FREE AP Calculus AB Study Guide 2026: All 8 Units, Limits to Integrals
Every College Board AP Calculus AB unit — limits, derivatives, integrals, and their applications — taught to the exam, with worked examples, theorems, built-in quizzes, and flashcards.
This free AP Calculus AB study guide teaches to the College Board’s current course — all eight units, in the order the exam is built, from to to .[1] AP Calculus AB covers roughly the first two semesters of college calculus and is scored from 1 to 5, with a 3 generally counting as passing for college credit.[2]
It’s interactive, not a wall of text: every unit has a built-in checkpoint quiz, hover-able glossary terms, worked examples with full derivative and integral notation, labeled diagrams, and concept questions, so you learn by doing. Read it unit by unit, test yourself at each checkpoint, then round out your free prep with our practice questions and flashcards.
The three Big Ideas of AP Calculus AB
BIG IDEA 1LimitsThe foundation. A limit describes the value a function approaches — it makes both the derivative and the integral rigorous.Unit 1
BIG IDEA 2DerivativesInstantaneous rate of change and the slope of a tangent line. Rules, the chain rule, and applications to motion, related rates, and graph analysis.Units 2–5
BIG IDEA 3Integrals & the FTCAccumulation of change and area. The Fundamental Theorem of Calculus ties integration back to the derivative.Units 6–8
Limits make the derivative precise; the derivative and the integral are inverse operations linked by the Fundamental Theorem of Calculus.
AP Calculus AB is one of the 17 AP exams — explore our AP study guides to compare and prep across the whole family.
AP Calculus AB Exam Snapshot
AP Calculus AB exam at a glance (2026)
Detail
AP Calculus AB
Questions
45 multiple choice + 6 free response
Format
Section I (MCQ, 50%) and Section II (FRQ, 50%), each split calculator / no-calculator
Total time
About 3 hours 15 minutes (1 h 45 m MCQ + 1 h 30 m FRQ)
Score scale
1–5; a 3 is generally considered passing for credit
Calculator
Required on MCQ Part B (15 Q) and FRQ Part A (2 Q); none on the other parts
Units
8 official College Board units (limits through applications of integration)
Course level
Roughly the first two semesters of college calculus
When / who
May, after a year-long AP course; open to any prepared student
Publisher
College Board
How the AP Calculus AB exam is built — 45 MCQ + 6 FRQ
Multiple choice and free response are weighted 50% each. Two parts of the exam allow a graphing calculator and two do not.
Section I, Part A — Multiple Choice (no calculator)30 questions · 60 min. Worked entirely by hand — limits, derivative rules, and antiderivatives you must know cold.
↓
Section I, Part B — Multiple Choice (calculator)15 questions · 45 min. A graphing calculator is required for some items (numeric integrals, roots, derivatives at a point).
↓
Section II, Part A — Free Response (calculator)2 questions · 30 min. Show your setup and reasoning; a graphing calculator is permitted and often needed.
↓
Section II, Part B — Free Response (no calculator)4 questions · 60 min. Justify answers with correct notation and supporting work — points are awarded for the work, not just the answer.
About 3 hours 15 minutes total. Scored 1–5; a 3 or higher is generally considered passing for college credit.
Multiple choice and free response are each worth 50% of your score.[3] The free-response section rewards justification — you earn points for correct setup, notation, and reasoning, not only the final number. Spend your study time across all eight units, but weight it toward the heaviest:
AP Calculus AB exam weighting by unit (2026 MCQ ranges)
Unit 6 · Integration & Accumulation18% · 17–20%
Unit 5 · Analytical Applications17% · 15–18%
Unit 4 · Contextual Applications13% · 10–15%
Unit 8 · Applications of Integration13% · 10–15%
Unit 3 · Composite/Implicit/Inverse11% · 9–13%
Unit 1 · Limits & Continuity11% · 10–12%
Unit 2 · Differentiation Basics11% · 10–12%
Unit 7 · Differential Equations9% · 6–12%
College Board reports each unit’s share of the multiple-choice section as a range, so the exact mix shifts slightly each year.[1] This guide teaches all eight units as eight study modules, in the order they build on one another.
1 · Limits & Continuity
About 10–12% of the exam. Limits are the foundation of the whole course — they make both the derivative and the integral rigorous.[1] A is the value f(x) approaches as x nears a target, and it can exist even where the function does not.
Defining & Estimating Limits
A two-sided limit limx→af(x)=L exists only when the agree: limx→a−f(x)=limx→a+f(x). You can estimate a limit from a graph or table, or read it off directly when the function is continuous there.
Evaluating Limits Algebraically
Try direct substitution first. If it gives 00, use algebra — factor and cancel, multiply by a conjugate, or simplify a complex fraction. For limits at infinity of a rational function, compare the degrees of numerator and denominator.
Limits at infinity of a rational function
Compare degrees
Limit as x → ∞
Numerator degree < denominator
0
Numerator degree = denominator
Ratio of leading coefficients
Numerator degree > denominator
±∞ (no finite limit)
Continuity, IVT & Discontinuities
at x=a needs three things: f(a) is defined, limx→af(x) exists, and they are equal. Discontinuities come in three flavors: removable (a hole), jump (one-sided limits disagree), and infinite (a vertical asymptote). The uses continuity to guarantee a function hits every value between f(a) and f(b).
Checkpoint · Unit 1 · Limits & Continuity
Question 1 of 10
Evaluate lim x → 2 (x³ - 8)/(x - 2).
2 · Differentiation: Definition & Basic Rules
About 10–12% of the exam. The is the instantaneous rate of change — the slope of the tangent line.[1] Unit 2 builds it from the limit definition, then gives you the rules that make differentiation fast.
The derivative: the limit of secant slopes as h → 0
f′(a) = limh→0 [ f(a + h) − f(a) ] / h
The secant slope between (a) and (a + h) approaches the tangent slope as h shrinks to zero. That tangent slope is the derivative f′(a) — the instantaneous rate of change.
The Derivative as a Limit
The derivative is the limit of the : f′(a)=limh→0hf(a+h)−f(a). It is the limiting slope of secant lines as the second point slides toward the first. Where this limit fails — a corner, cusp, or vertical tangent — the function is not differentiable, even if it is continuous.
Power, Constant & Sum Rules
The is your workhorse: dxdxn=nxn−1 for any real n. Rewrite roots and reciprocals as powers first — e.g. x=x1/2. Combine it with the constant-multiple and sum rules and the key transcendental derivatives:
Core derivative rules you should know cold
Function
Derivative
xn
nxn−1
ex
ex
lnx
x1
sinx
cosx
cosx
−sinx
tanx
sec2x
Product & Quotient Rules
For a product, use the (fg)′=f′g+fg′. For a quotient, use the (gf)′=g2f′g−fg′. The most common error is reversing the order in the quotient rule’s numerator.
Checkpoint · Unit 2 · Differentiation Basics
Question 1 of 10
The derivative of a function f is defined as a limit. Geometrically, what does the value of f'(a) represent for the graph of f?
About 9–13% of the exam. This unit is the and everything it unlocks — composite functions, , and the derivatives of inverse functions.[1]
The Chain Rule
The chain rule differentiates a composite f(g(x)): dxdf(g(x))=f′(g(x))⋅g′(x) — outer derivative at the inner function, times the inner derivative. It is the most-used rule in the course, often nested inside a product or quotient.
Implicit Differentiation
When a curve is given by an equation not solved for y — like x2+y2=25 — differentiate both sides in x, attaching a dxdy to every y-term (chain rule), then solve for dxdy.
Inverse & Inverse-Trig Derivatives
If g is the inverse of f, then g′(x)=f′(g(x))1. Two inverse-trig derivatives are tested most:
Inverse-trig derivatives on AP Calculus AB
Function
Derivative
arcsinx
1−x21
arctanx
1+x21
Checkpoint · Unit 3 · Composite, Implicit & Inverse
Question 1 of 10
Find the derivative of f(x) = e^(3x²).
4 · Contextual Applications of Differentiation
About 10–15% of the exam. Derivatives in the real world: , , , and straight-line motion.[1]
Related Rates
Related rates connect the time rates of two linked quantities. Write the equation relating them, differentiate both sides with respect to t, then substitute known values after differentiating.
Linearization & L’Hopital’s Rule
uses the tangent line L(x)=f(a)+f′(a)(x−a) to estimate f near a. For a limit in the indeterminate form 00 or ∞∞, replaces it with limg′(x)f′(x).
Straight-Line Motion
For a particle with position s(t), velocity is v(t)=s′(t) and acceleration is a(t)=v′(t)=s′′(t). The particle is at rest when v=0, and it is speeding up when v and a share the same sign.
Checkpoint · Unit 4 · Contextual Applications
Question 1 of 10
In a related rates problem, what relationship is being analyzed?
5 · Analytical Applications of Differentiation
About 15–18% of the exam — one of the two heaviest units. Using f′ and f′′ to analyze graphs, the key theorems (, ), and optimization.[1]
Reading a graph from f′ and f″
f′ > 0f is increasing — graph rising
f′ < 0f is decreasing — graph falling
f′ = 0 or undefinedcritical point — candidate max/min
f″ > 0f is concave up — cups upward (∪)
f″ < 0f is concave down — caps downward (∩)
f″ changes signinflection point — concavity flips
The first derivative controls increasing/decreasing and locates extrema; the second derivative controls concavity and locates inflection points.
MVT & the Extreme Value Theorem
The says that if f is continuous on [a,b] and differentiable on (a,b), some c gives f′(c)=b−af(b)−f(a) — the tangent is parallel to the secant. The guarantees an absolute max and min when f is continuous on a closed interval.
First & Second Derivative Tests
At a (f′=0 or undefined), the First Derivative Test checks the sign of f′: a change +→− is a relative max, −→+ a relative min. The Second Derivative Test uses f′′ at the point: f′′>0 ⟹ min, f′′<0 ⟹ max. An is where f′′ changes sign.
Optimization & Curve Sketching
Optimization finds the largest or smallest value of a quantity. Write the quantity as a function of one variable, differentiate, find critical points, and test them — checking the endpoints too on a closed interval (the guarantees the extreme is attained there).
Checkpoint · Unit 5 · Analytical Applications
Question 1 of 10
What two hypotheses must a function f satisfy on the interval from a to b for the Mean Value Theorem to apply?
6 · Integration & Accumulation of Change
About 17–20% of the exam — the single heaviest unit. , the as accumulated area, the , and .[1]
The definite integral = signed area under the curve
∫ab f(x) dx = (signed) area between the curve and the x-axis from a to b
Area above the x-axis counts positive, area below counts negative. The Fundamental Theorem evaluates it as F(b) − F(a), where F is any antiderivative of f.
Riemann Sums & Accumulation
A approximates area with rectangles whose heights come from left endpoints, right endpoints, or midpoints. As the rectangles shrink, the sum becomes the definite integral. An g(x)=∫axf(t)dt stores total change up to x.
The Fundamental Theorem of Calculus
The ties the two halves of calculus together. Part 1:dxd∫axf(t)dt=f(x). Part 2 (evaluation):∫abf(x)dx=F(b)−F(a), where F is any of f.
Antiderivatives & u-Substitution
Reverse the basic derivative rules to find antiderivatives, then use to reverse the chain rule. Three you should know:
Antiderivatives every AP student should know
Integral
Result
∫xndx,n=−1
n+1xn+1+C
∫x1dx
ln∣x∣+C
∫exdx
ex+C
∫cosxdx
sinx+C
∫sinxdx
−cosx+C
Checkpoint · Unit 6 · Integration & Accumulation
Question 1 of 10
A right Riemann sum is used to approximate the area under a continuous, increasing function on a closed interval using equal-width rectangles. Compared with the exact area under the curve, this approximation will be:
7 · Differential Equations
About 6–12% of the exam. A differential equation relates a function to its derivative. On AB you them with slope fields and analytically.[1]
Slope Fields
A draws a short segment at each grid point with slope dxdy=f(x,y) there, picturing the family of solution curves. Segments are horizontal where dxdy=0 and steep where the slope is large.
Separable Equations & Growth
A can be rearranged so all y-terms (with dy) are on one side and all x-terms (with dx) on the other; integrate both sides and use an initial condition for C. The model dtdy=ky gives y=y0ekt.
Checkpoint · Unit 7 · Differential Equations
Question 1 of 10
Which of the following is the defining characteristic of a separable first-order differential equation?
8 · Applications of Integration
About 10–15% of the exam. Putting the integral to work: , area between curves, accumulated change, and .[1]
Area Between Curves & Average Value
The area between y=f(x) (top) and y=g(x) (bottom) is ∫ab[f(x)−g(x)]dx — always top minus bottom. The of f on [a,b] is b−a1∫abf(x)dx. Total distance traveled by a particle is ∫∣v(t)∣dt (use the absolute value).
Volumes of Revolution
Revolve a region about an axis and integrate the cross-sectional area. Use the V=π∫R2dx when the region touches the axis, and the V=π∫(R2−r2)dxwhen a gap leaves a hollow core. For a solid with known cross sections (squares, triangles), integrate that cross-section’s area instead.
Volumes of revolution — disk vs. washer
Disk methodRegion touches the axis (no gap). Each slice is a solid disk of radius R.V = π ∫ R² dx
Washer methodA gap between region and axis. Each slice is a ring: outer radius R, inner radius r.V = π ∫ (R² − r²) dx
Use a disk when the region meets the axis of rotation, a washer when a gap leaves a hollow core. Both integrate the cross-sectional area along the axis.
Checkpoint · Unit 8 · Applications of Integration
Question 1 of 10
To find the area of the region bounded between the curves y = f(x) on top and y = g(x) on the bottom from x = a to x = b, which definite integral should be evaluated?
How to Use This Study Guide
A study guide is a map, not the whole territory — use it alongside official College Board practice (AP Classroom and released free-response questions). The eight units build on one another, so work them in order; limits underpin derivatives, and derivatives underpin integrals. Because the free-response section rewards justification and notation, practice writing out your reasoning, not just the answer.
A study loop that actually works
1
Read a unit here
Work through one unit at a time, in order — limits first, then derivatives, then integrals.
2
Take the checkpoint
The quick check at the end of each unit exposes what didn't stick.
3
Drill the gaps
Send your weak unit straight into the free practice questions and flashcards.
4
Practice full, timed work
Sit timed multiple-choice sets and released free-response questions, then review every miss and the scoring notes.
AP Calculus AB Concept Questions
The core calculus concepts the AP exam actually measures — at least one per College Board unit. Tap any card for a short, exam-ready answer backed by an official source (College Board), then test yourself on them as flashcards.
AP Calculus AB Concept · Unit 1: Limits & Continuity
What is a limit in calculus?
Quick answer
A limit is the single value a function f(x) approaches as x gets arbitrarily close to a target — written lim(x→a) f(x). The limit can exist even when f(a) is undefined; it describes where the function is headed, not necessarily where it lands.[1]
Limits are the foundation of AP Calculus AB (Unit 1) — they make both the derivative and the integral rigorous.
A two-sided limit exists only when the left-hand and right-hand limits agree.
AP Calculus AB Concept · Unit 1: Limits & Continuity
What are the three conditions for a function to be continuous at a point?
Quick answer
A function f is continuous at x = a when three things all hold: f(a) is defined, the limit lim(x→a) f(x) exists, and that limit equals f(a). If any one fails, there is a discontinuity — removable, jump, or infinite.[1]
Continuity is a Unit 1 skill and a hypothesis for major theorems (IVT, EVT, MVT, FTC).
A removable discontinuity (a hole) occurs when the limit exists but does not equal f(a).
AP Calculus AB Concept · Unit 1: Limits & Continuity
What does the Intermediate Value Theorem say?
Quick answer
The Intermediate Value Theorem says that if f is continuous on a closed interval [a, b], then f takes every value between f(a) and f(b) at least once on that interval. In particular, if f(a) and f(b) have opposite signs, f has a root between them.[1]
The IVT requires continuity on the closed interval — that hypothesis is essential and often tested.
It guarantees a value exists but does not tell you where; it is an existence theorem.
AP Calculus AB Concept · Unit 2: Differentiation Basics
What is the definition of the derivative?
Quick answer
The derivative f′(a) is the limit of the difference quotient: f′(a) = lim(h→0) [f(a + h) − f(a)] / h. Geometrically it is the slope of the line tangent to the graph at x = a — the instantaneous rate of change of f.[1]
The limit definition is a Unit 2 essential; the AP exam expects you to recognize and apply it.
The derivative exists only where this limit exists — a corner, cusp, or vertical tangent makes f nondifferentiable there.
AP Calculus AB Concept · Unit 2: Differentiation Basics
What is the power rule for derivatives?
Quick answer
The power rule says that if f(x) = xⁿ, then f′(x) = n·xⁿ⁻¹ — bring down the exponent as a coefficient and reduce the power by one. It works for any real exponent, so you can rewrite roots like √x as x^(1/2) and reciprocals like 1/x as x⁻¹ first.[1]
The power rule is the most-used differentiation tool in Unit 2 and underlies nearly every AP derivative problem.
Combine it with the constant-multiple and sum rules: the derivative of c·f is c·f′, and derivatives add term by term.
AP Calculus AB Concept · Unit 2: Differentiation Basics
What are the product rule and quotient rule?
Quick answer
The product rule: (f·g)′ = f′·g + f·g′. The quotient rule: (f/g)′ = (f′·g − f·g′) / g². Use them when a function is a product or quotient of two functions that each depend on x and cannot simply be multiplied or divided out first.[1]
These are Unit 2 rules; mixing up the order in the quotient rule's numerator is the classic error.
A memory aid for the quotient rule: 'low d-high minus high d-low, over the square of what's below.'
AP Calculus AB Concept · Unit 3: Composite, Implicit & Inverse
What is the chain rule?
Quick answer
The chain rule differentiates a composite function f(g(x)): its derivative is f′(g(x))·g′(x) — the derivative of the outer function evaluated at the inner function, times the derivative of the inner function. It is the rule for 'a function inside a function.'[1]
The chain rule is the core skill of Unit 3 and appears throughout the exam, often nested inside the product or quotient rule.
Example: d/dx sin(4x) = cos(4x)·4 = 4cos(4x); the inner derivative '4' must not be dropped.
AP Calculus AB Concept · Unit 3: Composite, Implicit & Inverse
What is implicit differentiation?
Quick answer
Implicit differentiation finds dy/dx for a curve defined by an equation that is not solved for y, such as x² + y² = 25. Differentiate both sides with respect to x, treating y as a function of x (so each y term picks up a dy/dx by the chain rule), then solve for dy/dx.[1]
Implicit differentiation is a Unit 3 skill, essential for related rates and for tangent lines to non-function curves.
Every time you differentiate a term containing y, attach dy/dx — that is what distinguishes it from ordinary differentiation.
AP Calculus AB Concept · Unit 4: Contextual Applications
How do you solve a related rates problem?
Quick answer
Related rates connect the rates of change of two quantities tied by an equation. Write the equation relating the variables, differentiate both sides with respect to time t (using the chain rule), then substitute the known values and the known rate to solve for the unknown rate.[1]
Related rates are a Unit 4 application of the chain rule; substitute numbers only after differentiating, never before.
Common setups: a circle's area as its radius grows, a ladder sliding down a wall, a draining conical tank.
AP Calculus AB Concept · Unit 4: Contextual Applications
What do velocity and acceleration mean in terms of derivatives?
Quick answer
For a particle with position s(t), velocity is the first derivative v(t) = s′(t) and acceleration is the second derivative a(t) = s″(t) = v′(t). The particle is at rest when v = 0, and it is speeding up when velocity and acceleration share the same sign.[1]
Motion along a line is a Unit 4 application of derivatives; the sign of velocity gives direction, its magnitude gives speed.
Speeding up vs. slowing down depends on whether v and a agree in sign — not on the sign of acceleration alone.
AP Calculus AB Concept · Unit 5: Analytical Applications
What does the Mean Value Theorem say?
Quick answer
The Mean Value Theorem says that if f is continuous on [a, b] and differentiable on (a, b), then there is at least one c in (a, b) where the instantaneous rate f′(c) equals the average rate [f(b) − f(a)] / (b − a). The tangent at c is parallel to the secant through the endpoints.[1]
The MVT is a Unit 5 theorem; both hypotheses — continuity on the closed interval and differentiability on the open interval — are required.
It connects average rate of change (a secant slope) to instantaneous rate of change (a tangent slope).
AP Calculus AB Concept · Unit 5: Analytical Applications
How do the first and second derivative tests find extrema?
Quick answer
At a critical point (where f′ = 0 or is undefined), the First Derivative Test checks the sign of f′ on each side: a change from + to − is a relative maximum, − to + a relative minimum. The Second Derivative Test instead uses f″ at the point: f″ > 0 means a minimum, f″ < 0 a maximum.[1]
Classifying critical points is a central Unit 5 skill for graph analysis and optimization.
If f″ = 0 at the critical point, the Second Derivative Test is inconclusive — fall back to the First Derivative Test.
AP Calculus AB Concept · Unit 6: Integration & Accumulation
What is the Fundamental Theorem of Calculus?
Quick answer
The Fundamental Theorem of Calculus links derivatives and integrals. Part 1: if g(x) = ∫ₐˣ f(t) dt, then g′(x) = f(x). Part 2 (evaluation): ∫ₐᵇ f(x) dx = F(b) − F(a), where F is any antiderivative of f. Differentiation and integration are inverse operations.[1]
The FTC is the keystone of Unit 6 and the most important theorem in the course.
Part 2 turns the hard problem of summing area into the easy problem of evaluating an antiderivative at two endpoints.
AP Calculus AB Concept · Unit 6: Integration & Accumulation
What is a Riemann sum?
Quick answer
A Riemann sum approximates the area under a curve by adding up the areas of rectangles. You split the interval into subintervals and use the function's value at the left endpoint, right endpoint, or midpoint of each as the rectangle's height. As the rectangles get thinner, the sum approaches the definite integral.[1]
Riemann sums are a Unit 6 idea — they define the definite integral as a limit of these sums.
For an increasing function, a left sum underestimates and a right sum overestimates the true area.
AP Calculus AB Concept · Unit 6: Integration & Accumulation
How do you use u-substitution to evaluate an integral?
Quick answer
U-substitution reverses the chain rule. Pick an inner function u, compute du, and rewrite the integral entirely in terms of u and du so it becomes a basic antiderivative. For a definite integral, either change the limits to u-values or convert back to x before evaluating.[1]
U-substitution is the main integration technique tested on AP Calculus AB (Unit 6).
Example: ∫ 2x(x² + 1)⁴ dx with u = x² + 1 gives du = 2x dx, so the integral becomes ∫ u⁴ du = (1/5)u⁵ + C.
AP Calculus AB Concept · Unit 7: Differential Equations
How do you solve a separable differential equation?
Quick answer
A separable differential equation can be rewritten so all the y terms (with dy) are on one side and all the x terms (with dx) are on the other. Integrate both sides, add the constant C, then use an initial condition to find C and produce the particular solution.[1]
Separable equations are the only type solved analytically on AP Calculus AB (Unit 7).
The equation dy/dt = k·y models exponential growth or decay; its solution is y = y₀·e^(kt).
AP Calculus AB Concept · Unit 7: Differential Equations
What is a slope field?
Quick answer
A slope field is a grid of short line segments, each drawn at a point with the slope that the differential equation dy/dx = f(x, y) gives there. It pictures the family of solution curves: a solution through any point follows the direction of the nearby segments without crossing them.[1]
Slope fields are a Unit 7 way to visualize a differential equation without solving it.
Segments are horizontal where dy/dx = 0 and steep where the slope is large in magnitude.
AP Calculus AB Concept · Unit 8: Applications of Integration
How do you find the area between two curves?
Quick answer
The area between curves y = f(x) (top) and y = g(x) (bottom) from x = a to x = b is ∫ₐᵇ [f(x) − g(x)] dx — always top minus bottom. First find where the curves intersect to set the limits, and check which function is on top over that interval.[1]
Area between curves is a Unit 8 application; subtracting in the wrong order flips the sign of the area.
If the curves cross within the interval, split the integral so 'top minus bottom' stays correct on each piece.
AP Calculus AB Concept · Unit 8: Applications of Integration
What is the average value of a function?
Quick answer
The average value of a continuous function f on [a, b] is (1 / (b − a)) · ∫ₐᵇ f(x) dx — the total accumulation divided by the length of the interval. It is the constant height of a rectangle on [a, b] with the same area as the region under f.[1]
Average value is a Unit 8 application of the definite integral, distinct from the average rate of change.
The Mean Value Theorem for Integrals guarantees f actually attains this average value somewhere on [a, b].
Quick definitions for the terms and theorems you’ll see most across AP Calculus AB:
Accumulation function
A function defined by an integral with a variable upper limit, g(x)=∫axf(t)dt; its derivative is f(x).
Antiderivative
A function F whose derivative is f. The indefinite integral ∫f(x)dx=F(x)+C.
Average value
The average value of f on [a,b] is b−a1∫abf(x)dx.
Chain rule
The derivative of a composite f(g(x)) is f′(g(x))⋅g′(x) — outer derivative times inner derivative.
Concavity
The way a curve bends: concave up where f′′(x)>0 (cups upward) and concave down where f′′(x)<0.
Continuity
A function f is continuous at x=a when f(a) is defined, limx→af(x) exists, and the limit equals f(a).
Critical point
A point where f′(x)=0 or f′(x) is undefined — a candidate for a relative maximum or minimum.
Definite integral
∫abf(x)dx — the signed area between f and the x-axis from a to b; a limit of Riemann sums.
Derivative
The instantaneous rate of change of f, defined as f′(a)=limh→0hf(a+h)−f(a) — the slope of the tangent line at x=a.
Difference quotient
The average rate of change hf(a+h)−f(a) — the slope of a secant line; its limit as h→0 is the derivative.
Disk method
Finds a volume of revolution with no gap to the axis: V=π∫R2dx, where R is the radius of each slice.
Exponential growth
Change modeled by dtdy=ky, whose solution is y=y0ekt; the rate of change is proportional to the current amount.
Extreme Value Theorem
A function continuous on a closed, bounded interval attains both an absolute maximum and an absolute minimum on that interval.
Fundamental Theorem of Calculus
Links derivatives and integrals: dxd∫axf(t)dt=f(x) (Part 1) and ∫abf(x)dx=F(b)−F(a) (Part 2).
Implicit differentiation
Finding dxdy from an equation not solved for y by differentiating both sides in x and treating y as a function of x.
Inflection point
A point where a graph's concavity changes — where f′′(x) changes sign.
Intermediate Value Theorem
If f is continuous on [a,b], it takes every value between f(a) and f(b); opposite signs guarantee a root in between.
L'Hopital's Rule
For a limit in the indeterminate form 00 or ∞∞, the limit equals limg′(x)f′(x).
Limit
The single value a function approaches as the input approaches a target. Written limx→af(x), it can exist even when f(a) is undefined.
Linearization
Using the tangent line at x=a, L(x)=f(a)+f′(a)(x−a), to estimate f near a.
Mean Value Theorem
If f is continuous on [a,b] and differentiable on (a,b), some c gives f′(c)=b−af(b)−f(a).
One-sided limit
The value a function approaches from only the left (x→a−) or only the right (x→a+). A two-sided limit exists only when both one-sided limits agree.
Power rule
If f(x)=xn, then f′(x)=nxn−1 for any real exponent n.
Product rule
(f⋅g)′=f′g+fg′ — used to differentiate a product of two functions of x.
Quotient rule
(gf)′=g2f′g−fg′ — used to differentiate a quotient of two functions.
Related rates
A problem that links the time rates of two quantities sharing an equation; you differentiate the equation with respect to t and solve for the unknown rate.
Removable discontinuity
A 'hole' in a graph where the limit exists but does not equal the function's value (or the value is undefined), often from a common factor that cancels.
Riemann sum
An approximation of area using rectangles whose heights come from the function at left endpoints, right endpoints, or midpoints of subintervals.
Separable differential equation
A differential equation that can be written so all y-terms (with dy) are on one side and all x-terms (with dx) on the other, then integrated.
Slope field
A grid of short segments, each with slope dxdy=f(x,y) at that point, picturing the solution curves of a differential equation.
Squeeze theorem
If g(x)≤f(x)≤h(x) near a and g and h share the same limit L at a, then f also has limit L.
u-substitution
An integration technique that reverses the chain rule: substitute u for an inner function so the integral becomes a basic antiderivative.
Washer method
Finds a volume of revolution with a gap to the axis: V=π∫(R2−r2)dx, outer radius R, inner radius r.
Free AP Calculus AB Study Materials & Resources
Everything you need to prepare for AP Calculus AB is free here — no paywall, no sign-up. This guide is the foundation; pair it with the rest of our free AP Calculus AB study materials for active recall, timed practice, and last-minute review:
AP Calculus AB Flashcards — active-recall decks for the derivative rules, integral forms, and theorems you must know cold.
AP Calculus AB Study Guide FAQ
The AP Calculus AB exam has 45 multiple-choice questions and 6 free-response questions. Multiple choice is split into Part A (30 questions, no calculator, 60 minutes) and Part B (15 questions, calculator, 45 minutes). Free response has Part A (2 questions, calculator) and Part B (4 questions, no calculator).
The exam runs about 3 hours and 15 minutes: 1 hour 45 minutes for the 45 multiple-choice questions and 1 hour 30 minutes for the 6 free-response questions. Multiple choice and free response are each worth 50% of the score.
AP exams are scored from 1 to 5. A 3 is generally considered passing and is the most common threshold for college credit or placement, though some selective colleges require a 4 or 5. Each college sets its own credit policy, so check the school you plan to attend.
The College Board organizes the course into 8 units: Limits and Continuity; Differentiation Definition and Fundamental Properties; Differentiation of Composite, Implicit, and Inverse Functions; Contextual Applications of Differentiation; Analytical Applications of Differentiation; Integration and Accumulation of Change; Differential Equations; and Applications of Integration.
Integration and Accumulation of Change (Unit 6, 17–20%) and Analytical Applications of Differentiation (Unit 5, 15–18%) carry the most weight on multiple choice, followed by Contextual Applications (Unit 4) and Applications of Integration (Unit 8), each 10–15%. Together, integration and the analytical use of derivatives make up roughly half the exam.
A graphing calculator is required for two parts of the exam — Section I Part B (15 multiple-choice questions) and Section II Part A (2 free-response questions). The other two parts must be worked entirely by hand. Bring a College Board–approved graphing calculator.
AP Calculus AB covers roughly the first two semesters of college calculus — limits, derivatives, integrals, and their applications. AP Calculus BC covers all of AB plus additional topics such as series, parametric and polar functions, and more integration techniques. AB is the smaller, more focused course.
Work through the 8 units in order — each builds on the last, from limits to derivatives to integrals. After each unit, take the checkpoint quiz to find your gaps, then drill that unit with our free practice questions and flashcards. Spend extra time on the heaviest units (6, 5, 4, and 8) and on free-response notation.
Yes — the full guide, the checkpoints, the glossary, the practice questions, and the flashcards are 100% free, with no account required.
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