Your FREE GRE Mathematics Subject Test Practice Questions 2026 – 150+ Q&A
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GRE Math Practice Questions
What is the derivative of f(x)=e2xsin(x)?
e2xcos(x)
2e2xsin(x)+e2xcos(x)
e2xsin(x)+e2xcos(x)
2e2xcos(x)−e2xsin(x)
Correct answer: 2e2xsin(x)+e2xcos(x)
Correct answer: 2e2xsin(x)+e2xcos(x). Explanation: Use the product rule for differentiation.
Find the integral of ∫xln(x)1dx.
ln∣ln(x)∣+C
ln∣x∣+C
ln(x)1+C
ln(x)x+C
Correct answer: ln∣ln(x)∣+C
Correct answer: ln∣ln(x)∣+C. Explanation: Use substitution, setting u=ln(x).
What is the area enclosed by the curve y=x2 and the lines x=−1,x=2, and y=0?
3 square units
4.5 square units
9 square units
5.5 square units
Correct answer: 3 square units
Correct answer: 3 square units. Explanation: Calculate the definite integral of x2 from -1 to 2.
Determine the convergence or divergence of the series ∑n=1∞n21.
Converges
Diverges
Converges conditionally
Cannot be determined
Correct answer: Converges
Correct answer: Converges. Explanation: Use the p-series test where p=2>1, indicating convergence.
If f(x)=ln(x), what is f′′(e)?
e1
−e1
e21
−e21
Correct answer: −e21
Correct answer: −e21. Explanation: Calculate the second derivative of ln(x) and evaluate at x=e.
Calculate the derivative of f(x)=x(x2+1).
2x1(x2+1)+2xx
2x1+2xx
23xx
21x−21+2x23
Correct answer: 2x1(x2+1)+2xx
Correct answer: 2x1(x2+1)+2xx. Explanation: Apply the product rule and simplify.
Evaluate the definite integral ∫02(3x2−2x)dx.
4
6
8
10
Correct answer: 4
Correct answer: 4. Explanation: Find the antiderivative x3−x2 and apply the Fundamental Theorem of Calculus: (8−4)−0=4.
Find the derivative of g(t)=t4ln(t).
4t3ln(t)
4t3ln(t)+t3
4t3+t3ln(t)
t4+4t3ln(t)
Correct answer: 4t3ln(t)+t3
Correct answer: 4t3ln(t)+t3. Explanation: Use the product rule for differentiation.
Evaluate the integral: ∫(3x2−2x+1)dx.
x3−x2+x+C
x3−2x2+x+C
x3−x2+2x+C
x3+x2+x+C
Correct answer: x3−x2+x+C
Correct answer: x3−x2+x+C. Explanation: Integrate each term separately.
Determine the limit: limx→∞2x3+54x3−x.
0
1
24
∞
Correct answer: 24
Correct answer: 24. Explanation: Divide each term by x3 and take the limit.
Find the area under the curve y=e2x from x=0 to x=1.
e2−1
2e2−1
e2
2e2
Correct answer: 2e2−1
Correct answer: 2e2−1. Explanation: Evaluate the definite integral of the function.
Evaluate: limx→0xsin(3x).
0
1
3
Undefined
Correct answer: 3
Correct answer: 3. Explanation: Apply the standard limit limx→0xsin(x)=1 with a change of variable.
What is the derivative of f(x)=x5sin(x2)?
5x4sin(x2)+2x6cos(x2)
5x4sin(x2)+x6cos(x2)
5x4cos(x2)
x5cos(x2)
Correct answer: 5x4sin(x2)+2x6cos(x2)
Correct answer: 5x4sin(x2)+2x6cos(x2). Explanation: Apply the product rule and the chain rule.
Calculate the derivative of f(x)=x2+x+11.
(x2+x+1)2−2x−1
(x2+x+1)2−2x+1
(x2+x+1)22x−1
(x2+x+1)22x+1
Correct answer: (x2+x+1)2−2x−1
Correct answer: (x2+x+1)2−2x−1. Explanation: Apply the quotient rule to find the derivative.
Evaluate the limit: limx→0xex−1.
0
1
e
Undefined
Correct answer: 1
Correct answer: 1. Explanation: This is a standard limit for exponential functions.
Find the indefinite integral: ∫xcos(x2)dx.
21sin(x2)+C
sin(x2)+C
cos(x2)+C
21cos(x2)+C
Correct answer: 21sin(x2)+C
Correct answer: 21sin(x2)+C. Explanation: Use substitution with u=x2.
Compute the area between the curves y=x2 and y=x for 0≤x≤1.
61
31
21
32
Correct answer: 61
Correct answer: 61. Explanation: Subtract the integrals of the two functions over the given interval.
Determine the convergence or divergence of the series ∑n=1∞n3(−1)n.
Converges
Diverges
Converges conditionally
Cannot be determined
Correct answer: Converges
Correct answer: Converges. Explanation: The series converges absolutely: the terms n31 form a convergent p-series with p=3>1, so the alternating series converges. 'Converges conditionally' is incorrect because the absolute series already converges.
What is the maximum value of the function f(x)=−x2+4x−3 on the interval [0, 3]?
1
2
3
4
Correct answer: 1
Correct answer: 1. Explanation: Find the vertex of the parabola or use calculus to find the maximum.
Evaluate the integral: ∫xx2−1dx.
ln∣x+x2−1∣+C
arcsinx1+C
arcsecx+C
ln∣x2−x2−1∣+C
Correct answer: arcsecx+C
Correct answer: arcsecx+C. Explanation: Use substitution and trigonometric identities.
Find the derivative of g(y)=arctan(y).
2y(1+y)1
2y(1+y2)1
1+y1
1+y21
Correct answer: 2y(1+y)1
Correct answer: 2y(1+y)1. Explanation: Apply the chain rule and simplify.
Compute the limit: limx→∞xx2+x−x.
0
21
1
Undefined
Correct answer: 0
Correct answer: 0. Explanation: Multiply by the conjugate and simplify.
If x and y are integers such that x2+y2=100, what is the maximum possible value of x+y?
10
14
17
20
Correct answer: 14
Correct answer: 14. Explanation: The maximum value occurs when one variable is maximized while keeping the sum of squares equal to 100.
Find the roots of the equation x3−6x2+11x−6=0.
1, 2, 3
1, 3, 6
2, 4, 5
3, 4, 5
Correct answer: 1, 2, 3
Correct answer: 1, 2, 3. Explanation: Use the Rational Root Theorem or factorization to find the roots.
If 32x−1=27, what is the value of x?
1
2
3
4
Correct answer: 2
Correct answer: 2. Explanation: Express 27 as a power of 3 and solve the resulting equation.
Given f(x)=x2−4x+4, for what value of x is f(x)=0?
0
2
4
6
Correct answer: 2
Correct answer: 2. Explanation: Solve the quadratic equation x2−4x+4=0.
If (2x−1)(x+3)=0, what are the possible values of x?
−3 and 21
−3 and 31
3 and 21
3 and 31
Correct answer: −3 and 21
Correct answer: −3 and 21. Explanation: Set each factor equal to zero and solve for x.
Given a quadratic equation x2+kx+16=0, where k is a constant. If the equation has two distinct real roots, which of the following must be true?
k>4
k>8
k2>64
k2−64>0
Correct answer: k2−64>0
Correct answer: k2−64>0. Explanation: For two distinct real roots, the discriminant must be positive.
If 52x−1=125, what is the value of x?
1
2
3
4
Correct answer: 2
Correct answer: 2. Explanation: Express 125 as a power of 5 and solve the resulting equation.
What are the solutions to the equation x2−5x+6=0?
2 and 3
1 and 6
-2 and -3
-1 and -6
Correct answer: 2 and 3
Correct answer: 2 and 3. Explanation: Factorize the quadratic equation or use the quadratic formula.
If x and y satisfy the equation 3x−2y=6, which of the following represents y in terms of x?
23x−6
26−3x
2x−3
3−2x
Correct answer: 23x−6
Correct answer: 23x−6. Explanation: Solve the linear equation for y in terms of x.
If 2x+3y=12 and 3x+2y=12, what is the value of x−y?
0
1
2
3
Correct answer: 0
Correct answer: 0. Explanation: Solve the system of linear equations and find x−y.
A set contains all integers x such that −2<x<3. How many elements are in this set?
3
4
5
6
Correct answer: 4
Correct answer: 4. Explanation: The set includes the integers -1, 0, 1, and 2, which are 4 in total.
In a class of 30 students, 18 are studying French, 15 are studying German, and 7 are studying both. How many students are not studying either language?
4
6
8
10
Correct answer: 4
Correct answer: 4. Explanation: Use the principle of inclusion-exclusion. Total studying at least one language is 18+15−7=26. So, 30−26=4 are studying neither.
What is the area of a triangle with sides of length 13, 14, and 15?
84
88
90
92
Correct answer: 84
Correct answer: 84. Explanation: Use Heron's formula with semi-perimeter s=213+14+15=21: Area =21×8×7×6=7056=84.
If the sum of the first n terms of an arithmetic sequence is given by Sn=3n2+5n, what is the first term of the sequence?
8
9
10
11
Correct answer: 8
Correct answer: 8. Explanation: The first term is S1=3(1)2+5(1)=8.
In a certain sequence, the term an=n(n+1)1 for n≥1. What is the sum of the first 10 terms of this sequence?
1110
101
21
109
Correct answer: 1110
Correct answer: 1110. Explanation: Observe the telescoping nature of the series and compute the sum.
What is the remainder when 2100 is divided by 7?
1
2
3
4
Correct answer: 2
Correct answer: 2. Explanation: Use the properties of exponents and modular arithmetic to find the pattern of remainders.
A rectangle is inscribed in a circle of radius r. If the perimeter of the rectangle is 20, what is the maximum possible area of the rectangle?
25
50
75
100
Correct answer: 25
Correct answer: 25. Explanation: Use the relationship between the radius of the circle and the dimensions of the rectangle.
If x and y are integers such that x2+y2=25, what is the maximum possible value of x?
3
4
5
6
Correct answer: 5
Correct answer: 5. Explanation: Consider the possible integer pairs that satisfy the equation.
A fair six-sided die is rolled twice. What is the probability that the sum of the two rolls is 9?
365
61
41
364
Correct answer: 364
Correct answer: 364. Explanation: Count the favorable outcomes and divide by the total possible outcomes.
What is the value of n in the permutation equation P(n,3)=60?
5
6
7
8
Correct answer: 5
Correct answer: 5. Explanation: Solve the permutation equation P(n,3)=n(n−1)(n−2).
A circle has a circumference of 8π. What is the area of the circle?
16π
32π
64π
128π
Correct answer: 16π
Correct answer: 16π. Explanation: Use the formula for circumference C=2πr to find the radius, then calculate the area.
What is the hundredth term of the arithmetic sequence 3, 6, 9, ... ?
297
300
303
306
Correct answer: 300
Correct answer: 300. Explanation: Use the formula for the n-th term of an arithmetic sequence.
What is the equation of the line perpendicular to y=2x+3 and passing through the point (1,−2)?
y=−21x+21
y=−21x−23
y=−21x−2
y=−21x−25
Correct answer: y=−21x−23
Correct answer: y=−21x−23. Explanation: Find the slope of the perpendicular line and use the point to find the equation.
If a set contains all numbers x such that 1<x2<9, what is the range of x?
−2<x<2
−3<x<3
1<x<3
−3<x<−1 and 1<x<3
Correct answer: −3<x<−1 and 1<x<3
Correct answer: −3<x<−1 and 1<x<3. Explanation: Consider both positive and negative square roots of the given range.
The sum of the interior angles of a polygon is 1260 degrees. How many sides does the polygon have?
7
8
9
10
Correct answer: 9
Correct answer: 9. Explanation: Use the formula 180(n−2) where n is the number of sides.
A cylinder has a radius of 3 and a height of 4. What is the volume of the cylinder?
36π
48π
54π
72π
Correct answer: 36π
Correct answer: 36π. Explanation: Use the formula for the volume of a cylinder V=πr2h.
If log2x+log2y=5 and log2x−log2y=1, what is the value of x?
2
4
8
16
Correct answer: 8
Correct answer: 8. Explanation: Solve the system of logarithmic equations.
Using integration by parts, what is the value of the integral of xex with respect to x?
xex+ex+C
xex−ex+C
2x2ex+C
ex(x+1)+C
Correct answer: xex−ex+C
The antiderivative is xex−ex+C. Integration by parts uses the formula ∫udv=uv−∫vdu; choosing u=x (so du=dx) and dv=exdx (so v=ex) gives xex−∫exdx=xex−ex+C. The tempting xex+ex+C reverses the sign of the second term.
Apply L'Hopital's rule to evaluate limx→0x2ex−1−x.
21
1
Does not exist
0
Correct answer: 21
The limit equals 21. The form is 00, so differentiating top and bottom gives 2xex−1, still 00; a second application gives 2ex, which approaches 21 as x→0. Stopping after one application and concluding the limit is 0 misses the second indeterminate form.
The Mean Value Theorem guarantees a point c in (1,4) for f(x)=x2 where the instantaneous rate of change equals the average rate of change. What is c?
5
3
2.5
2
Correct answer: 2.5
The value is c=2.5. The Mean Value Theorem requires f′(c)=4−1f(4)−f(1)=316−1=5; since f′(x)=2x, setting 2c=5 gives c=2.5, which lies in (1,4). The midpoint 2.5 of the interval coincidentally equals the answer here because f is quadratic, but the theorem is satisfied by the derivative condition.
By the Fundamental Theorem of Calculus, if F(x) is the integral from 0 to x of cos(t2)dt, what is F′(x)?
−sin(x2)⋅2x
cos(x2)
21sin(x2)
cos(x2)⋅2x
Correct answer: cos(x2)
F′(x)=cos(x2). The Fundamental Theorem of Calculus (Part 1) states that the derivative of an integral with a constant lower limit and variable upper limit x is simply the integrand evaluated at x. No chain-rule factor of 2x appears because the upper limit is x itself, not x2.
Using the chain rule, what is the derivative of f(x)=(3x2+1)5?
30x(3x2+1)4
5(6x)4
6x(3x2+1)4
5(3x2+1)4
Correct answer: 30x(3x2+1)4
The derivative is 30x(3x2+1)4. The chain rule multiplies the derivative of the outer power, 5(3x2+1)4, by the derivative of the inner function 3x2+1, which is 6x, giving 5⋅6x=30x times (3x2+1)4. Forgetting the inner derivative leaves the incorrect 5(3x2+1)4.
By the alternating series test, which condition on the terms bn (all positive) must hold for the series ∑(−1)nbn to converge?
bn must equal n1 exactly
bn must be increasing
bn must approach 0 and be eventually decreasing
The sum of bn must converge
Correct answer: bn must approach 0 and be eventually decreasing
The terms bn must approach 0 and be eventually monotonically decreasing. The alternating series test (Leibniz test) guarantees convergence when these two conditions hold, even if the series of absolute values diverges. Requiring the sum of bn to converge would describe absolute convergence, a strictly stronger condition than the test requires.
Green's theorem converts a line integral around a positively oriented simple closed curve C into a double integral over the enclosed region D. For the field F=(P,Q), the line integral of Pdx+Qdy equals the double integral over D of which expression?
∂y∂P−∂x∂Q
∂y∂Q−∂x∂P
∂x∂P+∂y∂Q
∂x∂Q−∂y∂P
Correct answer: ∂x∂Q−∂y∂P
The integrand is ∂x∂Q−∂y∂P. Green's theorem equates the counterclockwise circulation line integral of Pdx+Qdy to the double integral of the scalar curl, Qx−Py, over the enclosed region. Reversing this to Py−Qx flips the sign and corresponds to clockwise orientation.
Using the limit comparison test with bn=n21, what can be concluded about the series ∑n=1∞n3+5n+1?
It converges
It diverges
It converges only conditionally
The test is inconclusive
Correct answer: It converges
The series converges. The limit comparison test compares an=n3+5n+1 with bn=n21; the limit of bnan equals the limit of n3+5n2(n+1)=1, a finite positive number. Since ∑n21 is a convergent p-series (p=2>1), the given series also converges.
What is the Maclaurin series for cos(x)?
1−2!x2+4!x4−6!x6+⋯
1−x+2!x2−3!x3+⋯
x−3!x3+5!x5−⋯
1+x+2!x2+3!x3+⋯
Correct answer: 1−2!x2+4!x4−6!x6+⋯
The Maclaurin series for cos(x) is 1−2!x2+4!x4−6!x6+⋯, containing only even powers of x with alternating signs. A Maclaurin series is a Taylor series centered at 0; the series with only odd powers (x−3!x3+⋯) is the expansion of sin(x), not cosine.
Using Lagrange multipliers to extremize f(x,y)=x+y subject to the constraint x2+y2=8, what is the maximum value of f?
22
2
4
8
Correct answer: 4
The maximum value is 4. Setting ∇f=λ∇g gives 1=2λx and 1=2λy, so x=y; substituting into x2+y2=8 yields 2x2=8, x=2, so x=y=2 and f=4. The competing value 22 is the distance 8, not the sum x+y.
For f(x,y)=x2y+3y3, what is the partial derivative of f with respect to y?
x2+3y2
2xy+9y2
2xy
x2+9y2
Correct answer: x2+9y2
The partial derivative with respect to y is x2+9y2. When differentiating partially with respect to y, x is held constant, so x2y differentiates to x2 and 3y3 differentiates to 9y2. The expression 2xy is the partial derivative with respect to x of the first term, not with respect to y.
The integral test can be applied to ∑n=1∞n(lnn)21 starting at n=2. What does it conclude?
The series converges
The series oscillates
The integral test does not apply
The series diverges
Correct answer: The series converges
The series converges. The integral test applies because f(x)=x(lnx)21 is positive, continuous, and decreasing for x≥2; the improper integral from 2 to infinity equals the limit of −lnx1, which converges to ln21. Since the integral converges, so does the series.
A spherical balloon is inflated so its volume increases at 36π cubic cm per second. Using related rates, how fast is the radius increasing when the radius is 3 cm? (V=34πr3.)
1 cm/s
4π cm/s
2 cm/s
3 cm/s
Correct answer: 1 cm/s
The radius increases at 1 cm/s. Differentiating V=34πr3 gives dtdV=4πr2dtdr; substituting dtdV=36π and r=3 gives 36π=4π(9)dtdr=36πdtdr, so dtdr=1. The related rates method links the rates through the chain rule applied to the volume formula.
Evaluate the line integral of the scalar field f(x,y)=x along the curve C parameterized by x=t, y=t for t from 0 to 1, with respect to arc length ds.
22
1
21
2
Correct answer: 22
The line integral equals 22. With x=t and y=t, ds=(dx/dt)2+(dy/dt)2dt=2dt, and f=t, so the integral is ∫01t2dt=2⋅21=22. Omitting the 2 arc-length factor gives the incorrect value 21.
According to the epsilon-delta definition of a limit, the statement 'limx→af(x)=L' means: for every ϵ>0 there exists a δ>0 such that which condition holds?
If 0<∣x−a∣<δ then ∣f(x)−L∣<ϵ
If ∣f(x)−L∣<δ then ∣x−a∣<ϵ
If x=a then f(x)=L
If ∣x−a∣<ϵ then ∣f(x)−L∣<δ
Correct answer: If 0<∣x−a∣<δ then ∣f(x)−L∣<ϵ
The correct condition is: if 0<∣x−a∣<δ then ∣f(x)−L∣<ϵ. The epsilon-delta definition says that for any tolerance ϵ on the output, a positive δ on the input can be found so that all x within δ of a (but not equal to a) map to f(x) within ϵ of L. Swapping the roles of ϵ and δ describes a different, incorrect statement.
What is the sum of the telescoping series ∑n=1∞(n1−n+11)?
0
1
21
Diverges
Correct answer: 1
The sum is 1. In a telescoping series, successive terms cancel: the partial sum SN=1−N+11, and as N approaches infinity, N+11 approaches 0, leaving 1. Recognizing the cancellation pattern is the key technique rather than applying a convergence test.
Evaluate the double integral over the rectangle 0≤x≤2, 0≤y≤3 of the function f(x,y)=xy.
18
6
9
12
Correct answer: 9
The double integral equals 9. Because the integrand separates as x times y over a rectangle, the value is (∫02xdx)(∫03ydy)=2⋅4.5=9. The value 18 would result from forgetting the factor of one-half in one of the single integrals.
Using the ratio test, what does the test conclude about the series ∑n=1∞10nn!?
The ratio test is inconclusive
It converges
It converges conditionally
It diverges
Correct answer: It diverges
The series diverges. The ratio test computes the limit of anan+1=n!/10n(n+1)!/10n+1=10n+1, which approaches infinity. Since this limit exceeds 1, the ratio test guarantees divergence; the factorial grows far faster than the exponential 10n.
For what values of the common ratio r does the geometric series ∑n=0∞rn converge, and to what value?
All r, converging to 1+r1
∣r∣≤1, converging to 1−r1
r>0, converging to 1−rr
∣r∣<1, converging to 1−r1
Correct answer: ∣r∣<1, converging to 1−r1
The geometric series converges if and only if ∣r∣<1, with sum 1−r1. When the absolute value of the ratio is at least 1, the terms do not approach 0 and the series diverges. The endpoint r=1 gives 1+1+1+⋯, which diverges, so the inequality must be strict.
Apply the root test to the series ∑n=1∞(2n+1n)n. What is the conclusion?
It converges to 21
It converges
The root test is inconclusive
It diverges
Correct answer: It converges
The series converges. The root test evaluates the limit of the nth root of ∣an∣, which is the limit of 2n+1n=21. Because this limit 21 is less than 1, the root test guarantees convergence. The value 21 is the limit used by the test, not the sum of the series.
How do you find limx→2x−2x2−4?
The limit does not exist
Substitute directly to get 0
Factor and cancel to get 4
Apply the squeeze theorem to get 2
Correct answer: Factor and cancel to get 4
Factoring and canceling gives the limit 4. The expression x−2x2−4 factors as x−2(x−2)(x+2); canceling the common factor leaves x+2, which evaluates to 4 at x=2. Direct substitution initially yields the indeterminate form 00, so algebraic simplification is the correct technique.
What is the radius of convergence of the power series ∑n=0∞n!xn?
e
1
0
Infinity
Correct answer: Infinity
The radius of convergence is infinity. Applying the ratio test to n!xn gives the limit of (n+1)!∣x∣n!=n+1∣x∣, which approaches 0 for every x. Since the limit is less than 1 for all real x, the series (which equals ex) converges everywhere.
What is the difference between absolute convergence and conditional convergence of a series?
Absolute applies only to positive series; conditional only to negative series
Absolute means ∑∣an∣ converges; conditional means the series converges but ∑∣an∣ diverges
They are two names for the same property
Absolute means the series diverges; conditional means it converges
Correct answer: Absolute means ∑∣an∣ converges; conditional means the series converges but ∑∣an∣ diverges
A series is absolutely convergent when the sum of the absolute values of its terms converges, whereas it is conditionally convergent when the series itself converges but the sum of absolute values diverges. The alternating harmonic series ∑n(−1)n is the classic conditionally convergent example, since ∑n1 diverges.
Using the direct comparison test, what is concluded about the series ∑n=1∞n2+3n1?
It diverges because each term is at least n1
It converges only conditionally
The comparison test does not apply
It converges because each term is at most n21
Correct answer: It converges because each term is at most n21
The series converges because n2+3n1≤n21 for all n≥1, and ∑n21 is a convergent p-series. The direct comparison test states that if terms of a positive series are dominated by the terms of a known convergent series, the given series also converges.
A function f is differentiable at a point. Which statement about continuity and differentiability is true?
Differentiability at a point implies continuity there, but continuity does not imply differentiability
Continuity at a point implies differentiability there
Neither property implies the other
Differentiability implies the function is constant
Correct answer: Differentiability at a point implies continuity there, but continuity does not imply differentiability
Differentiability at a point implies continuity at that point, but the converse fails. The absolute value function ∣x∣ is continuous at x=0 yet not differentiable there because its left and right derivatives differ. Thus continuity is a necessary but not sufficient condition for differentiability.
Determine whether the sequence an=n+23n+1 converges, and if so, to what limit.
Converges to 3
Converges to 21
Diverges to infinity
Converges to 0
Correct answer: Converges to 3
The sequence converges to 3. Dividing numerator and denominator by n gives 1+2/n3+1/n; as n approaches infinity, the n1 and n2 terms vanish, leaving 13=3. The ratio of the leading coefficients determines the limit when numerator and denominator have the same degree.
How can you tell whether the series ∑n=1∞n1 is convergent or divergent?
It converges because the terms approach 0
It diverges to −∞
It diverges; it is the harmonic series, a p-series with p=1
It converges to 1
Correct answer: It diverges; it is the harmonic series, a p-series with p=1
The harmonic series ∑n1 diverges. It is a p-series with p=1, and p-series diverge whenever p≤1. The fact that the individual terms n1 approach 0 is necessary but not sufficient for convergence, which is a common misconception.
How do you find the Taylor series of a function f about a point a?
∑n=0∞f(a)n(x−a)n
∑n=0∞n!f(n)(a)(x−a)n
Differentiate f once and multiply by (x−a)
∑n=0∞n!f(n)(x)an
Correct answer: ∑n=0∞n!f(n)(a)(x−a)n
The Taylor series of f about a is ∑n=0∞n!f(n)(a)(x−a)n. Each coefficient is the nth derivative of f evaluated at the center a, divided by n!. When the center a is 0, this reduces to the Maclaurin series.
For the scalar function f(x,y)=x2+3xy, what is the gradient vector at the point (1,2)?
(8,3)
(8,6)
(2,3)
(5,6)
Correct answer: (8,3)
The gradient is (8,3). The gradient in multivariable calculus is the vector of partial derivatives: fx=2x+3y and fy=3x; at (1,2) these give 2(1)+3(2)=8 and 3(1)=3, so ∇f=(8,3). The gradient points in the direction of steepest increase of f.
What is the Taylor series (about 0) of the common function 1−x1 for ∣x∣<1?
1+x+x2+x3+⋯
x+2x2+3x3+⋯
1+1!x+2!x2+⋯
1−x+x2−x3+⋯
Correct answer: 1+x+x2+x3+⋯
The series for 1−x1 is 1+x+x2+x3+⋯, the geometric series with ratio x, valid for ∣x∣<1. This is one of the standard Taylor series of common functions. The alternating version 1−x+x2−⋯ corresponds instead to 1+x1.
Evaluate the improper integral ∫1∞x21dx.
Diverges
1
2
21
Correct answer: 1
The improper integral equals 1. The antiderivative of x21 is −x1; evaluating from 1 to b gives −b1+1, and as b→∞, −b1 approaches 0, leaving 1. This contrasts with the integral of x1, which diverges.
A particle's position is s(t)=t3−6t2+9t. At what time t>0 does the particle change direction for the first time?
t=3
t=1
t=2
t=0
Correct answer: t=1
The particle first changes direction at t=1. Velocity is s′(t)=3t2−12t+9=3(t−1)(t−3); the velocity changes sign at t=1, going from positive to negative. The other root t=3 is the second direction change, not the first.
What is the value of the integral ∫0π/2sin(x)cos(x)dx?
21
0
4π
1
Correct answer: 21
The integral equals 21. Using the substitution u=sin(x), du=cos(x)dx, the integral becomes ∫01udu=21. Alternatively, sin(x)cos(x)=21sin(2x), whose integral over this interval also gives 21.
Find the local minimum value of f(x)=x3−3x on its domain of all real numbers.
−2
−1
0
2
Correct answer: −2
The local minimum value is −2. Setting f′(x)=3x2−3=0 gives critical points x=1 and x=−1; the second derivative f′′(x)=6x is positive at x=1, indicating a local minimum, and f(1)=1−3=−2. The point x=−1 yields a local maximum value of 2.
What is the arc length of the curve y=32x3/2 from x=0 to x=3?
314
6
313
316
Correct answer: 314
The arc length is 314. The formula is ∫1+(y′)2dx; here y′=x1/2, so 1+(y′)2=1+x, and ∫031+xdx=32(1+x)3/2 evaluated from 0 to 3 equals 32(8−1)=314.
Evaluate limx→∞(1+x3)x.
3
e3
e
∞
Correct answer: e3
The limit equals e3. The standard limit limx→∞(1+xa)x=ea; here a=3, so the value is e3. This is the continuous-compounding form of the exponential limit definition.
What is the derivative of f(x)=arcsin(x)?
−1−x21
1+x21
x2−11
1−x21
Correct answer: 1−x21
The derivative of arcsin(x) is 1−x21. This is a standard inverse-trigonometric derivative valid on (−1,1). The expression 1+x21 is the derivative of arctan(x), a common point of confusion.
Using implicit differentiation, find dxdy for the curve x2+xy+y2=7 at a general point.
−2y2x+y
−x+2y2x+y
−2x+yx+2y
x+2y2x+y
Correct answer: −x+2y2x+y
The derivative is −x+2y2x+y. Differentiating implicitly gives 2x+y+xdxdy+2ydxdy=0; collecting dxdy terms yields (x+2y)dxdy=−(2x+y), so dxdy=−x+2y2x+y. The product rule on the xy term contributes both y and xdxdy.
What is the value of the integral ∫011+x21dx?
ln2
2π
4π
1
Correct answer: 4π
The integral equals 4π. The antiderivative of 1+x21 is arctan(x); evaluating from 0 to 1 gives arctan(1)−arctan(0)=4π−0=4π. This is a frequently used definite integral connecting calculus to the value of π.
For the function f(x,y)=x2−y2, classify the critical point at the origin using the second derivative test.
Saddle point
Inconclusive
Local maximum
Local minimum
Correct answer: Saddle point
The origin is a saddle point. The second-derivative (Hessian) test computes D=fxxfyy−(fxy)2=(2)(−2)−0=−4; a negative discriminant D indicates a saddle point regardless of the signs of the individual second partials. The function increases along the x-axis and decreases along the y-axis.
Evaluate limx→0+xln(x).
Does not exist
0
1
−∞
Correct answer: 0
The limit is 0. Rewriting xln(x) as 1/xln(x) gives the indeterminate form ∞−∞, and L'Hopital's rule differentiates to −1/x21/x=−x, which approaches 0. The product of a quantity approaching 0 and one approaching −∞ resolves to 0 here.
What is the average value of f(x)=x2 on the interval [0,3]?
4.5
9
3
6
Correct answer: 3
The average value is 3. The average value of a function on [a,b] is b−a1∫abf(x)dx; here it is 31∫03x2dx=31(9)=3. The integral itself equals 9, but the average requires dividing by the interval length.
Evaluate the integral over the region bounded by switching the order: ∫01∫y1ex2dxdy.
e−1
2e−1
2e2−1
21
Correct answer: 2e−1
The value is 2e−1. Because ex2 has no elementary antiderivative, reversing the order of integration to ∫01∫0xex2dydx gives ∫01xex2dx, which by substitution u=x2 equals 21(e−1). Recognizing when to switch the order is essential here.
What is the curvature of a circle of radius 5?
51
251
25
5
Correct answer: 51
The curvature of a circle of radius 5 is 51. Curvature is defined as the reciprocal of the radius of the osculating circle, so for a circle of radius r the curvature is constant and equals r1. A larger radius corresponds to a gentler bend and thus smaller curvature.
Using partial fractions, evaluate ∫x2−11dx.
21lnx+1x−1+C
ln∣x2−1∣+C
arctan(x)+C
21ln∣x2−1∣+C
Correct answer: 21lnx+1x−1+C
The antiderivative is 21lnx+1x−1+C. Decomposing x2−11 into x−11/2−x+11/2 and integrating each term gives 21ln∣x−1∣−21ln∣x+1∣, which combines into 21ln of the ratio. Partial fraction decomposition is the standard technique for rational integrands with factorable denominators.
Using Green's theorem, evaluate the counterclockwise line integral ∮−ydx+xdy around the circle x2+y2=4.
16π
4π
2π
8π
Correct answer: 8π
The line integral equals 8π. Green's theorem converts the boundary integral of Pdx+Qdy into the double integral of ∂x∂Q−∂y∂P over the enclosed region; with P=−y and Q=x, the integrand is 1−(−1)=2, so the value is 2 times the enclosed area. The disk of radius 2 has area 4π, giving 2×4π=8π. Forgetting the factor of 2 yields the tempting 4π.
Apply the limit comparison test to determine whether the series ∑n=1∞n3+n2n+1 converges.
The test is inconclusive
Converges, comparing with ∑n21
Converges, comparing with ∑n1
Diverges, comparing with ∑n1
Correct answer: Converges, comparing with ∑n21
The series converges by comparison with ∑n21. The limit comparison test takes the ratio of the term n3+n2n+1 to n21, which simplifies to n3+n2n3+n2 and approaches the finite positive limit 2. Because the comparison series ∑n21 converges as a p-series with p=2, the original series converges as well.
Determine whether the geometric series ∑n=0∞(32)n converges, and if so to what value.
Converges to 32
Diverges
Converges to 3
Converges to 23
Correct answer: Converges to 3
The geometric series converges to 3. A geometric series with first term a and common ratio r converges when ∣r∣<1, and its sum is 1−ra. Here a=1 (the n=0 term) and r=32, so the sum is 1−2/31=1/31=3. The value 23 mistakenly uses a ratio of 31 instead of 32.
Compute the determinant of the 3×3 matrix with rows (2,1,3), (0,4,1), and (5,2,1).
−51
51
−39
9
Correct answer: −51
The determinant equals −51. Expanding along the first row by cofactors: 2(4⋅1−1⋅2)−1(0⋅1−1⋅5)+3(0⋅2−4⋅5)=2(2)−1(−5)+3(−20)=4+5−60=−51. Each 2×2 minor must keep the sign pattern +−+ along the top row, and sign errors on the middle and right terms produce the positive distractors.
A 2×2 matrix has trace 7 and determinant 12. What are its eigenvalues?
−3 and −4
2 and 6
1 and 6
3 and 4
Correct answer: 3 and 4
The eigenvalues are 3 and 4. For a 2×2 matrix the eigenvalues are the roots of λ2−(trace)λ+(determinant)=λ2−7λ+12=(λ−3)(λ−4). The pair must sum to the trace (3+4=7) and multiply to the determinant (3⋅4=12); 2 and 6 multiply to 12 but sum to 8, so they fail the trace condition.
Find an eigenvector of the matrix with rows (4,1) and (2,3) corresponding to the eigenvalue 5.
(1,0)
(2,1)
(1,−2)
(1,1)
Correct answer: (1,1)
The vector (1,1) is an eigenvector for eigenvalue 5. Solving (A−5I)v=0 gives the equations −x+y=0 and 2x−2y=0, both requiring x=y, so any nonzero multiple of (1,1) works. Multiplying A by (1,1) gives (5,5)=5(1,1), confirming it.
Which statement correctly defines an eigenvalue of a square matrix A?
A vector v satisfying Av=0
Any entry on the main diagonal of A
A scalar λ such that Av=λv only when v is the zero vector
A scalar λ such that Av=λv for some nonzero vector v
Correct answer: A scalar λ such that Av=λv for some nonzero vector v
An eigenvalue is a scalar λ for which there exists a nonzero vector v with Av=λv. The nonzero requirement is essential, since Av=λv always holds trivially for v=0 and would make every scalar an eigenvalue. Diagonal entries are eigenvalues only for triangular matrices, not in general.
Which statement best describes an eigenvector of a matrix A?
The column of A with the largest entry
Any vector in the null space of A
A nonzero vector whose direction is unchanged (up to scaling) when multiplied by A
A vector orthogonal to every row of A
Correct answer: A nonzero vector whose direction is unchanged (up to scaling) when multiplied by A
An eigenvector is a nonzero vector v such that Av is a scalar multiple of v, meaning A only stretches or compresses it without changing its line of direction. Null-space vectors are the special case of eigenvalue 0, but a general eigenvector need not lie in the null space.
A linear map T from R5 to R4 has a matrix of rank 3. By the rank-nullity theorem, what is the dimension of the kernel of T?
2
5
3
1
Correct answer: 2
The kernel has dimension 2. The rank-nullity theorem states rank+nullity=dim(domain), so nullity=5−3=2. The domain is R5 (the source space), not the codomain R4, so the relevant dimension to subtract from is 5.
What is the rank of the matrix with rows (1,2,3), (2,4,6), and (1,1,1)?
1
0
3
2
Correct answer: 2
The rank is 2. The second row is exactly twice the first, so it contributes no new information, leaving the first and third rows, which are linearly independent (not scalar multiples of each other). Row reduction yields exactly two nonzero rows, so the rank is 2, not the full 3.
Which condition guarantees that an n×n matrix A is diagonalizable over the real numbers?
A is invertible
A has determinant equal to 1
A has trace equal to zero
A has n distinct real eigenvalues
Correct answer: A has n distinct real eigenvalues
Having n distinct real eigenvalues guarantees diagonalizability, because eigenvectors corresponding to distinct eigenvalues are linearly independent, producing a full set of n independent eigenvectors. Invertibility is unrelated to diagonalizability (a matrix can be invertible yet non-diagonalizable, like a Jordan block), and determinant or trace conditions say nothing about eigenvector independence.
Which set of vectors in R3 is linearly independent?
(1,1,0),(0,0,0),(0,1,1)
(1,2,3),(2,4,6),(0,0,1)
(1,2,1),(2,4,2),(3,6,3)
(1,0,0),(0,1,0),(1,1,1)
Correct answer: (1,0,0),(0,1,0),(1,1,1)
The set (1,0,0),(0,1,0),(1,1,1) is linearly independent because no vector is a linear combination of the others, and the 3×3 matrix they form has nonzero determinant 1. Any set containing the zero vector is automatically dependent, and the other rejected sets contain a vector that is a scalar multiple of another.
Which of the following is required for a set V to be a vector space over a field F?
V contains finitely many elements
Every nonzero element of V has a multiplicative inverse in V
V is closed under addition and under scalar multiplication by elements of F, with an additive identity and additive inverses
V is closed under multiplication of its elements
Correct answer: V is closed under addition and under scalar multiplication by elements of F, with an additive identity and additive inverses
A vector space must be closed under vector addition and scalar multiplication, contain a zero vector, and provide additive inverses, along with the usual associativity, commutativity, and distributivity axioms. Vector spaces are typically infinite, and there is no requirement that vectors multiply together or have multiplicative inverses, which distinguishes a vector space from a field.
For a linear transformation T from a vector space V to W, the image of T is best described as which of the following?
The set of all vectors w in W such that w=T(v) for some v in V
The set of all v in V with T(v)=0
The set of eigenvalues of T
A subspace of V
Correct answer: The set of all vectors w in W such that w=T(v) for some v in V
The image (range) of T is the set of all outputs w in W achievable as T(v) for some v in V, and it is a subspace of the codomain W. The set of v with T(v)=0 is the kernel, which lives in the domain V, so confusing image with kernel is the trap here.
Let T from R2 to R2 send (x,y) to (x+y,x−y). What is the matrix representation of T with respect to the standard basis?
Rows (1,1) and (1,−1)
Rows (1,1) and (−1,1)
Rows (1,−1) and (1,1)
Rows (1,0) and (0,−1)
Correct answer: Rows (1,1) and (1,−1)
The matrix has rows (1,1) and (1,−1). The columns of a standard-basis matrix are the images of the basis vectors: T(1,0)=(1,1) is the first column and T(0,1)=(1,−1) is the second column, giving the matrix whose rows read (1,1) and (1,−1). Swapping signs or transposing yields the distractors.
Which of the following is an example of an abelian group under the given operation?
The nonzero quaternions under multiplication
The set of 2×2 invertible real matrices under multiplication
The symmetric group S3 under composition
The integers under addition
Correct answer: The integers under addition
The integers under addition form an abelian group, since addition is commutative: a+b=b+a for all integers. The general linear group of 2×2 invertible matrices, the symmetric group S3, and the quaternions are all groups but are non-commutative (non-abelian), so they fail the defining abelian property.
By Lagrange's theorem, which statement about a subgroup H of a finite group G must be true?
The order of G divides the order of H
G must be cyclic
H must be a normal subgroup of G
The order of H divides the order of G
Correct answer: The order of H divides the order of G
Lagrange's theorem states that the order of any subgroup H divides the order of the group G, because the left cosets of H partition G into equal-sized blocks. This forces ∣H∣ to divide ∣G∣, not the reverse, and Lagrange's theorem says nothing about normality or whether G is cyclic.
A group G of order 14 acts on a finite set, and one element x has an orbit of size 7. By the orbit-stabilizer theorem, what is the order of the stabilizer of x?
7
1
14
2
Correct answer: 2
The stabilizer has order 2. The orbit-stabilizer theorem says ∣orbit∣×∣stabilizer∣=∣G∣, so ∣stabilizer∣=14/7=2. Equivalently, the size of an orbit equals the index of the stabilizer, so a stabilizer of index 7 in a group of order 14 has order 2.
A subgroup N of G is normal if and only if which condition holds for all g in G?
gN=Ng (the left and right cosets coincide)
N has exactly two elements
N is the trivial subgroup
g is in N
Correct answer: gN=Ng (the left and right cosets coincide)
N is normal exactly when its left and right cosets agree, gN=Ng for every g in G, equivalently gNg−1=N. This coset condition is what allows the quotient G/N to inherit a well-defined group operation. The other choices describe special cases or unrelated properties, not the defining condition.
If N is a normal subgroup of G with ∣G∣=24 and ∣N∣=8, what is the order of the quotient group G/N?
24
3
16
8
Correct answer: 3
The quotient group G/N has order 3. The order of a quotient is the index [G:N]=∣G∣/∣N∣=24/8=3, which counts the distinct cosets of N in G. Normality of N is exactly what makes the set of cosets into a group of this size.
What is the order of the element 4 in the additive group of integers modulo 6 (Z/6Z)?
3
2
4
6
Correct answer: 3
The order of 4 in Z/6Z is 3. The order is the smallest positive integer k with k⋅4≡0(mod6): 4,8(≡2),12(≡0), so adding 4 three times gives 0. Equivalently, the order equals 6 divided by gcd(4,6)=6/2=3.
What is the kernel of a group homomorphism ϕ from G to H?
The set of elements fixed by every automorphism of G
The center of G
The set of elements g in G with ϕ(g) equal to the identity of H
The image of ϕ inside H
Correct answer: The set of elements g in G with ϕ(g) equal to the identity of H
The kernel of ϕ is the set of all g in G that map to the identity element of H, and it is always a normal subgroup of G. By the first isomorphism theorem, G modulo this kernel is isomorphic to the image of ϕ. The image lives in H, not G, so confusing kernel with image is the trap.
How many groups of order 15 exist up to isomorphism?
2
1
4
3
Correct answer: 1
There is exactly one group of order 15 up to isomorphism, and it is cyclic. By the Sylow theorems, since 15=3⋅5, the number of Sylow 5-subgroups divides 3 and is congruent to 1 mod 5, forcing it to be 1, and likewise the Sylow 3-subgroup is unique; both normal subgroups give a direct product isomorphic to the cyclic group Z/15Z.
Which property must hold in an integral domain that need not hold in an arbitrary commutative ring with unity?
Addition is commutative
Every nonzero element has a multiplicative inverse
The ring contains a multiplicative identity
The product of two nonzero elements is nonzero
Correct answer: The product of two nonzero elements is nonzero
An integral domain is a commutative ring with unity that has no zero divisors, so a product of two nonzero elements is never zero. Requiring inverses for all nonzero elements would make it a field, a stronger condition; commutativity of addition and the existence of a unity already hold in any commutative ring with unity.
What distinguishes a field from a general commutative ring with unity in abstract algebra?
In a field, every nonzero element has a multiplicative inverse
A field cannot be finite
A field may have zero divisors
A field need not have a multiplicative identity
Correct answer: In a field, every nonzero element has a multiplicative inverse
A field is a commutative ring with unity in which every nonzero element has a multiplicative inverse, making the nonzero elements a group under multiplication. This forces a field to have no zero divisors, and finite fields such as the integers modulo a prime certainly exist, so the claim that fields cannot be finite is false.
Which condition must a nonempty subset I of a commutative ring R satisfy to be an ideal?
I contains the multiplicative identity of R
I is a field
I is closed under multiplication only
I is closed under addition and absorbs multiplication by every element of R
Correct answer: I is closed under addition and absorbs multiplication by every element of R
An ideal I must be an additive subgroup of R and must absorb products: for every r in R and a in I, the product r⋅a lies in I. This absorption property is precisely what lets the quotient ring R/I be well defined. Containing the unity would force I to equal all of R, so that is not a defining requirement.
Using Fermat's little theorem, what is the remainder when 3100 is divided by 7?
2
6
1
4
Correct answer: 4
The remainder is 4. Fermat's little theorem gives 36≡1(mod7) (since 7 is prime and does not divide 3). Writing 100=6⋅16+4, we get 3100≡34=81, and 81=7⋅11+4, so the remainder is 4.
Find the smallest positive integer x satisfying x≡2(mod3), x≡3(mod5), and x≡2(mod7).
23
53
68
8
Correct answer: 23
The smallest such x is 23, found via the Chinese remainder theorem. The first two congruences combine to x≡8(mod15); writing x=8+15k and imposing x≡2(mod7) gives 1+k≡2(mod7), so k=1 and x=23. Checking: 23=3⋅7+2, 23=5⋅4+3, 23=7⋅3+2.
What is the greatest common divisor of 252 and 198 computed via the Euclidean algorithm?
54
18
6
9
Correct answer: 18
The greatest common divisor is 18. The Euclidean algorithm gives 252=1⋅198+54, then 198=3⋅54+36, then 54=1⋅36+18, then 36=2⋅18+0; the last nonzero remainder, 18, is the gcd. Each step replaces the pair with the divisor and the remainder until the remainder is zero.
In modular arithmetic, what is 7×8 modulo 9?
2
6
1
5
Correct answer: 2
The result is 2. Compute 7⋅8=56, then reduce modulo 9: 56=9⋅6+2, so 56≡2(mod9). Equivalently, reduce first (7≡−2 and 8≡−1 modulo 9, giving (−2)(−1)=2), which confirms the answer.
The binomial coefficient C(n,k) counts the number of ways to choose k items from n without regard to order. What is the value of C(10,3)?
1024
720
30
120
Correct answer: 120
The value of C(10,3) is 120. The binomial coefficient is computed as n! divided by k!(n−k)!, which here gives 10!/(3!⋅7!)=(10⋅9⋅8)/(3⋅2⋅1)=720/6=120. The value 720 is the ordered count P(10,3)=10⋅9⋅8, which fails to divide out the 3! orderings of the chosen items.
In the binomial expansion of (x+y)6, what is the coefficient of the term x4y2?
15
12
6
30
Correct answer: 15
The coefficient of x4y2 is 15. By the binomial theorem, the coefficient of the term xn−kyk in (x+y)n is the binomial coefficient C(n,k). Here n=6 and k=2, so the coefficient is C(6,2)=6!/(2!⋅4!)=15. The answer 30 comes from forgetting to divide by 2! when computing the combination.
Using the symmetry identity of the binomial coefficient, which expression is always equal to C(n,k) for 0≤k≤n?
C(n−1,k)
C(n,n−k)
C(n,k−1)
C(k,n)
Correct answer: C(n,n−k)
The binomial coefficient satisfies C(n,k)=C(n,n−k). Choosing k items to include is equivalent to choosing the n−k items to exclude, so the two counts must be identical. This symmetry is why Pascal's triangle rows read the same forwards and backwards. The form C(k,n) equals zero for k<n and is not equal in general.
A continuous random variable X is uniformly distributed on the interval [0,4]. What is the variance of X?
2
316
32
34
Correct answer: 34
The variance is 34. For a uniform distribution on [a,b], the variance is (b−a)2/12. Here (4−0)2/12=16/12=34. The value 2 is the mean (a+b)/2, not the variance; confusing the two is a common error with the uniform probability distribution.
For a binomial probability distribution with n=10 trials and success probability p=0.3, what is the variance of the number of successes?
2.1
0.21
7.0
3.0
Correct answer: 2.1
The variance is 2.1. For a binomial distribution the variance equals n times p times (1−p), so 10⋅0.3⋅0.7=2.1. The value 3.0 is the mean np, not the variance. Knowing that the binomial mean is np while its variance is npq is a standard probability-distribution fact.
A Poisson random variable models the number of events in a fixed interval with mean rate λ=2. What is the probability of observing exactly zero events?
2e−2
e−2
1−e−2
e−1
Correct answer: e−2
The probability of zero events is e−2, approximately 0.135. The Poisson probability distribution gives P(X=k)=(λke−λ)/k!, so for k=0 this is (20e−2)/0!=e−2. The expression 2e−2 is P(X=1), not P(X=0).
How many nonnegative integer solutions are there to the equation a+b+c+d=10?
715
286
10000
210
Correct answer: 286
There are 286 solutions. This is a stars-and-bars problem: distributing 10 identical units among 4 variables corresponds to C(10+4−1,4−1)=C(13,3)=286. The stars-and-bars formula C(n+r−1,r−1) counts the ways to place r−1 dividers among n items. Treating the variables as distinct ordered objects gives the wrong count.
In how many distinguishable ways can the letters of the word MISSISSIPPI be arranged?
1663200
39916800
34650
11550
Correct answer: 34650
There are 34650 distinguishable arrangements. The word has 11 letters with repeats: 4 I's, 4 S's, 2 P's, and 1 M. The number of distinct permutations is 11! divided by the product 4!⋅4!⋅2!⋅1!, which equals 39916800/1152=34650. The value 39916800 is 11!, which wrongly treats every letter as unique.
In how many distinct ways can 6 people be seated around a circular table, where seatings that differ only by rotation are considered the same?
360
720
120
60
Correct answer: 120
There are 120 ways. For circular permutations of n distinct objects, fixing one person to remove rotational symmetry leaves (n−1)! arrangements of the rest, giving 5!=120. The value 720 is 6!, the count for a straight line, which overcounts each circular arrangement 6 times by treating all rotations as different.
Three events A, B, and C in a sample space are pairwise mutually exclusive. By the inclusion-exclusion principle, the probability of their union P(A∪B∪C) equals which expression?
P(A)P(B)P(C)
P(A)+P(B)+P(C)
P(A)+P(B)+P(C)−P(A)P(B)P(C)
1−P(A)−P(B)−P(C)
Correct answer: P(A)+P(B)+P(C)
For pairwise mutually exclusive events the union probability is simply P(A)+P(B)+P(C). Inclusion-exclusion subtracts pairwise intersection probabilities, but mutual exclusivity makes every intersection empty with probability zero, so all correction terms vanish. The product form would apply to independence of a joint event, not to a union of disjoint events.
Two events A and B satisfy P(A)=0.6, P(B)=0.5, and P(A∩B)=0.3. Are A and B independent, and what is the basis for the conclusion?
Dependent, because P(A∩B) is not zero
Independent, because P(A)+P(B)>1
Independent, because P(A∩B)=P(A)P(B)
Dependent, because P(A)>P(B)
Correct answer: Independent, because P(A∩B)=P(A)P(B)
The events are independent because P(A∩B)=P(A)P(B). Independence is defined by the multiplication rule: here P(A)P(B)=0.6⋅0.5=0.3, which matches the given joint probability exactly. Independence is unrelated to mutual exclusivity; disjoint events with positive probabilities are in fact dependent, so a nonzero intersection does not by itself imply dependence.
A factory has two machines producing identical parts: machine A makes 70% of parts with a 2% defect rate, and machine B makes 30% with a 5% defect rate. A randomly chosen part is defective. By Bayes' theorem, what is the probability it came from machine B?
About 0.30
About 0.52
About 0.62
About 0.39
Correct answer: About 0.52
The probability is about 0.52. By Bayes' theorem, P(B∣defective)=P(defective∣B)P(B)/P(defective). The total defect probability is 0.7(0.02)+0.3(0.05)=0.014+0.015=0.029. Then P(B∣defective)=0.015/0.029=0.517. The prior 0.30 ignores that machine B's higher defect rate raises the posterior once a defect is observed.
A standard fair die is rolled once. What is the variance of the outcome?
2.92
3.50
6.00
1.71
Correct answer: 2.92
The variance is approximately 2.92, exactly 1235. The variance is E[X2] minus (E[X])2. The mean is 3.5, and E[X2]=(1+4+9+16+25+36)/6=91/6=15.1667, so the variance is 15.1667−12.25=2.9167. The value 3.5 is the mean, not the variance.
A game pays 10 dollars if a fair coin lands heads and costs you 4 dollars if it lands tails. What is the expected net value of playing once?
6 dollars
3 dollars
5 dollars
7 dollars
Correct answer: 3 dollars
The expected value is 3 dollars. Expected value weights each outcome by its probability: (1/2)(+10)+(1/2)(−4)=5−2=3. The answer 7 incorrectly averages the magnitudes 10 and 4 instead of accounting for the sign of the loss. A positive expected value means the game favors the player.
In a metric space, the closure of a set A is defined as the smallest closed set containing A. What is the closure of the open interval (0,1) in the real line with the standard metric?
[0,1)
[0,1]
(0,1)
(0,1]
Correct answer: [0,1]
The closure of (0,1) is the closed interval [0,1]. The closure adds all limit points of the set; the endpoints 0 and 1 are limit points of (0,1) even though they are not members, so they are included. The result [0,1] is the smallest closed set containing the original interval. Leaving out either endpoint would not be closed.
In the real line with the standard topology, which of the following sets is closed but not open?
The whole real line R
The empty set
The open interval (1,4)
The closed interval [1,4]
Correct answer: The closed interval [1,4]
The closed interval [1,4] is closed but not open. It contains all its limit points (so it is closed), yet its endpoints have no surrounding open interval lying entirely inside the set (so it is not open). The empty set and all of R are both open and closed (clopen), and (1,4) is open but not closed.
Which subset of the real line R with the usual topology is compact, by the Heine-Borel characterization?
The interval [5,∞)
The set {2,4,6} of three points
The interval (3,7]
The set of rationals in [0,2]
Correct answer: The set {2,4,6} of three points
The finite set {2,4,6} is compact. By the Heine-Borel theorem a subset of R is compact exactly when it is closed and bounded; a finite set of points is automatically both. The half-open interval (3,7] is not closed, the ray [5,∞) is not bounded, and the rationals in [0,2] are not closed because their limits can be irrational.
A key property of compactness in topology is that the continuous image of a compact set is compact. If f is a continuous real-valued function and K is a compact subset of its domain, what can be concluded about f(K)?
f(K) is a single point
f(K) is closed and bounded
f(K) is connected but possibly unbounded
f(K) is open
Correct answer: f(K) is closed and bounded
The image f(K) is closed and bounded. Continuity preserves compactness, so f(K) is compact, and in the real line compactness is equivalent to being closed and bounded by Heine-Borel. This is precisely why a continuous function on a compact interval attains its maximum and minimum. Connectedness is preserved separately and does not guarantee boundedness on its own.
In topology, a space is connected if it cannot be written as the union of two disjoint nonempty open sets. Which property is preserved under a continuous function?
A continuous image of a connected set is always finite
A continuous image of a connected set is connected
A continuous image of a connected set is always open
A continuous image of a connected set is always closed
Correct answer: A continuous image of a connected set is connected
The continuous image of a connected set is connected. If the image could be split into two disjoint nonempty open pieces, their preimages would split the connected domain the same way, a contradiction. This is exactly the topological generalization of the Intermediate Value Theorem, where the connected interval maps to a connected (interval) image.
Which subset of the plane R2 with the standard topology is connected?
The set of points with integer coordinates
The complement of a closed disk's boundary circle
A single straight line through the origin
Two disjoint closed disks
Correct answer: A single straight line through the origin
A single straight line through the origin is connected; it is a continuous image of the connected real line and cannot be separated into two disjoint nonempty open pieces. Two disjoint disks form an obviously disconnected set, the integer lattice is a discrete set of isolated points, and removing a circle splits the plane into a disconnected inside-and-outside.
On the set of real numbers, define d(x,y)=0 if x=y and d(x,y)=1 if x is not equal to y. This is the discrete metric. Under this metric, which statement is true?
No single point is an open set
Every subset is open
The metric violates the triangle inequality
Distances can exceed 1
Correct answer: Every subset is open
Under the discrete metric every subset is open. Each point x is contained in the open ball of radius 21, which contains only x itself, so every singleton is open; since arbitrary unions of open sets are open, every subset is open. The discrete metric does satisfy all metric axioms including the triangle inequality, and its distances never exceed 1.
The complex cube roots of 8 lie equally spaced on a circle in the complex plane. What is the radius of that circle (the modulus of each root)?
8
4
8
2
Correct answer: 2
The modulus of each 38 is 2. The n-th roots of a complex number with modulus r all have modulus r1/n; here r=8 and n=3, so the modulus is 81/3=2. The three roots are 2, and 2 times the two primitive cube roots of unity, all sitting on a circle of radius 2 and spaced 120 degrees apart. The value 8 ignores taking the modulus's cube root 38.
Newton's method is applied to find a root of f(x)=x2−2 starting from x0=1. Using the update xn+1=xn−f(xn)/f′(xn), what is the first iterate x1?
1.4142
1.5
2.0
1.25
Correct answer: 1.5
The first iterate is 1.5. Newton's method uses x1=x0−f(x0)/f′(x0), where f′(x)=2x. At x0=1, f(1)=−1 and f′(1)=2, so x1=1−(−1)/2=1+0.5=1.5. The value 1.4142 is the true root 2, which the iteration only approaches after further steps rather than reaching at x1.
Find the volume of the solid generated by revolving the region bounded by y=x, y=0, and x=4 about the x-axis.
8π
4π
16π
316π
Correct answer: 8π
Correct answer: 8π. Using the disk method, the volume is V=π∫04(x)2dx=π∫04xdx=π[2x2]04=π⋅8=8π.
Using the quotient rule, what is the derivative of f(x)=x−1x2+1?
12x
(x−1)2x2−2x−1
(x−1)2x2+2x−1
(x−1)22x(x−1)+(x2+1)
Correct answer: (x−1)2x2−2x−1
Correct answer: (x−1)2x2−2x−1. The quotient rule gives f′(x)=(x−1)2(2x)(x−1)−(x2+1)(1)=(x−1)22x2−2x−x2−1=(x−1)2x2−2x−1.
At what x-value does the curve y=x3−6x2+5 have an inflection point?
x=4
x=0
x=2
x=3
Correct answer: x=2
Correct answer: x=2. An inflection point occurs where the second derivative changes sign. Here y′=3x2−12x and y′′=6x−12; setting y′′=0 gives 6x−12=0, so x=2, and the concavity changes there.
For which values of p does the p-series ∑n=1∞np1 converge?
p≥1
p>1
p<1
All real p
Correct answer: p>1
Correct answer: p>1. The p-series ∑1/np converges precisely when p>1 and diverges when p≤1; for example p=1 gives the divergent harmonic series.
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Click Start Test above to launch a full-length GRE Math practice test weighted exactly like the real GRE Mathematics Subject Test, or drill a single area — Calculus, Algebra, or Additional Topics. Every question includes a clear explanation so you learn the reasoning, not just the answer.
The GRE Mathematics Subject Test is a graduate-admissions exam administered by Educational Testing Service (ETS) and is one of the surviving GRE Subject Tests, alongside Physics and Psychology.
[1]It is a separate exam from the GRE General Test’s Quantitative Reasoning section: the Subject Test assesses advanced undergraduate mathematics, while Quantitative Reasoning covers high-school-level math.
These free GRE Math practice questions mirror the official content distribution so you practice the way the real exam is built.[3] To round out your prep, pair these with our free study guide, flashcards.
GRE Math at a Glance
GRE Mathematics Subject Test at a glance
Detail
GRE Mathematics Subject Test
Administering body
Educational Testing Service (ETS)
Questions
Approximately 66 multiple-choice questions
Question type
Multiple choice
Time limit
2 hours, 50 minutes
Format
Computer-delivered
Scaled score range
200 to 990 (no pass/fail)
Test dates
Offered in September, October, and April
Fee
About $175 (verify current fee with ETS)
What Is on the GRE Math Test?
The GRE Mathematics Subject Test covers three content areas: Calculus (about 50%), Algebra (about 25%), and Additional Topics (about 25%).[1]
Calculus is the largest area, spanning single- and multivariable calculus, sequences and series, and applications. Algebra covers elementary, linear, and abstract algebra plus number theory, and Additional Topics covers real analysis, discrete mathematics, probability and statistics, and numerical analysis. Our full practice test is weighted to match:
GRE Math weighting by content area
Calculus50% · ≈33 Qs
Algebra25% · ≈17 Qs
Additional Topics25% · ≈16 Qs
Practice Questions by Topic
Use Start Test for a full weighted GRE Math simulation, or open the hub and pick a single area to drill your weak spot. After each full exam, your results show a per-area breakdown so you know exactly where to focus — most candidates need the most reps on calculus, since it is half the test.
Who Takes the GRE Math Test?
There are no formal eligibility requirements to take the GRE Mathematics Subject Test — it is open to anyone, though it is intended for applicants to graduate programs in mathematics and related quantitative fields.[2] The test assumes mastery of undergraduate-level mathematics, so candidates are typically advanced undergraduates or graduates. Check each program you apply to, since some require the Mathematics Subject Test, some recommend it, and others do not use it at all.
How Do You Register for the GRE Math Test?
You register for the GRE Mathematics Subject Test online through your ETS account at ets.org: create an account, register for the test, pay the fee (about $175, which includes sending scores to up to four programs — verify the current fee), and schedule your computer-delivered appointment on one of the available test dates, typically in September, October, and April.[4]
Review the current ETS information bulletin and the official Practice Book for Mathematics for logistics and ID requirements before you register.
How Is the GRE Math Test Scored?
The GRE Mathematics Subject Test is scored on a single scaled score from 200 to 990 in 10-point increments, along with a percentile rank, and there is no pass or fail.[5]
Your raw score is the number of questions answered correctly (there is no penalty for wrong answers), converted to the scaled score through ETS’s equating process so scores are comparable across editions. Because this is a graduate-admissions exam, programs set their own expectations and interpret your scaled score and percentile in context.
How Hard Is the GRE Math Test?
The GRE Mathematics Subject Test is demanding: it packs the full sweep of undergraduate mathematics into roughly 66 questions in 170 minutes, rewarding both broad coverage and quick, accurate problem solving under time pressure.[3]
The difficulty comes from the breadth of advanced topics and the pace rather than any single concept. Because there is no pass/fail threshold, the meaningful benchmark is the score range of admitted students at your target programs.
200–990
Scaled score range
no pass/fail
~66
Questions
in 2 hr 50 min
50%
Calculus
largest content area
The takeaway: drill until you’re consistently fast and accurate on full-length practice — especially calculus and your weaker areas in analysis and abstract algebra — before you book your test date.
What to Expect on Exam Day
Arrive at your test center early to check in — bring a valid, unexpired government-issued photo ID whose name matches your ETS registration.[4] The Mathematics Subject Test is computer-delivered, with approximately 66 multiple-choice questions and a 2-hour, 50-minute time limit.
There is no penalty for wrong answers, so pace yourself and answer every question. ETS converts your raw score to the 200–990 scaled score and reports it with a percentile rank; there is no pass or fail. Having simulated the full timing with practice tests makes that clock feel routine.
How to Use This GRE Math Practice Test
Recreate exam conditions. Take the full test timed, with no notes.[3]
Diagnose, then drill. Use a full simulation to find weak areas, then drill them.
Prioritize calculus. It’s half the test and the biggest score-mover.
Learn the why. Read every explanation — understanding beats memorizing.
Answer everything. There’s no guessing penalty, so never leave a question blank.
Why Take the GRE Math Subject Test?
A strong Mathematics Subject Test score signals advanced mathematical preparation to graduate-admissions committees and can strengthen applications to competitive mathematics and quantitative programs.[2] These free GRE Math practice tests are the most efficient way to build that readiness.
Conclusion
Doing well on the GRE Mathematics Subject Test comes down to broad coverage of calculus, algebra, and additional topics, plus speed under pressure. Use this free GRE Math practice test to find your weak areas, drill them to mastery, and reinforce them with our study guide, flashcards so you walk in confident on test day.
GRE Math Practice Test FAQ
The GRE Mathematics Subject Test is a graduate-admissions exam administered by Educational Testing Service (ETS) that assesses advanced undergraduate mathematics. It is one of the surviving GRE Subject Tests, alongside Physics and Psychology, and is used by graduate programs in mathematics and related quantitative fields.
No. The Mathematics Subject Test is a separate exam that covers advanced undergraduate math — calculus, algebra, and additional topics. GRE Quantitative Reasoning is a section of the GRE General Test that covers high-school-level math. They are different tests with different purposes.
Yes. ETS still offers the Mathematics Subject Test as a computer-delivered exam, typically on multiple dates in September, October, and April. Physics and Psychology are the other surviving GRE Subject Tests.
The GRE Mathematics Subject Test has approximately 66 multiple-choice questions with a time limit of 2 hours and 50 minutes. There is no penalty for wrong answers, so it is to your advantage to answer every question.
Content is drawn from three areas: Calculus (about 50%), Algebra (about 25%), and Additional Topics (about 25%) such as real analysis, discrete mathematics, probability and statistics, and numerical analysis. These weights come from the official ETS content distribution.
Scores are reported on a scaled range of 200 to 990 in 10-point increments, plus a percentile rank. Your raw number of correct answers is converted to the scaled score through ETS equating so scores are comparable across editions. There is no pass or fail.
A good GRE Mathematics Subject Test score is one that is competitive for the programs you are applying to, since it is an admissions test with no passing threshold. Strong applicants to top mathematics programs aim for high percentile scores, so use admitted-student score ranges as your benchmark.
Review across all three content areas with an emphasis on calculus, practice timed problem sets to build speed, and shore up weaker areas like real analysis and abstract algebra. Use the official ETS Practice Book for Mathematics and a realistic practice test like this one to find weak spots before test day.
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