FREE Exam P Study Guide 2026: Probability for the SOA/CAS Exam
Every SOA/CAS Exam P topic — probability, distributions, and the Central Limit Theorem — taught to the exam, with worked calculus-based examples, built-in quizzes, and flashcards.
Your exam readiness — tap to see where you stand.Check sections to boost your scoreCheck off sections to raise your exam readiness score
This free Exam P study guide teaches the probability you need for the Society of Actuaries (SOA) / Casualty Actuarial Society (CAS) Probability Exam — every topic the official syllabus tests, organized the way the exam is built.[2] Exam P is the first exam on the path to actuarial credentials: a three-hour, calculus-based, 30-question multiple-choice test of how you model and quantify risk.[1]
The guide covers the three official topics — General Probability, Univariate Random Variables, and Multivariate Random Variables— broken into eight study modules. It’s interactive, not a wall of text: every module has a built-in checkpoint quiz, hover-able glossary terms, worked examples, and concept questions, so you learn by doing. Because Exam P assumes calculus, you’ll integrate densities and differentiate moment generating functions throughout.[2]
Already comfortable with probability and looking ahead to financial mathematics? When you’re ready, move on to our Exam FM study guide. Read this guide module by module, test yourself at each checkpoint, then round out your free Exam P prep with our practice questions and flashcards.
Exam P at a Glance
SOA/CAS Exam P at a glance (2026)
Detail
Actuarial Exam P (Probability)
Questions
30 multiple-choice (5 options A–E each), plus a few unscored pilot questions
Format
Computer-based test (CBT) at Prometric
Time
3 hours
Topics
General Probability · Univariate Random Variables · Multivariate Random Variables
Math assumed
Calculus — series, differentiation, and integration
Provided
Standard-normal distribution table (Exhibit button)
Scoring
Pass/fail by SOA scaling; unanswered = incorrect, so answer every question
Sponsors
Society of Actuaries (SOA) and Casualty Actuarial Society (CAS)
Exam P syllabus weight by topic (2026, SOA/CAS)
Univariate Random Variables
40–47%
Multivariate Random Variables
40–47%
General Probability
10–17%
The two random-variable topics together are roughly 85% of the exam — General Probability is the foundation, but the bulk of your 30 questions test distributions.
The two random-variable topics together are roughly 85% of the exam, so most of your study time belongs in distributions.[2] But General Probability is the language everything else is written in — get fluent with conditional probability and Bayes first:
Exam P topic weights (2026, SOA/CAS official ranges)
Univariate Random Variables47% · 44–50%
General Probability27% · 23–30%
Multivariate Random Variables27% · 23–30%
The SOA reports topic shares as ranges, so the exact mix shifts slightly from form to form.[2] This guide teaches all three topics as eight modules — the General Probability foundation first, then the univariate distributions, then the multivariate material.
1 · Foundations of Probability
Part of General Probability (23–30%). Every Exam P problem rests on the same foundation: a of outcomes, events as subsets, and the three .[2]
Sample Spaces, Events & Axioms
A probability is a function on events satisfying three axioms: P(A)≥0, the whole sample space has P(S)=1, and for events probabilities add. From these come the complement rule P(Ac)=1−P(A) and the bounds 0≤P(A)≤1.
Addition Rule & Combinatorics
The general addition rule is P(A∪B)=P(A)+P(B)−P(A∩B); the last term is 0 when the events are mutually exclusive. To count equally-likely outcomes, use a when order matters and a when it does not:
Counting tools for probability problems
Tool
Formula
Use when
Permutation
nPr=(n−r)!n!
Order matters (arrange, rank)
Combination
(rn)=r!(n−r)!n!
Order does not matter (choose, committee)
Multiplication
n1×n2×⋯
Independent stages of a process
Venn Diagrams & De Morgan’s Laws
A Venn diagram turns set algebra into pictures. let you switch between unions and intersections: (A∪B)c=Ac∩Bc and (A∩B)c=Ac∪Bc. For three events the inclusion-exclusion principle adds the singles, subtracts the pairs, and adds back the triple.
Checkpoint · Topic 1 · Foundations of Probability
Question 1 of 10
Which statement correctly defines the sample space of a random experiment?
2 · Conditional Probability & Bayes’ Theorem
The heart of General Probability (23–30%).Conditional probability, independence, the law of total probability, and Bayes’ theorem appear on nearly every Exam P form.[2]
Conditional Probability & Independence
is P(A∣B)=P(B)P(A∩B), which rearranges to the multiplication rule P(A∩B)=P(A∣B)P(B). Events are exactly when P(A∩B)=P(A)P(B) — equivalently when P(A∣B)=P(A).
Law of Total Probability
When an event A can happen through several mutually exclusive causes, the averages over them: P(A)=∑iP(A∣Bi)P(Bi). Picture a tree: each branch is a cause with its probability, and A occurs along that branch with a conditional probability.
Law of total probability & Bayes’ theorem
1 · Partition the sample spaceSplit into mutually exclusive, exhaustive causes B₁, B₂, … Bₙ (e.g. three machines making parts).
↓
2 · Law of total probabilityP(A) = Σ P(A | Bᵢ) · P(Bᵢ) — the weighted average of the conditional probabilities.
↓
3 · Bayes’ theorem (reverse it)P(Bₖ | A) = [ P(A | Bₖ) · P(Bₖ) ] ÷ P(A) — update the cause given the evidence A.
Total probability runs cause → effect; Bayes runs effect → cause. The denominator is just P(A) from step 2.
Bayes’ Theorem
reverses the conditioning to update a cause given the evidence: P(Bk∣A)=P(A)P(A∣Bk)P(Bk). The denominator is just P(A) from the law of total probability.
Checkpoint · Topic 1 · Conditional Probability & Bayes
Question 1 of 10
An insurer finds that 30% of policyholders file an auto claim, 20% file a home claim, and 8% file both in a year. What is the probability a randomly chosen policyholder files at least one of these claims?
3 · Random Variables & Their Functions
The start of Univariate Random Variables (44–50%) — the biggest topic. A assigns a number to each outcome. Master the functions that describe it, then the named distributions fall into place.[2]
pmf, pdf & CDF
A discrete variable is described by a p(x)=P(X=x), whose values sum to 1. A continuous variable uses a f(x), where probability is area: P(a≤X≤b)=∫abf(x)dx. Both share a F(x)=P(X≤x), and for a continuous variable f(x)=F′(x).
Mean, Median, Mode & Percentiles
The is the long-run average, E[X]=∫xf(x)dx for a continuous variable. The median solves F(m)=0.5, the mode maximizes the density, and the p-th percentile solves F(x)=p.
Summary measures of a distribution
Measure
What it is
Mean (expected value)
The long-run average, E[X] = ∫ x·f(x) dx; sensitive to tails
Median
The value m with F(m) = 0.5; resists outliers
Mode
The value where the density f(x) is largest
pth percentile
The value x with F(x) = p (the 90th percentile has F(x) = 0.90)
Checkpoint · Topic 2 · Random Variables & Their Functions
Question 1 of 8
For a continuous random variable X with probability density function f(x), which property must the function satisfy over its entire support?
4 · Discrete Distributions
Univariate Random Variables (44–50%). The named discrete families — and knowing when each applies — are bread-and-butter Exam P points.[2]
The Exam P distribution map — discrete vs continuous
Discrete (counts)
Bernoulli / BinomialCounts of successes in n trials
PoissonCounts of rare events in a fixed interval
Geometric / Neg. BinomialTrials until the first / r-th success
HypergeometricSuccesses when sampling without replacement
Continuous (measures)
UniformEqually likely over an interval [a, b]
ExponentialWaiting time; memoryless
GammaSum of exponential waits
NormalSums/averages — the CLT limit
Discrete variables use a probability mass function (pmf) and sums (Σ); continuous variables use a probability density function (pdf) and integrals (∫).
Bernoulli, Binomial & Hypergeometric
A single success/failure trial is Bernoulli (mean p, variance p(1−p)). The counts successes in n independent trials: P(X=k)=(kn)pk(1−p)n−k, mean np, variance np(1−p). Use the instead when you sample without replacement from a finite population.
Poisson
The models counts of rare events at rate λ: P(X=k)=k!e−λλk. Uniquely, its mean and variance are bothλ. Sums of independent Poissons are Poisson, with rates adding.
Geometric & Negative Binomial
The counts trials until the first success (mean 1/p) and is the discrete distribution. The generalizes it to the trials needed for r successes.
Discrete distributions — mean and variance
Distribution
Models
Mean
Variance
Bernoulli(p)
One trial
p
p(1−p)
Binomial(n, p)
Successes in n trials (with replacement)
np
np(1−p)
Poisson(λ)
Rare event counts at rate λ
λ
λ
Geometric(p)
Trials to first success
1/p
(1−p)/p2
Checkpoint · Topic 2 · Discrete Distributions
Question 1 of 10
In a binomial distribution with n trials and success probability p, what is the expected number of successes?
5 · Continuous Distributions
Univariate Random Variables (44–50%). The continuous families you integrate — uniform, exponential, gamma, beta, and the all-important normal.[2]
Uniform
The continuous on [a,b] has constant density b−a1, mean 2a+b, and variance 12(b−a)2.
Exponential & Gamma
The models a waiting time with rate λ: density λe−λx, mean and standard deviation both 1/λ, variance 1/λ2. It is and has a constant hazard rate. A is a sum of independent exponential waits.
Normal & Beta
The is the symmetric bell curve. Standardize any normal value with z=σx−μ, then read the standard-normal table the exam provides.[2] The is the fast check:
The normal distribution and the empirical (68–95–99.7) rule
≈ 68% within μ ± 1σ
≈ 95% within μ ± 2σ
≈ 99.7% within μ ± 3σ
Standardize with z = (x − μ) ÷ σ, then read the standard-normal table. The empirical rule is the fast mental check.
The distribution lives on [0,1] and is used to model proportions and probabilities.
Continuous distributions — mean and variance
Distribution
Mean
Variance
Uniform(a, b)
2a+b
12(b−a)2
Exponential(λ)
1/λ
1/λ2
Normal(μ, σ²)
μ
σ2
Checkpoint · Topic 2 · Continuous Distributions
Question 1 of 10
The standard normal distribution has which mean and standard deviation?
Univariate Random Variables (44–50%). Moments summarize a distribution, and the syllabus explicitly tests turning a loss random variable into a payment random variable.[2]
Moments, Variance & Transformations
measures spread: Var(X)=E[X2]−(E[X])2. Under a linear transform Y=aX+b, the mean scales and shifts (E[Y]=aE[X]+b) while the variance ignores the shift and scales by the square: Var(Y)=a2Var(X).
Skewness, MGFs & the Coefficient of Variation
The third central moment measures skewness: positive means a long right tail (mode < median < mean). The is σ/μ. The M(t)=E[etX] generates moments by differentiation — M′(0)=E[X], M′′(0)=E[X2] — and uniquely identifies a distribution.
Deductibles, Coinsurance & Policy Limits
Exam P turns a loss X into a payment through policy provisions. With an ordinary d, the payment per loss is max(X−d,0); multiplies by a fraction α; and a caps the payment.
How a loss X becomes an insurance payment
Ordinary deductible dThe insurer pays nothing until the loss exceeds d. Payment per loss = max(X − d, 0).
↓
Coinsurance factor αThe insurer pays a fraction α of the amount above the deductible: α · (X − d).
↓
Policy limit / maximum uThe payment is capped: the insurer never pays more than the maximum covered amount u.
Exam P loss problems are read in this order: subtract the deductible, apply coinsurance, then cap at the policy limit.
For a random variable X with E(X) = 5, a transformed variable Y = -2X + 10 is defined. What is E(Y)?
7 · Joint, Marginal & Conditional Distributions
The start of Multivariate Random Variables (23–30%). Now two or more variables interact. Master the joint distribution and you can extract everything else from it.[2]
Joint & Marginal Distributions
A gives p(x,y)=P(X=x,Y=y) (discrete) or a joint density f(x,y) (continuous). The distribution of one variable comes from summing or integrating out the other: fX(x)=∫f(x,y)dy. Variables are independent exactly when the joint factors into the marginals, f(x,y)=fX(x)fY(y).
Conditional Distributions & Expectation
The conditional density of Y given X=x is the joint over the marginal, fY∣X(y∣x)=fX(x)f(x,y). The conditional expectation E[X∣Y=y] is the mean of that conditional distribution. The double-expectation rule gives E[X]=E[E[X∣Y]].
For two discrete random variables X and Y, the joint cumulative distribution function F(x, y) gives which quantity?
8 · Covariance, the CLT & Order Statistics
Multivariate Random Variables (23–30%). How variables co-vary, how their linear combinations behave, and the theorem that makes the normal universal.[2]
Covariance & Correlation
measures co-movement: Cov(X,Y)=E[XY]−E[X]E[Y]; it is 0 for independent variables (though 0 covariance alone does not prove independence). The ρ=σXσYCov(X,Y) standardizes it to [−1,1]. Covariance is bilinear: Cov(aX,bY)=abCov(X,Y).
Linear Combinations & the CLT
For any two variables, Var(X+Y)=Var(X)+Var(Y)+2Cov(X,Y); when they are independent the covariance term vanishes and the variances simply add. The says the standardized sum of many i.i.d. variables is approximately standard normal: σnSn−nμ→N(0,1).
The Central Limit Theorem — why the normal is everywhere
Any distributionX₁, X₂, … Xₙ are i.i.d. with mean μ and variance σ² — they need NOT be normal (e.g. skewed claim sizes).
↓
Sum or average themForm the sum Sₙ = ΣXᵢ or the mean X̄. E[X̄] = μ and Var(X̄) = σ²/n.
↓
Becomes approximately normalFor large n, the standardized sum (Sₙ − nμ) ÷ (σ√n) is approximately standard normal — regardless of the original shape.
This is why aggregate claims and sample means are modeled with the normal distribution — and why the normal dominates the exam.
Order Statistics
are a sample sorted smallest to largest. For n i.i.d. observations with CDF F, the maximum has CDF [F(t)]n and the minimum has 1−[1−F(t)]n. The sample range is the largest minus the smallest order statistic.
Checkpoint · Topic 3 · Covariance, the CLT & Order Statistics
Question 1 of 10
Four independent observations are drawn from a continuous distribution with cumulative distribution function F. An actuary wants the distribution of the largest of the four values. The cumulative distribution function of this maximum at a point t is given by which expression?
How to Use This Study Guide
A study guide is a map, not the whole territory — use it alongside official SOA sample questions and our free tools.[3] Exam P is heavily computational, so practice solving problems against the clock, not just reading. Spend the bulk of your time on Univariate Random Variables (nearly half the exam), but never skip General Probability — Bayes and conditional probability thread through everything, including the multivariate material.
A study loop that actually works
1
Read a module here
Work through one module at a time — Foundations and Bayes first, then the univariate distributions, then the multivariate topics.
2
Take the checkpoint
The quick check at the end of each module exposes what didn't stick.
3
Drill the gaps
Send your weak topic straight into the free practice questions and flashcards.
4
Take full, timed practice
Sit full 30-question, three-hour practice exams to build stamina, then review every miss.
Exam P Concept Questions
Core probability concepts the SOA/CAS Exam P actually tests — at least one per official topic. Tap any card for a short, exam-ready answer backed by an official source (SOA), then test yourself on them as flashcards.
Exam P Concept · General Probability
What is Bayes' theorem and when do you use it?
Quick answer
Bayes' theorem reverses a conditional probability: P(B | A) = [P(A | B) · P(B)] ÷ P(A). Use it to update the probability of a cause B after observing evidence A — for example, the chance a part came from a given machine after seeing that it is defective.[1]
Bayes is a core General Probability outcome. The denominator P(A) is usually found first with the law of total probability, P(A) = Σ P(A | Bᵢ) · P(Bᵢ).
On Exam P it appears in classic 'reverse' setups: defect-by-machine, disease-given-a-positive-test, and claim-by-risk-class problems.
What is the difference between mutually exclusive and independent events?
Quick answer
Mutually exclusive events cannot both occur, so P(A and B) = 0. Independent events do not affect each other's probability, so P(A and B) = P(A) · P(B). Two events with positive probability cannot be both mutually exclusive and independent — those are different ideas, not the same.[1]
This is a General Probability outcome that examiners deliberately try to confuse. Mutually exclusive is about overlap (none); independent is about influence (none).
For mutually exclusive events the addition rule simplifies to P(A or B) = P(A) + P(B).
What is the difference between a permutation and a combination?
Quick answer
A permutation counts arrangements where order matters: nPr = n! ÷ (n − r)!. A combination counts selections where order does not matter: nCr = 'n choose r' = n! ÷ [r!(n − r)!]. Combinations are the permutations divided by r! to remove the orderings.[1]
Combinatorics is a General Probability outcome used to build the numerators and denominators of equally-likely probability problems.
If the question says 'arrange,' 'order,' or 'rank,' use permutations; if it says 'choose,' 'select,' or 'committee,' use combinations.
The law of total probability finds P(A) by averaging over a partition of the sample space into mutually exclusive, exhaustive events B₁, …, Bₙ: P(A) = Σ P(A | Bᵢ) · P(Bᵢ). It is the weighted average of the conditional probabilities, weighted by how likely each cause is.[1]
This General Probability tool is the setup step that feeds Bayes' theorem — it supplies the denominator P(A).
Picture a tree: each branch is a cause Bᵢ with probability P(Bᵢ), then A occurs along that branch with probability P(A | Bᵢ).
What is the difference between a probability mass function and a probability density function?
Quick answer
A probability mass function (pmf) gives the probability at each value of a discrete random variable, and the values sum to 1. A probability density function (pdf) describes a continuous variable; probability is the area under the curve, so you integrate it, and the total integral is 1.[1]
This is a foundational Univariate Random Variables outcome. For a continuous variable, P(X = x) = 0 — only intervals have positive probability.
The cumulative distribution function F(x) = P(X ≤ x) works for both; the pdf is its derivative, f(x) = F′(x).
What are the mean and variance of a binomial distribution?
Quick answer
A binomial random variable counts the successes in n independent trials, each with success probability p. Its mean is E[X] = np and its variance is Var(X) = np(1 − p). The pmf is P(X = k) = (n choose k) · pᵏ · (1 − p)ⁿ⁻ᵏ.[1]
The binomial is a key discrete distribution in Univariate Random Variables. A single trial (n = 1) is the Bernoulli distribution, with mean p and variance p(1 − p).
Use the binomial when trials are independent with replacement; use the hypergeometric when sampling without replacement.
The Poisson distribution models the count of rare events in a fixed interval of time or space, given an average rate λ. Its pmf is P(X = k) = e⁻λ · λᵏ ÷ k!, and uniquely its mean and variance are both equal to λ.[1]
The Poisson is a central discrete distribution in Univariate Random Variables and the standard model for claim counts.
The sum of independent Poisson variables is again Poisson, with rate equal to the sum of the individual rates.
Why is the exponential distribution called memoryless?
Quick answer
The exponential distribution is memoryless: P(X > s + t | X > s) = P(X > t). A used component that has already survived s hours has the same remaining-life distribution as a brand-new one. It models waiting times, and its mean and standard deviation are both equal to 1/λ.[1]
The exponential is the key continuous waiting-time distribution in Univariate Random Variables, with variance 1/λ² (the square of the mean).
It has a constant hazard (force of failure) rate λ — the only continuous distribution with this property.
How do you use the standard normal distribution to find probabilities?
Quick answer
Standardize the value with z = (x − μ) ÷ σ, which converts any normal variable to the standard normal (mean 0, standard deviation 1). Then read the cumulative probability from the normal table. By the empirical rule, about 68%, 95%, and 99.7% of values fall within 1, 2, and 3 standard deviations.[1]
The normal is the most-tested continuous distribution in Univariate Random Variables; Exam P supplies a standard-normal table during the test.
Because of symmetry, P(Z ≤ −z) = 1 − P(Z ≤ z), and P(Z > 0) = 0.5.
How do expected value and variance behave under a linear transformation?
Quick answer
For Y = aX + b, the expected value scales and shifts: E[Y] = aE[X] + b. The variance ignores the shift and scales by the square of the coefficient: Var(Y) = a²·Var(X), so the standard deviation scales by |a|. Adding a constant b never changes the spread.[1]
These rules are core Univariate Random Variables results used constantly for rescaling and inflation problems.
Variance can also be computed as Var(X) = E[X²] − (E[X])² — the shortcut formula.
The moment generating function (MGF) is M(t) = E[e^(tX)]. Differentiating it and setting t = 0 produces the moments: M′(0) = E[X], M″(0) = E[X²]. MGFs uniquely identify a distribution, and the MGF of a sum of independent variables is the product of their MGFs.[1]
MGFs are a powerful Univariate tool for finding means and variances and for proving that a sum of distributions keeps its family (e.g. independent Poissons sum to a Poisson).
If two random variables have the same MGF, they have the same distribution.
How does an insurance deductible affect the expected payment?
Quick answer
With an ordinary deductible d, the insurer's payment per loss is max(X − d, 0): nothing is paid until the loss exceeds d, then the excess is paid. Because small losses are zeroed out, the expected payment is always less than the expected loss E[X].[1]
Calculating payment-amount random variables from loss random variables is an explicit Univariate Random Variables outcome on the syllabus.
Layer the provisions in order: subtract the deductible, apply any coinsurance fraction, then cap at the policy limit.
Covariance measures how two random variables move together: Cov(X, Y) = E[XY] − E[X]·E[Y]. A positive value means they tend to rise together, negative means one rises as the other falls, and zero means no linear relationship. Independent variables always have covariance 0.[1]
Covariance is a core Multivariate Random Variables outcome, and it scales bilinearly: Cov(aX, bY) = ab·Cov(X, Y).
The correlation coefficient ρ = Cov(X, Y) ÷ (σX·σY) standardizes it to the range −1 to 1.
What is the variance of a sum of two random variables?
Quick answer
For any two random variables, Var(X + Y) = Var(X) + Var(Y) + 2·Cov(X, Y). When X and Y are independent, the covariance is 0, so the variances simply add: Var(X + Y) = Var(X) + Var(Y). Means always add regardless of independence.[1]
This is a heavily tested Multivariate result for linear combinations. For Var(X − Y) the covariance term is subtracted: Var(X) + Var(Y) − 2·Cov(X, Y).
The Central Limit Theorem says that the sum (or average) of many independent, identically distributed random variables is approximately normal for large n, no matter the original distribution's shape. The standardized sum (Sₙ − nμ) ÷ (σ√n) approaches the standard normal.[1]
Applying the CLT to approximate probabilities for linear combinations of i.i.d. variables is an explicit Multivariate Random Variables outcome.
It is why aggregate claim totals and sample means are modeled with the normal distribution even when individual losses are skewed.
Order statistics are a sample of independent observations sorted from smallest to largest. The minimum is the first order statistic, the maximum the last. For n i.i.d. observations with CDF F, the maximum's CDF is [F(t)]ⁿ and the minimum's is 1 − [1 − F(t)]ⁿ.[1]
Determining the distribution of order statistics for independent random variables is a named Multivariate Random Variables outcome.
The sample range is the largest order statistic minus the smallest — useful for warranty and extreme-value style problems.
Quick definitions for the terms you’ll see most across SOA/CAS Exam P:
Axioms of probability
The three rules every probability obeys: P(A)≥0; P(S)=1; and for mutually exclusive events, the probability of their union is the sum of their probabilities.
Bayes' theorem
Reverses a conditional probability: P(Bk∣A)=P(A)P(A∣Bk)P(Bk), where the denominator comes from the law of total probability.
Beta distribution
A continuous distribution on the interval [0,1], often used to model proportions and probabilities.
Binomial distribution
Counts successes in n independent trials with success probability p: P(X=k)=(kn)pk(1−p)n−k, mean np, variance np(1−p).
Central Limit Theorem
The sum or average of many independent, identically distributed variables is approximately normal for large n, whatever the original shape.
Coefficient of variation
The standard deviation divided by the mean, σ/μ — a relative measure of spread.
Coinsurance
A provision under which the insurer pays a fraction α of the covered loss above the deductible, e.g. 80%.
Combination
A selection of objects where order does NOT matter: (rn)=r!(n−r)!n!.
Conditional probability
The probability of A given that B has occurred: P(A∣B)=P(B)P(A∩B), defined when P(B)>0.
Correlation coefficient
ρ=σXσYCov(X,Y), a standardized covariance ranging from −1 to 1.
Covariance
Measures how two variables move together: Cov(X,Y)=E[XY]−E[X]E[Y]; positive, negative, or 0 (always 0 if independent).
Cumulative distribution function
F(x)=P(X≤x). It is nondecreasing from 0 to 1; for a continuous variable f(x)=F′(x).
Deductible
An amount the policyholder absorbs before the insurer pays. With an ordinary deductible d, the payment per loss is max(X−d,0).
Empirical rule
For a normal distribution, about 68%, 95%, and 99.7% of values fall within 1, 2, and 3 standard deviations of the mean.
Expected value
The long-run average of a random variable: E[X]=∑xxp(x) (discrete) or ∫xf(x)dx (continuous).
Exponential distribution
Models waiting time with rate λ; density λe−λx, mean and standard deviation 1/λ, variance 1/λ2. It is memoryless.
Gamma distribution
A continuous distribution generalizing the exponential; a sum of α independent exponential waits has a gamma distribution.
Geometric distribution
Counts trials (or failures) until the first success, with mean 1/p. It is the discrete memoryless distribution.
Hypergeometric distribution
Models successes when sampling a fixed number of items WITHOUT replacement from a finite two-type population.
Independent events
Events whose occurrence does not affect each other, so P(A∩B)=P(A)P(B). Independence concerns influence; mutual exclusivity concerns overlap — they are not the same.
Joint distribution
Describes two (or more) random variables together: p(x,y)=P(X=x,Y=y) (discrete) or a joint density f(x,y) (continuous).
Law of total probability
For a partition B1,…,Bn of the sample space, P(A)=∑iP(A∣Bi)P(Bi) — the weighted average of conditional probabilities.
Marginal distribution
The distribution of one variable alone, found by summing or integrating the joint distribution over the other variable.
Memoryless property
P(X>s+t∣X>s)=P(X>t): a used item that has survived s has the same remaining-life distribution as a new one. Held by the exponential and geometric.
Moment generating function
M(t)=E[etX]. Its derivatives at 0 give the moments (M′(0)=E[X]); it uniquely identifies a distribution.
Mutually exclusive
Two events that cannot both occur, so P(A∩B)=0. For mutually exclusive events the addition rule simplifies to P(A∪B)=P(A)+P(B).
Negative binomial distribution
Counts the trials needed to reach a fixed number r of successes — a generalization of the geometric distribution.
Normal distribution
The symmetric bell curve with mean μ and standard deviation σ. Standardize with z=σx−μ to use the standard-normal table.
Order statistics
A sample sorted from smallest to largest. For n i.i.d. variables with CDF F, the maximum has CDF [F(t)]n and the minimum has 1−[1−F(t)]n.
Permutation
An arrangement of objects where order matters: nPr=(n−r)!n!.
Poisson distribution
Counts rare events at rate λ: P(X=k)=k!e−λλk, with mean and variance both equal to λ.
Policy limit
The maximum amount an insurer will pay on a loss; the payment is capped at this value.
Probability density function
For a continuous variable, f(x)≥0 whose integral over the support is 1; probability is the area under it, P(a≤X≤b)=∫abf(x)dx.
Probability mass function
For a discrete variable, p(x)=P(X=x); the values are nonnegative and sum to 1.
Random variable
A function that assigns a number to each outcome of an experiment. It is discrete if it takes countable values, continuous if it takes values on an interval.
Sample space
The set of all possible outcomes of a random experiment, usually written S or Ω. An event is any subset of the sample space.
Uniform distribution
All outcomes equally likely. Continuous on [a,b] it has density b−a1, mean 2a+b, and variance 12(b−a)2.
Variance
A measure of spread: Var(X)=E[(X−μ)2]=E[X2]−(E[X])2. Its square root is the standard deviation σ.
Free Exam P Study Materials & Resources
Everything you need to prepare for Exam P is free here — no paywall, no sign-up. This guide is the foundation; pair it with the rest of our free Exam P study materials for active recall, timed practice, and last-minute review:
Exam P Practice Test — exam-style probability questions across all three topics, with worked explanations.
Exam P Flashcards — active-recall decks for the named distributions, their means and variances, and the key theorems.
Exam FM Study Guide — the next preliminary exam, on financial mathematics, for when you move past Exam P.
Exam P Study Guide FAQ
Exam P is a three-hour computer-based test (CBT) consisting of 30 multiple-choice questions, each with five answer choices (A–E). A few additional unscored pilot questions are randomly placed in the exam and do not count toward your score.
Exam P is a three-hour exam administered as a computer-based test (CBT) at Prometric centers during scheduled testing windows. Unofficial pass/fail results are emailed within about an hour of finishing.
Exam P covers three topics: General Probability (23–30%) — set theory, combinatorics, conditional probability, independence, and Bayes' theorem; Univariate Random Variables (44–50%) — discrete and continuous distributions, expectation, variance, moments, and insurance applications; and Multivariate Random Variables (23–30%) — joint, marginal and conditional distributions, covariance, linear combinations, the Central Limit Theorem, and order statistics.
Yes. Exam P assumes a working knowledge of calculus — series, differentiation, and integration — because continuous distributions are defined by densities you integrate and moments you compute with integrals. Candidates are also expected to be familiar with the 'Risk and Insurance' study note.
For discrete variables: Bernoulli, binomial, geometric, hypergeometric, negative binomial, Poisson, and discrete uniform. For continuous variables: uniform, exponential, gamma, beta, and normal. Know each one's mean, variance, and the situations it models.
A table of values for the standard normal distribution is provided during the exam under an Exhibit button (and in hard copy for paper administrations), so you do not bring your own. The SOA also publishes the approved calculator list on the exam's home page.
Each scored question is worth the same; unanswered questions are marked incorrect, so you should answer every question. The SOA sets the pass mark through its scaling process rather than publishing a fixed percentage, and results are reported as pass or fail. Exam P typically has a historically low pass rate, so thorough preparation matters.
Work through the eight modules in order — Foundations and Bayes first, then the univariate distributions, then the multivariate topics. After each module take the checkpoint quiz to find gaps, then drill that topic with our free practice questions and flashcards before sitting full, timed practice exams.
Yes — the full guide, the checkpoints, the glossary, the practice questions, and the flashcards are 100% free, with no account required.
Career Employer is the ultimate resource to help you get started working the job of your dreams. We cover topics from general career information, career searching, exam preparation with free study materials, career interviewing, and becoming successful in your career of choice.
Here at Career Employer, we focus a lot on providing factually accurate information that is always up to date. We strive to provide correct information using strict editorial processes, article editing, and fact-checking for all of the information found on our website. We only utilize trustworthy and relevant resources. To find out more, make sure to read our full editorial process page here.