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Your FREE ALEKS PPL Math Placement Practice Test 2026 – 220+ Q&A

Prepare with realistic, ALEKS PPL-style questions — take a full ALEKS practice test or drill one math topic at a time.

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Click Start Test above to launch a full-length ALEKS practice test spanning every math topic, or drill a single area — real numbers, equations and inequalities, functions, polynomials, rational and radical expressions, logarithms, or geometry and trigonometry. Every question includes a clear explanation so you learn the reasoning, not just the answer.

The ALEKS PPL (Placement, Preparation and Learning) assessment is an online, adaptive math placement test used by colleges and universities to decide which math course you are ready to take.

It is published by ALEKS Corporation (McGraw Hill) and adapts to your answers in real time, probing across about 314 math topics to pinpoint exactly what you know.[1] It is delivered fully online, often with online proctoring.

One important note: the real ALEKS uses open-response questions you build with an on-screen math toolbar — it is not multiple choice.[2] This free practice test uses multiple-choice questions to help you review the same topics quickly; expect open-response items on the official assessment.

These practice questions follow the published ALEKS PPL topic list so you can build readiness across the full range of skills.[3] To go deeper, pair these with our free study guide, flashcards, and cheat sheet.

Formats, score cutoffs, and policies are set by ALEKS and your individual school — always verify the current details at aleks.com and with your institution before you test.

ALEKS at a Glance

ALEKS PPL at a glance
DetailALEKS PPL
FormatOnline, adaptive (questions adjust to your answers)
QuestionsAbout 25 or fewer per assessment, drawn from ~314 topics
Question typeOpen-response on the real exam (this practice uses multiple choice)
Time limitAbout 90 minutes to complete
ResultPlacement score 0-100 (no universal pass/fail)
CutoffsEach school sets its own course-placement cutoffs
Published byALEKS Corporation (McGraw Hill)
RetakesUsually up to 5 attempts; Prep & Learning Module hours required between

What Is on the ALEKS Assessment?

The ALEKS PPL placement assessment spans eight broad math areas, from real numbers and basic algebra up through exponentials, logarithms, and trigonometry. Because it is adaptive, it keeps asking questions until it finds the edge of what you can do.[2]

Our full practice test mirrors that range so you can see your readiness across every topic area at once:

ALEKS practice coverage by topic
Real Numbers13% · fractions, integers, percentages
Equations & Inequalities13% · linear, systems, quadratics
Linear & Quadratic Functions13% · graphs, lines, parabolas
Exponents & Polynomials13% · factoring, polynomial equations
Rational Expressions13% · rational equations & functions
Radical Expressions13% · roots, rational exponents
Exponentials & Logarithms10% · inverses, log properties
Geometry & Trigonometry10% · area, volume, trig

The official ALEKS does not publish fixed per-topic weightings because the adaptive engine decides what to ask based on your responses — so treat the coverage above as a balanced way to practice the whole syllabus, not as the exact mix you will see.

ALEKS practice test — practice questions by math topic with answer explanations

Practice Questions by Topic

Use Start Test for a full ALEKS-style simulation, or open the hub and pick a single topic to target your weak area. After each full test, your results show a per-topic breakdown so you know exactly where to focus before you reassess in the official Prep and Learning Module.

Who Takes the ALEKS Placement Assessment?

The ALEKS PPL assessment is taken by incoming and transfer college students whose institution requires a math placement before they can register for math-bearing courses.[1] There is no formal prerequisite to sit it.

Most schools assign it to first-year students, but it is also common for returning students and anyone changing into a STEM major. Whether you take it depends entirely on your college’s placement policy.

Because requirements vary, confirm with your school whether ALEKS is required, which proctoring option you must use, and how recent your result has to be — placement scores typically expire after a set window such as six to twelve months.

How Do You Take the ALEKS?

You access the ALEKS PPL assessment through your school’s ALEKS portal or a link your institution provides, usually after paying any required access fee bundled by the college.[4]

Many schools require the placement attempt that counts to be proctored — either at a campus testing center or through online proctoring with a webcam — while a first, unproctored practice attempt may be allowed to gauge where you stand.

Before you start, ALEKS walks you through a short tools tutorial so you can practice entering open-response answers with the on-screen math toolbar. Have a quiet space, a valid photo ID for proctored attempts, and scratch paper ready.

Verify the exact steps, fees, and proctoring rules with your institution and at aleks.com, since these are set per school and can change.

How Is the ALEKS Scored?

The ALEKS PPL assessment produces a single placement score from 0 to 100 along with subscores across the topic areas, and there is no national pass/fail standard.[3]

Each college maps score ranges to specific courses, so the same number can place you differently from one school to the next. As a rough industry pattern, many institutions place into college algebra or precalculus in the 61 to 75 range and into calculus at 76 and above — but only your school’s published cutoffs are authoritative.

Your subscores show relative strengths and weaknesses across topics like equations, rational expressions, and logarithms, which is exactly what the Prep and Learning Module then targets to help you raise your placement on a retake.

How Hard Is the ALEKS?

The ALEKS is challenging mainly because of its breadth and adaptivity — it can reach well beyond what you last studied, and because it is open-response there is no guessing your way through.[2] It is not pass/fail, so the real question is how high you place, not whether you “pass.”

The adaptive engine ramps difficulty as you answer correctly, so strong students still face questions at the edge of their ability — that is by design, since the goal is to find your true placement level.

Open-response entry also rewards genuine fluency: you must produce exact answers, simplify correctly, and use the math toolbar accurately. Reviewing each topic until you can solve cleanly without prompts is what moves your score.

0-100
Placement score range
no pass/fail
~25
Questions per assessment
from ~314 topics
5
Attempts allowed
study hours between

The takeaway: practice every topic until you can solve it cleanly, then spend the required hours in the official Prep and Learning Module before each retake — that combination is what reliably raises an ALEKS placement.

What to Expect on Test Day

For a proctored ALEKS attempt, you check in with a valid government-issued photo ID and, for online proctoring, a working webcam and a clear desk.[4] You may use the provided scratch paper and on-screen tools, but not outside notes or your own calculator unless allowed.

A short tutorial first lets you practice the answer-entry tools, then you work through the adaptive assessment — about 25 open-response questions or fewer — at your own pace within the roughly 90-minute window.

Your placement score is available essentially right away, along with a personalized Prep and Learning Module that targets the topics you missed so you can improve before any retake. Having simulated the topic mix with practice tests makes the real assessment feel familiar.

How to Use This ALEKS Practice Test

  • Cover the whole syllabus. Take the full test to see every topic, since ALEKS is adaptive and wide-ranging.[2]
  • Diagnose, then drill. Use a full simulation to find weak topics, then drill them one at a time.
  • Practice solving, not guessing. The real test is open-response — work each answer out fully before checking.
  • Learn the why. Read every explanation so you can reproduce the method, not just recognize the answer.
  • Bridge to the official module. Spend the required hours in the ALEKS Prep and Learning Module before you reassess.

Why the ALEKS Matters

Your ALEKS placement decides which math course you start in — and that single result can save you a semester (and tuition) by placing you out of remedial math, or set you up to succeed by placing you where you can actually keep up.[5] Because each school sets its own cutoffs, even a few points can change your placement, so practicing every topic until it is automatic is the highest-leverage prep you can do. These free ALEKS practice tests are the most efficient way to get there.

Conclusion

Doing well on the ALEKS comes down to broad math fluency — from fractions and algebra to functions, logarithms, and trigonometry — plus the ability to produce exact answers on an adaptive, open-response test. Use this free ALEKS practice test to find your weak topics, drill them to mastery, and pair it with our free study guide, flashcards, and cheat sheet so you place into the course you want.

ALEKS Practice Test FAQ

ALEKS PPL (Placement, Preparation and Learning) is an online, adaptive math placement assessment from ALEKS Corporation (McGraw Hill). Colleges and universities use it to determine which math course a new or transfer student is ready for, from basic math up through calculus. It is intended for incoming students whose institution requires a math placement before registration.

ALEKS question bank

All 223 questions, by domain

A reference copy of every question in this practice test. Each answer stays hidden until you choose to show it. To practice with scoring, timing and your readiness score, use Start Test at the top of the page.

Real Numbers (fractions, integers, percentages) (33)

  1. Evaluate the expression 24 - 4 squared / 2 + 6 using the order of operations.

    • A.166
    • B.22
    • C.30
    • D.8
    Show answerHide answer

    Correct answer: 22

    The value is 22. Order of operations requires exponents first: 4 squared is 16. Then division: 16 divided by 2 is 8. The expression becomes 24 - 8 + 6, and working left to right gives 24 - 8 = 16, then 16 + 6 = 22. Subtracting 8 only after adding 6 to it would change the grouping and give a different, incorrect value.

  2. Which calculation correctly applies the order of operations to 2 + 6 / 3 x 4?

    • A.Divide 6 by 3, multiply by 4, then add 2 to get 10.
    • B.Add 2 and 6, divide by 3, then multiply by 4 to get about 10.7.
    • C.Multiply 3 by 4, divide 6 by 12, then add 2 to get 2.5.
    • D.Add everything in sequence to get 6.
    Show answerHide answer

    Correct answer: Divide 6 by 3, multiply by 4, then add 2 to get 10.

    The correct approach divides 6 by 3, multiplies by 4, then adds 2 to get 10. Multiplication and division share the same priority and are performed left to right, so 6 / 3 is done first to get 2, then 2 x 4 gives 8, and finally 2 + 8 equals 10. Multiplying 3 by 4 first violates the left-to-right rule for operations of equal priority, which is why that path produces a wrong result.

  3. Find 7/12 + 3/8 and write the answer in lowest terms.

    • A.10/20
    • B.23/24
    • C.5/10
    • D.17/24
    Show answerHide answer

    Correct answer: 23/24

    The sum is 23/24. The least common denominator of 12 and 8 is 24, so 7/12 becomes 14/24 and 3/8 becomes 9/24. Adding the numerators gives 14 + 9 = 23, producing 23/24, which has no common factor to reduce. The choice 10/20 comes from adding numerators and denominators straight across, which is not how fractions are added.

  4. Subtract 2 1/3 - 5/6 and express the result as a mixed number in lowest terms.

    • A.1 1/3
    • B.2 1/2
    • C.1 5/6
    • D.1 1/2
    Show answerHide answer

    Correct answer: 1 1/2

    The difference is 1 1/2. Rewriting 2 1/3 as an improper fraction gives 7/3, and using a common denominator of 6 turns 7/3 into 14/6 and leaves 5/6 unchanged. Subtracting gives 14/6 - 5/6 = 9/6, which reduces to 3/2, or 1 1/2 as a mixed number. Subtracting only the fraction parts while ignoring the borrowing needed from the whole number would give an incorrect smaller value.

  5. What is 4/9 of 6/10, written in lowest terms?

    • A.10/19
    • B.24/90
    • C.4/15
    • D.2/3
    Show answerHide answer

    Correct answer: 4/15

    The product is 4/15. The word 'of' signals multiplication, so multiply numerators and denominators: 4 x 6 = 24 and 9 x 10 = 90, giving 24/90. Dividing both parts by their greatest common factor 6 reduces 24/90 to 4/15. The choice 24/90 is the same value before reducing, so it is not in lowest terms.

  6. A recipe calls for 3/4 cup of flour per batch. How many full batches can be made from 6 cups of flour?

    • A.4 1/2
    • B.6
    • C.8
    • D.9
    Show answerHide answer

    Correct answer: 8

    The answer is 8 batches. Finding how many 3/4-cup portions fit into 6 cups means dividing 6 by 3/4, which equals multiplying 6 by the reciprocal 4/3. That gives 24/3 = 8, so exactly 8 full batches can be made. Multiplying 6 by 3/4 instead of dividing would wrongly give 4 1/2, but that asks how much flour, not how many batches.

  7. Convert the fraction 5/8 to a decimal.

    • A.0.58
    • B.0.625
    • C.0.85
    • D.0.16
    Show answerHide answer

    Correct answer: 0.625

    The decimal form is 0.625. Dividing the numerator by the denominator, 5 divided by 8 equals 0.625, a terminating decimal. The value 0.58 simply rearranges the original digits rather than performing the division, so it does not represent the same quantity as 5/8.

  8. A shirt costs $32 before tax. With an 8% sales tax added, what is the total price?

    • A.$40.00
    • B.$32.08
    • C.$34.56
    • D.$33.60
    Show answerHide answer

    Correct answer: $34.56

    The total price is $34.56. The tax is 8% of $32, which is 0.08 x 32 = $2.56. Adding the tax to the original price gives 32 + 2.56 = $34.56. Treating 8% as $8 and adding it to get $40.00 misreads the percent as a flat dollar amount rather than a fraction of the price.

  9. 45 is what percent of 180?

    • A.40%
    • B.4%
    • C.75%
    • D.25%
    Show answerHide answer

    Correct answer: 25%

    The answer is 25%. To find what percent one number is of another, divide the part by the whole and multiply by 100: 45 divided by 180 equals 0.25, which is 25%. Dividing in the reverse order, 180 by 45, would give 4 and lead to a wrong reading of 400%, so the part must always be divided by the whole.

  10. A blueprint uses a scale where 2 inches represents 15 feet. How many feet does a length of 9 inches represent?

    • A.67.5
    • B.30
    • C.120
    • D.22.5
    Show answerHide answer

    Correct answer: 67.5

    The length represents 67.5 feet. Setting up the proportion 2 inches over 15 feet equal to 9 inches over x feet and cross-multiplying gives 2x = 15 x 9 = 135, so x = 67.5 feet. The value 30 comes from multiplying the 15 feet by the ratio of inches incorrectly, ignoring that 9 inches is 4.5 times the 2-inch unit, which must scale the 15 feet by the same factor.

  11. Evaluate -7 + (-12) - (-5).

    • A.-14
    • B.-24
    • C.-10
    • D.24
    Show answerHide answer

    Correct answer: -14

    The result is -14. Adding two negatives, -7 + (-12), gives -19, and subtracting a negative is the same as adding its positive, so -19 - (-5) becomes -19 + 5 = -14. Treating the final subtraction as a further decrease would give -24, but subtracting a negative always moves the value upward.

  12. What is the product of -6 and -9?

    • A.-54
    • B.54
    • C.-15
    • D.15
    Show answerHide answer

    Correct answer: 54

    The product is 54. Multiplying two negative numbers yields a positive result, so -6 times -9 equals positive 54. The choice -54 keeps a negative sign, but a negative times a negative cannot stay negative.

  13. Evaluate -48 divided by -8.

    • A.6
    • B.-6
    • C.-40
    • D.40
    Show answerHide answer

    Correct answer: 6

    The quotient is 6. Dividing a negative by a negative produces a positive result, and 48 divided by 8 is 6, so the answer is positive 6. The choice -6 keeps the result negative, but matching signs in a quotient always give a positive value.

  14. Simplify the expression |{-15}| - |{8}|.

    • A.-7
    • B.23
    • C.7
    • D.-23
    Show answerHide answer

    Correct answer: 7

    The value is 7. The absolute value of -15 is 15 and the absolute value of 8 is 8, so the expression becomes 15 - 8 = 7. The choice -7 reverses the subtraction order, but the bars are evaluated first and then 15 - 8 is computed as written.

  15. What is the absolute value of the expression 4 - 11?

    • A.7
    • B.-7
    • C.15
    • D.-15
    Show answerHide answer

    Correct answer: 7

    The answer is 7. Inside the bars, 4 - 11 equals -7, and the absolute value of -7 is its distance from zero, which is 7. The choice -7 stops before applying the absolute value, but the bars require a nonnegative result.

  16. Find the greatest common factor of 36 and 60.

    • A.6
    • B.18
    • C.12
    • D.180
    Show answerHide answer

    Correct answer: 12

    The greatest common factor is 12. The factors of 36 include 1, 2, 3, 4, 6, 9, 12, 18, and 36, while 60 has factors including 12, and 12 is the largest value dividing both evenly. The choice 6 also divides both numbers but is not the greatest such factor, since 12 is larger and still divides each.

  17. What is the least common multiple of 8 and 12?

    • A.96
    • B.4
    • C.24
    • D.48
    Show answerHide answer

    Correct answer: 24

    The least common multiple is 24. Multiples of 8 are 8, 16, 24, 32, and multiples of 12 are 12, 24, 36, so the smallest value appearing in both lists is 24. The choice 96 is a common multiple because 8 times 12 equals 96, but it is not the least common multiple.

  18. Express the fraction 18/24 in lowest terms.

    • A.9/12
    • B.6/8
    • C.3/4
    • D.2/3
    Show answerHide answer

    Correct answer: 3/4

    In lowest terms the fraction is 3/4. The greatest common factor of 18 and 24 is 6, and dividing both the numerator and denominator by 6 gives 18 divided by 6 equals 3 and 24 divided by 6 equals 4. The choice 9/12 divides only by 2, leaving a fraction that can still be reduced further.

  19. Write the improper fraction 23/5 as a mixed number.

    • A.4 3/5
    • B.3 4/5
    • C.5 3/4
    • D.4 4/5
    Show answerHide answer

    Correct answer: 4 3/5

    The mixed number is 4 3/5. Dividing 23 by 5 gives a whole-number part of 4 with a remainder of 3, and the remainder becomes the new numerator over the original denominator 5. The choice 3 4/5 swaps the whole-number part and the numerator, which does not match the division result.

  20. Convert the mixed number 3 2/7 to an improper fraction.

    • A.6/7
    • B.23/7
    • C.11/7
    • D.5/7
    Show answerHide answer

    Correct answer: 23/7

    The improper fraction is 23/7. Multiply the whole number 3 by the denominator 7 to get 21, then add the numerator 2 to reach 23, keeping the same denominator 7. The choice 6/7 multiplies the whole number by the numerator instead of the denominator, which is not the correct procedure.

  21. Which symbol correctly compares the fractions 5/8 and 7/12?

    • A.5/8 = 7/12
    • B.5/8 < 7/12
    • C.5/8 > 7/12
    • D.Cannot be determined
    Show answerHide answer

    Correct answer: 5/8 > 7/12

    The correct comparison is 5/8 > 7/12. Using a common denominator of 24, 5/8 becomes 15/24 and 7/12 becomes 14/24, and since 15/24 is larger than 14/24 the first fraction is greater. The choice 5/8 < 7/12 reverses the comparison, which the common-denominator numerators 15 and 14 contradict.

  22. Convert the decimal 0.45 to a fraction in lowest terms.

    • A.45/100
    • B.4/5
    • C.9/20
    • D.45/1000
    Show answerHide answer

    Correct answer: 9/20

    The fraction is 9/20. The decimal 0.45 means 45 hundredths, written as 45/100, and dividing both parts by their greatest common factor 5 gives 9/20. The choice 45/100 is correct before reducing but is not in lowest terms as requested.

  23. Write 0.7 as a percent.

    • A.0.7%
    • B.7%
    • C.70%
    • D.700%
    Show answerHide answer

    Correct answer: 70%

    The percent is 70%. Converting a decimal to a percent multiplies by 100, which moves the decimal point two places to the right, turning 0.7 into 70%. The choice 7% moves the decimal only one place, which undercounts the value by a factor of ten.

  24. Write 125% as a decimal.

    • A.12.5
    • B.1.25
    • C.0.125
    • D.125
    Show answerHide answer

    Correct answer: 1.25

    The decimal is 1.25. Converting a percent to a decimal divides by 100, moving the decimal point two places to the left, so 125% becomes 1.25. The choice 12.5 moves the point only one place, which leaves the value ten times too large.

  25. Round the number 4.768 to the nearest tenth.

    • A.4.7
    • B.4.8
    • C.4.77
    • D.5.0
    Show answerHide answer

    Correct answer: 4.8

    Rounded to the nearest tenth the number is 4.8. The tenths digit is 7, and the digit just after it is 6, which is 5 or greater, so the tenths digit rounds up from 7 to 8. The choice 4.7 keeps the tenths digit unchanged, ignoring that the following 6 forces a round-up.

  26. Add the decimals 3.6 + 0.45 + 12.

    • A.16.05
    • B.4.83
    • C.16.5
    • D.15.81
    Show answerHide answer

    Correct answer: 16.05

    The sum is 16.05. Aligning the decimal points and treating 12 as 12.00 gives 3.60 + 0.45 + 12.00, and adding column by column yields 16.05. The choice 4.83 results from adding the digits without aligning place values, which mixes tenths and hundredths incorrectly.

  27. Multiply 0.6 by 0.04.

    • A.0.24
    • B.2.4
    • C.0.024
    • D.0.0024
    Show answerHide answer

    Correct answer: 0.024

    The product is 0.024. Multiplying 6 by 4 gives 24, and since 0.6 has one decimal place and 0.04 has two, the product must have three decimal places, placing the digits as 0.024. The choice 0.24 uses only two decimal places, which misplaces the decimal point by one position.

  28. What is 30% of 250?

    • A.75
    • B.83.3
    • C.7.5
    • D.750
    Show answerHide answer

    Correct answer: 75

    The answer is 75. Finding a percent of a number multiplies the decimal form of the percent by the number, so 0.30 times 250 equals 75. The choice 7.5 misplaces the decimal point by treating 30% as 0.03 instead of 0.30.

  29. A jacket originally priced at $80 is marked down by 25%. What is the sale price?

    • A.$55
    • B.$20
    • C.$75
    • D.$60
    Show answerHide answer

    Correct answer: $60

    The sale price is $60. A 25% discount on $80 is 0.25 times 80, or $20, and subtracting that discount gives 80 - 20 = $60. The choice $20 reports only the amount of the discount rather than the price the shopper actually pays.

  30. A town's population grew from 4,000 to 4,600 in one year. What was the percent increase?

    • A.6%
    • B.60%
    • C.15%
    • D.13%
    Show answerHide answer

    Correct answer: 15%

    The percent increase is 15%. The amount of increase is 4,600 - 4,000 = 600, and dividing the increase by the original amount, 600 divided by 4,000, gives 0.15, or 15%. The choice 13% incorrectly divides the increase by the new population instead of the original value.

  31. The ratio of cats to dogs at a shelter is 3 to 5. If there are 24 cats, how many dogs are there?

    • A.40
    • B.14
    • C.45
    • D.8
    Show answerHide answer

    Correct answer: 40

    There are 40 dogs. Setting the ratio 3 cats to 5 dogs equal to 24 cats to x dogs and cross-multiplying gives 3x = 5 times 24 = 120, so x = 40. The choice 14 comes from adding the difference between 24 and 3 to 5, which ignores that the two quantities scale by the same multiplier.

  32. A car travels 165 miles using 5 gallons of gas. At this rate, how many miles can it travel on 8 gallons?

    • A.264
    • B.33
    • C.132
    • D.320
    Show answerHide answer

    Correct answer: 264

    The car can travel 264 miles. The unit rate is 165 divided by 5, which equals 33 miles per gallon, and multiplying 33 by 8 gallons gives 264 miles. The choice 33 reports only the miles per gallon, not the total distance for 8 gallons.

  33. Estimate the value of 50\sqrt{50} to the nearest whole number.

    • A.8
    • B.6
    • C.25
    • D.7
    Show answerHide answer

    Correct answer: 7

    The closest whole number is 7. Since 7 squared is 49 and 8 squared is 64, 50\sqrt{50} lies between 7 and 8, and because 50 is just above 49 it rounds to 7. The choice 25 results from dividing 50 by 2 rather than finding a number whose square is near 50.

Equations and Inequalities (linear equations, linear inequalities, systems, quadratic equations) (33)

  1. Solve the linear equation 5(x - 3) + 4 = 2x + 7 for x.

    • A.6
    • B.2
    • C.9
    • D.4
    Show answerHide answer

    Correct answer: 6

    The solution is x = 6. Distributing the 5 gives 5x - 15 + 4 = 2x + 7, which simplifies to 5x - 11 = 2x + 7. Subtracting 2x from both sides and adding 11 gives 3x = 18, so x = 6. Forgetting to distribute the 5 to the -3 inside the parentheses would drop the -15 term and lead to a smaller, incorrect value.

  2. A taxi charges a flat fee of $4 plus $2.50 per mile. If a ride costs $26.50, the relationship is 4 + 2.5m = 26.50. How many miles was the ride?

    • A.12.2
    • B.11
    • C.9
    • D.9.4
    Show answerHide answer

    Correct answer: 9

    The ride was 9 miles. Subtracting the flat fee from both sides gives 2.5m = 22.50, and dividing both sides by 2.5 gives m = 9. Dividing the full $26.50 by 2.5 without first removing the $4 flat fee would overstate the distance, because the flat fee is charged once rather than per mile.

  3. Solve the inequality -3x + 5 > 14 and choose the correct solution set.

    • A.X > -3
    • B.X < -3
    • C.X > 3
    • D.X < 3
    Show answerHide answer

    Correct answer: X < -3

    The solution is x < -3. Subtracting 5 from both sides gives -3x > 9, and dividing both sides by -3 requires reversing the inequality symbol, producing x < -3. Keeping the symbol as 'greater than' after dividing by a negative number is the classic error, since dividing an inequality by a negative value always flips the direction of the sign.

  4. Which graph on a number line correctly represents the solution to 2x - 1 <= 7?

    • A.An open circle at 4 shading to the right
    • B.A closed circle at 4 shading to the left
    • C.A closed circle at 4 shading to the right
    • D.An open circle at 4 shading to the left
    Show answerHide answer

    Correct answer: A closed circle at 4 shading to the left

    The correct picture is a closed circle at 4 shading to the left. Adding 1 to both sides gives 2x <= 8, then dividing by 2 gives x <= 4, so 4 itself is included and all smaller values satisfy the inequality. A closed (filled) circle marks that 4 is part of the solution, and shading left covers the values less than 4; an open circle would wrongly exclude 4.

  5. Solve the absolute value equation |2x - 5| = 9 for all values of x.

    • A.X = 7 only
    • B.X = 2 and x = -7
    • C.X = 7 and x = -2
    • D.X = -2 only
    Show answerHide answer

    Correct answer: X = 7 and x = -2

    The solutions are x = 7 and x = -2. An absolute value equal to 9 means the inside expression equals either 9 or -9, giving two equations: 2x - 5 = 9 yields x = 7, and 2x - 5 = -9 yields x = -2. Solving only the positive case and reporting x = 7 alone misses the second branch, which is why absolute value equations typically produce two solutions.

  6. Solve the system of equations: 3x + y = 11 and x - y = 1.

    • A.X = 3, y = 2
    • B.X = 2, y = 5
    • C.X = 4, y = -1
    • D.X = 1, y = 8
    Show answerHide answer

    Correct answer: X = 3, y = 2

    The solution is x = 3 and y = 2. Adding the two equations eliminates y because y and -y cancel, giving 4x = 12, so x = 3. Substituting x = 3 into x - y = 1 gives 3 - y = 1, so y = 2. The ordered pair (3, 2) satisfies both equations, while a pair that works in only one equation cannot be the system's solution.

  7. A vendor sells adult tickets for $8 and child tickets for $5. On a day with 200 tickets sold for $1,330 total, the system is a + c = 200 and 8a + 5c = 1330. How many adult tickets were sold?

    • A.90
    • B.120
    • C.80
    • D.110
    Show answerHide answer

    Correct answer: 110

    The vendor sold 110 adult tickets. Solving a + c = 200 for c gives c = 200 - a, and substituting into 8a + 5c = 1330 gives 8a + 5(200 - a) = 1330, which simplifies to 3a + 1000 = 1330, so 3a = 330 and a = 110. Substituting c instead of solving for the adult count, or mixing up which price goes with which ticket type, would produce a count that fails the revenue equation.

  8. Solve the quadratic equation x2−7x+12=0 x^2 - 7x + 12 = 0 by factoring.

    • A.X = -3 and x = -4
    • B.X = 3 and x = 4
    • C.X = 2 and x = 6
    • D.X = -2 and x = -6
    Show answerHide answer

    Correct answer: X = 3 and x = 4

    The solutions are x = 3 and x = 4. The trinomial factors into (x - 3)(x - 4) because -3 and -4 multiply to +12 and add to -7. Setting each factor equal to zero gives x = 3 and x = 4. Choosing -3 and -4 reverses the signs; those values multiply to +12 but add to -7 only when the factors are (x - 3)(x - 4), so the roots are the positive numbers.

  9. Use the quadratic formula to solve 2x2+3x−2=0 2x^2 + 3x - 2 = 0 .

    • A.x=12 x = \frac{1}{2} and x=−2 x = -2
    • B.x=−12 x = -\frac{1}{2} and x=2 x = 2
    • C.x=2 x = 2 and x=−3 x = -3
    • D.x=−1 x = -1 and x=2 x = 2
    Show answerHide answer

    Correct answer: x=12 x = \frac{1}{2} and x=−2 x = -2

    The solutions are x=12 x = \frac{1}{2} and x=−2 x = -2 . With a=2 a = 2 , b=3 b = 3 , and c=−2 c = -2 , the discriminant b2−4ac b^2 - 4ac equals 9−4(2)(−2)=9+16=25 9 - 4(2)(-2) = 9 + 16 = 25 , whose square root is 5. The formula gives x=−3±54 x = \frac{-3 \pm 5}{4} , producing −3+54=12 \frac{-3 + 5}{4} = \frac{1}{2} and −3−54=−2 \frac{-3 - 5}{4} = -2 . Treating the c value as +2 instead of -2 would make the discriminant smaller and yield the wrong roots.

  10. For the equation 3x2−5x+4=0 3x^2 - 5x + 4 = 0 , the quadratic formula uses the discriminant b2−4ac b^2 - 4ac . What does the discriminant reveal about the solutions?

    • A.Two distinct real solutions, because the discriminant is positive
    • B.Exactly one real solution, because the discriminant is zero
    • C.No real solutions, because the discriminant is negative
    • D.Three solutions, because the equation is quadratic
    Show answerHide answer

    Correct answer: No real solutions, because the discriminant is negative

    The equation has no real solutions because the discriminant is negative. With a=3 a = 3 , b=−5 b = -5 , and c=4 c = 4 , the discriminant b2−4ac b^2 - 4ac equals 25−4(3)(4)=25−48=−23 25 - 4(3)(4) = 25 - 48 = -23 . A negative value under the square root means no real number satisfies the equation. Concluding two real solutions would require a positive discriminant, which this equation does not have.

  11. Solve the linear equation 6x+11=4x−3 6x + 11 = 4x - 3 for x x .

    • A.-7
    • B.7
    • C.-4
    • D.4
    Show answerHide answer

    Correct answer: -7

    The solution is x=−7 x = -7 . Subtracting 4x 4x from both sides gathers the variable terms, giving 2x+11=−3 2x + 11 = -3 , and subtracting 11 from both sides gives 2x=−14 2x = -14 , so x=−7 x = -7 . Subtracting 4x 4x from the left while forgetting to keep the constant on the right balanced is the common slip that flips the sign and yields a positive value instead.

  12. Solve the linear equation 8−2(3x−1)=4x+30 8 - 2(3x - 1) = 4x + 30 for x x .

    • A.2
    • B.-2
    • C.-1
    • D.4
    Show answerHide answer

    Correct answer: -2

    The solution is x=−2 x = -2 . Distributing the -2 gives 8−6x+2=4x+30 8 - 6x + 2 = 4x + 30 , which simplifies to 10−6x=4x+30 10 - 6x = 4x + 30 . Adding 6x 6x to both sides and subtracting 30 gives −20=10x -20 = 10x , so x=−2 x = -2 . Distributing -2 only to the 3x 3x and ignoring the -1 inside the parentheses drops a +2 term and produces a wrong value.

  13. A gym charges a one-time $30 sign-up fee plus $22 per month. If a member has paid $250 in total, the equation is 30+22m=250 30 + 22m = 250 . How many months has the member been enrolled?

    • A.12
    • B.11
    • C.10
    • D.8
    Show answerHide answer

    Correct answer: 10

    The member has been enrolled 10 months. Subtracting the $30 sign-up fee from both sides gives 22m=220 22m = 220 , and dividing both sides by 22 gives m=10 m = 10 . Dividing the full $250 by 22 without first removing the one-time fee overstates the count, because the sign-up fee is charged once rather than every month.

  14. Solve the literal equation P=2L+2W P = 2L + 2W for W W in terms of P P and L L .

    • A.W=P−2L W = P - 2L
    • B.W=P−L2 W = \frac{P - L}{2}
    • C.W=P2−L2−L W = \frac{P}{2} - \frac{L}{2} - L
    • D.W=P−2L2 W = \frac{P - 2L}{2}
    Show answerHide answer

    Correct answer: W=P−2L2 W = \frac{P - 2L}{2}

    The result is W=P−2L2 W = \frac{P - 2L}{2} . Subtracting 2L 2L from both sides isolates the W W term, giving P−2L=2W P - 2L = 2W , and dividing both sides by 2 gives W=P−2L2 W = \frac{P - 2L}{2} . Dividing only the P P by 2 while leaving the 2L 2L unscaled fails to divide the entire side by 2, which is why every term in the numerator must be split by the same divisor.

  15. Solve the proportion x+25=3x−49 \frac{x + 2}{5} = \frac{3x - 4}{9} for x x .

    • A.193 \frac{19}{3}
    • B.6
    • C.196 \frac{19}{6}
    • D.3
    Show answerHide answer

    Correct answer: 193 \frac{19}{3}

    The solution is x=193 x = \frac{19}{3} . Cross-multiplying gives 9(x+2)=5(3x−4) 9(x + 2) = 5(3x - 4) , which expands to 9x+18=15x−20 9x + 18 = 15x - 20 . Subtracting 9x 9x and adding 20 to both sides gives 38=6x 38 = 6x , so x=386=193 x = \frac{38}{6} = \frac{19}{3} . Multiplying straight across the tops and bottoms instead of cross-multiplying the diagonal terms misapplies the proportion rule and gives a wrong value.

  16. Solve the inequality 5x+7<2x−8 5x + 7 < 2x - 8 and choose the correct solution set.

    • A.x>−5 x > -5
    • B.x<−5 x < -5
    • C.x<5 x < 5
    • D.x>5 x > 5
    Show answerHide answer

    Correct answer: x<−5 x < -5

    The solution is x<−5 x < -5 . Subtracting 2x 2x from both sides gives 3x+7<−8 3x + 7 < -8 , and subtracting 7 gives 3x<−15 3x < -15 , so dividing by the positive 3 gives x<−5 x < -5 without flipping the symbol. Because the division is by a positive number, the inequality direction stays the same; reversing it would be the error reserved for dividing by a negative.

  17. Solve the inequality x4−3≥1 \frac{x}{4} - 3 \ge 1 and choose the correct solution set.

    • A.x≤16 x \le 16
    • B.x≥8 x \ge 8
    • C.x≥16 x \ge 16
    • D.x≥−8 x \ge -8
    Show answerHide answer

    Correct answer: x≥16 x \ge 16

    The solution is x≥16 x \ge 16 . Adding 3 to both sides gives x4≥4 \frac{x}{4} \ge 4 , and multiplying both sides by the positive 4 gives x≥16 x \ge 16 with the symbol unchanged. Multiplying by 4 is by a positive number, so the inequality direction is preserved; only adding 3 once instead of clearing the fraction would understate the result and give 8.

  18. Solve the inequality −2(x−4)>6 -2(x - 4) > 6 and choose the correct solution set.

    • A.x>1 x > 1
    • B.x<−1 x < -1
    • C.x>−1 x > -1
    • D.x<1 x < 1
    Show answerHide answer

    Correct answer: x<1 x < 1

    The solution is x<1 x < 1 . Distributing the -2 gives −2x+8>6 -2x + 8 > 6 , and subtracting 8 gives −2x>−2 -2x > -2 . Dividing both sides by -2 reverses the inequality symbol, producing x<1 x < 1 . Keeping the symbol as 'greater than' after dividing by the negative 2 is the classic error, since dividing by a negative value always flips the direction.

  19. A delivery van can carry at most 1,500 pounds. It already holds 480 pounds of equipment, and it will load boxes weighing 35 pounds each. The inequality is 480+35b≤1500 480 + 35b \le 1500 . What is the greatest number of whole boxes it can carry?

    • A.29
    • B.30
    • C.31
    • D.44
    Show answerHide answer

    Correct answer: 29

    The greatest number of whole boxes is 29. Subtracting 480 from both sides gives 35b≤1020 35b \le 1020 , and dividing by 35 gives b≤29.14 b \le 29.14 . Because the van can only hold whole boxes and must stay at or under the limit, the value must be rounded down to 29. Rounding up to 30 would push the load to 480 + 1050 = 1530 pounds, which exceeds the 1,500-pound maximum, so 29 is the largest count that fits.

  20. Which graph on a number line correctly represents the solution to −x+2≥5 -x + 2 \ge 5 ?

    • A.A closed circle at -3 shading to the right
    • B.A closed circle at -3 shading to the left
    • C.An open circle at -3 shading to the left
    • D.An open circle at 3 shading to the right
    Show answerHide answer

    Correct answer: A closed circle at -3 shading to the left

    The correct picture is a closed circle at -3 shading to the left. Subtracting 2 from both sides gives −x≥3 -x \ge 3 , and multiplying by -1 reverses the symbol to give x≤−3 x \le -3 , so -3 is included and all smaller values qualify. A closed circle marks that -3 is part of the solution, and shading left covers values less than -3; failing to flip the symbol when multiplying by -1 would point the shading the wrong way.

  21. Which ordered pair is NOT a solution to the linear inequality y≥2x−1 y \ge 2x - 1 ?

    • A.(0, 0)
    • B.(1, 3)
    • C.(4, 5)
    • D.(-2, -3)
    Show answerHide answer

    Correct answer: (4, 5)

    The point (4, 5) is not a solution. Substituting x=4 x = 4 gives 2(4)−1=7 2(4) - 1 = 7 , and the inequality requires y≥7 y \ge 7 , but y y is only 5, so the point fails. The pair (0, 0) gives 2(0)−1=−1 2(0) - 1 = -1 and 0≥−1 0 \ge -1 holds, so it satisfies the inequality. A point below the boundary line y=2x−1 y = 2x - 1 does not belong to the solution region for a 'greater than or equal to' inequality.

  22. For the boundary of the inequality y<3x+2 y < 3x + 2 , how should the line be drawn and which side shaded?

    • A.A solid line with shading below it
    • B.A dashed line with shading above it
    • C.A solid line with shading above it
    • D.A dashed line with shading below it
    Show answerHide answer

    Correct answer: A dashed line with shading below it

    The boundary is a dashed line with shading below it. The strict 'less than' symbol means points on the line itself are not included, so the line is dashed rather than solid. Because y is less than the expression, the solution region lies below the line, where y-values are smaller. Using a solid line would wrongly include the boundary, and shading above would capture y-values that are too large.

  23. Solve the absolute value equation ∣5−x∣=12 |5 - x| = 12 for all values of x x .

    • A.X = -7 and x = 17
    • B.X = 7 and x = -17
    • C.X = 17 only
    • D.X = -7 only
    Show answerHide answer

    Correct answer: X = -7 and x = 17

    The solutions are x = -7 and x = 17. An absolute value equal to 12 means the inside expression equals either 12 or -12: solving 5−x=12 5 - x = 12 gives x=−7 x = -7 , and solving 5−x=−12 5 - x = -12 gives x=17 x = 17 . Reporting only one value ignores the second branch, which is why an absolute value equation with a positive right side produces two solutions.

  24. Solve the absolute value equation 2∣x+1∣−3=7 2|x + 1| - 3 = 7 for all values of x x .

    • A.X = 4 and x = 6
    • B.X = 4 and x = -6
    • C.X = 5 and x = -7
    • D.X = -6 only
    Show answerHide answer

    Correct answer: X = 4 and x = -6

    The solutions are x = 4 and x = -6. First isolate the absolute value by adding 3 and dividing by 2, giving ∣x+1∣=5 |x + 1| = 5 . Then x+1=5 x + 1 = 5 yields x=4 x = 4 , and x+1=−5 x + 1 = -5 yields x=−6 x = -6 . Splitting into the two cases before isolating the absolute value bar, while the 2 and -3 are still attached, produces incorrect values, so the absolute value must be alone first.

  25. Solve the absolute value inequality ∣x−2∣<5 |x - 2| < 5 and choose the correct solution set.

    • A.x<−3 x < -3 or x>7 x > 7
    • B.−7<x<3 -7 < x < 3
    • C.−3<x<7 -3 < x < 7
    • D.x<7 x < 7
    Show answerHide answer

    Correct answer: −3<x<7 -3 < x < 7

    The solution is −3<x<7 -3 < x < 7 . A 'less than' absolute value inequality becomes a single compound inequality, −5<x−2<5 -5 < x - 2 < 5 , and adding 2 to all three parts gives −3<x<7 -3 < x < 7 . The 'less than' case always produces an 'and' interval between two bounds, while an 'or' set of two separate rays would be the result of a 'greater than' absolute value inequality instead.

  26. Solve the system of equations by substitution: y=3x−4 y = 3x - 4 and 2x+y=11 2x + y = 11 .

    • A.X = 5, y = 1
    • B.X = 1, y = -1
    • C.X = 2, y = 7
    • D.X = 3, y = 5
    Show answerHide answer

    Correct answer: X = 3, y = 5

    The solution is x = 3 and y = 5. Substituting 3x−4 3x - 4 for y y in 2x+y=11 2x + y = 11 gives 2x+(3x−4)=11 2x + (3x - 4) = 11 , which simplifies to 5x−4=11 5x - 4 = 11 , so 5x=15 5x = 15 and x=3 x = 3 . Putting x=3 x = 3 back into y=3x−4 y = 3x - 4 gives y=5 y = 5 . The ordered pair (3, 5) satisfies both equations, while a pair that works in only one cannot solve the system.

  27. How many solutions does the system 2x+4y=8 2x + 4y = 8 and x+2y=4 x + 2y = 4 have?

    • A.Infinitely many solutions
    • B.Exactly one solution
    • C.No solution
    • D.Exactly two solutions
    Show answerHide answer

    Correct answer: Infinitely many solutions

    The system has infinitely many solutions. Multiplying the second equation by 2 gives 2x+4y=8 2x + 4y = 8 , which is identical to the first equation, so both describe the same line. Every point on that line satisfies both equations. Concluding one unique solution assumes the lines cross at a single point, but two equations for the same line overlap completely.

  28. A canoe travels 24 miles downstream in 2 hours and the same 24 miles upstream in 3 hours. With boat speed b b and current speed c c , the system is 2(b+c)=24 2(b + c) = 24 and 3(b−c)=24 3(b - c) = 24 . What is the speed of the boat in still water?

    • A.12 mph
    • B.10 mph
    • C.8 mph
    • D.2 mph
    Show answerHide answer

    Correct answer: 10 mph

    The boat's still-water speed is 10 mph. Dividing the first equation by 2 gives b+c=12 b + c = 12 , and dividing the second by 3 gives b−c=8 b - c = 8 . Adding these eliminates c c , giving 2b=20 2b = 20 , so b=10 b = 10 . Subtracting instead would solve for the current speed of 2 mph, which is not what the question asks for.

  29. Solve the quadratic equation 3x2−27=0 3x^2 - 27 = 0 using the square root method.

    • A.X = 9 and x = -9
    • B.X = 3 only
    • C.X = 3 and x = -3
    • D.X = 27 and x = -27
    Show answerHide answer

    Correct answer: X = 3 and x = -3

    The solutions are x = 3 and x = -3. Adding 27 to both sides gives 3x2=27 3x^2 = 27 , and dividing by 3 gives x2=9 x^2 = 9 . Taking the square root, x2=9 \sqrt{x^2} = \sqrt{9} , of both sides yields x=3 x = 3 or x=−3 x = -3 , because both values square to 9. Taking only the positive root and reporting x = 3 alone drops the negative branch that the square root method always includes.

  30. Solve the quadratic equation 2x2+7x+3=0 2x^2 + 7x + 3 = 0 by factoring.

    • A.x=12 x = \frac{1}{2} and x=3 x = 3
    • B.x=−12 x = -\frac{1}{2} and x=3 x = 3
    • C.x=−3 x = -3 and x=−2 x = -2
    • D.x=−12 x = -\frac{1}{2} and x=−3 x = -3
    Show answerHide answer

    Correct answer: x=−12 x = -\frac{1}{2} and x=−3 x = -3

    The solutions are x=−12 x = -\frac{1}{2} and x=−3 x = -3 . The trinomial factors into (2x+1)(x+3) (2x + 1)(x + 3) because the outer and inner products combine to 7x 7x and the last terms multiply to 3. Setting 2x+1=0 2x + 1 = 0 gives x=−12 x = -\frac{1}{2} , and setting x+3=0 x + 3 = 0 gives x=−3 x = -3 . Choosing the positive versions reverses the signs; the constant +3 with a middle term of +7 requires both roots to be negative.

  31. Use the quadratic formula to solve x2−6x+9=0 x^2 - 6x + 9 = 0 .

    • A.X = 3 (a single repeated root)
    • B.X = 3 and x = -3
    • C.X = 9 and x = 1
    • D.X = -3 (a single repeated root)
    Show answerHide answer

    Correct answer: X = 3 (a single repeated root)

    The solution is x = 3 as a single repeated root. With a=1 a = 1 , b=−6 b = -6 , and c=9 c = 9 , the discriminant b2−4ac b^2 - 4ac equals 36−36=0 36 - 36 = 0 , so the formula gives x=6±02=3 x = \frac{6 \pm 0}{2} = 3 . A discriminant of zero produces one repeated value, so listing two different roots would wrongly assume a positive discriminant that this perfect-square trinomial does not have.

  32. For the quadratic equation x2+2x+5=0 x^2 + 2x + 5 = 0 , what does the discriminant b2−4ac b^2 - 4ac reveal about the solutions?

    • A.Two distinct real solutions, because the discriminant is positive
    • B.No real solutions, because the discriminant is negative
    • C.Exactly one real solution, because the discriminant is zero
    • D.Two rational solutions, because the discriminant is a perfect square
    Show answerHide answer

    Correct answer: No real solutions, because the discriminant is negative

    The equation has no real solutions because the discriminant is negative. With a=1 a = 1 , b=2 b = 2 , and c=5 c = 5 , the discriminant b2−4ac b^2 - 4ac equals 4−4(1)(5)=4−20=−16 4 - 4(1)(5) = 4 - 20 = -16 . A negative value under the square root means no real number satisfies the equation. Concluding two real solutions would require a positive discriminant, which this equation does not have.

  33. Solve the quadratic equation x2+4x−1=0 x^2 + 4x - 1 = 0 by completing the square, leaving the answer in exact radical form.

    • A.X = 2 plus or minus 5\sqrt{5}
    • B.X = -2 plus or minus 3\sqrt{3}
    • C.X = -2 plus or minus 5\sqrt{5}
    • D.X = -4 plus or minus 5\sqrt{5}
    Show answerHide answer

    Correct answer: X = -2 plus or minus 5\sqrt{5}

    The solutions are x = -2 plus or minus 5\sqrt{5}. Moving the constant gives x2+4x=1 x^2 + 4x = 1 , and adding the square of half the middle coefficient, which is (4/2)2=4 (4/2)^2 = 4 , to both sides gives x2+4x+4=5 x^2 + 4x + 4 = 5 . The left side becomes the perfect square (x+2)2=5 (x + 2)^2 = 5 , so x+2=±5 x + 2 = \pm\sqrt{5} and x=−2±5 x = -2 \pm\sqrt{5} . Adding 2 instead of 4 to complete the square uses the wrong constant and breaks the perfect-square factoring.

Linear and Quadratic Functions (graphs and functions, linear functions, parabolas) (8)

  1. What is the slope of the line passing through the points (2, 3) and (6, 11)?

    • A.2
    • B.4
    • C.12 \frac{1}{2}
    • D.8
    Show answerHide answer

    Correct answer: 2

    The slope is 2. Slope is the change in y divided by the change in x, so 11−36−2 \frac{11 - 3}{6 - 2} equals 84 \frac{8}{4} , which is 2. Dividing the change in x by the change in y instead would invert the ratio and give 12 \frac{1}{2} , but slope always places the vertical change over the horizontal change.

  2. A line is written in slope-intercept form as y=−3x+7 y = -3x + 7 . What is the y-intercept of this line?

    • A.(0, 7)
    • B.(0, -3)
    • C.(7, 0)
    • D.(-3, 0)
    Show answerHide answer

    Correct answer: (0, 7)

    The y-intercept is (0, 7). In slope-intercept form y=mx+b y = mx + b , the constant b is the y-intercept and m is the slope, so here b=7 b = 7 marks where the line crosses the y-axis at x=0 x = 0 . Choosing (0, -3) confuses the slope -3 with the intercept, and writing (7, 0) places the value on the wrong axis since a y-intercept always has an x-coordinate of 0.

  3. Write the equation of the line with slope 4 that passes through the point (1, 2) in slope-intercept form.

    • A.y=4x−2 y = 4x - 2
    • B.y=4x+2 y = 4x + 2
    • C.y=4x+6 y = 4x + 6
    • D.y=x+4 y = x + 4
    Show answerHide answer

    Correct answer: y=4x−2 y = 4x - 2

    The equation is y=4x−2 y = 4x - 2 . Starting from y=mx+b y = mx + b with m=4 m = 4 and substituting the point (1, 2) gives 2=4(1)+b 2 = 4(1) + b , so b=2−4=−2 b = 2 - 4 = -2 . The line is therefore y=4x−2 y = 4x - 2 . Choosing y=4x+2 y = 4x + 2 forgets to solve for b and simply reuses the point's y-value as the intercept, which does not satisfy the given point.

  4. Which statement correctly describes the relationship between the lines y=2x+1 y = 2x + 1 and y=−12x+4 y = -\frac{1}{2} x + 4 ?

    • A.They are perpendicular because their slopes are negative reciprocals.
    • B.They are parallel because their slopes are equal.
    • C.They are the same line because they share a y-intercept.
    • D.They never intersect because both have positive slopes.
    Show answerHide answer

    Correct answer: They are perpendicular because their slopes are negative reciprocals.

    The lines are perpendicular because their slopes are negative reciprocals. One slope is 2 and the other is −12 -\frac{1}{2} , and multiplying them gives 2×−12=−1 2 \times -\frac{1}{2} = -1 , the defining condition for perpendicular lines. They are not parallel because parallel lines require identical slopes, and 2 does not equal −12 -\frac{1}{2} .

  5. What are the coordinates of the vertex of the parabola y=(x−3)2+5 y = (x - 3)^2 + 5 ?

    • A.(3, 5)
    • B.(-3, 5)
    • C.(3, -5)
    • D.(5, 3)
    Show answerHide answer

    Correct answer: (3, 5)

    The vertex is (3, 5). In vertex form y=(x−h)2+k y = (x - h)^2 + k , the vertex is the point (h, k), and here h=3 h = 3 and k=5 k = 5 . Note that the value subtracted inside the parentheses makes h positive, so x−3 x - 3 gives h=3 h = 3 , not -3; choosing (-3, 5) misreads the sign of h inside vertex form.

  6. For the parabola y=x2−6x+8 y = x^2 - 6x + 8 , which way does it open and where does it cross the x-axis?

    • A.Opens upward, crossing the x-axis at x = 2 and x = 4
    • B.Opens downward, crossing the x-axis at x = 2 and x = 4
    • C.Opens upward, crossing the x-axis at x = -2 and x = -4
    • D.Opens downward, with no x-intercepts
    Show answerHide answer

    Correct answer: Opens upward, crossing the x-axis at x = 2 and x = 4

    The parabola opens upward and crosses the x-axis at x=2 x = 2 and x=4 x = 4 . The leading coefficient on x2 x^2 is positive (a=1 a = 1 ), so the parabola opens upward. Setting y=0 y = 0 and factoring gives (x−2)(x−4)=0 (x - 2)(x - 4) = 0 , so the x-intercepts are 2 and 4. A negative leading coefficient would open the curve downward, but none is present here.

  7. A function is defined by f(x)=2x2−5 f(x) = 2x^2 - 5 . What is the value of f(−3) f(-3) ?

    • A.13
    • B.-23
    • C.31
    • D.-13
    Show answerHide answer

    Correct answer: 13

    The value is 13. Substituting x=−3 x = -3 gives f(−3)=2(−3)2−5 f(-3) = 2(-3)^2 - 5 , and because (−3)2=9 (-3)^2 = 9 , this becomes 2(9)−5=18−5=13 2(9) - 5 = 18 - 5 = 13 . Choosing -13 squares only the 3 while wrongly keeping the negative sign inside the squaring, but squaring a negative number always produces a positive result.

  8. Which set of ordered pairs represents a function?

    • A.{(1, 2), (3, 4), (5, 6)}
    • B.{(1, 2), (1, 4), (5, 6)}
    • C.{(2, 3), (2, 5), (2, 7)}
    • D.{(4, 1), (4, 2), (4, 3)}
    Show answerHide answer

    Correct answer: {(1, 2), (3, 4), (5, 6)}

    The set {(1, 2), (3, 4), (5, 6)} represents a function. A relation is a function only when each input (x-value) maps to exactly one output, and in this set every x-value appears just once. The set {(1, 2), (1, 4), (5, 6)} fails because the input 1 is paired with both 2 and 4, giving one input two different outputs.

Exponents and Polynomials (integer exponents, polynomial arithmetic, factoring, polynomial equations) (33)

  1. Simplify the expression x5×x3 x^5 \times x^3 using the laws of exponents.

    • A.x8 x^8
    • B.x15 x^{15}
    • C.x2 x^2
    • D.2x8 2x^8
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    Correct answer: x8 x^8

    The result is x8 x^8 . When multiplying powers that share the same base, the exponents are added, so x5×x3 x^5 \times x^3 equals x5+3=x8 x^{5 + 3} = x^8 . Multiplying the exponents to get x15 x^{15} is the rule for raising a power to a power, not for multiplying like bases, which is why addition of exponents is correct here.

  2. Rewrite 5x−3 5x^{-3} with a positive exponent.

    • A.5x3 \frac{5}{x^3}
    • B.15x3 \frac{1}{5x^3}
    • C.−5x3 -5x^3
    • D.−15x -15x
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    Correct answer: 5x3 \frac{5}{x^3}

    The expression equals 5x3 \frac{5}{x^3} . A negative exponent moves only its base to the denominator, so x−3 x^{-3} becomes 1x3 \frac{1}{x^3} , leaving the coefficient 5 in the numerator to give 5x3 \frac{5}{x^3} . Writing 15x3 \frac{1}{5x^3} incorrectly sends the 5 to the denominator too, but the negative exponent applies only to x, not to the coefficient.

  3. Add the polynomials (3x2+5x−2) (3x^2 + 5x - 2) and (x2−4x+7) (x^2 - 4x + 7) .

    • A.4x2+x+5 4x^2 + x + 5
    • B.4x2+9x+5 4x^2 + 9x + 5
    • C.2x2+x+5 2x^2 + x + 5
    • D.4x2−x+9 4x^2 - x + 9
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    Correct answer: 4x2+x+5 4x^2 + x + 5

    The sum is 4x2+x+5 4x^2 + x + 5 . Adding polynomials means combining like terms: the x2 x^2 terms 3x2+x2 3x^2 + x^2 give 4x2 4x^2 , the x terms 5x+(−4x) 5x + (-4x) give x, and the constants −2+7 -2 + 7 give 5. Combining 5x and -4x to get 9x ignores the negative sign on 4x, but those terms subtract to leave only x.

  4. Multiply the binomials (2x+3)(x−5) (2x + 3)(x - 5) .

    • A.2x2−7x−15 2x^2 - 7x - 15
    • B.2x2+7x−15 2x^2 + 7x - 15
    • C.2x2−13x−15 2x^2 - 13x - 15
    • D.2x2−7x+15 2x^2 - 7x + 15
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    Correct answer: 2x2−7x−15 2x^2 - 7x - 15

    The product is 2x2−7x−15 2x^2 - 7x - 15 . Using the distributive (FOIL) method, 2x×x 2x \times x gives 2x2 2x^2 , 2x×−5 2x \times -5 gives -10x, 3×x 3 \times x gives 3x, and 3×−5 3 \times -5 gives -15. Combining the middle terms −10x+3x -10x + 3x gives -7x, so the result is 2x2−7x−15 2x^2 - 7x - 15 . Getting +7x reverses the sign when combining the inner and outer products.

  5. Factor the trinomial x2+9x+20 x^2 + 9x + 20 completely.

    • A.(x + 4)(x + 5)
    • B.(x + 2)(x + 10)
    • C.(x - 4)(x - 5)
    • D.(x + 1)(x + 20)
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    Correct answer: (x + 4)(x + 5)

    The factored form is (x + 4)(x + 5). Factoring a trinomial requires two numbers that multiply to the constant 20 and add to the middle coefficient 9; those numbers are 4 and 5 because 4 times 5 is 20 and 4 plus 5 is 9. The pair 2 and 10 multiplies to 20 but adds to 12, so it does not match the required middle term.

  6. Factor the difference of squares 9x2−25 9x^2 - 25 .

    • A.(3x−5)(3x+5) (3x - 5)(3x + 5)
    • B.(3x−5)2 (3x - 5)^2
    • C.(9x−5)(x+5) (9x - 5)(x + 5)
    • D.(3x−25)(3x+1) (3x - 25)(3x + 1)
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    Correct answer: (3x−5)(3x+5) (3x - 5)(3x + 5)

    The factored form is (3x−5)(3x+5) (3x - 5)(3x + 5) . A difference of squares a2−b2 a^2 - b^2 factors into (a−b)(a+b) (a - b)(a + b) ; here 9x2 9x^2 is (3x)2 (3x)^2 and 25 is 52 5^2 , so a=3x a = 3x and b=5 b = 5 , giving (3x−5)(3x+5) (3x - 5)(3x + 5) . Writing (3x−5)2 (3x - 5)^2 would expand to 9x2−30x+25 9x^2 - 30x + 25 , which adds an unwanted middle term, so the two-binomial form with opposite signs is correct.

  7. Solve the polynomial equation x2−5x=0 x^2 - 5x = 0 by factoring.

    • A.X = 0 and x = 5
    • B.X = 5 only
    • C.X = -5 and x = 0
    • D.X = 5 and x = 1
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    Correct answer: X = 0 and x = 5

    The solutions are x = 0 and x = 5. Factoring out the common factor x gives x(x - 5) = 0, and the zero-product property means either x = 0 or x - 5 = 0, so x = 0 or x = 5. Dividing both sides by x to get only x = 5 discards the valid solution x = 0, which is a common error because dividing by a variable can remove a root.

  8. Simplify the expression (2x3)4 (2x^3)^4 using exponent rules.

    • A.16x12 16x^{12}
    • B.2x12 2x^{12}
    • C.8x7 8x^7
    • D.16x7 16x^7
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    Correct answer: 16x12 16x^{12}

    The result is 16x12 16x^{12} . Raising a product to a power applies the exponent to each factor, so (2x3)4=24×(x3)4=16×x3×4=16x12 (2x^3)^4 = 2^4 \times (x^3)^4 = 16 \times x^{3 \times 4} = 16x^{12} . Leaving the coefficient as 2 ignores that the outer exponent must also be applied to the 2, which becomes 24=16 2^4 = 16 .

  9. Simplify the quotient y9 y^9 divided by y4 y^4 using the laws of exponents.

    • A.y5 y^5
    • B.y13 y^{13}
    • C.y2.25 y^{2.25}
    • D.y36 y^{36}
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    Correct answer: y5 y^5

    The result is y5 y^5 . When dividing powers that share the same base, the exponents are subtracted, so y9 y^9 divided by y4 y^4 equals y9−4=y5 y^{9 - 4} = y^5 . Adding the exponents to get y13 y^{13} is the rule for multiplying like bases, not for dividing them, so subtraction is the correct operation here.

  10. Simplify the expression (m4)3 (m^4)^3 using the laws of exponents.

    • A.m12 m^{12}
    • B.m7 m^7
    • C.m64 m^{64}
    • D.m1 m^1
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    Correct answer: m12 m^{12}

    The result is m12 m^{12} . Raising a power to a power means multiplying the exponents, so (m4)3 (m^4)^3 equals m4×3=m12 m^{4 \times 3} = m^{12} . Adding the exponents to get m7 m^7 is the rule for multiplying like bases, but a power raised to a power requires multiplication of the exponents.

  11. Evaluate the expression 70 7^0 .

    • A.1
    • B.0
    • C.7
    • D.Undefined
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    Correct answer: 1

    The value is 1. Any nonzero base raised to the zero power equals 1 by the zero-exponent rule, so 70=1 7^0 = 1 . Answering 7 confuses the zero exponent with a first power, but the zero power of any nonzero number is always 1.

  12. Rewrite the expression 2−4 2^{-4} as a positive number.

    • A.116 \frac{1}{16}
    • B.-16
    • C.18 \frac{1}{8}
    • D.-8
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    Correct answer: 116 \frac{1}{16}

    The value is 116 \frac{1}{16} . A negative exponent means the reciprocal of the base raised to the positive exponent, so 2−4 2^{-4} equals 124=116 \frac{1}{2^4} = \frac{1}{16} . Writing -16 treats the negative exponent as a negative sign on the result, but a negative exponent produces a reciprocal, not a negative value.

  13. Simplify the expression (3a2b)(4a3b5) (3a^2b)(4a^3b^5) .

    • A.12a5b6 12a^5b^6
    • B.12a6b5 12a^6b^5
    • C.7a5b6 7a^5b^6
    • D.12a5b5 12a^5b^5
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    Correct answer: 12a5b6 12a^5b^6

    The product is 12a5b6 12a^5b^6 . Multiply the coefficients 3 and 4 to get 12, then add exponents on like bases: a2 a^2 times a3 a^3 gives a5 a^5 and b1 b^1 times b5 b^5 gives b6 b^6 . Adding the coefficients to get 7 is wrong because coefficients are multiplied, not added, when multiplying monomials.

  14. Simplify the expression (x4y6) (x^4 y^6) divided by (x2y2) (x^2 y^2) .

    • A.x2y4 x^2 y^4
    • B.x2y3 x^2 y^3
    • C.x6y8 x^6 y^8
    • D.x8y12 x^8 y^{12}
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    Correct answer: x2y4 x^2 y^4

    The result is x2y4 x^2 y^4 . Dividing like bases subtracts their exponents, so x4 x^4 divided by x2 x^2 gives x4−2=x2 x^{4 - 2} = x^2 and y6 y^6 divided by y2 y^2 gives y6−2=y4 y^{6 - 2} = y^4 . Dividing y6 y^6 by y2 y^2 to get y3 y^3 mistakenly divides the exponents, but exponents are subtracted when dividing like bases.

  15. Simplify the expression (2x2y3)3 \left(\frac{2x^2}{y^3}\right)^3 .

    • A.8x6y9 \frac{8x^6}{y^9}
    • B.6x6y9 \frac{6x^6}{y^9}
    • C.8x5y6 \frac{8x^5}{y^6}
    • D.2x6y9 \frac{2x^6}{y^9}
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    Correct answer: 8x6y9 \frac{8x^6}{y^9}

    The result is 8x6y9 \frac{8x^6}{y^9} . A power of a quotient applies the outer exponent to every factor, so the coefficient becomes 23=8 2^3 = 8 , the numerator variable becomes x2×3=x6 x^{2 \times 3} = x^6 , and the denominator becomes y3×3=y9 y^{3 \times 3} = y^9 . Leaving the coefficient as 6 multiplies 2 by 3 instead of cubing it, but the 2 must be raised to the third power.

  16. What is the degree of the polynomial 5x3−2x4+7x−1 5x^3 - 2x^4 + 7x - 1 ?

    • A.4
    • B.3
    • C.5
    • D.1
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    Correct answer: 4

    The degree is 4. The degree of a polynomial is the largest exponent on the variable, and here the term −2x4 -2x^4 has the highest exponent of 4, so the polynomial has degree 4. Choosing 3 looks only at the first written term, but the degree is determined by the greatest exponent regardless of term order.

  17. Subtract the polynomials (6x2+3x−5)−(2x2−4x+1) (6x^2 + 3x - 5) - (2x^2 - 4x + 1) .

    • A.4x2+7x−6 4x^2 + 7x - 6
    • B.4x2−x−4 4x^2 - x - 4
    • C.4x2+7x−4 4x^2 + 7x - 4
    • D.8x2−x−6 8x^2 - x - 6
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    Correct answer: 4x2+7x−6 4x^2 + 7x - 6

    The difference is 4x2+7x−6 4x^2 + 7x - 6 . Subtracting a polynomial distributes the negative sign to every term, turning the second group into −2x2+4x−1 -2x^2 + 4x - 1 , then combining like terms gives 6x2−2x2=4x2 6x^2 - 2x^2 = 4x^2 , 3x+4x=7x 3x + 4x = 7x , and −5−1=−6 -5 - 1 = -6 . Getting −x -x for the middle term fails to distribute the negative across the −4x -4x , which becomes +4x +4x .

  18. Multiply the monomial and binomial 3x(2x2−5x+4) 3x(2x^2 - 5x + 4) .

    • A.6x3−15x2+12x 6x^3 - 15x^2 + 12x
    • B.6x3−5x+4 6x^3 - 5x + 4
    • C.6x2−15x2+12x 6x^2 - 15x^2 + 12x
    • D.5x3−15x2+12x 5x^3 - 15x^2 + 12x
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    Correct answer: 6x3−15x2+12x 6x^3 - 15x^2 + 12x

    The product is 6x3−15x2+12x 6x^3 - 15x^2 + 12x . Distributing 3x 3x to each term multiplies coefficients and adds exponents: 3x 3x times 2x2=6x3 2x^2 = 6x^3 , 3x 3x times −5x=−15x2 -5x = -15x^2 , and 3x 3x times 4=12x 4 = 12x . Leaving the last terms unmultiplied to get 6x3−5x+4 6x^3 - 5x + 4 distributes 3x 3x to only the first term, but it must reach every term inside the parentheses.

  19. Expand the square of the binomial (x+4)2 (x + 4)^2 .

    • A.x2+8x+16 x^2 + 8x + 16
    • B.x2+16 x^2 + 16
    • C.x2+4x+16 x^2 + 4x + 16
    • D.x2+8x+8 x^2 + 8x + 8
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    Correct answer: x2+8x+16 x^2 + 8x + 16

    The expansion is x2+8x+16 x^2 + 8x + 16 . Squaring a binomial follows (a+b)2=a2+2ab+b2 (a + b)^2 = a^2 + 2ab + b^2 , so with a=x a = x and b=4 b = 4 the result is x2+2(x)(4)+16=x2+8x+16 x^2 + 2(x)(4) + 16 = x^2 + 8x + 16 . Writing only x2+16 x^2 + 16 forgets the middle term 2ab 2ab , which a binomial square always includes.

  20. Multiply the conjugate binomials (x−7)(x+7) (x - 7)(x + 7) .

    • A.x2−49 x^2 - 49
    • B.x2+49 x^2 + 49
    • C.x2−14x−49 x^2 - 14x - 49
    • D.x2−14x+49 x^2 - 14x + 49
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    Correct answer: x2−49 x^2 - 49

    The product is x2−49 x^2 - 49 . Multiplying conjugates of the form (a−b)(a+b) (a - b)(a + b) gives a2−b2 a^2 - b^2 because the middle terms cancel, so here x2−49 x^2 - 49 . The choice x2+49 x^2 + 49 uses the wrong sign, since a difference of squares produces subtraction of the second squared term, not addition.

  21. Factor out the greatest common factor of 12x3+18x2 12x^3 + 18x^2 .

    • A.6x2(2x+3) 6x^2(2x + 3)
    • B.6x(2x2+3x) 6x(2x^2 + 3x)
    • C.2x2(6x+9) 2x^2(6x + 9)
    • D.6x2(2x+18) 6x^2(2x + 18)
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    Correct answer: 6x2(2x+3) 6x^2(2x + 3)

    The factored form is 6x2(2x+3) 6x^2(2x + 3) . The greatest common factor of 12 and 18 is 6, and the lowest power of x x shared by both terms is x2 x^2 , so factoring 6x2 6x^2 leaves 2x+3 2x + 3 inside. The form 6x(2x2+3x) 6x(2x^2 + 3x) pulls out only x x instead of x2 x^2 , so it is not fully factored to the greatest common factor.

  22. Factor the trinomial x2−11x+28 x^2 - 11x + 28 completely.

    • A.(x - 4)(x - 7)
    • B.(x + 4)(x + 7)
    • C.(x - 2)(x - 14)
    • D.(x - 4)(x + 7)
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    Correct answer: (x - 4)(x - 7)

    The factored form is (x - 4)(x - 7). Two numbers must multiply to 28 and add to -11, and -4 and -7 work because (-4)(-7) = 28 and -4 + (-7) = -11. The pair +4 and +7 multiplies to 28 but adds to +11, giving the wrong sign on the middle term, so both factors must be negative.

  23. Factor the trinomial 2x2+7x+3 2x^2 + 7x + 3 completely.

    • A.(2x + 1)(x + 3)
    • B.(2x + 3)(x + 1)
    • C.(2x - 1)(x - 3)
    • D.(x + 1)(x + 3)
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    Correct answer: (2x + 1)(x + 3)

    The factored form is (2x+1)(x+3) (2x + 1)(x + 3) . Checking by expansion, 2x 2x times x=2x2 x = 2x^2 , the outer and inner products 6x+x=7x 6x + x = 7x , and 1 1 times 3=3 3 = 3 , matching the trinomial. The arrangement (2x+3)(x+1) (2x + 3)(x + 1) expands to 2x2+5x+3 2x^2 + 5x + 3 , whose middle term is 5x 5x rather than 7x 7x , so it does not match.

  24. Factor the perfect-square trinomial x2+12x+36 x^2 + 12x + 36 .

    • A.(x+6)2 (x + 6)^2
    • B.(x+12)2 (x + 12)^2
    • C.(x−6)2 (x - 6)^2
    • D.(x+6)(x−6) (x + 6)(x - 6)
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    Correct answer: (x+6)2 (x + 6)^2

    The factored form is (x+6)2 (x + 6)^2 . A perfect-square trinomial a2+2ab+b2 a^2 + 2ab + b^2 factors as (a+b)2 (a + b)^2 ; here x2 x^2 is x x squared, 36 is 6 squared, and the middle term 12x 12x equals 2 times x x times 6, so it factors to (x+6)2 (x + 6)^2 . Writing (x+12)2 (x + 12)^2 would expand to x2+24x+144 x^2 + 24x + 144 , which does not match the given trinomial.

  25. Simplify the expression by combining like terms: 4x2+3x−x2+5x 4x^2 + 3x - x^2 + 5x .

    • A.3x2+8x 3x^2 + 8x
    • B.3x2+2x 3x^2 + 2x
    • C.5x2+8x 5x^2 + 8x
    • D.3x4+8x2 3x^4 + 8x^2
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    Correct answer: 3x2+8x 3x^2 + 8x

    The simplified form is 3x2+8x 3x^2 + 8x . Combining like terms adds the x2 x^2 terms 4x2−x2=3x2 4x^2 - x^2 = 3x^2 and the x x terms 3x+5x=8x 3x + 5x = 8x . Adding 4x2 4x^2 and x2 x^2 to get 5x2 5x^2 ignores the subtraction sign, but the second squared term is being removed, so the coefficient is 3.

  26. Multiply the binomials (3x−2)(2x+5) (3x - 2)(2x + 5) .

    • A.6x2+11x−10 6x^2 + 11x - 10
    • B.6x2−11x−10 6x^2 - 11x - 10
    • C.6x2+11x+10 6x^2 + 11x + 10
    • D.5x2+11x−10 5x^2 + 11x - 10
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    Correct answer: 6x2+11x−10 6x^2 + 11x - 10

    The product is 6x2+11x−10 6x^2 + 11x - 10 . Using FOIL, 3x 3x times 2x=6x2 2x = 6x^2 , 3x 3x times 5=15x 5 = 15x , −2 -2 times 2x=−4x 2x = -4x , and −2 -2 times 5=−10 5 = -10 ; combining 15x−4x 15x - 4x gives 11x 11x . Getting −11x -11x for the middle term reverses the signs of the inner and outer products, but 15x−4x 15x - 4x is positive 11x 11x .

  27. Multiply the binomial by the trinomial (x+2)(x2+3x+1) (x + 2)(x^2 + 3x + 1) .

    • A.x3+5x2+7x+2 x^3 + 5x^2 + 7x + 2
    • B.x3+3x2+x+2 x^3 + 3x^2 + x + 2
    • C.x3+5x2+6x+2 x^3 + 5x^2 + 6x + 2
    • D.x3+6x2+7x+2 x^3 + 6x^2 + 7x + 2
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    Correct answer: x3+5x2+7x+2 x^3 + 5x^2 + 7x + 2

    The product is x3+5x2+7x+2 x^3 + 5x^2 + 7x + 2 . Distributing x x gives x3+3x2+x x^3 + 3x^2 + x , distributing 2 gives 2x2+6x+2 2x^2 + 6x + 2 , and combining like terms yields x3+(3x2+2x2)+(x+6x)+2=x3+5x2+7x+2 x^3 + (3x^2 + 2x^2) + (x + 6x) + 2 = x^3 + 5x^2 + 7x + 2 . The choice with 3x2 3x^2 fails to add the 2x2 2x^2 from distributing the 2, so the squared coefficient is too small.

  28. Write the polynomial 4−9x2+2x3−x 4 - 9x^2 + 2x^3 - x in standard form (descending powers).

    • A.2x3−9x2−x+4 2x^3 - 9x^2 - x + 4
    • B.4−x−9x2+2x3 4 - x - 9x^2 + 2x^3
    • C.2x3−9x2+x+4 2x^3 - 9x^2 + x + 4
    • D.−9x2+2x3−x+4 -9x^2 + 2x^3 - x + 4
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    Correct answer: 2x3−9x2−x+4 2x^3 - 9x^2 - x + 4

    The standard form is 2x3−9x2−x+4 2x^3 - 9x^2 - x + 4 . Standard form lists terms from highest exponent to lowest, so the order is the x3 x^3 term, then x2 x^2 , then x x , then the constant, keeping each term's sign: 2x3 2x^3 , −9x2 -9x^2 , −x -x , +4 +4 . The version with +x +x changes the sign of the −x -x term, but rearranging must preserve each term's original sign.

  29. Factor the difference of squares x2−1 x^2 - 1 completely.

    • A.(x−1)(x+1) (x - 1)(x + 1)
    • B.(x−1)2 (x - 1)^2
    • C.(x+1)2 (x + 1)^2
    • D.x(x−1) x(x - 1)
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    Correct answer: (x−1)(x+1) (x - 1)(x + 1)

    The factored form is (x−1)(x+1) (x - 1)(x + 1) . A difference of squares a2−b2 a^2 - b^2 factors into (a−b)(a+b) (a - b)(a + b) ; here x2 x^2 is x squared and 1 is 1 squared, so it becomes (x−1)(x+1) (x - 1)(x + 1) . Writing (x−1)2 (x - 1)^2 would expand to x2−2x+1 x^2 - 2x + 1 , which adds an unwanted middle term, so the conjugate pair is correct.

  30. Find the value of the polynomial P(x)=x2−4x+3 P(x) = x^2 - 4x + 3 when x=5 x = 5 .

    • A.8
    • B.48
    • C.23
    • D.-2
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    Correct answer: 8

    The value is 8. Substituting x=5 x = 5 gives (5)2−4(5)+3=25−20+3=8 (5)^2 - 4(5) + 3 = 25 - 20 + 3 = 8 . The answer 48 comes from squaring after multiplying or mishandling order of operations, but the exponent must be evaluated before the products are subtracted, giving 8.

  31. Identify the leading coefficient of the polynomial −3x4+6x2−x+9 -3x^4 + 6x^2 - x + 9 .

    • A.-3
    • B.9
    • C.6
    • D.-1
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    Correct answer: -3

    The leading coefficient is -3. The leading coefficient is the number multiplying the term with the highest exponent, which here is −3x4 -3x^4 , so the leading coefficient is -3. Choosing 9 picks the constant term instead, but the leading coefficient comes from the highest-degree term, not the constant.

  32. Solve the polynomial equation x2−3x−10=0 x^2 - 3x - 10 = 0 by factoring.

    • A.x=5 x = 5 and x=−2 x = -2
    • B.x=−5 x = -5 and x=2 x = 2
    • C.x=5 x = 5 and x=2 x = 2
    • D.x=−5 x = -5 and x=−2 x = -2
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    Correct answer: x=5 x = 5 and x=−2 x = -2

    The solutions are x=5 x = 5 and x=−2 x = -2 . Factoring needs two numbers that multiply to -10 and add to -3, which are -5 and 2, giving (x−5)(x+2)=0 (x - 5)(x + 2) = 0 , so the zero-product property yields x=5 x = 5 or x=−2 x = -2 . The pair x=−5 x = -5 and x=2 x = 2 comes from swapping the signs in the factors, which would give the wrong middle term.

  33. Simplify the product of powers (x3y2)(xy4)z0 (x^3 y^2)(x y^4) z^0 .

    • A.x4y6 x^4 y^6
    • B.x4y6z x^4 y^6 z
    • C.x3y8 x^3 y^8
    • D.x4y8z0 x^4 y^8 z^0
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    Correct answer: x4y6 x^4 y^6

    The result is x4y6 x^4 y^6 . Adding exponents on like bases gives x3+1=x4 x^{3 + 1} = x^4 and y2+4=y6 y^{2 + 4} = y^6 , while z0 z^0 equals 1 and therefore drops out entirely. Keeping z in the answer ignores that any nonzero base to the zero power is 1, so the z factor disappears.

Rational Expressions (rational equations and rational functions) (33)

  1. Simplify the rational expression x2−9x2+7x+12 \frac{x^2 - 9}{x^2 + 7x + 12} .

    • A.x−3x+4 \frac{x - 3}{x + 4}
    • B.x+3x+4 \frac{x + 3}{x + 4}
    • C.x−3x−4 \frac{x - 3}{x - 4}
    • D.x−9x+12 \frac{x - 9}{x + 12}
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    Correct answer: x−3x+4 \frac{x - 3}{x + 4}

    The simplified form is x−3x+4 \frac{x - 3}{x + 4} . The numerator x2−9 x^2 - 9 factors as (x−3)(x+3) (x - 3)(x + 3) , and the denominator x2+7x+12 x^2 + 7x + 12 factors as (x+3)(x+4) (x + 3)(x + 4) . The common factor (x+3) (x + 3) cancels, leaving x−3x+4 \frac{x - 3}{x + 4} . Keeping (x+3) (x + 3) in the numerator instead cancels the wrong factor, since only the matching (x+3) (x + 3) terms cancel.

  2. Multiply the rational expressions 3x4×89x2 \frac{3x}{4} \times \frac{8}{9x^2} .

    • A.23x \frac{2}{3x}
    • B.24x36x2 \frac{24x}{36x^2}
    • C.2x3 \frac{2x}{3}
    • D.32x \frac{3}{2x}
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    Correct answer: 23x \frac{2}{3x}

    The product is 23x \frac{2}{3x} . Multiplying straight across gives 3x×84×9x2=24x36x2 \frac{3x \times 8}{4 \times 9x^2} = \frac{24x}{36x^2} . Dividing numerator and denominator by their common factors, 24x36x2 \frac{24x}{36x^2} reduces by 12x to give 23x \frac{2}{3x} . Leaving the answer as 24x36x2 \frac{24x}{36x^2} is correct in value but not simplified, while the final reduced form cancels the shared x and the numerical factor.

  3. Add the rational expressions 3x+52x \frac{3}{x} + \frac{5}{2x} and write the result as a single fraction.

    • A.112x \frac{11}{2x}
    • B.83x \frac{8}{3x}
    • C.82x \frac{8}{2x}
    • D.152x2 \frac{15}{2x^2}
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    Correct answer: 112x \frac{11}{2x}

    The sum is 112x \frac{11}{2x} . The least common denominator of x and 2x is 2x, so 3x \frac{3}{x} becomes 62x \frac{6}{2x} while 52x \frac{5}{2x} stays the same. Adding the numerators gives 6+5=11 6 + 5 = 11 over the common denominator, producing 112x \frac{11}{2x} . Adding numerators and denominators separately to get 83x \frac{8}{3x} ignores the need for a common denominator.

  4. Divide the rational expressions x25÷x10 \frac{x^2}{5} \div \frac{x}{10} .

    • A.2x 2x
    • B.x2 \frac{x}{2}
    • C.x350 \frac{x^3}{50}
    • D.2x \frac{2}{x}
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    Correct answer: 2x 2x

    The quotient is 2x 2x . Dividing by a fraction means multiplying by its reciprocal, so x25÷x10 \frac{x^2}{5} \div \frac{x}{10} equals x25×10x \frac{x^2}{5} \times \frac{10}{x} . Multiplying gives 10x25x \frac{10x^2}{5x} , which reduces to 2x 2x after canceling the common factor 5x. Multiplying the two fractions directly without flipping the second would give x350 \frac{x^3}{50} , missing the reciprocal step required for division.

  5. Solve the rational equation 4x=8x+3 \frac{4}{x} = \frac{8}{x + 3} for x.

    • A.X = 3
    • B.X = 6
    • C.X = -3
    • D.X = 12
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    Correct answer: X = 3

    The solution is x = 3. Cross-multiplying the proportion gives 4(x + 3) = 8x, which expands to 4x + 12 = 8x. Subtracting 4x from both sides gives 12 = 4x, so x = 3. Choosing x = -3 would make the denominator x + 3 equal to zero, which is excluded, confirming that x = 3 is the valid answer.

  6. For the rational function f(x)=5x−4 f(x) = \frac{5}{x - 4} , what is the domain restriction?

    • A.X cannot equal 4
    • B.X cannot equal -4
    • C.X cannot equal 0
    • D.X cannot equal 5
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    Correct answer: X cannot equal 4

    The restriction is that x cannot equal 4. A rational function is undefined wherever its denominator equals zero, and x - 4 = 0 when x = 4, so that value must be excluded from the domain. Choosing x cannot equal -4 misreads the sign, since solving x - 4 = 0 gives positive 4, not -4.

  7. Two painters working together can finish a wall in a time given by the equation 1x+112=14 \frac{1}{x} + \frac{1}{12} = \frac{1}{4} , where x is one painter's solo time in hours. How long would that painter take alone?

    • A.6 hours
    • B.8 hours
    • C.3 hours
    • D.16 hours
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    Correct answer: 6 hours

    The painter takes 6 hours alone. Multiplying every term by the common denominator 12x clears the fractions: 12 + x = 3x. Subtracting x from both sides gives 12 = 2x, so x = 6 hours. Choosing 8 hours does not satisfy the original equation, because substituting it would make the combined rate too small to finish in 4 hours.

  8. Subtract the rational expressions 7x+2−3x+2 \frac{7}{x + 2} - \frac{3}{x + 2} and simplify.

    • A.4x+2 \frac{4}{x + 2}
    • B.42x+4 \frac{4}{2x + 4}
    • C.10x+2 \frac{10}{x + 2}
    • D.4x2+4 \frac{4}{x^2 + 4}
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    Correct answer: 4x+2 \frac{4}{x + 2}

    The difference is 4x+2 \frac{4}{x + 2} . Because both fractions already share the denominator x + 2, only the numerators subtract: 7−3=4 7 - 3 = 4 , giving 4x+2 \frac{4}{x + 2} . The denominator stays the same when fractions have a common denominator, so doubling it to 2x + 4 is an error; the denominator is never added or combined during subtraction of like denominators.

  9. Simplify the rational expression (x2−25)/(x2−2x−15) (x^2 - 25) / (x^2 - 2x - 15) .

    • A.(x−5)/(x−3) (x - 5) / (x - 3)
    • B.(x−5)/(x+3) (x - 5) / (x + 3)
    • C.(x+5)/(x−3) (x + 5) / (x - 3)
    • D.(x+5)/(x+3) (x + 5) / (x + 3)
    Show answerHide answer

    Correct answer: (x+5)/(x+3) (x + 5) / (x + 3)

    The simplified form is (x+5)/(x+3) (x + 5) / (x + 3) . The numerator x2−25 x^2 - 25 factors as (x−5)(x+5) (x - 5)(x + 5) , and the denominator x2−2x−15 x^2 - 2x - 15 factors as (x−5)(x+3) (x - 5)(x + 3) . The common factor (x−5) (x - 5) cancels, leaving (x+5)/(x+3) (x + 5) / (x + 3) . Choosing (x+5)/(x−3) (x + 5) / (x - 3) keeps the wrong surviving denominator factor, since the denominator factors as (x−5)(x+3) (x - 5)(x + 3) , so it is (x+3) (x + 3) that remains after the (x−5) (x - 5) terms cancel.

  10. Reduce the rational expression (6x+18)/(x2−9) (6x + 18) / (x^2 - 9) to lowest terms.

    • A.(x+3)/6 (x + 3) / 6
    • B.6/(x+3) 6 / (x + 3)
    • C.6/(x−3) 6 / (x - 3)
    • D.6/(x2−3) 6 / (x^2 - 3)
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    Correct answer: 6/(x−3) 6 / (x - 3)

    The reduced form is 6/(x−3) 6 / (x - 3) . Factoring the numerator gives 6(x+3) 6(x + 3) , and factoring the denominator x2−9 x^2 - 9 gives (x+3)(x−3) (x + 3)(x - 3) . Canceling the shared (x+3) (x + 3) leaves 6/(x−3) 6 / (x - 3) . Choosing 6/(x+3) 6 / (x + 3) cancels the wrong factor, because it is the (x+3) (x + 3) pair that cancels and the (x−3) (x - 3) factor that remains.

  11. Multiply the rational expressions (x+2)/(x−5) (x + 2) / (x - 5) times (x2−25)/(x2−4) (x^2 - 25) / (x^2 - 4) .

    • A.(x−5)/(x+2) (x - 5) / (x + 2)
    • B.(x+5)/(x−2) (x + 5) / (x - 2)
    • C.(x+5)/(x+2) (x + 5) / (x + 2)
    • D.(x−2)/(x+5) (x - 2) / (x + 5)
    Show answerHide answer

    Correct answer: (x+5)/(x−2) (x + 5) / (x - 2)

    The product is (x+5)/(x−2) (x + 5) / (x - 2) . Factoring gives (x+2)/(x−5) (x + 2) / (x - 5) times (x−5)(x+5)/((x−2)(x+2)) (x - 5)(x + 5) / ((x - 2)(x + 2)) . The (x−5) (x - 5) factors cancel and the (x+2) (x + 2) factors cancel, leaving (x+5)/(x−2) (x + 5) / (x - 2) . Choosing (x−5)/(x+2) (x - 5) / (x + 2) fails to cancel either matched pair, leaving factors that should have been removed.

  12. Multiply the rational expressions (10/(x+4)) (10 / (x + 4)) times ((x2+4x)/15) ((x^2 + 4x) / 15) .

    • A.2/(3x) 2 / (3x)
    • B.3x/2 3x / 2
    • C.10x/15 10x / 15
    • D.2x/3 2x / 3
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    Correct answer: 2x/3 2x / 3

    The product is 2x/3 2x / 3 . Factoring x2+4x x^2 + 4x as x(x+4) x(x + 4) gives (10/(x+4)) (10 / (x + 4)) times (x(x+4)/15) (x(x + 4) / 15) . The (x+4) (x + 4) factors cancel, leaving 10x/15 10x / 15 , which reduces to 2x/3 2x / 3 after dividing top and bottom by 5. Leaving 10x/15 10x / 15 is correct in value but not in lowest terms as required.

  13. Divide the rational expressions ((x2−1)/(x+3)) ((x^2 - 1) / (x + 3)) divided by ((x−1)/(x+3)) ((x - 1) / (x + 3)) .

    • A.(x2−1)/(x−1) (x^2 - 1) / (x - 1)
    • B.x−1 x - 1
    • C.(x+1)/(x+3) (x + 1) / (x + 3)
    • D.x+1 x + 1
    Show answerHide answer

    Correct answer: x+1 x + 1

    The quotient is x+1 x + 1 . Dividing means multiplying by the reciprocal: ((x2−1)/(x+3)) ((x^2 - 1) / (x + 3)) times ((x+3)/(x−1)) ((x + 3) / (x - 1)) . The (x+3) (x + 3) factors cancel, and factoring x2−1 x^2 - 1 as (x−1)(x+1) (x - 1)(x + 1) lets the (x−1) (x - 1) factors cancel, leaving x+1 x + 1 . Choosing (x+1)/(x+3) (x + 1) / (x + 3) forgets to cancel the (x+3) (x + 3) introduced by the reciprocal.

  14. Divide the rational expressions (8/(x−6)) (8 / (x - 6)) divided by (12/(x2−36)) (12 / (x^2 - 36)) .

    • A.3(x+6)/2 3(x + 6) / 2
    • B.2(x+6)/3 2(x + 6) / 3
    • C.2(x−6)/3 2(x - 6) / 3
    • D.8(x+6)/12 8(x + 6) / 12
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    Correct answer: 2(x+6)/3 2(x + 6) / 3

    The quotient is 2(x+6)/3 2(x + 6) / 3 . Multiplying by the reciprocal gives (8/(x−6)) (8 / (x - 6)) times ((x2−36)/12) ((x^2 - 36) / 12) . Factoring x2−36 x^2 - 36 as (x−6)(x+6) (x - 6)(x + 6) cancels the (x−6) (x - 6) , leaving 8(x+6)/12 8(x + 6) / 12 , which reduces to 2(x+6)/3 2(x + 6) / 3 by dividing the numbers by 4. Choosing 8(x+6)/12 8(x + 6) / 12 stops before reducing the numerical factor.

  15. Add the rational expressions 5/(x+1)+2/(x−1) 5/(x + 1) + 2/(x - 1) and write the result as a single fraction.

    • A.(7x−3)/(x2−1) (7x - 3) / (x^2 - 1)
    • B.7/(x2−1) 7 / (x^2 - 1)
    • C.(7x+3)/(x2−1) (7x + 3) / (x^2 - 1)
    • D.(7x−3)/(2x) (7x - 3) / (2x)
    Show answerHide answer

    Correct answer: (7x−3)/(x2−1) (7x - 3) / (x^2 - 1)

    The sum is (7x−3)/(x2−1) (7x - 3) / (x^2 - 1) . The least common denominator is (x+1)(x−1) (x + 1)(x - 1) , so the numerators become 5(x−1)+2(x+1)=5x−5+2x+2=7x−3 5(x - 1) + 2(x + 1) = 5x - 5 + 2x + 2 = 7x - 3 over (x+1)(x−1) (x + 1)(x - 1) , which is x2−1 x^2 - 1 . Choosing 7/(x2−1) 7 / (x^2 - 1) wrongly adds the numerators 5 and 2 without first multiplying by the missing factors.

  16. Add the rational expressions 4/(3x)+1/(2x) 4/(3x) + 1/(2x) and write the result as a single fraction.

    • A.5/(5x) 5 / (5x)
    • B.11/(6x) 11 / (6x)
    • C.5/(6x) 5 / (6x)
    • D.11/(5x) 11 / (5x)
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    Correct answer: 11/(6x) 11 / (6x)

    The sum is 11/(6x) 11 / (6x) . The least common denominator of 3x 3x and 2x 2x is 6x 6x , so 4/(3x) 4/(3x) becomes 8/(6x) 8/(6x) and 1/(2x) 1/(2x) becomes 3/(6x) 3/(6x) . Adding the numerators gives 8+3=11 8 + 3 = 11 over 6x 6x , producing 11/(6x) 11 / (6x) . Choosing 5/(5x) 5 / (5x) adds the numerators and denominators directly, ignoring the need for a common denominator.

  17. Subtract the rational expressions 3/(x−2)−1/(x+2) 3/(x - 2) - 1/(x + 2) and write the result as a single fraction.

    • A.2/(x2−4) 2 / (x^2 - 4)
    • B.(2x−8)/(x2−4) (2x - 8) / (x^2 - 4)
    • C.(2x+8)/(x2−4) (2x + 8) / (x^2 - 4)
    • D.(2x+8)/(2x) (2x + 8) / (2x)
    Show answerHide answer

    Correct answer: (2x+8)/(x2−4) (2x + 8) / (x^2 - 4)

    The difference is (2x+8)/(x2−4) (2x + 8) / (x^2 - 4) . Using the common denominator (x−2)(x+2) (x - 2)(x + 2) , the numerators become 3(x+2)−1(x−2)=3x+6−x+2=2x+8 3(x + 2) - 1(x - 2) = 3x + 6 - x + 2 = 2x + 8 over (x−2)(x+2) (x - 2)(x + 2) , which equals x2−4 x^2 - 4 . Choosing (2x−8)/(x2−4) (2x - 8) / (x^2 - 4) mishandles the distribution of the minus sign across the second numerator.

  18. Subtract the rational expressions (x+6)/(x+3)−3/(x+3) (x + 6)/(x + 3) - 3/(x + 3) and simplify.

    • A.(x+9)/(x+3) (x + 9) / (x + 3)
    • B.(x+3)/(x+3) (x + 3) / (x + 3)
    • C.x/(x+3) x / (x + 3)
    • D.1
    Show answerHide answer

    Correct answer: 1

    The difference is 1. Because both fractions share the denominator x+3 x + 3 , only the numerators subtract: (x+6)−3=x+3 (x + 6) - 3 = x + 3 , giving (x+3)/(x+3) (x + 3) / (x + 3) . Since the numerator now matches the denominator, the expression equals 1. Choosing x/(x+3) x / (x + 3) subtracts only the constants and overlooks that the entire x+3 x + 3 numerator cancels with the denominator.

  19. Solve the rational equation 6/x=9/(x+2) 6/x = 9/(x + 2) for x x .

    • A.x=−4 x = -4
    • B.x=4 x = 4
    • C.x=2 x = 2
    • D.x=6 x = 6
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    Correct answer: x=4 x = 4

    The solution is x=4 x = 4 . Cross-multiplying the proportion gives 6(x+2)=9x 6(x + 2) = 9x , which expands to 6x+12=9x 6x + 12 = 9x . Subtracting 6x 6x from both sides gives 12=3x 12 = 3x , so x=4 x = 4 . Choosing x=2 x = 2 does not satisfy the equation, since substituting it makes the two sides unequal.

  20. Solve the rational equation 1/x+1/4=1/2 1/x + 1/4 = 1/2 for x x .

    • A.x=6 x = 6
    • B.x=2 x = 2
    • C.x=4 x = 4
    • D.x=8 x = 8
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    Correct answer: x=4 x = 4

    The solution is x=4 x = 4 . Multiplying every term by the common denominator 4x 4x clears the fractions: 4+x=2x 4 + x = 2x . Subtracting x x from both sides gives 4=x 4 = x , so x=4 x = 4 . Choosing x=2 x = 2 would make the left side 1/2+1/4 1/2 + 1/4 , which is too large, so it fails the original equation.

  21. Solve the rational equation 5/(x−3)=10 5/(x - 3) = 10 for x x .

    • A.x=3.5 x = 3.5
    • B.x=2.5 x = 2.5
    • C.x=4 x = 4
    • D.x=8 x = 8
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    Correct answer: x=3.5 x = 3.5

    The solution is x=3.5 x = 3.5 . Multiplying both sides by (x−3) (x - 3) gives 5=10(x−3) 5 = 10(x - 3) , which expands to 5=10x−30 5 = 10x - 30 . Adding 30 to both sides gives 35=10x 35 = 10x , so x=3.5 x = 3.5 . Choosing x=2.5 x = 2.5 reverses the sign when solving, since 35 35 divided by 10 10 is positive 3.5, not 2.5.

  22. Solve the rational equation (x+4)/(x−1)=2 (x + 4)/(x - 1) = 2 for x x .

    • A.x=3 x = 3
    • B.x=−6 x = -6
    • C.x=6 x = 6
    • D.x=2 x = 2
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    Correct answer: x=6 x = 6

    The solution is x=6 x = 6 . Multiplying both sides by (x−1) (x - 1) gives x+4=2(x−1) x + 4 = 2(x - 1) , which expands to x+4=2x−2 x + 4 = 2x - 2 . Subtracting x x and adding 2 to both sides gives 6=x 6 = x , so x=6 x = 6 . Choosing x=3 x = 3 does not satisfy the equation, since (3+4)/(3−1) (3 + 4)/(3 - 1) equals 3.5, not 2.

  23. Solve the rational equation 2/(x−1)+3/(x−1)=5 2/(x - 1) + 3/(x - 1) = 5 for x x .

    • A.x=0 x = 0
    • B.x=1 x = 1
    • C.x=6 x = 6
    • D.x=2 x = 2
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    Correct answer: x=2 x = 2

    The solution is x=2 x = 2 . Since both fractions share the denominator x−1 x - 1 , the left side combines to 5/(x−1)=5 5/(x - 1) = 5 . Multiplying both sides by (x−1) (x - 1) gives 5=5(x−1) 5 = 5(x - 1) , so 1=x−1 1 = x - 1 and x=2 x = 2 . Choosing x=1 x = 1 is rejected because it makes the denominator zero, which is excluded.

  24. Solve the rational equation 3/(x+2)=1/(x−2) 3/(x + 2) = 1/(x - 2) for x x .

    • A.x=2 x = 2
    • B.x=−4 x = -4
    • C.x=4 x = 4
    • D.x=8 x = 8
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    Correct answer: x=4 x = 4

    The solution is x=4 x = 4 . Cross-multiplying gives 3(x−2)=1(x+2) 3(x - 2) = 1(x + 2) , which expands to 3x−6=x+2 3x - 6 = x + 2 . Subtracting x x and adding 6 to both sides gives 2x=8 2x = 8 , so x=4 x = 4 . Choosing x=2 x = 2 is rejected because it makes the denominator x−2 x - 2 equal to zero, which is excluded.

  25. Identify the value that must be excluded from the solution of any rational equation containing the term 7/(x−9) 7/(x - 9) .

    • A.x=9 x = 9
    • B.x=−9 x = -9
    • C.x=7 x = 7
    • D.x=0 x = 0
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    Correct answer: x=9 x = 9

    The excluded value is x=9 x = 9 . A rational expression is undefined wherever its denominator equals zero, and x−9=0 x - 9 = 0 when x=9 x = 9 , so that value can never be a solution. Choosing x=−9 x = -9 misreads the sign, since solving x−9=0 x - 9 = 0 gives positive 9, not negative 9.

  26. For the rational function g(x)=(x+5)/(x2−16) g(x) = (x + 5) / (x^2 - 16) , which values are excluded from the domain?

    • A.x=4 x = 4 only
    • B.x=−5 x = -5 only
    • C.x=16 x = 16 only
    • D.x=4 x = 4 and x=−4 x = -4
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    Correct answer: x=4 x = 4 and x=−4 x = -4

    The excluded values are x=4 x = 4 and x=−4 x = -4 . The domain excludes any input making the denominator zero, and x2−16=0 x^2 - 16 = 0 factors as (x−4)(x+4)=0 (x - 4)(x + 4) = 0 , giving x=4 x = 4 and x=−4 x = -4 . Choosing x=−5 x = -5 only confuses the numerator's zero with a domain restriction, but only the denominator determines excluded values.

  27. A boat travels 30 miles downstream in the same time it takes to travel 18 miles upstream. The current flows at 4 miles per hour. Using the equation 30/(b+4)=18/(b−4) 30/(b + 4) = 18/(b - 4) , find the boat's speed b b in still water.

    • A.16 mph
    • B.12 mph
    • C.8 mph
    • D.24 mph
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    Correct answer: 16 mph

    The boat's still-water speed is 16 mph. Cross-multiplying gives 30(b−4)=18(b+4) 30(b - 4) = 18(b + 4) , which expands to 30b−120=18b+72 30b - 120 = 18b + 72 . Subtracting 18b 18b and adding 120 gives 12b=192 12b = 192 , so b=16 b = 16 mph. Choosing 12 mph does not satisfy the equation, since the downstream and upstream times would no longer be equal.

  28. One pipe can fill a tank in 6 hours and a second pipe can fill it in 3 hours. Using 1/6+1/3=1/t 1/6 + 1/3 = 1/t , how long does it take both pipes working together?

    • A.2 hours
    • B.1 hour
    • C.4.5 hours
    • D.9 hours
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    Correct answer: 2 hours

    Together the pipes take 2 hours. Adding the rates 1/6+1/3 1/6 + 1/3 with common denominator 6 gives 1/6+2/6=3/6 1/6 + 2/6 = 3/6 , which simplifies to 1/2 1/2 , so 1/t=1/2 1/t = 1/2 and t=2 t = 2 hours. Choosing 9 hours adds the individual times rather than the rates, which is not how combined work is computed.

  29. Simplify the complex fraction (1/2+1/4) (1/2 + 1/4) divided by (3/4) (3/4) .

    • A.3/4 3/4
    • B.1
    • C.1/2 1/2
    • D.2
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    Correct answer: 1

    The simplified value is 1. The numerator 1/2+1/4 1/2 + 1/4 combines to 3/4 3/4 using a common denominator of 4, so the expression becomes (3/4) (3/4) divided by (3/4) (3/4) . Dividing a quantity by itself gives 1. Choosing 3/4 3/4 reports only the combined numerator and forgets to carry out the division by 3/4 3/4 .

  30. Simplify the complex fraction (x/(x+1)) (x / (x + 1)) divided by (x2/(x+1)) (x^2 / (x + 1)) .

    • A.x x
    • B.1/x 1 / x
    • C.x/(x+1) x / (x + 1)
    • D.x2 x^2
    Show answerHide answer

    Correct answer: 1/x 1 / x

    The simplified form is 1/x 1 / x . Rewriting the division as multiplication by the reciprocal gives (x/(x+1)) (x / (x + 1)) times ((x+1)/x2) ((x + 1) / x^2) . The (x+1) (x + 1) factors cancel and one x x cancels from x x and x2 x^2 , leaving 1/x 1 / x . Choosing x x inverts the reduction, since the larger power x2 x^2 sits in the denominator after flipping.

  31. Multiply the rational expressions ((x2+6x+9)/(x+1)) ((x^2 + 6x + 9) / (x + 1)) times ((x+1)/(x+3)) ((x + 1) / (x + 3)) .

    • A.x+3 x + 3
    • B.x+1 x + 1
    • C.(x+3)/(x+1) (x + 3) / (x + 1)
    • D.(x+3)2 (x + 3)^2
    Show answerHide answer

    Correct answer: x+3 x + 3

    The product is x+3 x + 3 . Factoring x2+6x+9 x^2 + 6x + 9 as (x+3)(x+3) (x + 3)(x + 3) gives ((x+3)(x+3)/(x+1)) ((x + 3)(x + 3) / (x + 1)) times ((x+1)/(x+3)) ((x + 1) / (x + 3)) . The (x+1) (x + 1) factors cancel and one (x+3) (x + 3) cancels, leaving x+3 x + 3 . Choosing (x+3)2 (x + 3)^2 fails to cancel the second (x+3) (x + 3) factor against the one in the second denominator.

  32. Solve the rational equation 9/(x2−9)=1/(x−3) 9/(x^2 - 9) = 1/(x - 3) for x x .

    • A.x=6 x = 6
    • B.x=3 x = 3
    • C.x=−3 x = -3
    • D.x=0 x = 0
    Show answerHide answer

    Correct answer: x=6 x = 6

    The solution is x=6 x = 6 . Factoring x2−9 x^2 - 9 as (x−3)(x+3) (x - 3)(x + 3) and multiplying both sides by it gives 9=1(x+3) 9 = 1(x + 3) , so x+3=9 x + 3 = 9 and x=6 x = 6 . Choosing x=3 x = 3 is rejected because it makes the denominator zero, but x=6 x = 6 keeps every denominator nonzero and satisfies the original equation.

  33. Add the rational expressions 2/x+3 2/x + 3 and write the result as a single fraction.

    • A.(2x+3)/x (2x + 3) / x
    • B.(2+3)/x (2 + 3) / x
    • C.5/x 5 / x
    • D.(3x+2)/x (3x + 2) / x
    Show answerHide answer

    Correct answer: (3x+2)/x (3x + 2) / x

    The sum is (3x+2)/x (3x + 2) / x . Writing 3 as 3x/x 3x/x gives a common denominator of x x , so 2/x+3x/x 2/x + 3x/x combines to (2+3x)/x (2 + 3x) / x , which is the same as (3x+2)/x (3x + 2) / x . Choosing 5/x 5 / x incorrectly treats 3 as 3/x 3/x and adds only the numerators, ignoring that the whole number 3 equals 3x 3x over x x .

Radical Expressions (higher roots, rational exponents) (33)

  1. Simplify the radical expression 72\sqrt{72} to simplest form.

    • A.626\sqrt{2}
    • B.2182\sqrt{18}
    • C.36236\sqrt{2}
    • D.838\sqrt{3}
    Show answerHide answer

    Correct answer: 626\sqrt{2}

    The simplified form is 626\sqrt{2}. The largest perfect-square factor of 72 is 36, so 72\sqrt{72} equals 36×2 \sqrt{36 \times 2} , which separates into 36×2\sqrt{36} \times \sqrt{2} = 626\sqrt{2}. Writing 2182\sqrt{18} is not fully simplified because 18 still contains the perfect square 9.

  2. Evaluate 643\sqrt[3]{64}.

    • A.4
    • B.8
    • C.16
    • D.21.3
    Show answerHide answer

    Correct answer: 4

    The 643\sqrt[3]{64} is 4. A cube root asks which number multiplied by itself three times gives the value, and 4 times 4 times 4 equals 64, so the answer is 4. Choosing 8 finds 64\sqrt{64} instead, which uses two factors rather than the three factors a cube root requires.

  3. Rewrite the expression x2/3 x^{2/3} using radical notation.

    • A.x23\sqrt[3]{x^{2}}
    • B.x3\sqrt{x^{3}}
    • C.x33\sqrt[3]{x^{3}}
    • D.x2\sqrt{x^{2}}
    Show answerHide answer

    Correct answer: x23\sqrt[3]{x^{2}}

    The expression equals x23\sqrt[3]{x^{2}}. A rational exponent of the form m/n means the numerator m is the power and the denominator n is the root index, so x2/3 x^{2/3} is the cube root (index 3) of x raised to the power 2. Writing x3\sqrt{x^{3}} swaps the roles of numerator and denominator, putting the power as the index instead.

  4. Add the radical expressions 535\sqrt{3} plus 232\sqrt{3}.

    • A.737\sqrt{3}
    • B.767\sqrt{6}
    • C.10310\sqrt{3}
    • D.797\sqrt{9}
    Show answerHide answer

    Correct answer: 737\sqrt{3}

    The sum is 737\sqrt{3}. Radical terms add only when they are like radicals sharing the same radicand, and both terms contain 3\sqrt{3}, so the coefficients add: 5 + 2 = 7, giving 737\sqrt{3}. Adding the radicands to get 6\sqrt{6} is incorrect, because the number under the radical stays the same when combining like radicals.

  5. Multiply and simplify 6×10\sqrt{6} \times \sqrt{10}.

    • A.2152\sqrt{15}
    • B.60\sqrt{60}
    • C.2302\sqrt{30}
    • D.16\sqrt{16}
    Show answerHide answer

    Correct answer: 2152\sqrt{15}

    The product is 2152\sqrt{15}. Multiplying radicals combines the radicands under one root: 6×10\sqrt{6} \times \sqrt{10} equals 60\sqrt{60}. Since 60 has the perfect-square factor 4, 60\sqrt{60} simplifies to 2152\sqrt{15}. Leaving it as 60\sqrt{60} is correct in value but not fully simplified.

  6. Rationalize the denominator of the expression 6 divided by 3\sqrt{3}.

    • A.232\sqrt{3}
    • B.636\sqrt{3}
    • C.32\frac{\sqrt{3}}{2}
    • D.222\sqrt{2}
    Show answerHide answer

    Correct answer: 232\sqrt{3}

    The result is 232\sqrt{3}. Rationalizing means multiplying numerator and denominator by 3\sqrt{3} to clear the radical from the bottom: (636\sqrt{3}) divided by (3×3\sqrt{3} \times \sqrt{3}) equals (636\sqrt{3}) divided by 3. Dividing 6 by 3 gives 2, so the answer is 232\sqrt{3}.

  7. Solve the radical equation x+5\sqrt{x + 5} = 4 for x.

    • A.X = 11
    • B.X = -1
    • C.X = 16
    • D.X = 9
    Show answerHide answer

    Correct answer: X = 11

    The solution is x = 11. Squaring both sides removes the radical, turning x+5\sqrt{x + 5} = 4 into x + 5 = 16. Subtracting 5 from both sides gives x = 11, and checking confirms 11+5\sqrt{11 + 5} = 16\sqrt{16} = 4. Choosing x = 16 forgets to subtract the 5, stopping at the squared value rather than solving for x.

  8. Evaluate 271/3 27^{1/3} .

    • A.3
    • B.9
    • C.81
    • D.13.5
    Show answerHide answer

    Correct answer: 3

    The value is 3. An exponent of 1/3 means the cube root, so 271/3 27^{1/3} is 273\sqrt[3]{27}, which is the number that multiplied by itself three times gives 27. Since 3 times 3 times 3 equals 27, the answer is 3. Choosing 9 mistakes the operation for squaring or dividing, but a one-third exponent specifically calls for the cube root.

  9. Simplify the radical expression 50\sqrt{50} to simplest form.

    • A.525\sqrt{2}
    • B.252\sqrt{5}
    • C.25225\sqrt{2}
    • D.10510\sqrt{5}
    Show answerHide answer

    Correct answer: 525\sqrt{2}

    The simplified form is 525\sqrt{2}. The largest perfect-square factor of 50 is 25, so 50\sqrt{50} equals 25×2 \sqrt{25 \times 2} , which separates into 25×2\sqrt{25} \times \sqrt{2} = 525\sqrt{2}. Writing 252\sqrt{5} mistakenly pulls out the 2 instead of the perfect square 25.

  10. Evaluate 1253\sqrt[3]{125}.

    • A.5
    • B.25
    • C.15
    • D.11.2
    Show answerHide answer

    Correct answer: 5

    The 1253\sqrt[3]{125} is 5. A cube root asks which number multiplied by itself three times gives the value, and 5 times 5 times 5 equals 125, so the answer is 5. Choosing 25 finds 625\sqrt{625} or mistakenly squares, but a cube root requires three equal factors, not two.

  11. Simplify the quotient 48\sqrt{48} divided by 3\sqrt{3}.

    • A.4
    • B.16
    • C.16\sqrt{16}
    • D.232\sqrt{3}
    Show answerHide answer

    Correct answer: 4

    The quotient equals 4. Dividing radicals combines the radicands under one root, so 48\sqrt{48} divided by 3\sqrt{3} equals 48/3 \sqrt{48 / 3} = 16\sqrt{16}, which is 4. Leaving it as 16\sqrt{16} is correct in value but not fully evaluated, since 16 is a perfect square.

  12. Subtract the radical expressions 959\sqrt{5} minus 454\sqrt{5}.

    • A.555\sqrt{5}
    • B.505\sqrt{0}
    • C.13513\sqrt{5}
    • D.5105\sqrt{10}
    Show answerHide answer

    Correct answer: 555\sqrt{5}

    The difference is 555\sqrt{5}. Like radicals share the same radicand, and both terms contain 5\sqrt{5}, so the coefficients subtract: 9 - 4 = 5, giving 555\sqrt{5}. The radicand stays 5\sqrt{5} because only the coefficients change when combining like radicals.

  13. Simplify the radical expression 12\sqrt{12} plus 27\sqrt{27}.

    • A.535\sqrt{3}
    • B.39\sqrt{39}
    • C.636\sqrt{3}
    • D.565\sqrt{6}
    Show answerHide answer

    Correct answer: 535\sqrt{3}

    The sum is 535\sqrt{3}. First simplify each term: 12\sqrt{12} = 232\sqrt{3}, and 27\sqrt{27} = 333\sqrt{3}. Now they are like radicals, so adding the coefficients 2 + 3 gives 535\sqrt{3}. Adding the radicands to get 39\sqrt{39} ignores that the terms must first be simplified to combine.

  14. Rationalize the denominator of the expression 10 divided by 5\sqrt{5}.

    • A.252\sqrt{5}
    • B.10510\sqrt{5}
    • C.52\frac{\sqrt{5}}{2}
    • D.222\sqrt{2}
    Show answerHide answer

    Correct answer: 252\sqrt{5}

    The result is 252\sqrt{5}. Rationalizing means multiplying numerator and denominator by 5\sqrt{5}: (10510\sqrt{5}) divided by (5×5\sqrt{5} \times \sqrt{5}) equals (10510\sqrt{5}) divided by 5. Dividing 10 by 5 gives 2, so the answer is 252\sqrt{5}.

  15. Solve the radical equation 2x−1\sqrt{2x - 1} = 5 for x.

    • A.X = 13
    • B.X = 12
    • C.X = 26
    • D.X = 3
    Show answerHide answer

    Correct answer: X = 13

    The solution is x=13 x = 13 . Squaring both sides turns 2x−1\sqrt{2x - 1} = 5 into 2x−1=25 2x - 1 = 25 . Adding 1 gives 2x=26 2x = 26 , and dividing by 2 gives x=13 x = 13 ; checking confirms 2×13−1 \sqrt{2 \times 13 - 1} = 25\sqrt{25} = 5. Choosing x=26 x = 26 stops after isolating 2x 2x and forgets to divide by 2.

  16. Evaluate 163/4 16^{3/4} .

    • A.8
    • B.12
    • C.64
    • D.2
    Show answerHide answer

    Correct answer: 8

    The value is 8. A rational exponent m/n m/n means take the n-th root and raise to the m power, so 163/4 16^{3/4} is 164\sqrt[4]{16}, raised to the third power. The 164\sqrt[4]{16} is 2 because 2 times 2 times 2 times 2 = 16, and 2 cubed is 8. Choosing 64 mistakenly cubes 16 first without taking the fourth root.

  17. Simplify the radical expression 98\sqrt{98}.

    • A.727\sqrt{2}
    • B.2492\sqrt{49}
    • C.49249\sqrt{2}
    • D.777\sqrt{7}
    Show answerHide answer

    Correct answer: 727\sqrt{2}

    The simplified form is 727\sqrt{2}. The largest perfect-square factor of 98 is 49, so 98\sqrt{98} equals 49×2 \sqrt{49 \times 2} = 49×2\sqrt{49} \times \sqrt{2} = 727\sqrt{2}. Writing 2492\sqrt{49} leaves a perfect square under the radical, so it is not fully simplified.

  18. Evaluate 814\sqrt[4]{81}.

    • A.3
    • B.9
    • C.27
    • D.20.25
    Show answerHide answer

    Correct answer: 3

    The 814\sqrt[4]{81} is 3. A fourth root asks which number multiplied by itself four times gives the value, and 3 times 3 times 3 times 3 equals 81, so the answer is 3. Choosing 9 finds 81\sqrt{81} instead, which uses only two equal factors rather than the four a fourth root requires.

  19. Multiply and simplify 232\sqrt{3}, times 565\sqrt{6}.

    • A.30230\sqrt{2}
    • B.101810\sqrt{18}
    • C.797\sqrt{9}
    • D.10210\sqrt{2}
    Show answerHide answer

    Correct answer: 30230\sqrt{2}

    The product is 30230\sqrt{2}. Multiply the coefficients (2 times 5 = 10) and the radicands (3×6\sqrt{3} \times \sqrt{6} = 18\sqrt{18}), giving 101810\sqrt{18}. Since 18 has the perfect-square factor 9, 18\sqrt{18} = 323\sqrt{2}, so 10 times 3 = 30, giving 30230\sqrt{2}.

  20. Rewrite the radical expression x35\sqrt[5]{x^{3}} using a rational exponent.

    • A.x3/5 x^{3/5}
    • B.x5/3 x^{5/3}
    • C.x3+5 x^{3+5}
    • D.x15 x^{15}
    Show answerHide answer

    Correct answer: x3/5 x^{3/5}

    The expression equals x3/5 x^{3/5} . A radical converts to a rational exponent where the power inside becomes the numerator and the root index becomes the denominator, so the fifth root (index 5) of x raised to the 3 power is x3/5 x^{3/5} . Writing x5/3 x^{5/3} swaps the index and the power, putting the root in the wrong position.

  21. Simplify 543\sqrt[3]{54} to simplest form.

    • A.3233\sqrt[3]{2}
    • B.2332\sqrt[3]{3}
    • C.9639\sqrt[3]{6}
    • D.3633\sqrt[3]{6}
    Show answerHide answer

    Correct answer: 3233\sqrt[3]{2}

    The simplified form is 3233\sqrt[3]{2}. The largest perfect-cube factor of 54 is 27, so 543\sqrt[3]{54} equals 27×23 \sqrt[3]{27 \times 2} = 273×23\sqrt[3]{27} \times \sqrt[3]{2} = 3233\sqrt[3]{2}. With cube roots you must look for a perfect cube factor like 27, not a perfect square.

  22. Rationalize the denominator of the expression 4 divided by (7\sqrt{7} minus 3\sqrt{3}).

    • A.7\sqrt{7} plus 3\sqrt{3}
    • B.7\sqrt{7} minus 3\sqrt{3}
    • C.4 times (7\sqrt{7} plus 3\sqrt{3})
    • D.7\sqrt{7} plus 3\sqrt{3}, all divided by 4
    Show answerHide answer

    Correct answer: 7\sqrt{7} plus 3\sqrt{3}

    The result is 7\sqrt{7} plus 3\sqrt{3}. Multiply numerator and denominator by the conjugate 7\sqrt{7} plus 3\sqrt{3}, which makes the denominator (7)2−(3)2=7−3=4 (\sqrt{7})^2 - (\sqrt{3})^2 = 7 - 3 = 4 . The numerator becomes 4 times (7\sqrt{7} plus 3\sqrt{3}), and dividing by 4 leaves 7\sqrt{7} plus 3\sqrt{3}.

  23. Simplify the radical expression 75\sqrt{75} minus 12\sqrt{12}.

    • A.333\sqrt{3}
    • B.63\sqrt{63}
    • C.737\sqrt{3}
    • D.232\sqrt{3}
    Show answerHide answer

    Correct answer: 333\sqrt{3}

    The difference is 333\sqrt{3}. Simplify each term first: 75\sqrt{75} = 535\sqrt{3} and 12\sqrt{12} = 232\sqrt{3}. As like radicals, subtract the coefficients 5 - 2 = 3, giving 333\sqrt{3}. Subtracting the radicands to get 63\sqrt{63} skips the required simplification step.

  24. Evaluate the expression 82/3 8^{2/3} .

    • A.4
    • B.16
    • C.6
    • D.2.67
    Show answerHide answer

    Correct answer: 4

    The value is 4. The exponent 2/3 2/3 means take the cube root and then raise to the second power, so 82/3 8^{2/3} is 83\sqrt[3]{8} (which is 2) squared. Since 2 squared is 4, the answer is 4. Choosing 16 squares 8 first without taking the cube root, which ignores the denominator of the exponent.

  25. Simplify the expression 8×2\sqrt{8} \times \sqrt{2}.

    • A.4
    • B.16\sqrt{16}
    • C.282\sqrt{8}
    • D.16
    Show answerHide answer

    Correct answer: 4

    The product is 4. Multiplying radicals combines the radicands under one root, so 8×2\sqrt{8} \times \sqrt{2} equals 16\sqrt{16}, and 16\sqrt{16} is 4. Leaving the answer as 16\sqrt{16} is correct in value but not fully evaluated since 16 is a perfect square.

  26. Solve the radical equation x−23\sqrt[3]{x - 2} = 3 for x.

    • A.X = 29
    • B.X = 11
    • C.X = 5
    • D.X = 27
    Show answerHide answer

    Correct answer: X = 29

    The solution is x = 29. To undo a cube root, cube both sides, turning x−23\sqrt[3]{x - 2} = 3 into x - 2 = 27. Adding 2 gives x = 29; checking confirms 29−23\sqrt[3]{29 - 2} = 273\sqrt[3]{27} = 3. Choosing x = 11 mistakenly squares the 3 instead of cubing it, since the equation involves a cube root.

  27. Simplify the radical expression 45\sqrt{45} divided by 5\sqrt{5}.

    • A.3
    • B.9
    • C.9\sqrt{9}
    • D.353\sqrt{5}
    Show answerHide answer

    Correct answer: 3

    The quotient is 3. Dividing radicals combines the radicands, so 45\sqrt{45} divided by 5\sqrt{5} equals 45/5 \sqrt{45 / 5} = 9\sqrt{9}, which is 3. Leaving it as 9\sqrt{9} is correct in value but not fully evaluated since 9 is a perfect square.

  28. Simplify the expression x6\sqrt{x^{6}}, assuming x is positive.

    • A.x3 x^3
    • B.x2 x^2
    • C.x36 x^{36}
    • D.x\sqrt{x} times 6
    Show answerHide answer

    Correct answer: x3 x^3

    The expression equals x3 x^3 . Taking a square root divides the exponent by 2, so x6\sqrt{x^{6}} is x6/2=x3 x^{6/2} = x^3 . Choosing x2 x^2 mistakenly subtracts 2 from the exponent or divides by 3, but a square root corresponds to dividing the exponent by the index 2.

  29. Simplify the radical expression 3183\sqrt{18}.

    • A.929\sqrt{2}
    • B.393\sqrt{9}
    • C.999\sqrt{9}
    • D.636\sqrt{3}
    Show answerHide answer

    Correct answer: 929\sqrt{2}

    The simplified form is 929\sqrt{2}. The 18\sqrt{18} simplifies because 18 = 9 times 2, giving 323\sqrt{2}; multiplying by the coefficient 3 outside gives 3 times 3 = 9, so the result is 929\sqrt{2}. Forgetting to multiply the outside 3 by the new coefficient leaves the answer unfinished.

  30. Rationalize the denominator of the expression 2\sqrt{2} divided by 5\sqrt{5}.

    • A.105\frac{\sqrt{10}}{5}
    • B.102\frac{\sqrt{10}}{2}
    • C.75\frac{\sqrt{7}}{5}
    • D.2 over 5\sqrt{5}
    Show answerHide answer

    Correct answer: 105\frac{\sqrt{10}}{5}

    The result is 105\frac{\sqrt{10}}{5}. Multiply numerator and denominator by 5\sqrt{5}: the numerator becomes 2×5\sqrt{2} \times \sqrt{5} = 10\sqrt{10}, and the denominator becomes 5×5\sqrt{5} \times \sqrt{5} = 5. So the rationalized form is 105\frac{\sqrt{10}}{5}, which clears the radical from the denominator.

  31. Evaluate −83\sqrt[3]{-8}.

    • A.-2
    • B.2
    • C.-4
    • D.Not a real number
    Show answerHide answer

    Correct answer: -2

    The −83\sqrt[3]{-8} is -2. Odd roots of negative numbers are real, and the number that multiplied by itself three times gives negative 8 is -2, since -2 times -2 times -2 = -8. The answer is not 2 because a positive cube would give positive 8, and odd roots preserve the negative sign.

  32. Simplify the radical expression 163\sqrt[3]{16} to simplest form.

    • A.2232\sqrt[3]{2}
    • B.4234\sqrt[3]{2}
    • C.2432\sqrt[3]{4}
    • D.8238\sqrt[3]{2}
    Show answerHide answer

    Correct answer: 2232\sqrt[3]{2}

    The simplified form is 2232\sqrt[3]{2}. The largest perfect-cube factor of 16 is 8, so 163\sqrt[3]{16} equals 8×23 \sqrt[3]{8 \times 2} = 83×23\sqrt[3]{8} \times \sqrt[3]{2} = 2232\sqrt[3]{2}. Looking for a perfect-square factor instead would not simplify a cube root correctly.

  33. Solve the radical equation 3x+4\sqrt{3x + 4} = x+10\sqrt{x + 10} for x.

    • A.X = 3
    • B.X = 7
    • C.X = 14
    • D.X = 6
    Show answerHide answer

    Correct answer: X = 3

    The solution is x = 3. Squaring both sides removes the radicals because the two square roots are equal, giving 3x + 4 = x + 10. Subtracting x from both sides gives 2x + 4 = 10, then subtracting 4 gives 2x = 6 and x = 3; checking confirms both sides equal 13\sqrt{13}. Choosing x = 7 misadds the constants when solving.

Exponentials and Logarithms (function compositions, inverse functions, properties of logarithms, logarithmic equations) (25)

  1. Given f(x)=2x+1 f(x) = 2x + 1 and g(x)=x2 g(x) = x^2 , what is the composition f(g(3)) f(g(3)) ?

    • A.19
    • B.49
    • C.13
    • D.37
    Show answerHide answer

    Correct answer: 19

    The value is 19. A composition is evaluated from the inside out, so first compute g(3)=32=9 g(3) = 3^2 = 9 , then apply f to that result: f(9)=2(9)+1=19 f(9) = 2(9) + 1 = 19 . Computing f(3) first and then squaring would give the wrong order of operations, since f(g(3)) f(g(3)) requires g to act on 3 before f does.

  2. What is the inverse function of f(x)=3x−6 f(x) = 3x - 6 ?

    • A.f−1(x)=x+63 f^{-1}(x) = \frac{x + 6}{3}
    • B.f−1(x)=x−63 f^{-1}(x) = \frac{x - 6}{3}
    • C.f−1(x)=3x+6 f^{-1}(x) = 3x + 6
    • D.f−1(x)=x+36 f^{-1}(x) = \frac{x + 3}{6}
    Show answerHide answer

    Correct answer: f−1(x)=x+63 f^{-1}(x) = \frac{x + 6}{3}

    The inverse is f−1(x)=x+63 f^{-1}(x) = \frac{x + 6}{3} . To find an inverse, replace f(x) with y, swap x and y to get x=3y−6 x = 3y - 6 , then solve for y: adding 6 gives x+6=3y x + 6 = 3y , and dividing by 3 gives y=x+63 y = \frac{x + 6}{3} . Subtracting 6 instead of adding reverses the operation incorrectly, since the inverse must undo the original subtraction with addition.

  3. Rewrite the logarithmic equation log base 2 of 32 = x in exponential form and find x.

    • A.X = 5
    • B.X = 16
    • C.X = 4
    • D.X = 6
    Show answerHide answer

    Correct answer: X = 5

    The value is x = 5. The logarithm log base 2 of 32 = x means 2 raised to the power x equals 32, and since 25=32 2^5 = 32 , the answer is x = 5. Choosing 16 confuses 32 with a different power of 2, but 25=32 2^5 = 32 while 24=16 2^4 = 16 , so the exponent that produces 32 is 5.

  4. Use the properties of logarithms to write log base b of (xy2) (xy^2) as a sum or difference of logarithms.

    • A.Log base b of x + 2 log base b of y
    • B.Log base b of x + log base b of y2 y^2 multiplied together
    • C.2 (log base b of x + log base b of y)
    • D.Log base b of x - 2 log base b of y
    Show answerHide answer

    Correct answer: Log base b of x + 2 log base b of y

    The expanded form is log base b of x + 2 log base b of y. The product rule turns the log of a product into a sum of logs, giving log base b of x + log base b of y2 y^2 , and the power rule then moves the exponent 2 in front of the y term, producing 2 log base b of y. Using subtraction would apply the quotient rule, which does not fit a product.

  5. An investment grows according to the exponential model A=500(2)t A = 500(2)^t , where t is measured in decades. What is the account value after 3 decades?

    • A.4000
    • B.3000
    • C.1500
    • D.2500
    Show answerHide answer

    Correct answer: 4000

    The value is 4000. Substituting t=3 t = 3 gives A=500(2)3 A = 500(2)^3 , and since 23=8 2^3 = 8 , this becomes 500×8=4000 500 \times 8 = 4000 . Multiplying 500 by 2 and then by 3 to get 3000 treats the growth as repeated multiplication by a constant rather than as an exponent, but the model raises 2 to the power t t , as 2t 2^t .

  6. Solve the exponential equation 5x=125 5^x = 125 for x.

    • A.X = 3
    • B.X = 25
    • C.X = 5
    • D.X = 2
    Show answerHide answer

    Correct answer: X = 3

    The solution is x = 3. Both sides can be written with base 5 because 125 equals 53 5^3 , so 5x=53 5^x = 5^3 means the exponents must be equal, giving x = 3. Choosing 25 confuses the value 125 with a square, but 5 raised to the power 3 equals 125, while 5 squared is only 25.

  7. Evaluate log base 3 of 81.

    • A.27
    • B.3
    • C.9
    • D.4
    Show answerHide answer

    Correct answer: 4

    The value is 4. The expression log base 3 of 81 asks for the exponent that turns 3 into 81, and since 3 raised to the power 4 equals 81, the answer is 4. Choosing 27 confuses 81 with 3 cubed, but 33 3^3 equals 27 while 34 3^4 equals 81.

  8. Given f(x) = x - 4 and g(x) = 2x, what is the composition g(f(7))?

    • A.18
    • B.10
    • C.6
    • D.3
    Show answerHide answer

    Correct answer: 6

    The value is 6. Composition works from the inside out, so first evaluate f(7) = 7 - 4 = 3, then apply g to that result: g(3) = 2(3) = 6. Doubling 7 first and then subtracting 4 to get 10 reverses the required order, since g(f(7)) needs f to act on 7 before g does.

  9. Rewrite the exponential statement 43=64 4^3 = 64 in logarithmic form.

    • A.Log base 3 of 64 = 4
    • B.Log base 64 of 4 = 3
    • C.Log base 4 of 64 = 3
    • D.Log base 4 of 3 = 64
    Show answerHide answer

    Correct answer: Log base 4 of 64 = 3

    The correct form is log base 4 of 64 = 3. An exponential statement baseexponent=result \text{base}^{\text{exponent}} = \text{result} converts to a logarithm where the base stays the base, the result becomes the argument, and the exponent becomes the value, giving log base 4 of 64 = 3. Writing log base 3 of 64 = 4 swaps the exponent and base incorrectly.

  10. A bacteria population is modeled by P=200(3)t P = 200(3)^t , where t is in hours. What is the population after 2 hours?

    • A.1200
    • B.1800
    • C.600
    • D.400
    Show answerHide answer

    Correct answer: 1800

    The value is 1800. Substituting t = 2 gives P=200(3)2 P = 200(3)^2 , and since 32=9 3^2 = 9 , this becomes 200 times 9 = 1800. Multiplying 200 by 3 and then by 2 to get 1200 treats the growth as a constant multiplier rather than an exponent, but the model raises 3 to the power t.

  11. Use the quotient rule for logarithms to expand log base 5 of (x / 7).

    • A.Log base 5 of x + log base 5 of 7
    • B.Log base 5 of x divided by log base 5 of 7
    • C.Log base 5 of 7 - log base 5 of x
    • D.Log base 5 of x - log base 5 of 7
    Show answerHide answer

    Correct answer: Log base 5 of x - log base 5 of 7

    The expanded form is log base 5 of x - log base 5 of 7. The quotient rule states that the log of a quotient equals the log of the numerator minus the log of the denominator, so log base 5 of (x / 7) becomes log base 5 of x - log base 5 of 7. Using addition would apply the product rule, which does not fit a quotient.

  12. Solve the logarithmic equation log base 4 of x = 3 for x.

    • A.12
    • B.81
    • C.64
    • D.7
    Show answerHide answer

    Correct answer: 64

    The solution is x = 64. The equation log base 4 of x = 3 converts to exponential form as 4 raised to the power 3 equals x, and since 43=64 4^3 = 64 , the value of x is 64. Multiplying 4 by 3 to get 12 treats the relationship as multiplication, but the logarithm makes 3 an exponent on the base 4.

  13. What is the inverse function of f(x) = (x / 2) + 5?

    • A.F inverse (x) = 2(x - 5)
    • B.F inverse (x) = 2x - 5
    • C.F inverse (x) = (x - 5) / 2
    • D.F inverse (x) = 2x + 5
    Show answerHide answer

    Correct answer: F inverse (x) = 2(x - 5)

    The inverse is f inverse (x) = 2(x - 5). To find an inverse, write y = (x / 2) + 5, swap x and y to get x = (y / 2) + 5, subtract 5 to get x - 5 = y / 2, then multiply by 2 to get y = 2(x - 5). Dividing by 2 instead of multiplying fails to undo the original division.

  14. Solve the exponential equation 2x+1=16 2^{x + 1} = 16 for x.

    • A.4
    • B.8
    • C.5
    • D.3
    Show answerHide answer

    Correct answer: 3

    The solution is x = 3. Both sides can be written with base 2 since 16 equals 24 2^4 , so 2x+1=24 2^{x + 1} = 2^4 means the exponents are equal, giving x + 1 = 4 and therefore x = 3. Choosing 4 forgets to subtract the 1 from the exponent, but x + 1 must equal 4, so x is 3.

  15. Use the power rule for logarithms to rewrite log base 2 of x5 x^5 .

    • A.5 log base 2 of x
    • B.Log base 2 of x + 5
    • C.(log base 2 of x) raised to the 5th power
    • D.5 + log base 2 of x
    Show answerHide answer

    Correct answer: 5 log base 2 of x

    The rewritten form is 5 log base 2 of x. The power rule lets an exponent inside a logarithm move to the front as a coefficient, so log base 2 of x5 x^5 becomes 5 log base 2 of x. Raising the entire logarithm to the 5th power misapplies the rule, since the exponent multiplies the log rather than acting as an outer power.

  16. A car loses value according to V=20000(0.8)t V = 20000(0.8)^t , where t is in years. What is the value after 1 year?

    • A.18000
    • B.16000
    • C.4000
    • D.10000
    Show answerHide answer

    Correct answer: 16000

    The value is 16000. Substituting t = 1 gives V=20000(0.8)1 V = 20000(0.8)^1 , and since 0.8 raised to the power 1 is just 0.8, this becomes 20000 times 0.8 = 16000. Subtracting 0.8 from 20000 or treating 0.8 as a flat loss gives a wrong figure, but the decay multiplies the value by 0.8 each year.

  17. Evaluate the natural logarithm ln⁡(e4) \ln(e^4) .

    • A.e4 e^4
    • B.4
    • C.1
    • D.4e
    Show answerHide answer

    Correct answer: 4

    The value is 4. The natural logarithm and the base e are inverse operations, so ln⁡(e4) \ln(e^4) simply returns the exponent, which is 4. Leaving the answer as e4 e^4 ignores the cancellation, but ln of e raised to any power equals that power because ln has base e.

  18. Condense the expression log base 3 of 5 + log base 3 of 4 into a single logarithm.

    • A.Log base 3 of 9
    • B.Log base 3 of 1.25
    • C.Log base 3 of 20
    • D.Log base 6 of 20
    Show answerHide answer

    Correct answer: Log base 3 of 20

    The condensed form is log base 3 of 20. The product rule states that the sum of two logarithms with the same base equals the log of the product, so log base 3 of 5 + log base 3 of 4 becomes log base 3 of (5 times 4) = log base 3 of 20. Adding the arguments to get 9 misuses the rule, since the arguments are multiplied, not added.

  19. What is the value of log base 10 of 1000?

    • A.3
    • B.100
    • C.10
    • D.2
    Show answerHide answer

    Correct answer: 3

    The value is 3. The common logarithm log base 10 of 1000 asks for the power of 10 that gives 1000, and since 10 raised to the power 3 equals 1000, the answer is 3. Choosing 100 confuses the argument with the answer, but 103 10^3 equals 1000 while 102 10^2 equals only 100.

  20. Given f(x) = 3x and g(x) = x + 2, find the composition (f composed with g)(x).

    • A.3x + 2
    • B.3x + 6
    • C.X + 6
    • D.3x2+2 3x^2 + 2
    Show answerHide answer

    Correct answer: 3x + 6

    The composition is 3x + 6. The notation (f composed with g)(x) means f(g(x)), so substitute g(x) = x + 2 into f to get f(x + 2) = 3(x + 2) = 3x + 6. Writing 3x + 2 only multiplies the x term and ignores distributing 3 across the entire input x + 2.

  21. Solve the exponential equation 10x=0.01 10^x = 0.01 for x.

    • A.2
    • B.-1
    • C.0.1
    • D.-2
    Show answerHide answer

    Correct answer: -2

    The solution is x = -2. The value 0.01 equals 10 raised to the power negative 2, so 10x=10−2 10^x = 10^{-2} means x = -2. Choosing positive 2 ignores that 0.01 is less than 1, which requires a negative exponent because 10 raised to a positive power gives a number greater than 1.

  22. Solve the logarithmic equation log base 2 of (x + 3) = 4 for x.

    • A.5
    • B.13
    • C.11
    • D.1
    Show answerHide answer

    Correct answer: 13

    The solution is x = 13. Converting log base 2 of (x + 3) = 4 to exponential form gives 2 raised to the power 4 equals x + 3, so 16 = x + 3, and subtracting 3 gives x = 13. Forgetting to subtract the 3 leaves 16, but the argument x + 3 equals 16, so x must be 13.

  23. What is the inverse function of the exponential function f(x)=7x f(x) = 7^x ?

    • A.F inverse (x) = log base 7 of x
    • B.F inverse (x) = x7 x^7
    • C.F inverse (x) = log base x of 7
    • D.F inverse (x) = 7 / x
    Show answerHide answer

    Correct answer: F inverse (x) = log base 7 of x

    The inverse is f inverse (x) = log base 7 of x. The logarithm is defined as the inverse of an exponential function with the same base, so the inverse of f(x)=7x f(x) = 7^x is the logarithm base 7. Writing x7 x^7 confuses an exponential function with a power function, but only a logarithm undoes a base raised to a variable exponent.

  24. Evaluate log base 6 of 1.

    • A.0
    • B.1
    • C.6
    • D.Undefined
    Show answerHide answer

    Correct answer: 0

    The value is 0. Any positive base raised to the power 0 equals 1, so log base 6 of 1 asks for the exponent that gives 1, which is 0. Choosing 1 confuses the argument with the answer, but 60 6^0 equals 1 while 61 6^1 equals 6.

  25. A savings account follows the continuous growth model A=1000e0.05t A = 1000e^{0.05t} . Which value represents the initial amount when t = 0?

    • A.1050
    • B.1005
    • C.1000
    • D.0
    Show answerHide answer

    Correct answer: 1000

    The initial amount is 1000. Setting t = 0 gives A=1000e0.05×0=1000e0 A = 1000e^{0.05 \times 0} = 1000e^0 , and since e0 e^0 equals 1, the result is 1000 times 1 = 1000. Choosing 1050 incorrectly adds growth at time zero, but no time has passed when t = 0, so the exponent is 0 and the account holds only the starting amount.

Geometry and Trigonometry (perimeter, area, and volume, coordinate geometry, trigonometric functions, identities and equations) (25)

  1. On the unit circle, what is the value of cos⁡(60∘) \cos(60^\circ) ?

    • A.12 \frac{1}{2}
    • B.32\frac{\sqrt{3}}{2}
    • C.22\frac{\sqrt{2}}{2}
    • D.0
    Show answerHide answer

    Correct answer: 12 \frac{1}{2}

    The value is 12 \frac{1}{2} . On the unit circle a point is written as (cos⁡θ,sin⁡θ) (\cos\theta, \sin\theta) , and the terminal side of 60 degrees lands at the coordinates (12,32) (\frac{1}{2}, \frac{\sqrt{3}}{2}) . The x-coordinate of that point gives the cosine, which is 12 \frac{1}{2} . Reporting 32\frac{\sqrt{3}}{2} mistakes the y-coordinate (the sine of 60 degrees) for the cosine.

  2. A right triangle has legs of length 9 and 12. What is the length of the hypotenuse?

    • A.21
    • B.15
    • C.63\sqrt{63}
    • D.225
    Show answerHide answer

    Correct answer: 15

    The hypotenuse is 15. The Pythagorean theorem states that the square of the hypotenuse equals the sum of the squares of the legs, so c2=92+122=81+144=225 c^2 = 9^2 + 12^2 = 81 + 144 = 225 , and 225\sqrt{225} is 15. Choosing 225 stops at c2 c^2 without taking the square root, and choosing 21 simply adds the legs instead of using the theorem.

  3. What is the distance between the points (2, -1) and (7, 11) in the coordinate plane?

    • A.13
    • B.17
    • C.119\sqrt{119}
    • D.12
    Show answerHide answer

    Correct answer: 13

    The distance is 13. The distance formula takes (Δx)2+(Δy)2 \sqrt{(\Delta x)^2 + (\Delta y)^2} , the root of the sum of the squared differences in the coordinates: the horizontal change is 7−2=5 7 - 2 = 5 and the vertical change is 11−(−1)=12 11 - (-1) = 12 , giving 52+122 \sqrt{5^2 + 12^2} = 25+144\sqrt{25 + 144} = 169\sqrt{169} = 13. Adding the differences 5 and 12 to get 17 skips the squaring and square-root steps that the formula requires.

  4. What is the midpoint of the segment connecting (-4, 6) and (10, -2)?

    • A.(7, 4)
    • B.(-2, 2)
    • C.(3, 2)
    • D.(14, -8)
    Show answerHide answer

    Correct answer: (3, 2)

    The midpoint is (3, 2). The midpoint formula averages the x-coordinates and the y-coordinates separately: the x-coordinate is −4+102=62=3 \frac{-4 + 10}{2} = \frac{6}{2} = 3 , and the y-coordinate is 6+(−2)2=42=2 \frac{6 + (-2)}{2} = \frac{4}{2} = 2 . The point (14, -8) results from subtracting the coordinates instead of averaging them, which finds a difference rather than the center of the segment.

  5. A cylindrical water tank has a radius of 5 feet and a height of 8 feet. Using the formula V=πr2h V = \pi r^2 h , what is its volume in terms of π \pi ?

    • A.80π 80\pi cubic feet
    • B.40π 40\pi cubic feet
    • C.200π 200\pi cubic feet
    • D.400π 400\pi cubic feet
    Show answerHide answer

    Correct answer: 200π 200\pi cubic feet

    The volume is 200π 200\pi cubic feet. The volume of a cylinder equals π \pi times the radius squared times the height, so V=π⋅52⋅8=π⋅25⋅8=200π V = \pi \cdot 5^2 \cdot 8 = \pi \cdot 25 \cdot 8 = 200\pi . Getting 80π 80\pi comes from multiplying the radius by 2 instead of squaring it, since 5⋅2⋅8=80 5 \cdot 2 \cdot 8 = 80 , but the formula requires the radius to be squared.

  6. A rectangular garden is 18 meters long and 11 meters wide. A walking path is built around its entire outer edge. What length of path is needed, and how does it differ from the garden's area?

    • A.The path (perimeter) is 58 meters, while the area is 198 square meters.
    • B.The path (perimeter) is 198 meters, while the area is 58 square meters.
    • C.The path (perimeter) is 29 meters, while the area is 198 square meters.
    • D.The path (perimeter) is 58 meters, while the area is 29 square meters.
    Show answerHide answer

    Correct answer: The path (perimeter) is 58 meters, while the area is 198 square meters.

    The path is 58 meters and the area is 198 square meters. Perimeter measures the distance around the rectangle, so it adds all four sides: 2×(18+11)=2×29=58 2 \times (18 + 11) = 2 \times 29 = 58 meters. Area measures the surface enclosed, so it multiplies length by width: 18×11=198 18 \times 11 = 198 square meters. Swapping the two results confuses a one-dimensional boundary length with a two-dimensional region.

  7. If sin⁡(θ)=35 \sin(\theta) = \frac{3}{5} and theta is an acute angle, what is the value of cos⁡(θ) \cos(\theta) ?

    • A.53 \frac{5}{3}
    • B.34 \frac{3}{4}
    • C.22\frac{\sqrt{2}}{2}
    • D.45 \frac{4}{5}
    Show answerHide answer

    Correct answer: 45 \frac{4}{5}

    The value is 45 \frac{4}{5} . The Pythagorean identity states that sin⁡2θ+cos⁡2θ=1 \sin^2\theta + \cos^2\theta = 1 , so cos⁡2θ=1−(35)2=1−925=1625 \cos^2\theta = 1 - (\frac{3}{5})^2 = 1 - \frac{9}{25} = \frac{16}{25} , and the positive square root for an acute angle is 45 \frac{4}{5} . Reporting 53 \frac{5}{3} inverts the given sine ratio rather than applying the identity, which does not produce the cosine of the same angle.

  8. A triangle has a base of 14 centimeters and a height of 6 centimeters. What is its area?

    • A.20 square centimeters
    • B.42 square centimeters
    • C.84 square centimeters
    • D.42 centimeters
    Show answerHide answer

    Correct answer: 42 square centimeters

    The area is 42 square centimeters. The area of a triangle equals one-half times the base times the height, so A = (1/2) times 14 times 6 = (1/2) times 84 = 42. Choosing 84 square centimeters forgets the factor of one-half and gives the area of a rectangle with those dimensions instead of a triangle.

  9. A circle has a radius of 7 inches. Using the formula C = 2 pi r, what is its circumference in terms of pi?

    • A.7 pi inches
    • B.14 pi inches
    • C.49 pi inches
    • D.28 pi inches
    Show answerHide answer

    Correct answer: 14 pi inches

    The circumference is 14 pi inches. The circumference of a circle equals 2 times pi times the radius, so C = 2 times pi times 7 = 14 pi. Choosing 49 pi inches squares the radius, which produces the area instead, because squaring is the operation used for area rather than for circumference.

  10. A circle has a radius of 4 meters. Using the formula A = pi r squared, what is its area in terms of pi?

    • A.8 pi square meters
    • B.4 pi square meters
    • C.16 pi square meters
    • D.16 pi meters
    Show answerHide answer

    Correct answer: 16 pi square meters

    The area is 16 pi square meters. The area of a circle equals pi times the radius squared, so A = pi times 4 squared = pi times 16 = 16 pi. Choosing 8 pi square meters doubles the radius instead of squaring it, but the formula requires the radius to be multiplied by itself.

  11. Two angles are complementary, and one of them measures 35 degrees. What is the measure of the other angle?

    • A.145 degrees
    • B.65 degrees
    • C.55 degrees
    • D.35 degrees
    Show answerHide answer

    Correct answer: 55 degrees

    The other angle is 55 degrees. Complementary angles add up to 90 degrees, so the missing angle is 90 minus 35 = 55. Choosing 145 degrees uses 180 instead of 90, which is the rule for supplementary angles rather than complementary angles.

  12. Two angles are supplementary, and one of them measures 110 degrees. What is the measure of the other angle?

    • A.70 degrees
    • B.20 degrees
    • C.250 degrees
    • D.90 degrees
    Show answerHide answer

    Correct answer: 70 degrees

    The other angle is 70 degrees. Supplementary angles add up to 180 degrees, so the missing angle is 180 minus 110 = 70. Choosing 20 degrees uses 90 instead of 180, which is the rule for complementary angles rather than supplementary angles.

  13. In a right triangle, the angle theta has an opposite side of length 8 and a hypotenuse of length 17. What is sin(theta)?

    • A.17/8
    • B.8/15
    • C.15/17
    • D.8/17
    Show answerHide answer

    Correct answer: 8/17

    The value is 8/17. The sine of an angle equals the length of the opposite side divided by the hypotenuse, so sin(theta) = 8/17. Choosing 17/8 inverts the ratio by placing the hypotenuse over the opposite side, which does not match the definition of sine.

  14. A rectangular box has a length of 6 inches, a width of 3 inches, and a height of 4 inches. What is its volume?

    • A.13 cubic inches
    • B.72 cubic inches
    • C.36 cubic inches
    • D.72 square inches
    Show answerHide answer

    Correct answer: 72 cubic inches

    The volume is 72 cubic inches. The volume of a rectangular box equals length times width times height, so V = 6 times 3 times 4 = 72. Choosing 13 cubic inches adds the three dimensions instead of multiplying them, but volume requires the product of all three measurements.

  15. The two acute angles of a right triangle are in the ratio 2 to 3. What is the measure of the larger acute angle?

    • A.36 degrees
    • B.54 degrees
    • C.108 degrees
    • D.60 degrees
    Show answerHide answer

    Correct answer: 54 degrees

    The larger acute angle is 54 degrees. The two acute angles of a right triangle add to 90 degrees, so with parts 2x and 3x we have 2x + 3x = 90, giving 5x = 90 and x = 18; the larger angle is 3 times 18 = 54. Choosing 36 degrees reports the smaller angle, 2 times 18, rather than the larger one that the question asks for.

  16. A square has an area of 81 square feet. What is the length of one side?

    • A.40.5 feet
    • B.9 feet
    • C.20.25 feet
    • D.18 feet
    Show answerHide answer

    Correct answer: 9 feet

    The side length is 9 feet. The area of a square equals the side length squared, so the side equals area \sqrt{\text{area}} : 81\sqrt{81} is 9. Choosing 40.5 feet divides the area by 2, but finding a side from area requires taking a square root, not halving.

  17. A central angle in a circle measures 90 degrees, and the circle has a radius of 6 inches. What fraction of the circle's full area does the resulting sector cover?

    • A.One-half
    • B.One-third
    • C.One-fourth
    • D.One-eighth
    Show answerHide answer

    Correct answer: One-fourth

    The sector covers one-fourth of the circle. A full circle is 360 degrees, so a 90-degree central angle covers 90/360, which simplifies to one-fourth. Choosing one-half would correspond to a 180-degree angle, which is twice the angle actually given.

  18. In a right triangle, the side adjacent to angle theta has length 5 and the opposite side has length 12. What is tan(theta)?

    • A.5/12
    • B.13/12
    • C.12/13
    • D.12/5
    Show answerHide answer

    Correct answer: 12/5

    The value is 12/5. The tangent of an angle equals the length of the opposite side divided by the adjacent side, so tan(theta) = 12/5. Choosing 5/12 reverses the ratio by dividing the adjacent side by the opposite side, which contradicts the definition of tangent.

  19. A trapezoid has parallel sides of length 10 and 14 and a height of 5. What is its area?

    • A.60 square units
    • B.120 square units
    • C.35 square units
    • D.350 square units
    Show answerHide answer

    Correct answer: 60 square units

    The area is 60 square units. The area of a trapezoid equals one-half times the sum of the parallel sides times the height, so A = (1/2) times (10 + 14) times 5 = (1/2) times 24 times 5 = 60. Choosing 120 square units omits the factor of one-half, doubling the correct result.

  20. An angle measures 45 degrees. What is its equivalent measure in radians?

    • A.Pi/2 radians
    • B.Pi/3 radians
    • C.Pi/4 radians
    • D.Pi/6 radians
    Show answerHide answer

    Correct answer: Pi/4 radians

    The measure is pi/4 radians. To convert degrees to radians, multiply by pi over 180, so 45 times pi/180 = 45 pi/180, which simplifies to pi/4. Choosing pi/2 radians corresponds to 90 degrees, which is twice the given angle.

  21. A sphere has a radius of 3 centimeters. Using the formula V = (4/3) pi r cubed, what is its volume in terms of pi?

    • A.12 pi cubic centimeters
    • B.36 pi cubic centimeters
    • C.27 pi cubic centimeters
    • D.108 pi cubic centimeters
    Show answerHide answer

    Correct answer: 36 pi cubic centimeters

    The volume is 36 pi cubic centimeters. The volume of a sphere equals four-thirds times pi times the radius cubed, so V = (4/3) times pi times 3 cubed = (4/3) times pi times 27 = 36 pi. Choosing 108 pi cubic centimeters forgets the four-thirds factor by not dividing by 3, since 4 times 27 equals 108 before the division.

  22. Two parallel lines are cut by a transversal, and one of a pair of corresponding angles measures 73 degrees. What is the measure of the other corresponding angle?

    • A.107 degrees
    • B.17 degrees
    • C.73 degrees
    • D.146 degrees
    Show answerHide answer

    Correct answer: 73 degrees

    The other angle is 73 degrees. When two parallel lines are cut by a transversal, corresponding angles are equal, so the matching angle also measures 73 degrees. Choosing 107 degrees treats the angles as supplementary, but corresponding angles are congruent rather than adding to 180.

  23. A regular hexagon has a perimeter of 48 centimeters. What is the length of one side?

    • A.6 centimeters
    • B.8 centimeters
    • C.12 centimeters
    • D.24 centimeters
    Show answerHide answer

    Correct answer: 8 centimeters

    Each side is 8 centimeters. A regular hexagon has six equal sides, so each side equals the perimeter divided by 6: 48 divided by 6 = 8. Choosing 12 centimeters divides by 4 as if the figure were a square, but a hexagon has six sides rather than four.

  24. The interior angles of a triangle measure 40 degrees and 75 degrees. What is the measure of the third angle?

    • A.115 degrees
    • B.65 degrees
    • C.45 degrees
    • D.105 degrees
    Show answerHide answer

    Correct answer: 65 degrees

    The third angle is 65 degrees. The interior angles of any triangle add up to 180 degrees, so the third angle is 180 minus (40 + 75) = 180 minus 115 = 65. Choosing 115 degrees stops at the sum of the two known angles without subtracting from 180.

  25. A right circular cone has a radius of 6 feet and a height of 10 feet. Using the formula V = (1/3) pi r squared h, what is its volume in terms of pi?

    • A.360 pi cubic feet
    • B.120 pi cubic feet
    • C.60 pi cubic feet
    • D.1080 pi cubic feet
    Show answerHide answer

    Correct answer: 120 pi cubic feet

    The volume is 120 pi cubic feet. The volume of a cone equals one-third times pi times the radius squared times the height, so V = (1/3) times pi times 6 squared times 10 = (1/3) times pi times 36 times 10 = (1/3) times 360 pi = 120 pi. Choosing 360 pi cubic feet omits the one-third factor, which is what distinguishes a cone from a cylinder of the same base and height.

References

  1. 1.ALEKS Corporation (McGraw Hill). “ALEKS Placement, Preparation and Learning (ALEKS PPL).” mheducation.com. ↑
  2. 2.ALEKS Corporation (McGraw Hill). “Higher Education Math Placement — Placement Problem Types.” aleks.com. ↑
  3. 3.ALEKS Corporation (McGraw Hill). “ALEKS PPL — Knowledge Assessment.” mheducation.com. ↑
  4. 4.ALEKS Corporation (McGraw Hill). “Scheduling a Test — ALEKS Higher Education Math.” aleks.com. ↑
  5. 5.ALEKS Corporation (McGraw Hill). “ALEKS PPL Efficacy and Research.” mheducation.com. ↑
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