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AP Precalculus Practice Questions
A polynomial function f has a local maximum at x=−2 and a local minimum at x=5, with no other extrema. What is the minimum possible degree of f?
Degree 2
Degree 3
Degree 5
Degree 4
Correct answer: Degree 3
Degree 3 is correct. Two turning points require at least degree 3, because a degree-n polynomial has at most n−1 turning points, and 3−1=2. A quadratic allows only one turning point, so degree 2 is too small.
Using the rational zeros test, which value is a possible rational zero of f(x)=2x3+3x−4?
x=3
x=5
x=31
x=21
Correct answer: x=21
x=21 is correct. The rational zeros theorem says any rational zero is a factor of the constant term 4 over a factor of the leading coefficient 2, giving candidates like ±1,2,4,21. The value 21 fits this list, while 31 and 5 do not because 3 and 5 are not factors of 2 or 4.
When f(x)=x3−4x2+x+6 is divided by (x−3) using synthetic division, what is the remainder?
−3
9
0
6
Correct answer: 0
The remainder is 0. Evaluating f(3)=27−36+3+6=0, and by the remainder theorem this equals the synthetic division remainder. A remainder of zero also confirms that (x−3) is a factor.
A rational function r(x)=x2+1x2−4 has how many vertical asymptotes?
Zero
Two
One
Three
Correct answer: Zero
Zero is correct. Vertical asymptotes occur where the denominator equals zero for real inputs, but x2+1=0 has no real solutions since x2 is never negative. Therefore the function has no vertical asymptotes even though the numerator has real zeros.
The function f(x)=x−1x2+2x−3 can be simplified for x=1. What is the simplified form?
x−1
x+3
x−3
x+1
Correct answer: x+3
x+3 is correct. The numerator factors as (x+3)(x−1), and canceling the common (x−1) leaves x+3, valid everywhere except x=1 where a hole occurs. Choosing the wrong factor pair would give an incorrect simplification.
For the rational function f(x)=x−23x2−5, polynomial long division gives a slant asymptote. What is that line?
y=3x+6
y=3x
y=3x−6
y=x+2
Correct answer: y=3x+6
y=3x+6 is correct. Dividing 3x2−5 by x−2 yields a quotient of 3x+6 with a nonzero remainder, and the slant asymptote is exactly that linear quotient. The remainder term shrinks to zero for large inputs, so the graph approaches this line.
What is the value of the polynomial p(x)=x4−2x2 at x=−1?
3
1
−3
−1
Correct answer: −1
p(−1)=−1. Substituting gives (−1)4−2(−1)2=1−2×1=1−2=−1. Both even powers make the negative input positive before the subtraction.
A rational function f(x)=x2−16x+4 has a hole rather than an asymptote at which input?
x=−4
x=16
x=4
x=0
Correct answer: x=−4
x=−4 is correct. The denominator factors as (x−4)(x+4), so the (x+4) factor cancels with the numerator, leaving a removable discontinuity at x=−4. The factor (x−4) does not cancel, so x=4 is a genuine vertical asymptote.
Descartes' rule of signs is applied to f(x)=x3−x2+x−1. How many sign changes appear in f(x)?
Three
Two
Zero
One
Correct answer: Three
Three is correct. Reading the coefficient signs of x3−x2+x−1 gives plus, minus, plus, minus, which switches sign three times. This count gives the maximum number of positive real zeros under Descartes' rule.
The graph of a polynomial passes through (0,0), (1,0), and (−1,0), each a simple crossing. Which is the lowest-degree polynomial consistent with this?
f(x)=x(x−1)2
f(x)=x(x−1)(x+1)
f(x)=x2(x−1)
f(x)=(x−1)(x+1)
Correct answer: f(x)=x(x−1)(x+1)
f(x)=x(x−1)(x+1) is correct. Three simple crossings at 0, 1, and -1 require the three distinct factors x, (x−1), and (x+1), each to the first power for crossing behavior. Repeated factors would cause a bounce, and dropping a factor would miss a required zero.
For f(x)=x2, what is the difference quotient hf(x+h)−f(x) simplified?
2x+h
x+h
2xh
2x
Correct answer: 2x+h
2x+h is correct. Expanding f(x+h)=x2+2xh+h2 and subtracting x2 leaves 2xh+h2, and dividing by h gives 2x+h. This expression represents the average rate of change over an interval of width h.
A rational function has the equation f(x)=x2−12x2. What is its horizontal asymptote?
y=0
There is none
y=1
y=2
Correct answer: y=2
y=2 is correct. The numerator and denominator both have degree 2, so the horizontal asymptote is the ratio of leading coefficients, 12=2. Equal degrees rule out an asymptote of y=0, which requires a smaller numerator degree.
If a polynomial f has f(2)=0 and f(−3)=0, which product must divide f(x)?
(x+2)(x−3)
(x+2)(x+3)
(x−2)(x+3)
(x−2)(x−3)
Correct answer: (x−2)(x+3)
(x−2)(x+3) is correct. By the factor theorem, a zero at x=2 gives the factor (x−2) and a zero at x=−3 gives the factor (x+3), so their product divides f. The other choices place the zeros at the wrong values.
A polynomial model for the volume of an open box is V(x)=x(10−2x)(8−2x), where x is the cutout length. What is the domain that makes physical sense?
0<x<4
x>5
All real numbers
0<x<8
Correct answer: 0<x<4
0<x<4 is correct. The cutout x must be positive, and each side length 10−2x and 8−2x must stay positive, requiring x<5 and x<4 respectively. The tighter restriction x<4 controls, so the meaningful domain is 0<x<4.
What is the leading term of the product (3x2)(x3−2x)?
−6x3
x5
3x5
3x6
Correct answer: 3x5
3x5 is correct. Multiplying the highest-degree terms 3x2 and x3 gives 3×x2+3=3x5, which dominates end behavior. The term −6x3 is a lower-degree product, not the leading term.
The graph of a rational function flattens toward y=0 on both ends but spikes to infinity near x=4. Which description fits?
Slant asymptote and a hole at x=4
Two horizontal asymptotes
No asymptotes at all
Horizontal asymptote y=0 and a vertical asymptote at x=4
Correct answer: Horizontal asymptote y=0 and a vertical asymptote at x=4
Horizontal asymptote y=0 with a vertical asymptote at x=4 is correct. Flattening toward zero on both ends indicates the horizontal asymptote y=0, and the unbounded spike near x=4 marks a vertical asymptote there. A hole would not cause the output to spike to infinity.
A degree 4 polynomial with positive leading coefficient has exactly two real zeros, both simple. How many times does its graph touch but not cross the x-axis?
Two times
One time
Zero times
Four times
Correct answer: Zero times
Zero times is correct. Both real zeros are simple, meaning odd multiplicity, so the graph crosses at each rather than touching and turning. Touching without crossing requires even multiplicity, which is not present here.
When two polynomials of degrees 3 and 2 are added, what is the degree of the resulting polynomial?
2
3
5
6
Correct answer: 3
Degree 3 is correct. Adding polynomials keeps the highest degree present, and since 3 is larger than 2, the sum has degree 3 as long as the degree-3 term is not canceled. Degrees are multiplied, not added, only when multiplying polynomials.
A rational function f(x)=x2+1x3 has what type of end behavior asymptote?
A horizontal asymptote y=0
A horizontal asymptote y=1
A slant asymptote y=x
No asymptote
Correct answer: A slant asymptote y=x
A slant asymptote y=x is correct. The numerator degree 3 is exactly one more than the denominator degree 2, so division gives a linear quotient of y=x that the graph approaches. A horizontal asymptote would require the degrees to be equal or the numerator degree to be smaller.
The polynomial f(x)=6x2−13x+6 factors completely as which product?
(2x−3)(3x−2)
(2x−3)(3x+2)
(6x−1)(x−6)
(2x+3)(3x+2)
Correct answer: (2x−3)(3x−2)
(2x−3)(3x−2) is correct. Expanding gives 6x2−4x−9x+6=6x2−13x+6, matching the original. Both constants are negative to produce the positive constant 6 and negative middle term.
A polynomial p(x) is divided by (x+2) and leaves a nonzero remainder of −5. What is p(−2)?
5
0
2
−5
Correct answer: −5
p(−2)=−5. The remainder theorem states the remainder upon division by (x+2), which is (x−(−2)), equals p(−2). Since that remainder is −5, p(−2)=−5, and a nonzero remainder confirms (x+2) is not a factor.
A polynomial function is even and has a zero at x=3. Which other value must also be a zero?
x=0
x=−3
x=31
x=6
Correct answer: x=−3
x=−3 is correct. An even function satisfies f(−x)=f(x), so f(−3)=f(3)=0, forcing a matching zero at x=−3. The symmetry of even functions pairs zeros at opposite inputs.
For the function f(x)=x2+4x+45, what is the location and nature of the discontinuity?
A hole at x=−2
A vertical asymptote at x=−2
A vertical asymptote at x=2
No discontinuity
Correct answer: A vertical asymptote at x=−2
A vertical asymptote at x=−2 is correct. The denominator factors as (x+2)2, which is zero at x=−2, and since the numerator 5 is nonzero there, the function blows up to infinity, giving a vertical asymptote. There is no canceling factor, so it is not a hole.
A polynomial of degree 7 with real coefficients has 3 distinct non-real zeros listed. Why is this impossible?
All zeros of a degree 7 polynomial are real
A polynomial cannot have distinct zeros
Degree 7 polynomials have no complex zeros
Non-real zeros must come in conjugate pairs, so the count must be even
Correct answer: Non-real zeros must come in conjugate pairs, so the count must be even
Conjugate pairs require an even count, which is correct. For real-coefficient polynomials, each non-real zero is paired with its conjugate, so non-real zeros always total an even number. Three is odd, making the listed situation impossible.
A polynomial passes through the point (0,−8) and has no other information given. What is its constant term?
−8
Cannot be determined
0
8
Correct answer: −8
The constant term is −8. The y-intercept of a polynomial equals its constant term, found by evaluating at x=0, and the point (0,−8) gives f(0)=−8 directly. So the constant term must be −8.
The graph of f(x)=x3−x is rewritten in factored form. Which factorization is correct?
x(x2+1)
x2(x−1)
(x−1)(x+1)
x(x−1)(x+1)
Correct answer: x(x−1)(x+1)
x(x−1)(x+1) is correct. Factoring out x gives x(x2−1), and the difference of squares x2−1 factors into (x−1)(x+1). This reveals three simple real zeros at 0, 1, and -1.
A rational function model for drug concentration is C(t)=t2+950t. As t increases without bound, what does C approach?
9
0
Infinity
50
Correct answer: 0
C approaches 0. The denominator degree 2 exceeds the numerator degree 1, so the horizontal asymptote is y=0 and concentration tends toward zero for large times. This models a drug clearing from the system over time.
What is the standard form expansion of (x−4)(x+1)?
x2+3x−4
x2−5x−4
x2−3x−4
x2−4x+1
Correct answer: x2−3x−4
x2−3x−4 is correct. Multiplying gives x2+x−4x−4, and combining the middle terms yields x2−3x−4. The constant −4 comes from multiplying −4 by 1.
A function f is concave down on (−∞,1) and concave up on (1,∞). What occurs at x=1?
A point of inflection
A removable discontinuity
A vertical asymptote
A relative maximum
Correct answer: A point of inflection
A point of inflection is correct. Concavity changing from down to up at x=1 defines an inflection point, where the bending direction of the graph reverses. This is unrelated to extrema or to asymptotes, which involve direction changes or undefined behavior instead.
A rational function r(x)=x2−9x−3 is simplified. What is the simplified form and excluded value besides x=−3?
x−31, with x=3
x−3, with no restriction
x+31, with x=3
(x+3), with x=3
Correct answer: x+31, with x=3
x+31 with x=3 is correct. The denominator factors as (x−3)(x+3), and canceling the common (x−3) leaves x+31, creating a hole at x=3. The remaining factor (x+3) still gives a vertical asymptote at x=−3.
A degree 3 polynomial has end behavior falling on the left and rising on the right. What is true about its leading coefficient?
It cannot be determined from end behavior
It is zero
It is negative
It is positive
Correct answer: It is positive
Positive is correct. An odd-degree polynomial that falls on the left and rises on the right matches a positive leading coefficient, the same pattern as the basic cubic. A negative leading coefficient would reverse the ends to rise on the left and fall on the right.
Which polynomial has exactly the zeros x=0 (multiplicity 1), x=2 (multiplicity 2), and degree 3?
f(x)=x(x−2)
f(x)=x(x−2)2
f(x)=x(x+2)2
f(x)=x2(x−2)
Correct answer: f(x)=x(x−2)2
f(x)=x(x−2)2 is correct. The factor x gives a simple zero at 0, and (x−2)2 gives a double zero at 2, and the total degree 1+2=3 matches. The other forms misplace the multiplicities or the zero locations.
The average rate of change of f(x)=x3 over the interval from x=0 to x=2 is what value?
8
2
4
6
Correct answer: 4
The answer is 4. The average rate of change is 2−0f(2)−f(0)=28−0=4. Forgetting to divide by the interval width of 2 would incorrectly give 8.
A rational function has numerator (x2+1), which has no real zeros, and denominator (x−2). What does the lack of real numerator zeros tell you about the graph?
The graph has no x-intercepts
The graph has a hole at x=2
The graph has two x-intercepts
The graph has no vertical asymptote
Correct answer: The graph has no x-intercepts
No x-intercepts is correct. An x-intercept requires the numerator to be zero for a real input, but x2+1 is never zero for real x, so the graph never crosses the x-axis. The denominator zero at x=2 still produces a vertical asymptote.
When dividing f(x)=2x2+3x−2 by (x+2), what is the quotient?
2x+1
x−1
2x−1
2x−2
Correct answer: 2x−1
2x−1 is correct. Since f(−2)=8−6−2=0, (x+2) is a factor, and dividing gives the quotient 2x−1 because (x+2)(2x−1)=2x2+3x−2. The product check confirms the quotient.
A polynomial model of profit P(x)=−2(x−30)(x−70) describes profit by number of units x. At which x values is profit zero?
x=0 and x=100
x=−30 and x=−70
x=2 and x=50
x=30 and x=70
Correct answer: x=30 and x=70
x=30 and x=70 is correct. Setting each factor equal to zero gives x=30 and x=70, the break-even points where profit equals zero. The leading factor −2 affects the height of the parabola but not the locations of these zeros.
The reciprocal-squared function f(x)=x21 has what end behavior and sign?
It approaches y=1 on both ends
It approaches y=0 from above on both ends
It grows without bound on both ends
It approaches y=0 from below on both ends
Correct answer: It approaches y=0 from above on both ends
Approaching y=0 from above is correct. Squaring keeps the denominator positive for all nonzero inputs, so outputs stay positive, and for large magnitude inputs x21 shrinks toward zero. Thus the graph nears the horizontal asymptote y=0 from above on both sides.
A polynomial f has a graph that crosses the x-axis at x=−2, bounces at x=1, and crosses at x=4. What is the smallest possible degree?
5
4
2
3
Correct answer: 4
Degree 4 is correct. Crossing at -2 and 4 each requires odd multiplicity (at least 1 each), and bouncing at 1 requires even multiplicity (at least 2), giving a minimum total of 1+2+1=4. A lower degree could not provide the bounce plus two crossings.
A polynomial g(x)=(x2+5) has what kind of real zeros?
One real zero
Three real zeros
Two real zeros
No real zeros
Correct answer: No real zeros
No real zeros is correct. Setting x2+5=0 gives x2=−5, which has no real solution since a square is never negative. The zeros of this expression are non-real complex numbers, so the graph never touches the x-axis.
A polynomial f has zeros at x=−2, x=0, and x=3, each of multiplicity 1, and a positive leading coefficient with degree 3. What is the sign of f(x) on the interval between x=0 and x=3?
Positive throughout the interval
Negative throughout the interval
Zero throughout the interval
Positive then negative within the interval
Correct answer: Negative throughout the interval
Negative throughout is correct. With simple zeros at -2, 0, and 3 and a positive leading coefficient, the cubic is positive for x>3, then alternates sign at each crossing, making it negative on (0,3). A single-multiplicity zero produces one sign change, so the function does not switch sign again inside the interval.
A polynomial g(x) is the product (x−1)(x+4)(x−1). Which statement correctly describes its behavior at x=1?
The graph crosses the x-axis steeply at x=1
The graph touches the x-axis at x=1 and turns back
The graph has a vertical asymptote at x=1
The graph has a hole at x=1
Correct answer: The graph touches the x-axis at x=1 and turns back
Touching and turning is correct. The factor (x−1) appears twice, giving x=1 a multiplicity of 2, which is even, so the graph touches the axis there and reverses without crossing. Holes and asymptotes are rational-function features, not polynomial-zero behavior.
For the rational function f(x)=x2+x−6x+3, at which input is there a removable discontinuity?
x=2
x=−3
x=−2
x=6
Correct answer: x=−3
x=−3 is correct. The denominator factors as (x+3)(x−2), so the numerator (x+3) cancels with one denominator factor, removing the discontinuity at x=−3 and leaving a hole there. The remaining (x−2) factor does not cancel, so x=2 is a vertical asymptote, not a hole.
Which polynomial has end behavior in which both ends rise and exactly two distinct real zeros?
f(x)=−(x−1)(x+1)
f(x)=(x−1)2(x+1)2
f(x)=(x−1)(x+1)(x−2)
f(x)=−(x−1)2(x+1)2
Correct answer: f(x)=(x−1)2(x+1)2
The fourth-degree product (x−1)2(x+1)2 is correct. Its degree is 4 (even) with a positive leading coefficient, so both ends rise, and it has exactly two distinct real zeros at 1 and -1 (each multiplicity 2). The negative versions send both ends down, and the cubic has opposite end behaviors.
A rational function h(x)=x+2x2−4 is simplified. What is the resulting expression and its restriction?
x−2, with x=−2
x+2, with x=2
x−2, with no restriction
x+2, with x=−2
Correct answer: x−2, with x=−2
x−2 with x=−2 is correct. The numerator is a difference of squares, (x−2)(x+2); canceling the common (x+2) leaves x−2. The original function is undefined at x=−2, so that input is excluded, leaving a hole there.
A polynomial of degree 4 has a positive leading coefficient. What is the maximum number of times its graph can intersect a horizontal line?
2
4
3
5
Correct answer: 4
Four is correct. Setting the polynomial equal to a constant gives another degree-4 equation, which can have at most 4 real solutions, so the graph can meet any horizontal line at most 4 times. The count cannot exceed the degree.
Given f(x)=3x2 and the table values f(1)=3, f(2)=12, f(3)=27, what are the first differences of the outputs over these equally spaced inputs?
3 and 12
9 and 15
6 and 6
12 and 27
Correct answer: 9 and 15
9 and 15 is correct. The first differences subtract consecutive outputs: 12−3=9 and 27−12=15. These are not constant, which is expected for a quadratic, whose second differences (15−9=6) are the constant ones instead.
A rational function r(x) has a numerator of degree 2 and a denominator of degree 5. Which describes its end behavior?
It approaches a slant asymptote
It increases without bound on both ends
It approaches the horizontal asymptote y=0
It has no asymptotes
Correct answer: It approaches the horizontal asymptote y=0
Approaching y=0 is correct. Because the denominator degree (5) exceeds the numerator degree (2), the denominator dominates for large inputs and the outputs shrink toward zero. A slant asymptote would require the numerator degree to exceed the denominator degree by exactly one.
A polynomial p(x) yields p(−1)=0. Which factor must appear in its factored form?
(x−1)
(x+1)
(x+0)
(1−x)
Correct answer: (x+1)
(x+1) is correct. By the Factor Theorem, a zero at x=c corresponds to the factor (x−c); here c=−1, so the factor is (x−(−1))=(x+1). The factor (x−1) would correspond to a zero at x=1 instead.
The graph of a function rises to a peak, falls to a valley, rises to another peak, and then falls. What is the minimum polynomial degree consistent with this shape?
Degree 3
Degree 4
Degree 2
Degree 5
Correct answer: Degree 4
Degree 4 is correct. The described shape has three turning points (peak, valley, peak), and a degree-n polynomial allows at most n−1 turning points, so three turning points require at least degree 4. A cubic permits only two turning points.
Which expression is a fully factored polynomial with a zero of multiplicity 3 at x=4 and no other real zeros?
(x−4)3
(x+4)3
(x−4)2
(x−4)(x2+1)
Correct answer: (x−4)3
(x−4)3 is correct. The factor (x−4) raised to the third power gives a single real zero at x=4 with multiplicity 3 and no other real zeros. The version with (x+4) places the zero at -4, and the squared form has multiplicity 2.
For f(x)=x2−9x−3, what feature occurs at x=3?
A vertical asymptote
An x-intercept
A horizontal asymptote
A hole
Correct answer: A hole
A hole is correct. The denominator factors as (x−3)(x+3), and the (x−3) in the numerator cancels with one in the denominator, removing the discontinuity at x=3 and leaving a hole. The remaining (x+3) factor produces a vertical asymptote at x=−3 instead.
A polynomial model f(t) gives the height of a drone in meters at time t seconds. If f has a relative minimum at (6,10), what does this mean in context?
The drone is highest at 6 seconds
The drone reaches a local low of 10 meters at 6 seconds before rising again
The drone is on the ground at 6 seconds
The drone descends forever after 6 seconds
Correct answer: The drone reaches a local low of 10 meters at 6 seconds before rising again
A local low of 10 meters at 6 seconds is correct. A relative minimum is a point where the output is smaller than at nearby inputs, so the drone dips to 10 meters at 6 seconds and then climbs. It is not the overall lowest point nor ground level unless the height there were zero.
Which statement about the graph of an odd-degree polynomial with a negative leading coefficient is correct?
The left end falls and the right end rises
Both ends fall
Both ends rise
The left end rises and the right end falls
Correct answer: The left end rises and the right end falls
Left rises and right falls is correct. Odd degree gives opposite end behaviors, and a negative leading coefficient makes the right end fall while the left end rises. Both ends going the same way would require an even degree.
A rational function f(x)=2x2+34x2−1 has what horizontal asymptote?
y=4
y=0
y=2
There is no horizontal asymptote
Correct answer: y=2
y=2 is correct. The numerator and denominator both have degree 2, so the horizontal asymptote is the ratio of leading coefficients, 24=2. A value of y=0 would require the numerator degree to be smaller than the denominator degree.
If a polynomial has the factored form f(x)=(x−5)(x+2)3, what is the total degree of f?
5
3
4
2
Correct answer: 4
Degree 4 is correct. The total degree is the sum of the exponents on the factors: (x−5) contributes 1 and (x+2)3 contributes 3, giving 1+3=4. The degree counts multiplicities, not just the number of distinct factors.
A polynomial passes through (0,−6) and has the form f(x)=a(x−1)(x+3). What is the value of a?
2
-2
6
-6
Correct answer: 2
a=2 is correct. Substituting x=0 gives f(0)=a(0−1)(0+3)=a×(−1)×3=−3a, and setting this equal to -6 yields −3a=−6, so a=2. The other values do not satisfy the point.
The graph of a rational function has vertical asymptotes at x=−1 and x=4. Which denominator is consistent with this?
(x−1)(x+4)
(x+1)(x−4)
(x+1)(x+4)
(x−1)(x−4)
Correct answer: (x+1)(x−4)
(x+1)(x−4) is correct. Vertical asymptotes occur where the denominator is zero and does not cancel; setting (x+1)=0 gives x=−1 and (x−4)=0 gives x=4, matching the asymptotes. The other denominators place the zeros at the wrong values.
A polynomial f satisfies f(2)=5 and f(6)=13. What is its average rate of change on the interval from x=2 to x=6?
8
4
2
3
Correct answer: 2
The average rate of change is 2. It equals 6−2f(6)−f(2)=413−5=48=2. Forgetting to divide by the interval width of 4 would give the incorrect value of 8.
Which describes the relationship between the factors of a polynomial and the x-intercepts where the graph crosses versus touches the axis?
Even-multiplicity factors cause crossing; odd-multiplicity factors cause touching
Odd-multiplicity factors cause crossing; even-multiplicity factors cause touching
All factors cause the graph to cross
All factors cause the graph to touch and turn
Correct answer: Odd-multiplicity factors cause crossing; even-multiplicity factors cause touching
Odd causes crossing and even causes touching is correct. A factor with odd multiplicity makes the graph pass through the axis, while a factor with even multiplicity makes it touch and turn back. The behavior depends on whether the multiplicity is odd or even.
A rational function f(x)=x−2x2+1 has numerator degree one more than denominator degree. What type of asymptote does it have besides the vertical one?
A horizontal asymptote at y=1
A slant asymptote
A second vertical asymptote
No additional asymptote
Correct answer: A slant asymptote
A slant asymptote is correct. Since the numerator degree (2) exceeds the denominator degree (1) by exactly one, dividing gives a linear quotient that the graph approaches, producing a slant asymptote. There is no horizontal asymptote when the numerator degree is larger.
If a polynomial of degree 7 has 5 distinct real zeros and one of them has multiplicity 3 while the rest are simple, how many non-real zeros does it have, counted with multiplicity?
0
2
4
1
Correct answer: 0
Zero non-real zeros is correct. The real zeros account for 3 (from the triple) plus 4 simple zeros =7 total with multiplicity, which equals the degree. Since all 7 zeros are real, none are non-real.
The function f(x)=x3 is transformed into g(x)=21×x3. How does this affect the graph?
A vertical compression by a factor of 21
A horizontal stretch by a factor of 21
A vertical stretch by a factor of 2
A reflection over the x-axis
Correct answer: A vertical compression by a factor of 21
A vertical compression by 21 is correct. Multiplying the output by a constant between 0 and 1 shrinks every y-value toward the x-axis, compressing the graph vertically. A factor greater than 1 would stretch it instead, and a negative factor would add a reflection.
A polynomial model for a company's monthly profit has a y-intercept of -8 (in thousands of dollars). What does this represent in context?
The break-even production level
The maximum monthly profit
The profit when no units are produced, an 8 thousand dollar loss
The number of units that maximize profit
Correct answer: The profit when no units are produced, an 8 thousand dollar loss
An 8 thousand dollar loss at zero production is correct. The y-intercept is the output when the input is zero, so it gives the profit when no units are made, here a loss of 8 thousand dollars from fixed costs. Break-even points are zeros, not the y-intercept.
Which polynomial is written in standard form?
f(x)=3+2x2−x
f(x)=−x+3+2x2
f(x)=2x2−x+3
f(x)=2x2+3−x
Correct answer: f(x)=2x2−x+3
2x2−x+3 is correct. Standard form lists terms in order of decreasing exponent, here the squared term, then the linear term, then the constant. The other expressions contain the same terms but are not arranged from highest to lowest degree.
A rational function f(x)=x2+26 has what kind of vertical asymptotes?
One vertical asymptote at x=0
No vertical asymptotes
Two vertical asymptotes
A vertical asymptote at x=2
Correct answer: No vertical asymptotes
No vertical asymptotes is correct. The denominator x2+2 is always at least 2 and never equals zero for any real input, so the function is defined everywhere and has no vertical asymptotes. Vertical asymptotes require real zeros of the denominator.
Two equally spaced data sets are compared. Set A has constant first differences and Set B has constant second differences. Which polynomial degrees do they suggest?
Set A linear, Set B quadratic
Set A quadratic, Set B linear
Set A cubic, Set B quadratic
Both linear
Correct answer: Set A linear, Set B quadratic
Set A linear and Set B quadratic is correct. Constant first differences indicate a degree-1 (linear) pattern, and constant second differences indicate a degree-2 (quadratic) pattern. The order of differences that becomes constant matches the polynomial degree.
The polynomial f(x)=−(x+1)(x−2)(x−5) is evaluated for very large negative x. What is the end behavior on the left?
Rising on the left is correct. Expanding gives a leading term of −x3 (odd degree, negative leading coefficient), so the left end rises while the right end falls. For very large negative x, the negative coefficient times a large negative cube yields large positive outputs.
A polynomial graph touches the x-axis at x=0, crosses at x=3, and touches at x=−4. What is the minimum possible degree?
3
5
4
6
Correct answer: 5
Degree 5 is correct. Touching at x=0 requires multiplicity at least 2, crossing at x=3 requires multiplicity at least 1, and touching at x=−4 requires multiplicity at least 2, summing to 2+1+2=5. This is the smallest total degree consistent with the described behavior.
Which transformation of f(x)=x2 produces a parabola with vertex at (3,−1) that opens upward?
g(x)=(x−3)2−1
g(x)=(x+3)2−1
g(x)=(x−3)2+1
g(x)=−(x−3)2−1
Correct answer: g(x)=(x−3)2−1
g(x)=(x−3)2−1 is correct. The (x−3) shifts the vertex right to x=3, and the minus 1 shifts it down to y=−1, while the positive coefficient keeps it opening upward. The negative version would open downward, and (x+3) would move the vertex left.
A rational function f(x)=x−23x has what horizontal asymptote?
y=3
y=0
y=2
There is no horizontal asymptote
Correct answer: y=3
y=3 is correct. The numerator and denominator both have degree 1, so the horizontal asymptote is the ratio of leading coefficients, 13=3. The function levels off toward y=3 for large magnitude inputs.
If a polynomial has real coefficients and exactly the zeros 2, 2i, and −2i, what is its minimum possible degree?
2
1
4
3
Correct answer: 3
Degree 3 is correct. The real zero 2 contributes one factor, and the non-real zeros 2i and −2i form a conjugate pair contributing two more, giving a minimum of 1+2=3. Conjugate pairs are required because the coefficients are real.
A polynomial f is decreasing on the interval (1,5). What can be said about its average rate of change over that interval?
It is positive
It is zero
It is negative
It cannot be determined
Correct answer: It is negative
Negative is correct. If a function is decreasing across an entire interval, its output at the right endpoint is lower than at the left endpoint, so the net change is negative and the average rate of change is negative. A decreasing function cannot have a positive average rate of change over the interval.
Which polynomial has a graph that is symmetric about the origin?
f(x)=x3−4x
f(x)=x2+1
f(x)=x3+2
f(x)=x4
Correct answer: f(x)=x3−4x
f(x)=x3−4x is correct. Both terms have odd exponents and there is no constant term, so the function is odd and its graph is symmetric about the origin. The other options contain even-power terms or a nonzero constant, which break origin symmetry.
A rational function f(x)=(x+2)(x−4)(x−1)(x+2) is graphed. Which features appear at x=−2 and x=4 respectively?
Vertical asymptote at -2 and hole at 4
Hole at -2 and vertical asymptote at 4
Holes at both -2 and 4
Vertical asymptotes at both -2 and 4
Correct answer: Hole at -2 and vertical asymptote at 4
Hole at -2 and vertical asymptote at 4 is correct. The factor (x+2) cancels between numerator and denominator, producing a hole at x=−2, while the non-canceling (x−4) leaves the denominator zero at x=4, producing a vertical asymptote there.
A polynomial model for the volume of a box is V(x)=x(10−2x)(8−2x), where x is the height. For what positive inputs is the volume model physically meaningful (positive volume)?
0<x<4
0<x<5
x>5
All positive x
Correct answer: 0<x<4
0<x<4 is correct. Volume must be positive, which requires all three factors positive: x>0, 10−2x>0 (so x<5), and 8−2x>0 (so x<4). The most restrictive bound gives 0<x<4, where every dimension is positive.
What is the result of dividing the polynomial x2−x−6 by (x−3)?
x+2
x−2
x+3
x−6
Correct answer: x+2
x+2 is correct. The dividend factors as (x−3)(x+2), so dividing by (x−3) leaves the quotient x+2 with no remainder. This also confirms that x=3 is a zero of the original polynomial.
A polynomial of even degree has a positive leading coefficient and a negative value at its lowest turning point. How many real zeros must it have at minimum?
Exactly 1
At least 2
Exactly 0
Exactly the degree
Correct answer: At least 2
At least 2 is correct. With both ends rising (positive even-degree) and a turning point dipping below the x-axis, the graph must cross the axis on the way down and again on the way back up, giving at least two real zeros. An even-degree polynomial that dips below zero cannot have zero real zeros.
The reciprocal-squared function f(x)=x21 differs from f(x)=x1 in which way near its vertical asymptote at x=0?
x21 goes to positive infinity on both sides, while x1 goes to opposite infinities
Both go to negative infinity on both sides
x21 goes to opposite infinities on each side
Both behave identically near zero
Correct answer: x21 goes to positive infinity on both sides, while x1 goes to opposite infinities
x21 rising on both sides is correct. Squaring the denominator keeps outputs positive near zero, so x21 tends to positive infinity from both sides, whereas x1 is positive on one side and negative on the other, giving opposite infinities. The even power changes the sign behavior near the asymptote.
A polynomial p(x) has p(0)=4 and is known to be even. Which point must also lie on its graph?
(−4,0)
(4,0)
There is not enough information
(0,−4)
Correct answer: There is not enough information
Not enough information is correct. Knowing p(0)=4 fixes only the single point (0,4), and evenness gives symmetry about the y-axis but does not by itself determine the output at any other specific input. No additional point can be guaranteed from the y-intercept and symmetry alone.
Which expression is the complete factorization of x3−8?
(x−2)(x2+2x+4)
(x−2)(x2−2x+4)
(x−2)(x2−4)
(x+2)(x2−2x+4)
Correct answer: (x−2)(x2+2x+4)
The factorization (x−2)(x2+2x+4) is correct. As a difference of cubes, x3−23 factors into (x−2) times the quadratic x2+2x+4, using the pattern a3−b3=(a−b)(a2+ab+b2). The choice with a plus sign in the linear factor or the wrong sign in the quadratic does not match the difference-of-cubes pattern.
When the polynomial p(x)=x3−2x2+x−5 is divided by (x−2), what is the remainder?
5
0
-3
-5
Correct answer: -3
The remainder is -3. By the Remainder Theorem the remainder equals p(2), and substituting gives 8 minus 8 plus 2 minus 5 = -3. Computing p(2) directly avoids carrying out the full division, and the nonzero result confirms that (x−2) is not a factor.
A polynomial with real coefficients has degree 4 and zeros at x=1, x=1, and x=2i. What is its remaining zero?
x=1
x=−2i
x=2
x=−1
Correct answer: x=−2i
The remaining zero is x=−2i. A degree-4 polynomial has four zeros counted with multiplicity, and three are accounted for by the double zero at x=1 and the single zero at x=2i. Because real coefficients force non-real zeros into conjugate pairs, the partner of 2i must be its conjugate −2i.
Algebraically, which test confirms that f(x)=x3−4x is an odd function?
Showing f(−x)=f(x) for all x
Showing f(−x)=−f(x), since f(−x)=−x3+4x=−(x3−4x)
Showing every exponent is even
Showing f(0)=0
Correct answer: Showing f(−x)=−f(x), since f(−x)=−x3+4x=−(x3−4x)
Showing f(−x)=−f(x) is correct. Substituting −x gives (−x)3 minus 4(−x)=−x3 plus 4x, which is exactly the opposite of the original f(x)=x3−4x, confirming the function is odd. The condition f(−x)=f(x) would instead define an even function, and f(0)=0 alone does not establish odd symmetry.
For f(x)=x2+x, the average rate of change on [0,2] compared to the average rate of change on [2,4] is which of the following?
Smaller, because the function is concave up
Larger, because the function is concave up
Equal, because the function is a polynomial
Smaller, because the function is concave down
Correct answer: Smaller, because the function is concave up
Smaller is correct. On [0,2] the rate equals [6 minus 0] over 2 = 3, while on [2,4] it equals [20 minus 6] over 2 = 7, so the earlier interval has the smaller rate. This rising sequence of average rates of change is the hallmark of a concave up graph.
What are the coordinates of the vertex of the quadratic f(x)=(x−4)2−9?
(−4,−9)
(4,9)
(4,−9)
(−4,9)
Correct answer: (4,−9)
The vertex is (4,−9). In vertex form a(x−h)2+k, the vertex is the point (h,k); here h=4 and k=−9. The subtraction inside the squared term means the horizontal coordinate is positive 4, not -4, which the incorrect choices reverse.
The graph of g(x)=x−31+2 is the reciprocal function f(x)=x1 transformed how?
Shifted left 3 and down 2, with asymptotes x=−3 and y=−2
Shifted right 3 and up 2, with asymptotes x=3 and y=2
Shifted right 2 and up 3, with asymptotes x=2 and y=3
Shifted left 3 and up 2, with asymptotes x=−3 and y=2
Correct answer: Shifted right 3 and up 2, with asymptotes x=3 and y=2
Right 3 and up 2 is correct. Replacing x with x−3 moves the graph right 3, sending the vertical asymptote to x=3, and adding 2 outside moves it up 2, sending the horizontal asymptote to y=2. The inside subtraction shifts the graph in the positive x-direction, so a leftward shift does not apply.
In the factored polynomial f(x)=(x+1)(x−2)(x−2)(x+1), what is the multiplicity of the zero at x=2 and how does the graph behave there?
Multiplicity 1; the graph crosses the x-axis
Multiplicity 4; the graph crosses the x-axis
Multiplicity 3; the graph flattens and crosses
Multiplicity 2; the graph touches the x-axis and turns around
Correct answer: Multiplicity 2; the graph touches the x-axis and turns around
Multiplicity 2 with a touch-and-turn is correct. The factor (x−2) appears twice, giving the zero at x=2 a multiplicity of 2, and an even multiplicity causes the graph to touch the x-axis and bounce back without crossing. The factor (x+1) also appears twice but governs the separate zero at x=−1.
What is the value of log636?
6
2
3
12
Correct answer: 2
The value is 2. The expression asks for the power to which 6 must be raised to produce 36, and since 62 equals 36, the answer is 2. The other choices do not satisfy 6 raised to that power equaling 36.
What is the value of log281?
-3
3
-8
31
Correct answer: -3
The value is -3. Since one-eighth equals 2−3, the logarithm returns that exponent, giving -3. A positive answer would correspond to a value greater than 1, not a fraction less than 1.
An exponential function passes through (2,18) and (3,54). What is its base?
2
6
3
9
Correct answer: 3
The base is 3. The base equals the ratio of consecutive outputs over a unit increase in input, so 54 divided by 18 gives 3. The base is not the difference of the outputs or either output value itself.
Solve for x: 5x=125.
x=25
x=5
x=4
x=3
Correct answer: x=3
x=3 is correct. Rewriting 125 as 53 makes the bases match, so the exponents are equal and x equals 3. Dividing or taking a root does not isolate the exponent here.
Solve for x: 32x=81.
x=2
x=4
x=8
x=3
Correct answer: x=2
x=2 is correct. Since 81 equals 34, the exponents must be equal, so 2x equals 4 and x equals 2. Forgetting to divide by the coefficient of x would give the incorrect value 4.
What is the value of log93?
21
3
2
31
Correct answer: 21
The value is one-half. Since 9 raised to the one-half power equals 9, which is 3, the logarithm equals one-half. A whole-number answer would require 3 to be a whole-number power of 9, which it is not.
Rewrite the exponential statement 43=64 in logarithmic form.
log364=4
log464=3
log644=3
log43=64
Correct answer: log464=3
log464=3 is correct. The base of the power becomes the base of the logarithm, the result becomes the argument, and the exponent becomes the logarithm's value. The other forms swap the roles of these parts incorrectly.
What is the value of eln5?
ln5
1
5
E
Correct answer: 5
The value is 5. Because the natural exponential and natural logarithm are inverse functions, raising e to the natural log of a number returns that number, so the result is 5. The two functions undo each other entirely.
What is the value of ln(e4)?
4
1
E
e4
Correct answer: 4
The value is 4. Since the natural logarithm is the inverse of the natural exponential, taking ln of e to a power returns that exponent, giving 4. The base and exponent are not multiplied together.
Which transformation does g(x)=3×2x apply to f(x)=2x?
A horizontal shift right by 3
A vertical shift up by 3
A reflection over the y-axis
A vertical stretch by a factor of 3
Correct answer: A vertical stretch by a factor of 3
A vertical stretch by a factor of 3 is correct. Multiplying the entire function by 3 scales every output by 3, stretching the graph vertically away from the x-axis. A shift would require adding a constant, not multiplying.
Which transformation does g(x)=2−x apply to f(x)=2x?
A reflection over the x-axis
A vertical shift down
A reflection over the y-axis
A horizontal stretch
Correct answer: A reflection over the y-axis
A reflection over the y-axis is correct. Replacing x with negative x flips the graph horizontally across the y-axis, turning a growth curve into a decay curve. Negating the entire output, not the input, would instead reflect over the x-axis.
Expand logb(yx)3 using the properties of logarithms.
3(logbx−logby)
logbx−3logby
3logbx−logby
3(logbx×logby)
Correct answer: 3(logbx−logby)
3(logbx−logby) is correct. The outer exponent 3 moves out front by the power property, and the quotient inside becomes a difference of logarithms that the 3 distributes across. The coefficient must apply to both terms, not just one.
Condense into a single logarithm: logb8+2logbx.
logb(8+x2)
logb(16x)
logb(8x2)
logb(8×2x)
Correct answer: logb(8x2)
logb(8x2) is correct. The coefficient 2 becomes an exponent on x, and adding two logarithms combines them into the logarithm of a product, giving 8 times x2. Adding the arguments instead of multiplying them is invalid.
What is the value of log82?
31
3
4
41
Correct answer: 31
The value is one-third. Since 8 raised to the one-third power is 38, which equals 2, the logarithm equals one-third. A whole-number answer would require 2 to be a whole-number power of 8.
A bacteria culture follows N(t)=400×3t, where t is in hours. How many bacteria are present at t=2 hours?
2400
1200
3600
1800
Correct answer: 3600
The value is 3600. Substituting t=2 gives 400 times 32, which is 400 times 9, equal to 3600. Multiplying the initial value by the base only once would incorrectly give the one-hour value.
Express the change of base for log520 using natural logarithms.
ln5ln20
ln20×ln5
ln20ln5
ln20−ln5
Correct answer: ln5ln20
ln5ln20 is correct. The change of base formula places the logarithm of the argument over the logarithm of the original base, both in the new base, so it is ln 20 over ln 5. Reversing the ratio would compute a different logarithm.
What is the y-intercept of f(x)=7×(21)x?
21
0
1
7
Correct answer: 7
The y-intercept is 7. Evaluating at x=0 gives 7 times a base raised to the zero power, which is 7 times 1, so the graph crosses the y-axis at 7. The base does not affect the y-intercept because any base to the zero power is 1.
Solve for x: 2x+1=32.
x=4
x=6
x=5
x=16
Correct answer: x=4
x=4 is correct. Since 32 equals 25, the exponents must match, so x plus 1 equals 5 and x equals 4. Forgetting to subtract 1 from 5 would give the incorrect value 5.
If a quantity is multiplied by 4 every time the input increases by 1, what is the base of the exponential model?
41
0
4
1
Correct answer: 4
The base is 4. The base of an exponential function is the constant factor applied for each unit increase in the input, which is 4 here. A base less than 1 would indicate decay rather than this growth by a factor of 4.
Which value satisfies logx49=2?
x=24.5
x=49
x=7
x=14
Correct answer: x=7
x=7 is correct. Rewriting in exponential form gives x2 equals 49, so x equals 7 since the base must be positive. The base, not the argument, is what is being solved for here.
A loan balance is modeled by B(t)=10000×(1.05)t. What is the annual growth rate?
5 percent
1.05 percent
50 percent
105 percent
Correct answer: 5 percent
The annual growth rate is 5 percent. The base 1.05 equals 1 plus 0.05, so the rate of increase each year is 0.05, or 5 percent. The base itself is the growth factor, not the rate.
What is the value of log10010?
2
21
10
101
Correct answer: 21
The value is one-half. Since 100 raised to the one-half power is 100, which equals 10, the logarithm equals one-half. A value of 2 would instead describe log base 10 of 100.
An exponential decay function has the form f(x)=a⋅bx. Which describes the typical relationship between consecutive outputs?
Each output is a constant amount less than the previous
Each output equals the previous output
Each output is a fixed fraction of the previous output
Each output is the previous
Correct answer: Each output is a fixed fraction of the previous output
A fixed fraction of the previous output is correct. With a base between 0 and 1, multiplying by that base each step makes each output a constant fraction of the one before it. A constant subtracted amount would describe linear decay instead.
Solve for x: log5(2x)=2.
x=5
x=12.5
x=10
x=25
Correct answer: x=12.5
x=12.5 is correct. Converting to exponential form gives 52 equals 2x, so 25 equals 2x and x equals 12.5. Forgetting to divide by the coefficient 2 would leave the incorrect value 25.
Which statement correctly compares the steepness of f(x)=2x and g(x)=5x for positive x?
Both rise at exactly the same rate
Neither rises for positive x
G rises more steeply than f because its base is larger
F rises more steeply than g because its base is smaller
Correct answer: G rises more steeply than f because its base is larger
g rises more steeply is correct. A larger base multiplies each output by a bigger factor per unit, so the function with base 5 climbs faster than the one with base 2 for positive inputs. A smaller base produces gentler growth, not steeper.
What is the value of log4161?
-2
-4
2
21
Correct answer: -2
The value is -2. Since one-sixteenth equals 4−2, the logarithm returns that exponent, giving -2. Arguments less than 1 produce negative logarithms when the base is greater than 1.
A model gives the temperature of a cooling object as T(t)=20+60×(0.8)t. What value does the temperature approach as t grows large?
0
60
80
20
Correct answer: 20
The temperature approaches 20. As t grows, the term 60 times 0.8t decays toward zero, leaving the constant 20, which is the horizontal asymptote of the model. The constant added outside the exponential sets this long-run value.
Which expression is equivalent to logb(x)?
2logbx
xlogbx
(logbx)2
21logbx
Correct answer: 21logbx
21logbx is correct. A square root is the one-half power, and the power property moves that exponent out front as a coefficient of one-half. Treating the root as a multiplier of 2 would reverse the operation.
What is the value of log21+log216?
16
5
0
4
Correct answer: 4
The value is 4. The logarithm of 1 is 0 in any base, and log216 is 4 since 24 equals 16, so the sum is 0 plus 4, equal to 4. The first term contributes nothing because the log of 1 is always zero.
Solve for x: e2x=e6.
x=6
x=12
x=4
x=3
Correct answer: x=3
x=3 is correct. With equal bases of e, the exponents must be equal, so 2x equals 6 and x equals 3. Forgetting to divide the right side by 2 would give the incorrect value 6.
A savings account earns interest so that the balance triples every 4 years, modeled by A=P×3t/4. What does the divisor 4 represent?
The initial deposit
The number of years for the balance to triple
The annual interest rate
The final balance
Correct answer: The number of years for the balance to triple
The tripling time is correct. The divisor 4 in the exponent means the base 3 is fully applied once every 4 years, so 4 is the time required for the balance to triple. The divisor sets the length of each tripling period.
Which is the correct exponential form of the statement ln(7)=k?
e7=k
10k=7
ke=7
ek=7
Correct answer: ek=7
ek=7 is correct. The natural logarithm uses base e, so ln(7)=k converts to e raised to the k power equaling 7. Using base 10 would describe the common logarithm, not the natural one.
What is the value of log553?
125
3
15
5
Correct answer: 3
The value is 3. Because the logarithm and exponential share the base 5 and are inverses, log553 returns the exponent 3. The base and exponent are not multiplied to give 15.
A drug's concentration in the blood follows C(t)=50×(0.5)t/6 milligrams. What is the half-life of the drug?
50 hours
6 hours
0.5 hours
12 hours
Correct answer: 6 hours
The half-life is 6 hours. With base one-half and exponent t/6, the concentration is multiplied by one-half once every 6 hours, so the half-life is 6 hours. The divisor in the exponent sets this halving period.
Which property allows ln(a×b) to be rewritten?
lna×lnb
lna+lnb
lnblna
lna−lnb
Correct answer: lna+lnb
lna+lnb is correct. The product property of logarithms applies to natural logarithms as well, so the log of a product is the sum of the logs. Multiplying or dividing the logarithms is not a valid identity.
For the function f(x)=a⋅bx, what does the parameter b control?
The y-intercept of the graph
The location of the vertical asymptote
The horizontal asymptote
Whether the function grows or decays and how quickly
Correct answer: Whether the function grows or decays and how quickly
Controlling growth or decay and its rate is correct. The base b determines if outputs increase or decrease and the speed of that change, since it is the per-step multiplier. The initial value a sets the y-intercept, a separate feature.
What is the value of 4log49?
36
4
2
9
Correct answer: 9
The value is 9. Raising a base to the logarithm of a number in that same base returns the number, since the two operations are inverses, so the result is 9. The base and argument are not multiplied together.
Solve for x: log6x=0.
x=6
x=1
x=0
x=66
Correct answer: x=1
x=1 is correct. Converting to exponential form gives 60=x, and any nonzero base to the zero power is 1, so x=1. The logarithm of 1 is 0 in every base.
If f(x)=bx has a base b between 0 and 1, what is the end behavior as x increases without bound?
The outputs increase without bound
The outputs approach 0
The outputs approach 1
The outputs become negative
Correct answer: The outputs approach 0
Approaching 0 is correct. A base between 0 and 1 means repeated multiplication by a fraction, so the positive outputs shrink toward the asymptote y=0 as x grows. The outputs stay positive because a positive base to any power is positive.
An arithmetic sequence has first term 7 and common difference 4. What is the explicit formula for its nth term?
an=7+4(n−1)
an=7×4n−1
an=4+7(n−1)
an=7+4n
Correct answer: an=7+4(n−1)
The formula an=7+4(n−1) is correct. An arithmetic sequence's nth term is the first term plus the common difference times one less than the term number, here 7+4(n−1). Using a multiplicative factor would describe a geometric sequence instead.
A geometric sequence has first term 5 and common ratio 3. What is its explicit formula for the nth term?
an=5+3(n−1)
an=5×3n−1
an=3×5n−1
an=5×3n
Correct answer: an=5×3n−1
The formula an=5×3n−1 is correct. A geometric sequence's nth term is the first term times the common ratio raised to one less than the term number. Adding the ratio instead would give an arithmetic sequence.
An arithmetic sequence corresponds to which type of function when the term number is the input?
An exponential function
A linear function
A quadratic function
A logarithmic function
Correct answer: A linear function
A linear function is correct. Because an arithmetic sequence adds a constant common difference each step, its terms change by a constant additive amount, matching the constant slope of a linear function. A constant multiplicative change would correspond to an exponential function.
The fourth term of a geometric sequence is 54 and the common ratio is 3. What is the first term?
2
6
18
3
Correct answer: 2
The first term is 2. The fourth term equals the first term times the ratio cubed, so 54 equals first term times 27, giving a first term of 2. Dividing 54 by 27 isolates the first term.
For the exponential function f(x)=7×(41)x, by what factor does the output change each time x increases by 1?
It is multiplied by 41
It is multiplied by 7
It decreases by 4
It is multiplied by 4
Correct answer: It is multiplied by 41
Multiplying by 41 is correct. The base of an exponential function is the factor applied for each unit increase in the input, here 41. The coefficient 7 is the initial value, not the per-step factor.
If an exponential function has a growth factor of 1.5 per unit, what is the equivalent percent rate of change per unit?
A 50 percent increase
A 150 percent increase
A 1.5 percent increase
A 15 percent increase
Correct answer: A 50 percent increase
A 50 percent increase is correct. A growth factor of 1.5 equals 1 plus 0.50, so the quantity grows by 50 percent each unit. The factor 1.5 itself is not the percent; the percent comes from the part beyond 1.
An exponential function f satisfies f(0)=6 and has a constant ratio of 2 per unit increase in x. What is f(3)?
48
12
36
24
Correct answer: 48
The value is 48. Starting at 6 and doubling for each of three unit steps gives 6×23, which is 6×8=48. The ratio applies multiplicatively once per unit step.
Which describes the additive transformation property of an exponential function f(x)=bx?
f(x+k)=f(x)+f(k)
f(x+k)=f(x)×bk
f(x+k)=f(x)+k
f(x+k)=bkf(x)
Correct answer: f(x+k)=f(x)×bk
f(x+k)=f(x)×bk is correct. Adding k to the input multiplies the output by bk, because exponents add when powers of the same base multiply. This multiplicative response to additive input is the defining feature of exponentials.
What is the value of 272/3?
9
18
6
3
Correct answer: 9
The value is 9. A fractional exponent means take 327, which is 3, then square it to get 9. The denominator gives the root and the numerator gives the power.
What is the value of 16−1/2?
41
4
-4
161
Correct answer: 41
The value is 41. The exponent −1/2 means take 16, which is 4, then take the reciprocal because of the negative sign, giving 41. The negative exponent inverts rather than negates.
Which expression is equivalent to the b expressed with an exponent?
b1/2
b2
b−1/2
2b
Correct answer: b1/2
b1/2 is correct. A square root is the same as raising to the one-half power, since squaring that result returns b. A negative exponent would give a reciprocal instead.
Which expression equals (a×b)n?
an×bn
an+bn
a×bn
(a+b)n
Correct answer: an×bn
an×bn is correct. The power of a product distributes the exponent to each factor, so (a×b)n equals an×bn. Adding the powers is not a valid rule.
What is the value of log2(81)?
-3
3
−31
81
Correct answer: -3
The value is -3. Since 2−3=81, the logarithm is -3. A negative logarithm signals that the argument is a fraction between zero and one for a base greater than one.
Why is log5(−25) undefined over the real numbers?
No real power of 5 produces a negative number
Because 25 is too large
Because the base must be negative
Because logarithms require even arguments
Correct answer: No real power of 5 produces a negative number
No real power of a positive base is negative, so the expression is undefined. A positive base raised to any real exponent yields a positive result, so it can never equal -25. This is why logarithm arguments must be positive.
Using the product property, logb6 can be rewritten as which sum?
logb2+logb3
logb2×logb3
logb4+logb2
logb3−logb2
Correct answer: logb2+logb3
logb2+logb3 is correct. Because 6 equals 2 times 3, the product property turns the logarithm of the product into the sum of the logarithms of the factors. The factors must multiply to 6, which 2 and 3 do.
Expand logb(x2×y) using logarithm properties.
2logbx+logby
2logbx×logby
logbx+2logby
2(logbx+logby)
Correct answer: 2logbx+logby
2logbx+logby is correct. The product becomes a sum of logarithms, and the exponent 2 on x moves out front as a multiplier by the power property. The exponent applies only to x, not to y.
Expand logb(y3x) using logarithm properties.
logbx−3logby
logbx+3logby
3logbx−logby
logbx−logb3y
Correct answer: logbx−3logby
logbx−3logby is correct. The quotient becomes a difference of logarithms, and the exponent 3 on y moves out as a multiplier on its logarithm. Subtraction reflects the division and the multiplier reflects the power.
Use the change of base formula to write log520 with natural logarithms.
ln(5)ln(20)
ln(20)ln(5)
ln(20)×ln(5)
ln(20)−ln(5)
Correct answer: ln(5)ln(20)
ln(5)ln(20) is correct. The change of base formula puts the argument's logarithm over the base's logarithm in any common base, so the argument 20 goes on top and the base 5 on the bottom. Reversing the ratio would compute the wrong value.
Solve for x: 3x=81.
x=4
x=3
x=27
x=9
Correct answer: x=4
x=4 is correct. Since 81 equals 34, the equation becomes 3x=34, so the exponents match and x=4. Rewriting both sides with the same base makes the exponents directly comparable.
Solve for x: 2x+1=32.
x=4
x=5
x=6
x=16
Correct answer: x=4
x=4 is correct. Writing 32 as 25 gives 2x+1=25, so x+1=5 and x=4. The exponents must be equal once both sides share the same base.
Solve for x exactly: ex=10.
x=ln(10)
x=10/e
x=log10e
x=e10
Correct answer: x=ln(10)
x=ln(10) is correct. Taking the natural logarithm of both sides undoes the base e, leaving x equal to ln(10). The natural logarithm is the inverse of the natural exponential function.
Solve for x: 5x=17, expressed with logarithms.
x=log517
x=17/5
x=log175
x=5×log17
Correct answer: x=log517
x=log517 is correct. Converting the exponential equation to logarithmic form, the exponent equals the logarithm of the result in the equation's base. The base 5 stays the base of the logarithm and 17 becomes the argument.
Solve for x: log4(2x)=2.
x=8
x=4
x=16
x=2
Correct answer: x=8
x=8 is correct. Converting to exponential form gives 42=2x, so 2x=16 and x=8. After rewriting in exponential form, solve the resulting linear equation.
Solve for x: ln(x)=3, expressed exactly.
x=e3
x=3e
x=ln(3)
x=3/e
Correct answer: x=e3
x=e3 is correct. Converting ln(x)=3 to exponential form raises the base e to the power 3, giving x=e3. The natural logarithm and the base e exponential are inverse operations.
Solve for x: log6(x)+log6(x−5)=log624.
x=8
x=3
x=−3
x=24
Correct answer: x=8
x=8 is correct. Combining the left side with the product property gives log6[x(x−5)]=log624, so x(x−5)=24; solving x2−5x−24=0 gives x=8, rejecting the negative since the logarithm needs positive arguments.
Why must solutions to a logarithmic equation be checked in the original equation?
Some algebraic solutions can make a logarithm's argument zero or negative
Logarithms always have two solutions
Checking changes the value of the solution
Logarithmic equations never have valid solutions
Correct answer: Some algebraic solutions can make a logarithm's argument zero or negative
Checking for invalid arguments is correct. Algebraic steps may introduce extraneous solutions that make a logarithm's argument zero or negative, which is outside the domain, so each candidate must be verified. Only solutions keeping all arguments positive are valid.
The function g(x)=3×2x is which transformation of f(x)=2x?
A vertical stretch by a factor of 3
A horizontal shift right by 3
A vertical shift up by 3
A reflection over the y-axis
Correct answer: A vertical stretch by a factor of 3
A vertical stretch by a factor of 3 is correct. Multiplying the exponential by 3 scales every output away from the x-axis by that factor, stretching the graph vertically. The horizontal asymptote at y=0 stays in place.
The function g(x)=2−x is which transformation of f(x)=2x?
A reflection over the y-axis
A reflection over the x-axis
A vertical shift down
A horizontal shift left
Correct answer: A reflection over the y-axis
A reflection over the y-axis is correct. Replacing x with -x flips the graph horizontally across the y-axis, converting growth into decay. The outputs stay positive, so it is not a reflection over the x-axis.
The graph of g(x)=log2(x−3) is the graph of log2x shifted how?
Right by 3 units
Left by 3 units
Up by 3 units
Down by 3 units
Correct answer: Right by 3 units
Right by 3 units is correct. Subtracting 3 inside the logarithm shifts the graph to the right by 3, moving the vertical asymptote from x=0 to x=3. Inside changes move the graph horizontally, opposite to the sign.
After the transformation g(x)=2x−5, where is the horizontal asymptote?
y=−5
y=0
y=5
x=−5
Correct answer: y=−5
y=−5 is correct. Subtracting 5 from the exponential output shifts the entire graph, including its horizontal asymptote, down by 5 units from y=0 to y=−5. The asymptote moves with the vertical shift.
Find the equation of an exponential function passing through (0, 8) and (2, 2).
f(x)=8×(21)x
f(x)=8×2x
f(x)=2×(21)x
f(x)=8×(41)x
Correct answer: f(x)=8×(21)x
f(x)=8×(21)x is correct. The initial value is 8 from the first point, and the base squared must equal 2 divided by 8, which is 41, so the base is 21. The base is found from the ratio of outputs over the input change.
A bacteria culture triples every 4 hours and starts at 200 cells. Which model gives the count after t hours?
P=200×3t/4
P=200×34t
P=200×4t/3
P=200+3t
Correct answer: P=200×3t/4
P=200×3t/4 is correct. Tripling every 4 hours means the base 3 is applied once each 4-hour period, so the exponent is t divided by 4. The divisor sets how often the growth factor is applied.
A sample of 60 mg of a substance has a half-life of 8 years. Which model gives the amount after t years?
A=60×(21)t/8
A=60×(21)8t
A=60×2t/8
A=60−(81)t
Correct answer: A=60×(21)t/8
A=60×(21)t/8 is correct. A half-life of 8 years means the quantity is multiplied by one-half once every 8 years, so the exponent is t divided by 8 with base one-half. The divisor is the half-life.
An account earns 6 percent interest compounded annually on an initial 1000 dollars. Which model gives the balance after t years?
A=1000×(1.06)t
A=1000×(0.06)t
A=1000×(0.94)t
A=1000+60t
Correct answer: A=1000×(1.06)t
A=1000×(1.06)t is correct. Annual growth of 6 percent multiplies the balance by 1 plus 0.06 = 1.06 each year, applied to the initial 1000 dollars. A base of 0.06 or a linear form would not represent compound growth.
Approximately how many years does it take a quantity growing at a continuous rate of 7 percent to double, using the rule based on natural logarithms?
About 10 years, since 0.07ln(2) is roughly 9.9
About 2 years
About 50 years
About 14 years
Correct answer: About 10 years, since 0.07ln(2) is roughly 9.9
About 10 years is correct. Doubling time for continuous growth equals ln(2) divided by the rate, and ln(2) is about 0.69, so 0.070.69 is roughly 9.9 years. The natural logarithm of 2 governs continuous doubling time.
Which best describes how a logarithmic function grows for very large inputs?
It keeps increasing but grows slower than any positive power of x
It approaches a horizontal asymptote
It eventually decreases
It grows faster than exponential functions
Correct answer: It keeps increasing but grows slower than any positive power of x
Slow unbounded growth is correct. A logarithmic function increases without bound but more slowly than any positive power of the input, so it never levels off yet is outpaced by polynomial and exponential growth. It has no horizontal asymptote.
The decibel level is a logarithmic measure of sound intensity. If intensity increases by a factor of 100, how does this relate to a logarithmic scale based on powers of 10?
It is an increase of 2 on the base-10 log scale
It is an increase of 100 on the log scale
It is an increase of 10 on the log scale
It does not change the log value
Correct answer: It is an increase of 2 on the base-10 log scale
An increase of 2 is correct. A factor of 100 equals 102, so on a base-10 logarithmic scale the value rises by 2. Multiplying the underlying quantity by a power of ten adds that exponent on the log scale.
Data plotted on a graph with a logarithmic vertical axis falls along a straight line. What does this indicate about the underlying relationship?
The data follows an exponential model
The data follows a linear model
The data follows a logarithmic model
The data has no pattern
Correct answer: The data follows an exponential model
An exponential model is correct. When the logarithm of the outputs is linear in the inputs, the original relationship is exponential, which is exactly what a straight line on a semi-log plot reveals. This is the standard diagnostic for exponential data.
What is the value of the composition log3(37)?
7
21
3
10
Correct answer: 7
The value is 7. The logarithm and the exponential of the same base are inverses, so composing them returns the original exponent, here 7. The base and exponent are not multiplied together.
Which expression gives the exact solution of the equation 5x=20?
x=log5log20
x=log20log5
x=520
x=log20−log5
Correct answer: x=log5log20
x=log5log20 is correct. Taking the logarithm of both sides gives xlog5=log20, and dividing both sides by log5 isolates x as the quotient log5log20. Reversing the ratio or subtracting the logarithms does not solve for the exponent.
What is the value of tan4π?
31
1
0
3
Correct answer: 1
The value is 1. At 4π (45∘) the sine and cosine are both 22, so their ratio, the tangent, equals 1. Equal sine and cosine always give a tangent of 1.
What is the value of cos4π?
22
23
1
21
Correct answer: 22
The value is 22. At 4π (45∘) the unit circle point is (22,22), and the cosine is the x-coordinate. The sine there is the same value.
What is the value of cos2π?
-1
1
0
22
Correct answer: 0
The value is 0. At 2π (90∘) the unit circle point is (0,1), and the cosine equals the x-coordinate, which is 0. The sine at this angle is 1.
What is the value of sinπ?
22
-1
1
0
Correct answer: 0
The value is 0. At an angle of π (180∘) the unit circle point is (−1,0), and the sine equals the y-coordinate, which is 0. The cosine there is -1.
What is the value of sin23π?
23
1
0
-1
Correct answer: -1
The value is -1. At 23π (270∘) the unit circle point is (0,−1), and the sine equals the y-coordinate, which is -1. The cosine there is 0.
What is the value of tan3π?
21
3
1
33
Correct answer: 3
The value is 3. At 3π the sine is 23 and the cosine is 21, so the tangent, sine over cosine, equals 1/23/2=3.
What is the value of arcsin1?
π
2π
4π
0
Correct answer: 2π
The value is 2π. Arcsine returns the angle in the restricted range whose sine equals the input, and sin2π is 1. This is the largest output arcsine can give.
What is the value of arccos0?
4π
0
π
2π
Correct answer: 2π
The value is 2π. Arccosine returns the angle in its restricted range whose cosine equals the input, and cos2π is 0. So arccos0 is 2π.
What is the value of arctan1?
4π
0
2π
π
Correct answer: 4π
The value is 4π. Arctangent returns the angle in its restricted range whose tangent equals the input, and tan4π is 1. So arctan1 is 4π.
What is the range of the cosine function?
From 0 to 1
From -2 to 2
From -1 to 1, inclusive
All real numbers
Correct answer: From -1 to 1, inclusive
From -1 to 1 is correct. Since the cosine equals the x-coordinate of a point on the unit circle, its values stay between -1 and 1. This matches the range of the sine function.
What is the domain of the tangent function?
Only positive numbers
All real numbers
From -1 to 1
All real numbers except where cosine is zero
Correct answer: All real numbers except where cosine is zero
All reals except where cosine is zero is correct. Tangent is sine divided by cosine, so it is undefined at every angle where the cosine equals zero, such as 2π and its odd multiples. Everywhere else it is defined.
What is the range of the tangent function?
From −π to π
From 0 to ∞
All real numbers
From -1 to 1
Correct answer: All real numbers
All real numbers is correct. As an angle approaches a vertical asymptote, the tangent grows without bound in both directions, so it attains every real value. Its range is therefore all real numbers, unlike sine and cosine.
Which polar equation produces a four-petaled rose?
θ=4
r=cos(2θ)
r=4cosθ
r=4
Correct answer: r=cos(2θ)
r=cos(2θ) is correct. Rose curves have the form r equals a cosine or sine of (nθ); when n is even the rose has 2n petals, so n = 2 yields four petals. A constant r gives a circle instead.
A polar equation of the form r=a+acosθ traces what named curve?
A circle centered at the origin
A spiral
A cardioid
A straight line
Correct answer: A cardioid
A cardioid is correct. When the constant and the coefficient of cosine are equal, the limacon becomes a heart-shaped cardioid that passes through the origin. Different ratios produce other limacon shapes.
The polar curve r=1+2cosθ is an example of which family of curves?
A parabola
A line
A limacon
A rose
Correct answer: A limacon
A limacon is correct. Equations of the form r=a+bcosθ (or sinθ) are limacons; when b is larger than a, the curve forms an inner loop. Roses instead use a multiple of theta inside the trig function.
For the polar function r=f(θ), how is the rate of change of distance from the origin interpreted?
It is always zero
It tells how fast r changes as the angle θ changes
It equals the area enclosed by the curve
It gives the period of the curve
Correct answer: It tells how fast r changes as the angle θ changes
Rate of change of r with theta is correct. In a polar graph the rate of change of f describes how quickly the radial distance grows or shrinks as the angle increases. A positive rate means moving away from the origin; a negative rate means moving toward it.
On a polar graph, an interval where r is positive and decreasing means the curve is doing what?
Moving away from the origin
Staying at a fixed distance
Moving toward the origin while still on the same side as θ
Crossing to the opposite side of the origin
Correct answer: Moving toward the origin while still on the same side as θ
Moving toward the origin is correct. A positive r places the point in the direction of theta, and a decreasing r shrinks that distance, so the curve approaches the origin while rotating. The point stays on the theta side because r remains positive.
Which equation converts rectangular coordinates to the polar angle θ?
θ=x2+y2
θ=arctan(xy)
θ=x×y
θ=x+y
Correct answer: θ=arctan(xy)
Arctangent of y over x is correct. The angle is recovered from the ratio of the y- and x-coordinates using the inverse tangent, with quadrant adjustments as needed. The square root expression gives r, not theta.
A point has rectangular coordinates (0,3). What is a valid polar representation?
(3,2π)
(3,0)
(0,3)
(3,π)
Correct answer: (3,2π)
(3,2π) is correct. The point lies on the positive y-axis at distance 3 from the origin, so r=3 and θ=2π. The radial distance is 02+32=3.
Which identity correctly expresses sine squared theta using cosine?
sin2θ=cosθ
sin2θ=1−cos2θ
sin2θ=1+cos2θ
sin2θ=cos2θ−1
Correct answer: sin2θ=1−cos2θ
1−cos2θ is correct. Rearranging the Pythagorean identity sin2θ+cos2θ=1 isolates sine squared as 1−cos2θ. The other forms break the identity.
If cosθ=−54 and θ is in the second quadrant, what is sinθ?
−53
53
54
−54
Correct answer: 53
sinθ=53 is correct. From the Pythagorean identity, sin2θ=1−2516=259, so sinθ=±53; in the second quadrant the sine is positive, giving 53.
In which quadrant is the tangent function positive while the sine is negative?
Quadrant III
Quadrant I
Quadrant IV
Quadrant II
Correct answer: Quadrant III
Quadrant III is correct. There both sine and cosine are negative, so their ratio the tangent is positive, while the sine itself remains negative. This matches the requested combination of signs.
What is the reference angle for an angle of 65π?
2π
6π
65π
3π
Correct answer: 6π
The reference angle is 6π. The angle 65π lies in the second quadrant, and its reference angle is π−65π=6π, the acute angle to the x-axis.
What is the reference angle for an angle of 34π?
3π
6π
34π
32π
Correct answer: 3π
The reference angle is 3π. The angle 34π is in the third quadrant, and its reference angle is 34π−π=3π, the acute angle to the x-axis.
An angle of −4π is coterminal with which positive angle?
47π
45π
43π
4π
Correct answer: 47π
47π is correct. Adding a full rotation of 2π to −4π gives −4π+2π=47π, which shares the same terminal side. Coterminal angles differ by whole rotations.
What is the length of an arc subtended by a central angle of 3π in a circle of radius 6?
3π
2π
2π
6π
Correct answer: 2π
The arc length is 2π. Using s=rθ with r=6 and θ=3π gives s=6×3π=2π. The angle must be in radians for this formula.
What is 270∘ expressed in radians?
2π radians
23π radians
3π radians
32π radians
Correct answer: 23π radians
23π radians is correct. Multiplying 270∘ by 180π gives 180270π=23π radians. This is three-quarters of a full circle.
An angle of 32π radians equals how many degrees?
60∘
150∘
120∘
90∘
Correct answer: 120∘
120∘ is correct. Multiplying 32π by π180 gives 32×180=3360=120∘. The pi values cancel during conversion.
The graph of f(x)=sin(x−3π) is the sine graph shifted how?
Down by 3π
Left by 3π
Right by 3π
Up by 3π
Correct answer: Right by 3π
Shifted right by 3π is correct. Subtracting a positive constant inside the function argument translates the graph to the right by that amount. This is the phase shift of the sinusoid.
For f(x)=4sinx−2, what is the maximum value?
6
4
2
-6
Correct answer: 2
The maximum is 2. The amplitude is 4 and the midline is -2, so the peak is one amplitude above the midline at -2 plus 4 = 2. The minimum would be -2 minus 4 = -6.
For f(x)=4sinx−2, what is the minimum value?
-6
2
-4
-2
Correct answer: -6
The minimum is -6. With amplitude 4 and midline -2, the lowest point sits one amplitude below the midline at -2 minus 4 = -6. The maximum is -2 plus 4 = 2.
A sinusoid has a maximum of 12 and a minimum of -4. What is its amplitude?
8
4
16
12
Correct answer: 8
The amplitude is 8. Amplitude equals half the difference of the maximum and minimum, so (12 minus (-4)) divided by 2 = 16 divided by 2 = 8. The midline would be the average, which is 4.
A sinusoid has a maximum of 12 and a minimum of -4. What is its midline?
0
16
8
4
Correct answer: 4
The midline is 4. The midline is the average of the maximum and minimum, so (12 plus (-4)) divided by 2 = 8 divided by 2 = 4. The amplitude, the half-difference, is 8.
What is the period of f(x)=sin(3x)?
6π
3π
3π
32π
Correct answer: 32π
The period is 32π. The period equals 2π divided by the input coefficient, so with a coefficient of 3 the period is 32π. A larger coefficient shortens the period.
Which describes the relationship between the secant graph and the cosine graph?
Secant has vertical asymptotes where cosine equals zero and shares cosine's sign
Secant has the same range as cosine
The secant graph crosses zero wherever cosine does
Secant is the cosine graph shifted down
Correct answer: Secant has vertical asymptotes where cosine equals zero and shares cosine's sign
Asymptotes where cosine is zero is correct. Since secant is the reciprocal of cosine, it blows up to ∞ exactly where cosine equals zero and takes the same sign as cosine elsewhere. Its range excludes the interval between −1 and 1.
What is the value of sec0?
Undefined
-1
0
1
Correct answer: 1
The value is 1. Secant is 1 divided by cosine, and cos0 is 1, so sec0 is 1 divided by 1=1. Secant is undefined only where the cosine is zero.
What is the value of csc2π?
0
-1
Undefined
1
Correct answer: 1
The value is 1. Cosecant is 1 divided by sine, and sin2π is 1, so the cosecant is 1 divided by 1=1. Cosecant is undefined where the sine is zero.
Which sinusoidal function would best model a Ferris wheel where riders board at the lowest point and the height starts at its minimum?
A plain sine function with no shifts
A negative cosine function shifted up to the midline
A tangent function
A positive cosine function with a vertical shift
Correct answer: A negative cosine function shifted up to the midline
A negative cosine shifted up is correct. A negative cosine starts at its minimum at the input zero, matching boarding at the lowest point, and the vertical shift raises the midline to the wheel's center height. A plain sine starts at the midline instead.
What is the value of sin(−2π)?
0
1
Undefined
-1
Correct answer: -1
The value is -1. Because sine is an odd function, sin(−2π) equals the negative of sin2π, which is −1. The terminal point is (0,−1) on the unit circle.
What is the value of cos(−3π)?
−21
21
−23
23
Correct answer: 21
The value is 21. Because cosine is an even function, cos(−3π) equals cos3π, which is 21. The negative sign in the angle does not change an even function's output.
What is the value of cos23π?
0
-1
22
1
Correct answer: 0
The value is 0. At an angle of 23π (270 degrees) the unit circle point is (0,−1), and the cosine equals the x-coordinate, which is 0. The sine there is −1.
An angle of 45 degrees is equivalent to how many radians?
6π
3π
4π
2π
Correct answer: 4π
The value is 4π. Multiplying 45 degrees by 180π gives 45 pi over 180, which simplifies to 4π. This is the radian benchmark for a 45-degree angle.
An angle of 45π radians lies in which quadrant?
Quadrant III
Quadrant II
Quadrant I
Quadrant IV
Correct answer: Quadrant III
Quadrant III is correct. The angle 45π is between π and 23π, which spans the third quadrant. Both the sine and cosine are therefore negative at this angle.
What is the reference angle for an angle of 32π?
32π
4π
3π
6π
Correct answer: 3π
The reference angle is 3π. Since 32π lies in the second quadrant, its reference angle is π minus 32π, which equals 3π. The reference angle is the acute angle to the x-axis.
What is the value of cos32π?
21
−21
−23
23
Correct answer: −21
The value is −21. The angle 32π is in the second quadrant with reference angle 3π, where cosine is 21; cosine is negative in the second quadrant, so the value is −21.
What is the value of sin67π?
−21
−23
21
23
Correct answer: −21
The value is −21. The angle 67π lies in the third quadrant with reference angle 6π, where sine is 21; sine is negative in the third quadrant, so the value is −21.
The graph of the cosine function attains its maximum value of 1 at which input?
x=2π
x=23π
x=π
x=0
Correct answer: x=0
The value x=0 is correct. The cosine starts at its maximum of 1 when the input is 0, corresponding to the unit circle point (1,0). It returns to 1 again at every multiple of 2π.
Over the interval from 0 to 2π, the sine function is doing what?
Constant
Oscillating between extremes
Increasing
Decreasing
Correct answer: Increasing
Increasing is correct. On the interval from 0 to 2π, the sine rises from 0 up to its maximum of 1. After 2π it begins to decrease.
A sinusoidal graph is concave down near its maximum because the outputs there are doing what?
Decreasing at a decreasing rate toward the minimum
Increasing at an increasing rate
Changing from increasing to decreasing as the curve bends downward
Staying perfectly constant
Correct answer: Changing from increasing to decreasing as the curve bends downward
Bending downward at the peak is correct. Near a maximum a sinusoid is concave down, where the rate of change shifts from positive to negative and the curve turns over. Near a minimum, by contrast, the graph is concave up.
Where is the rate of change of the sine function greatest in magnitude?
Where it crosses the midline
At its maximum and minimum points
Where the amplitude is largest
Where the period ends
Correct answer: Where it crosses the midline
At the midline crossings is correct. A sinusoid changes fastest where it passes through the midline, since the graph is steepest there. At the maximum and minimum the rate of change is momentarily zero.
The cosecant function has vertical asymptotes wherever which function equals zero?
Tangent
Sine
Secant
Cosine
Correct answer: Sine
Where sine is zero is correct. Since cosecant is 1 divided by sine, it is undefined and has vertical asymptotes exactly where the sine equals zero, such as at 0, π, and 2π. These are different from the asymptotes of secant.
What is the range of the secant function?
All real numbers
All values less than or equal to −1 or greater than or equal to 1
Only positive numbers
From −1 to 1
Correct answer: All values less than or equal to −1 or greater than or equal to 1
Values at least 1 in magnitude is correct. Because secant is the reciprocal of cosine and cosine ranges from −1 to 1, the secant never lies strictly between −1 and 1; its outputs are at least 1 in absolute value.
What is the range of the arcsine function (its output angles)?
All real numbers
From −1 to 1
From −2π to 2π
From 0 to π
Correct answer: From −2π to 2π
From negative pi over 2 to pi over 2 is correct. Arcsine is defined to return angles only in the interval from −2π to 2π, the restricted domain that makes sine one-to-one. This guarantees a single output angle.
What is the range of the arccosine function (its output angles)?
From 0 to 2π
From −2π to 2π
From −1 to 1
From 0 to π
Correct answer: From 0 to π
From 0 to pi is correct. Arccosine returns angles only in the interval from 0 to π, the restricted domain on which cosine is one-to-one. This ensures each input ratio maps to a single output angle.
The tangent function has vertical asymptotes that repeat with what spacing along the x-axis?
Every 2π units
They do not repeat
Every π units
Every 2π units
Correct answer: Every π units
Every pi units is correct. The tangent's asymptotes occur where cosine is zero, at 2π plus integer multiples of π, so consecutive asymptotes are π apart. This matches the tangent's period of π.
Which polar equation produces a cardioid?
r=3
r=2+2cosθ
r=5cosθ
θ=4π
Correct answer: r=2+2cosθ
The equation r=2+2cosθ is correct. A cardioid is a limacon of the form r=a+acosθ where the constant and the coefficient are equal, producing a heart shape. A constant r gives a circle instead.
A polar equation of the form r=asin(nθ) with n a positive integer typically graphs as what?
A rose curve with petals
A parabola
A single circle centered at the origin
A straight line
Correct answer: A rose curve with petals
A rose curve is correct. Polar equations of the form r=asin(nθ) trace rose curves made of symmetric petals. The number of petals depends on whether n is odd or even.
For the rose curve r=acos(nθ), how many petals appear when n is an odd integer?
N petals
Always 4 petals
N divided by 2 petals
2n petals
Correct answer: N petals
n petals is correct. When n is odd, the rose curve r=acos(nθ) has exactly n petals because the petals retrace over the same paths. When n is even, the curve instead has 2n petals.
How far from the origin is the point with polar coordinates (6,45π)?
6 units
12 units
3 units
45π units
Correct answer: 6 units
6 units is correct. The first coordinate in a polar pair is the radial distance r, so the point lies 6 units from the origin regardless of the angle. The angle 45π only sets the direction.
A point has rectangular coordinates (0,−3). What is a polar representation?
(3,2π)
(3,23π)
(3,0)
(3,π)
Correct answer: (3,23π)
(3,23π) is correct. The point lies on the negative y-axis at distance 3 from the origin, so r is 3 and the angle pointing straight down is 23π. The angle 2π would point straight up instead.
On the graph of a polar function r=f(θ), the function value r reaches a relative maximum where the curve does what?
Reaches its farthest distance from the origin along that direction
Has zero radius
Crosses the origin
Becomes a straight line
Correct answer: Reaches its farthest distance from the origin along that direction
Farthest from the origin is correct. A relative maximum of r corresponds to a point where the curve is locally farthest from the pole. Reading polar graphs means relating the value of r to distance from the origin.
For a polar function r=f(θ), where r is positive and decreasing as θ increases, the curve is doing what?
Staying at a constant distance
Moving away from the origin
Stopping completely
Moving toward the origin while rotating
Correct answer: Moving toward the origin while rotating
Moving toward the origin is correct. When r is positive but decreasing as θ grows, the points get closer to the pole while the angle continues to increase, so the curve spirals inward. Increasing r would move it outward.
Two angles are supplementary if their measures add to what?
4π radians
π radians
2π radians
2π radians
Correct answer: π radians
pi radians is correct. Supplementary angles sum to a straight angle, which is π radians or 180 degrees. Angles summing to 2π would instead be complementary.
Which identity correctly relates tangent and secant?
1−tan2θ=sec2θ
1+tan2θ=sec2θ
tanθ=secθ
tan2θ=sec2θ
Correct answer: 1+tan2θ=sec2θ
1 plus tangent squared equals secant squared is correct. Dividing the Pythagorean identity by cosine squared yields 1+tan2θ=sec2θ. This is one of the standard Pythagorean identities.
If tanθ=43 and θ is in the first quadrant, what is sinθ?
35
43
54
53
Correct answer: 53
sinθ=53 is correct. With tangent equal to 43 in the first quadrant, picture a right triangle with opposite 3 and adjacent 4, so the hypotenuse is 5 and sine equals opposite over hypotenuse, 53. The cosine would be 54.
What is the value of sin(−6π)?
−21
23
−23
21
Correct answer: −21
The value is −21. Because sine is an odd function, sin(−6π) equals the negative of sin6π, and sin6π is 21, giving −21.
What is the value of cos(−3π)?
−23
21
−21
23
Correct answer: 21
The value is 21. Because cosine is an even function, cos(−3π) equals cos3π, which is 21. The even symmetry means the sign of the input does not change the output.
When fitting a sinusoidal regression model to periodic data, the technology produces which form?
An exponential equation
A quadratic equation
A model of the form y=asin(bx+c)+d
A linear equation
Correct answer: A model of the form y=asin(bx+c)+d
The sinusoidal form is correct. Sinusoidal regression estimates the parameters a, b, c, and d of a sine model to best fit periodic data. The result captures amplitude, period, phase shift, and midline of the trend.
In a sinusoidal model of hours of daylight over a year, which feature represents the difference between the longest and shortest days?
The midline
Twice the amplitude
The period
The phase shift
Correct answer: Twice the amplitude
Twice the amplitude is correct. The full swing from the maximum daylight to the minimum daylight equals the distance from peak to trough, which is two amplitudes. A single amplitude measures only from the midline to a peak.
The graph of f(x)=tanx passes through the origin and is increasing. Between two consecutive asymptotes, the tangent function does what?
Stays constant
Reaches a maximum then a minimum
Decreases throughout
Increases throughout from −∞ to +∞
Correct answer: Increases throughout from −∞ to +∞
Increasing across each branch is correct. On each interval between consecutive vertical asymptotes, the tangent rises continuously from −∞ to +∞. It has no maximum or minimum values.
A sinusoidal function crosses its midline at x=1 going upward and next crosses the midline going upward at x=7. What is its period?
7
12
3
6
Correct answer: 6
The period is 6. One full period is the distance between two successive midline crossings in the same direction, here from x=1 to x=7, a span of 6. A half-period would separate upward and downward crossings.
Which describes the graph of a polar equation r=1+3cosθ?
A limacon with an inner loop
A circle of radius 1
A straight line
A rose with three petals
Correct answer: A limacon with an inner loop
A limacon with an inner loop is correct. For r=a+bcosθ, when the coefficient b is larger than the constant a, the curve is a limacon that forms an inner loop. When they are equal it becomes a cardioid instead.
What is the exact value of cos65π?
−21
−23
21
23
Correct answer: −23
The value is −23. The angle 65π is in the second quadrant with reference angle 6π, where cosine is 23; cosine is negative in the second quadrant, giving the negative value.
When converting the rectangular point (1,1) to polar coordinates, which equation is used to find the angle θ?
θ=tanxy
θ=arctanxy (arctangent)
θ=yx
θ=x2+y2
Correct answer: θ=arctanxy (arctangent)
The arctangent of xy is correct. Because tanθ equals xy, the angle is recovered by applying the inverse tangent to that ratio, with the quadrant of the point checked to place θ correctly. The x2+y2 gives the radial distance r, not the angle.
To find us again, just search “Career Employer AP Precalculus”
If an exponential function has a growth factor of 1.5 per unit, what is the equivalent percent rate of change per unit?
Pick an answer to see the explanation
Click Start Test above to launch a full-length AP Precalculus multiple-choice practice test weighted exactly like the real exam, or drill a single unit — from Polynomial and Rational Functions to Trigonometric and Polar Functions. Every question includes a clear explanation so you learn the reasoning, not just the answer.
The AP Precalculus exam is a college-level assessment that measures your understanding of functions and your ability to model and reason with them across three assessed units.
It is administered by the College Board and is given once a year in May, with most students taking it after a year-long AP Precalculus course.[1] A strong score can earn you college credit or advanced placement.
These practice questions follow the published AP Precalculus course and exam description, mirroring the content and pacing of the real multiple-choice section so you can build readiness across every assessed unit.[2] To round out your prep, pair these with our free study guide, flashcards, and cheat sheet.
Dates, fees, and policies change — always verify the current details at collegeboard.org before you register.
AP Precalculus is one of the 17 AP exams — explore all our AP practice tests to compare and prep across the whole family.
AP Precalculus at a Glance
AP Precalculus at a glance
Detail
AP Precalculus
Questions
40 multiple-choice + 4 free-response (practice covers the 40 MCQ)
Format
Hybrid digital exam (Bluebook MCQ + handwritten free response)
Time limit
About 3 hours total (2 hr MCQ + 1 hr FRQ)
Calculator
Mixed — some parts no-calculator, others require a graphing calculator
Scoring / Result
Scored 1-5; a 3 or higher is generally passing and may earn college credit
Administered by
College Board (given once a year in May)
Eligibility
Open to any student; no formal prerequisite, but a year-long course is recommended
Cost / Fee
Approximately 99intheU.S.(about129 internationally); verify at collegeboard.org
Retakes
Offered only once a year in May — you can only retake it the next year
What Is on the AP Precalculus Exam?
The AP Precalculus exam has two sections: 40 multiple-choice questions in 2 hours (62.5% of the score) and 4 free-response questions in 1 hour (37.5% of the score). The multiple-choice section splits into a no-calculator Part A of 28 questions and a calculator-required Part B of 12 questions.[1]
The exam only assesses content from Units 1-3 — Unit 4 is taught in the course but is not tested. Each assessed unit carries a roughly equal weight on the multiple-choice section. Our full practice test mirrors these proportions:
AP Precalculus weighting by assessed unit
Unit 1: Polynomial and Rational Functions35% · ~35%
Unit 2: Exponential and Logarithmic Functions33% · ~32%
Unit 3: Trigonometric and Polar Functions33% · ~32%
Practice Questions by Unit
Use Start Test for a full weighted AP Precalculus simulation, or open the hub and pick a single unit to drill your weak area. After each full exam, your results show a per-unit breakdown so you know exactly where to focus — the three assessed units are weighted almost evenly, so balanced reps across all of them pay off.
Who Is Eligible to Take the AP Precalculus Exam?
The AP Precalculus exam is open to any student — there is no formal prerequisite and you do not have to take an AP course to sit for the exam.[6]
That said, the exam covers a full year of college-level precalculus, so most successful examinees have completed an AP Precalculus course or equivalent coursework in algebra, functions, and trigonometry.
If your school does not offer AP, you can usually arrange to test at a nearby school that administers AP exams. Contact that school’s AP coordinator early, because seats and ordering deadlines fill well before May.
How Do You Register for the AP Precalculus Exam?
You register for the AP Precalculus exam through your school’s AP coordinator, not directly with the College Board. In My AP, you indicate that you plan to test, and the coordinator orders your exam.[6]
The standard exam fee is approximately $99 at schools in the U.S., U.S. territories, Canada, and DoDEA schools, and about $129 internationally. Your AP coordinator collects any fees you owe.[4]
The final ordering deadline for full-year courses is typically in mid-November, and a late order fee applies after that. Verify the current fee and deadlines at collegeboard.org, as they change each year.
If your school does not offer AP, contact a participating school’s AP coordinator to arrange testing — do this in the fall, well ahead of the spring deadlines.
How Is the AP Precalculus Exam Scored?
AP Precalculus is scored on a scale of 1 to 5, where 5 means extremely well qualified, 3 means qualified, and 1 means no recommendation.[5]
The multiple-choice section counts for 62.5% of your composite score and the free-response section for 37.5%, which is converted to the final 1-5 scale. There is no penalty for wrong answers, so you should answer every multiple-choice question.
A score of 3 or higher is generally considered passing, and the College Board and ACE recommend that colleges grant credit for a 3 or above. Each college sets its own policy, so check the AP credit requirements at your target schools.
How Hard Is the AP Precalculus Exam?
AP Precalculus rewards reasoning about functions — analyzing, modeling, and connecting multiple representations — rather than simple recall.[2] The challenge is applying core ideas about functions to unfamiliar scenarios under time pressure.
The multiple-choice section pairs no-calculator questions with a calculator-required part, so you have to be fluent both by hand and with a graphing calculator. Reading graphs, tables, and equations quickly matters as much as content knowledge.
The free-response section then asks you to model with functions, justify reasoning, and communicate using correct notation. Because the three assessed units are weighted almost evenly, a weakness in any one unit can drag your score down.
1-5
Score scale
3+ generally passing
40
Multiple-choice Qs
62.5% of the score
3
Units assessed
Unit 4 is not tested
The takeaway: drill until you’re consistently scoring at or above your target college credit threshold on full-length, unit-weighted practice — across all three assessed units, both with and without a calculator — before exam day in May.
What to Expect on Exam Day
AP Precalculus is a hybrid digital exam: you answer the multiple-choice questions and view the free-response prompts in the Bluebook testing app, then handwrite your free-response answers in a paper booklet.[1]
You work through 40 multiple-choice questions in the first 2 hours — a no-calculator Part A of 28 questions, then a calculator-required Part B of 12 questions — take a short break, then complete 4 free-response questions in the final hour. A graphing calculator is required for the calculator parts, and a reference sheet is provided.
Bring an acceptable photo ID if required by your school, arrive early, and leave phones and personal items as instructed. Having simulated the full multiple-choice timing with practice tests makes the pacing feel routine.
How to Use This AP Precalculus Practice Test
Recreate exam conditions. Take the full multiple-choice test timed, with no notes.[2]
Diagnose, then drill. Use a full simulation to find weak units, then drill them.
Balance all three units. The assessed units are weighted almost evenly, so don’t neglect any.
Practice both ways. Train with and without a calculator to match the two MCQ parts.
Learn the why. Read every explanation — reasoning beats memorizing.
Answer everything. There’s no guessing penalty, so never leave a question blank.
Why the AP Precalculus Exam Matters
A strong AP Precalculus score is one of the clearest ways to earn college credit, skip an introductory math course, and strengthen your college applications — it gives admissions officers and colleges an objective measure of college-level readiness.[5] Because the exam is offered only once a year, every rep counts: you can’t retake it until the following May. These free AP Precalculus practice tests are the most efficient way to walk in ready the first time.
Conclusion
Performing well on the AP Precalculus exam comes down to fluency with functions across three assessed units, sharp reasoning across representations, and the stamina to apply it under timed conditions. Use this free AP Precalculus practice test to find your weak units, drill them to mastery, and pair it with our free study guide, flashcards, and cheat sheet to walk in confident on test day.
AP Precalculus Practice Test FAQ
The AP Precalculus exam is a college-level assessment administered by the College Board that measures your understanding of functions and modeling. It is intended for high school students who want to earn college credit or advanced placement by demonstrating mastery of the course content. Scoring well can let you skip an equivalent introductory college math course.
The AP Precalculus exam is about 3 hours long. Section I is 40 multiple-choice questions in 2 hours (62.5% of the score), split into a no-calculator Part A (28 questions) and a calculator-required Part B (12 questions). Section II is 4 free-response questions in 1 hour (37.5% of the score). Our practice test focuses on the 40-question multiple-choice section, weighted to the official unit breakdown.
AP exams are scored on a scale of 1 to 5, where 5 means extremely well qualified and 1 means no recommendation. The multiple-choice section counts for 62.5% of your composite score and the free-response section for 37.5%, which is then converted to the 1-5 scale. A score of 3 or higher is generally considered passing and is recommended for college credit.
A score of 3 or higher is generally treated as passing, and the College Board and ACE recommend that colleges award credit for scores of 3 and above. However, each college sets its own credit policy, so some competitive programs require a 4 or 5. Check the AP credit policy of your target schools to know the score you need.
No. The AP Precalculus exam only assesses content from Units 1 through 3: Polynomial and Rational Functions, Exponential and Logarithmic Functions, and Trigonometric and Polar Functions. Unit 4 (Functions Involving Parameters, Vectors, and Matrices) is taught in the course but is not assessed on the AP Exam, so our practice test mirrors only the three tested units.
The AP Precalculus exam fee is approximately $99 per exam at schools in the U.S., U.S. territories, Canada, and DoDEA schools, and about $129 elsewhere (verify the current fee at collegeboard.org, since fees change). You register through your school's AP coordinator, not directly with the College Board. If your school does not offer AP, you can arrange to test at a nearby participating school.
Yes, but AP exams are offered only once a year in May, so you cannot retake the exam in the same year. If you want a higher score, you must wait and take the exam again the next May. If you retake it, both scores are reported unless you request that one be withheld or canceled.
Because AP Precalculus rewards reasoning about functions across three assessed units, the most effective preparation is repeated, unit-weighted multiple-choice practice under timed conditions, paired with free-response practice. Practice both with and without a calculator, since the exam has distinct calculator and no-calculator parts. Read every explanation to learn the underlying reasoning, and reinforce weak units between sessions with a study guide, flashcards, and a cheat sheet.
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