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FREE Exam P Study Guide 2026: Probability for the SOA/CAS Exam

Every SOA/CAS Exam P topic — probability, distributions, and the Central Limit Theorem — taught to the exam, with worked calculus-based examples, built-in quizzes, and flashcards.

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This free Exam P study guide teaches the probability you need for the Society of Actuaries (SOA) / Casualty Actuarial Society (CAS) Probability Exam — every topic the official syllabus tests, organized the way the exam is built.[2] Exam P is the first exam on the path to actuarial credentials: a three-hour, calculus-based, 30-question multiple-choice test of how you model and quantify risk.[1]

The guide covers the three official topics — General Probability, Univariate Random Variables, and Multivariate Random Variables— broken into eight study modules. It’s interactive, not a wall of text: every module has a built-in checkpoint quiz, hover-able glossary terms, worked examples, and concept questions, so you learn by doing. Because Exam P assumes calculus, you’ll integrate densities and differentiate moment generating functions throughout.[2]

Already comfortable with probability and looking ahead to financial mathematics? When you’re ready, move on to our Exam FM study guide. Read this guide module by module, test yourself at each checkpoint, then round out your free Exam P prep with our practice questions and flashcards.

Exam P at a Glance

SOA/CAS Exam P at a glance (2026)
DetailActuarial Exam P (Probability)
Questions30 multiple-choice (5 options A–E each), plus a few unscored pilot questions
FormatComputer-based test (CBT) at Prometric
Time3 hours
TopicsGeneral Probability · Univariate Random Variables · Multivariate Random Variables
Math assumedCalculus — series, differentiation, and integration
ProvidedStandard-normal distribution table (Exhibit button)
ScoringPass/fail by SOA scaling; unanswered = incorrect, so answer every question
SponsorsSociety of Actuaries (SOA) and Casualty Actuarial Society (CAS)
Exam P syllabus weight by topic (2026, SOA/CAS)
Univariate Random Variables
40–47%
Multivariate Random Variables
40–47%
General Probability
10–17%

The two random-variable topics together are roughly 85% of the exam — General Probability is the foundation, but the bulk of your 30 questions test distributions.

The two random-variable topics together are roughly 85% of the exam, so most of your study time belongs in distributions.[2] But General Probability is the language everything else is written in — get fluent with conditional probability and Bayes first:

Exam P topic weights (2026, SOA/CAS official ranges)
Univariate Random Variables47% · 44–50%
General Probability27% · 23–30%
Multivariate Random Variables27% · 23–30%

The SOA reports topic shares as ranges, so the exact mix shifts slightly from form to form.[2] This guide teaches all three topics as eight modules — the General Probability foundation first, then the univariate distributions, then the multivariate material.

1 · Foundations of Probability

Part of General Probability (23–30%). Every Exam P problem rests on the same foundation: a of outcomes, events as subsets, and the three .[2]

Sample Spaces, Events & Axioms

A probability is a function on events satisfying three axioms: P(A)0 P(A) \ge 0 , the whole sample space has P(S)=1 P(S) = 1 , and for events probabilities add. From these come the complement rule P(Ac)=1P(A) P(A^c) = 1 - P(A) and the bounds 0P(A)1 0 \le P(A) \le 1 .

Addition Rule & Combinatorics

The general addition rule is P(AB)=P(A)+P(B)P(AB) P(A \cup B) = P(A) + P(B) - P(A \cap B) ; the last term is 0 when the events are mutually exclusive. To count equally-likely outcomes, use a when order matters and a when it does not:

Counting tools for probability problems
ToolFormulaUse when
PermutationnPr=n!(nr)! \,_nP_r = \dfrac{n!}{(n-r)!} Order matters (arrange, rank)
Combination(nr)=n!r!(nr)! \binom{n}{r} = \dfrac{n!}{r!(n-r)!} Order does not matter (choose, committee)
Multiplicationn1×n2× n_1 \times n_2 \times \cdots Independent stages of a process

Venn Diagrams & De Morgan’s Laws

A Venn diagram turns set algebra into pictures. let you switch between unions and intersections: (AB)c=AcBc (A \cup B)^c = A^c \cap B^c and (AB)c=AcBc (A \cap B)^c = A^c \cup B^c . For three events the inclusion-exclusion principle adds the singles, subtracts the pairs, and adds back the triple.

Checkpoint · Topic 1 · Foundations of Probability

Question 1 of 10

Which statement correctly defines the sample space of a random experiment?

2 · Conditional Probability & Bayes’ Theorem

The heart of General Probability (23–30%).Conditional probability, independence, the law of total probability, and Bayes’ theorem appear on nearly every Exam P form.[2]

Conditional Probability & Independence

is P(AB)=P(AB)P(B) P(A \mid B) = \dfrac{P(A \cap B)}{P(B)} , which rearranges to the multiplication rule P(AB)=P(AB)P(B) P(A \cap B) = P(A \mid B)\,P(B) . Events are exactly when P(AB)=P(A)P(B) P(A \cap B) = P(A)\,P(B) — equivalently when P(AB)=P(A) P(A \mid B) = P(A) .

Law of Total Probability

When an event A can happen through several mutually exclusive causes, the averages over them: P(A)=iP(ABi)P(Bi) P(A) = \sum_i P(A \mid B_i)\,P(B_i) . Picture a tree: each branch is a cause with its probability, and A occurs along that branch with a conditional probability.

Law of total probability & Bayes’ theorem
1 · Partition the sample spaceSplit into mutually exclusive, exhaustive causes B₁, B₂, … Bₙ (e.g. three machines making parts).
2 · Law of total probabilityP(A) = Σ P(A | Bᵢ) · P(Bᵢ) — the weighted average of the conditional probabilities.
3 · Bayes’ theorem (reverse it)P(Bₖ | A) = [ P(A | Bₖ) · P(Bₖ) ] ÷ P(A) — update the cause given the evidence A.

Total probability runs cause → effect; Bayes runs effect → cause. The denominator is just P(A) from step 2.

Bayes’ Theorem

reverses the conditioning to update a cause given the evidence: P(BkA)=P(ABk)P(Bk)P(A) P(B_k \mid A) = \dfrac{P(A \mid B_k)\,P(B_k)}{P(A)} . The denominator is just P(A) P(A) from the law of total probability.

Checkpoint · Topic 1 · Conditional Probability & Bayes

Question 1 of 10

An insurer finds that 30% of policyholders file an auto claim, 20% file a home claim, and 8% file both in a year. What is the probability a randomly chosen policyholder files at least one of these claims?

3 · Random Variables & Their Functions

The start of Univariate Random Variables (44–50%) — the biggest topic. A assigns a number to each outcome. Master the functions that describe it, then the named distributions fall into place.[2]

pmf, pdf & CDF

A discrete variable is described by a p(x)=P(X=x) p(x) = P(X = x) , whose values sum to 1. A continuous variable uses a f(x) f(x) , where probability is area: P(aXb)=abf(x)dx P(a \le X \le b) = \int_a^b f(x)\,dx . Both share a F(x)=P(Xx) F(x) = P(X \le x) , and for a continuous variable f(x)=F(x) f(x) = F'(x) .

Mean, Median, Mode & Percentiles

The is the long-run average, E[X]=xf(x)dx E[X] = \int x\,f(x)\,dx for a continuous variable. The median solves F(m)=0.5 F(m) = 0.5 , the mode maximizes the density, and the p-th percentile solves F(x)=p F(x) = p .

Summary measures of a distribution
MeasureWhat it is
Mean (expected value)The long-run average, E[X] = ∫ x·f(x) dx; sensitive to tails
MedianThe value m with F(m) = 0.5; resists outliers
ModeThe value where the density f(x) is largest
pth percentileThe value x with F(x) = p (the 90th percentile has F(x) = 0.90)

Checkpoint · Topic 2 · Random Variables & Their Functions

Question 1 of 8

For a continuous random variable X with probability density function f(x), which property must the function satisfy over its entire support?

4 · Discrete Distributions

Univariate Random Variables (44–50%). The named discrete families — and knowing when each applies — are bread-and-butter Exam P points.[2]

The Exam P distribution map — discrete vs continuous
Discrete (counts)
  • Bernoulli / BinomialCounts of successes in n trials
  • PoissonCounts of rare events in a fixed interval
  • Geometric / Neg. BinomialTrials until the first / r-th success
  • HypergeometricSuccesses when sampling without replacement
Continuous (measures)
  • UniformEqually likely over an interval [a, b]
  • ExponentialWaiting time; memoryless
  • GammaSum of exponential waits
  • NormalSums/averages — the CLT limit

Discrete variables use a probability mass function (pmf) and sums (Σ); continuous variables use a probability density function (pdf) and integrals (∫).

Bernoulli, Binomial & Hypergeometric

A single success/failure trial is Bernoulli (mean p p , variance p(1p) p(1-p) ). The counts successes in n n independent trials: P(X=k)=(nk)pk(1p)nk P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} , mean np np , variance np(1p) np(1-p) . Use the instead when you sample without replacement from a finite population.

Poisson

The models counts of rare events at rate λ \lambda : P(X=k)=eλλkk! P(X=k) = \dfrac{e^{-\lambda}\lambda^k}{k!} . Uniquely, its mean and variance are both λ \lambda . Sums of independent Poissons are Poisson, with rates adding.

Geometric & Negative Binomial

The counts trials until the first success (mean 1/p 1/p ) and is the discrete distribution. The generalizes it to the trials needed for r r successes.

Discrete distributions — mean and variance
DistributionModelsMeanVariance
Bernoulli(p)One trialp p p(1p) p(1-p)
Binomial(n, p)Successes in n trials (with replacement)np np np(1p) np(1-p)
Poisson(λ)Rare event counts at rate λλ \lambda λ \lambda
Geometric(p)Trials to first success1/p 1/p (1p)/p2 (1-p)/p^2

Checkpoint · Topic 2 · Discrete Distributions

Question 1 of 10

In a binomial distribution with n trials and success probability p, what is the expected number of successes?

5 · Continuous Distributions

Univariate Random Variables (44–50%). The continuous families you integrate — uniform, exponential, gamma, beta, and the all-important normal.[2]

Uniform

The continuous on [a,b] [a, b] has constant density 1ba \dfrac{1}{b-a} , mean a+b2 \dfrac{a+b}{2} , and variance (ba)212 \dfrac{(b-a)^2}{12} .

Exponential & Gamma

The models a waiting time with rate λ \lambda : density λeλx \lambda e^{-\lambda x} , mean and standard deviation both 1/λ 1/\lambda , variance 1/λ2 1/\lambda^2 . It is and has a constant hazard rate. A is a sum of independent exponential waits.

Normal & Beta

The is the symmetric bell curve. Standardize any normal value with z=xμσ z = \dfrac{x - \mu}{\sigma} , then read the standard-normal table the exam provides.[2] The is the fast check:

The normal distribution and the empirical (68–95–99.7) rule
μμ−σμ+σμ−2σμ+2σ68%within 1σ
≈ 68%
within μ ± 1σ
≈ 95%
within μ ± 2σ
≈ 99.7%
within μ ± 3σ

Standardize with z = (x − μ) ÷ σ, then read the standard-normal table. The empirical rule is the fast mental check.

The distribution lives on [0,1] [0, 1] and is used to model proportions and probabilities.

Continuous distributions — mean and variance
DistributionMeanVariance
Uniform(a, b)a+b2 \dfrac{a+b}{2} (ba)212 \dfrac{(b-a)^2}{12}
Exponential(λ)1/λ 1/\lambda 1/λ2 1/\lambda^2
Normal(μ, σ²)μ \mu σ2 \sigma^2

Checkpoint · Topic 2 · Continuous Distributions

Question 1 of 10

The standard normal distribution has which mean and standard deviation?

6 · Expectation, Variance & Insurance Applications

Univariate Random Variables (44–50%). Moments summarize a distribution, and the syllabus explicitly tests turning a loss random variable into a payment random variable.[2]

Moments, Variance & Transformations

measures spread: Var(X)=E[X2](E[X])2 \text{Var}(X) = E[X^2] - (E[X])^2 . Under a linear transform Y=aX+b Y = aX + b , the mean scales and shifts (E[Y]=aE[X]+b E[Y] = aE[X] + b ) while the variance ignores the shift and scales by the square: Var(Y)=a2Var(X) \text{Var}(Y) = a^2\,\text{Var}(X) .

Skewness, MGFs & the Coefficient of Variation

The third central moment measures skewness: positive means a long right tail (mode < median < mean). The is σ/μ \sigma/\mu . The M(t)=E[etX] M(t) = E[e^{tX}] generates moments by differentiation — M(0)=E[X] M'(0) = E[X] , M(0)=E[X2] M''(0) = E[X^2] — and uniquely identifies a distribution.

Deductibles, Coinsurance & Policy Limits

Exam P turns a loss X X into a payment through policy provisions. With an ordinary d d , the payment per loss is max(Xd, 0) \max(X - d,\ 0) ; multiplies by a fraction α \alpha ; and a caps the payment.

How a loss X becomes an insurance payment
Ordinary deductible dThe insurer pays nothing until the loss exceeds d. Payment per loss = max(X − d, 0).
Coinsurance factor αThe insurer pays a fraction α of the amount above the deductible: α · (X − d).
Policy limit / maximum uThe payment is capped: the insurer never pays more than the maximum covered amount u.

Exam P loss problems are read in this order: subtract the deductible, apply coinsurance, then cap at the policy limit.

Checkpoint · Topic 2 · Expectation, Variance & Insurance

Question 1 of 10

For a random variable X with E(X) = 5, a transformed variable Y = -2X + 10 is defined. What is E(Y)?

7 · Joint, Marginal & Conditional Distributions

The start of Multivariate Random Variables (23–30%). Now two or more variables interact. Master the joint distribution and you can extract everything else from it.[2]

Joint & Marginal Distributions

A gives p(x,y)=P(X=x,Y=y) p(x, y) = P(X = x, Y = y) (discrete) or a joint density f(x,y) f(x, y) (continuous). The distribution of one variable comes from summing or integrating out the other: fX(x)=f(x,y)dy f_X(x) = \int f(x, y)\,dy . Variables are independent exactly when the joint factors into the marginals, f(x,y)=fX(x)fY(y) f(x, y) = f_X(x)\,f_Y(y) .

Conditional Distributions & Expectation

The conditional density of Y Y given X=x X = x is the joint over the marginal, fYX(yx)=f(x,y)fX(x) f_{Y \mid X}(y \mid x) = \dfrac{f(x, y)}{f_X(x)} . The conditional expectation E[XY=y] E[X \mid Y = y] is the mean of that conditional distribution. The double-expectation rule gives E[X]=E[E[XY]] E[X] = E[\,E[X \mid Y]\,] .

Checkpoint · Topic 3 · Joint, Marginal & Conditional

Question 1 of 10

For two discrete random variables X and Y, the joint cumulative distribution function F(x, y) gives which quantity?

8 · Covariance, the CLT & Order Statistics

Multivariate Random Variables (23–30%). How variables co-vary, how their linear combinations behave, and the theorem that makes the normal universal.[2]

Covariance & Correlation

measures co-movement: Cov(X,Y)=E[XY]E[X]E[Y] \text{Cov}(X, Y) = E[XY] - E[X]\,E[Y] ; it is 0 for independent variables (though 0 covariance alone does not prove independence). The ρ=Cov(X,Y)σXσY \rho = \dfrac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y} standardizes it to [1,1] [-1, 1] . Covariance is bilinear: Cov(aX,bY)=abCov(X,Y) \text{Cov}(aX, bY) = ab\,\text{Cov}(X, Y) .

Linear Combinations & the CLT

For any two variables, Var(X+Y)=Var(X)+Var(Y)+2Cov(X,Y) \text{Var}(X + Y) = \text{Var}(X) + \text{Var}(Y) + 2\,\text{Cov}(X, Y) ; when they are independent the covariance term vanishes and the variances simply add. The says the standardized sum of many i.i.d. variables is approximately standard normal: SnnμσnN(0,1) \dfrac{S_n - n\mu}{\sigma\sqrt{n}} \to N(0, 1) .

The Central Limit Theorem — why the normal is everywhere
  1. Any distributionX₁, X₂, … Xₙ are i.i.d. with mean μ and variance σ² — they need NOT be normal (e.g. skewed claim sizes).
  2. Sum or average themForm the sum Sₙ = ΣXᵢ or the mean X̄. E[X̄] = μ and Var(X̄) = σ²/n.
  3. Becomes approximately normalFor large n, the standardized sum (Sₙ − nμ) ÷ (σ√n) is approximately standard normal — regardless of the original shape.

This is why aggregate claims and sample means are modeled with the normal distribution — and why the normal dominates the exam.

Order Statistics

are a sample sorted smallest to largest. For n n i.i.d. observations with CDF F F , the maximum has CDF [F(t)]n [F(t)]^n and the minimum has 1[1F(t)]n 1 - [1 - F(t)]^n . The sample range is the largest minus the smallest order statistic.

Checkpoint · Topic 3 · Covariance, the CLT & Order Statistics

Question 1 of 10

Four independent observations are drawn from a continuous distribution with cumulative distribution function F. An actuary wants the distribution of the largest of the four values. The cumulative distribution function of this maximum at a point t is given by which expression?

How to Use This Study Guide

A study guide is a map, not the whole territory — use it alongside official SOA sample questions and our free tools.[3] Exam P is heavily computational, so practice solving problems against the clock, not just reading. Spend the bulk of your time on Univariate Random Variables (nearly half the exam), but never skip General Probability — Bayes and conditional probability thread through everything, including the multivariate material.

A study loop that actually works
  1. 1

    Read a module here

    Work through one module at a time — Foundations and Bayes first, then the univariate distributions, then the multivariate topics.

  2. 2

    Take the checkpoint

    The quick check at the end of each module exposes what didn't stick.

  3. 3

    Drill the gaps

    Send your weak topic straight into the free practice questions and flashcards.

  4. 4

    Take full, timed practice

    Sit full 30-question, three-hour practice exams to build stamina, then review every miss.

Exam P Concept Questions

Core probability concepts the SOA/CAS Exam P actually tests — at least one per official topic. Tap any card for a short, exam-ready answer backed by an official source (SOA), then test yourself on them as flashcards.

Exam P Glossary

Quick definitions for the terms you’ll see most across SOA/CAS Exam P:

Axioms of probability
The three rules every probability obeys: P(A)0P(A) \ge 0; P(S)=1P(S) = 1; and for mutually exclusive events, the probability of their union is the sum of their probabilities.
Bayes' theorem
Reverses a conditional probability: P(BkA)=P(ABk)P(Bk)P(A)P(B_k \mid A) = \dfrac{P(A \mid B_k)\,P(B_k)}{P(A)}, where the denominator comes from the law of total probability.
Beta distribution
A continuous distribution on the interval [0,1][0,1], often used to model proportions and probabilities.
Binomial distribution
Counts successes in nn independent trials with success probability pp: P(X=k)=(nk)pk(1p)nkP(X=k) = \binom{n}{k}p^k(1-p)^{n-k}, mean npnp, variance np(1p)np(1-p).
Central Limit Theorem
The sum or average of many independent, identically distributed variables is approximately normal for large nn, whatever the original shape.
Coefficient of variation
The standard deviation divided by the mean, σ/μ\sigma / \mu — a relative measure of spread.
Coinsurance
A provision under which the insurer pays a fraction α\alpha of the covered loss above the deductible, e.g. 80%.
Combination
A selection of objects where order does NOT matter: (nr)=n!r!(nr)!\binom{n}{r} = \dfrac{n!}{r!\,(n-r)!}.
Conditional probability
The probability of A given that B has occurred: P(AB)=P(AB)P(B)P(A \mid B) = \dfrac{P(A \cap B)}{P(B)}, defined when P(B)>0P(B) > 0.
Correlation coefficient
ρ=Cov(X,Y)σXσY\rho = \dfrac{\text{Cov}(X,Y)}{\sigma_X \sigma_Y}, a standardized covariance ranging from 1-1 to 11.
Covariance
Measures how two variables move together: Cov(X,Y)=E[XY]E[X]E[Y]\text{Cov}(X,Y) = E[XY] - E[X]\,E[Y]; positive, negative, or 0 (always 0 if independent).
Cumulative distribution function
F(x)=P(Xx)F(x) = P(X \le x). It is nondecreasing from 0 to 1; for a continuous variable f(x)=F(x)f(x) = F'(x).
Deductible
An amount the policyholder absorbs before the insurer pays. With an ordinary deductible dd, the payment per loss is max(Xd,0)\max(X - d,\,0).
Empirical rule
For a normal distribution, about 68%, 95%, and 99.7% of values fall within 1, 2, and 3 standard deviations of the mean.
Expected value
The long-run average of a random variable: E[X]=xxp(x)E[X] = \sum_x x\,p(x) (discrete) or xf(x)dx\int x\,f(x)\,dx (continuous).
Exponential distribution
Models waiting time with rate λ\lambda; density λeλx\lambda e^{-\lambda x}, mean and standard deviation 1/λ1/\lambda, variance 1/λ21/\lambda^2. It is memoryless.
Gamma distribution
A continuous distribution generalizing the exponential; a sum of α\alpha independent exponential waits has a gamma distribution.
Geometric distribution
Counts trials (or failures) until the first success, with mean 1/p1/p. It is the discrete memoryless distribution.
Hypergeometric distribution
Models successes when sampling a fixed number of items WITHOUT replacement from a finite two-type population.
Independent events
Events whose occurrence does not affect each other, so P(AB)=P(A)P(B)P(A \cap B) = P(A)\,P(B). Independence concerns influence; mutual exclusivity concerns overlap — they are not the same.
Joint distribution
Describes two (or more) random variables together: p(x,y)=P(X=x,Y=y)p(x,y) = P(X=x,\,Y=y) (discrete) or a joint density f(x,y)f(x,y) (continuous).
Law of total probability
For a partition B1,,BnB_1,\dots,B_n of the sample space, P(A)=iP(ABi)P(Bi)P(A) = \sum_i P(A \mid B_i)\,P(B_i) — the weighted average of conditional probabilities.
Marginal distribution
The distribution of one variable alone, found by summing or integrating the joint distribution over the other variable.
Memoryless property
P(X>s+tX>s)=P(X>t)P(X > s + t \mid X > s) = P(X > t): a used item that has survived ss has the same remaining-life distribution as a new one. Held by the exponential and geometric.
Moment generating function
M(t)=E[etX]M(t) = E[e^{tX}]. Its derivatives at 0 give the moments (M(0)=E[X]M'(0)=E[X]); it uniquely identifies a distribution.
Mutually exclusive
Two events that cannot both occur, so P(AB)=0P(A \cap B) = 0. For mutually exclusive events the addition rule simplifies to P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B).
Negative binomial distribution
Counts the trials needed to reach a fixed number rr of successes — a generalization of the geometric distribution.
Normal distribution
The symmetric bell curve with mean μ\mu and standard deviation σ\sigma. Standardize with z=xμσz = \dfrac{x-\mu}{\sigma} to use the standard-normal table.
Order statistics
A sample sorted from smallest to largest. For nn i.i.d. variables with CDF FF, the maximum has CDF [F(t)]n[F(t)]^n and the minimum has 1[1F(t)]n1 - [1 - F(t)]^n.
Permutation
An arrangement of objects where order matters: nPr=n!(nr)!\,_nP_r = \dfrac{n!}{(n-r)!}.
Poisson distribution
Counts rare events at rate λ\lambda: P(X=k)=eλλkk!P(X=k) = \dfrac{e^{-\lambda}\lambda^k}{k!}, with mean and variance both equal to λ\lambda.
Policy limit
The maximum amount an insurer will pay on a loss; the payment is capped at this value.
Probability density function
For a continuous variable, f(x)0f(x) \ge 0 whose integral over the support is 1; probability is the area under it, P(aXb)=abf(x)dxP(a \le X \le b) = \int_a^b f(x)\,dx.
Probability mass function
For a discrete variable, p(x)=P(X=x)p(x) = P(X = x); the values are nonnegative and sum to 1.
Random variable
A function that assigns a number to each outcome of an experiment. It is discrete if it takes countable values, continuous if it takes values on an interval.
Sample space
The set of all possible outcomes of a random experiment, usually written S or Ω\Omega. An event is any subset of the sample space.
Uniform distribution
All outcomes equally likely. Continuous on [a,b][a,b] it has density 1ba\dfrac{1}{b-a}, mean a+b2\dfrac{a+b}{2}, and variance (ba)212\dfrac{(b-a)^2}{12}.
Variance
A measure of spread: Var(X)=E[(Xμ)2]=E[X2](E[X])2\text{Var}(X) = E[(X - \mu)^2] = E[X^2] - (E[X])^2. Its square root is the standard deviation σ\sigma.

Free Exam P Study Materials & Resources

Everything you need to prepare for Exam P is free here — no paywall, no sign-up. This guide is the foundation; pair it with the rest of our free Exam P study materials for active recall, timed practice, and last-minute review:

  • Exam P Practice Test — exam-style probability questions across all three topics, with worked explanations.
  • Exam P Flashcards — active-recall decks for the named distributions, their means and variances, and the key theorems.
  • Exam FM Study Guide — the next preliminary exam, on financial mathematics, for when you move past Exam P.

Exam P Study Guide FAQ

Exam P is a three-hour computer-based test (CBT) consisting of 30 multiple-choice questions, each with five answer choices (A–E). A few additional unscored pilot questions are randomly placed in the exam and do not count toward your score.

References

  1. 1.Society of Actuaries. “Probability (P) Exam.” Society of Actuaries.
  2. 2.Society of Actuaries. “Probability Exam Syllabus.” Society of Actuaries.
  3. 3.Society of Actuaries. “Studying for the Probability (P) Exam.” Society of Actuaries.
  4. 4.Casualty Actuarial Society. “Exam P — Probability.” Casualty Actuarial Society.

Sources for the concept answers

Every answer in the Exam P concept questions above is drawn from an official primary source:

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