 30-year-old healthy woman is incidentally found to have a midsystolic click followed by a late systolic murmur at the apex, with a normal heart otherwise. Which valvular condition does this auscultatory finding suggest?
- Mitral valve prolapse
- Aortic stenosis
- Pulmonic stenosis
- Tricuspid regurgitation
Correct answer: Mitral valve prolapse
A midsystolic click followed by a late systolic murmur at the apex is the classic finding of mitral valve prolapse, caused by myxomatous leaflets billowing into the left atrium during systole. It is common and usually benign. Aortic and pulmonic stenosis produce ejection murmurs, and tricuspid regurgitation gives a different location and pattern.
- A 60-year-old man has a high-pitched, blowing, early diastolic decrescendo murmur at the left sternal border, a wide pulse pressure, and bounding pulses. Which valvular lesion produces this combination of findings?
- Mitral stenosis
- Chronic aortic regurgitation
- Aortic stenosis
- Pulmonic regurgitation
Correct answer: Chronic aortic regurgitation
Chronic aortic regurgitation produces an early diastolic decrescendo murmur at the left sternal border with a wide pulse pressure and bounding (water-hammer) pulses from the large stroke volume and rapid diastolic runoff. Mitral and aortic stenosis are systolic or diastolic with different qualities, and pulmonic regurgitation lacks the wide systemic pulse pressure.
- A 55-year-old man develops a holosystolic murmur loudest at the apex radiating to the axilla after an inferior myocardial infarction. Which valvular lesion does this murmur most likely represent?
- Aortic stenosis
- Tricuspid stenosis
- Pulmonic stenosis
- Mitral regurgitation
Correct answer: Mitral regurgitation
A holosystolic murmur at the apex radiating to the axilla is characteristic of mitral regurgitation, which can arise acutely after infarction from papillary muscle dysfunction. The regurgitant jet into the left atrium produces the typical radiation. Aortic and pulmonic stenosis give ejection murmurs at the base, and tricuspid stenosis is a right-sided diastolic lesion.
- A 40-year-old intravenous drug user develops fever and a new murmur, and blood cultures grow Staphylococcus aureus with vegetations seen on the tricuspid valve. Which valve is most commonly affected by infective endocarditis in intravenous drug users?
- The aortic valve
- The mitral valve
- The pulmonic valve
- The tricuspid valve
Correct answer: The tricuspid valve
In intravenous drug users, infective endocarditis most commonly involves the tricuspid valve because injected organisms enter the venous system and first reach the right side of the heart. Staphylococcus aureus is the typical organism. Left-sided valves such as the aortic and mitral are more often affected in other populations.
- A patient with subacute bacterial endocarditis has painless erythematous macules on the palms and soles and small retinal hemorrhages with pale centers. These peripheral findings of endocarditis are caused mainly by which process?
- Direct bacterial growth in the skin
- Immune complex deposition and septic microemboli
- Vitamin deficiency
- Allergic contact dermatitis
Correct answer: Immune complex deposition and septic microemboli
The peripheral stigmata of endocarditis, such as Janeway lesions, Osler nodes, and Roth spots, arise from septic microemboli and immune complex deposition from the infected valve. These reflect the systemic embolic and immunologic consequences of valvular vegetations. They are not from local skin infection, nutrient deficiency, or allergy.
- A patient with a prosthetic heart valve develops endocarditis after a dental procedure. Which organism group is a common cause of subacute endocarditis on abnormal or prosthetic valves following dental manipulation?
- Viridans group streptococci
- Clostridium tetani
- Mycobacterium tuberculosis
- Influenza virus
Correct answer: Viridans group streptococci
Viridans group streptococci, normal oral flora, are classic causes of subacute endocarditis after dental procedures, especially on previously damaged or prosthetic valves. They enter the bloodstream during dental manipulation and adhere to abnormal valve surfaces. Clostridium tetani, Mycobacterium tuberculosis, and influenza virus are not typical endocarditis pathogens in this setting.
- A 45-year-old man develops fever, pleuritic chest pain that improves when he leans forward, and a scratchy three-component friction rub on auscultation. Which diagnosis best fits this presentation?
- Aortic dissection
- Pulmonary embolism
- Stable angina
- Acute pericarditis
Correct answer: Acute pericarditis
Pleuritic chest pain relieved by sitting forward together with a three-component pericardial friction rub is classic for acute pericarditis, inflammation of the pericardial sac often following a viral illness. The position-dependent pain and rub distinguish it. Aortic dissection, pulmonary embolism, and stable angina do not produce a pericardial friction rub.
- A patient with a large, rapidly accumulating pericardial effusion develops hypotension, muffled heart sounds, and distended neck veins. This combination, indicating cardiac tamponade, threatens the heart primarily by which mechanism?
- External compression that impairs diastolic filling of the chambers
- Direct destruction of the myocardium by the fluid
- Sudden coronary thrombosis
- Rupture of the aortic valve
Correct answer: External compression that impairs diastolic filling of the chambers
Cardiac tamponade compromises the heart through external compression by pericardial fluid that raises intrapericardial pressure and impairs diastolic filling, reducing cardiac output. Beck triad of hypotension, muffled sounds, and jugular venous distention reflects this. The fluid does not destroy myocardium, cause coronary thrombosis, or rupture a valve.
- A patient with suspected cardiac tamponade is found to have an exaggerated drop in systolic blood pressure of more than 10 mm Hg during inspiration. This physical finding is termed which of the following?
- Pulsus parvus et tardus
- Pulsus alternans
- A water-hammer pulse
- Pulsus paradoxus
Correct answer: Pulsus paradoxus
Pulsus paradoxus is an exaggerated inspiratory fall in systolic blood pressure greater than 10 mm Hg, classically seen in cardiac tamponade because inspiratory filling of the right ventricle further compresses the constrained left ventricle. Pulsus parvus et tardus occurs in aortic stenosis, pulsus alternans in severe systolic dysfunction, and a water-hammer pulse in aortic regurgitation.
- A 60-year-old man with a history of tuberculosis develops fatigue, edema, and a pericardial knock, with calcified thickening of the pericardium on imaging. This presentation of impaired diastolic filling from a rigid pericardium is termed which condition?
- Constrictive pericarditis
- Dilated cardiomyopathy
- Acute myocarditis
- Mitral valve prolapse
Correct answer: Constrictive pericarditis
Constrictive pericarditis results from a thickened, often calcified, rigid pericardium that restricts diastolic filling, producing systemic congestion and a pericardial knock. Prior tuberculosis is a classic cause. Dilated cardiomyopathy, acute myocarditis, and mitral valve prolapse have different mechanisms and findings.
- A medical student studies the cardiac action potential. The rapid upstroke (phase 0) of the action potential in ventricular myocytes is generated by the influx of which ion?
- Potassium
- Sodium
- Chloride
- Magnesium
Correct answer: Sodium
The phase 0 rapid upstroke of the ventricular action potential is caused by a fast influx of sodium through voltage-gated sodium channels, depolarizing the cell. Potassium efflux later repolarizes the cell, while calcium influx maintains the plateau. Chloride and magnesium are not responsible for the rapid depolarizing upstroke.
- In the cardiac action potential of a ventricular myocyte, the prolonged plateau phase that distinguishes cardiac from skeletal muscle is maintained primarily by the influx of which ion?
- Sodium
- Potassium
- Bicarbonate
- Calcium
Correct answer: Calcium
The plateau phase of the cardiac action potential is maintained by calcium influx through L-type calcium channels, which balances potassium efflux and prolongs depolarization. This calcium entry also triggers calcium-induced calcium release for contraction. Sodium drives the initial upstroke, potassium drives repolarization, and bicarbonate is not involved.
- A 70-year-old man with degenerative conduction disease develops complete (third-degree) atrioventricular block. In this rhythm, what is the relationship between atrial and ventricular activity on the electrocardiogram?
- P waves and QRS complexes are independent of each other (atrioventricular dissociation)
- Every P wave is followed by a normal QRS
- The PR interval progressively lengthens until a beat drops
- There are no P waves at all
Correct answer: P waves and QRS complexes are independent of each other (atrioventricular dissociation)
In complete heart block no atrial impulses conduct to the ventricles, so the atria and ventricles beat independently and the P waves and QRS complexes show no fixed relationship, a pattern called atrioventricular dissociation. A ventricular escape rhythm drives the QRS. Progressive PR lengthening describes a different, lesser degree of block.
- A young athlete collapses suddenly during play and is found to be in a chaotic, disorganized ventricular rhythm with no effective cardiac output. Which arrhythmia is the most common immediate cause of sudden cardiac death in this setting?
- First-degree atrioventricular block
- Ventricular fibrillation
- Sinus bradycardia
- Atrial flutter with 4:1 conduction
Correct answer: Ventricular fibrillation
Ventricular fibrillation, a chaotic disorganized ventricular rhythm that produces no effective output, is the most common immediate cause of sudden cardiac death and requires immediate defibrillation. First-degree block, sinus bradycardia, and rate-controlled atrial flutter do not cause sudden loss of circulation in this way.
- A patient is found to have a prolonged QT interval and develops a polymorphic ventricular tachycardia with a twisting QRS axis. This rhythm, torsades de pointes, is best treated acutely with which intervention?
- Intravenous calcium gluconate
- An oral beta-agonist
- A class IA antiarrhythmic
- Intravenous magnesium
Correct answer: Intravenous magnesium
Torsades de pointes, a polymorphic ventricular tachycardia associated with QT prolongation, is treated acutely with intravenous magnesium, which stabilizes the myocardium and suppresses the arrhythmia. Class IA antiarrhythmics further prolong the QT and can worsen it, and calcium gluconate and beta-agonists are not the appropriate acute therapy.
- A baroreceptor reflex is activated when a person stands up and blood pressure transiently falls. Sensing this drop, the carotid sinus baroreceptors decrease their firing, leading to which compensatory response?
- Increased sympathetic outflow raising heart rate and vasoconstriction
- Increased parasympathetic outflow slowing the heart
- Direct dilation of arterioles
- Suppression of renin release
Correct answer: Increased sympathetic outflow raising heart rate and vasoconstriction
When blood pressure falls on standing, carotid baroreceptor firing decreases, and the brainstem responds by increasing sympathetic outflow and reducing parasympathetic tone, raising heart rate, contractility, and vascular resistance to restore pressure. The reflex does not increase vagal tone, directly dilate arterioles, or suppress renin in this hypotensive scenario.
- A physiologist measures the major site of resistance in the systemic circulation. Which vessels contribute most to systemic vascular resistance and are the primary regulators of blood pressure through changes in their diameter?
- Large elastic arteries
- Capillaries
- Large veins
- Arterioles
Correct answer: Arterioles
Arterioles are the major site of systemic vascular resistance because their small radius and muscular walls allow large changes in diameter that strongly affect resistance and therefore blood pressure. Large arteries serve as conduits and pressure reservoirs, capillaries are sites of exchange, and veins are capacitance vessels.
- A patient becomes dehydrated, and the body releases antidiuretic hormone (vasopressin). Beyond promoting water reabsorption, vasopressin helps support blood pressure by acting on which receptor to constrict vessels?
- The beta-1 receptor on the heart
- The V1 receptor on vascular smooth muscle
- The muscarinic receptor on glands
- The H2 receptor on parietal cells
Correct answer: The V1 receptor on vascular smooth muscle
Vasopressin supports blood pressure by acting on V1 receptors on vascular smooth muscle to cause vasoconstriction, in addition to its V2-mediated water retention in the kidney. This dual action helps defend pressure during volume loss. Beta-1, muscarinic, and H2 receptors are not the targets of vasopressin's vasoconstrictive effect.
- A 68-year-old man with critical limb ischemia from peripheral arterial disease has a nonhealing foot ulcer and rest pain. The rest pain of severe peripheral arterial disease occurs because the resting arterial supply can no longer meet which demand?
- The oxygen demand only during vigorous exercise
- The venous drainage requirement of the limb
- The basal metabolic oxygen needs of the distal tissues even without exertion
- The lymphatic clearance of the foot
Correct answer: The basal metabolic oxygen needs of the distal tissues even without exertion
Rest pain marks critical limb ischemia, in which the diseased arteries cannot supply even the basal metabolic oxygen needs of distal tissues at rest, unlike claudication which appears only with exertion. This advanced ischemia threatens limb viability. The problem is arterial inflow, not venous or lymphatic drainage.
- A 65-year-old man with suspected peripheral arterial disease has the ratio of ankle to brachial systolic blood pressure measured. A low ankle-brachial index, such as 0.6, indicates which condition?
- Normal arterial flow to the legs
- Chronic venous insufficiency only
- Significant arterial obstruction reducing distal perfusion pressure
- An arteriovenous fistula
Correct answer: Significant arterial obstruction reducing distal perfusion pressure
The ankle-brachial index compares ankle to arm systolic pressure, and a low value such as 0.6 indicates significant arterial obstruction that lowers distal perfusion pressure, confirming peripheral arterial disease. A normal index is about 1.0 to 1.4. Venous insufficiency and arteriovenous fistula do not produce a reduced ankle-brachial index in this way.
- A 30-year-old woman has fever, fatigue, and unequal blood pressures between her arms with absent pulses, and imaging shows inflammation and narrowing of the aorta and its major branches. This large-vessel granulomatous vasculitis affecting young women is best described as which condition?
- Kawasaki disease
- Buerger disease
- Takayasu arteritis
- Polyarteritis nodosa
Correct answer: Takayasu arteritis
Takayasu arteritis is a large-vessel granulomatous vasculitis affecting the aorta and its branches, typically in young women, producing diminished or absent pulses (the pulseless disease) and unequal arm blood pressures. Kawasaki disease affects children with coronary involvement, Buerger disease affects small and medium vessels in smokers, and polyarteritis nodosa spares the lungs and affects medium arteries.
- A 5-year-old boy has 6 days of high fever, conjunctival injection, red cracked lips, a rash, and cervical lymphadenopathy. The most serious cardiovascular complication of this vasculitis (Kawasaki disease) involves which structures?
- The cardiac valves, which fuse
- The coronary arteries, which can develop aneurysms
- The pericardium, which calcifies
- The aortic root, which dissects
Correct answer: The coronary arteries, which can develop aneurysms
Kawasaki disease is a medium-vessel vasculitis of childhood whose most feared complication is coronary artery aneurysm formation, which can lead to thrombosis or myocardial infarction. Prompt treatment with intravenous immunoglobulin reduces this risk. Valve fusion, pericardial calcification, and aortic dissection are not the hallmark complications.
- A 38-year-old man who is a heavy smoker develops painful ischemia and ulceration of the fingers and toes, with segmental thrombosing inflammation of small and medium arteries and veins of the extremities. Which condition, strongly linked to tobacco use, does this describe?
- Giant cell (temporal) arteritis
- Wegener granulomatosis
- Thromboangiitis obliterans (Buerger disease)
- Henoch-Schonlein purpura
Correct answer: Thromboangiitis obliterans (Buerger disease)
Thromboangiitis obliterans, or Buerger disease, is a smoking-associated segmental thrombosing vasculitis of small and medium vessels in the extremities, causing distal ischemia, ulceration, and gangrene in young male smokers. Smoking cessation is essential. Giant cell arteritis affects the temporal artery in older adults, and the other options are distinct vasculitides.
- A 9-month-old infant is cyanotic with episodes relieved by squatting, and echocardiography shows pulmonary stenosis, right ventricular hypertrophy, an overriding aorta, and a ventricular septal defect. Which cyanotic congenital heart disease is described?
- Atrial septal defect
- Coarctation of the aorta
- Tetralogy of Fallot
- Patent ductus arteriosus
Correct answer: Tetralogy of Fallot
Tetralogy of Fallot comprises pulmonary stenosis, right ventricular hypertrophy, an overriding aorta, and a ventricular septal defect, producing cyanosis with hypercyanotic spells relieved by squatting, which increases systemic resistance and reduces right-to-left shunting. Atrial septal defect, coarctation, and patent ductus arteriosus are acyanotic lesions in their usual forms.
- A newborn is deeply cyanotic immediately after birth, and imaging shows the aorta arising from the right ventricle and the pulmonary artery from the left ventricle. Survival in this transposition of the great arteries before surgery depends on which feature?
- Complete separation of the two circulations
- An intact ventricular septum with no shunt
- A mixing site such as a patent ductus or septal defect allowing oxygenated and deoxygenated blood to mix
- Closure of the foramen ovale at birth
Correct answer: A mixing site such as a patent ductus or septal defect allowing oxygenated and deoxygenated blood to mix
In transposition of the great arteries the systemic and pulmonary circulations run in parallel, so survival before surgical correction depends on a mixing site such as a patent ductus arteriosus, atrial septal defect, or ventricular septal defect that allows oxygenated and deoxygenated blood to mix. Complete separation or closure of mixing sites would be incompatible with life.
- A medical student studies fetal circulation. In the fetus, the ductus venosus serves which function before birth?
- Connecting the two ventricles directly
- Draining the coronary sinus into the aorta
- Allowing blood to bypass the kidneys
- Shunting oxygenated umbilical venous blood past the liver to the inferior vena cava
Correct answer: Shunting oxygenated umbilical venous blood past the liver to the inferior vena cava
The fetal ductus venosus shunts oxygen-rich blood from the umbilical vein past the hepatic circulation directly into the inferior vena cava, helping deliver oxygenated blood toward the heart. After birth it closes to become the ligamentum venosum. It does not connect the ventricles, drain the coronary sinus, or bypass the kidneys.
- A 50-year-old man with longstanding hypertension and a dilated aortic root develops chronic aortic regurgitation. Over time, the left ventricle adapts to the regurgitant volume load with which structural change?
- Eccentric hypertrophy with chamber dilation
- Concentric hypertrophy with a small cavity
- Atrophy of the ventricular wall
- Fatty replacement of the right ventricle
Correct answer: Eccentric hypertrophy with chamber dilation
Chronic aortic regurgitation imposes a volume overload, and the left ventricle adapts with eccentric hypertrophy, adding sarcomeres in series so the chamber dilates to accommodate the extra returning blood. This contrasts with the concentric hypertrophy of pressure overload such as aortic stenosis. Wall atrophy and right ventricular fatty replacement are not the adaptive response.
- A 16-year-old tall, thin boy collapses and dies during basketball, and autopsy shows a markedly thickened interventricular septum with disordered myocyte architecture. The sudden death in hypertrophic cardiomyopathy during exertion is most often the immediate result of which event?
- A slow sinus bradycardia
- A fatal ventricular arrhythmia
- Acute pulmonary embolism
- Rupture of the aorta
Correct answer: A fatal ventricular arrhythmia
In hypertrophic cardiomyopathy, the disorganized hypertrophied myocardium is electrically unstable, and sudden death during exertion most often results from a fatal ventricular arrhythmia such as ventricular fibrillation. This risk is why high-risk patients may receive an implantable defibrillator. Sinus bradycardia, pulmonary embolism, and aortic rupture are not the usual mechanism here.
- A 72-year-old man with severe peripheral arterial disease and diabetes is counseled that the single most important measure to slow progression of his atherosclerotic arterial disease is which intervention?
- Increasing dietary salt
- Avoiding all physical activity
- Smoking cessation
- Taking high-dose vitamin E
Correct answer: Smoking cessation
Smoking cessation is the single most important measure to slow progression of peripheral arterial disease, because tobacco strongly accelerates atherosclerosis and worsens limb outcomes. Supervised exercise also helps claudication, while increasing salt, avoiding activity, and high-dose vitamin E do not slow the disease and may be harmful.
- A 45-year-old man with poorly controlled hypertension is found to have polyarteritis nodosa, a necrotizing vasculitis of medium-sized arteries. Which feature distinguishes the typical organ involvement of polyarteritis nodosa?
- Prominent pulmonary artery involvement
- Renal and visceral artery involvement that classically spares the lungs
- Isolated involvement of the temporal artery
- Exclusive involvement of the coronary arteries
Correct answer: Renal and visceral artery involvement that classically spares the lungs
Polyarteritis nodosa is a necrotizing vasculitis of medium-sized arteries that classically involves the renal and visceral arteries while sparing the pulmonary arteries, often causing hypertension, abdominal pain, and microaneurysms on angiography. Pulmonary involvement, isolated temporal artery disease, and exclusive coronary involvement describe other vasculitides.
- A 58-year-old man with stable coronary disease is started on a long-acting nitrate for angina. To preserve the drug's effectiveness over time, patients are advised to observe which dosing practice?
- A daily nitrate-free interval to prevent tolerance
- Continuous around-the-clock dosing with no breaks
- Doubling the dose every week
- Taking it only after symptoms have resolved
Correct answer: A daily nitrate-free interval to prevent tolerance
Long-acting nitrates lose effectiveness if used continuously because tolerance develops, so a daily nitrate-free interval of several hours is recommended to restore responsiveness. Continuous uninterrupted dosing promotes tolerance, dose doubling is not the solution, and nitrates for prophylaxis are dosed on a schedule rather than only after symptoms resolve.
- A patient with chronic atrial fibrillation and rapid ventricular rates is given a rate-controlling drug that slows conduction through the atrioventricular node. Which property describes how digoxin slows the ventricular rate in this rhythm?
- By dilating the coronary arteries
- By blocking sodium channels in the atria
- By thickening the pericardium
- By increasing vagal tone at the atrioventricular node
Correct answer: By increasing vagal tone at the atrioventricular node
Digoxin slows the ventricular response in atrial fibrillation largely by enhancing vagal (parasympathetic) tone at the atrioventricular node, which prolongs nodal conduction and refractoriness so fewer impulses reach the ventricles. Coronary dilation, atrial sodium-channel blockade, and pericardial thickening do not account for its rate-controlling effect.
- A 24-year-old with allergic asthma is taught how rescue and controller inhalers differ. During an acute attack causing sudden wheezing, which inhaled medication provides the most rapid relief of bronchospasm?
- A short-acting beta-2 agonist such as albuterol
- An inhaled corticosteroid
- A leukotriene receptor antagonist
- A long-acting muscarinic antagonist
Correct answer: A short-acting beta-2 agonist such as albuterol
A short-acting beta-2 agonist is the answer. Albuterol rapidly relaxes airway smooth muscle by raising cyclic AMP, relieving acute bronchospasm within minutes, which is why it is the rescue inhaler. Inhaled corticosteroids and leukotriene antagonists are controllers that act over days, and long-acting muscarinic antagonists are maintenance agents not used for rapid rescue.
- A pulmonologist reviews the natural history of asthma and explains that the disease is defined functionally by reversibility. After a patient with airflow obstruction inhales a bronchodilator, what spirometric change confirms reversible obstruction consistent with asthma?
- A fall in FEV1 of at least 12 percent
- An FEV1 increase of at least 12 percent and 200 mL
- No change in FEV1
- A rise only in total lung capacity
Correct answer: An FEV1 increase of at least 12 percent and 200 mL
An FEV1 increase of at least 12 percent and 200 mL is the answer. Significant bronchodilator reversibility, defined as that degree of FEV1 improvement, supports asthma by showing the obstruction is reversible. A decline or no change does not demonstrate reversibility, and a rise in total lung capacity alone reflects hyperinflation rather than reversibility.
- A patient with worsening asthma is found to overuse a short-acting beta-2 agonist daily. Why can frequent reliance on a beta-2 agonist without controller therapy be associated with poorer asthma outcomes?
- It cures the underlying inflammation
- It permanently widens the airways
- It relieves bronchospasm without treating the underlying airway inflammation, masking worsening disease
- It increases the basement membrane thickness directly
Correct answer: It relieves bronchospasm without treating the underlying airway inflammation, masking worsening disease
It relieves bronchospasm without treating inflammation is the answer. A beta-2 agonist provides symptomatic bronchodilation but does not address the eosinophilic airway inflammation that drives asthma, so heavy reliance can mask deteriorating control and delay needed controller therapy. It does not cure inflammation or permanently alter airway caliber.
- A child with a known asthma diagnosis presents with a sudden severe attack, and the clinician assesses the degree of respiratory distress. Which physical finding indicates the patient is using accessory muscles because of severe airflow obstruction?
- Slow, comfortable breathing with a normal posture
- Speaking in full sentences without effort
- Complete absence of any breathing effort
- Visible suprasternal and intercostal retractions with tripod positioning
Correct answer: Visible suprasternal and intercostal retractions with tripod positioning
Suprasternal and intercostal retractions with tripod positioning is the answer. In a severe asthma exacerbation, increased work of breathing recruits accessory muscles, producing visible retractions and a forward-leaning tripod posture. Comfortable breathing and speaking in full sentences indicate mild disease, not severe obstruction.
- A medical student studies the inflammatory cascade in asthma and learns that arachidonic acid is metabolized by 5-lipoxygenase to potent bronchoconstrictors. Which drug inhibits this enzyme to reduce leukotriene production in asthma?
- Zileuton
- Albuterol
- Tiotropium
- Theophylline
Correct answer: Zileuton
Zileuton is the answer. Zileuton blocks 5-lipoxygenase, the enzyme that converts arachidonic acid into leukotrienes, reducing leukotriene-driven bronchoconstriction and inflammation. Albuterol is a beta agonist, tiotropium is an antimuscarinic, and theophylline is a methylxanthine, none of which inhibit 5-lipoxygenase.
- A patient hospitalized with a COPD exacerbation is found to have worsening hypercapnia and a depressed level of consciousness. Which complication of severe carbon dioxide retention explains the altered mental status?
- Hypocapnic cerebral vasoconstriction
- Carbon dioxide narcosis from severe hypercapnia
- Hyperventilation alkalosis
- Cerebral hyperoxia
Correct answer: Carbon dioxide narcosis from severe hypercapnia
Carbon dioxide narcosis is the answer. Severe hypercapnia in a COPD exacerbation depresses the central nervous system, causing confusion, somnolence, and eventually coma, a state called carbon dioxide narcosis. It is not from hypocapnia, hyperventilation alkalosis, or excess cerebral oxygen.
- A patient with severe emphysema and disabling dyspnea despite maximal therapy is evaluated for lung volume reduction surgery. What is the physiologic rationale for removing the most damaged emphysematous lung tissue?
- It adds new alveoli to the lung
- It increases mucus production
- It reduces hyperinflation so the remaining lung and diaphragm can function more efficiently
- It eliminates the need for any bronchodilators permanently
Correct answer: It reduces hyperinflation so the remaining lung and diaphragm can function more efficiently
Reducing hyperinflation to improve diaphragm and lung function is the answer. Resecting the most destroyed, hyperinflated regions decompresses the chest, allowing the diaphragm to return to a more favorable position and the better lung to expand, improving mechanics and dyspnea. It does not regenerate alveoli or increase mucus.
- A patient with COPD is counseled that pulmonary rehabilitation is recommended. Which is the primary benefit of a structured pulmonary rehabilitation program in COPD?
- It reverses the airflow obstruction to normal
- It cures the emphysema
- It raises the FEV1 to a normal value
- It improves exercise capacity, symptoms, and quality of life
Correct answer: It improves exercise capacity, symptoms, and quality of life
Improving exercise capacity, symptoms, and quality of life is the answer. Pulmonary rehabilitation combines exercise training, education, and support to enhance functional capacity and reduce dyspnea in COPD, even though it does not change the underlying FEV1 or reverse the structural disease. It does not cure emphysema or normalize spirometry.
- A patient with COPD has chronic productive cough most days for three months in each of two consecutive years. This clinical description specifically defines which component of the disease?
- Chronic bronchitis
- Emphysema
- Bronchiectasis
- Asthma
Correct answer: Chronic bronchitis
Chronic bronchitis is the answer. Chronic bronchitis is defined clinically by a productive cough on most days for at least three months in two consecutive years, reflecting mucus hypersecretion. Emphysema is defined anatomically by alveolar destruction, and bronchiectasis and asthma are distinct entities.
- A patient with an acute glomerulonephritis is told that the inflammation reduces the filtration surface and lowers the glomerular filtration rate. Which clinical consequence directly follows this acute drop in filtration?
- Polyuria with low creatinine
- Oliguria with rising serum creatinine and fluid retention
- Glucosuria without azotemia
- Complete absence of any laboratory change
Correct answer: Oliguria with rising serum creatinine and fluid retention
Oliguria with rising creatinine and fluid retention is the answer. Acute glomerular inflammation reduces filtration, so urine output falls, nitrogenous wastes accumulate, and salt and water are retained, producing edema and hypertension. The other patterns do not reflect the acute fall in glomerular filtration of nephritis.
- A patient with poststreptococcal glomerulonephritis is monitored for the antibodies indicating recent streptococcal infection. Which serologic test supports a recent group A streptococcal infection in this setting?
- Antinuclear antibody
- Anti-cyclic citrullinated peptide antibody
- Antistreptolysin O titer
- Antimitochondrial antibody
Correct answer: Antistreptolysin O titer
Antistreptolysin O titer is the answer. A rising antistreptolysin O (or anti-DNase B) titer documents recent group A streptococcal infection, supporting the diagnosis of poststreptococcal glomerulonephritis. Antinuclear, anti-cyclic citrullinated peptide, and antimitochondrial antibodies point to lupus, rheumatoid arthritis, and primary biliary cholangitis respectively.
- A patient with a nephritic glomerulonephritis has hypertension that the clinician attributes to the renal disease. Which mechanism most directly drives the hypertension in acute nephritic syndrome?
- Excess loss of sodium in the urine
- Decreased blood volume
- Loss of all renin secretion
- Salt and water retention from reduced glomerular filtration
Correct answer: Salt and water retention from reduced glomerular filtration
Salt and water retention from reduced filtration is the answer. The fall in glomerular filtration in nephritic syndrome causes the kidney to retain sodium and water, expanding intravascular volume and raising blood pressure. It is not driven by sodium loss, volume depletion, or absent renin.
- A 6-year-old develops dark, tea-colored urine and periorbital edema two weeks after a sore throat. Which urinary finding would best confirm that the bleeding is glomerular in origin?
- Dysmorphic red blood cells and red cell casts
- Clumps of squamous epithelial cells
- Numerous bacteria with nitrites
- Large amounts of glucose
Correct answer: Dysmorphic red blood cells and red cell casts
Dysmorphic red blood cells and red cell casts is the answer. Red cells deformed by passage through the glomerular basement membrane and red cell casts formed in the tubules localize bleeding to the glomerulus, confirming glomerulonephritis. Squamous cells, bacteria with nitrites, and glucosuria do not indicate glomerular bleeding.
- A patient with a mixed acid-base disorder has an arterial pH of 7.40 but an elevated anion gap and an abnormally high bicarbonate. What does a normal pH in the presence of these abnormalities most strongly suggest?
- A single simple acid-base disorder
- Two or more opposing acid-base disturbances coexisting
- A laboratory error in every value
- Pure respiratory compensation
Correct answer: Two or more opposing acid-base disturbances coexisting
Two or more opposing acid-base disturbances coexisting is the answer. A normal pH alongside a high anion gap and an elevated bicarbonate indicates a mixed disorder, such as a high anion gap metabolic acidosis combined with a metabolic alkalosis whose effects on pH offset each other. A single simple disorder would not produce this contradictory combination.
- A patient with severe shock has an arterial pH of 7.10 with a low bicarbonate, and the clinician explains that acidemia of this severity threatens cardiovascular function. Which cardiovascular effect is most characteristic of severe metabolic acidosis?
- Increased responsiveness to catecholamines
- Marked hypertension
- Decreased myocardial contractility and reduced responsiveness to catecholamines
- Bradycardia with high cardiac output
Correct answer: Decreased myocardial contractility and reduced responsiveness to catecholamines
Decreased myocardial contractility and reduced catecholamine responsiveness is the answer. Severe acidemia depresses cardiac contractility and blunts the response to endogenous and exogenous catecholamines, worsening hypotension in shock. It does not enhance catecholamine responsiveness or cause hypertension with high output.
- A medical student calculates a patient's anion gap and finds it is low at 4 mEq/L. Which condition is a recognized cause of a low (decreased) anion gap?
- Lactic acidosis
- Diabetic ketoacidosis
- Ethylene glycol poisoning
- Hypoalbuminemia
Correct answer: Hypoalbuminemia
Hypoalbuminemia is the answer. Albumin is the major unmeasured anion, so a low serum albumin lowers the calculated anion gap; the gap should be corrected upward for hypoalbuminemia. Lactic acidosis, diabetic ketoacidosis, and ethylene glycol poisoning all raise rather than lower the anion gap.
- A patient with chronic diarrhea has lost large amounts of intestinal fluid rich in bicarbonate. Why does this produce a normal anion gap rather than a high anion gap metabolic acidosis?
- Bicarbonate is lost and replaced by chloride, keeping unmeasured anions unchanged
- Lactic acid accumulates
- Ketoacids accumulate
- Sulfate anions accumulate
Correct answer: Bicarbonate is lost and replaced by chloride, keeping unmeasured anions unchanged
Bicarbonate replaced by chloride keeping unmeasured anions unchanged is the answer. Gastrointestinal bicarbonate loss is matched by a rise in chloride to maintain electroneutrality, so no new unmeasured anion is added and the anion gap stays normal (hyperchloremic acidosis). Lactate, ketoacids, and sulfate would instead widen the gap.
- A patient is given furosemide and the clinician explains where it acts. At which nephron segment does this loop diuretic inhibit sodium reabsorption?
- The proximal convoluted tubule
- The thick ascending limb of the loop of Henle
- The distal convoluted tubule
- The cortical collecting duct
Correct answer: The thick ascending limb of the loop of Henle
The thick ascending limb of the loop of Henle is the answer. Furosemide inhibits the sodium-potassium-2-chloride cotransporter in the thick ascending limb, producing a powerful diuresis. The proximal tubule, distal convoluted tubule, and collecting duct are the sites of other diuretic classes.
- A patient on high-dose intravenous furosemide develops new hearing loss that improves when the drug is stopped. Which adverse effect of loop diuretics does this represent?
- Nephrolithiasis
- Hyperkalemia
- Ototoxicity
- Hypoglycemia
Correct answer: Ototoxicity
Ototoxicity is the answer. Loop diuretics, especially at high doses or with rapid infusion, can cause reversible (and rarely permanent) ototoxicity by affecting ion transport in the inner ear. They cause hypokalemia rather than hyperkalemia and are not characteristically associated with stones or hypoglycemia.
- A medical student studies how loop diuretics produce such a large diuresis compared with thiazides. Which feature of the thick ascending limb explains the high potency of loop diuretics?
- It reabsorbs only a tiny fraction of filtered sodium
- It is the final site of urine concentration
- It is impermeable to all ions
- It reabsorbs a large fraction of filtered sodium, so blocking it produces a major natriuresis
Correct answer: It reabsorbs a large fraction of filtered sodium, so blocking it produces a major natriuresis
It reabsorbs a large fraction of filtered sodium is the answer. The thick ascending limb reclaims roughly a quarter of the filtered sodium, so inhibiting its transporter prevents reabsorption of a large solute load and produces a high-ceiling diuresis. The other statements misdescribe the segment's role.
- A patient with nephrotic syndrome has marked peripheral edema, and the clinician explains the role of low oncotic pressure. Which laboratory abnormality most directly reduces plasma oncotic pressure and contributes to the edema?
- Hypoalbuminemia from urinary protein loss
- Hyperkalemia
- Hypernatremia
- Hypercalcemia
Correct answer: Hypoalbuminemia from urinary protein loss
Hypoalbuminemia from urinary protein loss is the answer. Heavy urinary albumin loss lowers serum albumin, reducing plasma oncotic pressure so fluid shifts into the interstitium, producing the characteristic nephrotic edema. Potassium, sodium, and calcium abnormalities do not drive the oncotic-pressure-related edema of nephrosis.
- A child with nephrotic syndrome has heavy proteinuria, and the clinician explains the threshold that defines nephrotic-range proteinuria in adults. Which value defines nephrotic-range proteinuria?
- Greater than 150 milligrams per day
- Greater than 3.5 grams of protein per day
- Greater than 30 milligrams per day
- Any detectable protein
Correct answer: Greater than 3.5 grams of protein per day
Greater than 3.5 grams per day is the answer. Nephrotic-range proteinuria in adults is defined as urinary protein excretion exceeding about 3.5 grams in 24 hours, reflecting severe glomerular barrier injury. Lower thresholds describe normal limits or microalbuminuria rather than nephrotic-range loss.
- A patient with HIV develops nephrotic syndrome, and biopsy shows a collapsing variant with prominent tubular microcysts. Which glomerular disease is most characteristically associated with HIV infection?
- Minimal change disease
- Membranous nephropathy
- Collapsing focal segmental glomerulosclerosis
- Thin basement membrane disease
Correct answer: Collapsing focal segmental glomerulosclerosis
Collapsing focal segmental glomerulosclerosis is the answer. HIV-associated nephropathy classically manifests as a collapsing variant of focal segmental glomerulosclerosis with tubular microcysts and rapidly progressive renal failure. Minimal change, membranous, and thin basement membrane diseases are not the typical HIV-associated lesion.
- A patient with acute kidney injury is classified by the clinician according to the anatomic site of the problem. A blocked urethra from severe benign prostatic enlargement causing bilateral hydronephrosis represents which category of acute kidney injury?
- Prerenal
- Intrinsic (intrarenal)
- None of these because obstruction does not affect the kidney
- Postrenal
Correct answer: Postrenal
Postrenal is the answer. Obstruction downstream of the kidneys, such as urethral blockage causing bilateral hydronephrosis, defines postrenal acute kidney injury. Prerenal injury arises from reduced perfusion and intrinsic injury from direct renal parenchymal damage.
- A patient with prerenal acute kidney injury from hypovolemia has a fractional excretion of sodium below 1 percent. What does this low value indicate about tubular function?
- The tubules are intact and avidly reabsorbing sodium in response to low perfusion
- The tubules are severely damaged and wasting sodium
- The glomerulus has failed completely
- There is postrenal obstruction
Correct answer: The tubules are intact and avidly reabsorbing sodium in response to low perfusion
Intact tubules avidly reabsorbing sodium is the answer. A fractional excretion of sodium below 1 percent shows the tubules are functioning and conserving sodium in response to reduced perfusion, characteristic of prerenal azotemia. Tubular injury would impair sodium reabsorption and raise the fractional excretion above 2 percent.
- A patient develops acute kidney injury during severe heart failure with poor cardiac output. Which type of acute kidney injury does the low forward perfusion of cardiorenal syndrome most directly cause?
- Postobstructive injury
- Prerenal azotemia from renal hypoperfusion
- Acute glomerulonephritis
- Crystal-induced obstruction
Correct answer: Prerenal azotemia from renal hypoperfusion
Prerenal azotemia from renal hypoperfusion is the answer. Low cardiac output in heart failure reduces renal blood flow, producing a prerenal pattern of acute kidney injury (a component of cardiorenal syndrome) with avid sodium retention. It is not caused by obstruction, glomerular inflammation, or crystal deposition.
- A patient is found to have a normal anion gap metabolic acidosis with hypokalemia, an inability to acidify the urine, and recurrent calcium stones. Which renal tubular acidosis is most consistent with this picture?
- Type 4 (hyperkalemic) renal tubular acidosis
- Respiratory acidosis
- Type 1 (distal) renal tubular acidosis
- Lactic acidosis
Correct answer: Type 1 (distal) renal tubular acidosis
Type 1 (distal) renal tubular acidosis is the answer. Distal RTA features impaired hydrogen ion secretion with an inappropriately alkaline urine, hypokalemia, and a tendency to calcium phosphate stones and nephrocalcinosis. Type 4 RTA is hyperkalemic, and respiratory and lactic acidoses are different disorders.
- A clinician explains why type 2 (proximal) renal tubular acidosis is associated with hypokalemia. Which mechanism best accounts for the potassium loss in proximal RTA?
- Aldosterone deficiency
- Reduced distal sodium delivery
- Excess hydrogen ion secretion distally
- Bicarbonate spilling distally increases distal sodium delivery and potassium secretion
Correct answer: Bicarbonate spilling distally increases distal sodium delivery and potassium secretion
Bicarbonate spilling distally increasing distal sodium delivery and potassium secretion is the answer. In proximal RTA the reabsorptive threshold for bicarbonate is reduced, so bicarbonate and sodium reach the distal nephron, where increased sodium delivery enhances potassium secretion and causes hypokalemia. Aldosterone deficiency and reduced distal delivery describe other conditions.
- A patient with a deep vein thrombosis develops sudden dyspnea and pleuritic chest pain. The clinician explains that the most common source of a pulmonary embolus is a clot in which location?
- The deep veins of the proximal lower extremities
- The superficial veins of the hand
- The pulmonary veins
- The carotid artery
Correct answer: The deep veins of the proximal lower extremities
The deep veins of the proximal lower extremities is the answer. Most clinically significant pulmonary emboli originate from thrombi in the deep veins of the thighs and pelvis that dislodge and travel to the lungs. Superficial hand veins, pulmonary veins, and arteries are not the usual source of venous thromboemboli.
- A patient with a confirmed pulmonary embolism has a wedge-shaped peripheral lung opacity adjacent to the pleura on imaging. This Hampton hump represents which pathologic process?
- A lung abscess
- Pulmonary infarction of lung distal to the occluded vessel
- A pleural effusion
- Lobar pneumonia
Correct answer: Pulmonary infarction of lung distal to the occluded vessel
Pulmonary infarction is the answer. A Hampton hump is a peripheral, pleura-based wedge-shaped opacity caused by infarction of lung tissue distal to an occluded pulmonary artery branch. An abscess, effusion, and lobar pneumonia produce different radiographic appearances.
- A patient survives an acute pulmonary embolism but months later develops progressive dyspnea and pulmonary hypertension from organized, unresolved clot obstructing the pulmonary arteries. Which long-term complication is this?
- Asthma
- Emphysema
- Chronic thromboembolic pulmonary hypertension
- Pleural effusion
Correct answer: Chronic thromboembolic pulmonary hypertension
Chronic thromboembolic pulmonary hypertension is the answer. When emboli fail to resolve and become organized fibrotic obstructions, they raise pulmonary vascular resistance over time, producing chronic thromboembolic pulmonary hypertension with progressive dyspnea. Asthma, emphysema, and pleural effusion are unrelated to organized thromboembolic obstruction.
- A medical student studies how the kidney handles a sudden water load. After drinking a large volume of water, suppression of antidiuretic hormone allows the kidney to produce which type of urine?
- A small volume of concentrated urine
- No urine at all
- Urine identical to plasma osmolality
- A large volume of dilute urine
Correct answer: A large volume of dilute urine
A large volume of dilute urine is the answer. A water load lowers plasma osmolality and suppresses antidiuretic hormone, so the collecting duct stays relatively impermeable to water and the kidney excretes a large volume of dilute urine to restore balance. The other responses describe water conservation rather than water excretion.
- A patient with the syndrome of inappropriate antidiuretic hormone secretion has euvolemic hyponatremia. Which urine finding is characteristic of this disorder?
- Inappropriately concentrated urine with elevated urine sodium
- Maximally dilute urine
- Anuria
- Glucosuria
Correct answer: Inappropriately concentrated urine with elevated urine sodium
Inappropriately concentrated urine with elevated urine sodium is the answer. Excess antidiuretic hormone causes the kidney to retain water and concentrate the urine despite low serum osmolality, and the volume-expanded state leads to natriuresis with elevated urine sodium. Maximally dilute urine would indicate appropriate suppression of the hormone, the opposite of this syndrome.
- A patient with severe hyperglycemia from uncontrolled diabetes develops polyuria. Which mechanism best explains this osmotic diuresis?
- Excess antidiuretic hormone
- Filtered glucose exceeding the tubular maximum draws water into the tubular fluid
- Increased sodium reabsorption
- Reduced glomerular filtration
Correct answer: Filtered glucose exceeding the tubular maximum draws water into the tubular fluid
Filtered glucose exceeding the tubular maximum is the answer. When the filtered glucose load surpasses the proximal tubule transport maximum, unreabsorbed glucose remains in the tubule as an osmotic agent that holds water, producing an osmotic diuresis and polyuria. It is not caused by excess antidiuretic hormone, increased sodium reabsorption, or reduced filtration.
- A patient with chronic kidney disease has the glomerular filtration rate estimated from a serum marker, age, and sex using an equation rather than a timed urine collection. Which serum substance is used in these estimating equations?
- Glucose
- Albumin
- Creatinine
- Bilirubin
Correct answer: Creatinine
Creatinine is the answer. Estimated glomerular filtration rate equations use serum creatinine together with age and sex (and sometimes cystatin C) to approximate filtration without a timed urine collection. Glucose, albumin, and bilirubin are not used in these standard estimating equations.
- A patient with stage 5 chronic kidney disease and refractory volume overload, hyperkalemia, and uremia is evaluated for renal replacement therapy. What is the definitive long-term treatment that restores most kidney functions in suitable candidates?
- Lifelong oral diuretics alone
- A single session of dialysis
- A high-protein diet
- Kidney transplantation
Correct answer: Kidney transplantation
Kidney transplantation is the answer. A successful kidney transplant restores filtration, endocrine functions such as erythropoietin and vitamin D activation, and fluid-electrolyte balance, making it the definitive treatment for end-stage kidney disease in suitable patients. Diuretics, a single dialysis session, and dietary changes do not replace lost kidney function long term.
- A patient with cystic fibrosis is found to have a sweat chloride concentration that is markedly elevated. Why is sweat chloride high in cystic fibrosis?
- Defective CFTR cannot reabsorb chloride from sweat in the duct
- Excess aldosterone
- Increased sweating rate alone
- Loss of sodium channels in the skin
Correct answer: Defective CFTR cannot reabsorb chloride from sweat in the duct
Defective CFTR failing to reabsorb chloride from sweat is the answer. In sweat ducts, CFTR normally reabsorbs chloride from the duct lumen; when CFTR is defective, chloride and sodium remain in sweat, producing the elevated sweat chloride that is diagnostic of cystic fibrosis. It is not due to aldosterone, sweat rate, or loss of skin sodium channels.
- A young adult with cystic fibrosis has chronic sinusitis, nasal polyps, and bronchiectasis. Which gastrointestinal manifestation is also commonly seen because the same channel defect affects the pancreas?
- Peptic ulcer disease
- Pancreatic exocrine insufficiency with malabsorption
- Lactose intolerance
- Hepatitis B infection
Correct answer: Pancreatic exocrine insufficiency with malabsorption
Pancreatic exocrine insufficiency with malabsorption is the answer. Thick secretions plug pancreatic ducts in cystic fibrosis, destroying exocrine tissue and causing enzyme deficiency with malabsorption and steatorrhea. Peptic ulcer disease, lactose intolerance, and hepatitis B are not the characteristic CFTR-related pancreatic manifestation.
- A medical student reviews the partial pressures of gases in the alveolus. At sea level breathing room air, why is the alveolar partial pressure of oxygen lower than the partial pressure of oxygen in inspired atmospheric air?
- Oxygen is destroyed in the alveolus
- The alveolus actively pumps oxygen out
- Water vapor and carbon dioxide in the alveolus dilute and displace oxygen
- Nitrogen is removed from the alveolus
Correct answer: Water vapor and carbon dioxide in the alveolus dilute and displace oxygen
Water vapor and carbon dioxide diluting and displacing oxygen is the answer. As air enters the airways it is humidified, adding water vapor, and in the alveolus it mixes with carbon dioxide; both lower the partial pressure of oxygen below that of dry inspired atmospheric air. Oxygen is not destroyed or pumped out, and nitrogen remains present.
- A patient at high altitude has a lower arterial oxygen content despite increased ventilation. Which change in inspired air at altitude is the fundamental cause of the hypoxemia?
- A lower fraction of oxygen in the air
- An increase in carbon dioxide in the atmosphere
- A rise in inspired oxygen pressure
- A lower barometric pressure reducing the partial pressure of inspired oxygen
Correct answer: A lower barometric pressure reducing the partial pressure of inspired oxygen
Lower barometric pressure reducing the partial pressure of inspired oxygen is the answer. The fraction of oxygen in air stays about 21 percent at altitude, but the reduced barometric pressure lowers the partial pressure of inspired oxygen, decreasing the driving pressure for oxygen uptake and causing hypoxemia. The oxygen fraction and atmospheric carbon dioxide do not change meaningfully.
- A clinician explains that oxygen diffusion across the alveolar-capillary membrane is normally perfusion-limited rather than diffusion-limited. What does perfusion-limited transfer mean for oxygen uptake in a healthy lung?
- Equilibration occurs quickly, so uptake depends mainly on blood flow
- Oxygen never reaches equilibrium with alveolar gas
- Uptake depends only on the thickness of the membrane
- Oxygen is actively transported across the membrane
Correct answer: Equilibration occurs quickly, so uptake depends mainly on blood flow
Equilibration occurring quickly so uptake depends on blood flow is the answer. In the normal lung, oxygen equilibrates between alveolus and capillary blood well before the red cell leaves the capillary, so the amount taken up is limited by how much blood flows, not by diffusion. Oxygen transfer is passive and reaches equilibrium under normal conditions.
- A patient with pneumonia has hypoxemia, and the clinician explains the local response that limits worsening of gas exchange. When an alveolus is poorly ventilated, hypoxic pulmonary vasoconstriction does what?
- Increases blood flow to the poorly ventilated alveolus
- Diverts blood away from poorly ventilated alveoli toward better-ventilated regions
- Dilates the airway
- Stops all pulmonary blood flow
Correct answer: Diverts blood away from poorly ventilated alveoli toward better-ventilated regions
Diverting blood away from poorly ventilated alveoli is the answer. Hypoxic pulmonary vasoconstriction constricts vessels supplying underventilated alveoli, redirecting blood to better-ventilated lung to improve ventilation-perfusion matching and limit hypoxemia. It does not increase flow to the hypoxic region, dilate airways, or halt all pulmonary flow.
- A patient with massive obesity develops chronic daytime hypercapnia and hypoxemia not explained by intrinsic lung disease, with hypoventilation worsened by body habitus. Which condition does this describe?
- Idiopathic pulmonary fibrosis
- Asthma
- Obesity hypoventilation syndrome
- Pulmonary embolism
Correct answer: Obesity hypoventilation syndrome
Obesity hypoventilation syndrome is the answer. Severe obesity can mechanically restrict ventilation and blunt the respiratory drive, producing chronic daytime hypercapnia and hypoxemia in the absence of another explanation, often with coexisting sleep-disordered breathing. Fibrosis, asthma, and embolism are distinct entities with different mechanisms.
- A medical student studies how carbon dioxide affects the binding of oxygen to hemoglobin. The Bohr effect describes how an increase in carbon dioxide and hydrogen ions in the tissues does what to oxygen delivery?
- Increases hemoglobin affinity for oxygen
- Prevents any oxygen unloading
- Converts oxygen to carbon dioxide
- Promotes release of oxygen from hemoglobin to the tissues
Correct answer: Promotes release of oxygen from hemoglobin to the tissues
Promoting release of oxygen from hemoglobin to the tissues is the answer. The Bohr effect means that rising carbon dioxide and hydrogen ion concentrations in metabolically active tissue lower hemoglobin oxygen affinity, enhancing oxygen unloading where it is needed. It increases, rather than prevents, oxygen delivery and does not raise affinity.
- A patient with severe scoliosis and a neuromuscular disease has chronic hypoventilation. Which arterial blood gas pattern is expected from chronic alveolar hypoventilation?
- Elevated carbon dioxide with a compensatory rise in bicarbonate
- Low carbon dioxide with high pH
- Normal carbon dioxide with low bicarbonate
- A pure metabolic acidosis
Correct answer: Elevated carbon dioxide with a compensatory rise in bicarbonate
Elevated carbon dioxide with a compensatory rise in bicarbonate is the answer. Chronic hypoventilation retains carbon dioxide, producing a respiratory acidosis that the kidney compensates for over time by retaining bicarbonate. Low carbon dioxide would indicate hyperventilation, and a primary metabolic acidosis is a different disturbance.
- A pathologist describes the gas-exchange surface of the lung. Which structure forms the thin barrier across which oxygen and carbon dioxide diffuse between alveolar air and capillary blood?
- The bronchial cartilage
- The fused basement membranes of type I pneumocytes and capillary endothelium
- The visceral pleura
- The mucus layer of the bronchi
Correct answer: The fused basement membranes of type I pneumocytes and capillary endothelium
The fused basement membranes of type I pneumocytes and capillary endothelium is the answer. Gas exchange occurs across the thin alveolar-capillary membrane formed by flat type I pneumocytes, the capillary endothelium, and their fused basement membranes, minimizing diffusion distance. Bronchial cartilage, pleura, and bronchial mucus are not the gas-exchange barrier.
- A patient with diffuse alveolar damage has injury to the cells that produce surfactant. Which cell type, when damaged, also serves as the progenitor that regenerates the alveolar lining?
- Type I pneumocytes
- Goblet cells
- Type II pneumocytes
- Ciliated cells
Correct answer: Type II pneumocytes
Type II pneumocytes are the answer. Type II pneumocytes both secrete surfactant and act as stem cells that proliferate to replace damaged type I pneumocytes after alveolar injury. Type I pneumocytes are terminally differentiated, and goblet and ciliated cells line the conducting airways rather than the alveoli.
- A 70-year-old long-term smoker presents with a central, cavitating lung mass that on biopsy shows keratin pearls and intercellular bridges. Which type of lung cancer is this?
- Adenocarcinoma
- Small cell carcinoma
- Bronchial carcinoid
- Squamous cell carcinoma
Correct answer: Squamous cell carcinoma
Squamous cell carcinoma is the answer. Keratin pearls and intercellular bridges are the histologic hallmarks of squamous cell carcinoma, which is typically central, strongly linked to smoking, and prone to cavitation. Adenocarcinoma is glandular and peripheral, small cell is neuroendocrine, and carcinoid is a low-grade neuroendocrine tumor.
- A patient with a lung mass undergoes biopsy showing small round blue cells with scant cytoplasm, nuclear molding, and very high mitotic activity, expressing neuroendocrine markers. Which aggressive lung cancer is this?
- Small cell carcinoma
- Squamous cell carcinoma
- Adenocarcinoma in situ
- Hamartoma
Correct answer: Small cell carcinoma
Small cell carcinoma is the answer. Small cell lung carcinoma is a highly aggressive neuroendocrine tumor of small round blue cells with nuclear molding and frequent paraneoplastic syndromes, strongly associated with smoking. Squamous and adenocarcinoma have different histology, and a hamartoma is a benign lung lesion.
- A patient with a peripheral lung adenocarcinoma is found to have an activating mutation that can be targeted with a specific oral inhibitor. Which mutation is a classic targetable driver in lung adenocarcinoma?
- BCR-ABL fusion
- Epidermal growth factor receptor (EGFR) mutation
- Factor V Leiden
- JAK2 V617F
Correct answer: Epidermal growth factor receptor (EGFR) mutation
Epidermal growth factor receptor mutation is the answer. Activating EGFR mutations are common targetable drivers in lung adenocarcinoma, particularly in nonsmokers, and respond to specific tyrosine kinase inhibitors. BCR-ABL drives chronic myeloid leukemia, factor V Leiden is a thrombophilia, and JAK2 V617F drives myeloproliferative disorders.
- A patient on chronic potassium-wasting diuretics is found to have hypokalemia. Beyond cardiac effects, hypokalemia from renal potassium loss can impair which kidney function, causing polyuria?
- Glomerular filtration of proteins
- Distal acidification by intercalated cells
- The urinary concentrating ability of the collecting duct
- Erythropoietin production
Correct answer: The urinary concentrating ability of the collecting duct
The urinary concentrating ability of the collecting duct is the answer. Chronic hypokalemia impairs the collecting duct response to antidiuretic hormone, reducing concentrating ability and producing a nephrogenic-type polyuria. It is not primarily a defect of protein filtration, distal acidification, or erythropoietin output.
- A patient with chronic kidney disease has hyperkalemia, and the team uses a potassium binder that exchanges sodium for potassium in the gut to lower serum potassium over time. Where does this resin act to remove potassium from the body?
- The renal collecting duct
- The pulmonary alveoli
- The cardiac myocytes
- The gastrointestinal tract
Correct answer: The gastrointestinal tract
The gastrointestinal tract is the answer. Cation-exchange potassium binders work in the gut lumen, exchanging cations for potassium so that potassium is excreted in the stool, lowering total body potassium over hours to days. They do not act in the collecting duct, alveoli, or heart.
- A patient develops hyperkalemia from acidosis, and the clinician explains the transcellular shift. How does acidemia raise serum potassium?
- Hydrogen ions move into cells in exchange for potassium moving out
- Potassium moves into cells
- Potassium is excreted faster by the kidney
- Aldosterone rises and drives potassium into cells
Correct answer: Hydrogen ions move into cells in exchange for potassium moving out
Hydrogen ions moving into cells in exchange for potassium moving out is the answer. In acidemia, excess extracellular hydrogen ions enter cells and potassium shifts out to maintain electroneutrality, raising serum potassium independent of total body stores. Acidosis does not drive potassium into cells or accelerate its renal excretion in this acute shift.
- A patient with heart failure and excessive sodium intake develops worsening edema. The kidney normally defends against volume expansion through pressure natriuresis. What does pressure natriuresis describe?
- Sodium retention when blood pressure rises
- Increased sodium and water excretion when arterial pressure rises
- Decreased urine output with higher pressure
- Potassium excretion driven by low pressure
Correct answer: Increased sodium and water excretion when arterial pressure rises
Increased sodium and water excretion when arterial pressure rises is the answer. Pressure natriuresis is the kidney's intrinsic response in which a rise in renal perfusion pressure increases sodium and water excretion, helping return blood volume and pressure toward normal. It is not sodium retention, reduced output, or a low-pressure potassium response.
- A patient with severe heart failure has intense activation of the renin-angiotensin-aldosterone system and avid sodium retention. Why does the failing heart trigger this sodium-retaining response despite total body fluid overload?
- The kidney senses high sodium directly
- Increased atrial natriuretic peptide drives retention
- Reduced effective arterial blood volume is sensed as underperfusion
- Aldosterone is suppressed
Correct answer: Reduced effective arterial blood volume is sensed as underperfusion
Reduced effective arterial blood volume sensed as underperfusion is the answer. In heart failure, low cardiac output reduces the effective arterial blood volume, which baroreceptors and the kidney interpret as hypovolemia, activating the renin-angiotensin-aldosterone system to retain sodium even though the patient is fluid-overloaded. Atrial natriuretic peptide rises but is outweighed, and aldosterone is elevated.
- A patient with mild renal insufficiency takes a calcium-based phosphate binder with meals. How does this medication help control hyperphosphatemia in kidney disease?
- It increases urinary phosphate excretion
- It blocks phosphate production in the liver
- It stimulates parathyroid hormone
- It binds dietary phosphate in the gut, reducing its absorption
Correct answer: It binds dietary phosphate in the gut, reducing its absorption
Binding dietary phosphate in the gut is the answer. Phosphate binders taken with food bind phosphate in the intestinal lumen so less is absorbed, lowering serum phosphate when the failing kidney can no longer excrete it adequately. They do not increase urinary phosphate, block hepatic production, or stimulate parathyroid hormone.
- A medical student studies how filtration is determined at the glomerulus. According to the forces of filtration, which pressure is the primary driving force that pushes fluid out of the glomerular capillary into Bowman space?
- Glomerular capillary hydrostatic pressure
- Bowman space hydrostatic pressure
- Plasma oncotic pressure
- Interstitial oncotic pressure
Correct answer: Glomerular capillary hydrostatic pressure
Glomerular capillary hydrostatic pressure is the answer. The high hydrostatic pressure within the glomerular capillaries is the main force driving plasma filtration into Bowman space, opposed by Bowman space hydrostatic pressure and plasma oncotic pressure. Those opposing forces reduce, rather than drive, filtration.
- A patient is given an angiotensin-converting enzyme inhibitor, and besides lowering angiotensin II it also reduces breakdown of a vasodilator peptide. Accumulation of which substance accounts for the dry cough sometimes caused by these drugs?
- Aldosterone
- Bradykinin
- Renin
- Antidiuretic hormone
Correct answer: Bradykinin
Bradykinin is the answer. Angiotensin-converting enzyme also degrades bradykinin, so inhibiting the enzyme allows bradykinin to accumulate, which can provoke a dry cough and contributes to vasodilation. Aldosterone, renin, and antidiuretic hormone do not cause this characteristic cough.
- A patient breathes 100 percent oxygen for several minutes, and the clinician calculates the shunt fraction. Why does a true anatomic shunt cause hypoxemia that does not fully correct even on 100 percent oxygen?
- Oxygen cannot dissolve in plasma
- The alveoli collapse with high oxygen
- Shunted blood never contacts ventilated alveoli, so it cannot pick up the extra oxygen
- Carbon dioxide blocks oxygen uptake
Correct answer: Shunted blood never contacts ventilated alveoli, so it cannot pick up the extra oxygen
Shunted blood never contacting ventilated alveoli is the answer. In a true shunt, deoxygenated blood bypasses ventilated alveoli entirely, so raising the inspired oxygen cannot oxygenate that fraction, and the mixed arterial oxygen remains low. The failure to correct is not due to oxygen solubility, alveolar collapse from oxygen, or carbon dioxide.
- A medical student studies dead space ventilation. Physiologic dead space includes the anatomic dead space plus which additional component in disease?
- Alveoli that are perfused but not ventilated
- The volume of blood in the capillaries
- The residual volume
- Alveoli that are ventilated but not perfused
Correct answer: Alveoli that are ventilated but not perfused
Alveoli that are ventilated but not perfused is the answer. Physiologic dead space equals the conducting-airway anatomic dead space plus alveolar dead space, which consists of alveoli that receive ventilation but no perfusion and therefore do not exchange gas. Perfused but unventilated alveoli constitute shunt, not dead space.
- A patient with chronic kidney disease has secondary hyperparathyroidism, and the clinician explains the role of a hormone made by bone that rises early in kidney disease and promotes phosphate excretion. Which hormone is this?
- Fibroblast growth factor 23
- Erythropoietin
- Renin
- Insulin
Correct answer: Fibroblast growth factor 23
Fibroblast growth factor 23 is the answer. As kidney function declines, bone-derived fibroblast growth factor 23 rises to promote urinary phosphate excretion and suppress active vitamin D, an early adaptation in the mineral disturbances of chronic kidney disease. Erythropoietin, renin, and insulin do not perform this phosphaturic role.
- A patient has a renal stone analyzed and is counseled on dietary measures. For a patient with recurrent calcium oxalate stones, why is severe dietary calcium restriction generally NOT recommended?
- Low calcium dissolves existing stones
- Low dietary calcium increases intestinal oxalate absorption and can raise urinary oxalate
- Calcium has no effect on oxalate
- Low calcium raises urine pH
Correct answer: Low dietary calcium increases intestinal oxalate absorption and can raise urinary oxalate
Low dietary calcium increasing intestinal oxalate absorption is the answer. Adequate dietary calcium binds oxalate in the gut, reducing its absorption; severe restriction frees more oxalate to be absorbed and excreted, paradoxically increasing urinary oxalate and stone risk. Calcium restriction does not dissolve stones or alter urine pH in a helpful way.
- A patient with a small, nonobstructing ureteral stone and controlled pain is managed conservatively while the stone is allowed to pass. Which size of ureteral stone is most likely to pass spontaneously without intervention?
- A staghorn calculus filling the renal pelvis
- A stone larger than 1 centimeter
- A stone smaller than about 5 millimeters
- Any size passes equally easily
Correct answer: A stone smaller than about 5 millimeters
A stone smaller than about 5 millimeters is the answer. Small ureteral stones, generally under 5 millimeters, have a high likelihood of passing spontaneously, whereas larger stones are more likely to obstruct and require intervention. A staghorn calculus and stones over 1 centimeter rarely pass on their own.
- A patient develops pneumonia in the hospital 5 days after admission and grows a resistant gram-negative organism. Which category does this infection represent, with implications for broader antibiotic coverage?
- Community-acquired pneumonia
- Aspiration pneumonitis from gastric acid alone
- Atypical walking pneumonia
- Hospital-acquired (nosocomial) pneumonia
Correct answer: Hospital-acquired (nosocomial) pneumonia
Hospital-acquired pneumonia is the answer. Pneumonia developing 48 hours or more after admission is classified as hospital-acquired and is more likely to involve resistant gram-negative organisms, warranting broader empiric coverage. Community-acquired and atypical pneumonias arise outside the hospital, and chemical aspiration pneumonitis is a distinct process.
- A patient receiving mechanical ventilation develops a new fever, purulent secretions, and a new infiltrate after several days on the ventilator. Which type of pneumonia is most likely?
- Ventilator-associated pneumonia
- Lobar pneumococcal pneumonia acquired before admission
- Pneumocystis pneumonia
- Bronchiolitis
Correct answer: Ventilator-associated pneumonia
Ventilator-associated pneumonia is the answer. Pneumonia developing more than 48 hours after endotracheal intubation is ventilator-associated, often caused by resistant organisms introduced past the airway defenses. Community pneumococcal pneumonia, Pneumocystis in immunosuppression, and bronchiolitis in infants are different scenarios.
- A patient develops acute respiratory distress syndrome, and the clinician explains the underlying alveolar injury. Which descriptive pathologic term best captures the lung injury in this syndrome?
- Reversible bronchospasm
- Diffuse alveolar damage with increased capillary permeability
- Pure chronic fibrosis
- Isolated pleural inflammation
Correct answer: Diffuse alveolar damage with increased capillary permeability
Diffuse alveolar damage with increased capillary permeability is the answer. Acute respiratory distress syndrome is characterized pathologically by diffuse alveolar damage in which inflammation injures the alveolar-capillary barrier, allowing protein-rich fluid to flood the alveoli and impair oxygenation. It is not reversible bronchospasm, chronic fibrosis alone, or isolated pleural disease.
- A patient with a transudative pleural effusion from heart failure is treated. Which intervention most directly addresses the underlying cause of a transudative effusion?
- Administering pleural antibiotics
- Pleural decortication
- Treating the heart failure to lower hydrostatic pressure
- Chemotherapy to the pleura
Correct answer: Treating the heart failure to lower hydrostatic pressure
Treating the heart failure to lower hydrostatic pressure is the answer. A transudative effusion from heart failure reflects elevated pulmonary capillary hydrostatic pressure, so managing the heart failure with diuresis and afterload reduction reduces the effusion. Antibiotics, decortication, and chemotherapy target infectious or malignant exudative processes, not a transudate.
- A patient with recurrent malignant pleural effusions undergoes a procedure to instill an irritant that fuses the pleural layers and prevents fluid reaccumulation. What is this procedure called?
- Thoracentesis alone
- Bronchoscopy
- Pericardiocentesis
- Pleurodesis
Correct answer: Pleurodesis
Pleurodesis is the answer. Pleurodesis introduces a sclerosing agent into the pleural space to inflame and adhere the visceral and parietal pleura, obliterating the space so recurrent effusions cannot accumulate. Thoracentesis only drains fluid, bronchoscopy examines airways, and pericardiocentesis drains the pericardium.
- A patient who quit smoking years ago still has fixed airflow obstruction. The clinician explains that the elastic recoil lost in emphysema affects expiration. Why does loss of elastic recoil cause airflow limitation during exhalation?
- The airways lose the radial traction that normally holds them open, so they collapse during expiration
- The airways become rigid and overdilated
- Mucus is completely cleared
- The diaphragm becomes stronger
Correct answer: The airways lose the radial traction that normally holds them open, so they collapse during expiration
Loss of radial traction allowing airway collapse is the answer. Alveolar walls normally tether and hold small airways open; when emphysema destroys these attachments, the airways lose radial traction and collapse during the positive pleural pressure of expiration, trapping air. The airways do not become rigid or overdilated, and clearing mucus would not cause this.
- A patient with severe sepsis has a high anion gap metabolic acidosis from lactate, and the clinician monitors the serum lactate to gauge tissue perfusion. A rising lactate in this setting most directly reflects what?
- Improving oxygen delivery
- Inadequate tissue oxygen delivery driving anaerobic metabolism
- Excess renal bicarbonate generation
- Respiratory alkalosis alone
Correct answer: Inadequate tissue oxygen delivery driving anaerobic metabolism
Inadequate tissue oxygen delivery driving anaerobic metabolism is the answer. When oxygen delivery to tissues is insufficient, cells generate lactate through anaerobic glycolysis, so a rising lactate signals worsening tissue hypoperfusion and a high anion gap acidosis. It does not indicate improving delivery, bicarbonate generation, or a respiratory alkalosis.
- A patient with renal artery stenosis is being evaluated, and the clinician describes how reduced perfusion to one kidney raises blood pressure. Reduced perfusion stimulates renin release, which ultimately generates which potent vasoconstrictor?
- Bradykinin
- Nitric oxide
- Angiotensin II
- Atrial natriuretic peptide
Correct answer: Angiotensin II
Angiotensin II is the answer. Renin from the underperfused kidney cleaves angiotensinogen to angiotensin I, which is converted to angiotensin II, a potent vasoconstrictor that also stimulates aldosterone, raising blood pressure in renovascular hypertension. Bradykinin and nitric oxide are vasodilators, and atrial natriuretic peptide promotes natriuresis.
- A patient with poorly controlled diabetes is found to have an early sign of diabetic kidney disease in which the glomerular filtration rate is actually elevated above normal. What is this early phase called?
- End-stage renal disease
- Acute tubular necrosis
- Renal artery stenosis
- Glomerular hyperfiltration
Correct answer: Glomerular hyperfiltration
Glomerular hyperfiltration is the answer. Early in diabetic nephropathy, increased glomerular pressure causes a phase of hyperfiltration with an elevated glomerular filtration rate before structural damage and declining function ensue. This is distinct from end-stage disease, acute tubular necrosis, and renal artery stenosis.
- A patient with diabetic nephropathy is counseled that controlling one modifiable factor most strongly slows progression of proteinuric kidney disease. Which intervention is most important for slowing diabetic nephropathy?
- Tight blood pressure and blood glucose control with renin-angiotensin blockade
- High protein intake
- Routine nephrotoxic analgesics
- Restricting all fluid intake
Correct answer: Tight blood pressure and blood glucose control with renin-angiotensin blockade
Tight blood pressure and glucose control with renin-angiotensin blockade is the answer. Aggressive control of blood pressure and glucose, together with angiotensin-converting enzyme inhibitors or angiotensin receptor blockers to reduce intraglomerular pressure and proteinuria, most effectively slows diabetic nephropathy. High protein intake, nephrotoxic analgesics, and indiscriminate fluid restriction are not protective.
- A patient with chronic kidney disease is started on an erythropoiesis-stimulating agent for anemia. What is the most important laboratory parameter to monitor and supplement to ensure the agent works effectively?
- Serum calcium
- Iron stores
- Serum bicarbonate
- White blood cell count
Correct answer: Iron stores
Iron stores are the answer. Erythropoiesis-stimulating agents require adequate iron to make hemoglobin, so iron deficiency must be identified and corrected for the agent to raise the hemoglobin effectively in renal anemia. Calcium, bicarbonate, and white cell count are not the limiting factor for the agent's efficacy.
- A patient with severe community-acquired pneumonia develops a paraneumonic effusion, and the clinician samples the fluid to decide whether a chest tube is needed. Which pleural fluid finding indicates a complicated effusion requiring drainage?
- A high pleural fluid glucose with normal pH
- A clear transudate
- A low pleural fluid pH and low glucose with positive gram stain
- Absence of any cells
Correct answer: A low pleural fluid pH and low glucose with positive gram stain
A low pH and low glucose with positive gram stain is the answer. A complicated parapneumonic effusion or empyema shows a low pleural fluid pH and glucose and may have organisms on gram stain, indicating that simple antibiotics will not suffice and drainage is required. Normal pH and glucose suggest an uncomplicated effusion that may resolve with antibiotics alone.
- A patient with chronic respiratory acidosis from COPD has a near-normal pH. Which renal change over days provides the metabolic compensation that returns the pH toward normal?
- Increased renal bicarbonate excretion
- Decreased ammonium production
- Increased urinary acid loss stopping
- Increased renal bicarbonate reabsorption and generation
Correct answer: Increased renal bicarbonate reabsorption and generation
Increased renal bicarbonate reabsorption and generation is the answer. In chronic respiratory acidosis, the kidney compensates by reabsorbing and generating more bicarbonate (with increased ammonium excretion of acid), raising serum bicarbonate to buffer the retained carbon dioxide and normalize pH. Excreting bicarbonate or reducing ammonium would worsen the acidosis.
- A patient is found to have a single nonfunctioning kidney that never developed, an absence of renal tissue on one side present since birth. Which congenital condition does this describe?
- Unilateral renal agenesis
- Acute tubular necrosis
- Renal cell carcinoma
- Acute pyelonephritis
Correct answer: Unilateral renal agenesis
Unilateral renal agenesis is the answer. Failure of one kidney to form during development results in unilateral renal agenesis, in which the remaining kidney typically hypertrophies to compensate. Acute tubular necrosis, renal cell carcinoma, and pyelonephritis are acquired conditions, not congenital absence of a kidney.
- A neonate with oligohydramnios is born with characteristic facial compression, limb deformities, and pulmonary hypoplasia. This Potter sequence results from severely reduced amniotic fluid, which is most directly caused by which fetal problem?
- Excess fetal swallowing
- Inadequate fetal urine output from bilateral renal anomalies
- Maternal diabetes alone
- A single umbilical artery alone
Correct answer: Inadequate fetal urine output from bilateral renal anomalies
Inadequate fetal urine output from bilateral renal anomalies is the answer. Fetal urine is the major source of amniotic fluid in later gestation, so bilateral renal agenesis or severe renal anomalies cause oligohydramnios, leading to the compression deformities and pulmonary hypoplasia of Potter sequence. Excess swallowing, maternal diabetes, and a single umbilical artery do not explain the oligohydramnios here.
- A child is found on imaging to have a kidney that crossed the midline and fused with the lower pole of the other kidney, with the isthmus trapped under the inferior mesenteric artery. Which congenital anomaly is this?
- Polycystic kidney disease
- Renal agenesis
- Horseshoe kidney
- Medullary sponge kidney
Correct answer: Horseshoe kidney
Horseshoe kidney is the answer. A horseshoe kidney forms when the lower poles fuse across the midline and the ascending kidney is caught beneath the inferior mesenteric artery, leaving it lower than normal. This differs from polycystic kidney disease, renal agenesis, and medullary sponge kidney.
- A patient with severe pneumonia and impending respiratory failure has rising carbon dioxide and falling oxygen despite supplemental oxygen and is becoming exhausted. Which finding most strongly indicates the need for mechanical ventilation?
- A single normal blood gas
- Resolution of dyspnea
- Improving oxygenation on room air
- Progressive hypercapnia with respiratory muscle fatigue and a depressed mental status
Correct answer: Progressive hypercapnia with respiratory muscle fatigue and a depressed mental status
Progressive hypercapnia with muscle fatigue and depressed mental status is the answer. When a patient can no longer sustain adequate ventilation, evidenced by rising carbon dioxide, exhaustion, and declining consciousness, mechanical ventilation is needed to support gas exchange. A normal blood gas, resolving dyspnea, or improving oxygenation would not indicate the need for intubation.
- A clinician distinguishes the two main types of respiratory failure. A patient with a low arterial oxygen but a normal or low carbon dioxide, as in early pneumonia, has which type of respiratory failure?
- Hypoxemic (type 1) respiratory failure
- Hypercapnic (type 2) respiratory failure
- Pure metabolic failure
- No respiratory failure
Correct answer: Hypoxemic (type 1) respiratory failure
Hypoxemic (type 1) respiratory failure is the answer. Type 1 respiratory failure is defined by hypoxemia with a normal or low carbon dioxide, typical of diseases that impair oxygenation such as pneumonia or pulmonary edema. Type 2 failure features hypercapnia from inadequate ventilation, a different pattern.
- A patient with a chronic neuromuscular disease develops respiratory failure characterized by an elevated carbon dioxide from inadequate ventilation. This pattern defines which type of respiratory failure?
- Hypoxemic (type 1) respiratory failure
- Hypercapnic (type 2) respiratory failure
- High-output cardiac failure
- Pure shunt physiology
Correct answer: Hypercapnic (type 2) respiratory failure
Hypercapnic (type 2) respiratory failure is the answer. Type 2 respiratory failure results from inadequate alveolar ventilation, as in neuromuscular weakness, leading to carbon dioxide retention and respiratory acidosis. Type 1 failure is defined by hypoxemia with normal or low carbon dioxide, a different mechanism.
- A medical student studies the muscles of breathing. During quiet inspiration, which muscle is the primary driver of air entry into the lungs?
- The internal intercostal muscles
- The abdominal rectus muscles
- The diaphragm
- The latissimus dorsi
Correct answer: The diaphragm
The diaphragm is the answer. Contraction of the dome-shaped diaphragm during quiet inspiration enlarges the thoracic cavity and lowers intrathoracic pressure, drawing air into the lungs. The internal intercostals and abdominal muscles assist with active expiration, and the latissimus dorsi is not a primary muscle of quiet breathing.
- A 39-year-old man with epigastric pain that improves with meals is found on endoscopy to have an ulcer in the duodenal bulb, and rapid urease testing of a biopsy specimen turns positive. Which feature of the organism most directly allows the urease test to identify the infection responsible for his peptic ulcer disease?
- It splits urea into ammonia and carbon dioxide, raising local pH
- It ferments lactose to produce acid
- It produces hydrogen sulfide from sulfur-containing compounds
- It cleaves hippurate to detect colonization
Correct answer: It splits urea into ammonia and carbon dioxide, raising local pH
Splitting urea into ammonia and carbon dioxide, raising local pH, is the answer. Helicobacter pylori produces abundant urease that hydrolyzes urea into ammonia and carbon dioxide, neutralizing gastric acid around the organism and forming the basis of the rapid urease and urea breath tests in peptic ulcer disease. Lactose fermentation, hydrogen sulfide production, and hippurate hydrolysis are not the reactions used to detect this organism.
- A 52-year-old man with peptic ulcer disease suddenly develops severe epigastric pain and a rigid, board-like abdomen, and an upright chest radiograph shows free air under the diaphragm. Which complication of his ulcer has most likely occurred?
- Gastric outlet obstruction
- Perforation of the ulcer into the peritoneal cavity
- Slow oozing from the ulcer base
- Conversion of the ulcer to a benign polyp
Correct answer: Perforation of the ulcer into the peritoneal cavity
Perforation of the ulcer into the peritoneal cavity is the answer. An ulcer that erodes completely through the wall releases air and gastric contents into the peritoneum, producing sudden severe pain, peritonitis with a rigid abdomen, and free air under the diaphragm on upright imaging. Gastric outlet obstruction causes vomiting and distension, slow oozing causes anemia rather than free air, and ulcers do not transform into benign polyps.
- A medical student compares duodenal and gastric ulcers. Compared with a typical gastric ulcer, pain from a classic duodenal ulcer is most characteristically described by which temporal relationship to eating?
- Pain that worsens immediately with eating
- Pain that occurs only during sleep and never with food
- Pain that improves with eating and recurs 2 to 3 hours later
- Pain that is unrelated to meals entirely
Correct answer: Pain that improves with eating and recurs 2 to 3 hours later
Pain that improves with eating and recurs 2 to 3 hours later is the answer. Duodenal ulcer pain classically eases when food buffers gastric acid and returns a few hours afterward as the stomach empties, whereas gastric ulcer pain often worsens with eating. Pain worsening immediately with food, occurring only in sleep, or unrelated to meals does not fit the classic duodenal ulcer pattern.
- A 67-year-old man with a posterior duodenal ulcer develops sudden massive upper gastrointestinal hemorrhage. Erosion of the ulcer into which artery, lying behind the first part of the duodenum, most likely accounts for this severe bleeding?
- Splenic artery
- Left gastric artery
- Inferior mesenteric artery
- Gastroduodenal artery
Correct answer: Gastroduodenal artery
Gastroduodenal artery is the answer. A posterior duodenal ulcer can erode into the gastroduodenal artery, which courses behind the first part of the duodenum, producing brisk, life-threatening hemorrhage. The splenic and left gastric arteries supply other regions, and the inferior mesenteric artery serves the distal colon, none of which lie behind the duodenal bulb.
- A researcher studies how Helicobacter pylori survives in the stomach yet damages the antral mucosa. Beyond urease, which additional virulence mechanism contributes most directly to chronic gastritis and ulceration?
- Flagellar motility and cytotoxin-associated proteins that injure epithelium and provoke inflammation
- Production of botulinum-like neurotoxin
- Formation of acid-fast cell walls resisting digestion
- Encapsulation that blocks all immune recognition
Correct answer: Flagellar motility and cytotoxin-associated proteins that injure epithelium and provoke inflammation
Flagellar motility and cytotoxin-associated proteins that injure epithelium and provoke inflammation is the answer. Helicobacter pylori uses flagella to burrow into the mucus layer and secretes cytotoxins such as the CagA and VacA proteins that damage epithelial cells and trigger an inflammatory response, driving chronic gastritis and ulcers. It does not make botulinum toxin, possess an acid-fast wall, or rely on a capsule to evade all immunity.
- A 19-year-old man develops periumbilical pain that migrates over several hours to the right lower quadrant, with low-grade fever, anorexia, and nausea. Tenderness is maximal at a point one-third of the way from the anterior superior iliac spine to the umbilicus. The early periumbilical pain of appendicitis reflects which feature of the appendix?
- Somatic innervation of the parietal peritoneum
- Visceral afferent pain from a midgut structure referred to the periumbilical region
- Direct irritation of the diaphragm
- Stretch of the renal capsule
Correct answer: Visceral afferent pain from a midgut structure referred to the periumbilical region
Visceral afferent pain from a midgut structure referred to the periumbilical region is the answer. The appendix is a midgut derivative, so early visceral distension is referred diffusely to the periumbilical area, and only after the inflamed appendix irritates the overlying parietal peritoneum does pain localize to the right lower quadrant at McBurney point. Somatic peritoneal innervation explains the later localized pain, not the early visceral phase, and the diaphragm and renal capsule are unrelated.
- A 24-year-old woman has suspected appendicitis. Pressing deeply in the left lower quadrant elicits pain in the right lower quadrant. Which named physical finding does this represent, supporting the diagnosis?
- Murphy sign
- Cullen sign
- Rovsing sign
- Courvoisier sign
Correct answer: Rovsing sign
Rovsing sign is the answer. Rovsing sign is referred right-lower-quadrant pain produced by palpation of the left lower quadrant and supports appendicitis through peritoneal irritation. Murphy sign indicates gallbladder inflammation, Cullen sign is periumbilical bruising from intra-abdominal hemorrhage, and Courvoisier sign is a palpable nontender gallbladder suggesting malignant biliary obstruction.
- A 16-year-old boy presents with acute appendicitis. In adolescents and young adults, obstruction of the appendiceal lumen, the initiating event in most cases, is most commonly caused by which of the following?
- A hardened fecal mass (fecalith)
- A carcinoid tumor
- Twisting of the appendix on its mesentery
- Lymphoid hyperplasia
Correct answer: Lymphoid hyperplasia
Lymphoid hyperplasia is the answer. In children and young adults, reactive hyperplasia of the abundant appendiceal lymphoid tissue is the most common cause of luminal obstruction that triggers appendicitis, whereas a fecalith is the more typical cause in older adults. A carcinoid tumor is an uncommon cause, and torsion of the appendix is rare.
- A patient with untreated appendicitis develops worsening diffuse abdominal pain, high fever, and a rigid abdomen 2 days after symptom onset. Which complication of the appendix has most likely occurred to produce these signs of generalized peritonitis?
- Rupture of the appendix with spillage of contents into the peritoneum
- Spontaneous resolution
- Formation of a duodenal ulcer
- Development of a gallstone
Correct answer: Rupture of the appendix with spillage of contents into the peritoneum
Rupture of the appendix with spillage of contents into the peritoneum is the answer. Progressive ischemia and pressure in an obstructed appendix lead to perforation, releasing infected contents into the peritoneal cavity and causing generalized peritonitis with diffuse pain, fever, and a rigid abdomen. Spontaneous resolution would not cause these findings, and a duodenal ulcer or gallstone is unrelated to appendiceal rupture.
- A 38-year-old patient is being evaluated for inflammatory bowel disease. Which feature is most characteristic of ulcerative colitis rather than Crohn disease?
- Transmural inflammation with fistula formation
- Continuous inflammation beginning at the rectum and extending proximally without skip areas
- Frequent involvement of the terminal ileum with sparing of the rectum
- Noncaseating granulomas in the bowel wall
Correct answer: Continuous inflammation beginning at the rectum and extending proximally without skip areas
Continuous inflammation beginning at the rectum and extending proximally without skip areas is the answer. Ulcerative colitis produces continuous mucosal and submucosal inflammation that starts in the rectum and spreads proximally without skip lesions and is limited to the colon. Transmural inflammation with fistulas, terminal ileal involvement with rectal sparing, and noncaseating granulomas are features of Crohn disease.
- A patient with longstanding ulcerative colitis develops severe colonic dilation, systemic toxicity, fever, and the risk of perforation. Which life-threatening complication, more typical of ulcerative colitis than Crohn disease, does this describe?
- Enterovesical fistula
- Perianal abscess
- Toxic megacolon
- Bowel wall fibrostenosis
Correct answer: Toxic megacolon
Toxic megacolon is the answer. Toxic megacolon is acute, marked colonic dilation with systemic toxicity and a high risk of perforation, classically a complication of ulcerative colitis. Enterovesical fistulas, perianal abscesses, and fibrostenotic strictures are more characteristic of the transmural, fistulizing nature of Crohn disease.
- A pathologist examines a colon resected for Crohn disease and notes deep, knife-like fissuring ulcers and a bumpy mucosal surface created by edema and ulceration. Which gross descriptive term applies to this characteristic appearance?
- Lead-pipe colon
- Apple-core lesion
- Pseudomembranes
- Cobblestone mucosa
Correct answer: Cobblestone mucosa
Cobblestone mucosa is the answer. In Crohn disease, deep fissuring ulcers separating islands of edematous, relatively spared mucosa create a cobblestone appearance. A lead-pipe colon with loss of haustra is seen in chronic ulcerative colitis, an apple-core lesion suggests an annular colon cancer, and pseudomembranes indicate Clostridioides difficile colitis.
- A 33-year-old woman with Crohn disease confined to the terminal ileum is most likely to develop a deficiency of which nutrient, given the absorptive role of that bowel segment?
- Vitamin B12
- Iron
- Folate
- Vitamin C
Correct answer: Vitamin B12
Vitamin B12 is the answer. The terminal ileum is the specific site of vitamin B12 (intrinsic factor complex) and bile salt absorption, so terminal ileal Crohn disease characteristically produces vitamin B12 deficiency. Iron and folate are absorbed more proximally in the duodenum and jejunum, and vitamin C deficiency is not specifically tied to terminal ileal disease.
- A 58-year-old man with longstanding hepatitis C develops a small, shrunken, nodular liver, ascites, and esophageal varices. Which fundamental histologic change defines the cirrhosis underlying these findings?
- Reversible accumulation of fat within hepatocytes
- Diffuse bridging fibrosis with regenerative nodules disrupting the normal architecture
- Acute neutrophilic infiltration without scarring
- Dilation of the central veins only
Correct answer: Diffuse bridging fibrosis with regenerative nodules disrupting the normal architecture
Diffuse bridging fibrosis with regenerative nodules disrupting the normal architecture is the answer. Cirrhosis is defined by diffuse fibrous septa bridging portal and central regions with regenerative nodules of hepatocytes, which distorts blood flow and produces portal hypertension and synthetic failure. Reversible steatosis, acute neutrophilic inflammation alone, and isolated central vein dilation do not define cirrhosis.
- A patient with cirrhosis is examined and found to have palmar erythema, spider angiomas, and gynecomastia. These signs are best explained by which derangement caused by impaired liver function?
- Excess production of cortisol by the adrenal gland
- Overproduction of thyroid hormone
- Reduced hepatic metabolism of estrogens leading to relative estrogen excess
- Increased renal clearance of androgens
Correct answer: Reduced hepatic metabolism of estrogens leading to relative estrogen excess
Reduced hepatic metabolism of estrogens leading to relative estrogen excess is the answer. The diseased liver clears estrogens less effectively, so relative estrogen excess produces spider angiomas, palmar erythema, and gynecomastia in cirrhosis. Excess cortisol, thyroid hormone overproduction, and increased renal androgen clearance do not account for these classic stigmata of chronic liver disease.
- A man with alcohol-related cirrhosis is found to have an elevated international normalized ratio that partially corrects with vitamin K. The cirrhotic liver's reduced ability to perform which of its normal functions most directly explains his coagulopathy?
- Storage of glycogen
- Conjugation of bilirubin
- Detoxification of ammonia
- Synthesis of clotting factors
Correct answer: Synthesis of clotting factors
Synthesis of clotting factors is the answer. The liver synthesizes most coagulation factors, so cirrhotic loss of synthetic capacity prolongs clotting times and produces a bleeding tendency. Impaired glycogen storage affects glucose homeostasis, defective bilirubin conjugation causes jaundice, and impaired ammonia detoxification causes encephalopathy, none of which directly explain the coagulopathy.
- A medical student studies hepatitis B serology. In a patient with resolved hepatitis B infection who is now immune, which serologic pattern is expected?
- Positive surface antibody and positive core antibody with negative surface antigen
- Positive surface antigen with negative surface antibody
- Positive surface antibody alone with no core antibody
- Positive e antigen with high viral DNA
Correct answer: Positive surface antibody and positive core antibody with negative surface antigen
Positive surface antibody and positive core antibody with negative surface antigen is the answer. A person who has cleared natural hepatitis B infection shows antibody to surface antigen (indicating immunity) plus antibody to core antigen (indicating prior infection), with surface antigen no longer detectable. Persistent surface antigen indicates ongoing infection, isolated surface antibody without core antibody indicates vaccination, and e antigen with high DNA indicates active replication.
- A healthy nursing student who completed the recombinant hepatitis B vaccine series has protective immunity. Which serologic finding confirms vaccine-induced immunity rather than prior natural infection?
- Positive hepatitis B surface antigen
- Positive hepatitis B surface antibody with negative core antibody
- Positive hepatitis B core antibody with negative surface antibody
- Positive hepatitis B e antigen
Correct answer: Positive hepatitis B surface antibody with negative core antibody
Positive hepatitis B surface antibody with negative core antibody is the answer. The vaccine contains only surface antigen, so vaccinated individuals develop surface antibody but never core antibody, distinguishing immunization from natural infection, which also produces core antibody. A positive surface antigen or e antigen indicates active infection, and isolated core antibody indicates past or resolving infection rather than vaccination.
- A patient with chronic hepatitis B has persistently detectable hepatitis B e antigen along with high circulating viral DNA. What does the presence of e antigen most directly indicate about the infection?
- The patient has cleared the virus and is immune
- The patient was vaccinated and never infected
- The patient has high viral replication and increased infectivity
- The patient has only a remote, inactive prior infection
Correct answer: The patient has high viral replication and increased infectivity
High viral replication and increased infectivity is the answer. Hepatitis B e antigen is a marker of active viral replication, correlating with high viral load and greater infectivity and transmission risk. It does not indicate clearance and immunity, a vaccinated uninfected state, or a remote inactive infection.
- A 30-year-old man with chronic hepatitis B is at increased long-term risk for hepatocellular carcinoma even without cirrhosis. Which property of the hepatitis B virus best explains this direct oncogenic potential?
- It is a retrovirus that reverse-transcribes RNA to DNA only
- It produces a preformed toxin that mutates DNA
- It exclusively replicates outside hepatocytes
- Its DNA can integrate into the host genome and promote malignant transformation
Correct answer: Its DNA can integrate into the host genome and promote malignant transformation
Its DNA can integrate into the host genome and promote malignant transformation is the answer. Hepatitis B is a DNA virus whose genome can integrate into host hepatocyte DNA and, along with chronic inflammation, contribute directly to hepatocellular carcinoma even before cirrhosis develops. It is not a pure RNA retrovirus, does not act through a preformed toxin, and replicates within hepatocytes.
- A 28-year-old woman with biopsy-proven celiac disease is counseled about which laboratory antibodies support the diagnosis. Which serologic test is the most sensitive and specific first-line study for celiac disease?
- Anti-tissue transglutaminase IgA antibody
- Anti-mitochondrial antibody
- Anti-smooth muscle antibody
- Anti-centromere antibody
Correct answer: Anti-tissue transglutaminase IgA antibody
Anti-tissue transglutaminase IgA antibody is the answer. IgA antibodies against tissue transglutaminase are the recommended first-line serologic test for celiac disease because of their high sensitivity and specificity. Anti-mitochondrial antibodies indicate primary biliary cholangitis, anti-smooth muscle antibodies suggest autoimmune hepatitis, and anti-centromere antibodies are associated with limited scleroderma.
- A patient with celiac disease asks why the disorder runs in families and is linked to specific immune genes. Celiac disease shows a strong association with which human leukocyte antigen alleles?
- HLA-B27
- HLA-DQ2 and HLA-DQ8
- HLA-B8 only
- HLA-A3
Correct answer: HLA-DQ2 and HLA-DQ8
HLA-DQ2 and HLA-DQ8 is the answer. Celiac disease is strongly associated with the HLA-DQ2 and HLA-DQ8 haplotypes, which present deamidated gliadin peptides to T cells and drive the immune-mediated mucosal injury. HLA-B27 is linked to spondyloarthropathies, and HLA-B8 and HLA-A3 are not the defining celiac associations.
- A medical student studies gastric acid secretion. Histamine released from enterochromaffin-like cells stimulates parietal cell acid secretion by binding which receptor and raising which intracellular second messenger?
- The H1 receptor, raising calcium
- The muscarinic M3 receptor, raising calcium
- The H2 receptor, raising cyclic AMP
- The gastrin (CCK-B) receptor, raising cyclic AMP
Correct answer: The H2 receptor, raising cyclic AMP
The H2 receptor, raising cyclic AMP, is the answer. Histamine acts on parietal cell H2 receptors coupled to a stimulatory G protein, increasing cyclic AMP and activating the proton pump to secrete acid, which is why H2 receptor antagonists reduce acid output. The H1 receptor mediates allergic responses, and the muscarinic and gastrin receptors act through calcium rather than the cyclic AMP pathway of histamine.
- A first-year student reviews the cells of the gastric glands. Which gastric cell type secretes gastrin to stimulate acid production, and where is it predominantly located?
- Parietal cells in the gastric fundus
- Chief cells in the gastric body
- D cells in the duodenum
- G cells in the gastric antrum
Correct answer: G cells in the gastric antrum
G cells in the gastric antrum is the answer. Gastrin is secreted by G cells located mainly in the gastric antrum and stimulates parietal cell acid secretion both directly and through histamine release. Parietal cells secrete acid, chief cells secrete pepsinogen, and D cells secrete inhibitory somatostatin rather than gastrin.
- A patient with severe diarrhea is studied for fluid handling along the gut. Under normal physiology, which segment of the gastrointestinal tract reabsorbs the largest portion of the daily fluid load, making its dysfunction a major cause of large secretory diarrhea volumes?
- The small intestine
- The stomach
- The colon
- The esophagus
Correct answer: The small intestine
The small intestine is the answer. The small intestine reabsorbs the great majority of the roughly nine liters of fluid presented to the gut each day, so disorders that impair small-bowel absorption or drive small-bowel secretion produce large-volume diarrhea. The colon reclaims a smaller residual volume, while the stomach and esophagus are not major sites of net fluid absorption.
- A medical student studies enterohepatic circulation. Most bile acids secreted into the duodenum are reclaimed and returned to the liver, and this reabsorption occurs primarily by active transport in which segment?
- The duodenum
- The terminal ileum
- The jejunum
- The colon
Correct answer: The terminal ileum
The terminal ileum is the answer. Conjugated bile acids are actively reabsorbed in the terminal ileum and returned to the liver through the portal circulation, a process called enterohepatic circulation that conserves the bile acid pool. The duodenum and jejunum perform little bile acid reabsorption, and the colon is not the principal site of this active uptake.
- A 70-year-old man undergoes screening colonoscopy that removes several adenomatous polyps. According to the adenoma-carcinoma sequence, the earliest genetic event initiating most sporadic colorectal cancers is mutation of which gene?
- The KRAS oncogene
- The TP53 tumor suppressor gene
- The APC tumor suppressor gene
- The RET proto-oncogene
Correct answer: The APC tumor suppressor gene
The APC tumor suppressor gene is the answer. Loss of APC function is the earliest step in the classic adenoma-carcinoma sequence, allowing formation of an adenomatous polyp, followed later by KRAS activation and TP53 loss as the lesion progresses to carcinoma. RET mutations are associated with multiple endocrine neoplasia rather than the colorectal adenoma-carcinoma pathway.
- A 62-year-old man presents with iron deficiency anemia and a few months of constipation, and colonoscopy reveals a circumferential, constricting mass causing an apple-core narrowing. Which part of the colon is the most likely site, given that lesions there tend to obstruct and present with changes in stool caliber?
- Cecum
- Ascending colon
- Appendix
- Left (descending and sigmoid) colon
Correct answer: Left (descending and sigmoid) colon
Left (descending and sigmoid) colon is the answer. Left-sided colon cancers grow in a narrower lumen with more solid stool, so they tend to be annular and constricting, producing obstruction, change in stool caliber, and the apple-core appearance. Right-sided cancers in the cecum and ascending colon more often bleed occultly and present with iron deficiency anemia rather than early obstruction, and the appendix is not the typical site.
- A patient with newly diagnosed colorectal adenocarcinoma has a serum tumor marker measured to follow treatment response and detect recurrence. Which marker is most commonly used for this purpose in colorectal cancer?
- Carcinoembryonic antigen
- Alpha-fetoprotein
- Prostate-specific antigen
- CA-125
Correct answer: Carcinoembryonic antigen
Carcinoembryonic antigen is the answer. Carcinoembryonic antigen is the standard serum marker used to monitor colorectal cancer for treatment response and recurrence, although it is not used for screening. Alpha-fetoprotein is associated with hepatocellular carcinoma and germ cell tumors, prostate-specific antigen with prostate cancer, and CA-125 with ovarian cancer.
- A 14-year-old boy with familial adenomatous polyposis also has osteomas of the jaw, multiple epidermoid cysts, and desmoid tumors. This combination of familial adenomatous polyposis with extraintestinal tumors is best described as which variant?
- Turcot syndrome
- Gardner syndrome
- Cowden syndrome
- Cronkhite-Canada syndrome
Correct answer: Gardner syndrome
Gardner syndrome is the answer. Gardner syndrome is a variant of familial adenomatous polyposis featuring the colonic adenomas plus osteomas, soft-tissue tumors such as epidermoid cysts, and desmoid tumors. Turcot syndrome combines polyposis with central nervous system tumors, while Cowden and Cronkhite-Canada syndromes are distinct polyposis-related entities.
- A medical student reviews the embryologic divisions of the gut. The hindgut, which gives rise to the distal third of the transverse colon through the upper anal canal, receives its arterial blood supply from which vessel?
- Celiac trunk
- Superior mesenteric artery
- Inferior mesenteric artery
- Internal pudendal artery
Correct answer: Inferior mesenteric artery
Inferior mesenteric artery is the answer. The hindgut, extending from the distal third of the transverse colon to the upper anal canal, is supplied by the inferior mesenteric artery. The celiac trunk supplies foregut structures, the superior mesenteric artery supplies the midgut, and the internal pudendal artery supplies the lower anal canal and perineum.
- A medical student studies the gastrointestinal hormone secretin, released from S cells of the duodenum in response to acid. Which is the principal physiologic action of secretin that helps neutralize acidic chyme entering the small intestine?
- Stimulating gastric parietal cells to secrete more acid
- Contracting the gallbladder
- Increasing gastric emptying
- Stimulating pancreatic duct cells to secrete bicarbonate-rich fluid
Correct answer: Stimulating pancreatic duct cells to secrete bicarbonate-rich fluid
Stimulating pancreatic duct cells to secrete bicarbonate-rich fluid is the answer. Secretin, released from duodenal S cells when acid enters the duodenum, stimulates pancreatic and biliary ductal cells to secrete bicarbonate that neutralizes the acidic chyme. It inhibits rather than stimulates gastric acid and emptying, and gallbladder contraction is driven by cholecystokinin.
- A medical student studies absorption of fat-soluble vitamins. In a patient with severe fat malabsorption, deficiency of which vitamin would most likely cause a coagulopathy due to impaired synthesis of clotting factors?
- Vitamin K
- Vitamin A
- Vitamin D
- Vitamin E
Correct answer: Vitamin K
Vitamin K is the answer. Vitamin K is a fat-soluble vitamin required for gamma-carboxylation of clotting factors II, VII, IX, and X, so fat malabsorption impairs its uptake and causes a bleeding tendency with a prolonged prothrombin time. Deficiencies of vitamins A, D, and E cause visual, bone, and neurologic problems respectively rather than this coagulopathy.
- A 4-week-old breastfed infant develops worsening jaundice, pale clay-colored stools, and dark urine, and is found to have conjugated hyperbilirubinemia from progressive obliteration of the extrahepatic bile ducts. Which condition, requiring prompt surgical evaluation, does this describe?
- Physiologic jaundice of the newborn
- Biliary atresia
- Breast milk jaundice
- Gilbert syndrome
Correct answer: Biliary atresia
Biliary atresia is the answer. Biliary atresia is progressive fibro-obliteration of the extrahepatic bile ducts presenting in the first weeks of life with conjugated hyperbilirubinemia, acholic (pale) stools, and dark urine, and it requires prompt surgical correction to prevent cirrhosis. Physiologic and breast milk jaundice and Gilbert syndrome cause unconjugated hyperbilirubinemia with normal-colored stools.
- A 55-year-old man with painless jaundice is found to have a malignant biliary stricture, and on examination he has a palpable, nontender, distended gallbladder. This Courvoisier sign in painless jaundice most strongly suggests which underlying process?
- A simple stone obstructing the cystic duct
- Acute viral hepatitis
- Malignant obstruction of the common bile duct, such as pancreatic head cancer
- Gilbert syndrome
Correct answer: Malignant obstruction of the common bile duct, such as pancreatic head cancer
Malignant obstruction of the common bile duct, such as pancreatic head cancer, is the answer. A nontender, palpably enlarged gallbladder with painless jaundice (Courvoisier sign) suggests gradual malignant obstruction of the common bile duct rather than stones, because chronic gallstone disease usually leaves a scarred, noncompliant gallbladder. Acute viral hepatitis and Gilbert syndrome do not cause an obstructed, distended gallbladder.
- A medical student examines the histology of the colon and contrasts it with the small intestine. Which feature is normally present in the small intestine but absent in the colon, reflecting their different functions?
- Goblet cells
- Crypts
- Muscularis mucosae
- Villi
Correct answer: Villi
Villi is the answer. The small intestine has villi that vastly increase its absorptive surface area, whereas the colon has a flat surface with crypts but no villi because its main role is water and electrolyte reabsorption. Goblet cells, crypts, and the muscularis mucosae are present in both segments.
- A patient with massive diarrhea from a secretory process is studied at the cellular level. Which transporter on the apical membrane of intestinal crypt cells is the principal channel through which chloride, and secondarily water, is secreted into the lumen?
- The cystic fibrosis transmembrane conductance regulator chloride channel
- The sodium-glucose cotransporter (SGLT1)
- The H+/K+ ATPase
- The sodium-potassium ATPase
Correct answer: The cystic fibrosis transmembrane conductance regulator chloride channel
The cystic fibrosis transmembrane conductance regulator chloride channel is the answer. The CFTR chloride channel on the apical surface of crypt cells secretes chloride into the lumen, drawing sodium and water with it, and its overactivation by toxins such as cholera toxin drives secretory diarrhea. SGLT1 mediates absorption, the H+/K+ ATPase secretes gastric acid, and the basolateral sodium-potassium ATPase maintains ion gradients rather than secreting luminal chloride.
- A premature infant with cystic fibrosis is being studied for gastrointestinal manifestations. Pancreatic insufficiency in cystic fibrosis leads to malabsorption primarily because of which defect in the exocrine pancreas?
- Autoimmune destruction of islet cells
- Thick secretions plugging pancreatic ducts and destroying acinar tissue
- A gastrin-secreting tumor
- Absence of the pancreas from birth
Correct answer: Thick secretions plugging pancreatic ducts and destroying acinar tissue
Thick secretions plugging pancreatic ducts and destroying acinar tissue is the answer. In cystic fibrosis, defective chloride transport produces viscous secretions that obstruct pancreatic ducts, causing back-pressure injury and fibrosis of the acinar tissue and resulting exocrine insufficiency with fat malabsorption. Islet autoimmunity, a gastrinoma, and congenital absence of the pancreas are not the mechanism.
- A medical student reviews the regulation of gastric emptying. After a large fatty meal enters the duodenum, gastric emptying slows. Which mechanism best explains this physiologic feedback?
- Fat stimulates gastrin to accelerate emptying
- Fat directly relaxes the pyloric sphincter
- Fat in the duodenum triggers hormonal and neural signals, including cholecystokinin, that inhibit gastric emptying
- Fat increases motilin to empty the stomach faster
Correct answer: Fat in the duodenum triggers hormonal and neural signals, including cholecystokinin, that inhibit gastric emptying
Fat in the duodenum triggering hormonal and neural signals, including cholecystokinin, that inhibit gastric emptying is the answer. Fat and acid in the duodenum activate enterogastric feedback, with hormones such as cholecystokinin slowing gastric emptying so the small intestine has time to digest and absorb the load. Fat does not speed emptying through gastrin or motilin, and it does not directly relax the pylorus to accelerate emptying.
- A 26-year-old woman has chronic watery diarrhea, and a 72-hour fast in the hospital causes the diarrhea to stop completely. This response to fasting most strongly indicates which mechanism of diarrhea?
- Secretory diarrhea
- Inflammatory diarrhea
- Motility-related diarrhea from hyperthyroidism
- Osmotic diarrhea
Correct answer: Osmotic diarrhea
Osmotic diarrhea is the answer. Osmotic diarrhea is driven by unabsorbed luminal solutes, so it resolves with fasting when the offending substance is no longer ingested, whereas secretory diarrhea persists despite fasting. Inflammatory diarrhea includes blood and leukocytes and does not reliably stop with fasting, and a motility cause from hyperthyroidism would not abruptly cease with a short fast.
- A medical student studies bilirubin metabolism. After heme is broken down, unconjugated bilirubin is transported in the blood and must be carried in a particular way because it is poorly water soluble. How is unconjugated bilirubin transported in plasma?
- Bound to albumin
- Dissolved freely in the aqueous plasma
- Packaged within chylomicrons
- Bound to transferrin
Correct answer: Bound to albumin
Bound to albumin is the answer. Unconjugated bilirubin is lipophilic and water insoluble, so it travels in plasma bound to albumin until it is taken up by hepatocytes for conjugation. It is not freely dissolved in plasma, carried in chylomicrons, or bound to transferrin, which transports iron.
- A newborn delivered at 35 weeks develops visible jaundice on day 3 of life with an elevated unconjugated bilirubin, normal-colored stools, and no signs of hemolysis, which resolves over the following week. Which mechanism best explains this physiologic jaundice of the newborn?
- Complete absence of UDP-glucuronosyltransferase
- Immature, transiently low activity of the bilirubin-conjugating enzyme
- Obstruction of the bile ducts
- Autoimmune destruction of hepatocytes
Correct answer: Immature, transiently low activity of the bilirubin-conjugating enzyme
Immature, transiently low activity of the bilirubin-conjugating enzyme is the answer. Physiologic neonatal jaundice results from the normally immature and transiently low activity of UDP-glucuronosyltransferase together with increased bilirubin production, producing a mild unconjugated hyperbilirubinemia that resolves as the enzyme matures. Complete enzyme absence describes Crigler-Najjar type 1, while duct obstruction and autoimmune hepatocyte destruction cause different patterns.
- A patient with a defect in bilirubin handling is found to have conjugated (direct) hyperbilirubinemia with a grossly black liver on biopsy, but otherwise normal liver function and a benign course. Which inherited disorder of bilirubin metabolism does this describe?
- Gilbert syndrome
- Crigler-Najjar syndrome
- Dubin-Johnson syndrome
- Hemolytic anemia
Correct answer: Dubin-Johnson syndrome
Dubin-Johnson syndrome is the answer. Dubin-Johnson syndrome is a benign defect in the canalicular transport of conjugated bilirubin, producing conjugated hyperbilirubinemia and a characteristically dark, pigmented liver, with an otherwise normal course. Gilbert and Crigler-Najjar syndromes cause unconjugated hyperbilirubinemia, and hemolysis raises unconjugated bilirubin without a black liver.
- A 45-year-old man with severe hypertriglyceridemia is admitted with acute pancreatitis. Aside from gallstones and alcohol, markedly elevated triglycerides are a recognized cause of pancreatitis primarily through which mechanism?
- Direct obstruction of the pancreatic duct by fat
- Autoimmune attack on islet cells
- Bacterial infection seeded by the triglycerides
- Release of toxic free fatty acids that injure acinar cells
Correct answer: Release of toxic free fatty acids that injure acinar cells
Release of toxic free fatty acids that injure acinar cells is the answer. In severe hypertriglyceridemia, pancreatic lipase liberates large amounts of free fatty acids that are directly toxic to acinar cells and the microvasculature, triggering acute pancreatitis. The triglycerides do not mechanically plug the duct, provoke islet autoimmunity, or directly seed a bacterial infection.
- A medical student studies the anatomy of the salivary glands and a complication of poor oral intake. Which gland, the largest salivary gland, secretes a primarily serous saliva and is the most common site of bacterial parotitis in dehydrated patients?
- Parotid gland
- Sublingual gland
- Submandibular gland
- Minor labial glands
Correct answer: Parotid gland
Parotid gland is the answer. The parotid is the largest salivary gland, produces mainly serous secretions, and is the classic site of acute bacterial parotitis when reduced salivary flow in dehydrated or postoperative patients allows ascending infection. The sublingual and submandibular glands and the minor labial glands are not the typical site of this serous-gland parotitis.
- A patient with severe vomiting from gastric outlet obstruction is found to have a metabolic disturbance. Loss of which gastric secretion best explains the development of a hypochloremic, hypokalemic metabolic alkalosis?
- Loss of bicarbonate-rich pancreatic fluid
- Loss of hydrochloric acid (hydrogen and chloride) from the stomach
- Loss of bile salts
- Loss of intrinsic factor
Correct answer: Loss of hydrochloric acid (hydrogen and chloride) from the stomach
Loss of hydrochloric acid (hydrogen and chloride) from the stomach is the answer. Protracted vomiting of gastric contents removes hydrogen and chloride ions, producing a hypochloremic metabolic alkalosis, with secondary potassium loss as the kidney exchanges potassium to conserve sodium. Loss of pancreatic bicarbonate would cause acidosis, and loss of bile salts or intrinsic factor does not produce this acid-base picture.
- A medical student studies the colon's microbial functions. Colonic bacteria ferment undigested dietary fiber into short-chain fatty acids that serve as the preferred energy source for which cells?
- Hepatocytes
- Pancreatic acinar cells
- Colonocytes (colonic epithelial cells)
- Gastric parietal cells
Correct answer: Colonocytes (colonic epithelial cells)
Colonocytes (colonic epithelial cells) is the answer. Bacterial fermentation of fiber in the colon yields short-chain fatty acids such as butyrate, which are the principal fuel for colonocytes and support mucosal health. Hepatocytes, pancreatic acinar cells, and gastric parietal cells do not depend on luminal short-chain fatty acids as their main energy source.
- A 60-year-old man with cirrhosis develops worsening ascites, and his physician explains the role of aldosterone in fluid retention. Activation of which system, triggered by reduced effective arterial blood volume in cirrhosis, most directly drives the sodium and water retention that worsens ascites?
- The hypothalamic-pituitary-thyroid axis
- The sympathetic nervous system acting on bronchi
- The clotting cascade
- The renin-angiotensin-aldosterone system
Correct answer: The renin-angiotensin-aldosterone system
The renin-angiotensin-aldosterone system is the answer. In cirrhosis, splanchnic vasodilation lowers effective arterial blood volume, activating the renin-angiotensin-aldosterone system, which promotes renal sodium and water retention and aggravates ascites, and explains the use of the aldosterone antagonist spironolactone. The thyroid axis, bronchial sympathetic effects, and the clotting cascade do not drive this fluid retention.
- A patient with malabsorption is evaluated with a stool study, and a markedly elevated stool fecal fat (steatorrhea) is found. Steatorrhea most directly reflects a problem with which digestive process?
- Fat digestion and absorption involving bile and pancreatic lipase
- Carbohydrate digestion by amylase
- Protein digestion by gastric pepsin
- Water reabsorption in the colon
Correct answer: Fat digestion and absorption involving bile and pancreatic lipase
Fat digestion and absorption involving bile and pancreatic lipase is the answer. Steatorrhea, the presence of excess fat in stool, indicates failure of fat digestion or absorption, which depends on bile salts to emulsify fat and pancreatic lipase to hydrolyze triglycerides. Defects in carbohydrate or protein digestion or colonic water reabsorption do not produce fatty stools.
- A 50-year-old woman undergoes laparoscopic cholecystectomy. The surgeon identifies the hepatocystic (Calot) triangle to safely ligate the cystic artery and cystic duct. Which structure forms the medial border of this triangle?
- The portal vein
- The common hepatic duct
- The inferior vena cava
- The pancreatic duct
Correct answer: The common hepatic duct
The common hepatic duct is the answer. The hepatocystic (Calot) triangle is bounded medially by the common hepatic duct, inferiorly by the cystic duct, and superiorly by the inferior edge of the liver, and it is used to locate the cystic artery during cholecystectomy. The portal vein, inferior vena cava, and pancreatic duct do not form this triangle.
- A medical student reviews the brush-border enzymes of the small intestine. Sucrose ingested in the diet is hydrolyzed at the brush border into glucose and fructose by which enzyme?
- Lactase
- Pepsin
- Sucrase
- Trypsin
Correct answer: Sucrase
Sucrase is the answer. Sucrase is a brush-border disaccharidase that cleaves dietary sucrose into glucose and fructose for absorption. Lactase splits lactose into glucose and galactose, while pepsin and trypsin are proteases that do not act on sucrose.
- A 14-year-old previously healthy boy is brought to the emergency department after two days of vomiting, deep rapid breathing, and increasing lethargy. He has lost weight over the past month despite a large appetite and has been urinating frequently. Serum glucose is 540 mg/dL, bicarbonate is low, and serum and urine ketones are strongly positive. Which underlying problem best explains this presentation?
- Near-total absence of insulin secretion due to autoimmune destruction of pancreatic beta cells
- Excess insulin secretion from a pancreatic islet cell tumor
- Resistance of peripheral tissues to normal circulating insulin
- Deficient secretion of glucagon from pancreatic alpha cells
Correct answer: Near-total absence of insulin secretion due to autoimmune destruction of pancreatic beta cells
Autoimmune destruction of beta cells leading to near-total insulin deficiency is the correct mechanism. This adolescent has classic new-onset type 1 diabetes presenting as diabetic ketoacidosis: profound insulin lack removes the brake on lipolysis, so free fatty acids are converted to ketoacids, producing the high anion-gap metabolic acidosis, Kussmaul breathing, and marked hyperglycemia. An insulinoma would cause hypoglycemia, insulin resistance characterizes type 2 disease (which rarely presents with florid ketoacidosis in a thin adolescent), and glucagon deficiency would not raise glucose this dramatically.
- A 52-year-old man with obesity, hypertension, and a strong family history of diabetes is found to have a fasting glucose of 142 mg/dL and a hemoglobin A1c of 7.4%. He has no ketones and is asymptomatic. Compared with type 1 diabetes, the metabolic defect most central to his condition is best described as which of the following?
- Antibodies directed against the insulin receptor causing receptor blockade
- Complete autoimmune loss of beta-cell insulin production
- Resistance of muscle, liver, and fat to insulin with relatively preserved insulin secretion
- A defect in glucokinase preventing any insulin release
Correct answer: Resistance of muscle, liver, and fat to insulin with relatively preserved insulin secretion
Peripheral insulin resistance with relatively preserved (often initially elevated) insulin secretion is the hallmark of type 2 diabetes. Target tissues respond poorly to insulin, so the pancreas compensates by secreting more, and hyperglycemia develops gradually without ketosis because residual insulin still suppresses lipolysis. Complete autoimmune beta-cell loss defines type 1 disease; insulin-receptor antibodies cause the rare type B insulin resistance syndrome, not common type 2 diabetes; and an isolated glucokinase defect describes a form of MODY, not typical obesity-associated type 2 diabetes.
- A patient in diabetic ketoacidosis is treated with intravenous insulin and isotonic fluids. Two hours later the serum potassium, initially 5.2 mEq/L, has fallen to 3.3 mEq/L. Which mechanism best explains this drop?
- Insulin increases renal tubular secretion of potassium directly
- Insulin drives potassium from the extracellular fluid into cells
- Correction of acidosis releases potassium into the urine via aldosterone
- Rehydration dilutes a falsely elevated potassium measurement
Correct answer: Insulin drives potassium from the extracellular fluid into cells
Insulin-driven shift of potassium into cells is the key mechanism. In untreated diabetic ketoacidosis, acidosis and insulin deficiency shift potassium out of cells, so the measured serum value can be normal or high even though total-body potassium is depleted from osmotic diuresis. Once insulin is given, it activates the sodium-potassium ATPase and rapidly moves potassium intracellularly, unmasking the deficit. This is why potassium must be monitored closely and repleted during therapy. Insulin does not directly stimulate renal potassium secretion, and the fall is too rapid and large to reflect mere dilution.
- A 19-year-old woman with type 1 diabetes presents with abdominal pain, vomiting, and fruity breath odor after running out of insulin. Arterial blood gas shows pH 7.18 with low bicarbonate, and the anion gap is elevated. Which laboratory finding best confirms the specific cause of her acidosis?
- Markedly elevated serum amylase
- Elevated serum lactate
- Elevated serum osmolal gap from methanol
- Elevated serum beta-hydroxybutyrate
Correct answer: Elevated serum beta-hydroxybutyrate
Elevated serum beta-hydroxybutyrate confirms ketoacidosis as the cause of the high anion-gap acidosis. In diabetic ketoacidosis, insulin deficiency accelerates fatty acid oxidation in the liver, producing the ketoacids acetoacetate and beta-hydroxybutyrate; the latter predominates and is the most reliable marker. Lactate elevation points to lactic acidosis, an osmolal gap suggests toxic alcohol ingestion, and a high amylase suggests pancreatitis. None of these explains the ketotic picture in an insulin-deficient diabetic.
- A 38-year-old woman reports a 15-pound weight loss, palpitations, heat intolerance, and tremor over three months. Examination shows a diffusely enlarged thyroid with a bruit, a fine tremor, and bilateral proptosis. Laboratory testing shows suppressed TSH and elevated free T4. Which antibody is most directly responsible for her disease?
- Antibody that stimulates the TSH receptor
- Antibody against thyroid peroxidase causing gland destruction
- Antibody against the acetylcholine receptor
- Antibody against parietal cell intrinsic factor
Correct answer: Antibody that stimulates the TSH receptor
A stimulating antibody against the TSH receptor is the direct cause of Graves disease. This thyroid-stimulating immunoglobulin binds and activates the TSH receptor, driving unregulated hormone synthesis and diffuse gland enlargement; the same antibody and associated inflammation produce the orbital changes seen as proptosis. Anti-thyroid peroxidase antibodies are more characteristic of Hashimoto thyroiditis with hypothyroidism, acetylcholine-receptor antibodies cause myasthenia gravis, and intrinsic-factor antibodies cause pernicious anemia.
- A patient with newly diagnosed Graves disease is started on a thionamide. The drug methimazole controls her hyperthyroidism primarily by which action?
- Destroying thyroid follicular cells with beta radiation
- Blocking peripheral conversion of T4 to T3 only
- Inhibiting thyroid peroxidase to block hormone synthesis
- Stimulating the release of preformed thyroid hormone
Correct answer: Inhibiting thyroid peroxidase to block hormone synthesis
Inhibition of thyroid peroxidase is methimazole's primary action. Thyroid peroxidase catalyzes oxidation and organification of iodide and coupling of iodotyrosines; blocking it reduces synthesis of new thyroid hormone, gradually lowering hormone levels. Radioactive iodine, not methimazole, destroys follicular cells with beta radiation. Propylthiouracil, a related drug, additionally blocks peripheral T4-to-T3 conversion, but the shared and principal mechanism of thionamides is peroxidase inhibition. Stimulating hormone release would worsen, not treat, the disease.
- A 45-year-old woman has central obesity, purple abdominal striae, proximal muscle weakness, hypertension, and easy bruising. A 1-mg overnight dexamethasone suppression test fails to suppress morning cortisol, and 24-hour urinary free cortisol is markedly elevated. These findings indicate which underlying abnormality?
- Deficiency of cortisol from adrenal destruction
- Chronic excess of circulating cortisol
- Excess aldosterone with normal cortisol
- Deficiency of growth hormone
Correct answer: Chronic excess of circulating cortisol
Chronic cortisol excess defines Cushing syndrome, which this clinical picture and biochemistry demonstrate. Persistent glucocorticoid excess produces the central adiposity, wide violaceous striae, proteolysis-related proximal weakness, hypertension, and capillary fragility causing bruising. Failure of low-dose dexamethasone to suppress cortisol plus elevated urinary free cortisol confirms autonomous hypercortisolism. Adrenal destruction would cause cortisol deficiency (Addison disease), isolated aldosterone excess would not cause striae or central obesity, and growth hormone deficiency does not produce this syndrome.
- In the workup of confirmed hypercortisolism, a patient is found to have a low plasma ACTH level that does not rise. Which source of cortisol excess is most consistent with this result?
- Exogenous administration of corticotropin
- An ACTH-secreting pituitary adenoma
- Ectopic ACTH production by a small cell lung carcinoma
- An autonomously functioning adrenal adenoma
Correct answer: An autonomously functioning adrenal adenoma
An autonomously functioning adrenal adenoma is the source most consistent with a suppressed, low ACTH. When cortisol is produced directly by the adrenal gland independent of pituitary control, the high cortisol feeds back to suppress hypothalamic-pituitary ACTH release, so ACTH is low. By contrast, a pituitary adenoma (Cushing disease) and ectopic ACTH-producing tumors both cause high ACTH, and administered corticotropin would itself raise measured ACTH-like activity. Identifying ACTH status is the first branch point in localizing the cause.
- A 40-year-old woman reports months of fatigue, weight loss, salt craving, dizziness on standing, and darkening of her skin creases and gums. Laboratory testing shows hyponatremia, hyperkalemia, and a low morning cortisol that fails to rise after synthetic ACTH stimulation. Which mechanism explains her hyperpigmentation?
- Elevated ACTH and its precursor stimulate melanocytes
- Excess aldosterone increases melanin synthesis
- Deposition of iron in the skin from hemochromatosis
- Increased thyroid hormone stimulating melanogenesis
Correct answer: Elevated ACTH and its precursor stimulate melanocytes
Elevated ACTH stimulating melanocytes explains the hyperpigmentation of primary adrenal insufficiency (Addison disease). When the adrenal cortex is destroyed, cortisol falls and loss of negative feedback drives high pituitary ACTH, which is cleaved from proopiomelanocortin along with melanocyte-stimulating hormone activity; this increases melanin in skin creases and mucosa. The failure of cortisol to rise after ACTH confirms an adrenal (primary) defect, and the accompanying mineralocorticoid loss produces the hyponatremia and hyperkalemia. Aldosterone and thyroid hormone do not cause this pigmentation, and hemochromatosis pigment reflects iron, not ACTH.
- A patient with known Addison disease develops vomiting and diarrhea from a viral illness and is brought in hypotensive and confused. Which immediate treatment most directly addresses the life-threatening hormone deficiency?
- Subcutaneous insulin
- Intravenous levothyroxine
- Intravenous hydrocortisone
- Oral propranolol
Correct answer: Intravenous hydrocortisone
Intravenous hydrocortisone is the immediate, lifesaving treatment for adrenal crisis in Addison disease. An intercurrent illness sharply increases physiologic glucocorticoid demand that the destroyed adrenal cortex cannot meet, producing hypotension, hyponatremia, and shock. Hydrocortisone replaces the missing glucocorticoid (and at stress doses provides mineralocorticoid effect) along with fluids and glucose. Levothyroxine, insulin, and propranolol do not correct the cortisol deficiency driving the crisis and could be harmful.
- A 24-year-old woman reports irregular periods occurring every 45 to 60 days, difficulty conceiving, acne, and increased facial hair. Examination shows mild obesity, and pelvic ultrasound reveals multiple small peripheral ovarian follicles. Laboratory testing shows an elevated LH-to-FSH ratio and elevated free testosterone. Which mechanism best accounts for her hyperandrogenism and anovulation?
- Premature destruction of ovarian follicles from autoimmune oophoritis
- Increased ovarian androgen production with disordered gonadotropin secretion and insulin resistance
- A prolactin-secreting pituitary adenoma suppressing all gonadotropins
- An adrenal enzyme block in cortisol synthesis present since birth
Correct answer: Increased ovarian androgen production with disordered gonadotropin secretion and insulin resistance
Increased ovarian androgen production driven by disordered gonadotropin secretion and insulin resistance characterizes polycystic ovary syndrome. Elevated LH relative to FSH stimulates ovarian theca cells to make excess androgens, while hyperinsulinemia both augments androgen output and lowers sex hormone-binding globulin, raising free testosterone; the androgen excess disrupts follicle maturation, causing anovulation and oligomenorrhea. Autoimmune oophoritis causes premature ovarian insufficiency with low estrogen, a prolactinoma causes galactorrhea with low gonadotropins, and a congenital cortisol-synthesis block describes congenital adrenal hyperplasia.
- A woman with polycystic ovary syndrome who is not seeking pregnancy is counseled that long-term anovulation places her at increased risk for which condition?
- Vaginal adenosis
- Cervical squamous cell carcinoma
- Ovarian dysgerminoma
- Endometrial hyperplasia and carcinoma
Correct answer: Endometrial hyperplasia and carcinoma
Endometrial hyperplasia and carcinoma is the key long-term risk. Chronic anovulation means the endometrium is exposed to continuous estrogen without the cyclic, opposing progesterone that normally follows ovulation. Unopposed estrogen drives endometrial proliferation, which over time can progress to hyperplasia and adenocarcinoma. This is why cyclic progestin or combined hormonal therapy is recommended. Cervical and vaginal lesions relate to HPV and diethylstilbestrol exposure, and dysgerminoma is a germ cell tumor unrelated to anovulatory estrogen exposure.
- A 29-year-old woman at 34 weeks gestation presents with a blood pressure of 162/104 mmHg, 3+ proteinuria, headache, and right upper quadrant pain. She had normal blood pressures before 20 weeks. Which abnormality is central to the pathophysiology of her condition?
- Abnormal placental development causing widespread maternal endothelial dysfunction
- Maternal autoimmune destruction of glomerular basement membrane
- A pheochromocytoma releasing catecholamines
- Primary aldosterone excess from an adrenal adenoma
Correct answer: Abnormal placental development causing widespread maternal endothelial dysfunction
Abnormal placental development causing maternal endothelial dysfunction is the central mechanism of preeclampsia. Inadequate remodeling of the spiral arteries leads to placental ischemia and release of antiangiogenic factors that injure maternal endothelium throughout the body, producing hypertension, glomerular leak with proteinuria, and the hepatic and cerebral manifestations seen here after 20 weeks of pregnancy. Anti-glomerular basement membrane disease, pheochromocytoma, and primary aldosteronism are not pregnancy-specific and do not explain the new-onset gestational hypertension with proteinuria.
- A woman with preeclampsia develops generalized tonic-clonic seizures, now classified as eclampsia. Which medication is the standard treatment to prevent and control these seizures?
- Lorazepam infusion
- Phenytoin
- Magnesium sulfate
- Labetalol
Correct answer: Magnesium sulfate
Magnesium sulfate is the standard agent for preventing and treating eclamptic seizures. It is more effective than traditional antiepileptics in this setting and also helps stabilize the neuromuscular irritability associated with severe preeclampsia. Labetalol controls blood pressure but does not prevent seizures, and phenytoin and benzodiazepines are inferior to magnesium for eclampsia. Definitive treatment of the underlying disease remains delivery of the fetus and placenta.
- A 48-year-old man with difficult-to-control hypertension is found to have a potassium of 2.9 mEq/L despite no diuretic use. Plasma aldosterone is high and plasma renin activity is suppressed, giving an elevated aldosterone-to-renin ratio. Which mechanism explains his hypokalemia and hypertension?
- Excess cortisol acting on mineralocorticoid receptors from a pituitary tumor
- Autonomous aldosterone secretion increasing renal sodium retention and potassium loss
- Renal artery stenosis activating the renin-angiotensin system
- Catecholamine excess from an adrenal medullary tumor
Correct answer: Autonomous aldosterone secretion increasing renal sodium retention and potassium loss
Autonomous aldosterone secretion is the mechanism in primary hyperaldosteronism (Conn syndrome). Aldosterone acts on the distal nephron to reabsorb sodium and water (raising blood pressure) while increasing renal excretion of potassium and hydrogen ions, producing hypokalemia and metabolic alkalosis. The high aldosterone suppresses renin through volume expansion, giving the elevated aldosterone-to-renin ratio that distinguishes it from secondary causes. Renal artery stenosis raises renin, a pituitary tumor would raise ACTH/cortisol, and a medullary tumor secretes catecholamines, not aldosterone.
- A 35-year-old woman is evaluated for resistant hypertension and incidental hypokalemia. Her primary hyperaldosteronism is confirmed, and imaging shows a unilateral 1.5-cm adrenal cortical adenoma with a normal contralateral gland. Which treatment is most appropriate for this cause?
- High-dose glucocorticoid replacement
- Lifelong spironolactone with no further evaluation
- Bilateral adrenalectomy
- Surgical removal of the affected adrenal gland
Correct answer: Surgical removal of the affected adrenal gland
Surgical removal of the affected adrenal gland (unilateral adrenalectomy) is most appropriate for an aldosterone-producing adenoma confined to one gland. Removing the single autonomous source typically cures or markedly improves the hypertension and hypokalemia. A mineralocorticoid-receptor antagonist such as spironolactone is the preferred treatment for bilateral adrenal hyperplasia, where surgery would not help, but it is not the optimal choice when a clearly lateralized adenoma can be resected. Bilateral adrenalectomy would needlessly create adrenal insufficiency, and glucocorticoid replacement does not treat aldosterone excess.
- A 30-year-old woman has episodic spells of pounding headache, drenching sweats, and palpitations, with blood pressure surging to 210/120 mmHg during attacks. Plasma and urine metanephrines are markedly elevated. Before surgical removal of the responsible tumor, which pharmacologic preparation is essential first?
- Alpha-adrenergic blockade before any beta blockade
- Beta-adrenergic blockade alone
- Immediate surgery without medical preparation
- Thyroid hormone suppression
Correct answer: Alpha-adrenergic blockade before any beta blockade
Alpha-adrenergic blockade established first is essential in pheochromocytoma. The catecholamine-secreting adrenal medullary tumor produces episodic hypertension; giving a beta blocker before adequate alpha blockade removes beta-mediated vasodilation and leaves unopposed alpha stimulation, which can precipitate a hypertensive crisis. Therefore an alpha blocker such as phenoxybenzamine is started days before surgery, with a beta blocker added only afterward if needed. Operating without preparation risks lethal intraoperative pressure swings, and thyroid suppression is irrelevant.
- A patient is diagnosed with a pheochromocytoma. Which embryologic origin explains why this tumor secretes catecholamines?
- Endoderm-derived follicular cells
- Mesoderm-derived cells of the adrenal cortex
- Neural crest-derived chromaffin cells of the adrenal medulla
- Ectoderm-derived anterior pituitary cells
Correct answer: Neural crest-derived chromaffin cells of the adrenal medulla
Neural crest-derived chromaffin cells of the adrenal medulla are the origin of pheochromocytoma. These cells are modified postganglionic sympathetic neurons that synthesize and release epinephrine and norepinephrine, which is why the tumor causes catecholamine-driven paroxysmal hypertension. The adrenal cortex is mesodermal and makes steroids, thyroid follicular cells are endodermal and make thyroid hormone, and the anterior pituitary arises from oral ectoderm; none of these produce catecholamines.
- A 30-year-old woman has fatigue, cold intolerance, constipation, dry skin, weight gain, and a slowed relaxation phase of the ankle reflex. Laboratory testing shows elevated TSH, low free T4, and high titers of anti-thyroid peroxidase antibodies. Which is the most likely diagnosis?
- Graves disease
- Hashimoto thyroiditis
- Subacute granulomatous thyroiditis
- Iodine-induced hyperthyroidism
Correct answer: Hashimoto thyroiditis
Hashimoto thyroiditis is the most likely diagnosis. It is the most common cause of hypothyroidism in iodine-sufficient regions and results from autoimmune lymphocytic infiltration and gradual destruction of the thyroid, marked by anti-thyroid peroxidase antibodies. The high TSH with low free T4 confirms primary hypothyroidism, and the symptoms reflect generalized slowing of metabolism. Graves disease causes hyperthyroidism, subacute granulomatous thyroiditis is typically painful and transient, and iodine-induced disease would not feature peroxidase antibodies as the central finding.
- A patient with primary hypothyroidism from Hashimoto disease is started on levothyroxine. Which laboratory value is most useful for monitoring adequacy of replacement therapy?
- Serum thyroglobulin
- Serum total T4 only
- Anti-thyroid peroxidase antibody titer
- Serum TSH
Correct answer: Serum TSH
Serum TSH is the most useful monitoring test in primary hypothyroidism. Because the pituitary is intact, TSH responds sensitively to circulating thyroid hormone; a normalized TSH indicates appropriate levothyroxine dosing, while a high TSH signals underreplacement and a suppressed TSH signals overreplacement. Total T4 is less reflective of tissue status, antibody titers track autoimmunity rather than dosing, and thyroglobulin is used mainly in thyroid cancer surveillance, not in titrating hypothyroidism therapy.
- A 60-year-old man with a recent parathyroidectomy is noted to have perioral numbness and tingling of the fingertips. Tapping over the facial nerve produces twitching of the ipsilateral facial muscles. Which laboratory abnormality best explains these findings?
- Low serum calcium
- High serum calcium
- Low serum sodium
- High serum potassium
Correct answer: Low serum calcium
Low serum calcium best explains these signs. The facial twitching elicited by tapping the facial nerve is Chvostek sign, a manifestation of neuromuscular hyperexcitability from hypocalcemia, which can follow inadvertent removal of or injury to the parathyroid glands during neck surgery. Reduced parathyroid hormone lowers serum calcium, increasing nerve membrane excitability and producing paresthesias and tetany. Hypercalcemia depresses excitability, and sodium and potassium disturbances do not produce Chvostek sign.
- A 55-year-old woman is found on routine testing to have a serum calcium of 11.6 mg/dL with a low phosphate. Further testing shows an inappropriately elevated parathyroid hormone level, and she reports constipation, polyuria, and a prior kidney stone. Which mechanism best explains her hypercalcemia?
- Excess calcitonin from a thyroid medullary carcinoma
- Decreased parathyroid hormone with vitamin D deficiency
- Autonomous overproduction of parathyroid hormone, usually from a parathyroid adenoma
- Renal failure with phosphate retention
Correct answer: Autonomous overproduction of parathyroid hormone, usually from a parathyroid adenoma
Autonomous parathyroid hormone overproduction, most often from a single parathyroid adenoma, explains primary hyperparathyroidism. Excess hormone raises serum calcium by mobilizing bone calcium, increasing renal calcium reabsorption, and stimulating renal activation of vitamin D, while promoting renal phosphate wasting that lowers phosphate. The elevated calcium causes the stones, polyuria, and constipation described. A high calcium should suppress normal parathyroid hormone, so an inappropriately high level points to autonomous secretion rather than vitamin D deficiency, calcitonin excess, or renal failure.
- A 7-year-old child has short stature with a fall across growth percentiles, increased subcutaneous fat, and delayed bone age. Stimulation testing shows a blunted rise in growth hormone, and IGF-1 is low. Which mechanism best explains the short stature?
- Excess growth hormone before epiphyseal closure
- Deficient growth hormone reducing IGF-1-mediated bone growth
- Resistance of tissues to thyroid hormone
- Premature fusion of growth plates from androgen excess
Correct answer: Deficient growth hormone reducing IGF-1-mediated bone growth
Deficient growth hormone reducing IGF-1-mediated bone growth explains this child's poor linear growth. Growth hormone, largely through hepatic IGF-1, stimulates chondrocyte proliferation at the epiphyseal growth plates; when it is deficient, linear growth slows, bone age is delayed, and adiposity increases. The blunted stimulated growth hormone and low IGF-1 confirm the deficiency. Growth hormone excess before plate closure causes gigantism (tall stature), thyroid hormone resistance and androgen-driven premature plate fusion produce different patterns and would not show low growth hormone and IGF-1.
- A 42-year-old man notes that his ring and shoe sizes have increased, his facial features have coarsened, and he now has a prominent jaw and large hands. He also has new diabetes and hypertension. IGF-1 is elevated and growth hormone fails to suppress after an oral glucose load. Which is the most likely cause?
- A prolactin-secreting tumor
- Excess cortisol from an adrenal adenoma
- Primary hypothyroidism
- A growth hormone-secreting pituitary adenoma
Correct answer: A growth hormone-secreting pituitary adenoma
A growth hormone-secreting pituitary adenoma causing acromegaly is the most likely cause. In adults whose growth plates have fused, growth hormone excess enlarges acral and soft tissues rather than increasing height, producing the enlarging hands, feet, and jaw, along with insulin resistance causing diabetes and hypertension. The diagnostic hallmark is failure of growth hormone to suppress after a glucose load plus an elevated IGF-1. Cortisol excess, hypothyroidism, and prolactinoma cause distinct syndromes that do not produce acral overgrowth.
- A 27-year-old woman who is not pregnant or breastfeeding reports milky nipple discharge and absent menstrual periods. Serum prolactin is markedly elevated, and she has no history of antipsychotic use. Which mechanism best explains her amenorrhea?
- Prolactin suppresses GnRH, lowering LH and FSH
- Prolactin directly destroys the ovarian follicles
- Prolactin stimulates excessive estrogen secretion
- Prolactin increases thyroid hormone, halting ovulation
Correct answer: Prolactin suppresses GnRH, lowering LH and FSH
Prolactin suppression of GnRH is the mechanism linking a prolactinoma to amenorrhea. Elevated prolactin inhibits hypothalamic gonadotropin-releasing hormone, which lowers pituitary LH and FSH secretion; the resulting hypogonadism halts ovulation and menses, while prolactin's action on breast tissue causes galactorrhea. Prolactin does not destroy follicles, raise estrogen, or work through thyroid hormone to stop ovulation. Dopamine agonists, which mimic the normal inhibitory control of prolactin, are the typical treatment.
- A 50-year-old man presents to the emergency department with confusion and lethargy. He is hypotensive and afebrile, and laboratory testing shows a serum sodium of 118 mEq/L. After a recent pituitary surgery he has been polyuric with very dilute urine and excessive thirst, but today his urine is concentrated despite the low sodium. Which hormone deficiency is the typical cause of his initial polyuria?
- Cortisol
- Aldosterone
- Antidiuretic hormone (vasopressin)
- Parathyroid hormone
Correct answer: Antidiuretic hormone (vasopressin)
Deficiency of antidiuretic hormone (vasopressin) causes central diabetes insipidus, the typical reason for polyuria and dilute urine after pituitary or hypothalamic surgery. Without vasopressin acting on renal collecting ducts, the kidney cannot concentrate urine, so large volumes of dilute urine are lost and thirst drives high water intake. The posterior pituitary stores vasopressin, making it vulnerable to surgical injury. Aldosterone, cortisol, and parathyroid hormone deficiencies do not cause this hypotonic polyuria.
- A hospitalized patient with small cell lung carcinoma develops hyponatremia. Laboratory studies show low serum osmolality, inappropriately concentrated urine, elevated urine sodium, and euvolemia, with normal thyroid and adrenal function. Which mechanism best explains these findings?
- Loss of antidiuretic hormone causing free water loss
- Excess antidiuretic hormone causing water retention
- Aldosterone deficiency causing sodium wasting
- Glucocorticoid excess causing sodium retention
Correct answer: Excess antidiuretic hormone causing water retention
Excess antidiuretic hormone causing water retention defines the syndrome of inappropriate antidiuretic hormone secretion, here from ectopic production by small cell lung carcinoma. Unregulated vasopressin makes the collecting ducts retain free water, diluting serum sodium and lowering serum osmolality while the urine stays inappropriately concentrated and sodium-rich; volume status is roughly normal. The opposite hormone problem causes diabetes insipidus with dilute urine, while aldosterone deficiency and glucocorticoid excess produce different volume and electrolyte patterns.
- A newborn girl has ambiguous genitalia, and at two weeks of age she presents with vomiting, dehydration, hyponatremia, and hyperkalemia. Testing reveals elevated 17-hydroxyprogesterone. A deficiency of which enzyme is the most common cause of this presentation?
- 5-alpha-reductase
- Aromatase
- 11-beta-hydroxysteroid dehydrogenase
- 21-hydroxylase
Correct answer: 21-hydroxylase
21-hydroxylase deficiency is the most common cause of congenital adrenal hyperplasia and of this salt-wasting presentation. The enzyme block impairs cortisol and aldosterone synthesis while shunting precursors into androgens; the result is elevated 17-hydroxyprogesterone, virilization causing ambiguous genitalia in a genetic female, and a salt-wasting crisis with hyponatremia and hyperkalemia from aldosterone deficiency. Aromatase and 5-alpha-reductase defects affect sex steroid metabolism differently, and 11-beta-hydroxysteroid dehydrogenase deficiency causes apparent mineralocorticoid excess, not salt wasting.
- A 16-year-old phenotypic female presents with primary amenorrhea. She has normal breast development but absent axillary and pubic hair, a blind-ending vagina, and no uterus. Karyotype is 46,XY and testosterone is in the normal male range. Which mechanism explains this presentation?
- A defective androgen receptor preventing tissue response to testosterone
- Deficiency of testosterone production by the testes
- Absence of anti-Mullerian hormone
- Excess conversion of testosterone to estrogen
Correct answer: A defective androgen receptor preventing tissue response to testosterone
A defective androgen receptor preventing tissue response to androgens explains complete androgen insensitivity syndrome. In a 46,XY individual the testes produce normal testosterone and anti-Mullerian hormone, but target tissues cannot respond to androgens, so external genitalia develop as female and pubic and axillary hair are sparse. Anti-Mullerian hormone still causes Mullerian regression, so there is no uterus, giving primary amenorrhea. Testosterone production is normal here, the absence of response (not absence of the hormone) is the defect, and peripheral aromatization to estrogen contributes to breast development.
- A 17-year-old boy is evaluated for tall stature, small firm testes, gynecomastia, and infertility. Karyotype shows 47,XXY. Which hormonal pattern is most characteristic of this condition?
- Normal testosterone with low FSH and LH
- High testosterone with suppressed gonadotropins
- Low testosterone with elevated FSH and LH
- Low estrogen with low gonadotropins
Correct answer: Low testosterone with elevated FSH and LH
Low testosterone with elevated FSH and LH is characteristic of Klinefelter syndrome. The extra X chromosome leads to progressive seminiferous tubule fibrosis and Leydig cell dysfunction, lowering testosterone and impairing sperm production; reduced negative feedback then raises pituitary FSH and LH (primary hypogonadism). The relative estrogen-to-androgen imbalance contributes to gynecomastia. High testosterone with suppressed gonadotropins or normal testosterone with low gonadotropins would not fit this primary testicular failure.
- A 15-year-old girl presents with primary amenorrhea, short stature, a webbed neck, widely spaced nipples, and a history of coarctation of the aorta. Karyotype is 45,X. Which ovarian finding best explains her amenorrhea and lack of pubertal development?
- Polycystic ovaries with excess androgens
- Streak gonads with accelerated follicle loss
- An estrogen-secreting granulosa cell tumor
- Functioning ovaries with an outflow obstruction
Correct answer: Streak gonads with accelerated follicle loss
Streak gonads with accelerated follicle loss explain the ovarian failure of Turner syndrome. The single X chromosome leads to premature depletion of ovarian follicles, leaving fibrous streak gonads that cannot produce estrogen, so puberty does not progress and amenorrhea results, accompanied by elevated gonadotropins. The associated short stature, webbed neck, and coarctation complete the picture. Polycystic ovaries, a hormone-secreting tumor, and a simple outflow obstruction would not produce the gonadal failure central to this karyotype.
- A 26-year-old woman has a positive home pregnancy test and presents with severe lower abdominal pain and vaginal bleeding at 7 weeks by dates. Transvaginal ultrasound shows an empty uterus and a complex mass adjacent to the right ovary, with serum beta-hCG of 4,000 mIU/mL. Which is the most likely diagnosis?
- Ruptured ovarian cyst unrelated to pregnancy
- Complete molar pregnancy
- Threatened intrauterine abortion
- Ectopic pregnancy in the fallopian tube
Correct answer: Ectopic pregnancy in the fallopian tube
Ectopic pregnancy in the fallopian tube is most likely. A positive pregnancy test with an empty uterus, an adnexal mass, and a beta-hCG above the level at which an intrauterine gestation should be visible strongly indicates implantation outside the uterine cavity, most commonly in the ampulla of the fallopian tube. This is a surgical and medical emergency because tubal rupture can cause life-threatening hemorrhage. A molar pregnancy usually shows a characteristic intrauterine pattern with very high hCG, and the pregnancy findings make an unrelated cyst unlikely.
- A 24-year-old woman presents with vaginal bleeding and a uterus larger than expected for 12 weeks of amenorrhea. Serum beta-hCG is extremely elevated, ultrasound shows a snowstorm pattern with no fetus, and she has hyperemesis. Which mechanism explains the markedly elevated beta-hCG?
- Proliferation of trophoblastic tissue without a normal fetus
- A multiple gestation with several normal fetuses
- Adrenal androgen excess raising hCG
- Ovarian follicle production of hCG
Correct answer: Proliferation of trophoblastic tissue without a normal fetus
Proliferation of trophoblastic tissue without a normal fetus explains the very high beta-hCG of a complete hydatidiform mole. Abnormal fertilization produces only paternal genetic material, generating grossly hydropic, proliferating chorionic villi (the snowstorm appearance) and no viable fetus; the massive trophoblastic mass secretes far more hCG than a normal pregnancy, which also drives the hyperemesis. The diagnosis matters because of the risk of progression to gestational trophoblastic neoplasia. Multiple gestation, adrenal androgens, and ovarian follicles do not produce this picture.
- During the menstrual cycle, a surge in luteinizing hormone triggers ovulation at midcycle. Which event most directly causes this LH surge?
- A fall in inhibin from the granulosa cells
- A sharp rise in progesterone from the corpus luteum
- A sustained high level of estradiol switching feedback from negative to positive
- A surge in prolactin from the anterior pituitary
Correct answer: A sustained high level of estradiol switching feedback from negative to positive
A sustained high level of estradiol switching feedback from negative to positive most directly triggers the LH surge. As the dominant follicle matures in the follicular phase, it secretes rising estradiol; once estradiol stays elevated past a threshold for long enough, it paradoxically stimulates rather than inhibits gonadotropin release, producing the midcycle LH surge that induces ovulation. Progesterone rises mainly after ovulation from the corpus luteum, inhibin selectively restrains FSH, and prolactin is not the ovulatory trigger.
- A woman has a regular 28-day menstrual cycle. After ovulation, the corpus luteum forms and secretes progesterone, which prepares the endometrium for implantation. If fertilization does not occur, which event causes the subsequent menstruation?
- A second LH surge degrading the endometrium
- Regression of the corpus luteum causing progesterone withdrawal
- Rising estrogen directly shedding the lining
- Increased FSH dissolving the endometrium
Correct answer: Regression of the corpus luteum causing progesterone withdrawal
Regression of the corpus luteum causing progesterone withdrawal triggers menstruation. The corpus luteum maintains the secretory endometrium through progesterone; without fertilization and the hCG that would rescue it, the corpus luteum involutes after roughly two weeks, progesterone (and estrogen) fall, the endometrial spiral arteries constrict, and the functional layer is shed as menses. A second LH surge does not occur, and neither estrogen nor FSH directly sheds the lining; it is the loss of luteal progesterone support that drives menstruation.
- A 60-year-old man reports a weak urinary stream, hesitancy, nocturia, and a sensation of incomplete emptying. Digital rectal examination reveals a smoothly enlarged, nontender prostate, and his prostate-specific antigen is mildly elevated. Which process best explains his symptoms?
- Fibrosis of the bladder wall from chronic infection
- Malignant transformation of the peripheral zone
- Acute bacterial infection of the prostate
- Hyperplasia of the periurethral transition zone of the prostate
Correct answer: Hyperplasia of the periurethral transition zone of the prostate
Hyperplasia of the periurethral transition zone characterizes benign prostatic hyperplasia. With aging and androgen action (notably dihydrotestosterone), the transition zone surrounding the urethra enlarges, compressing the urethra and producing obstructive symptoms such as hesitancy, weak stream, and nocturia, with a smoothly enlarged gland on examination. Prostate cancer typically arises in the peripheral zone and feels nodular, acute bacterial prostatitis is painful and febrile, and bladder fibrosis would not produce a smoothly enlarged prostate.
- A 22-year-old man presents with a painless, firm testicular mass. Ultrasound confirms a solid intratesticular lesion, and serum lactate dehydrogenase is elevated. Which tumor marker, if elevated, would most specifically indicate a nonseminomatous germ cell component such as yolk sac tumor?
- Alpha-fetoprotein
- Prostate-specific antigen
- Calcitonin
- Carcinoembryonic antigen
Correct answer: Alpha-fetoprotein
Alpha-fetoprotein elevation specifically indicates a nonseminomatous germ cell component, classically a yolk sac (endodermal sinus) tumor, and is also seen with embryonal carcinoma. Pure seminomas do not produce alpha-fetoprotein, so its elevation tells the clinician the tumor is at least partly nonseminomatous, which changes prognosis and treatment. Prostate-specific antigen relates to the prostate, calcitonin to medullary thyroid carcinoma, and carcinoembryonic antigen to gastrointestinal and other malignancies, none of which marks testicular germ cell histology this specifically.
- A 56-year-old postmenopausal woman presents with abdominal distension, early satiety, and a pelvic mass. Imaging shows a complex ovarian mass with ascites, and CA-125 is markedly elevated. Which factor is most strongly protective against this type of malignancy?
- Early menarche and late menopause
- Prior use of combined oral contraceptives
- Nulliparity
- A family history with BRCA1 mutation
Correct answer: Prior use of combined oral contraceptives
Prior use of combined oral contraceptives is the strongest protective factor against epithelial ovarian cancer. By suppressing ovulation, these agents reduce the repeated ovulatory surface trauma and proliferation thought to contribute to malignant transformation; the protective effect increases with duration of use. In contrast, conditions that increase lifetime ovulatory cycles, such as early menarche, late menopause, and nulliparity, raise risk, and a BRCA1 mutation markedly increases risk. Recognizing the protective role of ovulation suppression is high-yield reproductive pathophysiology.
- A 35-year-old woman has heavy, prolonged menstrual bleeding and pelvic pressure. Examination reveals an enlarged, firm, irregular uterus, and ultrasound shows several well-circumscribed myometrial masses. These benign tumors are most directly dependent on which hormone for growth?
- Aldosterone
- Cortisol
- Thyroid hormone
- Estrogen
Correct answer: Estrogen
Estrogen most directly drives the growth of uterine leiomyomas (fibroids), the benign smooth muscle tumors described. Fibroids express abundant estrogen and progesterone receptors and tend to enlarge during reproductive years and high-estrogen states such as pregnancy, then regress after menopause when estrogen falls. This hormone dependence explains why antiestrogen and gonadotropin-suppressing therapies can shrink them. Cortisol, thyroid hormone, and aldosterone do not govern fibroid growth.
- A 32-year-old woman reports severe pain with menstruation, pain with intercourse, and difficulty conceiving. Laparoscopy reveals ectopic endometrial glands and stroma on the ovaries and pelvic peritoneum, with chocolate-appearing ovarian cysts. Which feature best explains the cyclic pain?
- The ectopic tissue responds to cyclic hormones and bleeds locally
- The lesions secrete catecholamines causing spasms
- Bacterial infection of the implants causes recurrent abscesses
- Malignant invasion of pelvic nerves causes the pain
Correct answer: The ectopic tissue responds to cyclic hormones and bleeds locally
The ectopic endometrial tissue responding to cyclic hormones and bleeding locally explains the cyclic pelvic pain of endometriosis. Functional endometrial glands and stroma outside the uterus respond to the same hormonal fluctuations as the lining, so they proliferate and bleed with menses; the trapped blood and inflammation cause pain, adhesions, and the chocolate cysts (endometriomas), and can impair fertility. The implants do not secrete catecholamines, are not infectious abscesses, and are not malignant nerve invasion.
- A 9-year-old girl has breast development and pubic hair, accelerated growth, and an advanced bone age. Workup shows elevated LH and FSH and elevated estradiol, with no intracranial lesion identified. Which term best describes the mechanism of her early puberty?
- Premature thelarche without true puberty
- Peripheral precocious puberty from an ovarian tumor
- Central (gonadotropin-dependent) precocious puberty
- Exogenous estrogen exposure
Correct answer: Central (gonadotropin-dependent) precocious puberty
Central (gonadotropin-dependent) precocious puberty best describes this picture. Early activation of the hypothalamic-pituitary-gonadal axis raises GnRH-driven LH and FSH, which stimulate the gonads to produce sex steroids, advancing breast and pubic hair development and bone age in a normally sequenced pattern. The elevated gonadotropins distinguish it from peripheral causes, in which gonadotropins are suppressed by autonomous sex steroid production from a tumor or exogenous source. Premature thelarche shows isolated breast tissue without advanced bone age.
- A 19-year-old woman has never had a menstrual period. She has normal breast development and a uterus on ultrasound. Hormone testing shows low estradiol with low LH and FSH that fail to rise appropriately, and she has anosmia. Which condition best explains these findings?
- Primary ovarian insufficiency
- Kallmann syndrome with deficient GnRH secretion
- Polycystic ovary syndrome
- An estrogen-secreting tumor
Correct answer: Kallmann syndrome with deficient GnRH secretion
Kallmann syndrome with deficient GnRH secretion explains hypogonadotropic hypogonadism accompanied by anosmia. Failure of GnRH neurons to migrate properly during development impairs both gonadotropin-releasing hormone secretion and the sense of smell; low GnRH yields low LH and FSH and therefore low estradiol, producing primary amenorrhea and delayed puberty. Primary ovarian insufficiency would show high gonadotropins, polycystic ovary syndrome features androgen excess with normal or elevated LH, and an estrogen-secreting tumor would raise estradiol.
- A 28-year-old woman presents with a thyroid nodule, and family history reveals relatives with thyroid cancer, pheochromocytoma, and elevated calcium. Genetic testing shows a RET proto-oncogene mutation. Which thyroid malignancy is most associated with this syndrome?
- Anaplastic thyroid carcinoma
- Papillary thyroid carcinoma
- Follicular thyroid carcinoma
- Medullary thyroid carcinoma
Correct answer: Medullary thyroid carcinoma
Medullary thyroid carcinoma is most associated with this presentation of multiple endocrine neoplasia type 2 and germline RET mutation. Medullary carcinoma arises from calcitonin-secreting parafollicular C cells and clusters with pheochromocytoma and (in type 2A) parathyroid hyperplasia, the combination described. Recognizing the RET-driven syndrome matters because prophylactic thyroidectomy can prevent this aggressive cancer. Papillary and follicular carcinomas arise from follicular cells and are not features of this syndrome, and anaplastic carcinoma is an unrelated aggressive tumor of older adults.
- A 30-year-old man has recurrent peptic ulcers in unusual locations and chronic diarrhea. Fasting gastrin is markedly elevated, and he is found to also have a parathyroid adenoma and a pituitary tumor. Which inherited syndrome best unifies these findings?
- Multiple endocrine neoplasia type 1
- Multiple endocrine neoplasia type 2B
- Von Hippel-Lindau disease
- Neurofibromatosis type 1
Correct answer: Multiple endocrine neoplasia type 1
Multiple endocrine neoplasia type 1 best unifies these findings. This syndrome classically combines tumors of the parathyroid glands, the pancreatic islets (here a gastrin-secreting tumor causing the refractory ulcers and diarrhea), and the anterior pituitary, the so-called three Ps. It results from loss of the MEN1 tumor suppressor. Type 2B features medullary thyroid carcinoma, pheochromocytoma, and mucosal neuromas rather than a gastrinoma and parathyroid-pituitary combination, and von Hippel-Lindau and neurofibromatosis involve different tumor spectra.
- A 33-year-old woman is found to have a fasting hypoglycemia with documented serum glucose of 38 mg/dL accompanied by inappropriately high insulin and high C-peptide, with negative screening for sulfonylureas. Which lesion best explains these findings?
- Excess glucagon from an alpha cell tumor
- Factitious injection of exogenous insulin
- An insulin-secreting pancreatic islet tumor
- Cortisol excess from an adrenal adenoma
Correct answer: An insulin-secreting pancreatic islet tumor
An insulin-secreting pancreatic islet tumor (insulinoma) best explains fasting hypoglycemia with inappropriately elevated insulin and C-peptide. Because C-peptide is co-secreted with endogenous insulin, its elevation indicates the insulin is being produced by the patient's own beta cells rather than injected. The negative sulfonylurea screen excludes drug-induced secretion. Exogenous insulin would raise insulin but suppress C-peptide, a glucagonoma causes hyperglycemia, and cortisol excess raises rather than lowers glucose.
- During fetal development, the testes secrete a substance that causes regression of the paramesonephric (Mullerian) ducts in a male fetus. Which cell and product are responsible?
- Leydig cells secreting testosterone
- Sertoli cells secreting anti-Mullerian hormone
- Granulosa cells secreting inhibin
- Theca cells secreting androstenedione
Correct answer: Sertoli cells secreting anti-Mullerian hormone
Sertoli cells secreting anti-Mullerian hormone are responsible for Mullerian duct regression in the male fetus. This hormone causes involution of the paramesonephric ducts that would otherwise form the uterus and fallopian tubes, while Leydig cell testosterone separately promotes development of the mesonephric (Wolffian) ducts into male internal structures. Granulosa and theca cells are ovarian and not involved in male duct regression. This division of labor is a high-yield reproductive endocrinology concept.
- A 65-year-old man with metastatic prostate cancer is started on a GnRH agonist for androgen deprivation. He is warned that this drug can transiently worsen his disease in the first one to two weeks. Which mechanism explains both the initial flare and the eventual suppression of testosterone?
- Inhibition of 5-alpha-reductase
- Direct destruction of testicular Leydig cells
- Blockade of the androgen receptor in the prostate
- Initial stimulation then desensitization of pituitary GnRH receptors
Correct answer: Initial stimulation then desensitization of pituitary GnRH receptors
Initial stimulation followed by desensitization of pituitary GnRH receptors explains the biphasic effect of a GnRH agonist. Continuous, nonpulsatile agonist exposure first stimulates LH release, transiently raising testosterone and causing the tumor flare, but persistent stimulation then downregulates and desensitizes the receptors, suppressing LH and lowering testosterone to castrate levels. This is why an antiandrogen is often co-administered initially. The drug does not destroy Leydig cells, block the androgen receptor, or inhibit 5-alpha-reductase.
- A 30-year-old pregnant woman at 10 weeks gestation is noted to have a suppressed TSH and mildly elevated free T4 but no goiter, eye findings, or antibodies, and she feels well. Which mechanism most likely explains her transient biochemical hyperthyroidism?
- hCG cross-stimulation of the TSH receptor
- New-onset Graves disease
- Excess iodine intake
- A toxic thyroid adenoma
Correct answer: hCG cross-stimulation of the TSH receptor
hCG cross-stimulation of the TSH receptor most likely explains this mild, transient first-trimester picture. Human chorionic gonadotropin shares structural similarity with TSH and can weakly activate the TSH receptor; its peak in early pregnancy can mildly stimulate the thyroid, slightly lowering TSH and raising free T4 without the autoimmune features of Graves disease. The absence of antibodies, goiter, and eye signs and the spontaneous course fit this physiologic phenomenon rather than Graves disease, iodine excess, or an autonomous adenoma.
- A patient with type 2 diabetes is started on metformin. Which action is the primary mechanism by which metformin lowers blood glucose?
- Blocking intestinal glucose absorption entirely
- Stimulating insulin release from beta cells
- Decreasing hepatic gluconeogenesis
- Increasing renal glucose reabsorption
Correct answer: Decreasing hepatic gluconeogenesis
Decreasing hepatic gluconeogenesis is metformin's primary glucose-lowering action. By reducing the liver's output of glucose and modestly improving peripheral insulin sensitivity, metformin lowers glucose without directly stimulating insulin secretion, which is why it rarely causes hypoglycemia by itself. Sulfonylureas stimulate beta-cell insulin release, alpha-glucosidase inhibitors slow intestinal carbohydrate absorption, and SGLT2 inhibitors decrease (not increase) renal glucose reabsorption; none of these describes metformin.
- A patient with type 2 diabetes is started on an SGLT2 inhibitor. Through which mechanism does this drug lower blood glucose?
- Stimulating pancreatic insulin secretion
- Promoting urinary excretion of glucose by blocking proximal tubule reabsorption
- Inhibiting hepatic glucose production
- Slowing gastric emptying
Correct answer: Promoting urinary excretion of glucose by blocking proximal tubule reabsorption
Promoting urinary glucose excretion by blocking proximal tubule reabsorption is the mechanism of SGLT2 inhibitors. The sodium-glucose cotransporter 2 normally reabsorbs most filtered glucose in the proximal tubule; inhibiting it causes glucosuria, lowering serum glucose independent of insulin. This also produces mild osmotic diuresis. Insulin secretagogues act on beta cells, metformin reduces hepatic glucose production, and GLP-1-based agents slow gastric emptying; these are distinct mechanisms from renal glucose loss.
- A 50-year-old man with poorly controlled diabetes has progressively worsening kidney function, with increasing albuminuria and a thickened glomerular basement membrane. Biopsy shows nodular glomerulosclerosis. Which intervention most directly slows progression by reducing intraglomerular pressure?
- A nondihydropyridine calcium channel blocker
- A loop diuretic
- An alpha blocker
- An ACE inhibitor or angiotensin receptor blocker
Correct answer: An ACE inhibitor or angiotensin receptor blocker
An ACE inhibitor or angiotensin receptor blocker most directly slows diabetic kidney disease by lowering intraglomerular pressure. These agents preferentially dilate the efferent arteriole, reducing the high pressure within the glomerulus that drives albuminuria and progressive sclerosis in diabetes; this renoprotective effect is independent of and additive to systemic blood pressure control. Loop diuretics, alpha blockers, and calcium channel blockers can lower blood pressure but do not produce the same efferent arteriolar effect that protects the diabetic glomerulus.
- A patient with long-standing diabetes reports numbness and tingling in a stocking distribution of both feet and has lost protective sensation on monofilament testing. Which underlying process best explains this complication?
- Chronic hyperglycemia damaging peripheral nerves through metabolic and microvascular injury
- Autoimmune demyelination of peripheral nerves
- Compression of the spinal cord by a tumor
- Vitamin B12 deficiency from pernicious anemia
Correct answer: Chronic hyperglycemia damaging peripheral nerves through metabolic and microvascular injury
Chronic hyperglycemia damaging peripheral nerves through metabolic and microvascular injury explains diabetic peripheral neuropathy. Prolonged high glucose injures nerves through pathways such as sorbitol accumulation, advanced glycation end products, and damage to the vasa nervorum, producing the symmetric distal sensory loss in a stocking pattern that places diabetics at risk for foot ulcers. This is a complication of the endocrine disease itself rather than an autoimmune demyelination, a structural cord lesion, or a separate B12 deficiency.
- A 38-year-old woman six months postpartum reports fatigue, palpitations, and weight loss, then weeks later develops fatigue and cold intolerance. Examination shows a small, nontender goiter. Antithyroid peroxidase antibodies are positive, and a radioiodine uptake during the hyperthyroid phase is low. Which condition best explains this course?
- Toxic multinodular goiter
- Graves disease
- Postpartum thyroiditis
- Iodine deficiency
Correct answer: Postpartum thyroiditis
Postpartum thyroiditis best explains this biphasic course. Autoimmune lymphocytic inflammation of the thyroid after delivery releases preformed hormone, causing a transient hyperthyroid phase with a characteristically low radioiodine uptake (because the gland is not actively synthesizing hormone), often followed by a hypothyroid phase before recovery. Positive peroxidase antibodies support the autoimmune basis. Graves disease and toxic multinodular goiter show high uptake from active hormone production, and iodine deficiency causes hypothyroidism with goiter rather than this transient thyrotoxic phase.
- A 45-year-old man undergoes a normal stress response. Cortisol release from the adrenal cortex is regulated by a hormone from the anterior pituitary, which in turn responds to a hypothalamic releasing factor. Which sequence correctly represents this axis?
- ACTH from the hypothalamus stimulates CRH, which stimulates cortisol
- CRH from the hypothalamus stimulates ACTH, which stimulates cortisol
- Cortisol stimulates ACTH, which stimulates CRH
- TRH stimulates ACTH, which stimulates cortisol
Correct answer: CRH from the hypothalamus stimulates ACTH, which stimulates cortisol
CRH from the hypothalamus stimulating ACTH, which stimulates cortisol, correctly represents the hypothalamic-pituitary-adrenal axis. Corticotropin-releasing hormone from the hypothalamus drives ACTH release from the anterior pituitary, and ACTH stimulates the adrenal cortex to secrete cortisol; cortisol then exerts negative feedback on both the hypothalamus and pituitary. The other sequences reverse the hierarchy or substitute TRH, which regulates thyroid hormone rather than cortisol. Understanding this axis underlies interpretation of adrenal disorders.
- A patient is found to have hypercalcemia, and parathyroid hormone is appropriately suppressed. Workup reveals a granulomatous lung disease. Which mechanism best explains the elevated calcium in this setting?
- Renal phosphate wasting
- Parathyroid hormone overproduction from an adenoma
- Calcitonin deficiency
- Macrophages in granulomas activate vitamin D, increasing intestinal calcium absorption
Correct answer: Macrophages in granulomas activate vitamin D, increasing intestinal calcium absorption
Macrophages within granulomas activating vitamin D best explains this hypercalcemia. Activated macrophages express 1-alpha-hydroxylase and convert vitamin D to its active form independent of parathyroid hormone, increasing intestinal calcium absorption and raising serum calcium; the high calcium then appropriately suppresses parathyroid hormone. This is a classic mechanism in granulomatous diseases. A parathyroid adenoma would show elevated, not suppressed, parathyroid hormone, and calcitonin deficiency and phosphate wasting do not account for this vitamin D-mediated pattern.
- A 68-year-old man with metastatic squamous cell lung carcinoma is found to have a serum calcium of 13.8 mg/dL with a suppressed parathyroid hormone and a low phosphate. Which mediator most likely explains this paraneoplastic hypercalcemia?
- Parathyroid hormone-related peptide
- Calcitonin
- Aldosterone
- Insulin-like growth factor 1
Correct answer: Parathyroid hormone-related peptide
Parathyroid hormone-related peptide most likely explains this paraneoplastic hypercalcemia. Certain tumors, classically squamous cell carcinomas, secrete this peptide, which acts on parathyroid hormone receptors to raise serum calcium and increase renal phosphate excretion, mimicking hyperparathyroidism; the patient's own parathyroid hormone is suppressed by the high calcium. Calcitonin lowers calcium, aldosterone governs sodium and potassium, and insulin-like growth factor 1 does not cause hypercalcemia. Recognizing this mediator links oncology with endocrine calcium regulation.
- A 55-year-old woman has a single 2.5-cm thyroid nodule. Fine-needle aspiration shows cells with overlapping nuclei, nuclear grooves, and intranuclear inclusions, and psammoma bodies are present. Which thyroid cancer does this describe, and what is its typical behavior?
- Anaplastic carcinoma, which is rapidly fatal
- Follicular carcinoma, which spreads hematogenously
- Papillary carcinoma, which spreads via lymphatics and has a good prognosis
- Medullary carcinoma, which secretes calcitonin
Correct answer: Papillary carcinoma, which spreads via lymphatics and has a good prognosis
Papillary carcinoma with lymphatic spread and a generally good prognosis is described by these nuclear features and psammoma bodies. Papillary thyroid carcinoma, the most common thyroid malignancy, is recognized cytologically by ground-glass (Orphan Annie) nuclei, nuclear grooves, intranuclear inclusions, and laminated calcifications; it tends to metastasize to cervical lymph nodes yet carries an excellent prognosis. Follicular carcinoma spreads hematogenously, anaplastic carcinoma is highly aggressive, and medullary carcinoma secretes calcitonin and shows amyloid, not these papillary features.
- A clinician describes the principal action of glucagon during fasting. Which effect on the liver best represents glucagon's role in glucose homeostasis?
- Promoting glycogen synthesis to store glucose
- Stimulating glycogenolysis and gluconeogenesis to raise blood glucose
- Increasing peripheral glucose uptake into muscle
- Inhibiting hepatic ketone production
Correct answer: Stimulating glycogenolysis and gluconeogenesis to raise blood glucose
Stimulating hepatic glycogenolysis and gluconeogenesis to raise blood glucose best represents glucagon's role. Secreted by pancreatic alpha cells when glucose is low, glucagon mobilizes hepatic glycogen and promotes new glucose synthesis, opposing insulin to maintain euglycemia during fasting; it also promotes ketogenesis as an alternative fuel. Glycogen synthesis and increased peripheral muscle glucose uptake are insulin's effects, and inhibiting ketone production is the opposite of glucagon's action. This insulin-glucagon balance is foundational endocrine physiology.
- A medical student studies how insulin lowers blood glucose after a meal. Which cellular action most directly accounts for increased glucose uptake into skeletal muscle and adipose tissue in response to insulin?
- Opening of voltage-gated calcium channels
- Inhibition of the sodium-potassium ATPase
- Activation of glucagon receptors
- Translocation of GLUT4 transporters to the cell membrane
Correct answer: Translocation of GLUT4 transporters to the cell membrane
Translocation of GLUT4 transporters to the cell membrane most directly accounts for insulin-stimulated glucose uptake in muscle and fat. Insulin binding to its receptor triggers a signaling cascade that moves GLUT4-containing vesicles to the plasma membrane, dramatically increasing glucose entry into these insulin-sensitive tissues. This is why these tissues, unlike the brain or liver, depend on insulin for efficient glucose uptake. Insulin does not lower glucose by inhibiting the sodium-potassium ATPase, activating glucagon receptors, or opening calcium channels.
- A 24-year-old man with no pubertal development has small testes, a high-pitched voice, and absent secondary sexual characteristics. Hormone testing shows low testosterone with low LH and FSH, and MRI reveals a large nonfunctioning pituitary mass compressing the gland. Which mechanism explains his hypogonadism?
- Pituitary compression reducing gonadotropin secretion
- Primary testicular failure
- Excess prolactin from the mass alone
- Androgen receptor insensitivity
Correct answer: Pituitary compression reducing gonadotropin secretion
Pituitary compression reducing gonadotropin secretion explains this secondary (hypogonadotropic) hypogonadism. A large sellar mass can compress and destroy the gonadotroph cells, lowering LH and FSH and thereby reducing testicular stimulation and testosterone, which halts pubertal development. The low gonadotropins point to a central pituitary cause rather than primary testicular failure, which would raise LH and FSH. Although prolactin excess can also suppress gonadotropins, the described nonfunctioning mass acts mainly by compression, and androgen insensitivity would not lower testosterone.
- A 28-year-old woman who had a severe postpartum hemorrhage with hypotension later develops inability to lactate, amenorrhea, fatigue, and cold intolerance. Which mechanism best explains her panhypopituitarism?
- A prolactin-secreting adenoma
- An autoimmune attack on the posterior pituitary
- Ischemic necrosis of the enlarged anterior pituitary
- Hemorrhage into an adrenal gland
Correct answer: Ischemic necrosis of the enlarged anterior pituitary
Ischemic necrosis of the enlarged anterior pituitary explains Sheehan syndrome. During pregnancy the anterior pituitary enlarges and becomes more vulnerable to hypoperfusion; severe postpartum hemorrhage with hypotension can infarct it, causing loss of multiple anterior hormones. Failure of prolactin manifests as inability to lactate, loss of gonadotropins causes amenorrhea, and loss of TSH and ACTH causes the hypothyroid and adrenal symptoms. This is a pituitary infarction, not an autoimmune posterior process, a secreting tumor, or an adrenal hemorrhage.
- A 60-year-old man is incidentally found to have a 2-cm adrenal mass on abdominal imaging done for another reason. He is asymptomatic. Which initial step in evaluation is most appropriate?
- Immediately perform an adrenal biopsy
- Assess whether the mass is hormonally functional with biochemical testing
- Begin glucocorticoid replacement
- Proceed directly to bilateral adrenalectomy
Correct answer: Assess whether the mass is hormonally functional with biochemical testing
Assessing whether the adrenal incidentaloma is hormonally functional with biochemical testing is the most appropriate first step. Even asymptomatic adrenal masses can autonomously secrete cortisol, aldosterone, or catecholamines, so screening for hypercortisolism, primary aldosteronism, and pheochromocytoma guides management and prevents dangerous surprises (for example, operating on an unsuspected pheochromocytoma). Biopsy is generally avoided, especially before excluding pheochromocytoma, and neither empiric glucocorticoid replacement nor immediate bilateral adrenalectomy is indicated for an incidental mass.
- A medical student reviews calcium regulation. When serum calcium falls, parathyroid hormone is secreted. Which combination of actions does parathyroid hormone use to restore calcium?
- Increasing renal phosphate reabsorption and lowering vitamin D
- Decreasing bone resorption and increasing renal calcium excretion
- Stimulating thyroid C cells to release calcitonin
- Increasing bone resorption, renal calcium reabsorption, and renal vitamin D activation
Correct answer: Increasing bone resorption, renal calcium reabsorption, and renal vitamin D activation
Increasing bone resorption, renal calcium reabsorption, and renal vitamin D activation is how parathyroid hormone restores a low serum calcium. It mobilizes calcium from bone, enhances distal tubular calcium reabsorption, and stimulates renal conversion of vitamin D to its active form, which boosts intestinal calcium absorption; it simultaneously promotes renal phosphate excretion. Calcitonin from thyroid C cells lowers calcium and is not driven by parathyroid hormone, and decreasing bone resorption or reducing vitamin D would worsen, not correct, hypocalcemia.
- A 30-year-old woman with regular cycles is trying to conceive. To time intercourse, she tracks ovulation by detecting a hormone surge in her urine. Which hormone does an over-the-counter ovulation predictor kit detect?
- Luteinizing hormone
- Progesterone
- Estrogen
- Beta-hCG
Correct answer: Luteinizing hormone
Luteinizing hormone is what ovulation predictor kits detect. The midcycle LH surge precedes ovulation by roughly a day, so a urinary LH rise signals that ovulation is imminent and identifies the most fertile window. Progesterone rises after ovulation and confirms it has occurred rather than predicting it, estrogen peaks earlier but is not the test target, and beta-hCG is a marker of pregnancy, not ovulation. This applies menstrual cycle endocrinology to a practical reproductive scenario.
- A 25-year-old woman taking a combined oral contraceptive pill understands it prevents pregnancy mainly by stopping ovulation. Which mechanism most directly accounts for this contraceptive effect?
- They block fertilization by killing sperm in the uterus
- They cause permanent atrophy of the ovaries
- Estrogen and progestin suppress GnRH and the LH surge
- They prevent implantation by removing the endometrium entirely
Correct answer: Estrogen and progestin suppress GnRH and the LH surge
Estrogen and progestin suppressing GnRH and the LH surge most directly account for the contraceptive effect. The steady hormone levels provide negative feedback on the hypothalamus and pituitary, reducing FSH and LH and preventing the midcycle LH surge needed for ovulation; without ovulation, no egg is released. The pills also thicken cervical mucus and alter the endometrium as secondary effects, but they do not cause ovarian atrophy, kill sperm, or remove the endometrium. This applies reproductive endocrine feedback to pharmacology.
- A 58-year-old woman reports hot flashes, night sweats, vaginal dryness, and cessation of menses for over a year. Which hormonal change best characterizes the menopausal transition responsible for these symptoms?
- Rising ovarian estrogen with falling FSH
- Declining ovarian estrogen with rising FSH
- Increased progesterone from persistent corpora lutea
- Elevated prolactin suppressing the ovaries
Correct answer: Declining ovarian estrogen with rising FSH
Declining ovarian estrogen with rising FSH best characterizes menopause. Depletion of ovarian follicles reduces estrogen production, and the loss of negative feedback (and of inhibin) causes pituitary FSH to rise markedly; the low estrogen drives vasomotor symptoms such as hot flashes and the genitourinary changes like vaginal dryness. An elevated FSH supports the diagnosis. The other options reverse the normal physiology or invoke progesterone or prolactin changes that do not explain the menopausal symptom complex.
- A 35-year-old woman with newly diagnosed Graves disease who is pregnant requires antithyroid therapy. Why is propylthiouracil generally preferred over methimazole during the first trimester?
- Propylthiouracil increases thyroid hormone synthesis
- Propylthiouracil has no effect on the fetal thyroid
- Methimazole does not cross the placenta at all
- Methimazole is associated with specific fetal malformations in early pregnancy
Correct answer: Methimazole is associated with specific fetal malformations in early pregnancy
Methimazole's association with specific fetal malformations during organogenesis explains why propylthiouracil is generally preferred in the first trimester. Methimazole exposure in early pregnancy has been linked to embryopathy such as aplasia cutis and choanal or esophageal defects, so propylthiouracil is favored early, with many clinicians switching to methimazole later to limit propylthiouracil's hepatotoxicity risk. Both drugs cross the placenta and inhibit synthesis, so the choice is driven by the teratogenic profile, not by a claimed lack of placental transfer or fetal effect.
- A patient with type 1 diabetes uses a long-acting basal insulin once daily and rapid-acting insulin with meals. Which physiologic principle does this regimen most closely imitate?
- The normal pattern of low basal insulin with meal-stimulated insulin surges
- The complete absence of basal insulin between meals
- Continuous high insulin levels regardless of food
- Insulin secretion only during fasting
Correct answer: The normal pattern of low basal insulin with meal-stimulated insulin surges
The normal pattern of low basal insulin with meal-stimulated surges is what a basal-bolus regimen imitates. In health, the pancreas secretes a steady low level of insulin to restrain hepatic glucose output between meals and adds bursts of insulin in response to carbohydrate intake. Long-acting insulin reproduces the basal component while rapid-acting mealtime doses reproduce the prandial surges, closely matching physiology in a patient lacking endogenous insulin. The other options misstate normal insulin secretion.
- A 47-year-old woman with Cushing syndrome is found to have an elevated ACTH that does suppress with high-dose but not low-dose dexamethasone, and pituitary MRI reveals a small adenoma. Which is the correct diagnosis?
- Primary adrenal adenoma
- Ectopic ACTH from a carcinoid tumor
- Cushing disease from a pituitary corticotroph adenoma
- Exogenous glucocorticoid use
Correct answer: Cushing disease from a pituitary corticotroph adenoma
Cushing disease from a pituitary corticotroph adenoma is the correct diagnosis. A pituitary source of ACTH characteristically retains partial sensitivity to feedback, so cortisol fails to suppress with low-dose dexamethasone but does suppress with high-dose, and ACTH is elevated; the pituitary adenoma confirms the source. Ectopic ACTH-secreting tumors usually do not suppress even at high dose, a primary adrenal adenoma produces low ACTH, and exogenous glucocorticoid use would lower both ACTH and endogenous cortisol. This dexamethasone testing pattern is high-yield.
- A 19-year-old woman presents with primary amenorrhea and absence of breast development. Hormone testing shows low estradiol with markedly elevated FSH and LH, and karyotype is normal 46,XX. Which is the most likely site of the defect?
- The hypothalamus, indicating low GnRH
- The ovary, indicating primary ovarian insufficiency
- The pituitary, indicating gonadotropin deficiency
- The uterus, indicating an outflow obstruction
Correct answer: The ovary, indicating primary ovarian insufficiency
The ovary is the most likely site of the defect, indicating primary ovarian insufficiency. Low estradiol with high FSH and LH localizes the problem to the gonad: the ovaries are not producing estrogen, so the lack of negative feedback drives gonadotropins up. The absent breast development reflects the estrogen deficiency. A hypothalamic or pituitary defect would produce low gonadotropins, and an outflow obstruction would not alter these hormone levels. Interpreting the gonadotropin pattern to localize the lesion is a core reproductive endocrine skill.
- A 33-year-old pregnant woman is screened at 26 weeks with an oral glucose tolerance test and is diagnosed with gestational diabetes. Which hormonal change of pregnancy most directly produces the insulin resistance underlying this condition?
- Suppression of all counterregulatory hormones
- Increased maternal insulin secretion
- Decreased cortisol during pregnancy
- Placental hormones such as human placental lactogen antagonizing insulin
Correct answer: Placental hormones such as human placental lactogen antagonizing insulin
Placental hormones such as human placental lactogen antagonizing insulin most directly produce the insulin resistance of gestational diabetes. As pregnancy advances, the placenta secretes hormones that diminish maternal insulin sensitivity to shunt glucose to the fetus; when the maternal pancreas cannot compensate with enough additional insulin, gestational diabetes develops, which is why screening is performed in the late second trimester. Increased maternal insulin is a compensation rather than the cause, and cortisol and counterregulatory hormones rise rather than fall in pregnancy.
- A 70-year-old woman sustains a vertebral compression fracture after minimal trauma. Bone density testing confirms markedly low bone mineral density. Which hormonal change after menopause most contributes to this accelerated bone loss?
- Estrogen deficiency increasing osteoclast-mediated bone resorption
- Excess calcitonin suppressing bone turnover
- Growth hormone excess thickening bone
- Aldosterone excess depleting bone calcium
Correct answer: Estrogen deficiency increasing osteoclast-mediated bone resorption
Estrogen deficiency increasing osteoclast-mediated bone resorption most contributes to postmenopausal osteoporosis. Estrogen normally restrains osteoclast activity and survival; after menopause its decline tips bone remodeling toward resorption, so bone mass falls and fragility fractures such as vertebral and hip fractures become more likely. This endocrine basis is why estrogen-related and antiresorptive therapies are used. Calcitonin excess would reduce resorption, growth hormone excess does not cause this pattern, and aldosterone does not drive bone loss this way.
- A 45-year-old man with a long history of obesity and snoring is found to have central adiposity, hypertension, elevated fasting glucose, and high triglycerides with low HDL cholesterol. His clinician explains these clustered findings share a common metabolic driver. Which underlying abnormality best links them?
- Thyroid hormone excess
- Cortisol deficiency
- Insulin resistance
- Parathyroid hormone deficiency
Correct answer: Insulin resistance
Insulin resistance best links the clustered findings of metabolic syndrome. Reduced tissue sensitivity to insulin underlies the central obesity, hypertension, elevated fasting glucose, and atherogenic dyslipidemia (high triglycerides, low HDL) that define the syndrome, and it markedly raises cardiovascular and type 2 diabetes risk. Recognizing insulin resistance as the shared driver guides lifestyle and pharmacologic management. Cortisol deficiency, thyroid hormone excess, and parathyroid hormone deficiency do not produce this specific metabolic cluster.
- A newborn is noted on screening to have an elevated TSH with low T4. Without prompt treatment, this condition causes intellectual disability and growth failure. Which intervention prevents these outcomes?
- Methimazole therapy
- Early levothyroxine replacement
- Iodine restriction
- Growth hormone injections
Correct answer: Early levothyroxine replacement
Early levothyroxine replacement prevents the irreversible neurodevelopmental harm of congenital hypothyroidism. Thyroid hormone is essential for brain maturation and skeletal growth in infancy, so the high TSH and low T4 detected by newborn screening must be corrected promptly with thyroid hormone to ensure normal cognitive and physical development. Methimazole and iodine restriction treat hyperthyroidism, the opposite problem, and growth hormone does not address the thyroid hormone deficiency driving this condition.
- A 16-year-old boy has not yet entered puberty and has a height below the third percentile, but his growth velocity is normal and his bone age is delayed and matches his height age. His father reports being a late bloomer. Which is the most likely explanation?
- Precocious puberty
- Growth hormone deficiency
- Hypothyroidism
- Constitutional delay of growth and puberty
Correct answer: Constitutional delay of growth and puberty
Constitutional delay of growth and puberty is the most likely explanation. In this common, benign variant, the tempo of maturation is shifted later: growth velocity is normal, bone age is delayed and consistent with the child's height age, and there is often a family history of late puberty, so the child ultimately attains normal adult height and sexual maturation without treatment. Growth hormone deficiency and hypothyroidism slow growth velocity and require treatment, and precocious puberty is the opposite, accelerated maturation.
- A clinician reviews thyroid hormone action. Most circulating thyroid hormone is T4, but the more biologically active form is generated in peripheral tissues. Which statement about thyroid hormone activation is correct?
- Peripheral deiodinases convert T4 to the more active T3
- T3 is converted to the more active T4 in tissues
- T4 acts only after binding calcitonin
- Thyroid hormone has no nuclear receptor
Correct answer: Peripheral deiodinases convert T4 to the more active T3
Peripheral deiodinases converting T4 to the more active T3 is the correct statement. The thyroid secretes mostly T4, a relative prohormone, which peripheral tissues convert to the more potent T3 by removing an iodine atom via deiodinase enzymes; T3 then binds nuclear thyroid hormone receptors to regulate metabolism. The conversion runs from T4 to T3, not the reverse, thyroid hormone does not require calcitonin to act, and it works through nuclear receptors. This physiology underlies interpretation of thyroid function and drug effects.
- A 40-year-old woman with no symptoms is found on routine testing to have a mildly elevated TSH with a normal free T4. Repeat testing weeks later shows the same pattern. Which term best describes this thyroid state?
- Central hypothyroidism
- Overt hyperthyroidism
- Subclinical hypothyroidism
- Euthyroid sick syndrome
Correct answer: Subclinical hypothyroidism
Subclinical hypothyroidism best describes a mildly elevated TSH with a still-normal free T4. The rising TSH reflects early pituitary compensation for a slightly underactive thyroid before the free hormone falls below normal, and the patient is often asymptomatic. Overt hyperthyroidism would show a low TSH with high hormone, central hypothyroidism shows a low or inappropriately normal TSH with low T4 from a pituitary problem, and euthyroid sick syndrome occurs in acutely ill patients with altered testing. Recognizing this pattern guides monitoring decisions.
- A 70-year-old man with a urinary tract infection has a respiratory rate of 24, an altered mental status, and a systolic blood pressure of 95 mm Hg. The team uses a rapid bedside score that flags patients at higher risk of poor outcomes from sepsis using these three variables. Which screening tool is being applied?
- The quick Sequential Organ Failure Assessment (qSOFA)
- The Glasgow Coma Scale alone
- The CHA2DS2-VASc score
- The Wells score for pulmonary embolism
Correct answer: The quick Sequential Organ Failure Assessment (qSOFA)
The answer is the quick Sequential Organ Failure Assessment (qSOFA), which uses altered mentation, respiratory rate of at least 22, and systolic blood pressure of 100 mm Hg or less to identify patients with suspected infection at higher risk of deterioration. The Glasgow Coma Scale grades consciousness only, CHA2DS2-VASc estimates stroke risk in atrial fibrillation, and the Wells score stratifies pulmonary embolism probability.
- A patient with septic shock has a serum lactate of 5 mmol/L despite adequate blood pressure. Why does an elevated lactate signal tissue hypoperfusion even when the blood pressure appears acceptable?
- Lactate is produced only by the liver during rest
- Inadequate oxygen delivery forces cells toward anaerobic metabolism, generating lactate
- Lactate rises whenever the patient is given supplemental oxygen
- Lactate accumulates because the kidneys overexcrete bicarbonate
Correct answer: Inadequate oxygen delivery forces cells toward anaerobic metabolism, generating lactate
The answer is that inadequate oxygen delivery forces cells toward anaerobic metabolism, generating lactate. When perfusion at the microvascular level is insufficient, cells shift to anaerobic glycolysis and produce lactate even if macrovascular pressure looks adequate, making lactate a marker of occult hypoperfusion. It is not produced solely by the resting liver, raised by oxygen administration, or driven by renal bicarbonate loss.
- A patient with sepsis is started on empiric antibiotics. According to current sepsis management principles, what is the most important timing consideration for the first dose of appropriate antibiotics?
- Antibiotics should be delayed until all culture results return
- Antibiotics should be withheld until the lactate normalizes
- Appropriate broad-spectrum antibiotics should be given as early as possible, ideally within the first hour of recognition
- Antibiotics should be started only after a full week of observation
Correct answer: Appropriate broad-spectrum antibiotics should be given as early as possible, ideally within the first hour of recognition
The answer is that appropriate broad-spectrum antibiotics should be given as early as possible, ideally within the first hour of recognition of sepsis or septic shock, because delay increases mortality. Cultures should be drawn before antibiotics when feasible but must not delay treatment, and waiting for the lactate to normalize or for prolonged observation would dangerously postpone therapy.
- A patient is described as having sepsis-induced immunosuppression in the later phase of a prolonged septic illness. This paradoxical state, following the initial hyperinflammatory response, predisposes the patient to which complication?
- Spontaneous resolution requiring no further care
- Complete immunity to all future infections
- An allergic reaction to the patient's own tissues only
- Reactivation of latent viruses and secondary nosocomial infections
Correct answer: Reactivation of latent viruses and secondary nosocomial infections
The answer is reactivation of latent viruses and secondary nosocomial infections. After the early cytokine surge, many septic patients enter a compensatory immunosuppressed phase with lymphocyte apoptosis and impaired immune function, raising the risk of secondary and opportunistic infections. This state does not confer immunity, resolve on its own, or represent an autoimmune phenomenon.
- A clinician explains the difference between sepsis and septic shock to a trainee. According to current definitions, septic shock is distinguished from sepsis by which combination of findings?
- Persistent hypotension requiring vasopressors to maintain mean arterial pressure of 65 mm Hg plus a lactate above 2 mmol/L despite adequate fluids
- Any fever above 38 degrees Celsius
- An isolated elevated white blood cell count
- A single episode of tachycardia
Correct answer: Persistent hypotension requiring vasopressors to maintain mean arterial pressure of 65 mm Hg plus a lactate above 2 mmol/L despite adequate fluids
The answer is persistent hypotension requiring vasopressors to maintain a mean arterial pressure of at least 65 mm Hg plus a lactate above 2 mmol/L despite adequate fluid resuscitation, the criteria that define septic shock as a subset of sepsis with profound circulatory and metabolic derangement. Fever, leukocytosis, or transient tachycardia alone do not constitute septic shock.
- A child stung by a wasp develops hives, throat tightness, and wheezing within minutes. After intramuscular epinephrine, the family asks why epinephrine is preferred over an antihistamine for this reaction. Which property of epinephrine makes it first-line in anaphylaxis?
- It selectively blocks histamine receptors only
- It acts on adrenergic receptors to reverse airway swelling, bronchospasm, and vasodilation simultaneously
- It works exclusively to relieve itching
- It prevents the formation of IgE antibodies
Correct answer: It acts on adrenergic receptors to reverse airway swelling, bronchospasm, and vasodilation simultaneously
The answer is that it acts on adrenergic receptors to reverse airway swelling, bronchospasm, and vasodilation simultaneously. Epinephrine's alpha effects constrict vessels and reduce mucosal edema while its beta effects bronchodilate and support cardiac output, addressing the life-threatening features of anaphylaxis that antihistamines cannot. It is not a selective histamine blocker, an itch-only remedy, or an inhibitor of IgE production.
- A patient who develops anaphylaxis has a serum sample drawn shortly after the reaction. Elevation of which mediator, released from mast cells, can help confirm that an anaphylactic reaction occurred?
- Troponin
- Amylase
- Tryptase
- Creatine kinase
Correct answer: Tryptase
The answer is tryptase, a protease stored in and released from mast cells during degranulation; a transient rise supports the diagnosis of anaphylaxis when measured within hours of the event. Troponin marks myocardial injury, amylase reflects pancreatic or salivary disease, and creatine kinase indicates muscle damage, none of which are specific markers of mast cell activation.
- A patient on a beta-blocker develops anaphylaxis that responds poorly to repeated epinephrine. Which additional agent is recommended to overcome the blunted response to epinephrine in patients taking beta-blockers?
- Digoxin
- Adenosine
- Furosemide
- Glucagon
Correct answer: Glucagon
The answer is glucagon, which raises intracellular cyclic AMP through a receptor independent of beta-adrenergic receptors, restoring inotropy and vascular tone when beta-blockade limits the response to epinephrine. Digoxin, adenosine, and furosemide do not bypass beta-blockade to treat refractory anaphylaxis.
- A patient develops the cardinal features of anaphylaxis. Which set of mediators released by mast cells and basophils is chiefly responsible for the vasodilation, increased vascular permeability, and bronchoconstriction seen in this reaction?
- Histamine, leukotrienes, and prostaglandins
- Insulin and glucagon
- Thyroxine and cortisol
- Erythropoietin and thrombopoietin
Correct answer: Histamine, leukotrienes, and prostaglandins
The answer is histamine, leukotrienes, and prostaglandins. Cross-linking of mast cell IgE releases preformed histamine and newly synthesized leukotrienes and prostaglandins, which dilate vessels, increase permeability with edema, and constrict bronchial smooth muscle, producing the anaphylactic syndrome. The endocrine and hematopoietic hormones listed are not the effector mediators of anaphylaxis.
- A patient with sarcoidosis develops hypercalcemia. What is the mechanism by which sarcoid granulomas raise the serum calcium?
- Tumor secretion of parathyroid hormone-related peptide
- Activated macrophages in granulomas produce 1-alpha-hydroxylase, increasing active vitamin D
- Excess dietary calcium absorption from medications
- Destruction of bone by direct granuloma invasion of the skeleton
Correct answer: Activated macrophages in granulomas produce 1-alpha-hydroxylase, increasing active vitamin D
The answer is that activated macrophages in granulomas produce 1-alpha-hydroxylase, increasing conversion of vitamin D to its active form, which boosts intestinal calcium absorption and raises serum calcium in sarcoidosis. It is not from parathyroid hormone-related peptide, dietary excess, or direct skeletal invasion by granulomas.
- A young adult with sarcoidosis presents with painful red nodules on the shins, ankle arthritis, fever, and bilateral hilar lymphadenopathy. This acute, often self-limited presentation of sarcoidosis carrying a good prognosis is known as which of the following?
- Caplan syndrome
- Goodpasture syndrome
- Lofgren syndrome
- Meigs syndrome
Correct answer: Lofgren syndrome
The answer is Lofgren syndrome, the combination of erythema nodosum, hilar lymphadenopathy, migratory polyarthralgia, and fever, an acute form of sarcoidosis that frequently resolves spontaneously with a favorable prognosis. Caplan syndrome links pneumoconiosis with rheumatoid nodules, Goodpasture syndrome is anti-glomerular basement membrane disease, and Meigs syndrome involves an ovarian fibroma with ascites and effusion.
- A pathologist examines a lymph node from a patient with sarcoidosis. Which histologic finding is the hallmark of this disease?
- Caseating granulomas with central necrosis
- Reed-Sternberg cells
- Sheets of neutrophils forming an abscess
- Noncaseating (non-necrotizing) granulomas
Correct answer: Noncaseating (non-necrotizing) granulomas
The answer is noncaseating (non-necrotizing) granulomas, collections of epithelioid macrophages and giant cells without central caseous necrosis, which characterize sarcoidosis. Caseating granulomas suggest tuberculosis, Reed-Sternberg cells indicate Hodgkin lymphoma, and neutrophilic abscesses indicate pyogenic infection.
- A patient with sarcoidosis has progressive symptomatic disease, and the physician initiates first-line systemic therapy. Which class of medication is the mainstay of treatment for symptomatic sarcoidosis?
- Systemic corticosteroids
- Long-term broad-spectrum antibiotics
- Anticoagulants
- Antifungal agents
Correct answer: Systemic corticosteroids
The answer is systemic corticosteroids, the first-line therapy for symptomatic or organ-threatening sarcoidosis because they suppress the granulomatous inflammation driving organ damage. Antibiotics, anticoagulants, and antifungals do not target the immune-mediated granuloma formation of sarcoidosis.
- A patient with primary (AL) amyloidosis is being worked up. The misfolded precursor protein in AL amyloidosis is produced by which cell type?
- Hepatocytes producing transthyretin
- A clonal population of plasma cells producing immunoglobulin light chains
- Macrophages producing serum amyloid A
- Endothelial cells producing beta-2 microglobulin
Correct answer: A clonal population of plasma cells producing immunoglobulin light chains
The answer is a clonal population of plasma cells producing immunoglobulin light chains. In AL amyloidosis, a plasma cell dyscrasia overproduces monoclonal light chains that misfold into amyloid fibrils depositing in multiple organs. Hepatic transthyretin underlies ATTR amyloid, macrophage-derived serum amyloid A underlies AA amyloid, and beta-2 microglobulin underlies dialysis-related amyloid.
- A patient with a chronic inflammatory condition such as long-standing rheumatoid arthritis develops secondary amyloidosis. Which precursor protein deposits as amyloid in this setting?
- Immunoglobulin light chains
- Beta-amyloid precursor protein
- Serum amyloid A, an acute-phase reactant
- Calcitonin
Correct answer: Serum amyloid A, an acute-phase reactant
The answer is serum amyloid A, an acute-phase reactant produced by the liver during chronic inflammation; sustained elevation leads to AA (secondary) amyloidosis, classically with renal involvement, in diseases such as rheumatoid arthritis and chronic infections. Light chains cause AL amyloid, beta-amyloid precursor relates to Alzheimer disease, and calcitonin-derived amyloid occurs in medullary thyroid carcinoma.
- A pathologist applies a special stain to confirm amyloid deposits in a biopsy. Which finding is diagnostic of amyloid under polarized light?
- Bright blue color after Prussian blue staining
- Black granules after a silver stain
- Red fibers after a trichrome stain
- Apple-green birefringence after Congo red staining
Correct answer: Apple-green birefringence after Congo red staining
The answer is apple-green birefringence after Congo red staining, the classic confirmatory test for amyloid deposits viewed under polarized light. Prussian blue detects iron, silver stains highlight reticulin or organisms, and trichrome stains collagen, none of which is specific for amyloid.
- A patient with cardiac amyloidosis is being evaluated for the characteristic pattern of cardiac dysfunction. Amyloid infiltration of the myocardium most typically produces which type of cardiomyopathy?
- Restrictive cardiomyopathy with a stiff, poorly compliant ventricle
- Dilated cardiomyopathy with a thin, ballooned ventricle
- Hypertrophic obstructive cardiomyopathy from sarcomere mutation
- A purely electrical disorder with normal structure
Correct answer: Restrictive cardiomyopathy with a stiff, poorly compliant ventricle
The answer is restrictive cardiomyopathy with a stiff, poorly compliant ventricle. Amyloid deposits infiltrate the myocardium, increasing wall thickness while impairing relaxation and filling, producing a restrictive pattern with diastolic dysfunction and often low voltage on the electrocardiogram despite thick walls. It is not a dilated or sarcomeric hypertrophic process, nor a purely electrical abnormality.
- A patient in septic (distributive) shock has warm extremities early in the course. Which hemodynamic profile best characterizes early distributive shock?
- High systemic vascular resistance with low cardiac output
- Low systemic vascular resistance with high or normal cardiac output
- High filling pressures with pulmonary congestion
- Markedly reduced cardiac output from pump failure
Correct answer: Low systemic vascular resistance with high or normal cardiac output
The answer is low systemic vascular resistance with high or normal cardiac output. In early distributive shock such as sepsis, widespread vasodilation drops vascular resistance, and the heart compensates with a high output, producing warm skin and bounding pulses. Cardiogenic shock shows low output with high filling pressures, and hypovolemic shock raises resistance to compensate for low preload.
- A patient with an anterior wall myocardial infarction develops hypotension, pulmonary edema, and cold clammy skin. Which category of shock does this represent, and what is its underlying mechanism?
- Distributive shock from vasodilation
- Hypovolemic shock from volume loss
- Cardiogenic shock from failure of the heart as a pump
- Obstructive shock from a pulmonary embolus
Correct answer: Cardiogenic shock from failure of the heart as a pump
The answer is cardiogenic shock from failure of the heart as a pump. A large infarction reduces myocardial contractility, lowering cardiac output despite adequate volume, causing hypotension, backward congestion with pulmonary edema, and poor peripheral perfusion. Distributive shock involves vasodilation, hypovolemic shock follows volume loss, and obstructive shock results from mechanical impedance such as a pulmonary embolus.
- A patient develops massive bilateral pulmonary emboli with acute right heart strain and hypotension. The shock in this scenario is classified as which type?
- Hypovolemic shock
- Distributive shock
- Neurogenic shock
- Obstructive shock
Correct answer: Obstructive shock
The answer is obstructive shock. A large pulmonary embolus mechanically obstructs right ventricular outflow, impeding blood flow through the heart and lungs and reducing left-sided filling and cardiac output. This mechanical impedance to flow, also seen in tamponade and tension pneumothorax, defines obstructive shock, distinct from volume loss, vasodilation, or sympathetic failure.
- A patient in early hypovolemic shock has a narrowed pulse pressure. Why does the pulse pressure narrow before the systolic pressure falls substantially in hemorrhage?
- Compensatory vasoconstriction raises the diastolic pressure relative to the systolic, narrowing the gap
- The systolic pressure rises sharply while diastolic falls
- Both systolic and diastolic rise equally
- The heart rate falls, widening the pulse pressure
Correct answer: Compensatory vasoconstriction raises the diastolic pressure relative to the systolic, narrowing the gap
The answer is that compensatory vasoconstriction raises the diastolic pressure relative to the systolic, narrowing the gap. Catecholamine-driven peripheral vasoconstriction in early hemorrhage elevates diastolic pressure while stroke volume falls, narrowing the pulse pressure before frank hypotension appears. Systolic pressure does not rise, both do not increase together, and the heart rate rises rather than falls.
- A patient with high cervical spinal cord trauma develops hypotension with a paradoxically slow heart rate and warm, dry skin below the level of injury. This presentation is best explained by which type of shock?
- Hypovolemic shock from blood loss
- Neurogenic shock from loss of sympathetic outflow
- Cardiogenic shock from myocardial infarction
- Anaphylactic shock from an allergen
Correct answer: Neurogenic shock from loss of sympathetic outflow
The answer is neurogenic shock from loss of sympathetic outflow. A high spinal cord injury interrupts sympathetic tone, causing vasodilation with hypotension and, because unopposed vagal tone slows the heart, bradycardia rather than the tachycardia of other shock states, along with warm dry skin below the lesion. Hypovolemic and cardiogenic shock cause tachycardia and cool skin, and anaphylaxis follows allergen exposure.
- A patient with severe sepsis is found to have decreased responsiveness to catecholamines. Which mechanism best explains the relative resistance to vasopressors that can develop in advanced septic shock?
- Excess thyroid hormone production
- A surge in circulating insulin
- Nitric oxide overproduction and receptor downregulation causing vascular hyporesponsiveness
- Increased red cell mass
Correct answer: Nitric oxide overproduction and receptor downregulation causing vascular hyporesponsiveness
The answer is nitric oxide overproduction and receptor downregulation causing vascular hyporesponsiveness. Inducible nitric oxide synthase generates large amounts of nitric oxide, and adrenergic receptors become downregulated, blunting the vasoconstrictor response to catecholamines in severe sepsis. Thyroid hormone, insulin surges, and red cell mass do not account for vasopressor resistance.
- A clinician describes the progression from systemic inflammatory response to organ failure in a critically ill patient. The cytokine storm that drives early sepsis is initiated largely by activation of which receptors on innate immune cells?
- Insulin receptors on hepatocytes
- Beta-adrenergic receptors on the heart
- Estrogen receptors in the uterus
- Pattern-recognition receptors such as Toll-like receptors detecting microbial molecules
Correct answer: Pattern-recognition receptors such as Toll-like receptors detecting microbial molecules
The answer is pattern-recognition receptors such as Toll-like receptors detecting microbial molecules. These receptors recognize conserved pathogen-associated molecular patterns like lipopolysaccharide, triggering the cytokine release that drives the systemic inflammatory response in sepsis. Insulin, adrenergic, and estrogen receptors do not initiate the innate immune cytokine cascade of sepsis.
- A patient is being counseled on long-term outcomes after surviving a severe episode of sepsis. Survivors of severe sepsis are at increased risk of which long-term consequence affecting multiple systems?
- Long-term cognitive impairment, physical disability, and increased mortality (post-sepsis syndrome)
- Complete reversal of all prior chronic illnesses
- Lifelong immunity to all infections
- Permanent resolution of any baseline organ disease
Correct answer: Long-term cognitive impairment, physical disability, and increased mortality (post-sepsis syndrome)
The answer is long-term cognitive impairment, physical disability, and increased mortality, collectively termed post-sepsis syndrome. Many survivors experience persistent neurocognitive deficits, weakness, and a heightened risk of death and readmission long after the acute illness. Sepsis does not cure prior diseases or confer lasting immunity.
- A patient with a peanut allergy is prescribed an epinephrine autoinjector. Which counseling point best reflects appropriate use after a self-injection for a suspected anaphylactic reaction?
- Avoid seeking medical care if symptoms improve briefly
- Call emergency services and go to the hospital even if symptoms improve, because of the risk of a biphasic reaction
- Wait several hours before using the autoinjector to confirm anaphylaxis
- Use the autoinjector only after oral antihistamines have failed for an hour
Correct answer: Call emergency services and go to the hospital even if symptoms improve, because of the risk of a biphasic reaction
The answer is to call emergency services and go to the hospital even if symptoms improve, because of the risk of a biphasic reaction. Early epinephrine is critical, and observation is needed because symptoms can recur hours later. Delaying epinephrine to try antihistamines first or to confirm the diagnosis is dangerous and may be fatal.
- A patient with neurosarcoidosis is being evaluated. Among the cranial nerves, which is most commonly affected in sarcoidosis, producing facial weakness?
- The trochlear nerve (cranial nerve IV)
- The hypoglossal nerve (cranial nerve XII)
- The facial nerve (cranial nerve VII)
- The accessory nerve (cranial nerve XI)
Correct answer: The facial nerve (cranial nerve VII)
The answer is the facial nerve (cranial nerve VII), the most commonly involved cranial nerve in neurosarcoidosis, often causing facial palsy that may be bilateral. The trochlear, hypoglossal, and accessory nerves are far less frequently affected by sarcoid granulomatous infiltration.
- A patient with biopsy-proven amyloidosis develops orthostatic hypotension, early satiety, and erectile dysfunction. Which mechanism best explains these multisystem autonomic symptoms?
- Direct destruction of the spinal cord by amyloid
- An allergic reaction to amyloid fibrils
- Excess catecholamine secretion from amyloid deposits
- Amyloid deposition in autonomic nerves causing an autonomic neuropathy
Correct answer: Amyloid deposition in autonomic nerves causing an autonomic neuropathy
The answer is amyloid deposition in autonomic nerves causing an autonomic neuropathy. Amyloid infiltration of peripheral and autonomic nerves leads to orthostatic hypotension, gastrointestinal dysmotility, and genitourinary dysfunction across systems. It is not from spinal cord destruction, an allergic reaction, or excess catecholamine secretion.
- A patient is in compensated (early) shock. Which feature best distinguishes compensated shock from decompensated shock?
- Blood pressure is maintained near normal by compensatory mechanisms in the compensated phase
- Blood pressure has already collapsed in the compensated phase
- There is no tachycardia in the compensated phase
- Compensated shock always shows a normal lactate and no organ dysfunction permanently
Correct answer: Blood pressure is maintained near normal by compensatory mechanisms in the compensated phase
The answer is that blood pressure is maintained near normal by compensatory mechanisms in the compensated phase. Tachycardia and vasoconstriction preserve perfusion and pressure early, so recognizing compensated shock before pressure falls is key; in the decompensated phase these mechanisms fail and hypotension ensues. Compensated shock still shows tachycardia and can already involve rising lactate and early organ stress.
- A 24-year-old develops fever, hypotension, a diffuse erythematous rash, vomiting, and confusion days after a deep wound. Which superantigen-driven illness should be suspected, and what is the responsible organism class?
- Viral influenza pneumonia
- Staphylococcal or streptococcal toxic shock syndrome
- A fungal nail infection
- A protozoal gut infection
Correct answer: Staphylococcal or streptococcal toxic shock syndrome
The answer is staphylococcal or streptococcal toxic shock syndrome. Superantigens from Staphylococcus aureus or group A Streptococcus activate large numbers of T cells, producing a cytokine surge with fever, hypotension, rash, and multi-organ dysfunction. Influenza, a fungal nail infection, and a protozoal gut infection do not cause this superantigen-mediated multisystem shock.
- A patient who survived cardiac arrest is being managed in the intensive care unit. Targeted temperature management is used to improve neurologic outcomes by which mechanism?
- Raising the body temperature to accelerate metabolism
- Inducing fever to fight infection
- Lowering cerebral metabolic demand and reducing reperfusion injury after global ischemia
- Eliminating the need for any other supportive care
Correct answer: Lowering cerebral metabolic demand and reducing reperfusion injury after global ischemia
The answer is lowering cerebral metabolic demand and reducing reperfusion injury after global ischemia. Controlled cooling decreases the brain's oxygen requirements and blunts the inflammatory and excitotoxic cascade following the whole-body ischemia of cardiac arrest, supporting neurologic recovery. It does not raise temperature, induce fever, or replace other intensive supportive measures.
- A patient whose ischemic limb is revascularized after prolonged occlusion suddenly develops hyperkalemia, acidosis, and worsening organ function. This deterioration after restoring blood flow is best explained by which phenomenon?
- An immediate allergic reaction to oxygen
- Simple rehydration of the tissue
- Resolution of all tissue damage
- Ischemia-reperfusion injury releasing accumulated metabolites and generating reactive oxygen species
Correct answer: Ischemia-reperfusion injury releasing accumulated metabolites and generating reactive oxygen species
The answer is ischemia-reperfusion injury releasing accumulated metabolites and generating reactive oxygen species. When flow is restored, washout of potassium and acid plus a burst of reactive oxygen species and inflammation can paradoxically worsen local and systemic injury. It is not an oxygen allergy, simple rehydration, or full resolution of damage.
- A patient is found unresponsive with a metabolic acidosis, a normal pulse oximetry reading, and a history of exposure to combustion in an enclosed space. A bitter almond odor is noted. Which agent inhibits the mitochondrial electron transport chain, and what is its antidote category?
- Cyanide, treated with hydroxocobalamin or a nitrite plus thiosulfate regimen
- Carbon monoxide, treated with deferoxamine
- Iron, treated with naloxone
- Opioid, treated with flumazenil
Correct answer: Cyanide, treated with hydroxocobalamin or a nitrite plus thiosulfate regimen
The answer is cyanide, treated with hydroxocobalamin or a nitrite plus thiosulfate regimen. Cyanide binds cytochrome c oxidase, halting oxidative phosphorylation and forcing anaerobic metabolism with severe lactic acidosis despite adequate oxygen content. Carbon monoxide is not treated with deferoxamine, iron toxicity is not treated with naloxone, and flumazenil reverses benzodiazepines, not opioids.
- A patient with chronic acetaminophen overdose develops hepatic injury. Which antidote replenishes glutathione to detoxify the reactive metabolite responsible for liver damage?
- Atropine
- N-acetylcysteine
- Protamine sulfate
- Vitamin K
Correct answer: N-acetylcysteine
The answer is N-acetylcysteine, which replenishes hepatic glutathione and detoxifies the reactive metabolite N-acetyl-p-benzoquinone imine that accumulates and injures hepatocytes in acetaminophen toxicity. Atropine treats cholinergic crisis, protamine reverses heparin, and vitamin K reverses warfarin, none of which address acetaminophen-induced liver injury.
- A patient develops a high fever, agitation, diaphoresis, tremor, hyperreflexia, and clonus after a second serotonergic medication is added. This multisystem drug-induced syndrome is best described as which of the following?
- Malignant hyperthermia
- Neuroleptic malignant syndrome
- Serotonin syndrome
- Anticholinergic toxidrome
Correct answer: Serotonin syndrome
The answer is serotonin syndrome, a hyperserotonergic state from combining serotonergic drugs, characterized by autonomic instability, neuromuscular hyperactivity with clonus and hyperreflexia, and altered mental status. Malignant hyperthermia follows anesthetics, neuroleptic malignant syndrome involves dopamine blockade with rigidity and hyporeflexia, and the anticholinergic toxidrome lacks clonus and hyperreflexia.
- A patient with metastatic cancer and a high tumor burden begins chemotherapy and then develops hyperkalemia, hyperphosphatemia, hyperuricemia, and hypocalcemia with acute kidney injury. This constellation defines which oncologic emergency?
- Superior vena cava syndrome
- Spinal cord compression
- Hypercalcemia of malignancy
- Tumor lysis syndrome
Correct answer: Tumor lysis syndrome
The answer is tumor lysis syndrome, caused by rapid release of intracellular contents from dying tumor cells, producing high potassium, phosphate, and uric acid with low calcium and acute kidney injury from urate and phosphate precipitation. Superior vena cava syndrome, cord compression, and isolated hypercalcemia have distinct mechanisms and laboratory patterns.
- A patient presents with high fever, hypotension, and a maculopapular rash that began on the wrists and ankles and spread centrally, following a tick bite. Which systemic infection should be suspected?
- Rocky Mountain spotted fever caused by Rickettsia rickettsii
- Lyme disease only
- Influenza
- Streptococcal pharyngitis
Correct answer: Rocky Mountain spotted fever caused by Rickettsia rickettsii
The answer is Rocky Mountain spotted fever caused by Rickettsia rickettsii, which classically produces a rash starting on the wrists and ankles that spreads centrally, with fever and potential multi-organ involvement, and requires prompt doxycycline. Lyme disease causes erythema migrans, while influenza and streptococcal pharyngitis do not produce this centripetal petechial rash after a tick bite.
- A patient with chronic kidney disease develops renal osteodystrophy and vascular calcifications. Which set of derangements drives the bone and mineral complications across systems in advanced kidney disease?
- Hypophosphatemia with high active vitamin D
- Hyperphosphatemia, low active vitamin D, hypocalcemia, and secondary hyperparathyroidism
- Isolated hypernatremia
- Pure respiratory alkalosis
Correct answer: Hyperphosphatemia, low active vitamin D, hypocalcemia, and secondary hyperparathyroidism
The answer is hyperphosphatemia, low active vitamin D, hypocalcemia, and secondary hyperparathyroidism. Failing kidneys retain phosphate and cannot activate vitamin D, lowering calcium and driving parathyroid hormone up, which weakens bone and promotes vascular calcification. This is not caused by hypophosphatemia with high vitamin D, isolated hypernatremia, or respiratory alkalosis.
- A patient with severe vomiting for days develops a metabolic alkalosis. Which combination of losses best explains the alkalosis and accompanying electrolyte changes?
- Loss of bicarbonate-rich intestinal fluid
- Retention of fixed acids from renal failure
- Loss of gastric hydrogen ion and chloride with volume depletion driving bicarbonate retention
- Hyperventilation lowering carbon dioxide
Correct answer: Loss of gastric hydrogen ion and chloride with volume depletion driving bicarbonate retention
The answer is loss of gastric hydrogen ion and chloride with volume depletion driving bicarbonate retention. Vomiting removes acid and chloride, and the resulting volume contraction prompts the kidney to retain bicarbonate, producing a hypochloremic, hypokalemic metabolic alkalosis. Intestinal bicarbonate loss and renal acid retention cause acidosis, and hyperventilation causes respiratory rather than metabolic alkalosis.
- A patient with sepsis is found to have a high anion gap. Which calculation correctly defines the anion gap used to evaluate metabolic acidosis?
- Sodium plus potassium minus calcium
- Chloride minus bicarbonate only
- The sum of all measured cations and anions
- Sodium minus the sum of chloride and bicarbonate
Correct answer: Sodium minus the sum of chloride and bicarbonate
The answer is sodium minus the sum of chloride and bicarbonate, which estimates unmeasured anions; an elevated gap suggests added acids such as lactate, ketoacids, or toxins. The other expressions do not represent the standard anion gap formula used at the bedside.
- A patient with widely metastatic cancer develops cachexia with progressive weight loss and muscle wasting despite some food intake. Which mechanism best explains this multisystem wasting syndrome?
- Tumor- and host-derived cytokines such as tumor necrosis factor drive catabolism and anorexia
- Excess insulin secretion causing fat storage
- Simple voluntary dieting by the patient
- Overhydration causing apparent weight loss
Correct answer: Tumor- and host-derived cytokines such as tumor necrosis factor drive catabolism and anorexia
The answer is that tumor- and host-derived cytokines such as tumor necrosis factor drive catabolism and anorexia. Cancer cachexia is a systemic metabolic syndrome in which inflammatory mediators increase protein and fat breakdown and suppress appetite, producing wasting beyond what reduced intake alone explains. It is not from excess insulin, voluntary dieting, or overhydration.
- A patient is found to have a paraneoplastic cerebellar degeneration with ataxia in association with an underlying gynecologic cancer. Which mechanism best explains this paraneoplastic neurologic syndrome?
- Direct invasion of the cerebellum by the tumor
- Antibodies generated against tumor antigens cross-react with neuronal antigens
- A vitamin overdose
- An infection of the cerebellum by the tumor cells
Correct answer: Antibodies generated against tumor antigens cross-react with neuronal antigens
The answer is that antibodies generated against tumor antigens cross-react with neuronal antigens. In paraneoplastic cerebellar degeneration, an immune response to the tumor produces autoantibodies that attack Purkinje cells, causing ataxia remote from any tumor invasion. It is not direct invasion, a vitamin overdose, or a cerebellar infection.
- A patient receiving a multidrug regimen develops a widespread rash, fever, eosinophilia, and hepatitis two to six weeks after starting an anticonvulsant. This severe systemic drug reaction is best described as which of the following?
- Simple contact dermatitis
- Acute urticaria
- Drug reaction with eosinophilia and systemic symptoms (DRESS)
- Localized fixed drug eruption
Correct answer: Drug reaction with eosinophilia and systemic symptoms (DRESS)
The answer is drug reaction with eosinophilia and systemic symptoms (DRESS), a delayed, severe hypersensitivity reaction with rash, fever, eosinophilia, lymphadenopathy, and internal organ involvement such as hepatitis, often weeks after starting drugs like anticonvulsants. Contact dermatitis, urticaria, and a fixed drug eruption are localized or far less severe without this multi-organ syndrome.
- A patient with established sepsis is being assessed for organ dysfunction using a validated scoring system that grades function of the respiratory, coagulation, hepatic, cardiovascular, neurologic, and renal systems. Which score is used to quantify organ dysfunction in sepsis?
- The Bishop score
- The Apgar score
- The Ranson criteria
- The Sequential Organ Failure Assessment (SOFA) score
Correct answer: The Sequential Organ Failure Assessment (SOFA) score
The answer is the Sequential Organ Failure Assessment (SOFA) score, which grades dysfunction across six organ systems and is central to the current sepsis definition. The Bishop score assesses cervical readiness for labor, the Apgar score evaluates newborns, and the Ranson criteria predict pancreatitis severity.
- A patient develops fever, leukocytosis, and chills, and the team explains the febrile response. Which prostaglandin, produced in the hypothalamus in response to pyrogenic cytokines, directly raises the thermoregulatory set point?
- Prostaglandin E2
- Thromboxane A2
- Prostacyclin (prostaglandin I2)
- Leukotriene B4
Correct answer: Prostaglandin E2
The answer is prostaglandin E2. Pyrogenic cytokines such as interleukin-1 and interleukin-6 stimulate hypothalamic production of prostaglandin E2, which raises the thermoregulatory set point and produces fever; antipyretics work by inhibiting this prostaglandin synthesis. Thromboxane A2, prostacyclin, and leukotriene B4 do not set the febrile set point.
- A patient with shock is being categorized by cardiac output and vascular resistance. A patient with high cardiac output and low systemic vascular resistance most likely has which type of shock?
- Cardiogenic shock
- Distributive shock
- Hypovolemic shock
- Obstructive shock
Correct answer: Distributive shock
The answer is distributive shock. The combination of a high cardiac output with low systemic vascular resistance is the hallmark of distributive shock such as sepsis, anaphylaxis, or neurogenic shock, where pathologic vasodilation lowers resistance. Cardiogenic, hypovolemic, and obstructive shock instead show low output with elevated or high-normal vascular resistance.
- A patient with anaphylaxis is positioned by the care team while epinephrine takes effect. Which positioning is recommended for a hypotensive patient in anaphylaxis, and why?
- Standing upright at all times
- Strict prone positioning regardless of symptoms
- Supine with legs elevated to improve venous return, unless there is respiratory distress
- Sitting with legs dependent to lower blood pressure
Correct answer: Supine with legs elevated to improve venous return, unless there is respiratory distress
The answer is supine with legs elevated to improve venous return, unless there is respiratory distress, in which case the patient may sit up. Abruptly placing or keeping an anaphylactic patient upright can precipitate fatal hypotension by reducing venous return, so the supine position with leg elevation supports preload. Standing, prone positioning, or sitting to lower pressure are not appropriate.
- A patient develops widespread petechiae and oozing in the setting of acute promyelocytic leukemia, with prolonged clotting times and low fibrinogen. What is the most likely mechanism linking this leukemia to a consumptive coagulopathy?
- An inherited deficiency of factor VIII
- Dietary vitamin K deficiency
- A platelet storage pool defect
- Release of procoagulant granules from leukemic promyelocytes triggering disseminated intravascular coagulation
Correct answer: Release of procoagulant granules from leukemic promyelocytes triggering disseminated intravascular coagulation
The answer is release of procoagulant granules from leukemic promyelocytes triggering disseminated intravascular coagulation. The granules of acute promyelocytic leukemia activate the clotting cascade, consuming platelets and fibrinogen and producing a life-threatening systemic coagulopathy at presentation. This is not hemophilia A, dietary vitamin K deficiency, or a platelet storage pool defect.
- A patient is described as having an acute-phase response during a systemic illness. Which liver-derived protein characteristically falls during the acute-phase response, making it a negative acute-phase reactant?
- Albumin
- C-reactive protein
- Ferritin
- Fibrinogen
Correct answer: Albumin
The answer is albumin, a negative acute-phase reactant whose hepatic synthesis decreases during systemic inflammation as the liver prioritizes positive reactants. C-reactive protein, ferritin, and fibrinogen are positive acute-phase reactants that rise with inflammation, the opposite pattern from albumin.
- A patient with a multisystem inflammatory illness has a markedly elevated erythrocyte sedimentation rate and C-reactive protein. Which statement best describes the meaning of these tests?
- They are specific tests that identify the exact infecting organism
- They are nonspecific markers of inflammation that indicate its presence but not its cause
- They decrease with active inflammation
- They measure the oxygen-carrying capacity of blood
Correct answer: They are nonspecific markers of inflammation that indicate its presence but not its cause
The answer is that they are nonspecific markers of inflammation that indicate its presence but not its cause. The erythrocyte sedimentation rate and C-reactive protein rise with systemic inflammation from many causes, helping gauge and monitor activity but not pinpoint an etiology. They do not identify organisms, fall with active inflammation, or measure oxygen-carrying capacity.
- A patient develops an electrocardiogram showing tall peaked T waves, a widened QRS, and loss of P waves. Which life-threatening electrolyte derangement, common in renal failure and tumor lysis, do these progressive changes reflect?
- Hypokalemia
- Hypercalcemia
- Hyperkalemia
- Hypomagnesemia alone
Correct answer: Hyperkalemia
The answer is hyperkalemia. Rising potassium produces a sequence of peaked T waves, then PR prolongation and loss of P waves, then QRS widening that can progress to a sine wave and cardiac arrest, a multisystem emergency seen in renal failure and tumor lysis. Hypokalemia, hypercalcemia, and isolated hypomagnesemia produce different electrocardiographic patterns.
- A patient with a large burn is being resuscitated with intravenous fluids using a weight- and burn-size-based formula in the first 24 hours. The rationale for aggressive early fluid resuscitation in major burns is which of the following?
- Burns cause fluid overload requiring restriction
- Burns have no effect on fluid balance
- Fluids are given only to treat infection
- Massive capillary leak and fluid shifts cause hypovolemia and risk of shock
Correct answer: Massive capillary leak and fluid shifts cause hypovolemia and risk of shock
The answer is that massive capillary leak and fluid shifts cause hypovolemia and risk of shock. Major burns trigger systemic inflammation with increased capillary permeability, shifting plasma into tissues and producing hypovolemic shock unless large volumes are replaced early using a calculated formula. Burns cause depletion, not overload, and fluids address hemodynamics, not only infection.
- A patient with sepsis develops acute kidney injury during the illness. Which mechanism most directly links sepsis to acute kidney injury?
- Hypoperfusion, inflammation, and microvascular dysfunction reducing renal oxygen delivery
- Excess renal blood flow flooding the glomeruli
- A sudden rise in plasma albumin
- Direct mechanical obstruction of both ureters by bacteria
Correct answer: Hypoperfusion, inflammation, and microvascular dysfunction reducing renal oxygen delivery
The answer is hypoperfusion, inflammation, and microvascular dysfunction reducing renal oxygen delivery. Septic acute kidney injury arises from a combination of impaired perfusion, inflammatory injury, and microcirculatory derangement rather than excess flow, a rise in albumin, or bilateral mechanical ureteral obstruction.
- A patient with metastatic cancer is found to have both bone metastases and an elevated parathyroid hormone-related peptide. Which statement best explains why hypercalcemia of malignancy is considered a multisystem disorder?
- It affects only the bones with no systemic effects
- Elevated calcium affects the kidneys, gastrointestinal tract, nervous system, and heart simultaneously
- It is confined to the parathyroid gland
- It produces effects only in the skin
Correct answer: Elevated calcium affects the kidneys, gastrointestinal tract, nervous system, and heart simultaneously
The answer is that elevated calcium affects the kidneys, gastrointestinal tract, nervous system, and heart simultaneously. Hypercalcemia causes polyuria and stones, constipation and nausea, confusion and weakness, and cardiac conduction changes, illustrating its multisystem impact. It is not confined to bone, the parathyroid gland, or the skin.
- A patient with advanced liver disease develops worsening kidney function with a very low urine sodium and no structural kidney damage, unresponsive to volume. This functional renal failure secondary to severe liver disease is best described as which of the following?
- Acute tubular necrosis
- Cardiorenal syndrome
- Hepatorenal syndrome
- Postrenal obstruction
Correct answer: Hepatorenal syndrome
The answer is hepatorenal syndrome, a functional kidney failure in advanced liver disease driven by splanchnic vasodilation and intense renal vasoconstriction, with avid sodium retention (low urine sodium) and intact kidney structure unresponsive to fluids. Acute tubular necrosis shows structural injury, cardiorenal syndrome stems from heart failure, and postrenal failure is obstructive.
- A patient develops disseminated intravascular coagulation. Which laboratory marker reflects the simultaneous fibrinolysis that accompanies the widespread clotting in this disorder?
- Elevated hemoglobin
- Elevated albumin
- Elevated bicarbonate
- Elevated D-dimer
Correct answer: Elevated D-dimer
The answer is elevated D-dimer, a fibrin degradation product that rises as plasmin breaks down the fibrin formed during the widespread clotting of disseminated intravascular coagulation. Hemoglobin typically falls with microangiopathic hemolysis, and albumin and bicarbonate are not specific markers of the fibrinolysis in this consumptive coagulopathy.
- A patient is described as septic from a gram-positive organism. Which structural component of gram-positive bacteria can act as a potent stimulus of the inflammatory response, analogous to lipopolysaccharide in gram-negative sepsis?
- Lipoteichoic acid and peptidoglycan in the cell wall
- The nuclear membrane
- Ribosomal RNA only
- The mitochondrial inner membrane
Correct answer: Lipoteichoic acid and peptidoglycan in the cell wall
The answer is lipoteichoic acid and peptidoglycan in the cell wall. These gram-positive cell wall components are recognized by innate immune receptors and trigger cytokine release that can drive sepsis, paralleling the role of lipopolysaccharide endotoxin in gram-negative organisms. Bacteria lack a nuclear membrane and mitochondria, and ribosomal RNA alone is not the proinflammatory cell wall stimulus.
- A patient develops profound shock after a massive transfusion and is noted to have a low ionized calcium, hypothermia, and a coagulopathy. Recognizing how these factors interact is important because together they primarily worsen which problem?
- Excessive clotting only
- Bleeding and impaired hemostasis
- Improved cardiac contractility
- Resolution of acidosis
Correct answer: Bleeding and impaired hemostasis
The answer is bleeding and impaired hemostasis. Hypocalcemia from citrate, hypothermia, and dilution of clotting factors during massive transfusion impair coagulation enzyme function and platelet activity, worsening hemorrhage. These factors do not promote excessive clotting, improve contractility, or resolve acidosis.
- A clinician explains the term immune reconstitution inflammatory syndrome in a patient with advanced HIV who deteriorates after starting antiretroviral therapy. This multisystem worsening is best explained by which mechanism?
- The antiretroviral drugs directly poison the organs
- The HIV virus mutates into a bacterium
- A recovering immune system mounts an exaggerated inflammatory response to a preexisting or latent infection
- Complete and permanent failure of the immune system
Correct answer: A recovering immune system mounts an exaggerated inflammatory response to a preexisting or latent infection
The answer is that a recovering immune system mounts an exaggerated inflammatory response to a preexisting or latent infection. As antiretroviral therapy restores immune function, the reconstituted response against organisms such as mycobacteria or cryptococcus can paradoxically cause clinical worsening across systems. It is not direct drug poisoning, viral conversion to a bacterium, or immune failure.
- A patient with sepsis develops stress hyperglycemia despite no history of diabetes. Which mechanism best explains the elevated glucose during critical illness?
- Excess insulin secretion lowering glucose
- Complete shutdown of hepatic glucose production
- Loss of all glucose in the urine
- Counterregulatory hormones and inflammatory cytokines increase gluconeogenesis and insulin resistance
Correct answer: Counterregulatory hormones and inflammatory cytokines increase gluconeogenesis and insulin resistance
The answer is that counterregulatory hormones and inflammatory cytokines increase gluconeogenesis and insulin resistance. The stress response in sepsis raises cortisol, catecholamines, and glucagon and promotes cytokine-driven insulin resistance, elevating blood glucose even without diabetes. It is not from excess insulin, halted hepatic glucose output, or urinary glucose loss.
- A patient is being evaluated for a systemic vasculitis affecting small vessels with antineutrophil cytoplasmic antibodies, upper and lower respiratory tract involvement, and glomerulonephritis. Which vasculitis is most consistent with this multisystem picture?
- Granulomatosis with polyangiitis
- Giant cell arteritis
- Takayasu arteritis
- Kawasaki disease
Correct answer: Granulomatosis with polyangiitis
The answer is granulomatosis with polyangiitis, an ANCA-associated small-vessel vasculitis that classically involves the upper airway (sinuses), lungs, and kidneys with necrotizing granulomatous inflammation and glomerulonephritis. Giant cell and Takayasu arteritis affect large vessels, and Kawasaki disease is a medium-vessel vasculitis of childhood with coronary involvement.
- A patient receiving a chemotherapy agent develops profound neutropenia and then a fever. Why is febrile neutropenia treated as a medical emergency requiring immediate broad-spectrum antibiotics?
- Fever in neutropenia is always harmless
- The lack of neutrophils blunts signs of infection and allows rapid progression to overwhelming sepsis
- Neutropenia improves the immune response to infection
- Antibiotics should be withheld until cultures return in this setting
Correct answer: The lack of neutrophils blunts signs of infection and allows rapid progression to overwhelming sepsis
The answer is that the lack of neutrophils blunts signs of infection and allows rapid progression to overwhelming sepsis. With too few neutrophils, infections can spread swiftly with few localizing signs, so empiric broad-spectrum antibiotics are started immediately after cultures are drawn. Fever in neutropenia is dangerous, neutropenia weakens defenses, and delaying antibiotics is hazardous.
- A patient with disseminated cancer develops new confusion, and workup reveals leptomeningeal spread of tumor cells throughout the cerebrospinal fluid. This pattern of metastatic spread is best described as which of the following?
- A solitary brain metastasis only
- Direct skull invasion
- Carcinomatous meningitis (leptomeningeal carcinomatosis)
- A paraneoplastic syndrome without tumor cells in the fluid
Correct answer: Carcinomatous meningitis (leptomeningeal carcinomatosis)
The answer is carcinomatous meningitis (leptomeningeal carcinomatosis), in which malignant cells seed the leptomeninges and circulate in the cerebrospinal fluid, producing multifocal neurologic deficits and cranial neuropathies. A solitary metastasis is focal, skull invasion is bony, and a paraneoplastic syndrome lacks tumor cells in the fluid.